Answers
Answer:
\([I_2]=0.105M\)
Explanation:
Hello.
In this case, when hydrogen and iodine react at equilibrium, the reaction is:
\(H_2+I_2\rightleftharpoons 2HI\)
So the equilibrium expression is:
\(Kc=\frac{[HI]^2}{[H_2][I_2]}\)
Which can be also written in terms of the ICE chart knowing that Kc is 57.0:
\(Kc=\frac{(2x)^2}{([H_2]_0-x)([I_2]_0-x)}\)
Whereas the initial concentrations of both hydrogen and iodine are 0.100 M (0.500mol/1.00L), thus, we write:
\(Kc=\frac{(2x)^2}{(0.5-x)(0.5-x)}\\\\57.0=\frac{(2x)^2}{(0.5-x)^2}\)
Which can be solved as follows:
\(\sqrt{57.0} =\sqrt{\frac{(2x)^2}{(0.5-x)^2}} \\\\7.55=\frac{2x}{0.5-x} \\\\7.55*(0.5-x)=2x\\\\3.775-7.55x=2x\\\\x=\frac{3.775}{9.55}\\ \\x=0.395M\)
Therefore, the concentration of iodine at equilibrium is:
\([I_2]=0.5M-0.395M=0.105M\)
Best regards!
Related Questions
Most ecosystems originally get their energy from
Answers
What volume in mL of 0.220 M HBr solution is required to produce 0.0120 moles of HBr?
Answers
The volume of a 0.220 M HBr solution required to produce 0.0120 moles of HBr is 54.5 mL.
To calculate the volume of a 0.220 M HBr solution required to produce 0.0120 moles of HBr, we can use the following formula:
Volume (in liters) = moles / concentration
First, we need to convert the moles of HBr to liters:
0.0120 moles / (0.220 mol/L) = 0.0545 L
Next, we can convert liters to milliliters:
0.0545 L x 1000 mL/L = 54.5 mL
Therefore, the volume of a 0.220 M HBr solution required to produce 0.0120 moles of HBr is 54.5 mL.
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In using the Haber process in the formation of ammonia, what mass of hydrogen is needed to produce 51.0 grams of ammonia? 3 H₂(g) + N2 (g) → 2 NH3(g).
Answers
The mass of hydrogen needed to produce 51.0 grams of ammonia is ≈ 9.07 grams.
To determine the mass of hydrogen required to produce 51.0 grams of ammonia (NH3) using the Haber process, we need to calculate the stoichiometric ratio between hydrogen and ammonia.
From the balanced chemical equation:
3 H₂(g) + N₂(g) → 2 NH₃(g)
We can see that for every 3 moles of hydrogen (H₂), we obtain 2 moles of ammonia (NH₃).
First, we need to convert the given mass of ammonia (51.0 grams) to moles. The molar mass of NH₃ is 17.03 g/mol.
Number of moles of NH₃ = Mass / Molar mass
= 51.0 g / 17.03 g/mol
≈ 2.995 moles
Next, using the stoichiometric ratio, we can calculate the moles of hydrogen required.
Moles of H₂ = (Moles of NH₃ × Coefficient of H₂) / Coefficient of NH₃
= (2.995 moles × 3) / 2
≈ 4.493 moles
Finally, we can convert the moles of hydrogen to mass using the molar mass of hydrogen (2.02 g/mol).
Mass of H₂ = Moles × Molar mass
= 4.493 moles × 2.02 g/mol
≈ 9.07 grams
Therefore, approximately 9.07 grams of hydrogen is needed to produce 51.0 grams of ammonia in the Haber process.
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How many moles of Al will be consumed when 0.400 mol of Al2O3 are produced in
the following equation?
4A1+302 -> 2A1203
A)
0.200 mol
B) 0.400 mol
C) 0.800 mol
D) 0.600 mol
Answers
Answer:
C) 0.800 mol
Explanation:
4Al + 3O₂ → 2Al₂O₃In order to convert from moles of Al₂O₃ into moles of Al, we'll need to use the stoichiometric coefficients, using a conversion factor that has Al₂O₃ moles in the denominator and Al moles in the numerator:
0.400 mol Al₂O₃ * \(\frac{4molAl}{2molAl_2O_3}\) = 0.800 mol AlSo the correct answer is option C).
A certain metal M forms a soluble nitrate salt M NO Suppose the left half cell of a galvanic cell apparatus is filled with a 3.00 mM solution of M(NO) and the right half cell with a 3.00 M solution of the same substance. Electrodes made of M are dipped into both solutions and a voltmeter is connected between them. The temperature of the apparatus is held constant at 20.0 °C.
1. Which electrode will be positive? What voltage will the voltmeter show?
a. left
b. right
2. Assume its positive lead is connected to the positive electrode. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
Answers
Answer:
Explanation:
From the information given:
left half-cell = 3.00 mM M(NO)
right half-cell = 3.00 M M(NO)
Since the electrode are the same in both cells, then the concentration for the cell are also the same.
Negative electrode = Anode = lower concentration = 3.00 mM
Positive electrode = cathode = higher concentration = 3.00 M
Thus, right half cell will be postive electrode.
To determine the concentration cell:
\(Ecell =\Big( \dfrac{2.303\times R\times T}{nF} \Big)log\Big(\dfrac{[cathode]}{[anode]}\Big)\)
SInce [Cathode] > [anode],
\(R = 8.314 J/K/mol, \\ \\ T = 273+20 = 293 K \\ \\ Faraday's constant (F)= 96500 C/mol\)
n = 3
\(Ecell ={ \dfrac{2.303\times 8.314\times 293 }{(3\times 96500)}} log\dfrac{3}{0.003}\)
\(\mathbf{E_{cell} = 0.0582 V } \\ \\ \mathbf{E_{cell} = 0.06 V}\)
13. Which of the following is true about mixtures and compounds?
O A. A compound forms when different substances chemically combine to form a new substance.
OB. A mixture contains different substances that are not chemically combined with one another.
O C. Mixtures and compounds are both made of two or more different substances.
O D. all of these
Answers
Answer:
B.A mixture contains different substances that are not chemically combined with one anotherExplanation:
#stay home
#stay safe
#stay healthy
Answer:
D all of these
Explanation:
All of these are true about mixtures and compounds.
Mixtures and compounds are both made of two or more different substances.
The key difference between mixtures and compounds is that a compound is a new substance that
forms when other substances chemically combine. The new substance that is formed has
different properties from the original substances.
A mixture is simply a physical combination of two or more substances. Some of the individual
properties of the original substances are retained by the mixture.
What is the balanced chemical equation for wood burning
Answers
Answer:
P + O2 --> P2O5
Explanation:
For a simple match burning you can use the following equation: P + O2 --> P2O5 To balance the reaction you have to make sure you have the same amount of each element on both sides.
Electrical bonding refunding quick check!!
A team wants to understand the effects of molecular weight on boiling point. The team has access to five substances with
different molecular weights and the time to measure 50 boiling points. How can the team make the best use of the laboratory
testing time? (1 point)
O by taking 10 measurements of each of the five liquids and using the highest value from each set
O by taking 10 measurements of each of the five liquids and finding an average
O by taking measurements of the liquids one at a time, making sure that the correct results are achieved before
moving on to another liquid
O by taking one measurement of each liquid and then working to improve the least certain liquid in the group
Answers
Answer:
1. More data should be collected to get a more reliable average
2. A boiling point at 1.5 atmospheres could be predicted fairly well
3. The actual boiling point is probably between 34 C and 40 C
4. By taking 10 measurements of each of the five liquids and finding an average
5. The thermometer being used might need to be recalibrated
Explanation:
Took the quick check
What is the molecular formula of each of the following
compounds?
(a) empirical formula CH₂, molar mass = 84 g/mol
(b) empirical formula NH₂Cl, molar mass = 51.5 g/mol
Answers
(a) the molecular formula of the compound is C₆H₁₂.
(b) the molecular formula of the compound is NH₂Cl.
(a) Given the empirical formula CH₂ and a molar mass of 84 g/mol, we need to determine the molecular formula. To do so, we need to find the factor by which the empirical formula needs to be multiplied to achieve the given molar mass.
The empirical formula CH₂ has a molar mass of 14 g/mol (12 g/mol for carbon + 2 g/mol for hydrogen).
To find the factor, we divide the molar mass by the empirical formula mass:
Factor = (molar mass) / (empirical formula mass) = 84 g/mol / 14 g/mol = 6
Therefore, the molecular formula is obtained by multiplying the empirical formula by the factor:
CH₂ × 6 = C₆H₁₂
Thus, the molecular formula of the compound is C₆H₁₂.
(b) Given the empirical formula NH₂Cl and a molar mass of 51.5 g/mol, we follow a similar approach.
The empirical formula NH₂Cl has a molar mass of 51.5 g/mol (14 g/mol for nitrogen + 2 g/mol for each hydrogen + 35.5 g/mol for chlorine).
To find the factor, we divide the molar mass by the empirical formula mass:
Factor = (molar mass) / (empirical formula mass) = 51.5 g/mol / 51.5 g/mol = 1
Therefore, the molecular formula is the same as the empirical formula: NH₂Cl
Hence, the molecular formula of the compound is NH₂Cl.
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An unknown compound contains only carbon, hydrogen, nitrogen, and oxygen. Complete combustion of a 2.77 g sample of the compound gives 6.64 g CO2 and 1.67 g H2O. Another sample of mass 1.69 g was found to contain 0.143 g N. The molar mass of the compound was found to be 165 g mol−1. Find the molecular formula of the unknown compound
Answers
The molecular formula of the unknown compound is determined as C₉H₁₁NO₂.
Molecular formula of the compoundThe molecular formula is calculated as follows;
CHNO + O₂ ------------> CO₂ + H₂O
Mass of carbon, C: = (6.64 x 12)/44 = 1.81 g in 2.77 g sample
Mass of hydrogen, H: = (1.67 x 2)/18 = 0.186 g in 2.77 g sample
Mass of Nitrogen, N: = (2.77 x 0.143)/1.69 = 0.234 g
Mass of oxygen, O: = 2.77 g - 1.81 g - 0.186 g - 0.234 g = 0.54 g
molar ratio of the elements:C = 1.81 g = 0.15 mol
H = 0.186 g = 0.186 mol
N = 0.234 g = 0.017 mol
O = 0.54 g = 0.0337 mol
divide through with the smallest number of moles (0.017 mol);
C = 9
H = 11
N = 1
O = 2
Molecular formula = C₉H₁₁NO₂
Check the molar mass of the compound = (9 x 12) + (11 x 1) + (14) + (2 x 16) = 165 g/mol
Thus, the molecular formula of the unknown compound is determined as C₉H₁₁NO₂.
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Which diagram represents an element that is likely to form covalent bonds? A purple circle with 2 concentric circles around it. The inner circle has 2 small green spheres. The outer circle has 1 small green sphere. A purple circle with 3 concentric circles around it. The inner circle has 2 small green spheres. The middle circle has 8 small green spheres. The outer circle has 5 small green spheres. A purple circle with 3 concentric circles around it. The inner circle has 2 small green spheres. The middle circle has 8 small green spheres. The outer circle has 8 small green spheres.
Answers
Diagram represents an element that is likely to form covalent bonds is a purple circle with 3 concentric circles around it
Covalent bond means it consist of mutual sharing of one or more pair of electron between two atom and covalent bond diagram consist of in the middle the small circle which is purple color and three concentric circles around the purple circle and covalent bond diagram show the electron dot formulas and they often reffred to as lewis structure and are little different than electron dot formula used to represent the ionic bond
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What force is causing The object to eventually stop moving
Answers
Answer:
Hey buddy, here is your answer. Hope it helps you.
Explanation:
The force stopping the object's motion might be an obvious one - the ground! Friction is a force that slows or stops motion. Friction is the resistance to motion created by two objects rubbing against each other (the sled and the snow, for instance). Even air causes friction.
Select the statement that best describes how energy is passed from a herbivore to a carnivore. (2 points)
Group of answer choices
Energy from the food sources that both herbivores and carnivores eat is passed directly from them to plants.
Energy from the foods carnivores eat is passed directly to an herbivore.
When an herbivore eats meat, and a carnivore eats the herbivore, energy from the eaten meat is passed indirectly to the carnivore.
When an herbivore eats plants, and a carnivore eats the herbivore, energy from the eaten plants is passed indirectly to the carnivore.
Answers
answer:when an herbivore eats meat and a carnivore eats the herbivore energy from the eatin meat is passed indirectly to the carnivore.
Introduction
Sodium bicarbonate, NaHCO3 (MW 84.007 g/mol), is commonly known as baking soda. Sodium bicarbonate is a solid crystalline and
appears as a white powder. Sodium bicarbonate can be easily be converted to sodium carbonate, Na2CO3 (MW 105.988 g/mol) by
decomposition to produce H₂O and CO₂. This can be accomplished by placing the sample in the oven at 176 deg F.
Unbalanced chemical equation: NaHCO3 (s) + heat-> Na₂CO3 (s)+ H₂O(g) + CO₂(g)
Demonstration Video: [Click here for video]
Percent yield - (actual yield/ theoretical yield) x 100
Purpose
This assignment is designed to teach students about decomposition reactions and determine the percent yield. At the end of the experiment, the
student will have a better understanding of how this assignment will benefit their learning.
Task
-Write a balanced chemical equation
- Calculate the percent yield of the decomposition reaction (Must show your work)
Answers
We can actually deduce here that the purpose of this assignment is to teach students about decomposition reactions and allow them to determine the percent yield.
What is the experiment all about?By performing the experiment, students will gain a better understanding of the concepts involved and how they relate to their overall learning.
The specific focus of this assignment is the decomposition of sodium bicarbonate (NaHCO3) to produce sodium carbonate (Na2CO3), water (H2O), and carbon dioxide (CO2). The unbalanced chemical equation for this reaction is:
NaHCO3 (s) + heat -> Na2CO3 (s) + H2O (g) + CO2 (g)
To understanding the reaction itself, students will also learn about the concept of percent yield. Percent yield is a measure of the efficiency of a chemical reaction and is calculated by dividing the actual yield of the desired product by the theoretical yield, then multiplying by 100.
This calculation allows students to assess how well the reaction proceeds in terms of producing the expected amount of sodium carbonate.
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compare and contrast the cause of a flow of water in a pipe and the cause of a flow of electrons in a wire
Answers
The flow of water in a pipe and the flow of electrons in a wire are both examples of fluid flow and are caused by different physical phenomena.
The flow of water in a pipe is caused by a pressure difference, also known as a pressure gradient, between two points. If the pressure at one end of the pipe is higher than the pressure at the other end, water will flow from the high-pressure end to the low-pressure end. The flow rate will depend on the pressure difference, the diameter of the pipe, and the viscosity of the fluid.
The flow of electrons in a wire, on the other hand, is caused by a difference in electrical potential, also known as a voltage difference, between two points. If the voltage at one end of the wire is higher than the voltage at the other end, electrons will flow from the high-voltage end to the low-voltage end. The flow rate will depend on the voltage difference, the resistance of the wire, and the number of electrons available to flow.
In summary, the cause of the flow of water in a pipe is a pressure difference, while the cause of the flow of electrons in a wire is a voltage difference.
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PLEASE ANSWER QUICKLY!!
100 NaNO3
90
Solute per 100 g of H₂O (g)
0,80
NH,CI
70 KNO3
60
50
40
30
20
10
0
0 10 20 30 40 50 60 70 80 90 100
Temperature (°C)
KCIO3
60 g KNO3 has
been added to
100 g H₂O at
30 °C. What
type of solution
is this?
A. unsaturated
B. saturated
C. supersaturated
Answers
If 60 grams of the substance are added to 100 g of water, the solution can be categorized as supersaturated.
How saturated is this solution?The graph shows the number of grams that can be dissolved in 100 grams of water at different temperatures. In general, solubility increases with temperature.
According to the graph, at a temperature of 30°C, it is possible to dissolve a total of 48 to 49 grams of \(KNO_{3}\). This information implies that if we add 60 grams at this temperature not all the substance would be dissolved, and therefore the solution would be supersaturated.
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1. What volume of a 2.50M Kl(aq) is needed to make 200 ml of a 1.OOM KI)aq)?
Answers
Answer:
80 ml
Explanation:
From the question,
Applying Dilution formular
MV = mv................... Equation 1
Where M = Molarity of Kl before dilution, V = Volume of Kl before dilution, m = molarity of Kl after dilution, v = volume of Kl after dilution.
make V the subject of the equation
V = mv/M............. Equation 2
Given: m = 1.00 M, v = 200 ml, M = 2.50 M
Substitute these values into equation 2
V = (1.00×200)/2.50
V = 80 ml
What is paper made of?
Answers
Paper used as a writing material is made of pulp (wood).
What is paper?Paper is a sheet material used for writing on or printing on (or as a non-waterproof container), usually made by draining cellulose fibres from a suspension in water.
Paper is made from cellulose found in trees, which are the main source of cellulose fibre (or woodpulp). Besides woodpulp, paper can be made from other materials such as cotton, flax, esparto, straw, hemp, manilla and jute.
Wood pulp is usually a softwood, used for pulping to make paper.
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Question 2 (1 point)
What is the concentration when 45 mL of 1.5 M Na₂SO4 is diluted to 500 mL?
16.7 M
0.14 M
0.015 M
1.35 x 10-4 M
Answers
Answer: The concentration(molarity) of the solution will be 1.35 X10-4 M
Explanation: Molarity is defined as number of moles of solute present in one litre of any solution.
Mathematically,
Molarity= no of moles of solute/volume of solution(in liters)
M=N/V(liters)
Also upon dilution the number of moles of the solution remain unchanged
Therefore initial no of moles(before dilution)= final no of moles(after dilution)
M1V1=M2V2
According to the question,
Molarity of Na2S04 before dilution(M1)=1.5 M
Volume of NA2SO4(V1)=45 mL
Molarity of Na2S04 after dilution(M2)=x M
Volume of Na2S04(V2)=500 mL
x=M1V1/V2
=1.5X45/500
=0.135 M =1.35 X10-4 M
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Analyze This: The ionic bond between sodium (Na) and sulfur (S) forms as a
result of e transfer. One element donates or gives away one or more e's. The
other element accepts or receives the e's.
To begin, identify the e shell
diagram for sodium and for
sulfur:
Next
Na:
S:
Answers
To form ionic bonds, atoms transfer electrons. Consider sodium as: It is permanent in its anionic form and has one valence electron.
Ionic linkage Why does that matter?Ionic connections are created when specific electrons are fully transferred from one atom to another. When atoms lose one or more electrons, cations are produced (positively charged ions). When an atom receives one or more electrons, it produces an anion (negatively charged ion) .
Ionic bonding is demonstrated via the synthesis of sodium fluoride (NaF) from sodium and fluorine atoms. The sodium atom's lone valence electron is accepted in this process by a fluorine atom that has just enough area to accommodate it. Ions or charged molecules are referred to as "ionic" compounds. Ionic bonds are the interaction between ions with different charges. If we glance at the adjective, ionic, we can tell that the subject is science. Ionic bonds hold two or more atoms together to form ionic molecules.
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What is the density of an unknown compound in g/ml if 1.28 pounds of the compound has a volume of 4.50L
Answers
1.28 pounds * 453.59 grams/pound = 580.61 grams
Next, we can use the formula for density:
Density = Mass / Volume
Density = 580.61 grams / 4.50 L
Density = 128.91 g/L
Therefore, the density of the unknown compound is 128.91 g/L or 0.12891 g/mL (since there are 1000 mL in 1 L).
50 mL of 0.1 M acetic acid is mixed with 50 mL of 0.1 M sodium acetate (the conjugate base). The Ka of acetic acid is approximately 1. 74 X 10 -5. What is the pH of the resulting solution?
Answers
Answer:
4.76
Explanation:
In this case, we have to start with the buffer system:
\(CH_3COOH~->~CH_3COO^-~+~H^+\)
We have an acid (\(CH_3COOH\)) and a base (\(CH_3COO^-\)). Therefore we can write the henderson-hasselbach reaction:
\(pH~=~pKa+Log\frac{[CH_3COO^-]}{[CH_3COOH]}\)
If we want to calculate the pH, we have to calculate the pKa:
\(pH=-Log~Ka=4.76\)
According to the problem, we have the same concentration for the acid and the base 0.1M. Therefore:
\([CH_3COO^-]=[CH_3COOH]\)
If we divide:
\(\frac{[CH_3COO^-]}{[CH_3COOH]}~=~1\)
If we do the Log of 1:
\(Log~1=~zero\)
So:
\(pH~=~pKa\)
With this in mind, the pH is 4.76.
I hope it helps!
Write the balanced NET ionic equation for the reaction when ammonium bromide and lead(II) acetate are mixed in aqueous solution. If no reaction occurs, simply write only NR.
Answers
Answer:
2NH4br(aq)+pb(c2h3o2)(aq)PbBr2(s)
Pb2 +(aq) +2 Br(aq)-------->PbBr2(s)
the spectator ions
NH4+c2H3O2 are cancelled
The balanced net ionic equation for the reaction when ammonium bromide and lead(II) acetate are mixed in aqueous solution is
Pb²⁺ + 2Br⁻ -> PbBr₂
What is ionic equation?Ionic equation can be defined as a chemical equation in which the electrolytes in aqueous solution are expressed as dissociated ions.
Net ionic equation can be defined as a chemical equation in which only those ions undergoing chemical changes during the course of the reactions are represented.
NH4Br + Pb(CH3COO)2 -> CH3COONH4 + PbBr2
On balancing the equation
2NH4Br + Pb(CH3COO)2 -> 2CH3COONH4 + PbBr2
Now breaking into ions
2NH4⁺ + 2Br⁻ + Pb²⁺ + 2CH3COO⁻ -> 2CH3COO⁻ + 2 NH4⁺ + PbBr2
Canceling out spectator ions
Then the net ionic equation is
Pb²⁺ + 2Br⁻ -> PbBr₂
Thus, the balanced net ionic equation for the reaction when ammonium bromide and lead(II) acetate are mixed in aqueous solution is
Pb²⁺ + 2Br⁻ -> PbBr₂
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The hypothesis stated that the fraction of nuclei still radioactive after n half-life cycles should be 0.5n. How well does the regression equation support the hypothesis?
Answers
The regression equation supports the hypothesis by showing associations between sets of scientific data (in this case, half life cycle and radioactivity).
What is the regression equation?The regression equation is a type of mathematical tool employed to determine the association between variables.
The regression equation can help to understand the relationships between independent and dependent variables.
In conclusion, the regression equation supports the hypothesis by showing associations between sets of scientific data.
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Answer:
Quite Strongly
Explanation:
Got it right 2022 edge
33. what is the correct order for obtaining salt from a mixture of sand and water a) dissolving in water, filtration, evaporation b) evaporation, filtration, dissolving in water c) filtration, dissolving in water, evaporation.
Answers
To obtain salt from a mixture of salt and sand, the mixture is filtered, then dissolved in water, and finally, water is made to evaporate leaving the sand. So, option C is the correct answer.
Sand and salt mixture consists of soluble and insoluble components. Salt is soluble in water while sand is not. The sand from this mixture can be separated using filtration, a method of filtering insoluble components from a solvent, typically using filter paper or various mediums in an industrial process. This way sand is separated from the mixture.
However, there will be minute particles that may not be filtered but are mostly insoluble. So, the mixture is mixed in water where salt dissolves leaving the other impurities that are insoluble.
The salt water is then heated so that water evaporates leaving only the salt behind. In this way, only salt is obtained.
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The electron configuration of an element is 1s22s2. How many valence electrons does the element have?
1
2
3
4
Answers
1s²2s²
#The total electron/proton is the power
2 + 2 = 4
Answer : 4Answer:
Its 4, pls mark as brainliest
Explanation:
Check all the statements that describe applications and properties of substances that result from intermolecular forces.
Answers
Answer:
The ability for water to form bubbles
the formation of a meniscus in a graduated cylinder with water
the inability of water to mix with oil
the melting point of a substance
the ability of detergents to clean clothes
Explanation:
Answer:these are the answers
Explanation:
edge
Consider the following statements in reference to SN1, SN2, E1, and E2 reactions of haloalkanes. To which mechanism(s), if any, does each statement apply?
1. Involves a carbocation intermediate
2. Is first order in haloalkane and first order in base.
3. nvolves inversion of configuration at the site of substitution
4. Involves retention of configuration at the site of substitution
5. Substitution at a stereocenter gives predominantly a racemic product
6. Is first-order in alkyl halide and zero-order in base
7. Is first-order in alkyl halide and first order in base
8. Is greatly accelerated in protic solvents of increasing polarity.
9. Rearrangements are common
10. Order of reactivity is 3°> 2° > 1° > methyl
11. Order of reactivity of haloalkanes is methyl > 1° > 2° > 3°.
Answers
Answer:
1. Involves a carbocation intermediate- SN1, E1
2. Is first order in haloalkane and first order in base- E2
3. involves inversion of configuration at the site of substitution- SN2
4. Involves retention of configuration at the site of substitution- SN1
5. Substitution at a stereocenter gives predominantly a racemic product- SN1
6. Is first-order in alkyl halide and zero-order in base- E1
7. Is first-order in alkyl halide and first order in base- E2
8. Is greatly accelerated in protic solvents of increasing polarity- SN1,E1
9. Rearrangements are common- SN1, E1
10. Order of reactivity is 3°> 2° > 1° > methyl- SN1
11. Order of reactivity of haloalkanes is methyl > 1° > 2° > 3°- SN2
Explanation:
SN1 is mechanism of nucleophilic substitution in which a nucleophile reacts with an alkyl halide by first order mechanism. The reaction is first order in the alkyl halide and zero order in the nucleophile. The rate determining step is the formation of a carbocation. The ease of occurrence of SN1 reaction depends on the ease of formation of a stable carbocation. The order of carbocation stability is; 3°> 2° > 1° > methyl. SN1 mechanism leads to retention of configuration at the site of substitution and a racemization when substitution occurs at a chiral carbon atom.
SN2 is a bimolecular nucleophilic substitution mechanism which is first order in both nucleophile and alkyl halide. It is favoured by aprotic solvents which do not solvate the nucleophile significantly. The order of alkyl halide reactivity by SN2 mechanism is; methyl > 1° > 2° > 3°.
E1 mechanism refers to elimination reaction in which the rate determining step is the formation of a carbocation. It is common for tertiary alkyl halides. It mostly occurs with weak bases. The reaction is first order in the alkyl halide but zero order in the base.
E2 is an elimination mechanism which is first order in both alkyl halide and base. It is favoured by strong and bulky bases. Primary alkyl halides more commonly react by E2 mechanism.
a sample of a substance has a mass of 50.0 grams, g, and occupies a volume of 3.95 milliliters, ml. calculate the density of the object in grams per milliliter, gml.please choose the correct answer from the following choices, and then select the submit answer button. answer choices
Answers
Density of the given sample is 12.66 grams per milliliter.
Mass per unit volume is the definition of a material's density. The degree to which matter is packed together is fundamentally measured by density. It is a particular physical characteristic of a specific thing.
Density = mass/volume
Given mass = 50g
Given Volume = 3.95mL
According to question, we are required to find the density in units : grams per milliliter
Since the given values for mass and volume are grams and milliliters respectively, no change in units is required.
Putting the given values in the formula, Density = mass/volume
Density = 50/3.95
Density = 12.658 grams per milliliter
We can say, Density = 12.66 grams per milliliter
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P*V = n*R*T
where
P = pressure
V = volume
n = number of moles
R = the universal gas constant
T = temperature in degrees Kelvin
This equation is known as the ideal gas law, and it can be used to predict the behavior of many gases at relatively low pressure. From this equation, you can see that as the temperature of a gas increases,
A Either the pressure of the gas, the volume of the gas, or both, will increase.
B the pressure of the gas increases.
C the number of moles of gas will go down.
D either the pressure of the gas, the volume of the gas, or both, will decrease.
Answers
Answer: A
Explanation:
A Either the pressure of the gas, the volume of the gas, or both, will increase.
This is because the ideal gas law states that as the temperature of a gas increases, the pressure and volume of the gas will increase as well. This is because the molecules of the gas have more energy and move faster, causing the gas to expand. This increases the pressure and volume of the gas.