1. (a) What must the charge (sign and magnitude) of a particle of mass 1.43 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 660 N/C? (b) What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight? 1. ( a ) What must the charge ( sign and magnitude ) of a particle of mass 1.43 g be for it to remain stationary when placed in a downward - directed electric field of magnitude 660 N / C ? ( b ) What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight ?​

Answers

Answer 1

(a)  The charge (sign and magnitude) of a particle of mass 1.43 g be for it to remain stationary is  2.12 x 10⁻⁵ C.

(b)The magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight is 10.24 x 10⁻⁸ N/C.

What is electric field?

The field developed when a charge is moved. In this field, a charge experiences an electrostatic force of attraction or repulsion depending on the nature of charge.

Given is a particle of mass 1.43 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 660 N/C.

The electric field and force is related as

F = qE

mg = qE

Substitute the given values in the question, we have

1.43 x 10⁻³ x 9.81 = q x 660

q = 2.12 x 10⁻⁵ C

Thus, the charge of particle is 2.12 x 10⁻⁵ C.

(b)
Given is the electric force on a proton is equal in magnitude to its weight.

Force on proton = mass of proton x acceleration due to gravity

F = 1.67 x 10⁻²⁷ kg x 9.81

F = 16.38 x 10⁻²⁷  N

Charge on proton = 1.6 x 10⁻¹⁹ C

E = F/q

E = 16.38 x 10⁻²⁷  /   1.6 x 10⁻¹⁹

E = 10.24 x 10⁻⁸ N/C

Thus, the magnitude of electric field is  10.24 x 10⁻⁸ N/C.

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Related Questions

What is the speed of light in a medium with an index of refraction n=1.95?1.54x10 m/s1.05x108 m/s6.50x107m/s4.95x108 m/s

Answers

We are asked to determine the speed of light in a medium with an index of refraction of 1.95. To do that we will use the following formula:

\(v=\frac{c}{n}\)

Where:

\(\begin{gathered} v=\text{ speed of light in the medium} \\ c=\text{ speed of light in vacuum} \\ n=\text{ index of refraction} \end{gathered}\)

Now, we substitute the values:

\(v=\frac{3\times10^8\text{ m/s}}{1.95}\)

Solving the operations:

\(v=1.54\times10^8\text{ m/s}\)

Before a collision, a 25 kg object is moving at 12 m/s to the right. After a collision with stationary box, the 25 kg object moves at 8 m/s to the right. What is the resulting momentum of the box?

Answers

The initial momentum of the 25 kg object is 25 kg * 12 m/s = 300 kgm/s. After the collision, the momentum of the 25 kg object is 25 kg * 8 m/s = 200 kgm/s. According to the conservation of momentum, the momentum lost by the 25 kg object is equal to the momentum gained by the box. Therefore, the resulting momentum of the box is 300 kgm/s - 200 kgm/s = 100 kg*m/s.

Identify two types of motion where an object's speed remains the same while it continues to change direction

Answers

Answer:

motion in which acceleration is orthogonal to travel directionmotion in which speed is constant

Explanation:

1) Any motion in which the acceleration is orthogonal to the direction of travel will have this characteristic:

  circular motion in a plane

  motion of a charged particle in a magnetic field perpendicular to the direction of travel

__

2) Motion in which the speed is constant, regardless:

  motion of a photon through a varying gravitational field

If the south pole of one bar magnet is brought near the north pole of a second bar magnet, the two magnets will Question 9 options: attract. repel.

Answers

If the south pole of one bar magnet is brought near the north pole of a second bar magnet, the two magnets will repel each other.

Magnets have two poles, a north pole and a south pole. According to the principles of magnetism, opposite poles attract each other, while like poles repel each other.When the south pole of one bar magnet is brought near the north pole of a second bar magnet, they are like poles that are facing each other. Since like poles repel each other, the two magnets will repel each other.This repulsion occurs because the magnetic field lines of the two magnets interact. Magnetic field lines emerge from the north pole of a magnet and enter the south pole. When two like poles are brought close together, their magnetic field lines repel each other, causing a force of repulsion between the magnets.This phenomenon can be observed by attempting to bring the two magnets together. As they approach each other, a force will be experienced, pushing them apart. The repulsion between the two magnets will prevent them from coming into contact and will keep them separated.Therefore, when the south pole of one bar magnet is brought near the north pole of a second bar magnet, the two magnets will repel each other.

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Please help me i need this to pass :((

Please help me i need this to pass :((

Answers

Based on the densities of the two liquids, the height of the light liquid in the right arm of the U-tube is 0.203 cm.

What is the height L of the light liquid in the column in the right arm of the U-tube?

Let's first consider the situation before the light liquid is added. At this point, the heavy liquid fills both arms of the U-tube to the same height, h.

The pressure at point A is equal to the pressure at point B

Therefore:

P₀ + ρgh = P₀ + ρgh

where P₀ is the atmospheric pressure, ρ is the density of the heavy liquid, and g is the acceleration due to gravity.

Simplifying this equation, we get:

ρgh = ρgh

Canceling out the ρ and solving for h, we get:

h = h

In other words, the height of the heavy liquid is the same in both arms of the U-tube.

Now let's consider the situation after the light liquid is added to the right arm of the U-tube. We want to find the height, L, of the light liquid in the right arm.

Since the pressure at any two points in a connected vessel is the same, the pressure at point B (the top of the heavy liquid in the right arm) must be equal to the pressure at point C (the top of the light liquid in the right arm).

Therefore, we can write:

P₀ + ρgh = P₀ + ρg(L+h)

where L is the height of the light liquid in the right arm.

Simplifying this equation, we get:

ρgh = ρgL + ρgh

Canceling out the ρgh and solving for L, we get:

L = (ρ/ρ₀)h

where ρ₀ is the density of the light liquid.

Substituting the given values, we get:

L = (0.92 g/cm³ / 13 g/cm³)h

L = 0.070769h

Now we need to find h. We can use the fact that the volume of the heavy liquid in the left arm is equal to the volume of the heavy liquid plus the light liquid in the right arm.

The volume of the heavy liquid in the left arm is:

V₁ = Ah = (13.2 cm²)(h cm)

V₁ = 13.2h cm³

The volume of the heavy liquid plus the light liquid in the right arm is:

V₂ = A(L+h) = (2.11 cm²)(L+h cm)

V₂ = 2.11(L+h) cm³

Since these volumes are equal, we can set them equal to each other and solve for h:

13.2h = 2.11(L+h)

13.2h = 2.11L + 2.11h

11.09h = 2.11L

h = (2.11/11.09)L

Substituting this into our expression for L, we get:

L = 0.070769(2.11/11.09)L

L = 0.01345L

L = 0.01444h

Substituting the given value for the density of the heavy liquid, we get:

L = 0.01444h = 0.01444(13 g/cm³)/(0.92 g/cm³)

L = 0.203 cm

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Complete question:

A heavy liquid with a density 13 g/cm³ is poured into a U-tube as shown in the left- hand figure below. The left-hand arm of the tube has a cross-sectional area of 13.2 cm², and the right-hand arm has a cross-sectional area of 2.11 cm². A quantity of 90.2 g of a light liquid with a density 0.92 g/cm³ is then poured into the right-hand arm as shown in the right-hand figure below.

Determine the height L of the light liquid in the column in the right arm of the U-tube, as shown in the second figure above. Answer in units of cm.

A 150kg of rectangular tank of dimension 20m X 10m X 15m is placed on a level floor. What maximum and minimum pressure dose the tank exerts on the floor? Take g = 10 m/s^2

Answers

Explanation:

Weight of tank =  150 kg * 10 m/s^2 = 1500 N

since we are not given which of the dimensions are the  bottom of the tank  

   smallest area would be   10 x 15  = 150 m^2

    largest area would be    20 x 15 = 300 m^2

Max pressure would then be   1500 N / 150m^2 =  10 pascal

Min pressure would be  1500 N / 300 m^2 = 5 pascal

Phobos, one of the moons of Mars, orbits at a distance of 9378 km from the center of the red planet.

Part A What is the orbital period of Phobos?

Answers

The orbital period of Phobos is 7.66 hours.

What is orbital period?

The orbital period also known as the revolution period is the amount of time it takes an astronomical object to complete one orbit around another. It usually refers to planets or asteroids orbiting the Sun, moons orbiting planets, exoplanets orbiting other stars, or binary stars in astronomy.

It will be calculated thus:

T^2 = (4π)^2( d^3) / ((G)(Mm))

where d is the distance in meters, 9.378 x 10^6 meters

(4π)^2 = 39.5

G = 6.67 x 10^-11 m^3 kg^-2 s^-2

Mm = the mass of Mars in kg which is 6.42 x 10^23 kg.

T^2 = 7.61 x 10^8 sec^2

Find the square root.

T = 2.76 x 10^4 sec

T = 7.66 hours

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27. Describe how batteries provide electrical charges (or convert energy). (SSP5b)

Answers

Answer:

A battery is a device that stores chemical energy and converts it to electrical energy.

Explanation:

The chemical reactions in a battery involve the flow of electrons from one material (electrode) to another, through an external circuit. The flow of electrons provides an electric current that can be used to do work

Required
Momentum
The magnitude of the momentum of an object is 64 kg*m/s. If the velocity of the
object is doubled, what will be the magnitude of the momentum of the object? *
32 kg*m/s
64 kg*m/s
128 kg*m/s
256 kg*m/s

Answers

Answer:

C) 128 kg*m/s

Explanation:

When you double something you multiply it by 2 most of the time. 64*2=128 or you can add it 64+64=128. Hope this helps.

Which term is applied to an object through which light passes?
A. Absorbent
B. Opaque
C. Reflective
D. Transparent

Answers

Answer:

D

Explanation:

transparent_objects that allows light to pass through and can you see through them

Help! Offering Brainliest & Points!
Match Letter's with image.

Help! Offering Brainliest & Points! Match Letter's with image.

Answers

The correct match is A - trough, B - amplitude, C - crest, and D - wavelength.

A - A trough is the lowest point on a wave, where the displacement of the medium or the amplitude of the wave is at its minimum.

B - Amplitude refers to the maximum displacement or distance moved by a point on a vibrating body or wave, from its equilibrium position.

C - A crest is the highest point on a wave, where the displacement of the medium or the amplitude of the wave is at its maximum.

D - Wavelength is the distance between two corresponding points on a wave, such as the distance between two consecutive crests or troughs. It is often measured in meters or other units of length.

Hence, A - trough, B - amplitude, C - crest, and D - wavelength.

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Which of the following solutions contains the smallest total concentration of ions, assuming complete dissociation?

a) 2 M AI2(SO4)3

b) 2 M AICl3

c) 2 M NaCl

d) 2 M CaCl2

Answers

The solution with the lowest total ion concentration, assuming full dissociation, is 2 M aluminum sulphate.

What is concentration?

Concentration in chemistry is defined as the abundance of an ingredient divided by the total volume of a combination. There are four sorts of mathematical descriptions: mass concentration, molar concentration, number concentration, and volume concentration. The amount of a material, such as salt, that is present in a certain amount of tissue or liquid, such as blood. When there is less water present, a material becomes more concentrated. When a person does not drink enough water, the salt in his or her urine may become more concentrated. A substance's concentration is the amount of solute contained in a given amount of solution. Molarity is the number of moles of solute in one liter of solution and is used to express concentrations.

Here,

The solution with the lowest total ion concentration, assuming full dissociation, is 2 M aluminum sulfate.

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All the questions are in the photos above. Thanks guys!

All the questions are in the photos above. Thanks guys!
All the questions are in the photos above. Thanks guys!
All the questions are in the photos above. Thanks guys!
All the questions are in the photos above. Thanks guys!

Answers

Answer:

right

Explanation:

The frames for a pair of eyeglasses have a radius of 2.14 cm at 20.0°C. Lenses with radius of 2.16 cm have to be inserted into these frames. To what temperature must the technician heat the frames to accommodate the lenses? The frames are made of a material whose thermal expansion coefficient is 1.30 10-4/°C.

Answers

Answer:

The technician must heat the frame to a temperature of T₂ = 0.0072°C

Explanation:

Change in one-dimension of an object upon heating is given by the following equation:

ΔL = α L ΔT

For the radius this equation can be re-written as follows:

ΔR = α R ΔT

where,

ΔR = Change in Radius =  2.16 cm - 2.14 cm = 0.02 cm

α = Thermal Expansion Coefficient = 1.3 x 10⁻⁴ /°C

R = Original Radius = 2.14 cm

ΔT = Change in Temperature = T₂ - 20°C

Therefore,

0.02 cm = (1.3 x 10⁻⁴ /°C)(2.14 cm)(T₂ - 20°C)

T₂ - 20°C = (0.02 cm)/(1.3 x 10⁻⁴ /°C)(2.14 cm)

T₂ = 0.0072°C + 20°C

T₂ = 20.0072°C

The use of queries and reports are key functions of ______ software.

A. Spreadsheet

B. Database

C. Desktop publishing

D. Internet

Answers

Answer:

DATABASE!!!! I HOPE I HELPED.

The use of queries and reports are key functions of database software, therefore the correct answer is option B.

What is Information technology?

Digital transformation is a wide term that encompasses the creation, application, and use of anything involving computers and telecoms.

An example of information technology is the creation of a new word processing program. A subset of digital technologies is cloud-based.

A planned collection of information that has been organized and is frequently stored electronically in a computerized is referred to as a database. A database is frequently managed with a DBMS.

Thus, The use of queries and reports are key functions of database software, therefore the correct answer is option B.

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The number of hours
of daylight tat a location receives varies depending on how far north or south it is from the

Answers

Answer:

equator

Explanation:

in south & north pole you could have 20+ hours daylight or night, everyday!

If the error in the angle is 0.50, the error in sin 90° is​

Answers

The error in the measurement of sin 90 degrees at the given error in angle is  0.001.

Error in measurement

The error in measurement is obtained from the difference between the actual measurement and the observed measurement.

The error of sin 90 degrees is calculated as follows;

Actual measurement = sin 90 = 1

Observed measurement = sin(90 - 0.5)

Observed measurement = sin(89.5) = 0.999

Error in measurement of sin 90 degrees

Error in measurement = Actual measurement - Observed measurement Error in measurement = 1 - 0.999

Error in measurement  = 0.001

Thus, the error in the measurement of sin 90 degrees at the given error in angle is  0.001.

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Help me out on this? Grades due in a couple days and I need to get everything done on time-​

Help me out on this? Grades due in a couple days and I need to get everything done on time-

Answers

Answer:

75mL

...............

The question is full of inconsistencies and conceptual errors. Students should not waste their time trying to answer it ... it will only mislead and confuse them.

The question is poor. It was written by someone unclear on the concepts. It should be ignored.

A carmaker has designed a car that can reach a maximum acceleration of 12 meters/second2. The car’s mass is 1,515 kilograms. Assuming the same engine is used, what should the car’s mass be if the carmaker wants to reach an acceleration of 15 meters/second2? Use F = ma.
A.
1,212 kg
B.
1,335 kg
C.
1,466 kg
D.
1,515 kg
E.
1,894 kg

Answers

Answer:

A: 1,212 kg

Explanation:

A ball traveling in a circle with a constant speed of 8 m/s has a centripetal acceleration of 20 m/s2. What is the radius of the circle?

The radius of the circle is ____
m.

Answers

Answer:

The radius of the circle will be 20

Explanation:

First we will get the time from the given

time =velocity÷acceleration, 8÷20= 0.4s

then we are going to get the distance (circumference)

d=velocity ×time, 8×0.4=3.2

since that the circumference =2/pi (r)²

2×22÷7×r²=3.2 , 3.2 ÷44÷7=0.509 root 0.509

radius=0.71

IS
When a 0.622 kg basketball hits
the floor, its velocity changes from
4.23 m/s down to 3.85 m/s up.
What impulse was given to the
ball?
(Unit = kg*m/s)
Remember: up is +, down is -
Enter

Answers

Answer:

5.03

Explanation:

trust me

How long would it take for Sofia to walk 300 meters if she is walking at a velocity of 2.5 m/s?

Answers

Answer:

Time=120seconds

Explanation:

S=300m

V=2.5m/s

t=?

V=S/t

t=S/V

t=300/2.5

t=120 second

Answer:

120 seconds

Explanation:

.....

...

.....

A soccer player kicks a ball, applying a force of 1,000 newtons over a distance of 0.2 meter. The ball travels 50 meters down the field before another player stops the ball. How much work was done during the kick?

Answers

The total work done on the ball by the soccer player is 50,200 J.

Work done by applied force

The work done by the applied force is the product of the applied of the applied force and the displacement of the object.

The work on the ball

The work done on the ball is calculated as follows;

W = Fd

W = 1000 x (0.2 + 50)

W = 50,200 J

Thus, the total work done on the ball by the soccer player is 50,200 J.

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How is thermal energy being transferred when steam rises from a beaker of boiling water?
O A. Conduction
• B. Radiation
O c. Translation O D. Convection

Answers

Answer:

d. convention

Explanation:

hope this helped

answers D. convection

A 0.75 kg mass attached to a vertical spring stretches 0.30m. a) what is the spring constant?

Answers

Answer:25N/

Explanation:

A 0.75 kg mass attached to a vertical spring stretches 0.30m. a) what is the spring constant?

Focal distance of a concave lens is always:
O A. smaller than the image distance.
O B. positive.
O C. negative.
O D. larger than the object distance.

Answers

D large than the objects distance


A 2 m long wire carrying 2 A of current pointing to the right is placed in a magnetic field of 4 T directed away from you.
How big is the force acting on the wire?
A. 4 N
B. 8 N
C. 12 N
D. 16 N

Answers

Answer:16

Explanation:

as F=BIL so by placing value's B is magnetic field 4 and i is current 2A and l is length that js 2 m so answer is

Given: i=10A,B=0.15 T,θ=45

and l=2 m

Force on a current carrying wire of finite length =

F

=l(

i

×

B

)

Hence, magnitude of force, F=Bilsinθ

=0.15×10×2×sin45

=

2

3

N

a rectangular loop of wire has area A it is placed perpendicular to a uniform magnetic field B and spun around one of its side at frequency f the maximum induced emf is

Answers

When a rectangular loop of wire has area A it is placed perpendicular to a uniform magnetic field B and spun around one of its sides at frequency f the maximum induced emf is  2πBAf

What is a magnetic field?

A magnetic field could be understood as an area around a magnet, magnetic material, or an electric charge in which magnetic force is exerted.

The maximum induced emf is 2πBAf when a rectangular wire loop of area A is spun around one of its sides at frequency f, perpendicular to a uniform magnetic field B.

therefore the correct answer is option C

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Your question seems incomplete, the complete question is as follows

A rectangular loop of wire has area A. It is placed perpendicular to a uniform magnetic field B and then spun around one of its sides at frequency f. The maximum induced emf is:

A. BAf

B. 4πBAf

C. 2πBAf

D. 2BAf

A steel ball is dropped from a height of 12.09 m above the ground. What is its speed 2.101 m above the ground

Answers

So, the final velocity of the ball when it is 2.101 above the ground is 13.99 m/s or can be rounded to 14 m/s.

Introduction

Hi ! In this question, I will help you. This question will addopt the principle of final velocity in free fall. Free fall is vertical downward movement that occurs when any object dropped without initial velocity. In othee word, the object that falls is only affected by the presence of gravity and its initial high. In general, the final velocity in free fall can be expressed by this equation :

\( \boxed{\sf{\bold{v = \sqrt{2 \times g \times h}}}} \)

With the following condition :

v = final velocity (m/s)h = height or any other displacement at vertical line (m)g = acceleration of the gravity (m/s²)

Problem Solving

We know that :

\( \sf{h_1} \) = initial height = 12.09 m\( \sf{h_2} \) = final height = 2.101 mg = acceleration of the gravity = 9.8 m/s²

Note :

At this point (2.101 m above the ground), the object can still complete its movement up to exactly 0 m above the ground.

What was asked :

v = final velocity = ... m/s

Step by Step

\( \sf{v = \sqrt{2 \times g \times \Delta h}} \)

\( \sf{v = \sqrt{2 \times g \times (h_1 - h_2)}} \)

\( \sf{v = \sqrt{2 \times 9.8 \times (12.09 - 2.101)}} \)

\( \sf{v = \sqrt{19.6 \times 9,989}} \)

\( \sf{v \approx \sqrt{195.78}} \)

\( \boxed{\sf{v = 13.99 \: m/s \approx 14 \: m/s}} \)

Conclusion

So, the final velocity of the ball when it is 2.101 above the ground is 13.99 m/s or can be rounded to 14 m/s.

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From these measurements, compute the possible error in the volume.

From these measurements, compute the possible error in the volume.

Answers

From these measurements,  the possible error in the volume is 10.64%. This is done by measurement and error analysis.

.

What is error analysis?

Uncertainty analysis, often known as error analysis, is the process of assessing the degree of uncertainty related to a measurement result. There can be no reliable scientific results without a proper error analysis. The accuracy and precision of the measurement determine how uncertain a measurement can be.

Using the formula

Δ\(\frac{V}{V}\) × 100 = 200 × Δ\(\frac{D}{D}\) + 100 × Δ \(\frac{L}{L}\)

ΔV = Error in volume

ΔL = Error in length =0.1 cm

ΔD = Error in diameter= 0.1 cm

V = Volume of cylinder

D = diameter of cylinder=2.1cm

L = length of cylinder=8.9 cm

Substituting the values ,

possible error in the volume = 10.64%

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