1. Since minerals come from non-living things, they are
A. crystals
B. solids
C. coloured
D. inorganic substances​

Answer:

Volume

Explanation:

yo brother these are so easy, just study bro. I helped you answer 3 already lol

whatever.

Hope I helped :)

Answer:

Explanation:

To solve this problem, we can use the ideal gas law, which relates the pressure, volume, temperature, and number of moles of a gas:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the initial temperature of 25 °C to Kelvin:

T1 = 25 °C + 273.15 = 298.15 K

Then, we can use the initial conditions to find the number of moles of gas:

n = PV/RT1

where we can assume that the pressure is atmospheric pressure (1 atm) and R is the ideal gas constant (0.0821 L·atm/mol·K).

n = (1 atm)(0.5 L)/(0.0821 L·atm/mol·K)(298.15 K) = 0.0204 mol

Next, we can use the final temperature of 54 °C (327.15 K) to find the final volume:

V2 = nRT2/P

V2 = (0.0204 mol)(0.0821 L·atm/mol·K)(327.15 K)/(1 atm) = 0.551 L

Finally, we can subtract the initial volume from the final volume to find the potential volume increase:

ΔV = V2 - V1 = 0.551 L - 0.5 L = 0.051 L

Therefore, if the aerosol can is heated to 54 °C, the potential volume of the gas contained in the can would increase by approximately 0.051 L. However, this increase in volume would cause a corresponding increase in pressure, which could lead to an explosion if the can is not designed to withstand the increased pressure.

Answer:

By far the most abundant volcanic gas is water vapor, which is harmless. However, significant amounts of carbon dioxide, sulfur dioxide, hydrogen sulfide and hydrogen halides can also be emitted from volcanoes.

Answer:

Atomic Mass of Nitrogen is 14.01

Explanation:

Explanation:

The basic concepts behind Organic farming are: ... Control of pests, diseases, and weeds is achieved largely by the development of an ecological balance within the system and by the use of bio-pesticides and various cultural techniques such as crop rotation, mixed cropping, and cultivation.

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Answer:

Solid

Explanation:

Gas and liquids cant have definite shape which should be crossed off after you read shape because gas goes everywhere and liquids are too runny

Answer:

type of gasoline

Explanation:

Independent variable in an experiment is the variable that the experimenter changes or manipulates in order to bring out a measurable outcome or response.

In this experiment involving how the type of gasoline put in a car affect how fast the car can drive, the independent variable is the TYPE OF GASOLINE because it is what the experimenter changes in order to see it's effect on the speed of the car (dependent variable).

The order to understand the effects of adding CaCl2 to water, we need to discuss the concepts of boiling point elevation and freezing point depression. When a solute, such as CaCl2, is dissolved in a solvent, like water, the boiling point of the solution is generally higher than that of the pure solvent.

This is due to the solute particles interfering with the solvent molecules' ability to escape the liquid phase, requiring more energy (higher temperature) for the liquid to transition into the vapor phase. Freezing Point Depression Similarly, adding a solute like CaCl2 to a solvent like water will also lower the freezing point of the solution compared to the pure solvent.  Considering the given information, we have 0.50 moles of CaCl2 dissolved in 100g of H2O at 25°C and standard pressure. This solution, compared to the boiling point and freezing point of 100g of H2O at standard pressure, will have A higher boiling point: The presence of CaCl2 will cause the boiling point of the solution to be higher than that of pure water (100°Cat standard pressure. A lower freezing points the presence of CaCl2 will also cause the freezing point of the solution to be lower than that of pure water (0°Cat standard pressure). In summary, the solution containing 0.50 moles of CaCl2 in 100g of H2O at standard pressure will have a higher boiling point and a lower freezing point compared to 100g of pure water at standard pressure.

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Answer:

the reaction will come to a halt and the other reactant will still be present.

Answer:

Just add and multiply after divding and lol

Explanation: add then add

Answer:

oil, ores, and fossils.

Answer:

1

Explanation:

Answer:

I will try to solve these problems

The bromine atom in BrF3 is sp3d hybridized, in BrO2- it is sp3 hybridized, and in BrF5 it is sp3d2 hybridized.

The hybridization of bromine in each of the following compounds is as follows:

a) BrF3:

The central atom, bromine (Br), in BrF3 undergoes sp3d hybridization. It forms three sigma bonds with three fluorine atoms and has two lone pairs of electrons. The three sigma bonds are formed by overlapping of the sp3d hybrid orbitals of bromine with the 2p orbitals of the fluorine atoms.

b) BrO2-:

The central atom, bromine (Br), in BrO2- undergoes sp3 hybridization. It forms two sigma bonds with two oxygen atoms and has two lone pairs of electrons. The two sigma bonds are formed by overlapping of the sp3 hybrid orbitals of bromine with the 2p orbitals of the oxygen atoms.

c) BrF5:

The central atom, bromine (Br), in BrF5 undergoes sp3d2 hybridization. It forms five sigma bonds with five fluorine atoms and has one lone pair of electrons. The five sigma bonds are formed by overlapping of the sp3d2 hybrid orbitals of bromine with the 2p orbitals of the fluorine atoms.

Hybridization is a concept used to describe the mixing of atomic orbitals to form new hybrid orbitals in a molecule. It helps to explain the molecular geometry and bonding in the molecule. The hybridization of an atom depends on the number of sigma bonds it forms and the number of lone pairs of electrons it possesses.

In summary, the bromine atom in BrF3 is sp3d hybridized, in BrO2- it is sp3 hybridized, and in BrF5 it is sp3d2 hybridized. The hybridization of bromine determines the shape and geometry of the molecules and provides insights into the nature of their chemical bonding.

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Answer:

2,400,000 torr (3 s.f.)

Explanation:

Convert the pressure from Pascal to atm first:

\(\boxed{1 \: atm = 101325 \:Pa }\)

3.20 ×10⁸ Pa

= [(3.20 ×10⁸) ÷101325] atm

= 3158.2 atm (5 s.f.)

Convert atm to torr:

\(\boxed{1 \: atm = 760 \: torr}\)

3158.2 atm

= (3158.2 ×760) torr

= 2400000 torr (3 s.f.)

luster refers to how a mineral reflects light is the most accurate description of luster

lustre, in mineralogy, the appearance of a mineral surface in terms of its light-reflective qualities. Luster depends upon a mineral’s refractive power, diaphaneity (degree of transparency), and structure. Variations in these properties produce different kinds of luster, whereas variations in the quantity of reflected light produce different intensities of the same luster. The kind and intensity of lustre is the same for crystal faces of like symmetry but may be different on those with different symmetry.

The kinds of luster are usually described as follows (the prefix “sub-,” as in submetallic, is used to express imperfect luster of the kind): metallic, waxy, vitreous, silky, pearly, and dull are all types of luster.

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4.37 g/cm³ is the density of rhodium in grams per cubic centimeters.

What is the atomic weight of rhodium?

The atomic weight of rhodium is 102.9 g/mol. This means that one mole of rhodium atoms has a mass of 102.9 grams. Rhodium is a rare, silvery-white metal that is highly reflective and has a high melting and boiling point. It is often used in catalytic converters, electroplating, and jewelry. The atomic weight of rhodium is an important factor in determining its physical and chemical properties.

To calculate the density of rhodium, we need to divide its atomic weight by its volume. The volume of an fcc crystal can be found by using the formula:

V = a^3/2

where a is the atomic radius. Substituting the values, we get:

V = (0.1345 nm)^3/2 = 2.36 x 10⁻²³ cm³ .

Therefore, the density of rhodium is 102.9 g/mol / 2.36 x 10⁻²³ cm³ = 4.37 g/cm³.

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An ionic salt, is more soluble in water

Polar substances  are generally more soluble in water compared to nonpolar substances. This is because water is a polar solvent, meaning that it has a partial positive charge on one end and a partial negative charge on the other end due to the asymmetric arrangement of its atoms.

Polar substances also have a partial positive and partial negative charge on different parts of their molecules, which allows them to interact with water molecules through electrostatic interactions,

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In perovskite, the oxidation number of titanium (Ti) can vary depending on the specific compound and its composition. However, in many perovskite structures, titanium is commonly found in the +4 oxidation state (Ti4+).

In perovskite, the general formula is represented as ABX3, where A and B are cations and X is an anion. In this structure, titanium is typically the B-site cation, and it tends to exhibit a +4 oxidation state to maintain charge neutrality.

It's important to note that there can be variations and substitutions within the perovskite structure, leading to different oxidation states for titanium or other cations.

Therefore, the oxidation state of titanium in perovskite can vary depending on the specific compound and its composition.

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In the preceding equation, 6.67 moles of boric acid (\(H_3BO_3\)) will react to generate 10 moles of water (\(H_2O\)).

To determine the number of moles of boric acid that react in the equation to produce 10 moles of water, we need to examine the balanced chemical equation and use stoichiometry.

1. Begin by examining the balanced chemical equation for the reaction involving boric acid and water. Let's assume the equation is:

  \(3H_2O\) + \(3H_2O\) -> \(B_2O_3\) + \(6H_2O\)

2. From the balanced equation, we can see that 2 moles of boric acid (H3BO3) react with 3 moles of water (\(H_2O\)) to produce 6 moles of water (\(H_2O\)).

3. Use the given information that 10 moles of water (\(H_2O\)) are produced. Since the stoichiometric ratio between boric acid and water is 2:3, we can set up a proportion to find the number of moles of boric acid:

  2 moles \(H_3BO_3\) / 3 moles \(H_2O\) = x moles \(H_3BO_3\) / 10 moles \(H_2O\)

4. Cross-multiply and solve for x:

  (2 moles \(H_3BO_3\))(10 moles \(H_2O\)) = (3 moles \(H_2O\))(x moles \(H_3BO_3\))

  20 moles \(H_2O\) = 3x moles \(H_3BO_3\)

5. Divide both sides of the equation by 3 to isolate x:

  x moles \(H_3BO_3\) = (20 moles \(H_2O\)) / 3

6. Calculate the value of x:

  x moles \(H_3BO_3\) ≈ 6.67 moles \(H_3BO_3\)

Therefore, approximately 6.67 moles of boric acid (\(H_3BO_3\)) will react to produce 10 moles of water (\(H_2O\)) in the given equation.

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The first quantum number of a 3p₃ electron in phosphorus 1s2, 2s2, 2p6, 3s2, 3p3 is 3.

Quantum numbers are a set of numbers that describe the position and energy of an electron in an atom.

Principal, azimuthal, magnetic, and spin quantum numbers are the four types of quantum numbers.

Thus, the first quantum number of a 3p₃ electron in phosphorus 1s2, 2s2, 2p6, 3s2, 3p3 is 3.

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Answer:

n=3

Explanation:

i just took the test:)

Answer:    36.9 g

Explanation:

P4 + 5O2 = P4O10  Balanced equation

moles P4 present = 23.9 g x 1 mole/123.88 g = 0.193 moles

moles O2 present = 20.8 g x 1 mol/32 g = 0.65 moles O2

From balanced equation, mole ratio O2 : P4 is 5:1.  Is 0.65 moles O2 5x 0.193 moles?  NO.  You don't have enough O2.

O2 is limiting in this reaction.

theoretical moles of P4O10 = 0.65 moles O2 x 1 mole P4O10/5 moles O2 = 0.13 moles P4O10

mass of P4O10 produced = 0.13 moles x 283.9 g = 36.9 g

According to the give percent yield, the   observed yield of P₄O₁₀ is 9.514 g .

Percent yield is defined as the ratio of actual yield to the theoretical yield multiplied by 100. If the actual and theoretical yield are same then the percent yield is 100%.If actual yield is less than the theoretical yield then the percent yield is less than 100%.Reason of this condition arising is the incompletion of reaction or loss of sample during recovery process.

In cases where percent yield is over 100% it indicates that more sample is recovered than the predicted amount.This condition arises when there are other simultaneous reactions taking place leading to the formation of product. It can also arise if there is incomplete removal of impurities from the sample .

In the given example, observed yield is calculated by first calculating theoretical yield,which in this case is as follows, 123.88 g phosphorous gives 283.88 g of  P₄O₁₀

Hence, 6.20 g of phosphorous will produce 6.20×283.88/123.88=14.20 g.

Now, the observed yield is calculated as, percent yield×theoretical yield/100=67×14.20/100=9.514 g.

Thus, the observed yield of  P₄O₁₀ is 9.514 g.

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Answer:

The reaction involved in a campfire (burning of wood) includes:

\(${{C}_{6}}{{H}_{12}}{{O}_{6}}+{{O}_{2}}\xrightarrow{\Delta }C{{O}_{2}}(g)+{{H}_{2}}O(g)+Energy+Ash$\)

Explanation:

We can clearly find here that when wood burns in presence of oxygen, there is a loss of mass in the form of gaseous products. Thus, in this case, the law of conservation of mass does not come true.

I support Lisa’s statement but there is a fact associated with the law of conservation of mass. The law stands true only when there is a definite mass of the reactants and products mentioned.

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The treatment requirement (% removal) in the agricultural waste discharge to achieve 50mg/L concentration in the withdrawal location 80 km downstream is 99.57%

a. Control Volume

The schematic diagram of the control volume is given below.

b. Steady-state Phosphate concentration in water withdrawn 90 km downstream

The steady-state phosphate concentration in the water withdrawn 90 km downstream is given by:

C2 = (Q1C1 + Q2C2)/(Q1 + Q2)

Where,

C2 = Concentration of phosphate in the water withdrawn 90 km downstream

C1 = Concentration of phosphate in the upstream water (25 ppm)Q1 = Upstream flow (40 m 3/s)Q2 = Agricultural discharge (2.5 m^3/s)C2 = ((40 x 25) + (2.5 x 1000)) / (40 + 2.5)C2 = 59.3 ppm

Therefore, the steady-state phosphate concentration in the water withdrawn 90 km downstream is 59.3 ppm.c. Treatment requirement (% removal) in the agricultural waste discharge to achieve 50mg/L concentration in the withdrawal location 80 km downstream

The concentration of the waste-stream that will produce 50mg/L downstream concentration is given by:

50 = (Q1C1 + Q2C2)/(Q1 + Q2)C2 = ((40 x 25) + (2.5 x C2))/(40 + 2.5)50 = (1000 x 2.5) / (40 + 2.5) + (40 x 25) / (40 + 2.5)C2 = 4.3 ppm

The % removal from the difference of the influent wastewater concentration with respect to the initial waste-stream concentration is given by:

% removal = (C in - C out) / C in x 100Where,Cin = Influent wastewater concentration (1000 ppm)

C out = Concentration of waste-stream required to produce 50 ppm downstream concentration (4.3 ppm)\% removal = (1000 - 4.3) / 1000 x 100\% removal = 99.57%

Therefore, the treatment requirement ( % removal) in the agricultural waste discharge to achieve 50mg/L concentration in the withdrawal location 80 km downstream is 99.57%.

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Answer:

1000 gram

Explanation:

because mass is constant everywhere

Answer:

The Pressure  inside the container 5.56 atm

Explanation:

Given that:

the mass of CO2 = 50.0g

molar mass of CO2= 44 g/mol

So; the number of moles of CO2 = mass/molar mass

= 50.0 g/44 g/mol

= 1.1364 mol

Volume of the container = 5.0 L

Temperature = 25°C = ( 25+273.15)K = 298.15 K

universal gas constant R  = 0.08206 L atm mol⁻¹ K⁻¹

Using Ideal Gas Equation PV = nRT

P = nRT/V

P = (1.1364 × 0.08206  ×  298.15) / 5.0

P =  27.80337718/ 5.0

P = 5.560675436 atm

P ≅ 5.56 atm

Answer:

5N would be the net force if i'm correct 5N and 5N cancle each other out then all your left with would be 5N

Explanation:

BTW whats your

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The following chemical weathering process that is responsible for the breakdown of most silicate minerals is E. hydrolysis.

Hydrolysis is a chemical reaction between water and minerals that form new compounds. In this process, water breaks down the minerals, and the hydrogen ions (H⁺) and hydroxide ions (OH⁻) from the water combine with the mineral ions, forming new minerals.

Hydrolysis is an important process in the breakdown of silicate minerals, which are the most abundant minerals in the Earth's crust. The process is responsible for the formation of clay minerals, which are important components of soils and sediments. In summary, hydrolysis is the most significant chemical weathering process that breaks down most silicate minerals. So the correct answer is E. hydrolysis  is responsible for the breakdown of most silicate minerals.

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