Answer: x^2 + y^2 + 18y + 81 = 0
Step-by-step explanation:
The equation of a circle with center at the point (0, -9) and radius 9 is given by the following equation:
(x - 0)^2 + (y + 9)^2 = 9^2
This can be simplified to the following:
x^2 + y^2 + 18y + 81 = 0
This is the equation of a circle with center at (0, -9) and radius 9.
Please help me with the circled math question homework
The expressions are simplified to give;
7. 4n³(3n² + 4)
8. -3x(3x² - 4)
9. 5(k² - 8k + 2)
10. -10(6 + 6n² + 5n³)
11. 3(6n³ - 4n - 7)
12. 9(7n³ + 9n + 2)
What are algebraic expressions?Algebraic expressions are defined as mathematical expressions that are composed of variables, coefficients, terms, factors and constants.
These algebraic expressions are also made up of arithmetic operations, such as;
AdditionBracketSubtractionDivisionParenthesesMultiplicationTo factorize the expressions, we have;
12n⁵ + 16n³
Find the common term
4n³(3n² + 4)
-9x³ - 12x
find the common term
-3x(3x² - 4)
5k² - 40k + 10
find the common terms
5(k² - 8k + 2)
-60 + 60n² + 50n³
find the common term
-10(6 + 6n² + 5n³)
18n³ -12n - 21
find the common term
3(6n³ - 4n - 7)
63n³ + 81n + 18
Find the common term
9(7n³ + 9n + 2)
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The average dollar values of the 30 stocks in the DIA mutual fund on April 15, 2019 are summarized below. 100 130 200 DIA 300 330 Mutual Fund Minimum First Quartile (01) Third Quartile (03) Median Maximum DIA (a) 6.66 68.17 142.76 168.19 344.68 Answer the following about the DIA mutual fund by referring to the five-number summary and boxplot. If calculations are required, show your work and round results to two decimal places. Use correct units throughout. 2. What is the range in individual stock prices within this mutual fund? (3 pt) 3. An individual stock in the highest 25% of prices had a dollar value of at least how much? (2 pt) 4. If an individual stock price falls in the middle 50% of stock prices for this mutual fund, it must have a value between what two prices? Name them both. (4 pt) 5. Is the shape of the distribution of individual stock prices in this mutual fund approximately symmetric, left-skewed, or right-skewed? How do you know that from the boxplot? (4 pt) 6. Is the mean or the median a more appropriate measure of center for a distribution with this shape? Why? (4 pt) 7. Would you expect the mean of the individual stock prices within this mutual fund to be greater than, less than, or approximately equal to the median? Explain your choice. (4 pt)
2. The range in individual stock prices within this mutual fund is 230.
3. An individual stock in the highest 25% of prices had a dollar value of at least Q3 = 344.68.
4. Individual stock prices in the middle 50% range between Q1 and Q3.
So, the prices are between 142.76 and 344.68.
5. This indicates a right-skewed distribution.
6. The median is a more appropriate measure of center for a right-skewed distribution.
7. We would expect the mean of the individual stock prices within this mutual fund to be greater than the median.
What is mutual fund?A financial tool called a mutual fund collects money from several investors. After that, the combined funds are invested in assets such as listed company stocks, corporate bonds, government bonds, and money market instruments.
To answer the questions about the DIA mutual fund based on the given information, let's refer to the five-number summary and boxplot:
Given:
Minimum: 100
First Quartile (Q1): 142.76
Median (Q2): 168.19
Third Quartile (Q3): 344.68
Maximum: 330
2. Range in individual stock prices within this mutual fund:
The range is calculated as the difference between the maximum and minimum values.
Range = Maximum - Minimum = 330 - 100 = 230
Therefore, the range in individual stock prices within this mutual fund is 230.
3. An individual stock in the highest 25% of prices:
To find the value of the individual stock in the highest 25% of prices, we need to find the value corresponding to the third quartile (Q3).
An individual stock in the highest 25% of prices had a dollar value of at least Q3 = 344.68.
4. Individual stock prices in the middle 50%:
The middle 50% of stock prices corresponds to the interquartile range (IQR), which is the difference between the first quartile (Q1) and the third quartile (Q3).
Individual stock prices in the middle 50% range between Q1 and Q3.
So, the prices are between 142.76 and 344.68.
5. Shape of the distribution of individual stock prices:
The shape of the distribution can be determined by analyzing the boxplot.
If the boxplot is approximately symmetric, the distribution is symmetric. If the boxplot has a longer tail on the left, it is left-skewed. If the boxplot has a longer tail on the right, it is right-skewed.
Based on the boxplot, we can see that the box (representing the interquartile range) is closer to the lower values, and the whisker on the right side is longer. This indicates a right-skewed distribution.
6. Appropriate measure of center for a right-skewed distribution:
In a right-skewed distribution, where the tail is longer on the right side, the mean is influenced by the outliers or extreme values, while the median is a more robust measure of center that is not affected by extreme values. Therefore, the median is a more appropriate measure of center for a right-skewed distribution.
7. Comparison of mean and median in this mutual fund:
For a right-skewed distribution, the mean tends to be greater than the median. This is because the presence of a few large values on the right side of the distribution pulls the mean towards higher values. In this case, we would expect the mean of the individual stock prices within this mutual fund to be greater than the median.
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the distribution for the size of families in one u.s. city is shown below. size proportion 2 0.422 3 0.234 4 0.205 5 0.088 6 0.032 7 0.019 a family is selected at random. find the probability that the size of the family is at least 3.
0.578. is the probability that the size of the family is at least 3.
What does the math term "probability" mean?
The simple definition of probability is the likelihood that something will occur. We can discuss the probabilities of various outcomes, or how likely they are, whenever we are unsure of how an event will turn out.
Statistics describes the examination of events subject to probability.
P(X>=3) can be written as
= 1 - P(X<3)
= P(X<=2)
= 1-0.422
= 0.578
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find a vector equation of the line tangent to the graph of r(t) at the point p0 on the curve r(t)= (3t - 1) i + 13t j + 16 k; P0(-1, 4)
Vector equation of the line tangent to the graph of r(t) at the point p0 on the curve r(t) = (3t - 1) i + 13t j + 4 k.
What is the vector equation at the point P0(-1, 4)?To find a vector equation of the line tangent to the graph of r(t) at the point P0 on the curve r(t) = (3t - 1) i + 13t j + 16 k, where P0 is given as (-1,4), we can use the following steps:
Step 1: Find the derivative of r(t) with respect to t:
r'(t) = 3 i + 13 j
Step 2: Evaluate the derivative at the point P0:
r'(-1) = 3 i + 13 j
Step 3: Use the point P0 and the vector r'(-1) to form the vector equation of the tangent line:
r(t) = P0 + r'(-1) t
where t is a scalar parameter.
Plugging in the values, we get:
r(t) = (-1)i + 4j + (3i + 13j)t
Simplifying, we get:
r(t) = (3t - 1) i + 13t j + 4 k
Therefore, the vector equation of the line tangent to the graph of r(t) at the point P0 on the curve
r(t) = (3t - 1) i + 13t j + 16 k is
r(t) = (3t - 1) i + 13t j + 4 k.
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3. The decimal expansion of 13/625 will terminate
after how many places of decimal?
(a) 1
(b) 2
(c) 3
(d) 4
The decimal expansion of the given fraction is 0.0208. Therefore, the correct answer is option D.
The given fraction is 13/625.
Decimals are one of the types of numbers, which has a whole number and the fractional part separated by a decimal point.
Here, the decimal expansion is 13/625 = 0.0208
So, the number of places of decimal are 4.
Therefore, the correct answer is option D.
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M109) solve
cos²x + 2 cosx + 1 = 0
Answer:
Step-by-step explanation:
\( \: \: \: \: \: \: \: \: \: \huge \color{green}{ \fbox \colorbox{black}{ \fbox{ \green {Answer} \: }}}\)
\( \longrightarrow \sf \color{teal}{ \cos {}^{2} (x) + 2 \cos(x) + 1} = 0\)
\( \longrightarrow \sf \color{teal}{ \cos {}^{2} (x) + \cos(x) + \cos(x) + 1} = 0\)
\( \longrightarrow \sf \color{teal}{ \cos {}^{} (x) ( \cos(x) + 1)+ 1(\cos(x) + 1} )= 0\)
\( \longrightarrow \sf \color{teal}{ ( \cos(x) + 1)(\cos(x) + 1} )= 0\)
\( \longrightarrow \sf \color{teal}{ ( (\cos(x) + 1} {}^{} ) {}^{2} = 0\)
\( \longrightarrow \sf \color{teal}{ ( (\cos(x) + 1} {}^{} ) {}^{} = 0\)
\( \longrightarrow \sf \color{teal}{ \cos(x) {}^{} }= - 1\)
\(\longrightarrow \sf \color{teal}{ x{}^{} }= \cos {}^{ - 1}( - 1)\)
\(\longrightarrow \sf \color{teal}{ x = (2n + 1) \pi \: \: \: \: rad}\)
where, \({ n \in \{whole \:\; number\}} \)
Principle value -
\( \longrightarrow \sf \color{teal}{ x} {}^{} {}^{} = \cos {}^{ - 1} ( - 1) \)
\( \longrightarrow \sf \color{teal}{ x} {}^{} {}^{} = (2n + 1) \pi \: \: \: \: rad \: \)
put n = 0
\( \longrightarrow \sf \color{teal}{ x} {}^{} {}^{} = (2(0) + 1) \pi \: \: \: \: rad \: \)
\( \longrightarrow \sf \color{teal}{ x} {}^{} {}^{} = (0 + 1) \pi \: \: \: \: rad \: \)
\( \longrightarrow \sf \color{teal}{ x} {}^{} {}^{} = \pi \: \: \: \: rad \: = 180 \degree\)
MATH SUFACE AREA OF PYRAMIDS
WILL GIVE YOU MY LAST 10 POINTS!!!! AND BRAINLYIST!!
Step-by-step explanation:
the surface areas are always the sum of the areas of the individual sides and base area.
so, all we need to do here is calculating the areas of triangles, rectangles (actually squares) and a hexagon.
the area of a triangle is
baseline × height / 2
or with Heron's formula when we have all sides
s = (a+b+c)/2
area = sqrt(s×(s-a)×(s-b)×(s-c))
the area of a rectangle is
length × width
for a square that is then
side × side = side²
and the area of a regular hexagon can be created again as sum of multiple sub-shapes. but ultimately it is
3 × sqrt(3) × side² / 2
1.
square base area : 10×10 = 100 cm²
lateral areas :
one triangle is 10×13/2 = 65 cm²
4 triangles are then 4×65 = 260 cm²
total surface area :
100 + 260 = 360 cm²
2a.
3 lateral triangles :
3 × 8×10/2 = 120 units²
base area (Heron's, as all 3 sides are 8 units) :
s = 3×8/2 = 12
area = sqrt(12×4×4×4) = sqrt(3×4×4×4×4) = 16×sqrt(3)
total surface area :
120 + 16×sqrt(3) = 147.7128129... units²
2b.
4 lateral triangles :
4 × 8×10/2 = 160 units²
base area : 8×8 = 64 units²
total surface area :
160 + 64 = 224 units²
2c.
6 lateral triangles :
6 × 8×20/2 = 480 units²
base area :
3×sqrt(3)×8²/2 = 96×sqrt(3)
total surface area :
480 + 96×sqrt(3) = 646.2768775... units²
2d.
base area : 16² = 256 units²
4 lateral triangles. but we need to get their height first.
Pythagoras :
(16/2)² + 24² = height²
8² + 24² = height²
64 + 576 = height²
height² = 640
height = sqrt(640) = sqrt(64×10) = 8×sqrt(10)
4 triangles are
4 × 16×8×sqrt(10)/2 = 256×sqrt(10) units²
total surface area :
256 + 256×sqrt(10) = 256×(1 + sqrt(10) = 1,065.543081... units²
Find the sum of 1
5
and 7
10
The expression written in equivalent form with common denominators is .
The sum is
Answer:
2/10 + 7/10
9/10
Step-by-step explanation:
I did the test.
Answer:
The expression written in equivalent form with common denominators is
✔ 2/10 + 7/10
The sum is
✔ 9/10
Step-by-step explanation:
pls help again lolll srry :((
Answer: 9
Step-by-step explanation:
an article bought for rs. 800 is sold for 5/4 of the cost price.Find the profit percentage.
Answer:
25%
Step-by-step explanation:
Step 1: Find the sale price
First, we have to find the price it was sold for.
\(\longmapsto\) 5/4 of 800 = 5/4 * 800
\(\frac54 * 800 = \\\\\frac{4000}{4} = 1000\\\\\)
The article was sold for rs. 1000
Step 2: Finding the percentage
To find the percentage, we have to divide the sale price over the cost of the article
\(\frac{1000}{800} = \frac54 = 1.25 = 125percent\)
The cost of the article is 100% or 1
\(1.25 - 1 = 0.25 - or- 25percent\)
25%
-Chetan K
What is the average rate of change of the function f given by f(x) = x4 - 5x on the closed interval (0, 3)?
Answer:
The average rate of change of the function is 22.
Step-by-step explanation:
The given function is :
\(f(x)=x^4-5x\)
We need to find the average rate of change of the function on the closed interval (0, 3).
The average rate of change of a function in interval (a,b) is given by :
\(R=\dfrac{f(b)-f(a)}{b-a}\)
Here, a = 0 and b = 3
\(R=\dfrac{(3^4-5(3))-(0^4-5(0))}{3-0}\\\\=\dfrac{66}{3}\\\\=22\)
So, the average rate of change of the function is 22.
Answer:
22
Step-by-step explanation:
(f(3)-f(0))/3
=66/3
=22
ASAP!!!
Determine the perimeter of the right triangle shown. Round your final answer to the nearest whole number, if necessary.
5 units
12 units
16 units
25 units
The perimeter of the triangle ABC is 12 units. Hence, option (B) is correct.
What is a triangle?A triangle is a geometric figure with three edges, three angles and three vertices. It is a basic figure in geometry.
The sum of the angles of a triangle is always 180°
In the given right angle triangle,
The vertices are A(-3, 2), B(-3, -1) and C(1, -1)
The distance between AB = 3,
And the distance between BC = 4
To find the distance of AC, use Pythagoreans theorem,
AC² = AB² + BC²
= 3² + 4²
= 9 + 16
AC² = 25
AC = 5
The perimeter of triangle ABC = AB + BC + AC
= 3 + 4 + 5
= 12
The perimeter of the triangle ABC is 12 unit.
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f5 The ratio of boys to girls in a class is 2:3. There are 30 students in the class. How many students are boys?
Answer:
12 boys
Step-by-step explanation:
Boys are 2 parts to girls 3 parts
2 out of (2+3) are boys ====> 2/5 ths are boys
2/5 * 30 = 12 boys
Answer:
12 boys
Step-by-step explanation:
The fraction of boys in the class are :
⇒ Ratio part of boys / Sum of ratio parts
⇒ 2 / 2 + 3
⇒ 2/5
Finding the number of boys :
⇒ Number of students × fraction of boys
⇒ 30 × 2/5
⇒ 6 × 2
⇒ 12 boys
Each soccer player has one yellow, one blue, and one white jersey. For the last game of the season, each player could choose which jersey they wanted to wear. The table below shows the percentage of players that wore each color jersey.
Jersey Color Percentage of Players
Yellow 0.35
Blue 0.45
White 0.20
Compare the probabilities of a randomly selected player wearing a certain jersey color and interpret the likelihood. Choose the statement that is true.
The player will be more likely to wear a yellow jersey than a white jersey because P(Yellow) > P(White).
The player will be more likely to wear a white jersey than a yellow jersey because P(White) > P(Yellow).
The player will be more likely to wear a yellow jersey than a blue jersey because P(Yellow) > P(Blue).
The player will be equally likely to wear a yellow jersey or a white jersey because P(Yellow) = P(White).
Answer:
The player will be more likely to wear a yellow jersey because P(yellow) is more tha P(white).
Step-by-step explanation:
Get rid of the 0s. 35 is more than 20, therefore 0.35 will also be more than 0.20.
Hope this helps!
20000000000 in scientific notation
Answer:
2.0×10¹⁰
Step-by-step explanation:
....................
giving brain help please!
a random sample of 150 people was taken. 98 of the people in the sample favored candidate a. we are interested in determining whether or not the proportion of the population in favor of candidate a is significantly more than 57%. [r] refer to exhibit 9-6a. at the 0.1 level of significance, what conclusion do you draw? group of answer choices
At the 0.1 level of significance, the conclusion we come up with is to reject the null hypothesis.
we are given that a random sample of 150 people was taken. 98 of the people in the sample favored the candidate, were it to determine whether or not the proportion of the population in favor of candidate a is significantly more than 57%.So we need to find the test statistic, which is 1.98 determined from the z score, here the rejection region is the number more than 1.28, and 1.98 is greater than 1.28, so it is better to simply reject the null hypothesis.
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9. What property was used to get from line 1 to line 2?
line 1: 16 + 3x + 5 + 2x
line 2:2x + 3x + 5 + 16
line 3:5x + 21
Answer: Commutative Property of Addition
This property says that A+B = B+A. The order of addition doesn't matter.
As an example, 2+3 = 3+2 since both sides evaluate to 5.
Need this asap show the formula work A(n)=a*r^n-1, Follow the directions and solve this sequenc: 9,-36,144,-576
A.
CR:-4
10th term: -2,359,296
B.
CR:4
10th term: 2,359,296
C.
CR:-4
10th term: 2,359,296
Answer:B.
CR:4
10th term: 2,359,296
Step-by-step explanation:
I am not 100% sure but I think I will tell you this answer might be wrong I am not sure
Use the Laplace transform to solve the following initial value problem: y" - 10y' +9y = 5t, y(0) = -1, y'(0) = 2. [8 marks] (b) Solve the following initial value problem using a Laplace transform method. y"-6y + 5y = 3e²t, y(0) = 2,y'(0) = 3. [12 marks] (c) Use the Laplace transform to solve the given system of differential equations: dx dy 2 + = 5et dt dt dy dx - 3- = 5 dt dt Given that when t = 0, x = 0 and y = 0. [12 marks]
The Laplace transform is applied to obtain the solution for y(t). In the second problem, the Laplace transform is used to solve for y(t), and in the third problem, to solve the system of differential equations for x(t) and y(t).
(a) To solve the initial value problem y" - 10y' + 9y = 5t, y(0) = -1, y'(0) = 2, we take the Laplace transform of both sides of the equation. Using the properties of the Laplace transform, we convert the differential equation into an algebraic equation in terms of the Laplace transform variable s. Solving for the Laplace transform of y(t), Y(s), we then apply the inverse Laplace transform to find the solution y(t).
(b) For the initial value problem y" - 6y + 5y = 3\(e^2\)t, y(0) = 2, y'(0) = 3, we follow a similar procedure. Taking the Laplace transform of both sides, we obtain an algebraic equation in terms of the Laplace transform variable s. Solving for Y(s), the Laplace transform of y(t), and applying the inverse Laplace transform, we find the solution y(t).
(c) The given system of differential equations dx/dt + 2dy/dt = 5\(e^t\) and dy/dt - 3x - 5 = 0 is solved using the Laplace transform. Taking the Laplace transform of both equations and applying the initial conditions, we obtain two equations in terms of the Laplace transform variables s and X(s), Y(s). Solving these equations simultaneously, we find the Laplace transform of x(t) and y(t). Finally, applying the inverse Laplace transform, we obtain the solutions x(t) and y(t).
In all three problems, the Laplace transform provides a powerful method to solve the given initial value problems and the system of differential equations by transforming them into algebraic equations that can be easily solved.
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the area of a circle is 81 pi m^2. what is the circumference, in meters? express your answer in terms of pi.
============================================================
Explanation:
The area 81pi square meters leads to the radius 9 meters
Use the formula A = pi*r^2 to see why this is the case. You plug in A = 81pi and solve for r to get r = 9.
-----------------
Once you know the radius, you can determine the circumference C
C = 2*pi*r
C = 2*pi*9
C = 2*9*pi
C = 18pi
The circumference is the perimeter, or distance, around the circle.
You are analyzing survey results regarding whether or not people like low-cal buter or regular butter. 47 said they preferred low-cal and 59 said they preferred regular. What is the ratio of those who prefer the low-cal to those who prefer the regular?
Answer:
47:59
Step-by-step explanation:
The Pythagorean theorem is a2+b2=c2. Solve for b.
Answer: what is a and c
Step-by-step explanation:
We need a and c to solve for b.
Suppose that the characteristic of F is 0, and that K is a finite, but not normal, extension of F.(a) Let E = KG(K, F). Show that K is a normal extension of E, but not of any field F § E' § E.Solution. Proof:(b) Suppose K = F(a) for some a ⬠K. Let L be the splitting field of the minimal polynomial of a over F, withK C L. Prove that:(a) L is a normal extension of F.Solution. Put your answer here... (b) For any field L' such that K § L' § L, L' is not a normal extension of F. (L is called the normal closureof F in K.)Solution. Put your answer here...
Part (a) K is a normal extension of E, but not of F.
Part (b) L is a normal extension of F, but L' is not.
Part (a)
Let E = KG(K,F). Since E is a field extension of F and K is a finite extension of F, then K is a normal extension of E. This is because F[K] is a finite separable extension and hence normal.
However, K is not a normal extension of any field F ⊆ E. This is because K is not a normal extension of F by assumption.
Part (b)
(a) L is a normal extension of F. This is because K is a normal extension of F (by assumption) and L is a splitting field of a polynomial over F, and so is a finite extension of K. Hence, L is a normal extension of F.
(b) Let L be any field such that K ⊆ L and L ≠ L'. Then L is not a normal extension of F. This is because K is a normal extension of F, and if L were a normal extension of F, then L' would also be a normal extension of F by transitivity. Because L ≠ L', L is not a typical extension of F.
Complete Question:
Suppose that the characteristic of F is 0, and that K is a finite, but not normal, extension of F. (a) Let E = KG(K,F). Show that K s a normal extension of E, but not of any field F ES E. Solution. Proof (b) Suppose K -F(a) for some aE K. Let L be the splitting field of the minimal polynomial of a over F, with K C L. Prove that: (a) L is a normal extension of F Solution. Put your answer here... (b) For any field L, such that K L, Ç L, L' is not a normal extension of F. (L is called the normal closure of F in K.) Solution. Put your answer here...
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3(-4x - 8) = (Use distributive property to rewrite each expression)
Please help me answer.This is 100 points and whoever gets it right gets brainliest.
Thank you and good luck.
Answer:
Step-by-step explanation:
In first step, we just open the brackets and you should know that ++ = + and +- = - and -- = + and -+ is also equal to -
after opening the brackets we combine terms which are a like
then any order, any grouping you can write the answer in any order and you can also take - common and it will be written as
-(5p-7a+6)
if you multiply the minus it will be the same.
HELPPP WILL MAKE BRAINLIEST
Describe the error in the work shown.
3vx(y^12)/4^3 = 3vx^3(y^12)/3v4^3
=3vx^3(y^3)^4/3v4^3
=xy^3/4
The error in the work shown is in the second step of the calculation. Let's break down the incorrect step and identify the mistake:
3vx(y^12)/4^3 = 3vx^3(y^12)/3v4^3
The error occurs when simplifying the expression under the square root. The expression (y^12) is incorrectly simplified to (y^3)^4.
The correct simplification should be:
3vx^3(y^12)/3v4^3 = 3vx^3(y^3)^4/3v4^3
The mistake is that (y^12) cannot be simplified to (y^3)^4. In this step, the exponent should be divided by 3, not raised to the power of 4.
The correct simplification should be:
3vx^3(y^12)/3v4^3 = 3vx^3(y^4)/3v4^3
Therefore, the final simplified expression should be xy^4/4, instead of xy^3/4.
Kindly Heart and 5 Star this answer, thanks!For each type of effect listedâmain effects, two-way interactions, and three-way interactionsâidentify the maximum number of possible effects that could be tested in a 2 Ã 2 Ã 2 factorial design. - 3 main effects- 1 three- way interaction- 3 two-way interactions
The maximum number of possible effects that could be tested in a 2x2x2 factorial design with 3 main effects, 3 two-way interactions, and 1 three-way interaction is 7.
In a 2 x 2 x 2 factorial design, we can test the following maximum number of possible effects:
Main effects:
There are 3 main effects in this design, one for each factor (A, B, and C). You would analyze the effect of each factor independently on the outcome variable.
Two-way interactions:
There are 3 possible two-way interactions that can be tested in this design: AxB, AxC, and BxC.
These interactions examine the combined effects of two factors on the outcome variable.
Three-way interactions:
There is 1 possible three-way interaction that can be tested in this design: AxBxC.
This interaction examines the combined effect of all three factors (A, B, and C) on the outcome variable.
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pls help me i dont care if u get it wrong it wont bother me but pls help me :/
Answer:
3; 6; 9; 12; 15; 18;
Step-by-step explanation:
Multiples of 3:
3*1=3
3*2=6
3*3=9
3*4=12
3*5=15
3*6=18
Answer:
3,6,9,12,15,18
Step-by-step explanation:
I think this might be correct I'm not sure
Number 2 please help quick .Asap
Problem 2, Part (a)
A = event elevator's 1st stop at the 2nd floor
P(A) = 3/4
Since the elevator needs to go up one floor
B = event elevator has its 2nd stop at the 3rd floor
P(B given A) = probability event B happens given event A happened
P(B given A) = 3/4
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P(A and B) = P(A)*P(B given A)
P(A and B) = (3/4)*(3/4)
P(A and B) = 9/16
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Answer: 9/16===============================================================
Problem 2, Part (b)
A = event elevator's 1st stop at the 2nd floor
P(A) = 3/4
B = event elevator has its 2nd stop at the 3rd floor
P(B given A) = 3/4
C = event elevator has its 3rd stop at 4th floor
P(C given (A and B)) = 3/4
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P(A & B & C) = P(A)*P(B given A)*P(C given (A and B))
P(A & B & C) = (3/4)*(3/4)*(3/4)
P(A & B & C) = 27/64
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Answer: 27/64===============================================================
Problem 2, Part (c)
A = event elevator's 1st stop at the 2nd floor
x = P(A) = 3/4
B = event elevator has its 2nd stop at the 3rd floor
y = P(B given A) = 3/4
C = event elevator has its 3rd stop at 2nd floor
z = P(C given (A and B)) = 1/4
D = event elevator has its 4th stop at 1st floor
w = P(D given (A & B & C)) = 1/4
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P(A & B & C & D) = x*y*z*w
P(A & B & C & D) = (3/4)*(3/4)*(1/4)*(1/4)
P(A & B & C & D) = 9/256
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Answer: 9/256