The limiting reagent of the reaction is 1-butanol.
To determine the limiting reagent, we need to perform stoichiometric calculations. Given: 2.0g NaBr and 2.0 mL 1-butanol.
1. Convert mL of 1-butanol to grams:
Density of 1-butanol = 0.81 g/mL
2.0 mL * 0.81 g/mL = 1.62 g 1-butanol
2. Calculate moles of each reactant:
Molar mass of NaBr = 22.99 (Na) + 79.90 (Br) = 102.89 g/mol
Moles of NaBr = 2.0g / 102.89 g/mol = 0.0194 mol
Molar mass of 1-butanol = 74.12 g/mol
Moles of 1-butanol = 1.62g / 74.12 g/mol = 0.0218 mol
3. Compare mole ratios of reactants to their stoichiometric ratio:
Assuming a 1:1 stoichiometric ratio, divide the moles of each reactant by their coefficients in the balanced equation:
NaBr: 0.0194 mol / 1 = 0.0194
1-butanol: 0.0218 mol / 1 = 0.0218
Since 0.0194 (NaBr) is less than 0.0218 (1-butanol), NaBr would be completely consumed first, making 1-butanol the limiting reagent in this experiment.
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According to the law of conservation of mass, the total mass of the reacting substances is
always more than the total mass of the products.
always less than the total mass of the products.
sometimes more and sometimes less than the total mass of the products.
always equal to the total mass of the products.
Answer:
I would say the last one because mass is not created nor destroyed.
Explanation:
Question 11
Which formula represents a hydrocarbon?
C₂H6
C₂H5OH
C₂H5Cl
C₂H6O
Answer:
C₂H6
Explanation:
Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). Option A
A hydrocarbon is a compound that consists of only carbon and hydrogen atoms. It is important to identify the formula that represents a hydrocarbon among the given options:
A) C₂H6: This formula represents ethane, which is a hydrocarbon. Ethane consists of two carbon atoms bonded together with single bonds and six hydrogen atoms.
B) C₂H5OH: This formula represents ethanol, which is not a hydrocarbon. Ethanol contains a hydroxyl group (-OH), indicating the presence of oxygen in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.
C) C₂H5Cl: This formula represents ethyl chloride, which is not a hydrocarbon. Ethyl chloride contains a chlorine atom (Cl) in addition to carbon and hydrogen atoms. It is a haloalkane, not a hydrocarbon.
D) C₂H6O: This formula represents ethanol, which, as mentioned before, is not a hydrocarbon. Ethanol contains an oxygen atom (O) in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.
Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). It consists only of carbon and hydrogen atoms, making it a suitable representation of a hydrocarbon.
In summary, the formula C₂H6 (option A) represents a hydrocarbon, while the other options contain additional elements (oxygen or chlorine) that make them non-hydrocarbon compounds. Option A
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Turbo or supercharger
Bond energies do not account for the energy associated with the formation of aqueous solutions. Explain what energy is not accounted for AND how this energy contributes to the difference in calculated ∆Hrxn values using ∆Hf versus bond energy data ( -524 kJ/mol bond energy and -162.59 kJ/mol ∆Hf)
Answer:
Why do we all not know the answer to this on the practical
Explanation:
help plz i need help i need help i need help
Answer:
one of series of tests
Explanation:
test (something, especially a new product) to assess its suitability or performance.
"all seeds are carefully trialed in a variety of growing conditions"
Medical Definition of trial
1 : a tryout or experiment to test quality, value, or usefulness — see clinical trial. 2 : one of a number of repetitions of an experiment. trial.
Answer:
last onee
Explanation:
What is a solution?
a
a homogeneous mixture with particles between .01 and 1 nm
b
a homogeneous mixture with particles smaller than .01nm
c
a heterogeneous mixture with particles between .01 and 1 nm
d
a heterogeneous mixture with particles smaller than .01nm
how much energy is needed to convert 120g of ice at -35°C to steam at 150°C?
why is the average number of fish species not a whole number?
Answer:
Because in order to find the average, you need to divide by the number of sites tested. Sometimes that doesn't divide evenly.
Explanation:
what is kind of property is denisty?
Answer:
INTENSIVE PROPERTY OF MATTER
Explanation:
DENSITY IS AN INTENSIVE PROPERTY OF MATTER THAT ILLUSTRATES HOW MUCH MASS A SUBSTANCE HAS IN A GIVEN AMOUNT OF VALUE,
the half-life of a reaction of compound a to give compounds d and e is 8.50 min when the initial concentration of a is 0.150 m. how long will it take for the concentration to drop to 0.0300 m if the reaction is (a) first order with respect to a or (b) second order with respect to a?
It will take 20.33 min in the first order for the concentration to drop to 0.0300 M and 11.8 min for the concentration to drop to 0.0300 M in the second order.
What is compound?A substance created by chemically joining two or more different elements. Examples of compounds are table salt (NaCl), which is made from the elements sodium and chloride, and water (H2O), which is created from the elements hydrogen and oxygen.
(a) First order with respect to A:
The half-life of a first-order reaction is constant and does not depend on the initial concentration of the reactant. Therefore, we can use the half-life formula:
t1/2 = 0.693/k, where k is the rate constant of the reaction.
We are given that the half-life of the reaction is 8.50 min when the initial concentration of A is 0.150 M.
Since we know the half-life of the reaction, we can find the rate constant, k = 0.693/8.50 = 0.081 min^-1
To find how long it takes for the concentration of A to drop to 0.0300 M, we can use the formula:
[A]t = [A]0 * e^(-kt)
where [A]t is the concentration of A at time t, [A]0 is the initial concentration of A, k is the rate constant, and t is the time in minutes.
Plugging in the given values and solving for t, we get:
t = (ln (0.0300/0.150)) / (-0.081) = 20.33 min
For (b) Second order with respect to A:
The half-life of a second-order reaction is dependent on the initial concentration of the reactant.
t1/2 = 1/(k[A]) = 8.50 min
By solving for k, we can find k = 1/(8.5*0.15) = 0.0118 min^-1M^-1
To find how long it takes for the concentration of A to drop to 0.0300 M, we can use the formula:
1/[A]t = 1/[A]0 + kt
Plugging in the given values and solving for t, we get:
t = (1/0.0300 - 1/0.150) / 0.0118 = 11.8 min
Therefore, if the reaction is first order with respect to A it will take 20.33 min for the concentration to drop to 0.0300 M, and if the reaction is second order with respect to A it will take 11.8 min for the concentration to drop to 0.0300 M.
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Why was it so important that the scientist investigating the atom be young and unattached to existing scientific thinking
Answer:
so they can find the aswer and not get hurt
Explanation:
The scientist Neil Bohr has investigated the atom to be young and unattached to Albert Einstein thinking because he is fearless of his thinking and ready to find an explanation.
What is Einstein model?Einstein model is called as Einstein solid model. He stated as ever solid atom oscillate with the same frequency and contain large number of three dimensional quantum harmonic oscillation.
Bohr atomic model stated that electron revolve around the nucleus in its stable orbital without emitting radiant energy. It is primitive model of hydrogen atom. Bohr has given the expression l = nh / 2π
Where n = principle quantum number, l = angular momentum and h = plank constant
Thus, the scientist Neil Bohr has investigated the atom to be young and unattached to Albert Einstein thinking because he is fearless of his thinking and ready to find an explanation.
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identify the percent yield of end of experiment experiemnt 9 cu transformation
We can then use the following equation to calculate the percent yield: Percent yield = (amount of copper formed) / (amount of \(CuSO_4\) added) x 100%. Since it is expert experiment, Percent yield is 100%.
To calculate the percent yield of an experiment, we need to compare the amount of product formed to the amount of reactants used. The percent yield is calculated as follows:
Percent yield = (amount of product formed) / (amount of reactants used) x 100%
In this experiment, the product is likely the amount of copper that has been transformed from \(Cu_2\)+ to Cu+. The amount of reactants used is likely the amount of \(CuSO_4\) that was added to the solution.
To determine the percent yield, we would need to know the amount of copper that was formed and the amount of \(CuSO_4\) that was added to the solution.
Percent yield = (amount of copper formed) / (amount of \(CuSO_4\) added) x 100%.
To calculate the percent yield, we can use the following equation:
Percent yield = (amount of copper formed) / (amount of \(CuSO_4\) added) x 100%
= (100/100)* 100
= 100 %
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An element that does not conduct electricity is found to have a melting point of 1,985 K. Which of the following statements are true for this element? This element exists as discrete atoms or discrete molecules.This element exists as a continuous network of atoms.When this element melts, metallic bonds are overcome.When this element melts, covalent bonds are overcome.When this element melts, LDFs are overcome.
"When this element melts, metallic bonds are overcome" is not true for this element because it does not conduct electricity. Metallic bonds are responsible for the conductivity of metals.
So if an element does not conduct electricity, it cannot have metallic bonding. The statement "When this element melts, covalent bonds are overcome" is also not necessarily true because not all non-conductive elements have covalent bonding. However, the statement "This element exists as discrete atoms or discrete molecules" is likely to be true because non-conductive elements tend to have simple atomic or molecular structures. The statement "This element exists as a continuous network of atoms" is unlikely to be true because continuous networks typically result in conductive properties.
Finally, the statement "When this element melts, LDFs are overcome" is likely to be true because London dispersion forces (LDFs) are responsible for the intermolecular attractions between non-polar molecules or atoms. A metallic bond is the kind of bond that results from the sharing of free electrons between two metals. They have neither polarity nor directionality.Atoms in a metallic substance are held together by electrostatic forces of attraction found in metallic bonds. The valence electrons in a metal are not localised, as they are in covalently bound compounds, and they can flow around freely in a crystal lattice.
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Which chemicals generate the following colors in the fireworks? Red Blue Green Yellow Purple Orange Silver
Besides reduced ubiquinone, what other electron-carrying molecules that will accumulate in the presence of antimycin A?
a. succinate
b. NADH
c. NAD+
d. fumurate
In this context, besides reduced ubiquinone, the other electron-carrying molecule that will accumulate in the presence of antimycin A is NADH (option b).
Antimycin A is an inhibitor that specifically targets the electron transport chain (ETC) within the mitochondria. When antimycin A is present, it binds to and inhibits complex III (cytochrome bc1 complex) of the ETC. This inhibition disrupts the normal flow of electrons, leading to the accumulation of certain electron-carrying molecules.
NADH is produced during earlier stages of cellular respiration, specifically in the citric acid cycle and glycolysis. It donates its electrons to complex I (NADH dehydrogenase) of the ETC, initiating the electron flow. However, when complex III is inhibited by antimycin A, the electrons cannot be passed further along the chain, causing NADH to accumulate.
Succinate (option a) and fumarate (option d) are both involved in the citric acid cycle, but they do not directly carry electrons in the ETC. Instead, succinate is converted to fumarate by succinate dehydrogenase, producing reduced flavin adenine dinucleotide (FADH2) as the electron carrier. NAD+ (option c) is the oxidized form of NADH and will not accumulate since it is not an electron-carrying molecule in this context.
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select all the factors that likely played a role in jessie's fainting episode.
a.chronic hyperglycemia
b. her anticonvulsant medication c.overexertion while saving the drowning boy d.her diet in the days leading up to the episode e.diabetic ketoacidosis
f.her diet on the day of the episode
The factors that likely played a role in Jessie's fainting episode are a. chronic hyperglycemia, b. her anticonvulsant medication, c. overexertion while saving the drowning boy, and e. diabetic ketoacidosis.
Chronic hyperglycemia, indicated by option a, can affect blood flow and oxygen supply to the brain, potentially leading to fainting episodes. Anticonvulsant medication, mentioned in option b, can have side effects such as dizziness or lightheadedness, which may contribute to fainting. Overexertion, as stated in option c, can cause fatigue, dehydration, and low blood pressure, all of which increase the risk of fainting. Diabetic ketoacidosis, noted in option e, is a serious complication of diabetes that can lead to electrolyte imbalances and dehydration, potentially triggering a fainting episode.
Options a, b, c, and e are the correct answers.
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How many atoms are in 1 mole of Ba?
Answer:
6.0221415E+23 atoms
Explanation:
I will give brainliest and 76 points
Answer:
number 5 is the answer
Explanation:
How many atoms are in a 1.8 mol sample of Magnesium (Mg)?
Answer:
1.1 × 10²⁴ atoms Mg
General Formulas and Concepts:
Atomic Structure
MolesAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Stoichiometry
Using Dimensional AnalysisExplanation:
Step 1: Define
Identify
[Given] 1.8 mol Mg
[Solve] atoms Mg
Step 2: Identify Conversions
Avogadro's Number
Step 3: Convert
[DA] Set up: \(\displaystyle 1.8 \ mol \ Mg(\frac{6.022 \cdot 10^{23} \ atoms \ Mg}{1 \ mol \ Mg})\)[DA] Multiply [Cancel out units]: \(\displaystyle 1.08396 \cdot 10^{24} \ atoms \ Mg\)Step 4: Check
Follow sig fig rules and round. We are given 2 sig figs.
1.08396 × 10²⁴ atoms Mg ≈ 1.1 × 10²⁴ atoms Mg
Answer: 1.0836 * 10^24 atoms
This value is approximate
===========================================================
Explanation:
1 mole = 6.02*10^23 atoms approximately
This applies to any element.
Multiply both sides by 1.8 and we get...
1 mole = 6.02*10^23 atoms
1.8*1 mole = 1.8*6.02*10^23 atoms
1.8 mole = 10.836*10^23 atoms
1.8 mole = (1.0836*10)*10^23 atoms
1.8 mole = 1.0836 * 10^(1+23)
1.8 mole = 1.0836 * 10^24 atoms
A gaseous product of a reaction is collected at 280K and 0.95 atm. Given
R= 0.0821L⋅atm/mol⋅K , what is the molar mass of the gas, in grams per mole, if 3.25 g of gas occupies 2.56 L?
The molar mass of the gas, given that 3.25 g of the gas occupied 2.56 L is 30.66g/mol
How do I determine the molar mass of the gas?To obtain the molar mass of the gas, we shall first obtain the number of mole of the gas. This can be obtained as follow:
Temperature (T) = 280 KPressure (P) = 0.95 atmVolume (V) = 2.56 L Gas constant (R) = 0.0821 atm.L/Kmol Number of mole (n) =?PV = nRT
0.95 × 2.56 = n × 0.0821 × 280
Divide both sides by (0.0821 × 280)
n = (0.95 × 2.56) / (0.0821 × 280)
n = 0.106 mole
Haven obtain the mole of the gas, we shall determine the molar mass of the gas as follow:
Mole of gas = 0.106 moleMass of gas = 3.25 gMolar mass of gas =?Molar mass = mass / mole
Molar mass of gas = 3.25 / 0.106
Molar mass of gas = 30.66g/mol
Thus, the molar mass of the gas is 30.66g/mol
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a vessel contains 66 g co2 and 16 g o2 at a pressure of 10.0 atm. what is the partial pressure of co2?
This question is providing the masses of carbon dioxide and oxygen gases at 10.0 atm as 66 g and 16 g respectively, and is asking for the partial pressure of the former which turns out to be 7.50 atm after doing the math.
Thus, we can start solving this problem with the Dalton's law approach, in order to make a relationship for the total pressure, partial pressure and mole fraction, which means we must first determine the mole fraction of carbon dioxide gas in the mixture as shown below:
\(x_{CO_2}=\frac{n_{CO_2}}{n_{CO_2}+n_{O_2}}\)
Next, we calculate the moles of both gases by dividing the grams over the molar masses:
\(n_{CO_2}=\frac{66g}{44.01g/mol} =1.50mol\\\\n_{O_2}=\frac{16g}{32g/mol} =0.5mol\)
Then, the mole fraction of carbon dioxide as the required one by plugging in the previously calculated moles:
\(x_{CO_2}=\frac{1.5}{1.5+0.5}=0.75\)
Finally, we use the definition of the Dalton's law to calculate the partial pressure of carbon dioxide gas in the binary mixture:
\(P_{CO_2}=x_{CO_2}P\\\\P_{CO_2}=0.75*10.0atm\\\\P_{CO_2}=7.50 atm\)
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**asap!!** can someone write me a balanced equation with this sundae recipe
1. 12 banana hands
2. 2 bottles of chocolate syrup
3. 12 breyers vanilla ice cream
4. 2 containers of candy cherries each have 30 cherries.
5.1 bottle of whipped cream
Answer:
12 banana hands + 2 bottles of chocolate syrup + 12 scoops of Breyers ice cream + 2 containers of candy cherries(30 cherries/per) + bottle of whipped cream.
Explanation:
Hope this helps!
Select all of the following that are products in the overall equation for aerobic respiration. (select more than one)
ATP (adenosine triphosphate)
NaOH (natrium hidroxide)
CO2 (carbon dioxide)
CO (carbon monoxide)
The products in the overall equation for aerobic respiration are ATP (adenosine triphosphate) and CO2 (carbon dioxide).
What is aerobic respiration?
Aerobic respiration is a metabolic process that uses oxygen to convert glucose into energy. During aerobic respiration, glucose (sugar) is broken down in the presence of oxygen (O2) to produce energy in the form of ATP (adenosine triphosphate). This process also produces carbon dioxide (CO2) and water (H2O). The energy produced by aerobic respiration is used to fuel cellular processes such as protein synthesis and muscle contractions. Aerobic respiration is the main form of respiration in humans and other animals.
The overall equation for aerobic respiration is C6H12O6 + 6O2 yields 6CO2 + 6H2O + energy (as ATP). ATP (adenosine triphosphate) and CO2 (carbon dioxide) are products in the overall equation for aerobic respiration. NaOH (natrium hydroxide) and CO (carbon monoxide) are not products in the equation.
Therefore, ATP (adenosine triphosphate) and CO2 (carbon dioxide) are the answers.
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three students measure the volume of a liquid using a graduated cylinder. in a separate experiment, the actual value volume of the liquid is 152 ml. which set of data is the most precise? a) student 1 b) student 2 c) student 3 d) none of the students are precise
Three students measure the volume of a liquid using a graduated cylinder. in a separate experiment, the actual value volume of the liquid is 152 ml.
Student 3 set of data is the most precise
What is volume?
Generally, A volume is a measurement of the amount of space that is occupied in three dimensions. Quantification of it in terms of numbers often makes use of units derived from the SI or different imperial units. There is a connection between volu and the concept of length.
In conclusion, Using a graduated cylinder, three pupils determine the amount of a liquid that has been measured. In a different experiment, the volume of the liquid that was measured to be its real value was 152 milliliters.
The statistics collected from Student 3 are the most accurate.
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at a certain temperature, 0.800 mol so3 is placed in a 4.00 l container. 2so3(g)↽−−⇀2so2(g) o2(g) at equilibrium, 0.120 mol o2 is present. calculate c.
The concentratio is 0.03 M.(C)
The expression for calculating concentration is the number of moles of solute divided by the volume of the solution.
To find the concentration in this scenario, we will first find the number of moles of O₂ present and then divide it by the volume of the container that the equilibrium is taking place in.
Concentration (C) = 0.03 MExplanation:The given chemical equation is:2SO₃ (g) ⇌ 2SO₂ (g) + O₂ (g)At a certain temperature, 0.800 mol SO₃ is placed in a 4.00 L container.
When the system is at equilibrium, the concentration of O2 is 0.120 mol.We need to calculate the concentration C.Calculation:
At equilibrium, the equilibrium constant Kc is given as:[SO₂]²[O₂] / [SO₃]²Kc
= (0.120 mol/L) / (0.8 mol/L)²Kc
= 0.1875 M³/L²C
= (Kc × [SO₃]²)¹/²C
= (0.1875 M³/L² × (0.8 mol/4.00 L)²)¹/²C
= 0.03 M (rounded to 2 significant figures)
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In a chemical reaction, the reactants (beginning elements or compounds) but have the same number and type of atoms as the products (the new substance created). This is an example of...
a) law of conservation of mass
b) law of conservation of energy
c) covalent bonding
d) product synthesis
Answer:The law of conservation of matter says that matter cannot be created or destroyed. In chemical equations, the number of atoms of each element in the reactants must be the same as the number of atoms of each element in the products. ... There are two oxygen atoms in the reactants and two atoms of oxygen in the product.
Explanation:
2. Pick two materials that float from the table above.
Observe how high the two materials float in the water and compare this to the density of the two objects.
What do you notice?
An object with a lower density will float
than an object with a higher density.
(higher/lower)
Explanation:
so let's say fertilizer sinks it would be higher density and like salt it would be a solvent hope that helps honestly it probably did not but kind of a guide I guess and another one is ice it will be like a toy and here's a tip water is and always will be 1 gl
what type of volcanic eruption produce ash fall?
Explanation:
I would say explosive eruptions caused by decompression of the dissolved gases in the magma. The Mt Pinatubo eruption is an example of a massive ash fall that eventually closed down an American base in the Philippines. And just recently the island of St. Vincent suffered major damage from ash fall due to a volcanic eruption.
What is an alkyne?
A. A hydrocarbon containing all single bonds
B. A hydrocarbon containing a carbon-carbon double bond
C. A hydrocarbon containing a carbon-carbon triple bond
D. A hydrocarbon containing an aromatic ring
Alkynes are called the hydrocarbons. Ethyne is an important alkyne which is used in oxyacetylene gas cutting. A hydrocarbon containing a carbon-carbon triple bond is the alkyne. The correct option is C.
What is an alkyne?In organic chemistry, an alkyne is defined as the unsaturated hydrocarbon containing at least one carbon-carbon triple bond. The alkynes are unsaturated hydrocarbons and their general formula is CₙH₂ₙ₋₂ and the triple bond is known as the acetylene bond.
Many alkynes are found in nature. Ethyne is the first member of the alkyne family in which two carbon atoms are connected by a triple bond. Almost all alkynes are also found to be hydrophobic in nature.
Alkynes show three types of isomerism like chain isomerism, position isomerism and functional isomerism. The triple bond present in the alkynes is its functional group.
Thus the correct option is C.
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How many moles of phosphoric acid are required to neutralize 7.2 mol of potassium hydroxide?
Answer:
2.4 Moles of Phosphoric acid are required to neutralize 7.2 moles of potassium hydroxide
Explanation:
Phosphoric acid = Formula: H3PO4
Potassium hydroxide = Formula: KOH
H3PO4 + 3KOH = K3PO4 + 3H2O
Ratio 1:3
7.2 mol Potassium hydroxide = Formula: KOH
7.2/3 = 2.4 Mol Phosphoric acid = Formula: H3PO4