1. Earth releases about 44-46 Tw of heat, in fact heat can be converted into
other forms of energy that follows the law of conservation of energy. At present
a part of electrical energy in the Philippines is derived from electrical energy.
Briefly explain why our country cannot depend on this alternative source of
energy alone.
​

Answer:

Antonie van Leeuwenhoek

Explanation:

Answer:

biking to school

Explanation:

plato

The break shot speed of the player is determined as 96.5 ft/s.

use the following kinematic equation to determine the time of motion of the player.

h = vt + ¹/₂gt²

h = 0 + ¹/₂gt²

h = ¹/₂gt²

t = √(2h/g)

t = √(2 x 2.75/32.17)

t = 0.171 s

vx = x/t

vx = 16.5 ft / 0.171 s

vx = 96.5 ft/s

Thus, the break shot speed of the player is determined as 96.5 ft/s.

Learn more about break shot speed here: https://brainly.com/question/8852339

#SPJ1

Answer:

B and D

Explanation:

Answer:

It is B. inherits all the traits from its parent

And D. is identical to the parent's structure

Explanation:

Hope this helped have an amazing day!

Given,

The mass of the car moving east, m=1420 kg

The mass of the car moving south, M=1880 kg

The velocity of the car moving east, u₁=17.0 m/s

The velocity of the car moving south, u₂=-15.0 m/s

Here we assume that the eastward direction is the positive x-direction and the southward direction is the negative y-direction.

From the law of conservation of momentum, the momentum is conserved in both directions simultaneously and independently.

Considering the conservation of momentum in the x-direction,

Where v_x is the x-component of the final velocity of the two cars.

On substituting the known values,

Considering the conservation of momentum in the y-direction,

Where v_y is the y-component of the final velocity of the cars.

On substituting the known values,

A.

The magnitude of the velocity of the cars tight after the collision is given by,

On substituting the known values,

Thus the magnitude of the velocity of the cars right after the collision is 11.25 m/s

B.

The direction of the cars right after the collision is given by,

On substituting the known values,

Thus the direction of the cars right after the collision is -49.4°. That is 49.4° south of the east.

C.

The total kinetic energy of the system is before the collision is

On substituting the known values,

The kinetic energy of the system of two cars after the collision is,

Thus the kinetic energy lost during the collision is,

On substituting the known values,

Thus the total kinetic energy lost during the collision is 207.5 kJ

The tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.

To calculate the total displacement of the tank division, we need to find the vector sum of the two legs of their journey.

We can see that the tank division travelled 30 miles to the west (W30) and then 70 miles to the north (N70), so their total displacement is the vector sum of these two legs.

To add vectors, we need to break them down into their horizontal and vertical components.

For the first leg, the tank division travelled 30 miles to the west, so its horizontal component is -30 (since it's to the left of the base) and its vertical component is 0 (since it didn't travel up or down).

For the second leg, the tank division travelled 70 miles to the north, so its horizontal component is 0 (since it didn't travel left or right) and its vertical component is 70 (since it travelled directly north).

Now we can add these components to get the total displacement:

Horizontal component = -30 + 0 = -30

Vertical component = 0 + 70 = 70

So the total displacement is a vector with a horizontal component of -30 and a vertical component of 70.

We can use the Pythagorean theorem to find the magnitude of this vector:

|displacement| = √((-30)² + 70²) ≈ 75.9 miles

And we can use trigonometry to find the direction of this vector:

\(\theta = tan^{-1}\dfrac{70} { -30}\)

θ ≈ -67.4°

So the tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.

To know more about displacement follow

https://brainly.com/question/11924106

#SPJ9

(a) The maximum acceleration the car can have without causing the cup to slide is 1.96 m/s².

(b) The smallest amount of time in which the person can accelerate the car from rest to the final speed is 12.25 seconds.

The maximum acceleration the car can have without causing the cup to slide is calculated as follows;

For the car not to slide, the applied force must equal the force of friction, so the that the acceleration of the car is zero.

F - Ff = ma

F - Ff = 0

F = Ff

ma = μmg

a = μg

where;

a = 0.2 x 9.8 m/s²

a = 1.96 m/s²

The smallest amount of time in which the person can accelerate the car from rest to the final speed is calculated as follows;

v = u + at

v = 0 + at

t = v/a

t = (24 m/s) / (1.96)

t = 12.25 s

Learn more about maximum acceleration here: https://brainly.com/question/20595261

#SPJ1

Answer:

B. over the symbol.

Explanation:

vectors are represented with a symbol carrying an arrow head with also indicates direction

Answer:

The angular acceleration of CD player is \(13.93\ rad/s^2\).

Explanation:

Initial angular speed of a CD player is 0 and final angular speed is 41.8 rad/s. Time to change the angular speed is 3 s.

It is required to find the angular acceleration. The change in angular speed of the CD player divided by time taken is called its angular acceleration. It can be given by :

\(a=\dfrac{\omega_f-\omega_i}{t}\\\\a=\dfrac{41.8-0}{3}\\\\a=13.94\ rad/s^2\)

So, the angular acceleration of CD player is \(13.93\ rad/s^2\).

The minimum time necessary to pull out Margo is 2.64 seconds.

Given the data in the question;

There are two forces acting on Margo, as shown in the image below, the rope Tension acting upward and the force of gravity acting downward.

From Newton's second law of motion:

\(F = m*a\)  

where F is the Force acting on the body, m is the mass and a is the acceleration.

Also, \(F = T - mg\)

So, \(T - mg = ma\)

We know that the value of "g" gravitation due to gravity is \(9.81m/s^2\) and \(1Newton = 1 kg.m/s^2\)

We substitute in our values to find "a"

\(755 kg.m/s^2 - ( 70.0kg*9.81m/s^2) = (70kg * a )\)

\(755 kg.m/s^2 - 686.7 kg.m/s^2 = (70kg * a )\)

\(68.3kg.m/s^2 = (70kg * a )\)

\(a = \frac{68.3kg.m/s^2}{70kg}\)

\(a = 0.9757 m/s^2\)

Now, we set \(v_0 = 0\) to get the minimum time required

From the second equation of motion:

\(s = v_0t + \frac{1}{2} at^2\)

Since \(v_0 = 0\)

\(s = \frac{1}{2} at^2\)

We make time "t", the subject of the formula

\(t = \sqrt{\frac{2s}{a} }\)

We substitute in our values

\(t = \sqrt{\frac{2*3.4m}{0.9757m/s^2} }\)

\(t = 2.63995 s\\\\t = 2.64s\)

Therefore, the minimum time necessary to pull out Margo is 2.64 seconds.

Learn more; https://brainly.com/question/12977552?referrer=searchResults  

Answer:

the time taken t is 9.25 minutes

Explanation:

Given the data in the question;

The initial charge on the supercapacitor = 2.1 × 10³ mV = 2.1 V

now, every minute, the charge lost is 9.9 %  

so we need to find the time for which the charge drops below 800 mV or 0.8 V

to get the time, we can use the formula for compound interest in basic mathematics;

A = P × ( (1 - r/100 )ⁿ

where A IS 0.8, P is 2.1, r is 9.9

so we substitute

0.8 = 2.1 × ( 1 - 0.099 )ⁿ

0.8/2.1 = 0.901ⁿ

0.901ⁿ = 0.381

n = 9.25 minutes

Therefore, the time taken t is 9.25 minutes

Explanation:

41.3 kilocalories = 172 799.2 joules

\(hope \: it \: will \: help\)

The normal stress in portion AB is σ₁ = 79.48 psi and the normal stress in portion BC is σ₂ = 47.69 psi.

We can start by drawing a free body diagram of the polystyrene rod and identifying the unknown reactions at A and C:

|-------- 6 kips --------|

          A                       C

          |-----------------------|

          |                       |

          |          BC           |

          |          σ₂           |

          |          L₂           |

          |                       |

          |-----------------------|

          |                       |

          |          AB           |

          |          σ₁           |

          |          L₁           |

          |                       |

          |-------- 6 kips --------|

Where σ₁ and σ₂ are the normal stresses in portions AB and BC of the rod, respectively.

Next, we can use the equations of static equilibrium to solve for the reactions at A and C. Taking moments about point A, we have:

6 kips * L₂ + 6 kips * (L₁ + L₂) - Cz = 0

where z is the distance from A to the line of action of the force at C. Since the rod is symmetric about the midpoint of portion BC, we can take z = L₁ + L₂/2. Substituting the given values, we have:

6 kips * L₂ + 6 kips * (L₁ + L₂) - C(L₁ + L₂/2) = 0

Solving for C, we get:

C = (12 kips * L₁ + 18 kips * L₂) / (3 L₁ + 2 L₂)

Taking vertical forces, we have:

A + C - 12 kips - 6 kips - 6 kips = 0

Substituting the value of C we just obtained, we get:

A = 12 kips - C - 6 kips - 6 kips = 0.4 kips

Therefore, the reactions at A and C are A = 0.4 kips and C = 11.6 kips.

Next, we can calculate the normal stresses in each portion of the rod. Using the formula for normal stress, we have:

σ₁ = P₁ / A₁ = A₂ / A₁ * σ₂

where P₁ and A₁ are the axial load and cross-sectional area of portion AB, and A₂ is the cross-sectional area of portion BC. Since the rod is of uniform diameter and the areas of the cylindrical portions are proportional to their lengths, we have:

A₂ / A₁ = L₂ / L₁

Substituting this into the equation for σ₁, we get:

σ₁ = (L₂ / L₁) * σ₂

Substituting the given values, we have:

σ₂ = P₂ / A₂ = 6 kips / (π/4 * (0.6 in)^2) = 47.69 psi

σ₁ = (2.5 ft / 1.5 ft) * 47.69 psi = 79.48 psi

Therefore, the normal stress in portion AB is σ₁ = 79.48 psi and the normal stress in portion BC is σ₂ = 47.69 psi.

Learn more about polystyrene rod:

https://brainly.com/question/8106998

#SPJ4

The tax rate you will pay is displayed in tax brackets for each category of taxable income.

Thus, For instance, in 2022, the first $10,275 of your taxable income is subject to the lowest tax rate of 10% if you are single.

Up until the maximum amount of your taxable income, the following portion of your income is taxed at a rate of 12%.

As taxable income rises, the tax rate rises under the progressive tax system. Overall, this has the result that taxpayers with higher incomes often pay a greater rate of income tax than taxpayers with lower incomes.

Thus, The tax rate you will pay is displayed in tax brackets for each category of taxable income.

Learn more about Tax rate, refer to the link:

https://brainly.com/question/30629449

#SPJ1

Answer:

50N

Explanation:

F =ma

m=10kg and a=5m\s^2

f= (10)*5

f= 50 N

Answer:

7×160=1120kj so,1120kj=1.12j.

Explanation:

Energy is equal to force times distance,so we add all the distance and we multiply them with the total force of the spring to get the answer. However, the answer is in kilojoules so we have to change it in to joules by dividing the answer into joules by 1000..

Answer:

number of electrons = 2.18*10^18 e

Explanation:

In order to calculate the number of electrons that move trough the second wire, you take into account one of the Kirchoff's laws. All the current that goes inside the junction, has to go out the junction.

Then, if you assume that the current of the wire 1 and 3 go inside the junction, then, all this current have to go out trough the second junction:

\(i_1+i_3=i_2\)                 (1)

i1 = 0.40 A

i2 = 0.75 A

you solve the equation i3 from the equation (1):

\(i_3=i_2-i_1=0.75A-0.40A=0.35A\)

Next, you take into account that 1A = 1C/s = 6.24*10^18

Then, you have:

\(0.35A=0.35\frac{C}{s}=0.35*\frac{6.24*10^{18}e}{s}=2.18*10^{18}\frac{e}{s}\)

The number of electrons that trough the wire 3 is 2.18*10^18 e/s

Answer:

Step 1: We make the assumption that 125 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$.

Step 3: From step 1, it follows that $100\%=125$.

Step 4: In the same vein, $x\%=125$.

Step 5: This gives us a pair of simple equations:

$100\%=125(1)$.

Explanation:

The difference in its Kinetic energy of the mass is 3 (¹/₂mV₁² ).

The difference in the kinetic energy of the mass is calculated by applying the following formula as shown below.

ΔK.E = K.Ef - K.Ei

where;

The difference in its Kinetic energy of the mass is calculated as;

ΔK.E = ¹/₂m [ (2V₁²) - ( V₁²) ]

ΔK.E = ¹/₂m[ (4V₁²) - ( V₁²) ]

ΔK.E =  ¹/₂mV₁²[4  - 1]

ΔK.E =  3 (¹/₂mV₁² )

Learn more about change in kinetic energy here: https://brainly.com/question/1932411

#SPJ1

Given:

The focal length of the concave lens is f = -5 cm

The object distance from the lens is u = -15 cm

Required:

Ray diagram

Magnification

Explanation:

The rules related to incident ray and reflected ray are:

1) Any incident ray moving parallel to the principal axis will pass through focus after reflection.

2) Any incident ray passing through the focus will move parallel to the principal axis after reflection.

3) Incident ray passing through the optical center will reflect undeviated.

The ray diagram is shown below

Here, yellow lines represent incident rays passing parallel to the principal axis and the reflected ray passing through the focus.

The maroon line shows the incident ray passing through the optical center and the undeviated reflected ray.

The green color is the object and image.

In order to find magnification, first, we need to calculate the image distance given as

The magnification will be

Final Answer: Thus, the magnification is 0.25 which means the size of the image is 0.25 times the object.

ωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωωZ?

Answer: 11.8 m/s

Explanation: Multiply the height, 1.20 m by 9.8. This is because on earth free falling objects have a speed of 9.8 m/s^2 downward.

Projectile motion is the curved path motion of a body launched into the air near the Earth's surface and having a horizontal velocity.

Reason:

Given parameter are;

Initial velocity of the skateboarder, v₁ = 5.4 m/s

Inclination of the track, above the horizontal, θ = 48°

Height of the end of the elevated track, h ≈ 0.40 m

Path of the skateboarder when she leaves the track = Path of a projectile

Required:

Maximum height H to which she rises above the end of the track.

Solution;

From v² = u² - 2·g·h, at the end of the track where;

h = 0.40 m

u = Initial velocity = 5.4

g = 9.81 m/s²

We have;

v₂² ≈ 5.4² - 2 × 9.81 × 0.40 = 21.312

At the maximum height, H, we have;

\(\displaystyle v__y\) = 0

Therefore, from \(\displaystyle v__y\)² = \(\displaystyle u__y\)² - 2·g·H, where;

\(\displaystyle u__y\)² = 2·g·H

Which gives;

Therefore;

Learn more about projectile motion here:

https://brainly.com/question/12125940

First option is correct.Larry the Rock is going through Static Equilibrium.

In this situation, Larry is at rest and remains stationary despite the forces acting on him. While David and Pancho are exerting equal forces from opposite sides, their forces cancel each other out, resulting in a net force of zero. As a result, Larry does not move or experience any acceleration.

Static equilibrium occurs when an object's forces and torques balance each other, leading to a stable, balanced state. In this case, the forces exerted by David and Pancho are equal in magnitude and opposite in direction, creating a condition where the resultant force is zero. As a result, Larry remains in a state of rest, unable to experience any movement or acceleration.Therefore, the type of equilibrium that Larry the Rock is going through is Static Equilibrium.

For more such questions on Static Equilibrium

https://brainly.com/question/31818930

#SPJ8

(1/2)mv^2 = (1/2) * 100 * (2*3)^2 = 1800 [J]

The answers are 4. The distance from where the ball was kicked is 38.06 meters, 5. The speed of the ball 2.5 seconds after it was kicked is 13.82 m/s, and  6. The ball is 21.88 meters above the ground 2.5 seconds after it is kicked.

For more questions on speed

https://brainly.com/question/13943409

#SPJ8

The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.

Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.

Cost of operation for 10 hours a day;

Daily consumption = 3kW x 10 hours

Daily Consumption = 30kW

Since 1kWH = 79 francs;

Daily consumption amount = 30 x 79 francs

Daily consumption amount = 2,370 francs

Therefore, the monthly consumption (using 30days) will be;

2,370 francs x 30 = 71,100 francs

In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.

Learn more about power:https://brainly.com/question/25864308

#SPJ1

Assuming that 200 Mev of energy is released per fission of u235 , the mass of that undergoes fission reactor of power 1MW will be approximately will be the correct option is a i.e. 10^-2g.

The mass of the material that undergoes fission in a reactor with a power of 1 MW, you need to know the number of fissions that occur per second in the fission reactor. The power of a reactor is the rate at which energy is released by the fission reactions taking place inside it. The energy released per fission of uranium-235 is 200 MeV.

The relationship between power, energy, and time is given by the equation:

Power = Energy / Time

Rearranging this equation to solve for the number of fissions per second gives:

Number of fissions/second = Power / (Energy/fission)

Putting the values from the problem gives:

Number of fissions/second = 1 MW / (200 MeV/fission) = 5 x 10^22 fissions/second

Since the mass of uranium-235 is approximately 235.04 g/mol, the mass of the material that undergoes fission in the reactor is approximately:

Mass = (Number of fissions/second) x (235.04 g/mol) / (6.022 x 10^23 fissions/mol) = 3.93 x 10^-2 g

So, the mass of the material that undergoes fission in the reactor is approximately 3.93 x 10^-2 g, which corresponds to the answer choice "a. 10^-2g".

To know more about fission reactor please refer: https://brainly.com/question/23276812

#SPJ4

Answer:

V2 = (V1 - u) / (1 - V1 u / c^2)

V1 = speed of ship in observer frame = .99 c    to right

u = speed of frame 2 = -.99 c   to left relative to observer

V2 = speed of V1 relative to V2

V2 = (.99 - (-.99 ) / (1 - .99 (-.99)) c

V2 = 1.98 / (1 + .99^2) c = .99995 c