0.12g of compound "Y" dissolves in 10mlof acetone at 25 degree celsuis and 0.85g of the same compound dissolves in 10ml of boiling acetone. what volume of acetone would be required to purify a 5.0g sample of compound?

Answer:

C

Explanation:

I believe it would be weather because climate is the average temperature of a area. This leads me to believe it is c.

I am sorry if this is incorrect, but that is what I would've went with if I was taking the test. :)

Some types of solids that are insoluble in water are:

Many solids are insoluble in water, meaning they do not dissolve in water to a significant extent. Here are some examples of common solids that are generally insoluble in water:

Metals: Most metals, such as gold, silver, platinum, and copper, are insoluble in water.

Non-Metallic Elements: Many non-metallic elements, such as carbon (in the form of graphite or diamond), sulfur, phosphorus, and iodine, are insoluble in water.

Metal Oxides: Some metal oxides, particularly those of less reactive metals, are insoluble in water. Examples include aluminum oxide (Al2O3), iron(III) oxide (Fe2O3), and lead(II) oxide (PbO).

Metal Carbonates: Most metal carbonates are insoluble in water. Examples include calcium carbonate (CaCO3), lead(II) carbonate (PbCO3), and copper(II) carbonate (CuCO3).

Metal Sulfides: Many metal sulfides are insoluble in water. Examples include lead(II) sulfide (PbS), silver sulfide (Ag2S), and mercury(II) sulfide (HgS).

Insoluble Salts: Certain salts have limited solubility in water. Examples include silver chloride (AgCl), lead(II) iodide (PbI2), and calcium sulfate (CaSO4).

It's important to note that while these solids are generally insoluble in water, they may exhibit some solubility to a small extent. The solubility of a solid in water can vary depending on factors such as temperature, pressure, and the presence of other solutes.

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The mass(in grams) of iron, Fe produced from the 92.5g of iron (ii) oxide, FeO is 71.9 grams

The mass of Fe produced from the 92.5g of iron (ii) oxide, FeO can be obtained as follow:

2FeO → 2Fe + O₂

From the balanced equation above,

143.7 g of FeO reacted to produce 111.7 g of Fe

Therefore,

92.5 g of Fe will react to produce = (92.5 × 111.7) / 143.7 = 71.9 g of Fe

Thus, the mass of Fe produced from the reaction is 71.9 grams

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Complete question:

How many grams of Fe are produced from 92.5 g of FeO given the following reaction 2FeO → 2Fe + O₂

The Transcontinental Railroad was the main development that started a large movement of settlers to California. It was the first railway line to span the entire continent, connecting the east and west coasts of the United States.

The railroad greatly facilitated migration and allowed for widespread settlement of the West. It improved communication between the east and west coasts, sped up transportation, and made it possible for a more productive interchange of goods.

Also, the railroad made it possible for prospectors to reach California in search of the California Gold Rush. Also, the railroad made it possible for cattle ranchers to transport their herds of cattle to the California stockyards.

As a result, there was more beef available, which aided in the state's agriculture sector's expansion. Also, the railroad offered an effective way to ship mining and agricultural goods to the east coast.

Hence, the Transcontinental Railroad served as the main driving force behind the massive migration of settlers to California.

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Answer:

Exercises Example 6. How Many Moles Of Carbon Atoms And How Many Carbon Atoms Are Contained In 1.0 G Of C,H,OH

Explanation:

The mass of the propane that would have the same number of carbon atoms is  0.63 g.

We know that we can be able to obtain the number of the carbon atoms by the use of the simple stoichiometry of the reaction as we have it in the question that we have been asked here.

We can see that we have the molar mass of the ethanol as we can see as 46 g/mol. We have to obtain the number of moles of the ethanol that we have in the compound as follows;

Number of moles = 1 g/ 46 g/mol = 0.022 moles

Number of the carbon atoms that we have is; 0.022 moles * 2 * 6.02 * 10^23 = 2.6 * 10^22 atoms

Now the number of the grams of the propane that we have is;

2.6 * 10^22  = x * 3 * 6.02 * 10^23

Where x is the number of moles present

x =  2.6 * 10^22 / 1.806 * 10^24

x = 1.44 * 10^-2 moles

x = 0.0144 moles

Given that the molar mass of the propane is 44 g/mol

mass  =  0.0144 moles * 44 g/mol

Mass = 0.63 g

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The statements  'The precision is a measure of the spread of expected values for a given measurement .'  does not accurately describe the precision of a measurement .

Precision refers to how close measurements of the same item are to each other . Precision is independent of accuracy . That means it is possible to be very precise but not very accurate, and it is also possible to be accurate without being precise . The best quality scientific observations are both accurate and precise .

It is also define in one term as the quality or state of being precise .

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The correct options are: changes in shape or size, color changes, formation of precipitates or gases, and whether changes are easily reversible.

According to the lab guide, the following changes below will be looked for in order to test the hypothesis: changes in shape or sizecolor changesformation of precipitates or gaseswhether changes are easily reversibleThese changes are the characteristics that will be observed in order to test the hypothesis in the lab. Furthermore, temperature changes and changes of state (gas, liquid, or solid) may also occur and can be observed while testing the hypothesis.

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Answer:

A,B,E,F

Explanation:

Answer:

\(\rho =1.96\frac{g}{L}\)

Explanation:

Hello there!

In this case, since this imaginary gas can be modelled as an ideal gas, we can write:

\(PV=nRT\)

Which can be written in terms of density and molar mass as shown below:

\(\frac{P}{RT} =\frac{n}{V} \\\\\frac{P}{RT} =\frac{m}{MM*V}\\\\\frac{P*MM}{RT} =\frac{m}{V}=\rho\)

Thus, by computing the pressure in atmospheres, the resulting density would be:

\(\rho = \frac{165/760 atm * 314.2 g/mol}{0.08206\frac{atm*L}{mol*K}*425K} \\\\\rho =1.96\frac{g}{L}\)

Best regards!

A methane molecule (CH4) is considered symmetrical because it possesses a symmetric structure and exhibits symmetry operations.

Symmetry refers to a balanced arrangement of elements that can be divided into equal parts by a plane, axis, or center. In the case of methane, it exhibits several symmetrical characteristics.

Firstly, methane has a tetrahedral molecular geometry, with the carbon atom at the center and four hydrogen atoms positioned around it. This geometry ensures that the molecule is symmetrical in terms of its spatial arrangement.

Each hydrogen atom is located at one of the vertices of the tetrahedron, forming equal angles and distances with respect to the central carbon atom. This symmetry is maintained regardless of the orientation of the molecule.

Additionally, methane possesses rotational symmetry. It can be rotated around any of the carbon-hydrogen bonds, and the molecule will retain its overall appearance.

The symmetry of methane arises from its molecular structure and the equal distribution of electron density around the central carbon atom. The four hydrogen atoms are bonded to the carbon through sigma bonds, which have a cylindrical symmetry. This balanced arrangement of the atoms contributes to the overall symmetry of the molecule.

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Answer:

among these which is not a base is CaSO4

Answer:

Approximately \(43.9\%\) by mass.

Explanation:

Look up relevant relative atomic mass data on a modern periodic table:

Calculate the formula mass of \(\rm ZnSO_4\), \(\rm H_2O\), and \(\rm ZnSO_4\cdot 7\, H_2O\):

\(M(\rm ZnSO_4) \approx 65.38 + 32.06 + 4 \times 15.999 = 161.436\; \rm g \cdot mol^{-1}\).

\(M(\rm H_2O) \approx 2 \times 1.008 + 15.999 = 18.015\rm g \cdot mol^{-1}\).

\(M(\rm ZnSO_4\cdot 7\, H_2O) \approx 161.436 + 7 \times 18.015 \approx 287.541\; \rm g\cdot mol^{-1}\).

In other words, each mole of \(\rm ZnSO_4\cdot 7\, H_2O\) formula units has a mass of approximately \(287.541\; \rm g\).

However, that one mole of \(\rm ZnSO_4\cdot 7\, H_2O\) also contains seven moles of \(\rm H_2O\) molecules, which has a mass of approximately \(7 \times 18.015 = 126.105\; \rm g\).

Calculate the mass ratio of water in this compound:

\(\begin{aligned}& \%m(\text{water}) \\ &= \frac{m(\text{water})}{m(\text{compound})} \times 100\% \\ &\approx \frac{126.105\; \rm g}{287.541\; \rm g} \times 100\%\approx 43.9\%\end{aligned}\).

Answer:

The relative reactivity of carboxylic acid derivatives toward nucleophile substitutions is related to the electronegative leaving group's ability to activate the carbonyl. The more electronegative leaving groups withdraw electron density from the carbonyl, thereby increasing its electrophilicity.

Explanation:

Time = Distnace ×speed

so distance is 2000m

and speed is 100

so 100×2000

time = 200000s

The velocity of the tomato when it hits the ground is approximately 13.49 meters per second.

The potential energy of the tomato is at the height of 10 meters. When the tomato hits the ground, most of the potential energy is E1 = 0.909*mgh.

By the conservation of energy principle, the kinetic energy \(E_1\) is equal to the kinetic energy \(E_2\) of the tomato just before it hits the ground.

The kinetic energy \(E_2\) is given by\(1/2mv^2\), where v is the velocity of the tomato just before it hits the ground. Equating \(E_1\) and \(E_2\) solving for v, we get:

\(v = \sqrt{(20.909gh)\)

Substituting the values of \(g = 9.81 m/s^2\)and h = 10 m, we get:

v = \(\sqrt{(20.9099.81*10)}\) = 13.49 m/s

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--The complete Question is, Suppose a tomato is dropped from a height of 10 meters. If 90.9% of the work done on the tomato is converted to kinetic energy by the time it hits the ground, what is the velocity (in meters per second) of the tomato when it hits the ground? --

Answer

ΔH for the reaction is +12.2 kJ

Explanation

Given:

The given reaction is:

The following are the given data:

What to find:

To calculate the ΔH for the given reaction.

Step-by-step solution:

Step 1: Multiply (a) through by 2

Step 2: Reverse (b)

Step 3: (c)

Step 4: Combine (a), (b), and (c) and simplify.

Since the given equation is in 1 mole, then divide through by 2

Therefore, ΔH for the given reaction is +12.2 kJ

that H2O is on the opposite end of the equation, this is one of the reaction's products. We can therefore refer to the H2O element as just a product.

The thing being sold is called a product. An item or service can be considered a product. Physical, virtual, or cyberspace forms are all possible. Every good has a price because it costs money to produce it. The market, quality, marketing, and intended market group all affect the price which can be paid.

Anything that is created while another product is being manufactured or processed is known as a by-product. The by-product of is the source of the raw material.

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Answer:

the correct ansrew is c

Explanation:

because there are 2 molecules of h2o

Answer:

Hi, there!

The list of materials you can use for the doghouse roof is below. Can you sort them based on their physical properties?

The Answer Is Oak, Clay, Concrete, Slate UwU

xXxAnimexXx

Have a great day!

Answer:

The Answer Is Oak, Clay, Concrete, Slate

Hope this Helps you!

The equilibrium constant at this temperature is Kc= 4.17 x 10⁻⁶.

Since the equilibrium constant depends on the equilibrium concentration of both the reactants and the products of the chemical reaction.

Balanced reaction equation

2CH₄(g)⇌C₂H₂(g)+3H₂(g)

The initial concentration of the CH₄ = 0.093 M

The equilibrium concentration of the H = 0.017 M

Equilibrium constant = ?

Let's make the ice table

2CH₄(g) ⇌ C₂H₂(g) + 3H₂(g)

0.093 M 0 0

-2x +x +3x

0.093-2x x 0.017 M

3x = 0.017 M

Therefore, x =0.017 M /3 = 0.00567 M

Therefore, the equilibrium concentration of CH₄ =

0.093 M – 2x = 0.093 M – (2 x 0.00567 M) = 0.0817 M

Equilibrium concentration of the C₂H₄ = x = 0.00567 M

Let's write the equilibrium constant expression

Kc= [C₂H₄[H2]³/[CH₄]²

Let's put the values in the formula

Kc= [0.00567][0.017]³/[0.0817]²

Kc= 4.17 x 10⁻⁶

Therefore, the equilibrium constant is 4.17 x 10⁻⁶.

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Answer:

1. 10moles

2. Find the summarized equation below

Explanation:

Mole = mass ÷ molar mass

Molar mass of oleum (H2S2O7) = 1(2) + 32(2) + 16(7)

= 2 + 64 + 112

= 178g/mol

According to the information provided, the mass of oleum is 1780g, hence, the number of moles in it is:

Mole = 1780/178

Mole = 10moles

2. The summarized equation of the contact process is:

1) S + O2 → SO2

2) 2SO2 + O2 → 2SO3

3) SO3 + H2SO4 (conc. sulfuric acid) → H2S2O7

4) H2S2O7 + H2O → 2H2SO4 (dilute sulfuric acid)

Answer:

C. 1191.49 K.

Explanation:

Entropy and Free Energy => Temperature and Free Energy.

We can use the following formula that involves enthalpy (ΔH), entropy (ΔS), and temperature (T):

You can see that the units of enthalpy are kJ/mol, and entropy is J/Kmol. You can realize that we cannot do the calculation with these units because the energy unit is not equal (kJ≠J), so we can convert the enthalpy, 280 kJ/mol to J/mol remembering that 1 kJ equals 1000 J like this:

So now we have ΔH = 280000 J/mol and ΔS = 235 J/Kmol and we can replace these data in the given formula:

The answer would be that the temperature is C. 1191.49 K.

Answer:

73.2 pm

Explanation:

"The anions make contact along the diagonal of the face of the unit cell, so the diagonal of the face is equal to 4 ionic anion radii. By letting r represent the ionic radius of the anion, d represent the diagonal of the face of the unit cell, and x represent the edge length, then d=4r and

d^2=x^2+x^2=  2x^2

By substituting 4r for d, the second equation becomes

(4r)^2=(2)x^2

Solving this equation for r shows that

r=(x–√2)/4

Since the edge length x is 207 pm, the ionic radius of the anion is

r= ((207 pm) X \(\sqrt{2}\))/4=73.2 pm

Notice that the formulae used to describe atomic radii include constants with exact values. Therefore, these values do not constrain the number of significant figures."

The ionic radius of the anion in the FCC unit cell where anions are in contact along the diagonal of the face of the unit cell is 73.1pm.

Ionic radius is the distance between the center of the atom and the outermost part.

As in the question it is given that anions are in contact along the diagonal of the face of the unit cell, so the length of the diagonal is represented as: d = 4r, where

r = ionic radius

Length of edge i.e. a = 207 pm (given)

Two adjacent edges and diagonal of a FCC unit cell makes a right angle triangle, by using pythagoras theorem we can write as:

a² + a² = d²

2a² = (4r)²

2a²/16 = r²

2(207)²/16 = r²

85,698/16 =  r²

0r r = 73.18 pm

Hence, 73.18 pm is the ionic radius of the anion.

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Answer: about one month

Explanation:

Answer:

Potenz Hydrogen is the measure of acidity in any water soluble substance only.

Explanation:

Answer:

c

Explanation:

it is because the chemical reaction will have the exposure to all the minerals with Microsoft word

The gravimetric factor for Br- using silver bromide is 0.425.

The gravimetric factor is an expression that is used to convert grams of a compound into grams of a single element.

It is expressed as a ratio of the formula weight (FW) of the substance that is being determined to that of a second substance that is weighed.

For example formula of silver bromide is AgBr and the formula mass of silver bromide is 188 g/mol

Formula mass of bromide ion = 80 g/mol

Gravimetric factor = 80/1188

Gravimetric factor = 0.425

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Answer:

its D

Explanation:

I took the test its right

The data can lead us to conclude that an alcohol thermometer can measure the freezing point of a liquid that freezes at −80 °C..

The liquid in glass thermometers are those thermometers whose thermometric substance is a liquid. Usually the best liquids to be used are those that have a long liquid range.

The data can lead us to conclude that an alcohol thermometer can measure the freezing point of a liquid that freezes at −80 °C..

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Answer:

Option 4

Explanation:

In water molecule, oxygen has -2 charge on it while the hydrogen has +1 charge and one atom of oxygen combines with two hydrogen atoms. A hydrogen need only two electrons to complete its octet (one electron is its own the second electron is shared by oxygen) and a oxygen needs 8 electrons (It has six of its own and two are shared by two hydrogen atom).

Hence, option 4 is correct

Answer:

Option 2

It's more balanced than the others

The enthalpy change of the reaction C(diamond) → C(graphite) is -2.9 kJ.

The given information is ΔHrxn for the reaction C(diamond) → C(graphite) can be calculated with the given equations:Equations:  C(diamond) + O2(g) → CO2(g) ΔH = −395.4 kJ  2 CO2(g) → 2 CO(g) + O2(g) ΔH = 566.0 kJ  C(graphite) + O2(g) → CO2(g) ΔH = −393.5 kJ  2 CO(g) → C(graphite) + CO2(g) ΔH = −172.5 kJThe required reaction can be obtained by adding the equations (1) and (4), as follows:C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)Addition of the two equations (1) and (4) results in a reaction whose products are C(graphite) and CO2.

To get the final equation that involves only the required reactants and products, the equation (2) should be added, which consumes CO2 and produces O2, as shown below:C(diamond) + O2(g) → CO2(g)  ΔH = −395.4 kJ [eq. (1)]  2 CO(g) → C(graphite) + CO2(g)  ΔH = −172.5 kJ [eq. (4)]  2 CO2(g) → 2 CO(g) + O2(g)  ΔH = 566.0 kJ [eq. (2)]  C(diamond) + O2(g) + 2CO(g) → C(graphite) + 3CO2(g)  ΔHrxn=ΣΔHf(products)−ΣΔHf(reactants)  ΔHrxn=[(3 mol CO2)(-393.5 kJ/mol) + (1 mol C(graphite))(0 kJ/mol)] − [(1 mol C(diamond))(0 kJ/mol) + (1 mol O2)(0 kJ/mol) + (2 mol CO(g))(−172.5 kJ/mol)] − [(2 mol CO2)(566.0 kJ/mol)]  ΔHrxn=−2.9 kJ.

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Answer:

If you left a block of dry ice in a bow of room temperature all day, it would evaporate.dry ice undergo sublimation,it will go from solid to gas instead of going through the normal process

solid-liquid- gas

Answer:

A.) \(K_b = \frac{[CH_3NH_3^+][OH^-]}{[CH_3NH_2]}\)

Explanation:

The general Kb expression is:

\(K_b = \frac{[HA][OH^-]}{[A^-]}\)

In this equation

-----> Kb = equilibrium constant

-----> [HA] = acid

-----> [A⁻] = base

Since liquids are not included in equilibrium expressions, H₂O should not be present. The products are in the numerator while the reactant are in the denominator. In this reaction, CH₃NH₂ is acting as a base and CH₃NH₃⁺ is acting as an acid.

As such, the expression is:

\(K_b = \frac{[CH_3NH_3^+][OH^-]}{[CH_3NH_2]}\)