Answers
Answer =Angle L and Angle Q
Related Questions
Help
This is big
Plsss
Answers
Answer:
The answer for this would be:
Sin P = Opp/Hyp
Sin P = 55/73
Answer = 55/73
Please mark my answer as brainliest for further answers :)1. Identify each of the following statements as true of false and explain your reasoning in full sentences. The domain of discourse is the integers.
(a) ∃x∀y(y > x)
(b) ∀y∃x(y > x)
(c) ∃x(x = 0 → x = 1)
2. Write the formal negation of the following statements. Your negation must not contain any explicit negation symbols.
(a) ∀x∃y(2 < x ≤ y)
(b) ∀y∃x(y > 0 → x ≤ 0)
3. Negate verbally:
(a) "All people weigh at least 100 pounds."
(b) "Somebody did not see any animals in the zoo"
4. If P and Q are predicates over some domain, and if it is true that∀x(P(x)∨ Q(x)), must ∀xP(x)∨∀xQ(x) also be true? Explain.
Answers
The domain of discourse is the integers is smaller integer
What is Integer?
A zero, a positive natural number, or a negative integer with a minus sign is an integer. The negative numbers are the additive inverses of their positive counterparts.
1.(a) ∃x∀y(y > x)
The statement is False
it is impossible to find a single integer x that has the property that all integer y are bigger that it. for any integer x, the integer y =x-1 is smaller
(b) ∀y∃x(y > x)
the statement is true for every integer y, we can find a integer x that is smaller, for example x=y-1
(c) ∃x(x = 0 → x = 1)
The statement is True
there exist x such that (x = 0, x=1). in this statement when we select x =1. this statement is true regardless of x not equal to 0 therefore this statement is true if x=1 when x=1
2. (a) ∀x∃y(2 < x ≤ y)
we know
∀xP(x)=∃y(P(x))
∃xP(x)=∃y(P(x))
now apply de morgan law
∃x∀(y)=2>x v x>y
(b) ∀y∃x(y > 0 → x ≤ 0)
we know that A-B = A V B
∀y∃x (Y<0 V X< 0)
∀y∃x (Y<0 : X< 0)
3.(a) Given : All people weigh at least 100 pounds.
The negation is : Some people weigh less than 100 pounds. ( All negates to some, at least negates to less than )
(b) The statement is : Somebody did not see any animals in the zoo.
Equivalently : Somebody see no animals in the zoo.
Negation : Everybody saw some animals in the zoo. ( Somebody negates to everybody, No animals negates to some animals )
4. P(x,y): x is friends with y.
Then the given translates to " For all x there is a person y and a person z such that if y and z are not the same people that x and y are friends and x and z are friends."
The given statement is False. For every person x, we can always find two distinct persons y and z such that x is friends with y and y is friends with z. But, we reach a contradiction when we consider the case when x has only one friend. Then for that particular person x, we can find a person y such that P(x,y) but we cannot find a person z such that P(x,z). Hence, in that case, the statement is FALSE.
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The Land of Nod lies in the monsoon zone, and has just two seasons, Wet and Dry. The Wet season lasts for 1/3 of the year, and the Dry season for 2/3 of the year. During the Wet season, the probability that it is raining is 3/4; during the Dry season, the probability that it is raining is 1/6. (a) I visit the capital city, Oneirabad, on a random day of the year. What is the probability that it is raining when I arrive? (b) I visit Oneirabad on a random day, and it is raining when I arrive. Given this information, what is the probability that my visit is during the Wet season? (c) I visit Oneirabad on a random day, and it is raining when I arrive. Given this information, what is the probability that it will be raining when I return to Oneirabad in a year's time? (You may assume that in a year's time the season will be the same as today but, given the season, whether or not it is raining is independent of today's weather.)
Answers
Answer:
Step-by-step explanation:
(a) To find the probability that it is raining when you arrive in Oneirabad on a random day, we need to use the law of total probability.
Let A be the event that it is raining, and B be the event that it is the Wet season.
P(A) = P(A|B)P(B) + P(A|B')P(B')
Given that the Wet season lasts for 1/3 of the year, we have P(B) = 1/3. The probability that it is raining during the Wet season is 3/4, so P(A|B) = 3/4.
The Dry season lasts for 2/3 of the year, so P(B') = 2/3. The probability that it is raining during the Dry season is 1/6, so P(A|B') = 1/6.
Now we can calculate the probability that it is raining when you arrive:
P(A) = (3/4)(1/3) + (1/6)(2/3)
= 1/4 + 1/9
= 9/36 + 4/36
= 13/36
Therefore, the probability that it is raining when you arrive in Oneirabad on a random day is 13/36.
(b) Given that it is raining when you arrive, we can use Bayes' theorem to calculate the probability that your visit is during the Wet season.
Let C be the event that your visit is during the Wet season.
P(C|A) = (P(A|C)P(C)) / P(A)
We already know that P(A) = 13/36. The probability that it is raining during the Wet season is 3/4, so P(A|C) = 3/4. The Wet season lasts for 1/3 of the year, so P(C) = 1/3.
Now we can calculate the probability that your visit is during the Wet season:
P(C|A) = (3/4)(1/3) / (13/36)
= 1/4 / (13/36)
= 9/52
Therefore, given that it is raining when you arrive, the probability that your visit is during the Wet season is 9/52.
(c) Given that it is raining when you arrive, the probability that it will be raining when you return to Oneirabad in a year's time depends on the season. If you arrived during the Wet season, the probability of rain will be different from if you arrived during the Dry season.
Let D be the event that it is raining when you return.
If you arrived during the Wet season, the probability of rain when you return is the same as the probability of rain during the Wet season, which is 3/4.
If you arrived during the Dry season, the probability of rain when you return is the same as the probability of rain during the Dry season, which is 1/6.
Since the season you arrived in is independent of the weather when you return, we need to consider the probabilities based on the season you arrived.
Let C' be the event that your visit is during the Dry season.
P(D) = P(D|C)P(C) + P(D|C')P(C')
Since P(C) = 1/3 and P(C') = 2/3, we can calculate:
P(D) = (3/4)(1/3) + (1/6)(2/3)
= 1/4 + 1/9
= 9/36 + 4/36
= 13/36
Therefore, the probability that it will be raining when you return to Oneirabad in a year's time, given that it is raining when you arrive, is 13/36.
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A boy, flying a kite, holds the string 5 feet above the ground and plays out string at 2 ft./sec. as the kite moves horizontally at a height of 105 ft. Find the rate at which the kite is moving horizontally when 125 feet of string have been let out.
Answers
Answer:x = 75
Step-by-step explanation:y=105 - 5 = 100 ft
z=125 ft
dz/dt=2 ft/sec
by using Pythagorean Theorem, we find x
x^2 + 100^2 = 125^2
x = 75
in most situations, would it be reasonable to use a level .01 test in conjunction with a sample size of 40,000? why or why not?
Answers
In most situations, it would be reasonable to use a level .01 test with a sample size of 40,000 as it provides a high level of statistical power to detect smaller effects and reduce the likelihood of Type I error.
In most situations, it would be reasonable to use a level .01 test in conjunction with a sample size of 40,000. This is because a larger sample size provides more statistical power, meaning the test is more likely to detect a significant difference if one exists.
Additionally, a level .01 test is more conservative than a level .05 test, which reduces the risk of a type I error (rejecting the null hypothesis when it is actually true).
However, it is important to consider the context and specific research question being addressed, as well as potential confounding variables, to determine the appropriate statistical test and significance level for a given study.
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If we roll n standard 6-sided dice, the probability of rolling a sum of 2004 is nonzero and is exactly the same as getting a sum of X . What are the possible values of X
Answers
The possible values of X, such that the probability of rolling a sum of 2004 is the same as rolling a sum of X when rolling n standard 6-sided dice, depend on the coefficients in the expanded form of (x + x^2 + x^3 + x^4 + x^5 + x^6)^n.of X.
To determine the possible values of X such that the probability of rolling a sum of 2004 is the same as the probability of rolling a sum of X when rolling n standard 6-sided dice, we can use the concept of generating functions.
The generating function for a single 6-sided die is (x + x^2 + x^3 + x^4 + x^5 + x^6). When we roll n dice, the generating function becomes (x + x^2 + x^3 + x^4 + x^5 + x^6)^n.
We want the coefficient of x^2004 in the expanded form of (x + x^2 + x^3 + x^4 + x^5 + x^6)^n to be the same as the coefficient of x^X. This means that the probabilities of rolling a sum of 2004 and X are equal.
To find the possible values of X, we can expand the generating function (x + x^2 + x^3 + x^4 + x^5 + x^6)^n using techniques like the binomial theorem or using computational tools.
By examining the coefficients, we can determine the possible values of X for which the probability is the same as rolling a sum of 2004.
Without performing the calculations, it is difficult to determine the exact values of X in this scenario. The possible values of X will depend on the number of dice rolled (n) and the corresponding coefficients in the expanded form of (x + x^2 + x^3 + x^4 + x^5 + x^6)^n.
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UNIT RATE TRUE OR FALSE HELP ME!!!
Answers
Answer:
False
Step-by-step explanation:
This is not a unit rate because neither of the rates are equal to 1. A unit rate, for example, could be 25 ft per second.
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
A container releases fuel at a rate of 5 gallons per second. If y represents the amount of fuel remaining in the container and represents the number of seconds that have passed since the fuel started
dispensing, then x and y satisfy a linear relationship.
If the tank begins with 103 gallons, how many gallons will remain after 2 seconds?
Answers
If the tank begins with 103 gallons, then 93 gallon will remain after 2 seconds
The quantity of fuel releases from the container = 5 gallon per second
Consider the fuel remaining in the container = y
Consider the number of seconds that have passed since the fuel started dispensing = x
Then x and y satisfy a linear relationship
The quantity of fuel in the tank at the beginning = 103 gallon
Time taken = 2 seconds
Then the equation will be
y = 103 - 5x
Time taken is x = 2
y = 103 - 5× 2
y = 103 - 10
y = 93 gallon
Hence, if the tank begins with 103 gallons, then 93 gallon will remain after 2 seconds
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The table below shows the changes in the value of a company's stock over the past four weeks. By how many points would the stock value need to change in Week 5 to return to its value before Week 1? Explain.
Answers
ANSWER:
+ 4 7/8
STEP-BY-STEP EXPLANATION:
Assuming that we start in week 0, with a total of 0 points, we must operate the changes in each week and the value opposite to that result must be the change necessary to return to the original value.
Just like that:
\(\begin{gathered} 9\frac{1}{2}+6\frac{5}{8}-12\frac{3}{4}-8\frac{1}{4}=\frac{19}{2}+\frac{53}{8}-\frac{51}{4}-\frac{33}{4}=-\frac{39}{8}=-4\frac{7}{8} \\ -4\frac{7}{8}+4\frac{7}{8}=0 \end{gathered}\)Which means that to return to the initial value, 4 7/8 points must be added
Two points, a and b, are graphed on the number line below. Maynard says there is not
enough information to write an inequality statement comparing a and b. Which statement
explains whether or not Maynard is correct?
Answers
Answer:
where is the number line at?
Answer:
jhgvghj
Step-by-step explanation:
ihuvubij
When Nellie Newton hangs at rest in the middle of a clothesline, tensions will be the same in each side of the rope when:
a. the lengths of each rope are the same
b. the angles for both sides of the rope are equal
c. she is in equilibrium
Answers
The tensions in each side of the rope will be the same when Nellie Newton hangs at rest in the middle of a clothesline and the lengths of each rope are the same.
When Nellie Newton is in equilibrium, meaning she is at rest and not experiencing any acceleration or movement, the forces acting on her must be balanced. In the case of a clothesline, the tension in each side of the rope contributes to the balancing of forces.
For the tensions to be the same in each side of the rope, the lengths of the ropes must also be the same. This ensures that the forces applied to each side are equal and balanced, resulting in Nellie Newton remaining in a stable position without any net force acting on her.
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Need help with this math
Answers
Answer:
USE BODMAS
2^p+q
The ratio of students to teachers at Campbell Middle School is
23:3. If there are
1,350 students at the school, how many teachers are
there?
a. 176 b. 177 c. 10,350 d. 69
Answers
There are approximately 176 teachers at Campbell Middle School. The correct option is A
To solve this problemWe can make use of the 23:3 student to teacher ratio that is specified.
Let's set up a proportion using the ratio:
Students/Teachers = 23/3
We know that there are 1,350 students at the school. Let's denote the number of teachers as 'x'.
Plugging in the values, we get:
1,350/x = 23/3
To solve for 'x', we can cross-multiply:
23x = 1,350 * 3
23x = 4,050
Dividing both sides by 23:
x = 4,050/23
x ≈ 176.087
We round to the closest whole number because the number of teachers should be a whole number. Therefore, there are approximately 176 teachers at Campbell Middle School.
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f(x)=(x^2-x)/(x+1)
pls show work
Answers
Answer:
x - 2 + 2/(x + 1)
Step-by-step explanation:
These are really hard to type out and get the spacing right, so see the attached printout from a website that does carefully show steps in a polynomial division problem.
The website is:
https://www.emathhelp.net/calculators/algebra-1/polynomial-long-division-calculator/?numer=x%5E2-x&denom=x%2B1
A and B are two events. Let P(A) = 0.65, P (B) = 0.17, P(A|B) = 0.65 and P(B|4) = 0.17 Which statement is true?
1. A and B are not independent because P(A|B) + P(A) and P(B|4) + P(B).
2. A and B are not independent because P (A|B) + P(B) and P(B|4) + P(A)
3. A and B are independent because P (A|B) = P(A) and P(BIA) = P(B).
4. A and B are independent because P (A|B) = P(B) and P(B|A) = P(A).
Answers
Answer:
the statement that is true is: A and B are not independent because P(AIB) + P(B) is not equal to P(BIA) + P(A)
Step-by-step explanation:
ur welcome
At the movies, tickets cost $13.50 for adults and $4.50 for kids under 12. What would
be the total cost for 10 adult tickets and 6 kids tickets? What would be the total cost
for a adult tickets and k kids tickets?
Total cost, 10 adult tickets and 6 kids tickets:
Total cost, a adult tickets and k kids tickets:
Submit Answer
attempt 2 out of 2 / problem 1 out of max 1
Answers
Answer:
adult-135
kid-27
Step-by-step explanation:
13.50*10=135
4.50*6=27
Mrs. Byrne mowed 1 4 of her lawn. Her son mowed 2 7 of it. Who mowed most of the lawn? How much of the lawn still needs to be mowed?
Answers
Mrs. Byrne mowed 1/4 of her lawn. Her son mowed 2/7 of it. Mrs. Byrne mowed most of the lawn. The lawn still needs to be mowed is 13/28.
Mrs. Byrne mowed of his lawn = 2/7
Her son mowed of his lawn = 1/4
We firstly equal the denominator of both fraction by taking the LCM of both numbers.
The LCM of 7 and 4 is 28.
So we multiply and divide by 4 in the fraction 2/7 and by 7 in fraction 1/4. Now,
Mrs. Byrne mowed of his lawn = 2/7 × 4/4 = 8/28
Her son mowed of his lawn = 1/4 × 7/7 = 7/28
Now we compare the both fraction 8/28 and 7/28. The 8/28 is greater than 7/28. So we can say that Mrs. Byrne mowed most of his lawn.
The total lawn is 28/28.
So, the remaining lawn for mowed = 28/28 - (8/28 + 7/28)
The remaining lawn for mowed = 28/28 - (8 + 7)/28
The remaining lawn for mowed = 28/28 - 15/28
The remaining lawn for mowed = (28 - 15)/28
The remaining lawn for mowed = 13/28
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The complete question is:
Mrs. Byrne mowed 2/7 of his lawn. Her son mowed 1/4 of it. Who mowed most? How much of the lawn still needs to be mowed?
On Monday, 325 students went on a trip to the zoo. All 8 buses were filled and 5 students had to travel in cars. How many students were in each bus ?
Answers
Answer:40
Step-by-step explanation:
325 students - 5 going in cars.
320 students left / 8 busses = 40 students per bus
How do I Identify the zeros in these?
Answers
The zeros of the given quadratic function are: 9. x=7, 10. x=9, 11. x=-4, 12. x=10, 13. x=±4.
To find the zeros of each quadratic function, we need to solve for when f(x) equals zero. Using synthetic division or long division, we can find factor the cubic polynomial.
9. f(x) = -x + 7
Setting f(x) = 0, we get:
-x + 7 = 0
x = 7
Zero of f(x) is x = 7.
10. f(x) = 2/3 * x - 6
Setting f(x) = 0, we get:
2/3 * x - 6 = 0
2/3 * x = 6
x = 9
Zero of f(x) is x = 9.
11. f(x) = 1/2 * x + 2
Setting f(x) = 0 :
1/2 * x + 2 = 0
1/2 * x = -2
x = -4
Zero of f(x) is x = -4.
12. f(x) = -2/5 * x + 4
Let f(x) = 0, we get:
-2/5 * x + 4 = 0
-2/5 * x = -4
x = 10
Zero of f(x) is x = 10.
13. f(x) = \(x^2 - 16\)
\(x^2 - 16 = 0\)
(x - 4)(x + 4) = 0
x = -4 or x = 4
Zeros of f(x) are x = -4, x = 4.
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Identify the zeros in the given equations?
9. f(x) = - x + 7
10. f(x) = 2/3 * x - 6
11. f(x) = 1/2 * x + 2
12. f(x) = - 2/5 * x + 4
13. f(x) = \(x ^ 2 -16\).
What is the equivalent fraction for the following fraction using 5 as the multiplier?
Will give brainlest!!!
3/8
Answers
Answer:
Step-by-step explanation:
The answer is 15/40
Because 3 times 5 is 15 and 8 times 5 is 40
Answer:
15/40
Step-by-step explanation:
the equivalent fraction for 3/8 using 5 as a multiplier is :
3 x 5 / 8 x 5
= 15 / 40
Katie bought 4 gallons of punch for the school Halloween dance. If she places a pitcher with 12 gallon on each table at the dance, how many tables does she set up with punch? Question 1 options: 412 tables 2 tables 8 tables 1 table
Answers
Answer:
8 tables!
Thanks for clarifying.
g(x)=√8x
What is the domain of g?
Answers
X:7.74870453
G:7.87334975
Someone pls help me with this I will make you brain
Answers
Answer: B
Step-by-step explanation:
Answer:
Step-by-step explanation:
How can you use the graph of a quadratic equation to determine the number of real solutions of the equation?
Answers
Answer:
Step-by-step explanation:
The number of real solution of a quadratic equation can be found from the number of x-intercepts on the graph. If the curve passes through the x-axis twice, (2 x-intercepts), then the equation has two real solutions.
If it passes through once, (the vertex is on x-axis), then there is one real solution, and if it does not touch the x-axis at all (floating above it or below it), then it has no real solutions.
Hope this helped!
What is quadratic example?
Answers
The quadratic example is ax² + b x + c = 0 where x stands for an unknown value and where a, b, and c stand for known numbers is known as a quadratic equation in algebra.
What is quadratic example?Quadratic equations are second-degree polynomial equations with at least one squared term. It is also referred to as quadratic equations.
The numerical coefficients a, b, and c are known, while the unknown variable x is. For example , x2 + 2x + 1. It also goes by the name quadratic equation as in: b x +c=0
The terms a, b, and c are also referred to as quadratic coefficients.
'Examples of Quadratics
x² –x – 9 = 0
5x² – 2x – 6 = 0
3x² + 4x + 8 = 0
-x² +6x + 12 = 0 (an example of non-quadratic equation is x³ − x² − 5 = 0)
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I need help with this assignment.
Answers
Answer:
slope = - 1
Step-by-step explanation:
Calculate the slope m using the slope formula
m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)
with (x₁, y₁ ) = (- 2, 0) and (x₂, y₂ ) = (0, - 2) ← 2 points on the line
m = \(\frac{-2-0}{0-(-2)}\) = \(\frac{-2}{0+2}\) = \(\frac{-2}{2}\) = - 1
A cheese processing plant keeps the heavy cream for their product in a silo with a dome top. The silo has an overall diameter of 25. The height of the cylinder part is 31 feet tall. What is the volume of the silo as a whole? Round your answer to the nearest hundredth, if necessary. Use 3.14 for pi.
Answers
V = 3.14(12.5^2)(31)
V = 15209.38
what situation could -16/4 represent?
Answers
Answer:
I would say C
Step-by-step explanation:
Since two negatives make a positive
PLS Help!!!!!!!
4(x+9) = x+9
Answers
4 ( x + 9) = x + 9 (remove the parantheses)
4x + 36 = x + 9 (move the terms)
4x - x = 9 - 36 (collect like terms and calculate)
3x = -27 (divide both sides)
solution : x = -9
Answer:
Solution given:
4(x+9) = x+9
4x+36=x+9
4x-x=9-36
3x=-27
x=-27/3
x=-9.
Find the distance between the points (5,-8) and (-7,-3)
Answers
Answer:
Distance:
\(d = 13\)
Step-by-step explanation:
-To determine the distance, use the "distance formula":
\(d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2}\)
-Apply the points \((5,-8)\) and \((-7,-3)\) for the distance formula:
\(d = \sqrt{(-7 - 5)^2 + (-3 + 8)^2}\)
-Then, solve the equation:
\(d = \sqrt{(-7 - 5)^2 + (-3 + 8)^2}\)
\(d = \sqrt{(-12)^2 + (5)^2}\)
\(d = \sqrt{144 + 25}\)
\(d = \sqrt{169}\)
\(d = 13\)
So, the actual distance is \(13\).