1. Define gravitation.for class 10​

Answer:

If a player is fouled while shooting a three-point shot and makes it anyway, he is awarded one free throw. Thus, he could score four points on the play. Inbounds- If fouled while not shooting, the ball is given to the team the foul was committed upon.

The owl started out at a height of about 3.2 metres.

Gravity is the force that draws objects toward the center of a planet or other object.

Gravitational potential energy (GPE) is calculated as follows:

GPE = mass x gravity x height. Since we are aware of the owl's mass (4 kg) and the change in GPE (-800 J) in this case, we can rewrite the formula to account for the height: tallness = GPE / (mass x gravity).

On Earth, the acceleration caused by gravity is roughly 9.8 m/s2.

By entering the known numbers, we obtain the height change as follows: -800 J / (4 kg x 9.8 m/s2) = -0.408 metres.

By combining the ultimate height (which is believed to be 0 metres) with the height change, we may get the initial height as follows: 0 m + (-0.408 m) = -0.408 m = 0.408 m = 3.2m.

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Answer:

e

Explanation:

Answer:

i think 7000÷35= 200 m/s

(a)The equation of the shape of the room is (x - 0)²/(97/2)² + (y - 0)²/(23)² = 1. (b) The distance between the foci is approximately 94.2 ft.

a. For the given Statuary hall with dimensions 46 feet wide by 97 feet long, we have to find the equation of the shape of the room, center the ellipse at the origin, and let the major axis lie on the x-axis. We will use the formula of the ellipse:

(x-h)²/a² + (y-k)²/b² = 1,

where,

(a, 0) and (-a, 0) are the endpoints of the major axis

(b, 0) and (-b, 0) are the endpoints of the minor axis.

The major axis is on the x-axis, and therefore, h = 0. Since the ellipse is centered at the origin, k = 0.

The length of the major axis is 97, which is equal to 2a, so a = 97/2.

The length of the minor axis is 46, which is equal to 2b, so b = 46/2.

Therefore, a = 97/2 and b = 23.

The equation of the shape of the room is:(x - 0)²/(97/2)² + (y - 0)²/(23)² = 1

Simplifying the equation above,(x² / (97/2)²) + (y² / 23²) = 1(x² / (9409/4)) + (y² / 529) = 1(4x² / 9409) + (4y² / 529) = 4((2x / 97)² + (2y / 23)²) = 1

So, the equation of the shape of the room is ((2x / 97)² + (2y / 23)²) = 1.

b. The distance between the foci of the ellipse is equal to√(a² - b²).

Substituting the value of a and b we obtained above into the formula, we have;

√((97/2)² - 23²)=√(9409/4 - 529) = √(8880.25) = 94.2 (approx.)

Therefore, the distance between the foci is approximately 94.2 ft.

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(a) The course of the aeroplane is 234.3 km/h at 78⁰.

(b) The time  taken for the aeroplane to fly across is 2.5 hours.

The course of the aeroplane is calculated as follow;

Total vertical velocity = 220 km/h x sin(110) + 35 km/h x sin (40)

Total vertical velocity = 229.23 km/h

Total horizontal velocity = 220 km/h x cos(110) + 35 km/h x cos (40)

Total horizontal velocity = -48.43 km/h

The resultant velocity of the aeroplane is calculated as;

v = √ ( 229.23² + ( -48.43)² )

v = 234.3 km/h

The direction of the aeroplane

θ = arc tan ( Vy / Vx )

θ = arc tan ( 229.23 / 48.43 )

θ = 78⁰

The time of motion of the aroplane is calculated as follows;

t = ( 600 km ) / ( 234.3 km/h )

t = 2.5 hours

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Answer:

call me 7164013838 hurry bye

Explanation:

The work that leads towards the open mindness of people without any discrimination that contribute to a moral development is positive work

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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The momentum of the baseball with a mass of 0.14 kg and velocity of 41.26 m/s is determined as 5.78 kgm/s.

The momentum of the baseball is calculated by applying the following formula as shown below;

P = mv

where;

The momentum of the baseball is calculated as follows;

mass of the baseball = 0.14 kg

velocity of the baseball = 41.26 m/s

momentum, P = mv

P = 0.14 kg  x  41.26 m/s

P = 5.78 kgm/s.

Thus, the momentum of the baseball with a mass of 0.14 kg and velocity of 41.26 m/s is determined as 5.78 kgm/s by applying the formula for linear momentum.

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The complete question is below:

Imagine a baseball pitcher and a batter. The baseball has a mass of 0.14 kg. The ball is pitched to the right with a velocity of 41.26 m/s. What is the momentum of the baseball?

The force and acceleration alter as the object moves away from its equilibrium position.

The force on the object at any point is given by Hooke's Law:

F = -kx

where F = force, k = force constant of the spring, and x = displacement of the object from its equilibrium position.

The acceleration of the object at any point is given by Newton's Second Law:

a = F/m

where a = acceleration, F = force, and m = mass of the object.

Using these equations, calculate the force and acceleration at each of the specified points:

At x = 0.100 m:

F = -kx = -(1.30 x 10 N/m)(0.100 m) = -0.130 N

a = F/m = (-0.130 N)/(0.350 kg) = -0.371 m/s² (the negative sign indicates that the acceleration is in the opposite direction to the displacement)

At x = 0:

F = -kx = -(1.30 x 10 N/m)(0) = 0 N (the spring is at its equilibrium position)

a = F/m = 0 N/0.350 kg = 0 m/s²

At x = -0.0500 m:

F = -kx = -(1.30 x 10 N/m)(-0.0500 m) = 0.065 N (note that the force is positive because the displacement is negative)

a = F/m = (0.065 N)/(0.350 kg) = 0.186 m/s²

At x = -0.100 m:

F = -kx = -(1.30 x 10 N/m)(-0.100 m) = 0.130 N

a = F/m = (0.130 N)/(0.350 kg) = 0.371 m/s²

So, the force and acceleration change with the displacement of the object from its equilibrium position.

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The magnitude of the initial acceleration of the object is 4.2 m/s².

The tension in the string once the object starts moving is 13.65 N.

The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;

F(net) = ma

m₂g - μm₁g cosθ = a(m₁ + m₂)

where;

(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)

33.5 = 8a

a = 33.5/8

a = 4.2 m/s²

The tension in the string once the object starts moving is calculated as;

T = m₁a

T = 3.25 x 4.2

T = 13.65 N

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The velocities of the two balls after the collision are +70.0 cm/s to the right for both balls.

Velocity is described as  the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.

The  initial momenta of the two balls are:

p1 = mv1 = m(+40.0 cm/s) = +40m

p2 = mv2 = m(-30.0 cm/s) = -30m

m=  mass of each ball.

We know that by the conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision.

p1 + p2 = mv1' + mv2'

mv1 + m(-v2) = mv1' + mv2'

We then Substitute the values for the momenta and solving for v1 and v2

v1 = (-v2) + v1 = (-(-30.0 cm/s)) + (+40.0 cm/s) = +70.0 cm/s

v2 = v1 - v2 = (+40.0 cm/s) - (-30.0 cm/s) = +70.0 cm/s

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Answer:

first

Explanation:

also wat u need help with

If we rearrange the circuit so that the inductor and capacitor were connected in series,the impedance would be  Decreased and the resonant frequency would be unchanged.

Frequency is the rate at which something occurs over a particular period of time or in a given sample.

Sol-An LC circuit is made up of an inductor (L) and a capacitor (C). At the resonance condition of the LC circuit, the inductive reactance XL. becomes equal to the capacitive reactance Xc.

It is defined as-

XL= 2πfL

Xc= 1/2πfC

So when reactances are equal we have-

XL=Xc

2πfL= 1/2πfC

f^2=1/4π^2LC

f=1/2π√LC

The resonance condition is the same for both the parallel and series LC circuit, so the resonance frequency will not change.

The impedance of a parallel LC circuit is:

Z(w)= jL w^2-w^2•/w

In a series LC circuit, when w

, the impedance becomes equal to 0.

Therefore the impedance of a series LC circuit will decrease and the resonant frequency will remain the same.

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Let's see

\(\\ \rm\Rrightarrow x=Asin(\omega t)\dots(1)\)

Now we know the formula of acceleration

\(\\ \rm\Rrightarrow \alpha=-A\omega^2sin(\omega t)\)

\(\\ \rm\Rrightarrow \alpha=-Asin(\omega t)\times \omega^2\)

\(\\ \rm\Rrightarrow \alpha=-x\omega^2\)

Or

\(\\ \rm\Rrightarrow \alpha=-\omega^2x\)

Given that the position x of a particle along X-axis varies with time t by the equation:

\({:\implies \quad \sf x=A\sin (\omega t)}\)

As it defines the position, so x is just displacement here, and we need to find the acceleration first for telling with what if varies, so by definition, the second differential coefficient of displacement is acceleration, so differentiating both sides w.r.t.x of the above equation in accordance with chain rule we have:

\({:\implies \quad \sf \dfrac{dx}{dt}=A\cos (\omega t)\cdot \omega \cdot \dfrac{dt}{dt}}\)

\({:\implies \quad \sf \dfrac{dx}{dt}=A\omega \cos (\omega t)}\)

Differentiating both sides w.r.t.x by chain rule again to get the 2nd order derivative

\({:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-A\omega \sin (\omega t)\cdot \omega \dfrac{dt}{dt}}\)

\({:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-A\omega^{2}\sin (\omega t)}\)

Re-write as :

\({:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-\omega^{2}\{A\sin (\omega t)\}}\)

Can be further written as

\({:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-x\omega^{2}}\)

This is the Required answer

If they ask you the differential equation for the acceleration of a wave (as the given equation was general equation of a wave), you can simply write:

\({:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}+x\omega^{2}=0}\)

Impact ice is formed either from water present in the atmosphere as snow, sleet, or from exposure of liquid water to a temperature below 32°F.

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The skydiver is accelerating upward with an upward orientation with an acceleration of 0.556 m/s².

The pace at which a speed changes over time is called acceleration. In other words, it is a measurement of how quickly an object's velocity alters. It is a vector quantity with a direction and magnitude.

Finding the net force affecting the skydiver can be our first step. The vector sum of all forces acting on the skydiver is known as the net force. Weight and drag force are the two forces at play here as they affect the skydiver.

The skydiver's weight is determined by:

Weight= mass x acceleration due to gravity

Weight: 82.0 kg x 9.81 m/s² (acceleration due to gravity)

Weight= 804.42 N

The skydiver is under the following net force:

net force = weight - drag force

850 N - 804.42 N = Net force

45.58 N of net force (upwards)

The skydiver will accelerate upwards since the net force is upward. The magnitude of the acceleration can be determined by applying Newton's second law of motion:

Net force is calculated as follows:

Net force = mass x acceleration

45.58 N = 82.0 kg x acceleration

Acceleration = 0.556 m/s².

As a result, the skydiver is accelerating upward with an upward orientation with an acceleration of 0.556 m/s².

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The speed of the mass as it passes the natural length of the spring is approximately 0.316 m/s.

To find the speed of the mass as it passes the natural length of the spring, we can apply the principle of conservation of mechanical energy. Initially, the mass has potential energy stored in the compressed spring, and as it moves past the natural length, this potential energy is converted into kinetic energy.

The potential energy stored in the spring is given by the formula:

Potential Energy (PE) = (1/2) × k × x²

Here in the above equation k is said to be the spring constant and whereas x is said to be the length displaced

Given:

Mass (m) = 2 kg

Spring constant (k) = 20 N/m

Displacement (x) = 0.1 m

Plugging the values into the formula, we can calculate the potential energy:

PE = (1/2) × 20 N/m × (0.1 m)²

PE = 0.1 J

According to the principle of conservation of mechanical energy, the potential energy is converted entirely into kinetic energy when the mass reaches the natural length of the spring.

Kinetic Energy (KE) = Potential Energy (PE)

(1/2) × m × v² = 0.1 J

Rearranging the equation and solving for velocity (v):

v² = (2 × PE) / m

v² = (2 × 0.1 J) / 2 kg

v² = 0.1 J / kg

v² = 0.1 m²/s²

Taking the square root of both sides:

v = √(0.1 m²/s²)

v ≈ 0.316 m/s

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Using Coulomb's law:

Where:

Therefore:

Solve for q1:

Answer: B

Explanation: the teacher just told us the answer

The gravitational force between the two spheres is \(1.67 \times 10^{-11} \ N\).

The given parameters;

The gravitational force between the two spheres is determined by applying Newton's law of universal gravitation as shown below;

\(F = \frac{Gm_1 m_2 }{r^2} \\\\\)

where;

\(F = \frac{(6.67\times 10^{-11})\times (1\times 1)}{2^2} \\\\F = 1.67 \times 10^{-11} \ N\)

Thus, the gravitational force between the two spheres is \(1.67 \times 10^{-11} \ N\).

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Answer:

I wish I could help but iam srry

The disk is equivalent to a solid cylinder 0.700 cm high and 3.80 cm in diameter. The shear deformation is .∆x=3.34×10⁻⁶ m.

Deformation refers to the change in size or shape of and object whereas displacements are the absolute change in to the  position of a point on the  the object. Deflections is the relative changes in external displacements in an object.

The shear deformation is .

Given that,

Shearing force F = 600 nm

Shear modulus S=1×10⁹ n/m²

length = 0.700 cm

diameter = 4.00 cm

We need to find the shear deformation

Using formula of shear modulus

S=Flo/A ∆x

∆x=Flo/(rd²/4)S

∆x=4Flo/(rd²/)S

Put the value into the formula

∆x=4×600×0.700×10²/3.14×1×10⁹×(4.00×10²)

∆x=3.34×10⁻⁶ m

Hence, The shear deformation is .∆x=3.34×10⁻⁶m

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An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.

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Answer:

B: False

Explanation:

The second law of thermodynamics states that: the entropy of an isolated system will never decrease because isolated systems always tend to evolve towards thermodynamic equilibrium which is a state with maximum entropy.

Thus, it means that the entropy change will always be positive.

Therefore, the given statement in the question is false.

The models that predict galaxies should be getting farther apart now are; accelerating model, critical model,- and coasting model.

Observations show that the expansion of the universe is accelerating, such that the velocity at which a distant galaxy recedes from the observer is continuously increasing with time.

The accelerating model of the galaxies predicts that galaxies should be getting farther apart now.

From the model presented in the graph critical model of the galaxies also predict that galaxies should be getting farther apart now.

Another model that predicts that galaxies should be getting farther apart now is coasting model.

These models can be seen in the graph as they increase proportional with time. That is the distance between galaxies increase with increase in time measured in years.

Thus, we can conclude that there  models ( accelerating, critical and coasting model) predicts the relative position of the galaxies from us.

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Answer:

Stay the same

Explanation:

Since, friction is negligible:

Initial Momentum = Final Momentum

Initial KE = Final KE

m1 * v1 = m2 * v2

When m increases v decreases.

The momentum and kinetic energy remain the same if you drop paper clips into an open cart rolling along a straight horizontal track with negligible friction.

Between two surfaces that are sliding or attempting to slide over one another, there is a force called friction. For instance, friction makes it challenging to push a book down the floor. Friction always moves an object in a direction that is counter to the direction that it is traveling or attempting to move.

Given:

The paperclips into an open cart rolling along a straight horizontal track with negligible friction,

Calculate the momentum, Since friction is negligible,

Initial Momentum = Final Momentum

Initial Kinetic Energy = Final Kinetic Energy

m₁ × v₁ = m₁  × v₂

When m increases, v decreases,

Thus, momentum will remain the same.

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Surface tension is the energy required to increase the surface area of a liquid.  Option (b)

Surface tension is the propensity of liquid surfaces at rest to shrink to the smallest feasible surface area. Surface tension permits items with a higher density than water, such as razor blades and insects (such as water striders), to float on the water's surface without being immersed.

Surface tension at liquid-air contacts is caused by the higher attraction of liquid molecules to each other (owing to cohesion) than to air molecules (due to adhesion).There are two main systems at work. The first is an inward strain on the surface molecules, which causes the liquid to constrict.

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