1. A ship left port A heading for port B. It sailed due East for 40 miles. It then sailed due North

for 30 miles. Find:

i. The distance between the two ports

ii. The bearing of port B as measured from port A

iii. The bearing of port A as measured from port B

Answers

Answer 1

Answer:

i)Distance between port A and Port B is 500 miles.

ii)Bearing of port B from A= N 53.13°E

iii)Bearing of port A from B= S 53.13°W

Step-by-step explanation:

The movement of the ship from port A to port B formed a right angle triangle.

To calculate the distance from port A to post B,

Let distance AB = X

AC = y

CB= z

X² = y² + z²

x² = 40² + 30²

= 1600+900

= 2500

X²= 2500

X= 50

Distance between port A and Port B is 500 miles.

Angle at A

30/sin a= 50/sin 90

Sin a = 30/50

a= sin^-1( 0.6)

a= 36.87°

Bearing of port B from A

90-36.87= 53.13

Bearing of port B from A= N 53.13°E

Angle at B

=180-(90+36.87)

b= 53.13°

Bearing of port A from B= S 53.13°W


Related Questions

5x +60/x -15x +15/x-20​

Answers

Answer:

5x-60=x - solution,..........

Answer:

Answer:

5x +60/x -15x +15/x-20

60/x+15/x-15x+5x-20

75/x-10x-20

is your answer

combined liked terms by adding and subtracting.

the center of a circle is on the line y=2x and the line x=1 is tangent to the circle at (1,6).find the center and the radius

Answers

The radius and the center of the circle are 4 units and (1,2), respectively

How to determine the center and the radius?

The center of the circle is on

y = 2x and x = 1

Substitute x = 1 in y = 2x

y = 2 * 1

Evaluate

y = 2

This means that the center is

Center = (1, 2)

Also, we have the point of tangency to be:

(x, y) = (1, 6)

This point and the center have the same x-coordinate.

So, the distance between this point and the center is

d = 6 - 2

d = 4

This represents the radius

Hence, the radius and the center of the circle are 4 units and (1,2), respectively

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Which is true? A 0.9919 > 0.999 B 1.4359 < 1.446 C 2.6953 = 2.75 D 4. 9395 > 5.0

Answers

Option B. is true.

A isn't true because 0.9919 is lesser than 0.999.C is false because 2.6953 is lesser than 2.75. They are not equal.D is also false because 4.9395 is not greater than 5.0.

Answer:

B. 1.4359 < 1.446

Hope you could get an idea from here.

Doubt clarification - use comment section.

Two rectangles of the same shape have areas of 676 and 3,457 square centimetres. If the shorter side of the larger rectangle is 41 centimetres, what are the dimensions of the smaller one?

Answers

The dimensions of the smaller rectangle are 13 centimeters by 52 centimeters.

Let's assume the dimensions of the smaller rectangle are length L and width W (in centimeters).

We know that the area of the smaller rectangle is 676 square centimeters:

L * W = 676    ----(1)

We also know that the larger rectangle has a shorter side of 41 centimeters. Let's say the corresponding longer side of the larger rectangle is H centimeters.

The area of the larger rectangle is 3457 square centimeters:

41 * H = 3457    ----(2)

Our current set of equations contains two unknowns. In order to get the smaller rectangle's dimensions, we can simultaneously solve these equations.

In order to find H, we can use equation (2):

H = 3457 / 41

H ≈ 84.22

Now we can substitute this value of H into equation (1):

L * W = 676

We need to find the dimensions (L and W) that multiply to give 676. We can start by looking for factors of 676.

Factors of 676: 1, 2, 4, 13, 26, 52, 169, 338, 676

By trial and error, we can see that the factors that give a close match to the dimensions of the larger rectangle (41 and 84.22) are 13 and 52:

L = 13

W = 52

Therefore, the smaller rectangle has measurements of 13 by 52 centimetres.

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what is the answer and explain how ​

what is the answer and explain how

Answers

Answer:

770000

Step-by-step explanation:

multiply the volume value by 100000

Answer:

770,000cL

Step-by-step explanation:

kL= kiloliter

cL= centiliter

cL=kL*10^5

so basically add 5, 0's to whatever you have

7.7*10^5=770,000

or 7.7*100,000

The credit remaining on a phone card (in dollars) is a linear function of the total calling time made with the card (in minutes). The remaining credit after 36 minutes of calls is
$24.24, and the remaining credit after 55 minutes of calls is $21.20. What is the remaining credit after 63 minutes of calls?

Answers

The remaining credit after 63 minutes of calls is $19.92.

What is the remaining credit after 63 minutes of calls?

From the information illustrated, the remaining credit after 36 minutes of calls is $24.24, and the remaining credit after 55 minutes of calls is $21.20.

The rate will be:

= (24.24 - 21.20) / (55 - 36)

= 3.04 / 19

= 0.16

The remaining credit after 63 minutes of calls will be:

= $21.20 - ((63 - 55) × $0.16)

= $21.20 - $1.28

= $19.92

The credit is $19.92.

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1) If the 10 kg sugar is Rs. 880 . Find the cost of 15 sugar

2) 50 students in a hostel have provisions for 21 days . How long would it last for 75 students?

Answers

1) If the 10 kg sugar is Rs. 880 . Find the cost of 15 kg sugar.....

Solution,

let the required cost be Rs x

Here , the quantities of sugar and their cost are direct proportion

So, 10 : 15 = 8: x

\( \: \frac{10}{15} = \frac{880}{x} \\ x = \frac{880 \times 15}{10} \\ x = Rs1320\)

Hence , the cost of sugar is Rs.1320

-----------------------------------------------------------------

-----------------------------------------------------------------

2) 50 students in a hostel have provisions for 21 days . How long would it last for 75 students?

Solution,

Let the required number of a day = x

Here , the number of student and the number of days are in inverse proportion.

•°• 50 : 75. = x : 21

\( \frac{50}{75} = \frac{x}{21} \\ x = \frac{50 \times 21}{75} \\ x = 14 \: days \\ \)

Hence, the provisions last for 14 days for75 students

~nightmare 5474~

1) The cost of 15 kg sugar is; Rs. 1320

2) The number of days that it would take the provisions to last for 75 students is; 14 days

Proportion

1) Cost of 10 kg = Rs. 880

Thus, by proportion the cost of 15 kg sugar will be;

(15 × 880)/10

>> 13200/10

>> Rs. 1320

2) We are told that;

50 students = provisions for 21 days

Thus for 75 students the number of days the provisions would last them is gotten by proportion;

(50 × 21)/75

>> 1050/75

>> 14 days

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Using the graph determine the coordinates of the zeros of the parabola

Using the graph determine the coordinates of the zeros of the parabola

Answers

Answer:

-5 and -The zeros of a parabola are the points on the parabola that intersect the line y = 0 (the horizontal x-axis). Since these points occur where y = 0,

I NEED HELP PLEASE A LOT OF IT

I NEED HELP PLEASE A LOT OF IT

Answers

The answer is 27. 9•2 is 18, 3•2 is 5, and 2•2 is 4. 18+5+4 = 27

Plz Help! I need this ASAP! I will give brainlest!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Plz Help! I need this ASAP! I will give brainlest!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

7)  164.26

8)77.08

9)2405.364

steps for 7) attached

steps for 8)

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Plz Help! I need this ASAP! I will give brainlest!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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Each of the following functions f,g,h, and h represents the amount of money in a bank account in dollars as a function of time x, in years they are each written in form m(x)= a•b

Each of the following functions f,g,h, and h represents the amount of money in a bank account in dollars

Answers

Answer:

f(x)  :  exponential growth

g(x);  exponential growth

h(x):  exponential growth

j(x):   exponential decay

Step-by-step explanation:

In an exponential function such as
\(m(x) = a \cdot b^x\)

the factor that determines whether it is a growth or decay function depends entirely on the value of b since x cannot be negative

If b > 1, it is a growth function

If b < 1 then it is a decay function

If b = 1 neither growth or decay function values are constant

In this context
f(x) has b = 2 > 1 . Hence it is a growth function
g(x) has b = 3 > 1 hence growth function
h(x) has be = 3/2 > 1; hence growth function
j(x) has be = 0.5 < 1 hence decay function

Answer:

O f(x)  :  exponential growth

O g(x);  exponential growth

O h(x):  exponential growth

O j(x):   exponential decay

Step-by-step explanation: I used to do this before :)

so can u help me guys

so can u help me guys

Answers

Thus, 715,000 =  7.15 x 10⁵, using the concept of scientific notations, both the values are found to be equal.

Explain about the scientific notations:

The number of times that decimal point must be moved to obtain a number between 1 and 10 is the exponent in scientific notation. The decimal point is shifted to the left in order to represent this number in scientific notation.

The main goal of scientific notation is to simplify computations using numbers that are abnormally large or small. With scientific notation, every digit counts because zeros are just no longer used to denote the decimal point.

Given expression:

715,000 __ 7.15 x 10⁵

LHS = 715,000

Take the RHS value :

= 7.15 x 10⁵

This, can be simplifies as:

= 7.15 x 100,000

Now multiply the two values,

= 715,000 (RHS values)

as, LHS  = RHS

LHS = 715,000

715,000 (RHS values)

Thus, 715,000 =  7.15 x 10⁵, using the concept of scientific notations, both the values are found to be equal.

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Determine whether 81a^2 − 25z^6 is a difference of two squares. If so, factor it. If not, explain why.
(9a − 5z^3)(9a − 5z^3)
(9a + 5z^3)(9a − 5z^3)
(9a − 5z^6)(9a + 5z^6)
It is not a difference of squares because −25z^6 is not a perfect square.

Answers

The given polynomial 81a² − 25z⁶ is not a difference of two squares because −25z⁶ is not a perfect square.

We can see that 81a² is a perfect square because it is equal to (9a)². However, 25z⁶ is not a perfect square because it can't be written as the square of a single term.

Therefore, we cannot factor 81a² − 25z⁶ into the difference of two squares.

\( \: \: \: \)

3/5 of the students in a classroom are girls. If there are ten boys in the class, how many total students are there?


15

25

16

20

Answers

Answer:

25

Step-by-step explanation:

15=Girls

10=Boys

25 =The total of the number of students

Ders: Attempt 1
Question 1 (3 points)
A tourist exchanged $1,000 US dollars for 910 British pounds. How many
pounds did she receive for each US dollar?
To solve set up a proportional equation and cross multiply.

Answers

She earned 0.91 pounds for every $1 US dollar when a visitor traded $1,000 US dollars for 910 British pounds.

What is proportion?

A proportion is an equation that sets two ratios equal to each other. For example, if there is one guy and three girls, the ratio may be written as 1: 3. (for every one boy there are 3 girls) One-quarter are males and three-quarters are girls. 0.25 are males (by dividing 1 by 4). According to the notion of proportion, two ratios are in proportion when they are equivalent. It is a formula or statement that shows that two ratios or fractions are equivalent.

Here,

For 910 pounds, she spent $1000 US dollars.

For $1,

=910/1000 pound

=0.91 pounds

For each $1 US dollar, she received 0.91 pounds as tourist exchanged $1,000 US dollars for 910 British pounds.

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12. Write a multiplication expression with a
product of 8^13

Answers

Answer: (8^5)(8^8)

Step-by-step explanation:

Hoped this helped!!!

The multiplication expression with a product of 8¹³ will be  8⁵ × 8⁸.

What is the law of indices?

Index (indices) in Maths is the power or exponent which is raised to a number or a variable.

In another word the mathematics of power or exponent of any number is called indices.

For example 5³ = 5²5 here we break 5³ into 5² and 5 so it is called the law of indices.

Another example could be 7² = 7³/7 here we divide to obtain power 2.

An algebraic expression is a quantity made up of symbols and processes + - / and multiplication Expressions utilizing indices are made simpler using the laws of indices.

Given,

8¹³

By the law of indices that \(x^{c}\) = \(x^{a}\) \(x^{b}\) such that c = a + b.

So,

8¹³  = 8⁵ × 8⁸

So it will the multiplication expression with a product of 8¹³.

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Could you please try to help me and my grandson with this problem?

Could you please try to help me and my grandson with this problem?

Answers

To match up the given data:

1. Find the discount (in dollars) that each original price would have with each percentage of discount:

Multiply the original price by the discount (in decimals):

Original price: $24

\(\begin{gathered} 24*0.2=4.8 \\ 24*0.3=7.2 \\ 24*0.4=9.6 \end{gathered}\)

Original price: $35

\(\begin{gathered} 35*0.2=7 \\ 35*0.3=10.5 \\ 35*0.4=14 \end{gathered}\)

Original price: $30

\(\begin{gathered} 30*0.2=6 \\ 30*0.3=9 \\ 30*0.4=12 \end{gathered}\)

2. Find the discounted price for each one of the possibilities above:

Original price: $24

\(\begin{gathered} 24-4.8=19.2 \\ 24-7.2=16.8 \\ 24-9.6=14.4 \end{gathered}\)

Original price: $35

\(\begin{gathered} 35-7=28 \\ 35-10.5=24.5 \\ 35-14=21 \end{gathered}\)

Original price: $30

\(\begin{gathered} 30-6=24 \\ 30-9=21 \\ 30-12=18 \end{gathered}\)

3. Match up coincidences.

For the original price of $24; there are not coincidences wit the discounted prices; let this to the end.

For the original price of $35; there is a coincidence: Discounted 40% you get a discounted price of $21

For the original price of $30 (as the discounted price of $21 is taken) the coincidence is: Discounted 20% you get a discounted price of $24

Then, the % that match the original price of $24 is 30% and the missing data is a discounted price of $16.8

Final answer:

Could you please try to help me and my grandson with this problem?

I will give brainliest

I will give brainliest

Answers

Answer:

Step-by-step explanation:

make a right triangle to find the lenght of a side  which is also the hypotenuse of the triangle

c² = a² + b²

c² = 7² + 5²

c²  = 49 + 25

c²  =  = 74

Since the area of a square is s² and c = s

a = c²

a = 74 units²

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Using f(x) = 2x + 7 and g(x) = x - 3, find f(g(x)).

Answers

Answer:

f(g(x)) = 2x + 1

Step-by-step explanation:

f(g(x))

f(x - 3)

2(x - 3) + 7

2x - 6 + 7

2x + 1

For every x in f(x), plug in (x-3), then simplify.

f(g(x))=2(x-3)+7

=2x-6+7

=2x+1

What change do you have to make to the graph of f (x) = 7x in order to graph the function g (x) = 7x+10?

Answers

To graph the function g(x) = 7x + 10, we shift the graph of f(x) = 7x vertically by adding a constant term of +10. This means every y-coordinate on the graph increases by 10 units. The slope of the line remains the same at 7. The resulting graph is a straight line passing through (0, 10) with a slope of 7.

To graph the function g(x) = 7x + 10, you need to make the following change to the graph of f(x) = 7x:
1. Translation: The graph of f(x) = 7x can be shifted vertically by adding a constant term to the equation. In this case, the constant term is +10.
Here's how you can do it step by step:
1. Start with the graph of f(x) = 7x, which is a straight line passing through the origin (0,0) with a slope of 7.
2. To shift the graph vertically, add the constant term +10 to the equation. Now, the equation becomes g(x) = 7x + 10.
3. The constant term of +10 means that every y-coordinate of the points on the graph will increase by 10 units. For example, the point (0,0) on the original graph will shift to (0,10) on the new graph.
4. Similarly, if you take any other point on the original graph, such as (1,7), the corresponding point on the new graph will be (1,17) since you add 10 to the y-coordinate.
5. Keep in mind that the slope of the line remains the same, as only the y-values are affected. So, the new graph will still have a slope of 7.
By making this change, you will have successfully graphed the function g(x) = 7x + 10.

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In 2003, the population of an African country was about 8 million people, which is 3 million more than 2
times the population in 1950.
Enter and solve an equation to find the approximate population p (in millions) in 1950.
An equation is
The approximate population in 1950 was
million people.

Answers

In 2003, the population of an African country was about 8 million people, which is 3 million more than 2 times the population in 1950. Therefore the population in 1950 was approximately 2.5 million.

Let p (million) be the population in 1950.

In 2003, the equation for the population is 2p + 3 = 8

2p + 3 = 8

2p = 5

p = 2.5 million

Therefore the population in 1950 was approximately 2.5 million.

What is an equation?

An equation is a mathematical term defined as a statement that combines two expressions in a statement that is connected by an equal sign.For example: 2a + 7 = 16.An equation expresses the equality between two expressions.

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The Ice Chalet offers dozens of different beginning ice-skating classes. All of the class names are put into a bucket. The 5 P.M., Monday night, ages 8 to 12, beginning ice-skating class was picked. In that class were 64 girls and 16 boys. Suppose that we are interested in the true proportion of girls, ages 8 to 12, in all beginning ice-skating classes at the Ice Chalet. Assume that the children in the selected class are a random sample of the population.

Required:
Construct a 92% Confidence Interval for the true proportion of girls in the ages 8-12 beginning ice-skating classes at the Ice Chalet.

Answers

Answer:

The answer is "(0.73,0.87)".

Step-by-step explanation:

Given:

number of girls\(= 64\)

number of boys\(= 16\)

Total number of children\(= 64+16= 80\)

So,\(n=80\)

Calculating the value of the proportion which is given by girls:

\(\hat{p}= \frac{\text{number of girls}}{\text{total number of childrens}}\)

  \(=\frac{64}{80}\\\\=\frac{8}{10}\\\\= 0.8\)

Therefore the confidence interval is:  

\(\to \hat{p}\pm z_{(1-\frac{\alpha }{2})}\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\\\\\to 0.8 \pm 1.75\sqrt{\frac{0.8(1-0.8)}{80}}\\\\\to 0.8 \pm 1.75 \sqrt{\frac{0.8(0.2)}{80}}\\\\\to 0.8 \pm 1.75 \sqrt{\frac{0.16}{80}}\\\\\to 0.8 \pm 1.75 \sqrt{0.002}\\\\\to 0.8 \pm 1.75 (0.04)\\\\\to 0.8 \pm 0.07\\\\\to (0.73,0.87)\)

\(\therefore \\\\\text{The lower confidence limit} = 0.73\\\\\text{The upper confidence limit} = 0.87\\\)

In the following alphanumeric series, what letter comes next? V, Q, M, J, H, …

In the following alphanumeric series, what letter comes next? V, Q, M, J, H,

Answers

According to the given information, the letter that comes next in the given alphanumeric series is "N".

What is alphanumeric series?

An alphanumeric series is a sequence of letters and/or numbers that follows a certain pattern or rule. For example, "A, B, C, D, E..." is an example of an alphabetical series, and "1, 3, 5, 7, 9..." is an example of a numerical series. An alphanumeric series may combine both letters and numbers, such as "A1, B2, C3, D4, E5...". The pattern or rule followed by an alphanumeric series may be based on numerical or alphabetical order.

The given series V, Q, M, J, H, ... follows a pattern where each letter is the 6th letter from the previous letter. So, the next letter in the series would be 6 letters after H, which is N.

Therefore, the letter that comes next in the given alphanumeric series is "N".

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100 Points! Geometry question. Photo attached. Please show as much work as possible. Thank you!

100 Points! Geometry question. Photo attached. Please show as much work as possible. Thank you!

Answers

Answer:

\(BC=5.1\)

\(B=23^{\circ}\)

\(C=116^{\circ}\)

Step-by-step explanation:

The diagram shows triangle ABC, with two side measures and the included angle.

To find the measure of the third side, we can use the Law of Cosines.

\(\boxed{\begin{minipage}{6 cm}\underline{Law of Cosines} \\\\$c^2=a^2+b^2-2ab \cos C$\\\\where:\\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides.\\ \phantom{ww}$\bullet$ $C$ is the angle opposite side $c$. \\\end{minipage}}\)

In this case, A is the angle, and BC is the side opposite angle A, so:

\(BC^2=AB^2+AC^2-2(AB)(AC) \cos A\)

Substitute the given side lengths and angle in the formula, and solve for BC:

\(BC^2=7^2+3^2-2(7)(3) \cos 41^{\circ}\)

\(BC^2=49+9-2(7)(3) \cos 41^{\circ}\)

\(BC^2=49+9-42\cos 41^{\circ}\)

\(BC^2=58-42\cos 41^{\circ}\)

\(BC=\sqrt{58-42\cos 41^{\circ}}\)

\(BC=5.12856682...\)

\(BC=5.1\; \sf (nearest\;tenth)\)

Now we have the length of all three sides of the triangle and one of the interior angles, we can use the Law of Sines to find the measures of angles B and C.

\(\boxed{\begin{minipage}{7.6 cm}\underline{Law of Sines} \\\\$\dfrac{\sin A}{a}=\dfrac{\sin B}{b}=\dfrac{\sin C}{c} $\\\\\\where:\\ \phantom{ww}$\bullet$ $A, B$ and $C$ are the angles. \\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides opposite the angles.\\\end{minipage}}\)

In this case, side BC is opposite angle A, side AC is opposite angle B, and side AB is opposite angle C. Therefore:

\(\dfrac{\sin A}{BC}=\dfrac{\sin B}{AC}=\dfrac{\sin C}{AB}\)

Substitute the values of the sides and angle A into the formula and solve for the remaining angles.

\(\dfrac{\sin 41^{\circ}}{5.12856682...}=\dfrac{\sin B}{3}=\dfrac{\sin C}{7}\)

Therefore:

\(\dfrac{\sin B}{3}=\dfrac{\sin 41^{\circ}}{5.12856682...}\)

\(\sin B=\dfrac{3\sin 41^{\circ}}{5.12856682...}\)

\(B=\sin^{-1}\left(\dfrac{3\sin 41^{\circ}}{5.12856682...}\right)\)

\(B=22.5672442...^{\circ}\)

\(B=23^{\circ}\)

From the diagram, we can see that angle C is obtuse (it measures more than 90° but less than 180°). Therefore, we need to use sin(180° - C):

\(\dfrac{\sin (180^{\circ}-C)}{7}=\dfrac{\sin 41^{\circ}}{5.12856682...}\)

\(\sin (180^{\circ}-C)=\dfrac{7\sin 41^{\circ}}{5.12856682...}\)

\(180^{\circ}-C=\sin^{-1}\left(\dfrac{7\sin 41^{\circ}}{5.12856682...}\right)\)

\(180^{\circ}-C=63.5672442...^{\circ}\)

\(C=180^{\circ}-63.5672442...^{\circ}\)

\(C=116.432755...^{\circ}\)

\(C=116^{\circ}\)

\(\hrulefill\)

Additional notes:

I have used the exact measure of side BC in my calculations for angles B and C. However, the results will be the same (when rounded to the nearest degree), if you use the rounded measure of BC in your angle calculations.

A researcher examines the records of all registered voters in one city and finds that 43% are registered democrats. Is the evaluated group a population or a sample?

Answers

Answer: Population

Step-by-step explanation: Population is refers to the whole or entire members or of a given set. This is different from a sample which is used to refer to members of a subset (a subset is a certain portion or fraction of an entire set). In the scenario above, since the evaluation was based on the entire number of registered voters in the country, this means we are referring to a population. The inference about the percentage of democratic voters was drawn from a pool of all the entire number of registered voters available in the country and not from a certain subset or portion of registered voters. Hence, the evaluated group is a population.

The half-life a particular radioactive
substance is 1 year. If you started with
50 grams of this substance, how much
of it would remain after 3 years?
First, complete the equation:
Remaining Amount =

Answers

Answer:

Remaining amount is 6.25 gram

Step-by-step explanation:

After one year what you would be left with is 50/2 which is 25 gram

After the second year, you would be left with 50/4 which is 12.5

After the third year what's left is 50/8 i.e 6.25

Factor 21x^2 - 14x - 56

Answers

Answer:

7((x-2)(3x+4))

Step-by-step explanation:

Common factor of 7 in this quadratic formula. \(7(3x^2-2x-8)\); -8 * 3x^2 = -24x^2, now find factors of this product that equal to -2x when added. The factors that fit this is -6x and 4x. So, if you make a generic rectangle you can find the product.  You get 7((x-2)(3x+4))

Factor 21x^2 - 14x - 56

Question 6
A square is placed within a rectangle. Find the area of the shaded region.
Select one:
O


O
559 ft²
640 ft²
721 ft²
604 ft²
32 ft
19A
9 ft
20 ft

Answers

The area of the shaded region is 559 ft².

How to find the area of the shaded region?

In order to find the area of the shaded region, we will subtract the area of the square from the area of the rectangle. That is:

area of the shaded region = area of rectangle - area of square

area of the shaded region = (32 * 20) - (9 * 9)

area of the shaded region = 640 - 81

area of the shaded region = 559 ft²

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Question 6A square is placed within a rectangle. Find the area of the shaded region.Select one:OO559

Hi everyone. I just wanted to put out links for every educational website I know, so if teachers are on here, they can share them.
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Hi everyone. I just wanted to put out links for every educational website I know, so if teachers are
Hi everyone. I just wanted to put out links for every educational website I know, so if teachers are
Hi everyone. I just wanted to put out links for every educational website I know, so if teachers are
Hi everyone. I just wanted to put out links for every educational website I know, so if teachers are
Hi everyone. I just wanted to put out links for every educational website I know, so if teachers are

Answers

answer.

thanks for this

What is the percent discount if a 12,500 car is now on special for 10,250?

Answers

Answer:

Step-by-step explanation:

the answer is 2250 percent is = 22.5

Answer:

18% discount

Step-by-step explanation:

Percent discount is found by the following formula:

\(\frac{original-discount}{original}\)

In this scenario, the original is 12500 and the discount, or special is 10250.

We can plug this into the formula to get

\(\frac{12500-10250}{12500}\)

We can simplify the numerator by subtracting, and we get that answer as 2250.

We get the remainder of the answer as 2250 divided by 12500. We divide that, and get the answer as 0.18, which can be rewritten as 18%.

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