Answer:
1) a. Rs 440.
1) b. Rs 795.
2) a.Rs 145.
2) b. Rs 180.
Step-by-step explanation:
1) a.
Given,
Marked Price = Rs 480
Discount Amount = Rs 40
Selling Price = ?
Now,
Selling Price = Marked Price - Discount Amount
= Rs 480 - Rs 40 = Rs 440.
1) b.
Given,
Marked Price = Rs 870
Discount Amount = Rs 75
Selling Price = ?
Now,
Selling Price = Marked Price - Discount Amount
= Rs 870 - Rs 75 = Rs 795.
2) a.
Given,
Cost Price = Rs 120
Profit = 25
Selling Price = ?
Now,
Selling Price = Cost Price + Profit
= Rs 120 + Rs 25 = Rs 145.
2) b.
Given,
Selling Price = Rs 200
Profit = Rs 20
Cost Price = ?
Now,
Cost Price = Selling price - Profit
= Rs 200 - Rs 20 = Rs 180.
Are the experimental probabilities after 300 trials closer to the theoretical probabilities?
After 300 trials, the experimental probabilities may not align perfectly with the theoretical probabilities. However, with more trials, the experimental probabilities tend to converge towards the theoretical probabilities for closer alignment.
To examine whether experimental probabilities after 300 trials align closely with theoretical probabilities, let's consider an example of flipping a fair coin.
Theoretical probability: When flipping a fair coin, the theoretical probability of obtaining heads or tails is 0.5 each. This assumes that the coin is unbiased and has an equal chance of landing on either side.
Experimental probability: After conducting 300 trials of flipping the coin, we record the outcomes and calculate the experimental probabilities. Let's assume that heads occurred 160 times and tails occurred 140 times.
Experimental probability of heads: 160/300 = 0.5333
Experimental probability of tails: 140/300 = 0.4667
Comparing the experimental probabilities to the theoretical probabilities, we can observe that the experimental probability of heads is slightly higher than the theoretical probability, while the experimental probability of tails is slightly lower.
In this particular example, the experimental probabilities after 300 trials do not align perfectly with the theoretical probabilities. However, it is important to note that these differences can be attributed to sampling variability, as the experimental outcomes are subject to random fluctuations.
To draw a more definitive conclusion about the alignment between experimental and theoretical probabilities, a larger number of trials would need to be conducted. As the number of trials increases, the experimental probabilities tend to converge towards the theoretical probabilities, providing a closer alignment between the two.
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The question probable may be:
Do experimental probabilities after 300 trials tend to align closely with theoretical probabilities? Consider an example scenario and calculate both the theoretical and experimental probabilities to determine if they are close.
Round 9,526,789 to the nearest hundred thousand
Answer:
9,500,000. the ten thousands place has a two, which is one less than 3, rendering the 6 in the thousand's place ineffective
Step-by-step explanation:
4 or less let it rest, 5 or more let it score
If Jonny was 21 years old . He is 3 times as old as Becky determined Becky’s age
Answer:
Becky is 7 years old.
Step-by-step explanation: Let b - Becky's age ; Equation - 3b = 21. Divide both size by 3 to isolate the variable.
Answer:
Becky's 7 seven years old
Step-by-step explanation:
If 21 = 3x
x = 21/3
x = 7
Hope this helps :)
Pls brainliest...
find the area of this figure (50 points)
Answer:
\(A_{total} = 14\ in^2\)
Step-by-step explanation:
Step 1: Determine the area of the left rectangle
We can tell that the total shape seems like two rectangles glued together. We can separate the left rectangle and determine the area of it and then determine the area of the right rectangle and combine them. Lets first solve the left rectangle.
\(A = l * w\)
\(A_{left\ rectangle} = 2\ in * 4\ in\)
\(A_{left\ rectangle} = 8\ in^2\)
Step 2: Determine the area of the right rectangle
\(A = l * w\)
\(A_{right\ rectangle} = 3\ in * 2\ in\)
\(A_{right\ rectangle} = 6\ in^2\)
Step 3: Determine the total area
\(A_{total}=A_{left\ rectangle} + A_{right\ rectangle}\)
\(A_{total} = 8\ in^2 + 6\ in^2\)
\(A_{total} = 14\ in^2\)
Answer: \(A_{total} = 14\ in^2\)
Area of right rectangle
LB2(3)6in²Area of left rectangle
4(2)8in²Total
6+814in²A school cafeteria sold 1,280 slices of pizza the first week, 640 the second week, and 320 the third week. If this pattern continues, in what week will the cafeteria sell 40 slices? Explain how you got your answer.
If you look at the question, You would see a pattern. That pattern is the amount of slices in one week is divided by 2 the next week. So on the fourth week you would do 320/2 and get 160. if you keep carrying on the pattern yourself, you would do: 160/2 = 80. 80/2 = 40. And there's your answer. week 4 we had 160 slices sold. week 5 80 slices sold. Week 6 40 slices sold
Simplify this into your own words if you have to
The constraints of a problem are listed below. What are the vertices of the feasible region? 2x+3y≥12 5x+2y≥15 x ≥ 0 y ≥ 0
The vertices of the feasible region are (0 , 15/2) , (21/11 , 19/11) and (6 , 0)
Given, the constraints of a problem
2x+3y≥12
5x+2y≥15
x ≥ 0
y ≥ 0
On solving the equations, we get
( 2x + 3y ≥ 12 ) × 2
( 5x + 2y ≥ 15 ) × 3
4x + 6y ≥ 24
15x + 6y ≥ 45
On subtracting, we get
11x ≥ 21
x ≥ 21/11
x = 21/11
On putting the value of x, we get
42/11 + 3y = 12
y = 19/11
Hence, the vertices of the feasible region are (0 , 15/2) , (21/11 , 19/11) and (6 , 0)
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Solve (x+1)2 =13/4 using the square root property
Answer:
Starting with the equation:
(x + 1)^2 = 13/4
We can use the square root property, which states that if a^2 = b, then a is equal to the positive or negative square root of b.
Taking the square root of both sides, we get:
x + 1 = ±√(13/4)
Simplifying under the radical:
x + 1 = ±(√13)/2
Now we can solve for x by subtracting 1 from both sides:
x = -1 ± (√13)/2
Therefore, the solutions to the equation are:
x = -1 + (√13)/2 or x = -1 - (√13)/2
Step-by-step explanation:
a textbook store sold a combined total of 412 chemisty and physics textbooks in a week the number of chemeatry textbooks sold was three times the number of physics textbooks sold how many textbooks of each were sold
Using a system of equations, the number of each textbook sold in the week is as follows:
Physics = 103Chemistry = 309.What is a system of equations?To determine the number of each textbook sold during the week, we can set them as a system of equations.
A system of equations is called simultaneous equations because two or more equations are solved concurrently.
In this situation, the equation of chemistry textbooks is 3y while the equation of physics textbooks is y, and the total number sold is 412.
Solving the equations:
Let the number of chemistry textbooks = 3y
Let the number of physics textbooks = y
The number of textbooks sold for the week = 3y + y = 412
3y + y = 412
4y = 412
y = 103
Physics textbooks sold = 103
Chemistry textbooks sold = 3(103) = 309
Check:
3y + y = 412
3(103) + 103 = 412
309 + 103 = 412
412 = 412
Thus, we can conclude that 103 physics and 309 chemistry textbooks were sold using simultaneous equations.
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You are dressing a mannequin for a clothingstore display. You have 4 types of shoes, 5necklaces, 10 tops, and 7 bottoms to choosefrom. How many distinct outfits can youcréate? >
Given:
• Types of shoes = 4
,• Number if necklaces = 5
,• Number of tops = 10
,• Number of bottoms = 7
Let's find how many distinct outfits you can create.
To find the number of distinct outfits you can create, we have:
\(\begin{gathered} n=4*5*10*7 \\ \\ n=1400 \end{gathered}\)Therefore, the number of distinct outfits you can create is 1400.
ANSWER:
1400
1. suppose two fair 6-sided dice, each numbered {1,2,3,4,5,6} are rolled. let m be the maximum of the two dice. find e(m) and v ar(m).
For two fair 6-sided diced that are rolled, the expected value of maximum (E(m)) is 3.5 and variance of maximum (Var(m)) is 2.91.
To find the expected value of the maximum of two dice rolls, we need to find the sum of the products of each maximum value and its probability of occurring.The maximum value of each combination of two dice rolls can range from 2 to 6, with the following probabilities:
Maximum of 2: 1/36
Maximum of 3: 2/36
Maximum of 4: 3/36
Maximum of 5: 4/36
Maximum of 6: 5/36
So the expected value (E(m)) can be calculated as:
E(m) = (2 × 1/36) + (3 × 2/36) + (4 × 3/36) + (5 × 4/36) + (6 × 5/36)
E(m) = 3.5
To find the variance of the maximum (Var(m)), we need to use the formula for variance of a discrete random variable:
Var(m) = E((m - E(m))²)
Var(m) = E((m - 3.5)²)
Var(m) = (2 - 3.5)² × 1/36 + (3 - 3.5)² × 2/36 + (4 - 3.5)² × 3/36 + (5 - 3.5)² × 4/36 + (6 - 3.5)² × 5/36
Var(m) = 2.91
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Triangle ABC is dilated about the origin to create triangle A′B′C′. Triangle ABC with vertices at A negative 6 comma negative 4, B negative 2 comma negative 4, and C negative 2 comma 2 and triangle A prime B prime C prime with vertices at A prime negative 9 comma negative 6, B prime negative 3 comma negative 6, and C prime negative 3 comma 3. Determine the scale factor used to create the image. two fifths 1.5 one half 2.5
Answer:
1.5
Step-by-step explanation:
To determine the scale factor used to create the image, we can compare the distances between corresponding vertices of the two triangles.
Let's start by finding the distance between A and B in triangle ABC:
distance AB = sqrt[(x_B - x_A)^2 + (y_B - y_A)^2]
= sqrt[(-2 - (-6))^2 + (-4 - (-4))^2]
= sqrt[16 + 0]
= 4
Now let's find the distance between A' and B' in triangle A'B'C':
distance A'B' = sqrt[(x_B' - x_A')^2 + (y_B' - y_A')^2]
= sqrt[(-3 - (-9))^2 + (-6 - (-6))^2]
= sqrt[36 + 0]
= 6
To find the scale factor, we can divide the distance between corresponding vertices in the image triangle by the distance between the corresponding vertices in the original triangle:
scale factor = distance A'B' / distance AB
= 6 / 4
= 1.5
Therefore, the scale factor used to create the image is 1.5.
To find the scale factor of a dilation, one can divide a side length of the enlarged shape by the corresponding side length of the original shape. In this case, the scale factor from triangle ABC to A'B'C' is 6/4 = 1.5.
Explanation:In Mathematics, we can find the scale factor of a dilation by comparing corresponding distances in the original shape and its image. The scale factor can be found by dividing a side length of the enlarged shape (triangle A′B′C′) by the corresponding side length of the original shape (triangle ABC).
For example, the distance between points A and B in the original triangle ABC is 4 units (-2 - (-6) = 4), and the distance between points A′ and B′ in the enlarged triangle A′B′C′ is 6 units (-3 - (-9) = 6). So, the scale factor from ABC to A'B'C' is 6/4 = 1.5.
Therefore, the scale factor used to create the image of triangle A'B'C' from triangle ABC is 1.5.
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pls help!! Thank you!
Answer:
C
Step-by-step explanation:
\(\left(\frac{f}{g} \right)(x)=\frac{f(x)}{g(x)} \\ \\ \frac{f(x)}{g(x)}=\frac{\sqrt[3]{2x}}{2x+1}\)
The denominator cannot equal 0, so:
\(2x+1 \neq 0 \implies x \neq -\frac{1}{2}\)
You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 30 night students, and the sample mean GPA is 2.35 with a standard deviation of 0.46. You sample 25 day students, and the sample mean GPA is 2.58 with a standard deviation of 0.47. Test the claim using a 5% level of significance. Assume the sample standard deviations are unequal and that GPAs are normally distributed. Give answer to exactly 4 decimal places.
Hypotheses:
sub(H,0):sub(μ,1) = sub(μ,2)
sub(H,1):sub(μ,1) â sub(μ,2)
**I'm not sure how to calculate this in excel***
Enter the test statistic - round to 4 decimal places.
A=
Enter the p-value - round to 4 decimal places.
A=
Answer:
Test statistic t = -1.8246
P-value = 0.0737
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that the mean GPA of night students is different from the mean GPA of day students.
Step-by-step explanation:
This is a hypothesis test for the difference between populations means.
The claim is that the mean GPA of night students is different from the mean GPA of day students.
Then, the null and alternative hypothesis are:
\(H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0\)
The significance level is 0.05.
The sample 1, of size n1=30 has a mean of 2.35 and a standard deviation of 0.46.
The sample 2, of size n2=25 has a mean of 2.58 and a standard deviation of 0.47.
The difference between sample means is Md=-0.23.
\(M_d=M_1-M_2=2.35-2.58=-0.23\)
The estimated standard error of the difference between means is computed using the formula:
\(s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{0.46^2}{30}+\dfrac{0.47^2}{25}}\\\\\\s_{M_d}=\sqrt{0.007+0.009}=\sqrt{0.016}=0.1261\)
Then, we can calculate the t-statistic as:
\(t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{-0.23-0}{0.1261}=\dfrac{-0.23}{0.1261}=-1.8246\)
The degrees of freedom for this test are:
\(df=n_1+n_2-2=30+25-2=53\)
This test is a two-tailed test, with 53 degrees of freedom and t=-1.8246, so the P-value for this test is calculated as (using a t-table):
\(\text{P-value}=2\cdot P(t<-1.8246)=0.0737\)
As the P-value (0.0737) is greater than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that the mean GPA of night students is different from the mean GPA of day students.
The school principals has a Binet of $9.00 for making repairs to one of the play grounds she plans to cove the surface of the playground with soft rubber tiles.With money left over she will purchase new equipment.
The t
Effective:
Thirty children suffered broken bones last year because of outdated playground equipment.
Studies show that safe playground equipment helps promote children's development.
Tax money spent on our children's safety is tax money well spent.
New playground equipment can be used to enhance our children's education.
Ineffective:
Other schools in the area have new playground equipment.
The nurse's office is conveniently located next to the playground.
Here, we have,
The education is a discipline that is concerned with methods of teaching and learning in schools or school-like environments as opposed to various non-formal and informal means of socialization (e.g., rural development projects and education through parent-child relationships).
Education can be thought of as the transmission of the values and accumulated knowledge of a society. In this sense, it is equivalent to what social scientists term socialization or enculturation.
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complete question:
In a speech about the importance of installing new and safer school playground equipment, which reasons most effectively express the speaker's viewpoint?
label as
Effective or Ineffective
Thirty children suffered broken bones last year because of outdated playground equipment.
Studies show that safe playground equipment helps promote children's development.
New playground equipment can be used to enhance our children's education.
Other schools in the area have new playground equipment.
Tax money spent on our children's safety is tax money well spent.
The nurse's office is conveniently located next to the playground.
divide the complex number. show all steps. reduce if possible.
step 1
Determine the complex conjugate of the denominator
the complex conjugate of the denominator is (6-4i)
step 2
Multiply the numerator and denominator of the fraction by the complex conjugate of the denominator
we have
\(\frac{2-5i}{6+4i}\cdot\frac{6-4i}{6-4i}\)Multiply
\(\frac{2-5i}{6+4i}\cdot\frac{6-4i}{6-4i}=\frac{(12-8i-30i+20i^2)}{36-16i^2}\)Remmeber that
i^2=-1
substitute
\(\begin{gathered} \frac{(12-8i-30i-20)}{36+16} \\ \\ \frac{-8-38i}{52} \\ \\ -\frac{8}{52}-\frac{38}{52}i \end{gathered}\)Simplify
\(-\frac{2}{13}-\frac{19}{26}i\)
How many solutions does this system have? no solutions one unique solution O O two solutions O or an infinite number of solutions
Answer:
no solutions
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
equation of blue line is y = x + 2 , in slope- intercept form
with slope m = 1
equation of red line is y = x - 3 , in slope- intercept form
with slope m = 1
• Parallel lines have equal slopes
then the blue and red lines are parallel.
the solution to the system is at the point of intersection of the 2 lines
since the lines are parallel then they do not intersect each other.
thus the system shown has no solution.
Help me please I need help x^2 - 8x + 16
The set of factors used to factor the given trinomial are -4 and -4. Therefore, option C is the correct answer.
The given trinomial is x²-8x+16.
Factors of 16 Sum of factors
-1 and -16 -1+(-16)=-17
-2 and -8 -2+(-8)=-10
-4 and -4 -4+(-4)=-8
The set of factors would used to factor the trinomial are -4 and -4.
Therefore, option C is the correct answer.
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Help
Pls
Ion know the answers
Answer:
-3
Step-by-step explanation:
15. The cost of beverages in a vending machine is shown.
Beverages
Cost
1
2
$1.25
$2.50
$3.75
3
Answer:
I can't understand what you have written and what to find
A bag contains 10 blue marbles, 7 white marbles, 6 red marbles, and 2 Green marbles. what is the probability of randomly selecting the blue marble?
Answer:
Step-by-step explanation:
Number of blue marbles = 10
Number of white marbles = 7
Number of Red marbles = 6
Number of Green marbles = 2
Total marbles = 10 + 7 + 6 + 2 = 25
Probability of selecting the blue marble = 10/25 = 2/5
if you help me i`ll give you brainlest
Answer:
6*7=42
8*6=48
6*3=18
6*12=72
6*5=30
6*9=54
10*6=60
6*6=36
6*2=12
6*11=66
4*6=24
1*6=6
6*6=36
6*7=42
6*2=12
8*6=48
Step-by-step explanation:
Answer:
42, 48, 18, 72, 30, 72, 60, 30, 18, 66, 24, 6, 30 , 6 , 42, 12 66,48,60, 30, 18, 72, 52, 24 if this helped give brainlest please
Step-by-step explanation:
The city is building a rectangular parking lot. The city wants the width of the parking lot to be 5 yards the area of the parking lot to be more than 30 square yards all the city employees must park there write an inequality that describes a possible lengths in yards of the parking lot
An inequality that describes a possible length in yards of the rectangular parking lot is L < 6.
How to calculate the area of a rectangle?Mathematically, the area of a rectangle can be calculated by using this formula:
A = LW
Where:
A represents the area of a rectangle.W represents the width of a rectangle.L represents the length of a rectangle.Since the city wants the width of the parking lot to be 5 yards and the area of the rectangular parking lot to be more than 30 square yards, an inequality that models a possible lengths of the rectangular parking is giving by;
A > LW
30 > 5L
Dividing both sides of the inequality by 5, we have:
6 > L
L < 6
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Wendi got 15 out of 20 questions correct on her English quiz and 9 out of 10 question correct on her math quiz which quiz did she do better on
Answer:
she did better on her math quiz
Step-by-step explanation:
15/20<9/10
15/20<18/20
Simple but effective
Let me know if this helps
The volume of a tree stump can be modeled by considering it as a right cylinder. Lauren measures it’s height as 0.7ft and it’s radius as 20in find the volume of the stump in cubic inches. Round your answer to the nearest tenth if necessary
The volume of the tree stump is approximately 1005.3 cubic inches when rounded to the nearest tenth.
To calculate the volume of the tree stump, we can use the formula for the volume of a cylinder, which is given by:
Volume = π * r^2 * h
Given:
Radius (r) = 20 inches
Height (h) = 0.7 feet
First, let's convert the height from feet to inches since the radius is already in inches. There are 12 inches in 1 foot, so:
Height (h) = 0.7 feet * 12 inches/foot = 8.4 inches
Now, we can substitute the values into the volume formula:
Volume = π * (20 inches)^2 * 8.4 inches
Calculating the volume:
Volume = 3.14159 * (20 inches)^2 * 8.4 inches
≈ 3.14159 * 400 inches^2 * 8.4 inches
≈ 1005.3096 cubic inches
Rounding the volume to the nearest tenth:
Volume ≈ 1005.3 cubic inches
Therefore, the volume of the tree stump is approximately 1005.3 cubic inches when rounded to the nearest tenth.
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Solve for x in the following 4/2.6=5/x
The value of X is 3.25
Look at the attached picture
Hope it will help you
Good luck on your assignment
Using the quadratic formula to solve x2 = 5 – X, what are the values of x? -1 + 21 2 -12/19/ 2 5+21 2 1+ 191 2
Answer:
\( {x}^{2} = 5 - x \\ { \tt{ {x}^{2} + x - 5 = 0 }} \\ \\ { \bf{x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} }} \\ \\ { \tt{x = \frac{ - 1± \sqrt{21} }{2} }} \\\)
Help! I'll give brainliest to first correct answer.
1 to A
2 to C
3 to B
4 to D
and that's all
What is 12 to the power of negative 9 times 12 to the power of 3
Answer: 3.34897977 -7
Step-by-step explanation:
Ivan also decides to try putting together the “Multiples of 3” set from the numbers sitting around. How can he know if a number is a multiple of 3? (Hint: Build a lot of different multiples of 3. Then look at the sum of the digits of each number.
Multiples of 3 are: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, ...
The two digit numbers in that list above all have their digits adding to some other multiple of 3
1+2 = 31+5 = 61+8 = 92+1 = 32+4 = 62+7 = 93+0 = 33+3 = 63+6 = 9and so on.
Therefore, the rule is: If the digits add to a multiple of 3, then the original number is a multiple of 3.
8. What is the value of x in the diagram?
A
E
429
B
49
D
32°C
Answer:
D. \(10^{\circ}\)
Step-by-step explanation:
Let the measure of minor arc \(AE\) be \(\alpha\) and the measure of minor arc \(BD\) be \(\beta\).
Using the secant-secant theorem, \(\frac{\alpha-\beta}{2}=32 \implies \alpha-\beta=64^{\circ}\).
By the inscribed angle theorem, \(\alpha=84^{\circ}\).
Thus, \(\beta=20^{\circ}\).
By the inscribed angle theorem, \(x=10^{\circ}\).