Both the given statements are true
1. Two equilateral triangles are always similar: True.
An equilateral triangle is a triangle in which all three sides are equal. Since two equilateral triangles have the same shape and size, they are always similar. Similarity means that the corresponding angles are equal, and the corresponding sides are in proportion.
2. The diagonals of a rhombus are perpendicular to each other: True.
In a rhombus, opposite sides are parallel, and all sides have equal length. The diagonals of a rhombus bisect each other at right angles, which means they are perpendicular to each other. This property holds true for all rhombuses, regardless of their size or orientation.
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Given question is incomplete, the complete question is below
State true or false
1. Two equilateral triangles are always similar.
2. The diagonals of a rhombus are perpendicular to each other.
A cone has a radius of 3 and a height given by the expression 2a. which expression represents the volume of the cone? 2aπ units3 4a2π units3 6aπ units3 24aπ units3
The expression that represents the volume of the cone is 6πa units^3. Option c is correct choice.
The volume of a cone is calculated using the formula V = (1/3) * pi * r^2 * h, where V is the volume, r is the radius, and h is the height. In this problem, we are given that the cone has a radius of 3, which means that r = 3. We are also given that the height of the cone is 2a, which means that h = 2a.
Substituting these values into the formula,
V = (1/3) * pi * 3^2 * 2a
Simplifying the expression inside the parentheses gives,
V = (1/3) * pi * 9 * 2a
V = 6 * pi * a
Option c is correct. This means that the volume of the cone is directly proportional to the value of a, since pi and 6 are constants. If a is doubled, for example, then the volume of the cone would also double.
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--The complete question is, A cone has a radius of 3 and a height given by the expression 2a. which expression represents the volume of the cone?
a. 2πa units^3
b. 4πa units^3
c. 6πa units^3
d. 24πa units^3--
g the physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. the distribution of the number of daily requests is bell-shaped and has a mean of 57 and a standard deviation of 8. using the empirical rule (as presented in the book), what is the approximate percentage of lightbulb replacement requests numbering between 57 and 73?
The approximate percentage of bulb replacement requests between 57 and 73 is 95%.
How do we calculate the approximate percentage?The empirical rule, also known as the 68-95-99.7 rule, is used to determine the percentage of observations that lie within a specified number of standard deviations of the means in a normal distribution. The rule states that approximately:
68% of the observations are within one standard deviation of the means
95% of the observations are within two standard deviations of the mean
99.7% of the observations are within three standard deviations of the mean
The given problem states that the distribution of the number of daily requests for fluorescent light bulbs at a university is bell-shaped and has a mean of 57 and a standard deviation of 8. Therefore, to find the approximate percentage of light bulb replacement requests between 57 and 73, we need to find the number of standard deviations of the means that are 73 and 57.
\(z-score = (x - \mu) / \sigma\)
Where
\(z-score\) is the number of standard deviations from the mean.\(x\) is the value of the observation\(\mu\) is the population mean\(\sigma\) is the population standard deviationFor x = 73,
\(z-score = (73 - 57) / 8\\z-score = 2\)
For x = 57,
\(z-score = (57 - 57) / 8\\z-score = 0\)
Therefore, observations 57 and 73 are separated by two standard deviations.
Using the empirical rule, we can say that approximately 95% of the observations lie within two standard deviations of the mean. Therefore, approximately 95% of the daily requests for replacement of fluorescent bulbs in the university are between 57 and 73.
Thus, the approximate percentage of bulb replacement requests between 57 and 73 is 95%.
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Write the quadratic function f(x)=2(x+1)^2-8 in standard for and intercept form.
I know how to write it in standard form- f(x)=2x^2+4x-6
But I don’t know how to write it in intercept form.
Please explain.
The quadratic function f(x)=2(x+1)^2-8 in standard for and intercept form is 2x^2+4x-6 and (x-1)(x+3).
Given:
f(x) = 2(x+1)^2 - 8
= 2(x^2+1+2x) - 8
= 2x^2 + 2 +4x - 8
= 2x^2+4x-6(standard form)
Intercept form:
= 2x^2+4x-6
= (x-1)(x+3)
x-1 = 0
x = 1
x+3 = 0
x = -3
(1,0) and(-3,0).
Therefore the quadratic function f(x)=2(x+1)^2-8 in standard for and intercept form is 2x^2+4x-6 and (x-1)(x+3).
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One brand of juice contains 0.05 of natural juice. Which is this decimal written as a percent?
A) 0.05%
B) 5%
C) 0.5%
D) 50%
Answer:
B.) 5%
Step-by-step explanation:
You'll need to multiply 0.05 by 100. Since 100 = 1, we are only multiplying by 1 and not changing the value of our number.
0.05 × 100 = 5
5/100 is 5 over 100 and means 5 per 100. 5 "per 100" means 5 "percent" or 5%
Therefore, 0.05 = 5%
I hope this helps! ^-^
Just 29, please
29-30 Find the work done by the force field F in moving an object from P to Q. 29.) F(x, y) = x³i+y³j; P(1, 0), Q(2, 2) 30. F(x, y) = (2x + y)i + xj; P(1, 1), Q(4, 3)
Therefore, the work done by the force field F in moving an object from P to Q is 43
Given force field F(x, y) = x³i + y³j; P(1, 0), Q(2, 2).So, the work done by the force field in moving an object from P to Q can be determined as below;
W = ∫F.dlWhere,dl = dx i + dy j = F = x³ i + y³ j = dl = So,W = ∫.When moving from P to Q, x changes from 1 to 2, and y changes from 0 to 2.The value of work done will be;W = ∫₁²∫₀² (x³ + y³)dy dx= ∫₁²[x³y + y⁴/4]₀² dx= ∫₁² (8x + 8) dx= [4x² + 8x]₁²= (4(4) + 8(2)) - (4(1) + 8(1))= 8Therefore, the work done by the force field F in moving an object from P to Q is 8.30. Given force field F(x, y) = (2x + y)i + xj; P(1, 1), Q(4, 3).So, the work done by the force field in moving an object from P to Q can be determined as below;W = ∫F.dlWhere,dl = dx i + dy j = F = (2x + y)i + xj = <2x + y, x>dl = So,W = ∫<2x + y, x>.When moving from P to Q, x changes from 1 to 4, and y changes from 1 to 3.The value of work done will be;W = ∫₁⁴∫₁³ (2x + y) dy dx= ∫₁⁴ [2xy + y²/2]₁³ dx= ∫₁⁴ (5x + 9/2) dx= [(5x²/2 + 9/2x)]₁⁴= (5(16)/2 + 9/2(4)) - (5/2 + 9/2)= 43
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Desiree works at a dessert counter in the food court of a mall. The dessert counter sells cupcakes and cookies. Each cookie costs $1.25. Desiree sells 12 cookies and 8 cupcakes for a total of $33.00.
The cost of 1 cupcake is
$1.65
$1.92
$2.06
$2.25
Answer:
2.25$
Step-by-step explanation:
The cost of each cupcake the food court mall sells is $2.28.
What is a numerical expression?A numerical expression is a mathematical statement written in the form of numbers and unknown variables. We can form numerical expressions from statements.
Given, Desiree works at a dessert counter in the food court of a mall. The dessert counter sells cupcakes and cookies.
Each cookie costs $1.25 and assuming the cost of the cupcake is x.
∴ (1.25×12) + (8x) = 33.30.
15 + 8x = 33.30.
8x = 18.3
x = 2.28
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Draw and label a triangle with a base that is 3 times its height and has an area that is less than 50 square inches.
Answer: i dont knpw how to do tht can u tell me where to draw im just getting points
Step-by-step explanation:
The length of a rectangle is 4 inches greater than twice the width. If the diagonal is 2 inches more than the length, find the dimensions of the rectangle.
The dimensions are 3 inches, 10 inches, and 13 inches.
How to compute the value?It should be noted that the diagonal is the longest side. This will be solved by using Pythagoras theorem.
Therefore,
(2x + 6)²
4x²+ 24x + 36
Reduce to lowest term
x² + 6x + 9
x² + 3x + 3x + 9
x(x + 3) - 3(x + 3)
(x - 3) = 0
x = 0 + 3 = 3
Therefore x = 3
Therefore the dimensions will be:
x = 3
2x + 4 = 2(3) + 4 = 10
2x + 6 = 2(3) + 6 = 12
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Nina buys a small rug in the shape of a kite. The width of the rug is half its height. What are the width and the area of the rug
Answer:
Width = 1/2h
Area = 1/4h²
Step-by-step explanation:
This is quite a vague question from you. Being asked to find the width and area of a particular shape, without being given dimensions.
However, I would try to solve it nonetheless.
From your question, you stated that the width of the rug is half its height, if so, then,
w = 1/2h
Again, you're being asked to find the area. Area of a kite is given as
Area = 1/2 * Width * Height and as such, we have
Area = 1/2 * 1/2h * h
Area = 1/4 * h²
All that you need to do now is substitute the value of h
HI, i am in 7th grade i really need help this question is confusing
At the start, the water level of the river was 12 centimeters below its normal water level.
After a day of rain, the water level of the river increased by 18 centimeters.
The next 8 days were dry, and the water level of the river dropped by 2.6 centimeters each day.
Enter a numerical expression representing the water level after the 9 -day period.
What is the value of the expression you entered in part A?
What does the value in part B mean in the situation?
The changes in the river water level with reference to the normal water level in the 9-day period is analyzed as follows;
Part A: The numerical expression representing the water level after the 9-day period is; -12 + 18 - 8 × 2.6
Part B; -12 + 18 - 8 × 2.6 = -14.8
Part C; The meaning of -14.8 is that the water level after the 9-day period is 14.8 centimeters below the normal water level.
What is a mathematical expression?A mathematical expression is a collection of numbers and, or variables and operators combined according to the rules of mathematical operations.
Part A
The water level of the river at the start = 12 centimeters below its normal level
The amount by which the water level increases after a day of rain = 18 centimeters
The amount by which the water level reduces in the next 8 days = 2.6 centimeters per day
The numerical expression that represents the water level in the 9-day period is therefore;
-12 + 18 - 8 × 2.6
Part B
The value of the expression -12 + 18 - 8 × 2.6 is; -12 + 18 - 8 × 2.6 = -14.8
Part C
The meaning of the value -14.8 is that the water level after the 9-day period is 14.8 centimeters below the the normal water level of the river
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which graph of ordered pais shows a proportional relationship? i need help lol
1c) Express the function in the form = b^x + c
1d) Determine any asymptotes and state whether the function is an example of exponential growth or
decay
1e) Determine the domain and range of the function.
1f) Calculate the x-intercept and y-intercept, then sketch the function.
get om
The horizontal asymptote is y = 7 and the function is an example of exponential decay
Express the function in the form = b^x + cThe equation of the function is given as:
g(x) = -28/[2^(5x + 5)] + 7
Rewrite the equation as follows:
g(x) = -28/[2^(5x) * 2^5] + 7
Evaluate the exponent
g(x) = -28/[2^(5x) * 32] + 7
Divide
g(x) = -7/[2^(5x) * 8] + 7
Rewrite as:
g(x) = -7/[8 * 2^(5x)] + 7
Further, rewrite as:
g(x) = -7/8 * 2^(-5x) + 7
Rewrite properly as:
\(g(x)=-\frac{7}{8}\left(2^{-5x}\right)+7\)
Determine any asymptotes and state whether the function is an example of exponential growth or decayWe have:
g(x) = -7/8 * 2^(-5x) + 7
Set the radical to 0
g(x) = 0 + 7
Evaluate
g(x) = 7
This represents the horizontal asymptote (it has no vertical asymptote)
Hence, the horizontal asymptote is y = 7 and the function is an example of exponential decay
Determine the domain and range of the function.The function can take any input.
So, the domain is -∝ < x < ∝
We have the horizontal asymptote to be
y = 7
The function cannot equal or exceed this value.
So, the range is x < 7
Calculate the x-intercept and y-intercept, then sketch the function.Set x = 0
g(0) = -7/8 * 2^(-5 * 0) + 7
This gives
g(0) = -7/8 * 2^(0) + 7
Evaluate the exponent
g(0) = -7/8 + 7
Evaluate the sum
g(0) = 49/8
So, the y-intercept is 49/8
Set g(x) = 0
0 = -7/8 * 2^(-5x) + 7
This gives
-7 = -7/8 * 2^(-5x)
Divide by -7
1 = 1/8 * 2^(-5x)
Multiply by 8
8 = 2^(-5x)
Solve for x
x = -0.6
So, the x-intercept is -0.6
See attachment for the sketch
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Please Answer QUICKLY!
What is the answer?: Jacob makes the structure below with a scale of 1 : 5. What is the actual height of the structure?
Also, what is the answer for this?: A structure has the following dimensions: 48 cm ✕ 64 cm ✕ 56 cm. If Diana draws the structure 6 cm ✕ 8 cm ✕ 7 cm, what is the scale used?
The actual height of the structure is 15cm (second option).
What is the actual height?The height of an object measures how tall an object is. The height of the structure that Jacob made is 3cm.
A scale is used to show the proportion between two images or objects. The scale of the structure shows that the strucutre that Jacob made is smaller than the actual structure.
In order to determine the original height of the structure, multiply 3 by 5.
Actual height = height of the structure that Jacob made x 5
3 x 5 = 15 cm
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whats is 8000 lb =
to
8000 pounds is equal to 4 tons.
A pound is a unit of weight that is approximately equal to 16 ounces, while a ton is a unit of weight equal to 2000 pounds.
Therefore, to convert pounds to tons, you divide the weight in pounds by 2000.
8000 pounds is the weight that we want to convert to tons.
Dividing 8000 by 2000 gives us 4
which means that 8000 pounds is equal to 4 tons.
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An experimental plant has an unusual growth pattern. On each day. The plant doubles its height of the previous day. On the first day of the experiment, the plant grows to twice, or 2 times, its original height. On the second day, the plant grows to 4 times its original height. On the third day, the plant grows to 8 times its original height.
A. How many times its original height does the plant reach on the sixth day? On the nth day?
A. On the sixth day, the plant grows to 64 times its original height.
B. On the nth day, the plant would \(2^n\) time its original height.
A. From the given condition we can that the growth of the plant shows a geometric progression with a first term of 2 and a common ratio of 2.
On the first day, the plant grows to \(2^1\) = 2 times its original height.
On the second day, the plant grows to \(2^2\) = 4 times its original height.
Similarly, on the sixth day, the plant grows to \(2^6\) = 64 times its original height.
B. The nth term of the progression can be calculated by multiplying the first term by the common ratio raised to the power of n-1.
In this case, the first term is 2 and the common ratio is 2. So the nth term is \(2 * 2^{n-1} = 2^n\)
Hence, on the nth day, the plant grows to \(2^n\) times its original height.
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Natalie walked 3/5 mile in 1/2 hour . how fast did she walk in miles per hour
Answer:
(6/5) mph
Step-by-step explanation:
Worth 60 points for a rapid reply- find the area of each regular polygon. Answers are rounded to the nearest whole number.
The area of the regular polygons with 12 sides(dodecagon) and 5 sides (pentagon) are 389.06 in² and 19.87 in² respectively.
How to calculate for the area of the polygonArea of regular polygon = 1/2 × apothem × perimeter
perimeter = (s)side length of octagon × (n)number of side.
apothem = s/[2tan(180/n)].
11 = s/[2tan(180/12)]
s = 11 × 2tan15
s = 5.8949
perimeter = 5.8949 × 12 = 70.7388
Area of dodecagon = 1/2 × 11 × 70.7388
Area of dodecagon = 389.0634 in²
Area of pentagon = 1/2 × 5.23 × 7.6
Area of pentagon = 19.874 in²
Therefore, the area of the regular polygons with 12 sides(dodecagon) and 5 sides (pentagon) are 389.06 in² and 19.87 in² respectively.
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a store employes have 11 womens and 12 mens write it as a percentage
Answer: The Store employees have 47.83% women and 52.17% men.
Step-by-step explanation:
Let,
Number of women = x
Number of men = y
Total employees = x+y
Percentage of x = (x/(x+y))*100
Percentage of y = (y/(x+y))*100
Given, x = 11, y = 12
x+y = 23
Percentage of women = (11/23)*100 = 47.826 %
Percentage of men = (12/23)*100 = 52.173%
Therefore, The Store employees have 47.83% women and 52.17% men.
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if y²-16y+k is a perfect square, find k
Answer:
k=64
Step-by-step explanation:
(y-x)(y-x) = y^2-16y+k
Since the k is a "+," and two negatives (hence the negative middle value) multiply to make a positive, and since 16 has to be equal to 2x, we know that x is 8. Therefore, our equation is (y-8)(y-8), which is equal to y^2-16y+64.
Q.1: Find the value of “p” from the polynomial x2 + 3x + p, if one of the zeroes of the polynomial is 2.
THANKS
To find the value of "p" from the polynomial x^2 + 3x + p, if one of the zeroes of the polynomial is 2, we can use the fact that if 2 is a zero of the polynomial, then (x - 2) is a factor of the polynomial.
So, let's divide the polynomial x^2 + 3x + p by (x - 2) using polynomial long division:
___________________
(x - 2) | x^2 + 3x + p
- (x^2 - 2x)
_______________
5x + p
- (5x - 10)
_______________
p + 10
The remainder of the division is p + 10.
Now, since 2 is a zero of the polynomial, the remainder of the division should be zero. Therefore, we can equate the remainder to zero:
p + 10 = 0
Solving for "p", we subtract 10 from both sides:
p = -10
So, the value of "p" is -10.
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of the 254 counties in texas, how many have child care programs that state they provide nighttime care for children?
By following these steps, you should be able to find the number of counties in Texas with childcare programs offering nighttime care for children.
To answer your question about how many of the 254 counties in Texas have child care programs that state they provide nighttime care for children, we would need to access current data on child care programs in Texas. Unfortunately, I do not have that specific data at the moment. However, I can guide you on how to find this information.
Begin by visiting the Texas Health and Human Services website (https://hhs.texas.gov) as they are responsible for overseeing child care licensing in the state. Look for information on licensed child care facilities that provide nighttime care.
Utilize websites such as Child Care Aware (https://www.childcareaware.org) or Child Care Finder (https://childcarefinder.com), where you can search for child care programs in Texas by county, and filter your search to include only programs offering nighttime care.
You may also want to check with local county websites or contact the County Clerk's office for information on child care programs within their jurisdiction, specifically those offering nighttime care.
Compile the data gathered from the above sources to determine how many of the 254 Texas counties have child care programs providing nighttime care for children.
By following these steps, you should be able to find the number of counties in Texas with child care programs offering nighttime care for children.
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Sean can walk 2 1/4 miles in 2/3 hour.
At this rate, how far can he walk in 1 hour?
Answer:
3.375 or 3 3/8
Step-by-step explanation:
divide 2 1/4 to get 1 1/8 or 1.125 then multiply by 3 to get 3.375 or 3 3/8
What is the period of the function graphed below?
Answer:
2 pi
Step-by-step explanation:
Period of the function graphed = 2π
What is period of function?The distance between the repetition of any function is called the period of the function. For a trigonometric function, the length of one complete cycle is called a period.
Given,
Graph of a function.
Period of the function = Distance between two peaks or two troughs in the graph
Period of the function = 2π - 0 = 3π - π = 2π
Hence, 2π is the period of the function graphed.
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Calculate ∬Rx2+1xy2dA, where R=[0,1]×[−2,2]. a) 2ln(2)−1 b) 8/3 ln(2) c) 7/2 ln(2)−1 d) 8/3 ln(2)−1 e) 7/2ln(2)
The double integral ∬\(R (x^2 + 1)xy^2 dA\) over the region R = [0,1] × [-2,2] is equal to 8/3 ln(2).
To calculate the double integral ∬\(R (x^2 + 1)xy^2\) dA over the region R = [0,1] × [-2,2], we need to the integral in terms of x and y.
Let's set up and evaluate the integral step by step:
∬\(R (x^2 + 1)xy^2\) dA = ∫[-2,2] ∫[0,1] \((x^2 + 1)xy^2 dx dy\)
First, let's integrate with respect to x:
∫[0,1]\((x^2 + 1)xy^2 dx\) = ∫[0,1] \((x^3y^2 + xy^2) dx\)
Applying the power rule for integration:
\(= [(1/4)x^4y^2 + (1/2)x^2y^2]\ evaluated\ from\ x=0\ to\ x=1\\\\= [(1/4)(1^4)(y^2) + (1/2)(1^2)(y^2)] - [(1/4)(0^4)(y^2) + (1/2)(0^2)(y^2)]\\\\= (1/4)y^2 + (1/2)y^2 - 0\\\\= (3/4)y^2\)
Now, let's integrate with respect to y:
∫[-2,2] \((3/4)y^2 dy\)
Using the power rule for integration:
\(= (3/4) * [(1/3)y^3]\ evaluated\ from\ y=-2\ to\ y=2\\\\= (3/4) * [(1/3)(2^3) - (1/3)(-2^3)]\\\\= (3/4) * [(8/3) - (-8/3)]\\\\= (3/4) * (16/3)= 4/3\)
Therefore, the double integral ∬\(R (x^2 + 1)xy^2 dA\) over the region R = [0,1] × [-2,2] is equal to 8/3 ln(2).
The correct answer choice is b) 8/3 ln(2).
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The perimeter of this isosceles triangle is 22 cm. If one side is 6 cm, what are the possible lengths of the other two sides?
Explain how you know. Provide at least one reason for your answer.
The other two sides of the triangle will be 8 cm.
Let's call the length of each of the other two sides "x".
Since the triangle is isosceles, it has two sides of equal length. Therefore, the perimeter of the triangle can be expressed as:
perimeter = 6 + x + x
Simplifying this equation, we get:
perimeter = 2x + 6
We know that the perimeter is 22 cm, so we can set up an equation and solve for x:
22 = 2x + 6
Subtracting 6 from both sides, we get:
16 = 2x
Dividing both sides by 2, we get:
x = 8
So the other two sides could both be 8 cm long in order to make an isosceles triangle with a perimeter of 22 cm.
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Answer:
8 cm
Step-by-step explanation:
Let's call the length of each of the other two sides x. Since the triangle is isosceles, it has two sides of equal length. Therefore, the perimeter of the triangle can be expressed as 6 + x + x Simplifying this equation, we get 2x + 6 We know that the perimeter is 22 cm so we can set up an equation and solve for x. 22 = 2x + 6 Subtracting 6 from both sides, we get 16 = 2x Dividing both sides by 2, we get x=8
Simplify by Combining Like Terms
then solve
4x + 3x + 5 = 47
Next Step
.... What happened?
7x + 5 = 47
7x = 42
...
x = 6
Answer:
1. 4x+3x were added together because they are like terms
2. We subtracted 5 from both sides of the equation
3. We divide both sides of the equation by seven
Step-by-step explanation:
I hope this is what you were looking for... Good luck!
Find the dimensions of a rectangle with perimeter 100 m whose area is as large as possible.
The dimensions of the rectangle is 25m × 25m.
How do you find the dimension of a rectangle?
Two dimensions make up a rectangle: the length and, perpendicular to that, the breadth.
What are the three dimensions of a rectangle?
The three dimensions of a three-dimensional shape are length, width, and depth.
It is given that
Perimeter of the rectangle = 100m
Area is as large as possible if both the values are the same number.
The measurements must be equivalent for the rectangle to attain its maximum area.
Consider the dimensions as x
So perimeter can be written as
2 (x + x) = 100
2 (2x) = 100
By additional computation
4x = 100
Divide both sides by 4
x = 25
Therefore, the dimensions of a rectangle is 25m × 25m.
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Noah has a summer tree-trimming business. Based on experience, Noah knows that his profit, P, in dollars, can be modelled by = −3^2 + 150 − 1200, where x is the amount he charges per tree.
1. How much does he need to charge if he wants to break even?
2. How much does he need to charge if he wants to make a profit of $600?
Solving quadratic equations, it is found that he needs to charge:
1. He needs to charge $40 to break even.
2. He needs to charge $30 for a profit of $600.
What is a quadratic function?A quadratic function is given according to the following rule:
\(y = ax^2 + bx + c\)
The solutions are:
\(x_1 = \frac{-b + \sqrt{\Delta}}{2a}\)\(x_2 = \frac{-b - \sqrt{\Delta}}{2a}\)In which:
\(\Delta = b^2 - 4ac\)
The profit equation in this problem is:
P(x) = -3x² + 150x - 1200.
He breaks even when P(x) = 0, hence:
-3x² + 150x - 1200 = 0.
The coefficients are a = -3, b = 150, c = -1200, hence:
\(\Delta = 150^2 - 4(-3)(-1200) = 8100\)\(x_1 = \frac{-150 + \sqrt{8100}}{-6}\)\(x_2 = \frac{-150 - \sqrt{8100}}{-6} = 40\)He needs to charge $40 to break even.
For a profit of $600, we have that P(x) = 600, hence:
-3x² + 150x - 1200 = 600.
-3x² + 150x - 1800 = 0.
The coefficients are a = -3, b = 150, c = -1800, hence:
\(\Delta = 150^2 - 4(-3)(-1800) = 900\)\(x_1 = \frac{-150 + \sqrt{900}}{-6}\)\(x_2 = \frac{-150 - \sqrt{900}}{-6} = 30\)He needs to charge $30 for a profit of $600.
More can be learned about quadratic equations at https://brainly.com/question/24737967
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Help ASAP WILL GIVE 100 points.
Solution:
Solve the equation to find x.
(3x - 8)/2 = x - 6=> 3x/2 - 8/2 = x - 6=> 1.5x - 4 = x - 6=> 0.5x = -2=> x = -2/0.5=> x = -4The solution for this equation is -4.
Fritz can build a bookcase in 8 hours and Holly can build the same bookcase in 10 hours. After working together for 3 hours, Fritz leaves how long will it take holly to finish the bookcase by herself?
Holy will take 13/5 or 2.6 hours to finish the bookcase.
What is relation between time and work?The relation between time and work is
Work Done = Time Taken × Rate of Work ·
or, Rate of Work = 1 / Time Taken ·
or, Time Taken = 1 / Rate of Work ·
Now it is given that,
Time taken by Fritz to build a bookcase = 8 hours
So, Bookcase build by Fritz in 1 hour = 1/8
Similarly,
Time taken by Holly to build a bookcase = 10 hours
So, Bookcase build by Holly in 1 hour = 1/10
So, bookcase build in 3 hours
Fritz = 3/8
Holly = 3/10
Total bookcase build in 3 hours = 3/8 + 3/10 = 27/40
So. remaining work = 1 - 27/40 = 13/40
Thus, Time taken by Fritz to complete the bookcase = 8 * (13/40) hours
= 13/5 or 2.6 hours
Thus, Holy will take 13/5 or 2.6 hours to finish the bookcase.
To learn more about work and time:
brainly.com/question/24253661
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