1) Perform the following operations in System F(10, 5, −4, 4),
taking x = 113/8, y = 220/9 and z = −314/17. At the end, calculate
the relative error due to system restrictions and inform how many

Answers

Answer 1

(a)  0.0577 (b)-260.2774  (c)-7826.409 (d) 150.8776 (e)  14719.7032

(3 significant figures) .The relative error due to system restrictions for all calculations ranges from 0.0001 to 0.0132.

To perform the operations in System F(10, 5, -4, 4), we need to round the numbers to the given precision. Let's round the values of x, y, and z accordingly:

x = 113/8 ≈ 14.125

y = 220/9 ≈ 24.444

z = -314/17 ≈ -18.471

Now let's calculate the operations:

(a) 1/x + 1/y + 1/z

1/x ≈ 1/14.125 ≈ 0.0709

1/y ≈ 1/24.444 ≈ 0.0409

1/z ≈ 1/-18.471 ≈ -0.0541

1/x + 1/y + 1/z ≈ 0.0709 + 0.0409 - 0.0541 ≈ 0.0577

To determine the relative error due to system restrictions, we can compare the actual values of x, y, and z with the rounded values:

Relative error for x = |x - 14.125| / |x| ≈ |113/8 - 14.125| / |113/8| ≈ 0.0004

Relative error for y = |y - 24.444| / |y| ≈ |220/9 - 24.444| / |220/9| ≈ 0.0132

Relative error for z = |z - (-18.471)| / |z| ≈ |-314/17 - (-18.471)| / |-314/17| ≈ 0.0061

The relative error due to system restrictions is the maximum of these three values: 0.0132. To determine the number of significant figures, we look at the number with the fewest decimal places among x, y, and z. In this case, it is z with 3 decimal places. Therefore, the calculated number will have 3 significant figures.

(b) x/y + z * x

x/y ≈ 14.125 / 24.444 ≈ 0.5776

z * x ≈ -18.471 * 14.125 ≈ -260.855

x/y + z * x ≈ 0.5776 + (-260.855) ≈ -260.2774

Relative error for x/y: |0.5776 - (113/8) / (220/9)| / |0.5776| ≈ 0.0001

Relative error for z * x: |-260.855 - (-18.471 * 113/8)| / |-260.855| ≈ 0.0004

The relative error due to system restrictions is the maximum of these two values: 0.0004.

The number of significant figures is determined by the number with the fewest significant figures among x, y, and z, which is 3 significant figures.

(c) x * y * z

x * y * z ≈ 14.125 * 24.444 * (-18.471) ≈ -7826.409

The relative error for x * y * z is calculated as |(-7826.409) - (113/8) * (220/9) * (-314/17)| / |-7826.409| ≈ 0.0001.

The number of significant figures is determined by the number with the fewest significant figures among x, y, and z, which is 3 significant figures.

(d) x² - 2y

x² ≈ 14.125

² ≈ 199.7656

2y ≈ 2 * 24.444 ≈ 48.888

x² - 2y ≈ 199.7656 - 48.888 ≈ 150.8776

Relative error for x²: |199.7656 - (113/8)²| / |199.7656| ≈ 0.0001

Relative error for 2y: |48.888 - 2 * (220/9)| / |48.888| ≈ 0.0001

The relative error due to system restrictions is the maximum of these two values: 0.0001.

The number of significant figures is determined by the number with the fewest significant figures among x, y, and z, which is 3 significant figures.

(e) y³ + x/y

y³ ≈ 24.444³ ≈ 14719.1256

x/y ≈ 14.125 / 24.444 ≈ 0.5776

y³ + x/y ≈ 14719.1256 + 0.5776 ≈ 14719.7032

Relative error for y³: |14719.1256 - (220/9)³| / |14719.1256| ≈ 0.0002

Relative error for x/y: |0.5776 - (113/8) / (220/9)| / |0.5776| ≈ 0.0001

The relative error due to system restrictions is the maximum of these two values: 0.0002.

The number of significant figures is determined by the number with the fewest significant figures among x, y, and z, which is 3 significant figure.

The relative error due to system restrictions for all calculations ranges from 0.0001 to 0.0132.

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The complete question is:

1) Perform the following operations in System F(10, 5, −4, 4), taking

x = 113/8, y = 220/9 and z = −314/17.

At the end, calculate the relative error due to system restrictions and inform how many significant figures the calculated number has.

(a) 1/x + 1/y + 1/z

(b) x/y + z ∗ x

(c) x ∗ y ∗ z (

d) x² − 2y

(e) y³ + x/y


Related Questions

QUESTION 1 What is Statistical Process Control and Control Charts? O It is a method that uses basic graphics and statistical tools to analyze, control and reduce variability within a process by taking

Answers

Statistical Process Control (SPC) is a methodology used to monitor, control, and improve processes by analyzing data and applying statistical techniques. Control charts are a key tool in SPC.

It involves the collection and analysis of data from a process to understand and control its variability. The goal of SPC is to ensure that a process operates within specified limits and remains stable over time, leading to consistent and predictable outcomes.

Control charts are a key tool in SPC. They provide a visual representation of process data over time and help to distinguish between common cause variation (inherent to the process) and special cause variation (resulting from specific factors).

Control charts display process measurements, such as sample means or individual measurements, plotted against time or the sequence of data collection.

Control charts typically include three lines: a centerline, an upper control limit (UCL), and a lower control limit (LCL). The centerline represents the process mean, while the control limits are calculated based on the process variability.

These control limits act as thresholds, indicating when the process is operating within acceptable limits or when it has deviated from its usual behavior.

By monitoring the data points on the control chart, process operators can identify patterns, trends, or unusual observations that may signal special causes of variation. When special causes are detected, actions can be taken to investigate and eliminate them, thereby improving process performance and reducing variability.

The use of SPC and control charts provides several benefits, including early detection of process issues, reduction of defects and waste, improved process stability, and the ability to make data-driven decisions for process improvement.

By focusing on understanding and controlling variability, organizations can achieve higher process quality, efficiency, and customer satisfaction.

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Which equation shows the relationship between x and y?

Which equation shows the relationship between x and y?

Answers

Answer:

d

Step-by-step explanation:

Answer:

D. y = -3x

Step-by-step explanation:

plug x into the equation:

y = -3(-4) = 12 (s0 when x = -4, y = 12)

y = -3(-3) = 9

y = -3(-2) = 6

y = -3(-1) = 3

Determine whether each of the following is the graph of a function. Write Yes or No for your answer. 2 -10-8-6-4-2 2 4 6 8 10 - 2pts Information 5. Find the domain of: g(x) = 8 - x2

Answers

The given graph is not the graph of a function. The domain of the function g(x) = 8 - x^2 is all real numbers.

To determine whether the given graph is the graph of a function, we examine whether each input value (x-coordinate) corresponds to a unique output value (y-coordinate). In the given graph, for some x-values, there are multiple y-values, which violates the definition of a function. Therefore, the answer is No, the given graph is not the graph of a function.

Moving on to the second part, we need to find the domain of the function g(x) = 8 - x^2. The domain of a function represents all the possible input values (x-values) for which the function is defined. Since the function g(x) involves a quadratic term x^2, there are no restrictions on the domain. In other words, the function is defined for all real numbers.

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Find the coefficient of x^4 in the expansion of
(2x+1)^12

Answers

Answer:

7920

Step-by-step explanation:

you can use the binomial theorem obviously but you can also use symbolabs or wolframalpha and just solve it like that.

A camera regularly priced at 295 was placed on sale at 236. What percent of the regular price was the sale price?

Answers

Answer:

80%

Step-by-step explanation:

regular price was given as $295.

The sale of the camera was $236.

Needed Percentage of the regular price =( 236/295)

= 0.8

=(0.8 × 100%)

= 80%

Pamela is 7 years older than Jiri. The sum of their ages is 71. what is jiris age?

Answers

Answer:

jiris age is 32

Step-by-step explanation:

39(palma's age)+32(jiris age)=71

Can someone plz help me, I’ve been stuck on this question for ever

Can someone plz help me, Ive been stuck on this question for ever

Answers

Answer:

Step-by-step explanation:

A1 = 3 * 2,3 = 6,9 m^2

A2 = 8 * 4,5 = 36 m^2


A parachutist jumps from a plane 13,200 feet above the earth. If she landed in 3
minutes, what was her average speed in miles per hour?

Answers

Answer:

50 miles per hour

A study was conducted to examine the gender difference in daily smoking prevalence. State the research and null hypotheses for this test.

Answers

Research Hypothesis: There is a gender difference in daily smoking prevalence.

Null Hypothesis: There is no gender difference in daily smoking prevalence.

In this study, the research hypothesis states that there is a difference between genders concerning the prevalence of daily smoking. It implies that the proportion of individuals who smoke daily may vary between males and females.

The null hypothesis, on the other hand, assumes that there is no significant difference in the prevalence of daily smoking between genders. It suggests that any observed difference in smoking prevalence is due to random chance and does not reflect a true gender disparity.

The purpose of conducting statistical tests and analyzing data is to either accept the research hypothesis and reject the null hypothesis or fail to reject the null hypothesis, providing evidence for the absence of a gender difference in daily smoking prevalence.

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Read John Muir's "Calypso Borealis" and answer the question. [1] After earning a few dollars working on my brother-in law's farm near Portage [Wisconsin], I set off on the first of my long lonely excursions, botanising in glorious freedom around the Great Lakes and wandering through innumerable tamarac and arbor-vitae swamps, and forests of maple, basswood, ash, elm, balsam, fir, pine, spruce, hemlock, rejoicing in their bound wealth and strength and beauty, climbing the trees, revelling in their flowers and fruit like bees in beds of goldenrods, glorying in the fresh cool beauty and charm of the bog and meadow heathworts, grasses, carices, ferns, mosses, liverworts displayed in boundless profusion. [2] The rarest and most beautiful of the flowering plants I discovered on this first grand excursion was Calypso borealis (the Hider of the North). I had been fording streams more and more difficult to cross and wading bogs and swamps that seemed more and more extensive and more difficult to force one's way through. Entering one of these great tamarac and arbor-vitae swamps one morning, holding a general though very crooked course by compass, struggling through tangled drooping branches and over and under broad heaps of fallen trees, I began to fear that I would not be able to reach dry ground before dark, and therefore would have to pass the night in the swamp and began, faint and hungry, to plan a nest of branches on one of the largest trees or windfalls like a monkey's nest, or eagle's, or Indian's in the flooded forests of the Orinoco described by Humboldt. [3] But when the sun was getting low and everything seemed most bewildering and discouraging, I found beautiful Calypso on the mossy bank of a stream, growing not in the ground but on a bed of yellow mosses in which its small white bulb had found a soft nest and from which its one leaf and one flower sprung. The flower was white and made the impression of the utmost simple purity like a snowflower. No other bloom was near it, for the bog a short distance below the surface was still frozen, and the water was ice cold. It seemed the most spiritual of all the flower people I had ever met. I sat down beside it and fairly cried for joy.

[4] It seems wonderful that so frail and lovely a plant has such power over human hearts. This Calypso meeting happened some forty-five years ago, and it was more memorable and impressive than any of my meetings with human beings excepting, perhaps, Emerson and one or two others. When I was leaving the University, Professor J.D. Butler said, "John, I would like to know what becomes of you, and I wish you would write me, say once a year, so I may keep you in sight." I wrote to the Professor, telling him about this meeting with Calypso, and he sent the letter to an Eastern newspaper [The Boston Recorder] with some comments of his own. These, as far as I know, were the first of my words that appeared in print.

[5] How long I sat beside Calypso I don't know. Hunger and weariness vanished, and only after the sun was low in the west I splashed on through the swamp, strong and exhilarated as if never more to feel any mortal care. At length I saw maple woods on a hill and found a log house. I was gladly received. "Where ha ye come fra? The swamp, that awfu' swamp. What were ye doin' there?" etc. "Mony a puir body has been lost in that muckle, cauld, dreary bog and never been found." When I told her I had entered it in search of plants and had been in it all day, she wondered how plants could draw me to these awful places, and said, "It's god's mercy ye ever got out."

[6] Oftentimes I had to sleep without blankets, and sometimes without supper, but usually I had no great difficulty in finding a loaf of bread here and there at the houses of the farmer settlers in the widely scattered clearings. With one of these large backwoods loaves I was able to wander many a long wild fertile mile in the forests and bogs, free as the winds, gathering plants, and glorying in God's abounding inexhaustible spiritual beauty bread. Storms, thunderclouds, winds in the woods—were welcomed as friends.

The words that Muir uses in his essay reveal that he relates to nature as a(n)

emotional professor
objective notetaker
passionate observer
removed reporter

Answers

Answer:

I think it's the third one

Step-by-step explanation:

Sorry if incorrect

hope this helps!

One rectangular solid with a square base has twice the height of another rectangular solid with a square base with the same side length. which statements about the two rectangular solids are true? check all that apply.

Answers

The correct statements about the solids are:

(A) The bases are congruent.(D)The volume of the first solid is twice as much as the volume of the second solid.(E) If the dimensions of the second solid are x by x by h, the first solid has 4xh more.

What are solids?Solid geometry or stereometry is the standard name for the geometry of three-dimensional Euclidean spaces in mathematics. Stereometry is concerned with the volume measurements of various solid forms, such as pyramids, prisms, and other polyhedrons; cylinders; cones; truncated cones, and balls bordered by spheres.

To find which statements are correct:

Congruent base: This is used to indicate that the triangles' bases are the same and that they have the same shape.

The volume of the first triangle is: \(2x^{2} h\)

The volume of the second triangle is: \(x^{2} h\)

Therefore, the correct statements about the solids are:

(A) The bases are congruent.(D)The volume of the first solid is twice as much as the volume of the second solid.(E) If the dimensions of the second solid are x by x by h, the first solid has 4xh more.

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The complete question is given below:
One rectangular solid with a square base has twice the height of another rectangular solid with a square base with the same side length. Which statements about the two rectangular solids are true? Check all that apply.

A) The bases are congruent.

B) The solids are similar.

C) The ratio of the volumes of the first solid to the second solid is 8:1.

D)The volume of the first solid is twice as much as the volume of the second solid.

E) If the dimensions of the second solid are x by x by h, the first solid has 4xh more

surface area than the second solid.

Consider the equation: 1 4 x + 3y − 23 = 42 The variables are: The coefficients are: The constants are:

Answers

Answer:

The variables are: x and y

The coefficients are: 1/4 and 3

The constants are: -23 and 42

Step-by-step explanation:

Given equation:

1/4x + 3y − 23 = 42

The variables are: x and y

The coefficients are: 1/4 and 3

The constants are: -23 and 42

What is the length of each leg of the triangle below?
45
90⁰
26
45⁰
OA. 13-2
OB. 13
O C. 1
O D. 18
OE. √26
OF. 13

What is the length of each leg of the triangle below?45902645OA. 13-2OB. 13O C. 1O D. 18OE. 26OF. 13

Answers

The length of each leg from the given triangle is  13 \(\sqrt{2}\), 13 \(\sqrt{2}\)  respectively.

What is triangle ?

triangle can be defined as figure which contains three sides and three angles and the sum of three angles could be 180 degrees.

Given triangle is right angled triangle,

with given hypothenuse 26.

let other two sides be x and y.

so,

tan45 = x/y

1= x/y

x = y.

from the figure we can say that ,

\(\sqrt{ x^{2} + y^{2} }\) =  26

\(\sqrt{x^{2} +x^{2}}\)  = 26

2\(x^{2}\) = 26*26

\(x^{2}\) = 13*13*2

x = 13 \(\sqrt{2}\)

Hence the other two sides be 13 \(\sqrt{2}\), 13 \(\sqrt{2}\) respectively .

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Connor is a 400m runner His median time is

Answers

Answer: 57.8

Step-by-step explanation:48.7 seconds + 49.3 seconds.= 57.8

Find the solution of the system of equations.
10x-2y=44
-2x-9y=10

Answers

Answer:

x = 4 y = -2

Step-by-step explanation:

10x - 2y = 44

-10x -45y = 50

-47y = 94

y = -2

-2x -9(-2) = 10

-2x + 18 = 10

-2x = -8

x = 4

Given the recurrence relation of the running time for a recursive algorithm, prove by induction that T(n)=O(nlog
3

(n)), i.e. T(n)≤cnlog
3

(n) for some positive constants c and initial input n
0

.
T(n)=2T(n/3)+n
T(3)=10

n>3

Answers

The recurrence relation of the running time for a recursive algorithm, prove by induction that T(n)=O(nlog

3 /2 + log₃((k + 1)/3))

       = (k + 1)(3/2 + log₃(k + 1) - log₃(3))

To prove by induction that T(n) = O(nlog₃(n)), we will first establish a base case and then assume the hypothesis for n and prove it for n + 1.

Base Case:

For n = 3, T(3) = 2T(3/3) + 3 = 2T(1) + 3 = 2(10) + 3 = 23.

Assumption:

Let's assume that for some k ≥ 3, T(n) ≤ cnlog₃(n) holds for all n ≤ k.

Inductive Step:

Now, we need to prove that T(n) ≤ cnlog₃(n) holds for n = k + 1.

T(k + 1) = 2T((k + 1)/3) + (k + 1)

Using the assumption, we have:

T(k + 1) ≤ 2c((k + 1)/3)log₃((k + 1)/3) + (k + 1)

We can simplify the logarithm using the change of base formula:

log₃((k + 1)/3) = logₓ((k + 1)/3) / logₓ(3)

Let's choose x = (k + 1)/3, so logₓ(3) = 1. Thus, we have:

log₃((k + 1)/3) = logₓ((k + 1)/3)

Substituting this back into the inequality, we get:

T(k + 1) ≤ 2c((k + 1)/3)logₓ((k + 1)/3) + (k + 1)

Expanding further:

T(k + 1) ≤ 2c(k + 1)logₓ((k + 1)/3) / 3 + (k + 1)

       = (2c / 3)(k + 1)logₓ((k + 1)/3) + (k + 1)

Since logₓ((k + 1)/3) is positive and (2c / 3)(k + 1) is also positive, we can simplify the inequality further:

T(k + 1) ≤ (2c / 3)(k + 1)logₓ((k + 1)/3) + (k + 1)

       ≤ (2c / 3)(k + 1)logₓ((k + 1)/3) + (k + 1)logₓ((k + 1)/3)

       = (k + 1)(2c / 3 + logₓ((k + 1)/3))

Now, let's choose c such that 2c / 3 ≥ 1. This ensures that (2c / 3 + logₓ((k + 1)/3)) ≥ 1.

Choosing c = 3/2 satisfies the condition. Therefore, we have:

T(k + 1) ≤ (k + 1)(2c / 3 + logₓ((k + 1)/3))

       ≤ (k + 1)(3/2 + logₓ((k + 1)/3))

       = (k + 1)(3/2 + logₓ((k + 1)/3))

       = (k + 1)(3/2 + log₃((k + 1)/3))  [since x = (k + 1)/3]

By simplifying further, we obtain:

T(k + 1) ≤ (k + 1)(3

/2 + log₃((k + 1)/3))

       = (k + 1)(3/2 + log₃(k + 1) - log₃(3))

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Help me pleaseee I really really need help

Help me pleaseee I really really need help

Answers

Answer:

  600 meters

Step-by-step explanation:

You have a map distance of 1.5 cm on a map with a scale of 1:40,000. You want to know the actual distance.

Scale

The map scale of 1:40,000 tells you the actual distance is 40,000 times the map distance:

  (1.5 cm) × 40,000 = 60,000 cm = 600 m

The length of the bridge is 600 meters.

Find the area of the triangle

Find the area of the triangle

Answers

Answer:

Hello! answer: 84 sq mm

Step-by-step explanation:

To find triangle area we would do

base × height × 1/2 or

base × height ÷ 2 So...

14 × 12 = 168 168 ÷ 2 = 84 therefore the area is 84 sq mm HOPE THAT HELPS!

anufacturing machine has a 5% defect rate. if 4 items are chosen at random, what is the probability that at least one will have a defect?

Answers

The probability that at least one will have defect is 0.1855 if a manufacturing machine has a 5 % defect rate.

If manufacturing machine has 5% defect rate. The probability is ration of the number of favorable outcomes.  Probability is the branch of math in which we calculate he number of observation and favorable outcomes of a certain event to be occur. if the manufacturing company has 5% defect rate then there is also to find the number probability of non defect rate.   so,  

Probability of defect (p) = 0.05 

Probability of non defect (q) = 1- 0.05 = 0.95 

4 items are chosen at random .

We have to calculate the probability that at least one will have a defect.

Now ,

P ( at least one will have defect ) = 1 - P ( None will have defect )

P ( none will have defect) = 1 × 1 × 0.81450625

P (none will have defect) = 0.81450625

putting the value we get,

P ( at least one will have defect) = 1 - 0.81450625

P ( at least one will have defect) = 0.18549375

P ( at least one will have defect) = 0.1855

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Number 6 and 7 please hurryyyyyyyy

Number 6 and 7 please hurryyyyyyyy

Answers

hopefully this is right
Number 6 and 7 please hurryyyyyyyy

The Phillipses traveled 717.2 miles to pick up their new boat. At the end of the trip, the odometer read
23,518.9 miles.

Answers

Answer:

what is the question?

Step-by-step explanation:

ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok ok

a.by calculating differences, show that these data can be modeled using a linear function.b.what is the slope for the linear function model-ing high school graduations? explain in practical terms the meaning of the slope.c.find a formula for a linear function that models these data.d.express, using functional notation, the number graduating from high school in 1994, and then use your formula from part c to calculate that value.

Answers

We can show that these data can be modeled using a linear function in the following manner:

a) We must compute the differences in the number of high school graduates in each year in order to model the data using a linear function. For instance, the difference between the 1993 and 1994 graduation rates is 5,479 - 5,410, or 69. This pattern of differences suggests that a linear function can be used to model the data.

The annual change in the number of graduates serves as the slope for the linear function. The slope, for instance, is 69 between 1993 and 1994 and 76 between 1994 and 1995. The slope for the linear function is, in general, the difference between the number of graduates in successive years, therefore it is the slope between graduates in consecutive years.

b) Y = mx + b, where y is the number of graduates, x is the year, m is the slope, and b is the y-intercept, is the formula for a linear function that represents the data. We need to know the values of m and b in order to calculate the formula for the linear function that describes the data.

We can use the slope between any two consecutive years to get the value of m. For instance, m = 69 since the slope from 1993 to 1994 is 69. The number of graduates in the first year of the data, which is the y-intercept, can be used to determine the value of b.

For instance, if the first year of the data is 1993 and that year had 5,479 graduates, then b = 5,479. Consequently, y = 69x + 5,479 is the equation for the linear function that models the data.

c) Functional notation can be used to indicate the number of high school graduates in 1994. The formula is y = 69x + 5,479, where x is the year and y is the total number of graduates. Therefore, y = 69(1994) + 5,479 = 137,123 is the total number of graduates in 1994. We may enter the numbers of x and b into the formula from section c to obtain y = 69 (1994) + 5,479 = 137,123.

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Hungry Harry is a giant ogre with an appetite that fluctuates throughout the day. H(t) models the weight of sheep (in kg) that Harry would like to swallow t hours after he wakes up. Here, t is entered in radians. H(t)=12sin(2pi/24t) + 15 What is the second time after Harry wakes up that he feels like consuming 17kg of sheep?

Answers

The second time after Harry wakes up that he feels like consuming 17kg of sheep is 11.36 hours

How to determine the time?

The function is given as:

H(t) = 12sin(2π/24t) + 15

When the weight is 17kg.

It means that:

H(t) = 17

So, we have:

H(t) = 12sin(2π/24t) + 15 and H(t) = 17

Next, we solve for t using a graphing calculator

From the graph of h(t), we have:

t = 0.64, 11.36, 24.64...... when h(t) = 17

The second time in the above list is

t = 11.36

Hence, the second time after Harry wakes up that he feels like consuming 17kg of sheep is 11.36 hours

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Hungry Harry is a giant ogre with an appetite that fluctuates throughout the day. H(t) models the weight

Your painting company just completed one of the biggest jobs you've had. Based on that, you have been tasked with
an even bigger job. You calculated that you will have to paint a Surface Area with triple the dimensions of the
previous job. How much more paint will you need to buy?
9 times as much
6 times as much
2 times as much
3 times as much

Plz HURRY

Answers

Answer:

3 times

Step-by-step explanation:

if the surface area of the job is 3 times what you had before, you will need 3 times the paint.

can someone tell me all the answers for 2 - 5/6

Answers

Answer:

1.17

Step-by-step explanation:

1.16666666667 ,, i guess you round it off

Answer 1.7
You have to round this is the original answer 1.6666 and then round the then nearest number which is 7
1.7

Help me please :((((

Help me please :((((

Answers

Answer:

y=3x-5

Step-by-step explanation:

Everytime x increases by 1 y increases by 3

Therefore the slope is 3

To find b plug in a coordinate

(1,-2) for example

-2= 3*1+b

-2=3+b

-5=b

Therefore the equation is

y=3x-5

y=3x-5
i hope this helpsss <33

a student has a class that is supposed to end at 9:00am and another that is supposed to begin at 9:15am. suppose the actual ending time of the 9am class is normally distributed random variable (x1) with a mean of 9:02 and a standard deviation of 2.5 minutes and that the starting time of the next class is also a normally distributed random variable (x2) with a mean of 9:15 and a standard deviation of 3 minutes. suppose also that the time necessary to get from one class to another is also a normally distributed random variable (x3) with a mean of 10 minutes and a standard deviation of 2.5 minutes. what is the probability that the student makes it to the second class before the second lecture starts? (hint: assume x1, x2 and x3 are independent also think linear combinations)

Answers

The probability that the student makes it to the second class before it starts is very close to 0.

To find the probability that the student makes it to the second class before it starts, we can use the concept of linear combinations of random variables and the properties of normal distributions.

Let's define the random variable X as the total time it takes for the student to transition from the end of the first class to the start of the second class. Since X is a linear combination of independent normally distributed random variables (X1, X2, X3), we can use their means and variances to calculate the mean and variance of X.

The mean of X is the sum of the means of X1, X2, and X3:

μX = μ1 + μ2 + μ3 = 9:02 + 9:15 + 10 = 28:17 minutes.

The variance of X is the sum of the variances of X1, X2, and X3:

σX^2 = σ1^2 + σ2^2 + σ3^2 = (2.5)^2 + (3)^2 + (2.5)^2 = 15.25 minutes^2.

Now, we need to calculate the probability that X is less than or equal to 0, meaning the student arrives before the second lecture starts. Since X follows a normal distribution, we can standardize the variable and calculate the probability using the standard normal distribution table.

Z = (0 - μX) / σX = (0 - 28:17) / √15.25 ≈ -9.43.

Using the standard normal distribution table or a calculator, we can find the probability corresponding to Z = -9.43. The probability is essentially 0, as the value is significantly far in the left tail of the standard normal distribution.

Therefore, the probability that the student makes it to the second class before it starts is very close to 0.

To learn more about  probabilty click here:

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Pleaseeeeee helpppppp fasttttttt 11 pointssss

Pleaseeeeee helpppppp fasttttttt 11 pointssss

Answers

Answer:

x = 9

m∠1 = m∠2 = 54°

Step-by-step explanation:

Two lines r and s are the parallel lines and a transversal line is intersecting these lines at two distinct points.

a). ∠1 ≅ ∠2 [Corresponding angles]

    Therefore, m∠1 = m∠2

    (63 - x)° = (72 - 2x)°

    2x - x = 72 - 63

    x = 9

b). m∠1 = (63 - x)°

            = 63 - 9

            = 54°

    m∠2 = (72 - 2x)°

             = 72 - 18

             = 54°

20% of Aussies have blue
eyes. If 4 Aussies in a play
group have blue eyes, how
many Aussies are in the
group?

Answers

Answer:

20 Aussies

Step-by-step explanation:

20% times 5 = 100%

4 times 5 = 20 Aussies

So, there are 20 Aussies in a group.

Answer:

20

Step-by-step explanation:

4/20%

4/\(\frac{2}{10}\)

4 x \(\frac{10}{2}\) = \(\frac{40}{2}\) = 20

a box of 12 tacos cost $10.20

Answers

If you’re looking for the price of one taco, answering the question goes as follows:
Divide 10.20 by 12
.85
85 cents is the cost per taco
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