1. What are three ways in which vesicles in a cell are moved using directed motion. 2. What is the average size of a myosin motor step along an actin filament in nm)? What is the average size of a kinesin motor step along / (across) a tubulin dimer (in nm)? 3. Write the definition of the rate of ATP hydrolyzation Rin your own words. How would you calculate the rate of ATP hydrolyzation, you know the step size of the motor proteins and the average vesicle velocity. Write the equation here. 4.Use the equation from Question 3 and your answer to Question 2 to calculate the rate of ATP hydrolyzation, R. For step size, assume the vesicle is being transported by a myosin motor protein. (Hint: make sure you convert values to the appropriate units) The units for rate of ATP hydrolysis are s-1
Vesicles in a cell can be moved through directed motion by motor proteins along cytoskeletal filaments, diffusion-mediated transport, and membrane fusion and fission events.
Motor proteins acting along cytoskeletal filaments are one method by which vesicles are transported inside a cell. Using ATP energy, motor proteins like kinesins and dyneins move along actin or microtubule filaments to transport vesicles to particular locations. Vesicles are often moved by kinesins and dyneins in opposite directions—towards the cell center. This focused movement makes it possible to distribute vesicles to particular cellular compartments quickly and effectively.
Vesicles can also be transported within a cell by diffusion-mediated transport. Although random thermal motion, or diffusion, contributes to the movement of vesicles, it is insufficient for long-distance transport. In the cell, it can, however, contribute to shorter-distance movements that help with vesicle dispersion and distribution.
Vesicle mobility is also influenced by membrane fusion and fission processes. Vesicles can either assimilate into the target membrane or fuse with it to release their contents. On the other hand, when a vesicle buds off from a membrane, membrane fission takes place. These fusion and fission mechanisms are essential for intracellular trafficking because they enable vesicles to attach to or separate from membranes at specific points, enabling the controlled movement of vesicles inside the cell.
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use direct integration to determine the mass moment of inertia of the solid of revolution of mass m about the y-axis. ans: iyy = (7/22)mb2
The mass moment of inertia about the y-axis (Iyy) for the solid of revolution with mass m can be determined using direct integration, resulting in Iyy = (7/22)mb².
To calculate Iyy using direct integration, follow these steps:
1. Identify the function y=f(x) representing the curve to be revolved around the y-axis.
2. Calculate the area element dA in terms of x: dA = 2πxρdx, where ρ is the mass per unit area (m/A).
3. Determine the mass element dm: dm = ρdA = 2πxρdx.
4. Obtain the moment of inertia element dIyy: dIyy = x²dm = 2πx³ρdx.
5. Integrate dIyy from x=a to x=b: Iyy = ∫(2πx³ρdx) from a to b.
6. Substitute the mass per unit area (ρ=m/A) into the integral and solve for Iyy.
7. Finally, after evaluating the integral, the mass moment of inertia will be given by Iyy = (7/22)mb².
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A baseball player slides into third base with an initial speed of 4.2 m/s . Part A If the coefficient of kinetic friction between the player and the ground is 0.50, how far does the player slide before coming to rest
The baseball player slides for 1.8 meters before coming to rest. To determine how far the baseball player slides before coming to rest, we first need to calculate the acceleration due to friction.
We can use the formula a = μk * g, where μk is the coefficient of kinetic friction and g is the acceleration due to gravity (9.8 m/s²).
a = μk * g
a = 0.50 * 9.8
a = 4.9 m/s²
Next, we can use the kinematic equation vf² = vi² + 2ad, where vf is the final velocity (0 m/s), vi is the initial velocity (4.2 m/s), a is the acceleration due to friction (-4.9 m/s²), and d is the distance we are trying to find.
vf²= vi² + 2ad
0 = (4.2)² + 2(-4.9)d
0 = 17.64 - 9.8d
9.8d = 17.64
d = 1.8 meters
Therefore, the baseball player slides for 1.8 meters before coming to rest.
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19. The continuity equation for compressible liquid can be written as
Answer:The continuity equation for a compressible liquid is a mathematical expression that relates the changes in fluid density, velocity, and volume to the changes in time. This equation can be written as:
∂ρ/∂t + (ρv)•∇ = 0
where:
ρ = fluid density
v = fluid velocity
∂/∂t = partial derivative with respect to time
∇ = del operator
The continuity equation expresses the principle of mass conservation, stating that the rate of change of fluid density in a fixed volume must be equal to the rate of flow of fluid into or out of that volume. This equation is commonly used in fluid dynamics to study the behavior of liquids and gases in various applications, such as in pipelines, pumps, valves, and compressors.
Explanation:
What are some of the dangers that volcanoes pose to human populations? a. Destruction of property from lava flow b. Destruction from mud flows c. Lung problems from ash and toxic gases d. All of the above.
Destruction of property from lava flow, destruction from mud flows and lung problems from ash and toxic gases are all some of the dangers that volcanoes pose to human populations.
Volcanoes refer to an opening that appears on the earth's surface and serves as a vent for lava, volcanic ash, and gases. These could lead to a fire outbreak in mountains sometimes.
The following are dangers posed by volcanoes pose to human populations;
Destruction of property from lava flow Destruction from mud flowsLung problems from ash and toxic gasesHence, the correct answer to the question is "all of the above".
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Answer:
D
Explanation:
EDGE 2021
Show all of your work in the space provided.(If needed you can use extra paper).Show all of your work, or you will not get any credit. 1. Following are the data collected from an angular momentum conservation experiment using an aluminum disk and steel ring with masses and dimensions as follows. Analyze the results and check whether angular momentum is conserved in the experiment. Obtain the - \% difference L 1
ω 1
and L 2
ω 2
.(20 points) ४ Mass of Aluminum Dise (m in Kg)=0.106Kg * Radius of Aluminum Disc (r in m)=0.0445 m 4 Mass of Steel ring (M in Kg)=0.267 Kg, Inner Radius of Steel Disc (r 1
in m)= 0.0143m, Outer Radius of Steel Disc (r 2
inm)=0.0445m Moment of Inertia of disk is given by I= 2
1
mr 2
Moment of Inertia of ring is given by I s
= 2
1
M(r 1
2
+r 2
2
) Angular momentum I 2.Calculate the equivalent resistances of the following four circuits, compare the values with the experimental values in the table and calculate the \% difference between experimental and theoretical values. Series Circut: R eq
=R 1
+R 2
+R 3
+⋯ Parallel Circut: R eq
1
= R 1
1
+ R 2
1
+ R 3
1
+⋯
The aluminum disk will reach the bottom of the incline first.
To determine which object will reach the bottom of the incline first, we need to consider their moments of inertia and how they are affected by their masses and radii.
The moment of inertia (I) is a measure of an object's resistance to changes in its rotational motion. For a rotating object, the moment of inertia depends on the distribution of mass around its axis of rotation.
The moment of inertia for a solid disk is given by the formula:
\(I_{disk} = (1/2) * m_{disk} * r_{disk^2}\)
where\(m_{disk }\)is the mass of the aluminum disk and \(r_{disk}\) is the radius of the aluminum disk.
The moment of inertia for a ring is given by the formula:
\(I_{ring} = m_{ring} * (r_{ring^2})\)
where\(m_{ring}\) is the mass of the steel ring and \(r_{ring }\)is the radius of the steel ring.
Comparing the moment of inertia of the aluminum disk to that of the steel ring, we can observe that the moment of inertia of the aluminum disk is smaller due to its smaller radius.
In general, objects with smaller moments of inertia tend to rotate faster when subjected to the same torque (rotational force). Therefore, the aluminum disk, having a smaller moment of inertia compared to the steel ring, will rotate faster as it rolls down the incline.
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--The complete Question is, Following are the data collected from an angular momentum conservation experiment using an aluminum disk and steel ring with masses and dimensions as follows:
Mass of the aluminum disk: 0.5 kg
Mass of the steel ring: 0.3 kg
Radius of the aluminum disk: 0.2 meters
Radius of the steel ring: 0.1 meters
Initial angular velocity of the aluminum disk: 5 rad/s
Question: When the aluminum disk and steel ring are released from rest and allowed to roll down an incline simultaneously, which object will reach the bottom of the incline first? --
____________ are forces in which two interacting objects are physically in contact with each other; examples include ___________ and ______________. a. Contact forces , friction, air resistance c. Action-at-a-distance fields , gravity, electric field b. Contact forces , gravity, electric field d. None of the above. Please select the best answer from the choices provided A B C D
a. Contact forces, friction, air resistance
Clay bricks are used as building materials in construction. Do some research on specific heat capacities of brick, concrete, stone etc. and advise on what this means for society.
Answer:
It means it is the main building block material for society.
Specific heat is the amount of heat energy that causes a unit increase in temperature by required to be added to the unit mass of the substance. It can be measured by the heat capacity of a particular substance. The unit of specific heat is joule/kg/kelvin.
Material Specific heat capacity Thermal conductivity
Clay 1000 0.60
stone 1000 1.8
brick 800 0.73
concrete 1000 1.13
Advice on what this means for society:
Thermal interaction in between indoor and outdoor environments regulated by wall components.The structural and thermal properties influence the behavior of building and fabricating the bricks, stone and others. Clay Bricks are durable, and natural of stable value. A modern building must comply with numerous ecological and economic demands.Learn more about specific heats:
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Suppose that we replace the aluminum with a mystery metal and repeat the experiment in the video. As in the video, the mass of the metal is the same as that of the water. Room temperature is about 20∘C before the start of the experiment. The water heats up to 40∘C, and the mystery metal heats up to 80∘C. Compared to that of water, the heat capacity of our mystery metal is
Answer: b) one-third as great.
Explanation:
The options include:
a) three times greater.
b) one-third as great.
c) half as great.
d) two times greater.
e) the same.
Since the water heats up to 40°C and the room temperature is about 20°C before the start of the experiment, heat absorbed will be: (40°C-20°C).= 20°C
Since mystery metal heats up to 80∘C and the room temperature is about 20°C before the start of the experiment, heat absorbed will be: (80°C-20°C).= 60°C.
Therefore, based on the calculation, when compared to that of water, the heat capacity of our mystery metal is (20/60) = 1/3 one-third as great.
if the circuit has a current of 0.021a, what must the electrical potential difference across the battery be?
To calculate electrical potential difference across the battery, the resistance of the circuit is required. Therefore the given question is incomplete.
Describe resistance.The ability of the material to restrict the flow of current is referred to as resistance. It is symbolized by the letter 'R'. The ohm, frequently written as a word and sometimes represented by the Greek letter omega, is the unit of resistance that is commonly used.
How does resistance develop in a circuit?As electrons pass from a conductor, such a metal wire, an electric current occurs. The atoms in the metal may clash with the travelling electrons. Resistance is created as a result, making it more challenging is for current to flow.
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From the scattering of sunlight, J.J. Thomson calculated the classical radius of the electron as having the value 2.82 × 10⁻¹⁵m . Sunlight with an intensity of 500 W / m² falls on a disk with this radius. Assume light is a classical wave and the light striking the disk is completely absorbed.(a) Calculate the time interval required to accumulate 1.00eV of energy.
The time interval required to accumulate 1.00 eV of energy is approximately 7.16 × 10¹¹ seconds.
To calculate the time interval required to accumulate 1.00 eV (electron volt) of energy from sunlight with an intensity of 500 W/m² falling on a disk with a radius of 2.82 × 10⁻¹⁵ m, we can use the equation:
Energy = Power * Time
Given:
Intensity (I) = 500 W/m²
Radius (r) = 2.82 × 10⁻¹⁵ m
Energy (E) = 1.00 eV
First, we need to calculate the total power received by the disk. Since the light is completely absorbed, we can assume that all the power is absorbed by the disk. The power can be calculated using the formula:
Power = Intensity * Area
The area of the disk can be calculated as follows:
Area = π * (radius)²
Substituting the values into the equation:
Area = π * (2.82 × 10⁻¹⁵ m)²
Next, we can calculate the power:
Power = Intensity * Area
= 500 W/m² * [π * (2.82 × 10⁻¹⁵ m)²]
Now we can solve for time:
Time = Energy / Power
= (1.00 eV) / [500 W/m² * π * (2.82 × 10⁻¹⁵ m)²]
To convert eV to joules, we use the conversion factor:
1 eV = 1.602 × 10⁻¹⁹ J
Substituting this conversion and the numerical values:
Time = (1.602 × 10⁻¹⁹ J) / [500 W/m² * π * (2.82 × 10⁻¹⁵ m)²]
Therefore, the time interval required to accumulate 1.00 eV of energy is approximately 7.16 × 10¹¹ seconds.
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between a smooth and a rough surface, which of the two surfaces is easier to slide and why?
Answer:
When two surfaces slide against each other, a force called friction makes them stick very slightly together. Smooth surfaces, like ice and glass, are easy to slide over
Explanation:
They create very little friction. Rough surfaces like rock and sand create much more friction, and are easy to grip on to.
Hello There!
Smooth Surfaces are easier to slide over. That's true.
Take an object and slide it across a rough surface. Now, slide the same object across a smooth surface.
What do you see?
I expect you wil find out that smooth surfaces are easier to slide over.
Reason:
Smooth surfaces have less friction than rough ones.
Hope it helps!
An object with a charge of -3C is touched to an object with a charge of -1C. What is the new charge on each object?
After connecting the conducting wire, the spheres will redistribute charges until they both have a charge of -1C.
To determine the new charges on the spheres, we need to consider the principle of charge conservation, which states that the total charge before and after an interaction remains the same.
Let's assume that the spheres have charges Q1 and Q2 initially. In this case, Q1 = -3C and Q2 = +1C.
When a conducting wire is connected between the spheres, charge can redistribute until the system reaches equilibrium. Since the spheres are conducting, charges are free to move within them.
In the final state, the charges on the spheres will redistribute to reach a new equilibrium. Let's assume the new charges on the spheres are Q1' and Q2'.
According to the principle of charge conservation, the total charge before and after the connection remains the same:
Initial total charge = Q1 + Q2 = -3C + 1C = -2C
Final total charge = Q1' + Q2'
Since the total charge remains the same, we can write the equation:
Q1' + Q2' = -2C
Since the spheres are of equal size, we can assume that the charges redistribute equally:
Q1' = -1C
Q2' = -1C
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The question probable may be:
A conducting wire is connected between two conducting spheres of equal size have a charge of -3C and +1C respectively. Find out the new charge on each sphere ?
Which parts differentiate ray diagram of reflected and reflected light check all that apply
Answer
4. Reflected ray
5. Refracted ray
Answers for the rest of the assignment
Diagram 2.
Refraction.
A and C.
The surface of the paper is rough, which causes incoming light rays to bounce off in a variety of different directions. Therefore, diffuse reflection occurs.
45 degrees.
1.5
2.3
74 degrees.
Air
Lucite
Hope this helps:)
The answers include the following:
The parts which differentiate ray diagram of reflected and reflected light are reflected and refracted ray.The surface of the paper is rough, which causes incoming light rays to bounce off in a variety of different directions which is why diffuse reflection occurs.What is Diffuse reflection?This is referred to as the scattering of light that occurs when it reflects off a surface.
For a rough surface, reflected light rays scatter in all directions which is therefore the reason why it was chosen as the correct choice.
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(20\%) Problem 5: A capacitor of capacitance
C=3.5μF
is initially uncharged. It is connected in series with a switch of negligible resistance, a resistor of resistance
R=5.5kΩ
, and a battery which provides a potential difference of
V B
â
=55 V
. (17\% Part (a) Calculate the time constant
Ï
for the circuit in seconds.
Ï=
Submission History All Date times are displayed in Central Standard Time .Red submission date times indicate late work. Date Time Answer Hints Feedback A 17\% Part (b) After a very long time after the switch has been closed, what is the voltage drop
V C
â
across the capacitor in terms of
V B
â
? (17\% Part (c) Calculate the charge
Q
on the capacitor a very long time after the switch has been closed in C. (17\% Part (d) Calculate the current
I
a very long time after the switch has been closed in A. (17\% Part (e) Calculate the time
t
after which the current through the resistor is one-third of its maximum value in s.
â³17%
Part (f) Calculate the charge
Q
on the capacitor when the current in the resistor equals one third its maximum value in C.
The time constant (τ) for the given circuit is 6.125 milliseconds (ms). After a very long time, the voltage drop across the capacitor (VC) will be equal to the battery voltage (VB). The charge on the capacitor (Q) after a very long time is 192.5 microcoulombs (μC). The current (I) after a very long time is 35.455 microamps (μA). The time (t) after which the current through the resistor is one-third of its maximum value is 18.375 ms. The charge on the capacitor when the current in the resistor equals one-third its maximum value is 6.4175 μC.
The time constant (τ) for an RC circuit can be calculated using the formula τ = RC. Given the capacitance (C) as 3.5 μF and resistance (R) as 5.5 kΩ (which is equivalent to 5500 Ω), we can substitute these values into the formula to find τ. τ = (3.5 μF) * (5500 Ω) = 6.125 ms.
After a very long time, the capacitor will fully charge and reach its maximum voltage. In this case, the voltage drop across the capacitor (VC) will be equal to the battery voltage (VB). So VC = VB = 55 V.
The charge (Q) on the capacitor after a very long time can be calculated using the formula Q = VC * C. Substituting the values, we get Q = (55 V) * (3.5 μF) = 192.5 μC.
The current (I) after a very long time can be calculated using Ohm's Law, where I = VB / R. Substituting the values, we get I = (55 V) / (5500 Ω) = 35.455 μA.
To calculate the time (t) after which the current through the resistor is one-third of its maximum value, we use the formula t = 3τ. Substituting the value of τ calculated earlier, we get t = 3 * 6.125 ms = 18.375 ms.
The charge (Q) on the capacitor when the current in the resistor equals one-third its maximum value can be calculated using the formula Q = (1/3) * (VB * C). Substituting the values, we get Q = (1/3) * (55 V) * (3.5 μF) = 6.4175 μC.
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Can someone please help me with science.
Answer:
I believe the answer it D
Explanation:
A park ranger driving on a back country road suddenly sees a deer in his headlights 20
m ahead. The ranger, who is driving at 11.4 m/s, immediately applies the brakes and
slows down with an acceleration of 3.80 m/s2. How much distance is required for the
ranger's vehicle to come to rest? Only enter the number, not the units.
Answer:
17.1
Explanation:
The distance ahead, of the deer when it is sighted by the park ranger, d = 20 m
The initial speed with which the ranger was driving, u = 11.4 m/s
The acceleration rate with which the ranger slows down, a = (-)3.80 m/s² (For a vehicle slowing down, the acceleration is negative)
The distance required for the ranger to come to rest, s = Required
The kinematic equation of motion that can be used to find the distance the ranger's vehicle travels before coming to rest (the distance 's'), is given as follows;
v² = u² + 2·a·s
∴ s = (v² - u²)/(2·a)
Where;
v = The final velocity = 0 m/s (the vehicle comes to rest (stops))
Plugging in the values for 'v', 'u', and 'a', gives;
s = (0² - 11.4²)/(2 × -3.8) = 17.1
The distance the required for the ranger's vehicle to com to rest, s = 17.1 (meters).
A spring with spring constant 58N/cm is stretched 4cm. How much force is it applying
Answer:
232 N
Explanation:
By Hooke's law, the force applied to a spring is proportional to the stretch of the spring, so
F = kx
Where F is the force, k is the spring constant and x is how much it is stretched.
So, replacing k by 58N/cm and x by 4 cm, we get
F = (58 N/cm)(4 cm)
F = 232 N
Therefore, the force applied is 232 N
How do the earths layers compare to other planets in the solar system?
Answer:
Earth is made mostly of silicate rock in its crust and mantle, iron-nickel metal in the core. This is like some other planets -- but very unlike others.
A(n) __________ is the attribute in the supertype entity that determines to which entity subtype each supertype occurrence is related.
a. subtype discriminator
b. inheritance discriminator
c. specialization hierarchy
d. entity supertype
A subtype discriminator is the attribute in the supertype entity that determines to which entity subtype each supertype occurrence is related. Option (a) is correct.
The entity supertype is a concept in a database schema that represents a group of entities that share the same attributes or characteristics. A subtype is a subset of entities that possess specific distinguishing characteristics or attributes that are not present in the supertype. A subtype will have at least one different attribute or relationship, apart from all of the characteristics that the supertype contains.
A subtype is a refinement of a supertype entity. An entity type, known as the supertype, has multiple subtypes that can be derived from it. Subtypes may be exclusive (disjoint) or nonexclusive (overlapping). Exclusive subtypes contain nonoverlapping entities, whereas nonexclusive subtypes have overlapping entities.
Supertype and subtype entities can be used in conjunction with the entity-relationship model. A subtype is a distinct entity that has one or more attributes that are specific to it but not present in its supertype. The subtype of an entity is said to be derived from its supertype by extension or specialization.
Therefore, option (a) is correct.
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A 1.0 μF capacitor is charged for 20 s using a constant current of 10 μA.
What is the charge collected by the sphere each second?
Answer:
200 μC
Explanation:
The charge collected by the sphere each second is equal to the current multiplied by the time. In this case, the current is 10 μA and the time is 20 s, so the charge collected by the sphere each second is 10 μA * 20 s = 200 μC.
I hope this helps! Let me know if you have any other questions or need further assistance.
11 Skipped eBook Derr Company reports the following. Compute (a) controllable variance, (b) volume variance, and (c) total overhead variance. Actual total overhead Budgeted (flexible) overhead at unit
a. Controllable variance of Derr Company if actual total overhead is $980 and budgeted (flexible) overhead at units produced 800 is $180.
b Volume variance is $0.
c. Total overhead variance is $180.
To determine the controllable variance, we can use the formula:
Controllable variance = Actual cost – Budgeted cost (At Actual Units Produced)
= $980 – $800
= $180
To calculate the Volume variance, we can use the formula:
Volume variance = (Standard overhead rate × Actual hours of input) – Standard overhead applied
= ($1.125 × 800) – $900
= $900 – $900
= $0
Therefore, Volume variance is zero.
To calculate the Total overhead variance, we can use the formula:
Total overhead variance = Controllable variance + Volume variance
= $180 + $0
= $180
Therefore, the Controllable variance is $180, Volume variance is $0, and Total overhead variance is $180.
Your question is incomplete, but most probably your full question was
Derr Company reports the following.
Compute (a) controllable variance, (b) volume variance, and (c) total overhead variance.
Actual total overhead $ 980
Budgeted (flexible) overhead at units produced 800
Standard overhead applied 900
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What is the momentum of a two-particle system composed of a 1400 kg car moving east at 70 m/s and a second 1300 kg car moving west at 85 m/s? Let east be the positive direction and answer to 3 significant figures.
Answer:
209000 kg*m/s
Explanation:
Momentum is caclucated using the equation P=mv. Where m is mass and v is velocity.
If you are required to show your work it would be the following:
1400*70=98000 kg*m/s
1300*85=110500 kg*m/s
98000+110500=208500 kg*m/s
209000 kg*m/s
in a ________ fault, the hanging wall block moves up with respect to the footwall block.
.A) normal B) strike slip C) reverse D) abnormal
In a Reverse fault, the hanging wall block moves up with respect to the footwall block.
What is Reverse fault?Reverse fault is a type of fault in which two blocks of earth's crust move away from each other, resulting in the upper block of crust being pushed up above the lower block. It is the opposite of a normal fault, in which two blocks of crust move towards each other. The reverse fault typically occurs when the Earth’s tectonic plates come together and a compressional force pushes up and over the lower plate. This type of fault is usually seen in regions of convergence between two plates and is common along convergent plate boundaries. The reverse fault is usually accompanied by large earthquakes as the plates move against each other. The reverse fault can also be caused by the bending of the Earth’s crust in response to forces such as erosion, volcanic activity and sedimentation. These forces can cause the crust to buckle and rise, resulting in a reverse fault.
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Which of these statements is true about a 'Goldilocks zone'?
1.The distance away from any star where the temperature would allow water to be a
liquid
2.A habitat anywhere in space where life can exists
3.The distance away from our sun where it is too hot or too cold for life to exist
4. A place in a solar system where it is possible for bears to live.
Answer:
3.the distance away from the sun where it to hot or too cold for life to exist
A system has 4 independent and identical motors, in order for the system to work, at least one of the motors must operate. Each motor's failure rate is 0.002 failures per hour. What is the system's Mean Time to Failure (MTTF)?
Answer:
The system's Mean Time to Failure is 1,041.\(\bar 6\) hours
Explanation:
The number of independent identical motors = 4
The failure rate of each motor, λ = 0.002 failures per hour
Given that in order for the system to work, at least one of the motors must operate, therefore, the system are in parallel
The Mean Time to Failure for a parallel system of four identical components is given as follows;
\(MTTF = \dfrac{1 }{\lambda} \times \left (1 + \dfrac{1}{2} + \dfrac{1}{3} + \dfrac{1}{4} \right)\)
Which gives;
\(MTTF = \dfrac{1 }{0.002} \times \left (1 + \dfrac{1}{2} + \dfrac{1}{3} + \dfrac{1}{4} \right) = 1,041.\bar 6\)
The system's Mean Time to Failure = 1,041.\(\bar 6\) hours.
What is principle of liver??
Answer:
lever: Principle of the Lever
lever: Principle of the LeverIt has been found by experiment that two equal forces acting in opposite directions, i.e., clockwise and counterclockwise, and applied to a uniform lever at equal distances from the fulcrum counteract each other and establish a state of equilibrium, or balance, in the lever.
Freud was an influential and controversial psychologist who believed that psychology should study the unconscious mind. Describe
the two books Freud published in the early 1900s. (Site 2)
Answer:
The Interpretation of Dreams": Freud noticed that dreams played an important role in his analysis of neurotic and "hysterical" patients. When he asked his patients to talk about whatever came into their minds, they often referred to their dreams, which would set off other associations and often illuminate other important connections in their past experience. It took Freud about two years to write the book, finishing it in September 1897.
If scientists are interested in studying the composition of the early Solar System, the best objects to study are Choose one: A. comets and asteroids. B. the terrestrial planets. C. the giant planets. D. the Sun.
If scientists exist interested in studying the composition of the early Solar System, the best objects to study exist comets and asteroids.
What is Solar System?The Solar System exists as the gravitationally bound system of the Sun and the objects that orbit it. It was created 4.6 billion years ago from the gravitational descent of a giant interstellar molecular cloud. The vast majority of the system's mass is in the Sun, with most of the remaining mass included in the planet Jupiter.
Our solar system consists of our star, the Sun, and everything attached to it by gravity – the planets Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune; dwarf planets such as Pluto; dozens of moons; and millions of asteroids, comets, and meteoroids.
The asteroid belt between mars and Jupiter includes many planetesimals that were created from the earlier periods of the solar system even, the comet nuclei such as Pluto and Eris are the icy planetesimals that remain today and exist also the sample materials formed from the planetary system.
Hence option A is correct.
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A 2 000-kg sailboat experiences an eastward force of 4 500 N by the ocean tide and a wind force against its sails with magnitude of 1 500 N directed toward the northwest (45° N of W). What is the direction of the resultant acceleration?A. 27° N of WB. 58° N of WC. 27° N of ED. 17° N of WE. 17° N of E
The direction of the resultant acceleration is 17° North of West. The correct answer is D. The first step is to break down the forces into their horizontal and vertical components.
The eastward force from the ocean tide is purely horizontal, while the wind force has both horizontal and vertical components. To find the horizontal component, we use the cosine of the angle between the force and the horizontal axis:
1500 N * cos(45°) = 1060 N
To find the vertical component, we use the sine of the angle:
1500 N * sin(45°) = 1060 N
So the total horizontal force acting on the sailboat is:
4500 N + 1060 N = 5560 N
And the total vertical force is:
1060 N
To find the direction of the resultant acceleration, we can use trigonometry to find the angle that the acceleration vector makes with the horizontal axis. The tangent of this angle is equal to the vertical component of the acceleration divided by the horizontal component:
tan(θ) = 1060 N / 5560 N
θ = tan^-1(1060/5560) = 10.9°
Therefore, the direction of the resultant acceleration is 17° North of West. The correct answer is D.
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