(1 point) Find the minimum distance from the point Q(-4,-2, 1) to the plane 6x1 - 7x2 + 1x3 = -6. Minimum Distance

The requreid Miriam's test does not provide significant evidence that the true population mean is less than 18.

Since the sample size is small (n = 7) and the population standard deviation is unknown, we should use a t-test for this hypothesis test.

The test statistic is calculated as follows:

t = (x - μ) / (s / √n)

Given that Miriam's test statistic is t = -1.9, we can estimate the p-value associated with this test statistic. This denotes the probability of observing a test statistic as extreme as -1.9 or more extreme, assuming the null hypothesis is true.

Using a t-distribution table with 6 degrees of freedom (n-1), we find that the p-value for a one-tailed test at the 5% significance level is approximately 0.051.

Since the p-value (0.051) is greater than the significance level (0.05), we fail to reject the null hypothesis. We do not have sufficient evidence to conclude that the population mean is less than 18 at a 5% level of significance.

Thus, Miriam's test does not provide significant evidence that the true population mean is less than 18.

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The area of the region that lies inside the first curve and outside the second curve is 13π/4.

To find the area of the region that lies inside the first curve and outside the second curve, we need to find the points of intersection of these two curves.

Setting the two equations equal to each other, we have:

3 cos(θ) = 4 − cos(θ)

Simplifying, we get:

4 cos(θ) = 4

cos(θ) = 1

θ = 0

So the two curves intersect at θ = 0.

To find the area of the region between the curves, we integrate the difference of the two equations with respect to θ over the interval [0, π]:

A = ∫[0,π] (4 - cos(θ))^2/2 - (3cos(θ))^2/2 dθ

Simplifying, we get:

A = ∫[0,π] 8 - 7cos(θ) + cos^2(θ) dθ

Using trigonometric identities, we can simplify this to:

A = ∫[0,π] 13/2 - 7/2 cos(2θ) dθ

Evaluating the integral, we get:

A = [13/2θ - 7/4 sin(2θ)] [0,π]

A = 13π/4 - 0

A = 13π/4

Therefore, the area of the region that lies inside the first curve and outside the second curve is 13π/4.

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Answer:

$35

Step-by-step explanation:

jus trust

Yes, its true that the questionnaire is very carefully constructed by an individual to provide the measurement instrument.  

A questionnaire is a studies device which includes a sequence of questions for the motive of amassing facts from respondents. Questionnaires may be concept of as a form of written interview. A questionnaire is a listing of questions or gadgets used to collect facts from respondents approximately their attitudes, experiences, or opinions.

Questionnaires may be used to acquire quantitative and/or qualitative facts. Questionnaires are generally utilized in marketplace studies in addition to withinside the social and fitness sciences. Questionnaires are typically taken into consideration to be excessive in reliability. This is due to the fact it's miles feasible to invite a uniform set of questions. Any troubles withinside the layout of the survey may be ironed out after a pilot study. The greater closed questions used, the greater dependable the studies.

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Answer:

(16,1)

Step-by-step explanation:

The largest possible volume of a rectangular parcel where the smallest end is a square that can be sent by mail according to USPS regulation is 11664 cubic inches.

The volume of a rectangular parcel with dimensions l, w, and h is lwh. We can express the volume of the rectangular parcel in terms of one variable, say l, as lwh = l(108 - 2l)h. We want to maximize this expression subject to the constraint that l is a positive number less than 54 (the maximum value for l that still allows the parcel to fit within the 108-inch limit).

Taking the derivative of the volume with respect to l and setting it equal to zero, we find that the maximum volume occurs when:

l = (27 inches)

At this value, the dimensions of the parcel are:

l = 27 inches

w = 27 inches

h = 2(108 - 2l) = 2(72) = 144 inches

The volume of the parcel is then:

lwh = (27)(27)(144) = 11664 cubic inches

This is the largest possible volume of a rectangular parcel where the smallest end is a square that can be sent by mail according to USPS regulations.

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\(\huge\color{lime}\boxed{\colorbox{black}{Answer : - }}\)

sec² θ (1 + sin θ) (1 - sinθ ) = k

sec² θ(1-sin²θ ) = k

sec² θ cos² θ = k

sec² θ. 1 /sec²θ = k

1 = k

.. k = 1.

The directional derivative is (-3/2√10) + (2 ln(2)/√10).

To compute the directional derivative of f(x,y) = y² ln(x) at the point (2,1) in the direction of the vector v = -3i + j, first find the gradient of f and then take the dot product with the unit vector in the direction of v.

The gradient of f(x, y) is given by (∂f/∂x, ∂f/∂y) = (y²/x, 2y ln(x)). At the point (2,1), this becomes (1/2, 2 ln(2)).

Next, find the unit vector of v by dividing v by its magnitude: u = v/||v|| = (-3, 1)/√((-3)² + 1²) = (-3, 1)/√10.

Now, take the dot product of the gradient and the unit vector: ((1/2, 2 ln(2)) · (-3/√10, 1/√10)) = (-3/2√10) + (2 ln(2)/√10).

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Answer:

Step-by-step explanation:

Covert 21 out of 175 into percentage:

We need percentage

\(\\ \bull\sf\dashrightarrow \dfrac{21}{175}\times 100\)

\(\\ \bull\sf\dashrightarrow \dfrac{21}{7}\times 4\)

\(\\ \bull\sf\dashrightarrow 3(4)\)

\(\\ \bull\sf\dashrightarrow 12\%\)

Each box needs to have a minimum space of 576 cubic inches to hold the toy.

What is a cuboid?

A cuboid is a three-dimensional solid shape that has six rectangular faces, where each face meets at right angles with adjacent faces.

To calculate the space required for each box to hold a toy that is 8 inches tall by 12 inches wide and 6 inches deep, we need to calculate the volume of the toy.

The volume of the toy can be calculated as:

Volume = height x width x depth

Volume = 8 inches x 12 inches x 6 inches

Volume = 576 cubic inches

Therefore, each box needs to have a minimum space of 576 cubic inches to hold the toy.

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Answer:

I would think C, because they're all even.

Step-by-step explanation:

I think

\(15^{5} \div 15 ^{7} \)

\(15 ^{ 5 - 7} \)

\(15 ^{ - 2} \)

\( \tt \: alternate \: from : \\ \frac{1}{15 ^{2} } \)

Answer: Width = 5.7 feet, Length = 10.5 feet

Step-by-step explanation:

Let the width be w. Then, the length is 2w-0.9.

\(w(2w-0.9)=59.85\\\\2w^2 -0.9w-59.85=0\\\\w =\frac{-(-0.9) \pm \sqrt{(-0.9)^2 -4(2)(-59.85)}}{2(2)}\\\\w =5.7\\\\\implies 2w-0.9=10.5\)

Answer:

1 row = 205plants

9*205=1845plants

Therfore 1845 plants are there in 9 rows of tomato.

Step-by-step explanation:

Please mark as brainliest.

Even if R is anti-reflexive, R2 may not necessarily be anti-reflexive. It depends on the specific properties and composition of the relation R.

Let R be a relation that is reflexive and transitive. We want to prove that R2 = R for any relation R with these two properties.

To prove this, we need to show that for any ordered pair (a, b), (a, b) ∈ R2 if and only if (a, b) ∈ R.

First, let's consider (a, b) ∈ R2. By definition, (a, b) ∈ R2 means that there exists an element c such that (a, c) ∈ R and (c, b) ∈ R.

Since R is reflexive, we know that (a, a) ∈ R and (b, b) ∈ R.

By the transitivity of R, if (a, c) ∈ R and (c, b) ∈ R, then (a, b) ∈ R.

Therefore, (a, b) ∈ R2 implies (a, b) ∈ R.

Now, let's consider (a, b) ∈ R. Since R is reflexive, we have (a, a) ∈ R and (b, b) ∈ R.

By the definition of R2, (a, a) ∈ R2 and (b, b) ∈ R2.

Since R is transitive, if (a, a) ∈ R2 and (a, b) ∈ R2, then (a, b) ∈ R2.

Therefore, (a, b) ∈ R implies (a, b) ∈ R2.

We have shown that for any ordered pair (a, b), (a, b) ∈ R2 if and only if (a, b) ∈ R. Hence, R2 = R.

If the relation R is anti-reflexive, it is not necessarily true that R2 is anti-reflexive.

To understand why, let's consider an example. Let R be a relation defined on the set of integers such that R contains the ordered pairs (a, b) where a < b.

In this case, R is anti-reflexive because for any integer a, (a, a) is not in R.

Now, let's consider R2. R2 is the composition of R with itself. If (a, b) ∈ R and (b, c) ∈ R, then (a, c) ∈ R2.

In our example, if we take a = 1, b = 2, and c = 3, we have (1, 2) ∈ R and (2, 3) ∈ R. Therefore, (1, 3) ∈ R2.

However, (1, 1) is not in R2 because (1, 1) is not in R. Therefore, R2 is not anti-reflexive in this case.

This example demonstrates that even if R is anti-reflexive, R2 may not necessarily be anti-reflexive. It depends on the specific properties and composition of the relation R.

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After attempting to determine the mass of a few objects, Lashandra realizes there must be something wrong with her formula. What is Lashandra's error? She should have multiplied by 2 instead of dividing by 2. She should have multiplied by K equals StartFraction one-half EndFraction m v squared.!!

Answer:

32 songs

Step-by-step explanation:

60 - 12 = 48

48 ÷ 1.5 = 32

32 songs

The virtual condition for the .376² MMC pin with a perpendicularity tolerance of .008² diameter at MMC is approximately .001131.

To determine the virtual condition for a .376² MMC (Maximum Material Condition) pin with a perpendicularity tolerance of .008² diameter at MMC, we need to calculate the tolerance zone.

The perpendicularity tolerance specifies the allowable deviation of the pin from a perfect perpendicular orientation. The tolerance zone is defined as a cylindrical volume around the pin, with a diameter equal to the perpendicularity tolerance.

In this case, the perpendicularity tolerance is given as .008² diameter at MMC. Since the diameter at MMC is .376², we can calculate the tolerance zone as follows:

Tolerance zone = .008² * .376²

Simplifying the calculation:

Tolerance zone = .008 * (.376 * .376)

Tolerance zone = .008 * .141376

Tolerance zone = .001131

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Answer:

√{369×369}=√369²=369 is your answer

Answer:

your answer will be 369

Step-by-step explanation:

......

Answer:

What is the question?

Step-by-step explanation:

Answer:

OK!!!!!!!!!!!!!!!1

Step-by-step explanation:

Answer: What do you need help with? I think if you put out you will try and help.

Answer:

t + c <= 17

Step-by-step explanation:

This inequality states that the total number of tables and chairs sold (t + c) must be less than or equal to 17, in order to satisfy the constraint that the store can ship at most 17 pieces of furniture per day.

As per the given Ratio difference between the amount of money spent and the amount of money saved in a week is $2.

A ratio is an ordered pair of numbers a and b, denoted by the symbol a / b, where b does not equal zero. A proportion is an equation that sets two ratios equal to each other.

The ratio formula can be used to represent a ratio as a fraction. For any two quantities, say a and b, the ratio formula is a:b = a/b. Because a and b are separate amounts for two portions, the total quantity is given as (a + b).

et 5x be the money he spends and 4x be the amount he saves

therefore, 5x+4x= 18

9x= 18

x= 18/9= 2

Tom spends, 5×2 = $10

and he saves, 4×2= $8

Difference, = $10-$8= $2

Therefore, as per the given ratio in the question difference between the amount of money spent and the amount of money saved in a week is $2.

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Tom receives $18 from his father in a week. The ratio of the amount of

the money he spends to the amount of money he saves in a week is 5:4

What is the difference between the amount of money spent and

amount of money saved in a week?

The required all three situation are explained to the detector.

a. The equation for the distance-time graph of the student's motion is:

distance = rate × time + initial distance

where rate is the speed at which the student is walking (2 feet per second), time is the elapsed time in seconds, and initial distance is the distance between the student and the motion detector at the start (15 feet). This can be written in slope-intercept form as:

distance = 2t + 15

where the slope is 2 (the rate of change of distance with respect to time) and the y-intercept is 15 (the initial distance from the motion detector).

b. In this situation, the slope of the equation (2) represents the speed at which the student is walking towards the motion detector. It tells us that for every one second that passes, the student moves 2 feet closer to the motion detector. In other words, the slope represents the rate of change of distance with respect to time.

c. The y-intercept of the equation (15) represents the initial distance between the student and the motion detector. It tells us that at the start of the motion detector recording, the student was 15 feet away from the detector. When time is 0 (at the start), the distance traveled is just the initial distance, which is the y-intercept.

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A customer would  be charged $ 52 for an international phone call that started at 9:35 p.m. and ended at 11:15 p.m. the same day.

Charge for first 5 charged = $ 4.50

Charge for additional time = $ 0.50 per minute

Starting time = 9:35 p.m.

End time = 11:15 p.m.

Total minutes = 100 minutes

Total charge = 4.50 + (95 x 0.50)

                  = 4.50 + 47.50

                  = 52.00

Hence, a customer would  be charged $ 52 for an international phone call that started at 9:35 p.m. and ended at 11:15 p.m. the same day i.e. for 100 minutes.

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