1. in 2.0 s, 1.9 x 1019 electrons pass a certain point in a wire. what is the current i in the wire?

The angular speed of the soccer ball is approximately 0.197 radians per second.

To find the angular speed of the soccer ball, we need to convert the linear speed (distance over time) into angular speed (radians per second).

Radius of the soccer ball (r) = 11 cm = 0.11 m

Distance rolled (d) = 10 m

Time taken (t) = 3.50 s

First, let's calculate the circumference of the soccer ball:

Circumference (C) = 2 * π * r

Next, we can calculate the angular speed (ω) using the formula:

Angular speed (ω) = (Distance traveled) / (Time taken) = (C / t)

Substituting the values, we have:

Circumference (C) = 2 * π * 0.11 m

Angular speed (ω) = (10 m) / (3.50 s)

Calculating the circumference:

C = 2 * 3.1416 * 0.11 m = 0.689 m

Now, we can find the angular speed:

ω = (0.689 m) / (3.50 s) ≈ 0.197 radians per second

Therefore, the angular speed of the soccer ball is approximately 0.197 radians per second.

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Answer:

100,000 / 800,000 = 1 / 8    amount of sample after 12 hours

(1/2)^n = 1 / 8      after n half-lives 1/8 of sample will be left

n = 3

(D) is the correct answer - 1/2 half-life = 4 hours

The perceptual attribute of color best corresponds to that of the dominant wavelength of light.

Hue is the perceptual attribute of color that corresponds to the dominant wavelength of light and it is the "name" of the color, such as red, orange, yellow, green, blue, purple, etc. It is the most basic element of color and is determined by the dominant wavelength of light. The dominant wavelength is the wavelength of light that is the most intense within a given region of the visible spectrum, and it determines the hue of the color. For example, the dominant wavelength of a light that appears to be red is 700 nm, and so the hue of the color is red.

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Acccording to the statement This box contains a charge of q = 4.95 nc.

The amount that the electric field "flows through" a space is measured by its electric flux. The flow is determined as the imaginary product of the area factor perpendicular to a field and field strength.

Net flux through the close surface of rectangular box

Φe = Φ1 + Φ2 + Φ3 + Φ4 + Φ5 + Φ6

= 147.4 + 243.6 - 334.1 + 169.7 - 112.3 + 445.1

Φe = 559.4 N m^2/ C

q/E° = 559.4 N m^2/ C

q = 559.4 × 8.85 × 10^-12

∴ q = 4.95 nc

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The momentum of the dog is 50 kg·m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

Given parameters:

Mass of the  corgi dog: m = 10 kg.

Velocity of the dog; v = 5 m/s.

We have to find: momentum of the dog: p = ?

We know that: momentum = mass × velocity

= 10 kg × 5 m/s.

= 50 kg·m/s.

Hence, momentum of the corgi dog is 50 kg.m/s.

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Answer:

Explanation:

Given:

f(t) = 3*t³ - 3*t² + 1*t - 1

__________________

V - ?

a - ?

Velocity is the first derivative of the coordinate.

Acceleration is the first derivative of speed.

V(t) =  ( f(t) )' = 9*t² - 6*t + 1

a(t) = ( V(t) )' = 18*t - 6

a)

V(t) = 0

9*t² - 6*t + 1 = 0

(3*t - 1)² = 0

3*t - 1 = 0

3*t = 1

t = 1/3 ≈ 0.33 s

b)

a(t) = 0

18*t - 6 = 0

18*t = 6

t = 6 / 18 = 1/3 ≈ 0.33 s

Well, let's see ...

You said that f(t) = 3t³ - 3t² + t - 1

I have to assume that f(t) is the position of the praticle at time t .

Then the object's speed is the first derivative.  That's s(t) = 9t² - 6t + 1

Speed is zero when S(t) = 9t² - 6t + 1 = 0

Solve that ugly thing with the quadratic formula, and you'll get  t = 1/3 .

The object's acceleration is the second derivative.  That's A(t) = 18t - 6 .

Acceleration is zero when A(t) = 18t - 6 = 0 .

Solve this thing with elementary algebra, and you'll get  t = 1/3 .

Ordinarily we'd be surprised to encounter a praticle whose speed and acceleration are both apparently zero at the same time.  This would cause us discomfort, and we would check our work over and over about six times, but we'd keep coming up with the same answers.  We'd slink away then, more uncomfortable than ever and with the dark suspicion that this praticle must have some kind of goofy motion.  

THAT happens to be exactly what's going on.  The praticle's position f(t) is a third-order polynomial.  If you look at the graph, you find that its first and second derivatives are both zero at t=1/3 .  So everything is sunny and wonderful . . . not only fine, but dandy as well !

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 2000 × 3

We have the final answer as

Hope this helps you

Explanation:

It is given that,

The angle of projection is 60 degrees

Initial velocity of the ball is 120 m/s

We need to find the time taken to get to the maximum height and the time of flight.

Time taken to reach the maximum height is given by :

\(T=\dfrac{u^2\sin^2\theta}{2g}\)

g is acceleration due to gravity

\(T=\dfrac{(120)^2\times \sin^2(60)}{2\times 10}\\\\T=540\ s\)

(ii) Time of flight,

\(t=\dfrac{2u\sin\theta}{g}\)

So,

\(t=\dfrac{2\times 120\times \sin(60)}{10}\\\\t=20.78\ s\)

Hence, this is the required solution.

Answer: Everything except heat and density

Explanation:

Answer:33.75m

Explanation: If you are throwing a rock down a cliff with a speed of 7.50m/s and it reached the ground in 4.50 seconds the height of the cliff will be 33.75m because 7.50m/s x 4.50s = 33.75

Answer:

Explanation:

The higher the object is relative to some defined baseline (like the ground), the greater the potential energy.

Potential Energy = U = mgh

U is directly proportional to h (height of the object), so the greater the h the greater the U.

Solution: given that; velocity (v)=60km/hr, distance (d)=500km, time (t)=? From velocity=distance/time....... :. 60=500/t, cross-multiply..... 60t=500, divide both sides by 60...... 60t/60=500/60, t=500/60, t=8.33~. Therefore the bus took 8hours, 33 minutes to cover the distance of 500km.

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To determine the minimum speed that the motorcycle must have at the top of the loop to make it safely around, we need to consider the forces acting on the motorcycle at that point.

At the top of the loop, the motorcycle is experiencing two forces: the force of gravity pulling it downward and the normal force exerted by the track pushing it upward. The minimum speed required is when the normal force becomes zero, indicating that the motorcycle is just about to lose contact with the track.The net force acting on the motorcycle at the top of the loop is the centripetal force, which is given by:
F_net = m * (v^2 / r)
Where:F_net is the net force.m is the mass of the motorcycle (250 kg).v is the speed of the motorcycle.r is the radius of the circular track (12 m).At the top of the loop, the net force is the difference between the gravitational force and the normal force:
F_net = mg - N
Setting the net force equal to zero (N = 0), we can solve for the minimum speed:
mg = m * (v^2 / r)
Canceling out the mass:
g = v^2 / r
Solving for v:
v = √(g * r)
Plugging in the values:
v = √(9.8 m/s^2 * 12 m)
v ≈ √(117.6 m^2/s^2)
v ≈ 10.85 m/s
Therefore, the minimum speed that the motorcycle must have at the top of the loop to make it safely around is approximately 10.85 m/s.

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(a) The acceleration (in m/s²) of the two blocks is 4.42 m/s².

(b) The tension (in N) in the string connecting the blocks is 63.65 N.

The acceleration of the blocks is determined by applying Newton's second law of motion as shown below.

F(net) = ma

where;

F = m₁a + m₂a

F = a(m₁ + m₂)

a = F/(m₁ + m₂)

where;

a = (153) / (14.4 + 20.2)

a = 4.42 m/s²

The tension (in N) in the string connecting the blocks is calculated as follows;

T = m₁a

T = 14.4 x 4.42

T = 63.65 N

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The option There is a warm layer of air and a cold layer of air closer to the ground. is the correct answer

The normal force at point C is the force exerted perpendicular to the beam. Since the beam is in equilibrium, the sum of all forces in the vertical direction is equal to zero. Therefore, the normal force at point C will be equal in magnitude and opposite in direction to the total vertical force acting on the beam.

2. Shear force: The shear force at point C is the force acting parallel to the beam, causing it to shear or slide. To determine the shear force at point C, we need to consider the forces acting on either side of point C and take the sign convention into account. If we take the left side of point C, the shear force will be positive if it acts in the upward direction and negative if it acts in the downward direction. Similarly, if we take the right side of point C, the shear force will be positive if it acts in the downward direction and negative if it acts in the upward direction. We need to sum up the vertical forces on either side of point C and determine the difference to find the shear force at point C.

3. Moment: The moment at point C is the turning effect caused by the forces acting on either side of point C. To determine the moment at point C, we need to consider the forces acting on either side of point C and their perpendicular distances from point C. Again, we need to take the sign convention into account. Clockwise moments are considered positive, while counterclockwise moments are considered negative. We need to calculate the moments caused by the forces on either side of point C and determine the algebraic sum to find the moment at point C.

By applying these steps, we can determine the normal force, shear force, and moment at point C.

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Answer:

Density= 2.78 g/cm³

Relative density=2.8

Explanation:

To calculate the density of the cube we have to use the formula ρ=mass/volume

ρ stands for density.

So now we don't have the volume of the cube and to find the volume of the cube we have to use the formula a³

3³= 9 cm³

Now plug in the values. ρ= 25 g/9 cm³

ρ= 2.78 g/cm³

To find the relative density, we have to use the formula ρsample/ρH20

The sample means the density of the substance earlier. We do not know the density of water but it is constant at 997 kg/m³.

Now we have to make the units same so you change the unit of the density of cube to kg/m³

So, 25/1000= 0.025 kg

9/100×100×100 (because cm³ which means that there should be 3 meters to change the unit and to conver cm to meter we need to divide by 100 so 9cm/100, 9cm²/100×100, 9cm³/100×100×100)

=0.000009 m³

The new density= 0.025 kg/ 0.000009 m³

= 2777.78 kg/m³

Now plug the values into the formula:

relative density= 2.777.78 kg/m³ / 997 kg/m³

=2.8

There is no unit since kg/m³ and kg/m³ cancels

The new volume of the gas when the temperature is raised to 29°C and the pressure is not changed is approximately :4.73 L. The correct option is A.

To determine the new volume of a gas when its temperature is changed, we can use Charles' Law. Charles' Law states that the volume of a gas is directly proportional to its temperature, provided that the pressure remains constant. Your initial temperature (T1) is 14°C, and the initial volume (V1) is 4.5 L.

The final temperature (T2) is 29°C, and we need to find the new volume (V2). Remember to convert the temperatures from Celsius to Kelvin by adding 273.15 to each value (T1 = 287.15 K, T2 = 302.15 K).

Using Charles' Law, we have:

V1/T1 = V2/T2

Now, we can plug in the values:

(4.5 L)/(287.15 K) = V2/(302.15 K)

To find V2, multiply both sides by 302.15 K:

V2 = (4.5 L x 302.15 K) / 287.15 K

V2 ≈ 4.73 L

The new volume of the gas when the temperature is raised to 29°C and the pressure is not changed is approximately 4.73 L. The correct option is A.

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Complete  question:

A gas has a temperature of 14 °C, and a volume of 4. 5 L. If the temperature is raised to 29 °C and the pressure is not changed, what is the new volume of the gas?

A. 4. 7 L

B. 4. 9 L

C. 5. 3 L

D. 5. 5 L

The magnification of the image of Julitha Barber produced by the converging mirror is 0.0979

To find the magnification of the image, we need to use the formula:

magnification = -v/u,

where v is the distance of the image from the mirror, and u is the distance of the object from the mirror. Since the object is Julitha Barber standing at a distance of 553 m, we can take u as -553 m (negative because the object is on the same side as the mirror).
Now, we need to find the distance of the image from the mirror (v). For this, we can use the mirror formula: 1/v + 1/u = 1/f, where f is the focal length of the mirror, and is equal to half the radius of curvature (f = R/2). So, in this case, f = 1.20 × 102 m/2 = 60 m. Substituting the values in the formula, we get:
1/v + 1/-553 = 1/60
Solving for v, we get v = -54.12 m. (Note that the negative sign indicates that the image is virtual and upright.)
Now, we can use the magnification formula to find the magnification of the image:
magnification = -v/u = -(-55.6)/553 = 0.0979  (rounded to one decimal place)
Therefore, the magnification of the image of Julitha Barber produced by the converging mirror is 0.0.0979. This means that the image is 10 times smaller than the actual object and is virtual and upright.

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Answer:

Final volume, V2 = 24.62 L

Explanation:

Given the following data;

Initial volume = 40 L

Initial pressure = 80 Pa

Final pressure = 130 Pa

To find the final volume V2, we would use Boyles' law.

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

\( PV = K\)

\( P_{1}V_{1} = P_{2}V_{2} \)

Substituting into the equation, we have;

\( 80 * 40 = 130V_{2} \)

\( 3200 = 130V_{2} \)

\( V_{2} = \frac {3200}{130}\)

\( V_{2} = 24.62 \)

Final volume, V2 = 24.62 Liters

A car's bumper is designed to withstand a 4.32 km/h (1.2 m/s) collision with an immovable object without damage to the body of the car. the bumper cushions the shock by absorbing the force over a distance. The magnitude of the average force (in n) on a bumper that collapses 0.210 m while bringing a 950 kg car to rest from an initial speed of 1.2 m/s is 3138.46 N.

To calculate the average force exerted on the car's bumper, we can use the formula:
average force = (mass x change in velocity) / time
First, we need to calculate the time it takes for the car to come to a complete stop. We can use the equation:
distance = (initial velocity x time) + (0.5 x acceleration x \(time^2\))
Since the car comes to a stop, the final velocity is 0. Solving for time, we get:
0.210 m = (1.2 m/s x time) + (0.5 x (-a) x \(time^2\))
Where a is the acceleration of the car (which we don't know yet). Rearranging, we get a quadratic equation:
0.5 x (-a) x \(time^2\) + 1.2 m/s x time - 0.210 m = 0
Using the quadratic formula, we get:
time = 0.364 s
Now we can calculate the acceleration of the car using the equation:
acceleration = (final velocity - initial velocity) / time
Since the final velocity is 0, we get:
acceleration = -1.2 m/s / 0.364 s
acceleration = -3.30 \(m/s^2\)
Now we can use the formula for average force:
average force = (mass x change in velocity) / time
The change in velocity is just the initial velocity (1.2 m/s) since the car comes to a complete stop. The mass of the car is 950 kg. Plugging in these values, we get:
average force = (950 kg x 1.2 m/s) / 0.364 s
average force = 3138.46 N
Therefore, the magnitude of the average force exerted on the car's bumper is 3138.46 N.

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The difference in power for two people carrying the boxes up the ramp is 30 W.

Given the following data:

W = 40.0 N is the weight of a box.

The ramp's length is L = 2.00 m.

The platform height is h = 1.0 m.

t = 2.0 s is the time interval for the first person.

t' = 4.0 s is the time interval for the other person.

Power is the rate at which energy is used. The expression for the Power is given in the given question as,

P = W×(L+h)/t

Assume that you are solving for the first person.

P₁ = W(L+h)/t₁.................................................................. (1)

Substitute the following values into equation (1):

P₁ = 40(2+1)/2

P₁ = 20(3) (3)

P₁ = 60 W.

Regarding the second person,

P₂ = W(L+h)/t₂..................................................................... (2)

Fill in the blanks in equation (2) as follows:

P₂ = 40(2+1)/4

P₂ = 10*(3) *3)

P₂ = 30 W

Obtaining the difference in power as

P = P₁ - P₂

P = 60-30

P = 30 W

As a result, we can conclude that the difference in power for two people carrying the boxes up the ramp is 30 W.

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Answer: no exact answer

=

Explanation:

Scientific experiments follow principles called the scientific method that ensure that accurate tests are performed, reliable results are collected, and reasonable conclusions are drawn. Scientific experiments must follow the basic principles of good research so that the final presented results can be believed to be reliable.

Observations of new physical processes or phenomena occur infrequently, but there are areas of science that are not fully understood. Scientists must verbalize their observations in order to formulate meaningful hypotheses.

It's not enough to just guess why something happens. Scientists must prove their theories to be correct. Predictions are made to test observations under different circumstances. The aim is to learn more about this phenomenon and prove its existence. One of his ways of improving the scientific method is by creating 'models'. Models can be used to infer difficult and unobservable concepts.

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Answer:

Cracking of an egg is a physical change since the egg and the stuff inside does not change but the shape or appearance of the shell changes.

Explanation:

Hope it helps

The magnitudes of (a) the frictional force on the block from the floor is 7.14 N and (b) the block's acceleration is 3.19 m/s².

The first step to solving this problem is to determine the components of the force F. Since the force is given at an angle, we need to find its horizontal and vertical components.

To find the horizontal component, we use the equation Fx = F xcos(theta), where Fx represents the horizontal component and theta is the angle given (40.0 degrees). Plugging in the values, we get Fx = 22.0 N x cos(40.0 degrees) = 16.83 N.

To find the vertical component, we use the equation Fy = F x sin(theta), where Fy represents the vertical component. Plugging in the values, we get Fy = 22.0 N x sin(40.0 degrees) = 14.16 N.

Next, we need to calculate the frictional force on the block. The formula for the frictional force is Ffriction = coefficient of friction * normal force. The normal force is the force exerted by the floor on the block, which is equal to the weight of the block since it is on a horizontal surface. The formula for the weight is weight = mass * gravity. Plugging in the values, we get weight = 3.03 kg x9.8 m/s². = 29.74 N. Therefore, the normal force is equal to the weight, which is 29.74 N.

Plugging in the values for the coefficient of friction (0.240) and the normal force (29.74 N), we can calculate the frictional force using the formula Ffriction = 0.240 x 29.74 N = 7.14 N.

Now, let's calculate the acceleration of the block. The net force acting on the block is equal to the force Fx minus the frictional force (Fnet = Fx - Ffriction). Plugging in the values, we get Fnet = 16.83 N - 7.14 N = 9.69 N.

To find the acceleration, we use Newton's second law, which states that Fnet = mass x acceleration. Rearranging the formula, we can solve for acceleration: acceleration = Fnet / mass. Plugging in the values, we get acceleration = 9.69 N / 3.03 kg = 3.19 m/s².

In conclusion, the magnitudes of (a) the frictional force on the block from the floor is 7.14 N and (b) the block's acceleration is 3.19 m/s².

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The magnetic field at the center of a current-carrying loop is given by the formula: B = (μ₀/4π) * (2I/ r)

where B is the magnetic field at the center of the loop, I is the current in the loop, r is the radius of the loop, and μ₀ is the permeability of free space. In this case, we are given the magnetic field B = 3.00 mT = 3.00 × 10^(-3)  T and the radius r = 0.700 cm = 0.00700 m.Substituting these values into the above formula, we can solve for the current I: I = (B * r * 4π)/ (2 * μ₀)

I = (3.00 × 10^(-3) T * 0.00700 m * 4π)/ (2 * 4π × 10^(-7) T·m/A)

I = 0.0133 A

Therefore, the current in the loop is 0.0133 A (amperes).

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Answer:

a. the light diverges when it passes through the lens.

Explanation:

All the light rays after passing through the concave lens diverge and when produced backwards appear to meet at a point on the principal axis of the lens. This point is known as principal focus of a concave lens.