10) -6x + 8y = 0
-3x + 4y = 2

Infinite solution or no solution

Answer:

Step-by-step explanation:

Given the relationship between the elapsed time, tea, in days since the videos first uploaded, and the total number of views, V(d) that the video received modeled by the following function

V(d)=\(4^{1.25d}\)

In order to know the number of views the video will receive after 6 days, we will substitute the number of days i.e d = 6 into the modeled equation as shown;

\(V(6)=4^{1.25(6)}\\V(6)=4^{7.5}\\V(6) = 32,768views\)

Answer:

32,768

Step-by-step explanation:

Answer:

The solution is given below:

Step-by-step explanation:

Given that

The equation is 4.2x

It could present the total price for the no of goods

Here we take an example

The price per chips is $4.2

And, the number of chips purchased be x

And, the total price would be y

So if 5 chips were purchased, so the total price would be

y = $4.2 (5)

= $21

hence, the above represent the description

The region in the plane consists of points whose polar coordinates satisfy the given conditions, and it is enclosed by the circles r = 1 and r = 5, and the rays θ = 3π/4 and θ = 7π/4.

A more detailed explanation of the answer.

To sketch the region in the plane, follow these steps:

1. Identify the polar coordinate conditions: 1 ≤ r < 5, 3π/4 ≤ θ ≤ 7π/4.
2. Plot the radial boundaries: r = 1 and r = 5. These are circles with center at the origin (0, 0) and radii of 1 and 5, respectively.
3. Identify the angular boundaries: θ = 3π/4 and θ = 7π/4. These are rays extending from the origin at angles of 3π/4 (135°) and 7π/4 (315°), respectively.
4. Sketch the region enclosed by the radial and angular boundaries. The region will be a sector of an annulus (ring-like shape) bounded by the two circles and the two rays.

The region in the plane consists of points whose polar coordinates satisfy the given conditions, and it is enclosed by the circles r = 1 and r = 5, and the rays θ = 3π/4 and θ = 7π/4.

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Given:

Consider the expression is \(\sqrt{-12}\).

To find:

The value of given expression.

Solution:

We have,

\(\sqrt{-12}\)

It can be written as

\(\sqrt{-12}=\sqrt{-1\times 12}\)

\(\sqrt{-12}=\sqrt{-1}\times \sqrt{12}\)      \([\because \sqrt{ab}=\sqrt{a}\sqrt{b}]\)

\(\sqrt{-12}=i\times \sqrt{12}\)      \([\because \sqrt{-1}=i]\)

\(\sqrt{-12}=\sqrt{12}i\)

Therefore, the value of given expression is \(\sqrt{12}i\).

Note: all options are incorrect.

The perimeter of the non-shaded region in the figure can be calculated to be 14 inches.

Given a figure.

The middle portion of the figure is not shaded.

It is required to find the perimeter of the non-shaded region.

It is given that:

The whole area of the shaded region = 78 inches²

The area of the small square which is situated at the bottom is:

Area of small square = 2 × 4

                                  = 8 inches²

So, the area of the rest of the shaded area = 78 - 8

                                                                       = 70 inches²

Now, the area of the whole region without the small square is:

Area = 10 × (10 - 2)

        = 80 inches²

So, the area of the non-shaded region = 80 - 70

                                                                = 10 inches²

The width of the non-shaded rectangle is 2 inches.

So, length = 5 inches.

So, the perimeter is:

P = 2(5 + 2)

  = 14 inches

Hence, the perimeter is 14 inches.

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The figure is given below.

Answer:

NULL ; TRUE

Step-by-step explanation:

The sampling distribution is on the assumption that the null hypothesis is true .

The null hypothesis is a general statement that states that there

is no relationship between two phenomenon's under

consideration or that there is no association between two groups.

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The sampling distribution is based on the assumption that the null hypothesis is TRUE.  

A null hypothesis is a general statement that something is. There is no relationship between the two phenomena under or consider that there is no relationship between the two groups.  

The sampling distribution is based on the assumption that the null hypothesis is TRUE.

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Answer:

6π

Step-by-step explanation:

First we need to find the circumference of the circle. We know that the radius is 4 and the formula is πd or 2πr

Leaving it in terms of pi, the circumference is 8π

Now we need to find the length of the arc.

Since the missing part of the circle is labeled with a right angle, we know that it's exactly 1/4 of the whole circle. That means the arc we need to find is 3/4 of the circumference.

3/4 of 8π is 6π

The matrix representation of M with respect to the basis {1, i} is:

[0 -1]

[1 0]

The linear transformation M takes complex numbers and multiplies them by the imaginary unit i. In this case, we want to represent this transformation using a matrix. To do that, we need to determine the images of the basis vectors 1 and i under M. For the basis vector 1, when we apply M to it, we get i as the result. Similarly, for the basis vector i, applying M gives us -1. These results form the columns of the matrix representation. Therefore, the matrix representing M with respect to the basis {1, i} is [0 -1; 1 0], where the first column corresponds to the image of 1 and the second column corresponds to the image of i.

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The probability is approximately 0.9167 or 91.67%.

To find the probability that the sum of two dice numbers does not exceed 10, we need to determine the favorable outcomes (sums less than or equal to 10) and the total possible outcomes when rolling two dice.

There are 36 possible outcomes when rolling two dice because each die has six faces (1, 2, 3, 4, 5, and 6), and the total number of outcomes is obtained by multiplying the number of outcomes for each die (6 * 6 = 36).

Now let's determine the favorable outcomes (sums less than or equal to 10):

When the sum is 2: There is only one combination (1 + 1).

When the sum is 3: There are two combinations (1 + 2 and 2 + 1).

When the sum is 4: There are three combinations (1 + 3, 2 + 2, and 3 + 1).

When the sum is 5: There are four combinations (1 + 4, 2 + 3, 3 + 2, and 4 + 1).

When the sum is 6: There are five combinations (1 + 5, 2 + 4, 3 + 3, 4 + 2, and 5 + 1).

When the sum is 7: There are six combinations (1 + 6, 2 + 5, 3 + 4, 4 + 3, 5 + 2, and 6 + 1).

When the sum is 8: There are five combinations (2 + 6, 3 + 5, 4 + 4, 5 + 3, and 6 + 2).

When the sum is 9: There are four combinations (3 + 6, 4 + 5, 5 + 4, and 6 + 3).

When the sum is 10: There are three combinations (4 + 6, 5 + 5, and 6 + 4).

Adding up the favorable outcomes, we get: 1 + 2 + 3 + 4 + 5 + 6 + 5 + 4 + 3 = 33.

Therefore, the probability that the sum of the two dice numbers does not exceed 10 is given by:

Probability = Favorable outcomes / Total outcomes = 33 / 36 = 11/12 ≈ 0.9167.

So, the probability is approximately 0.9167 or 91.67%.

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(a) The probability that there are no calls within a 30-minute interval is approximately 0.3680. (b) 0.4689. (c) 0.2160. (d)47.60 minutes.

(a) To find the probability that there are no calls within a 30-minute interval, we can use the exponential distribution. The parameter λ (lambda) for the exponential distribution is equal to 1/mean.

Given that the mean time between calls is 16 minutes, we can calculate λ as:

λ = 1/16

Now, let's calculate the probability using the exponential distribution formula:

P(no calls within 30 minutes) = e^(-λt)

P(no calls within 30 minutes) = e^(-(1/16) * 30)

P(no calls within 30 minutes) ≈ 0.3680

So, the probability that there are no calls within a 30-minute interval is approximately 0.3680.

(b) To find the probability that at least one call arrives within a 10-minute interval, we can use the complementary probability. The complementary probability is 1 minus the probability of no calls within the interval.

P(at least one call within 10 minutes) = 1 - P(no calls within 10 minutes)

P(at least one call within 10 minutes) = 1 - e^(-λt)

P(at least one call within 10 minutes) = 1 - e^(-(1/16) * 10)

P(at least one call within 10 minutes) ≈ 0.4689

So, the probability that at least one call arrives within a 10-minute interval is approximately 0.4689.

(c) To find the probability that the first call arrives within 5 and 10 minutes after opening, we can subtract the probability of no calls within 10 minutes from the probability of no calls within 5 minutes.

P(first call within 5-10 minutes) = P(no calls within 10 minutes) - P(no calls within 5 minutes)

P(first call within 5-10 minutes) = e^(-λ*10) - e^(-λ*5)

P(first call within 5-10 minutes) ≈ 0.2160

So, the probability that the first call arrives within 5 and 10 minutes after opening is approximately 0.2160.

(d) To determine the length of an interval of time such that the probability of at least one call in the interval is 0.90, we need to find the value of t that satisfies the equation:

P(at least one call within t minutes) = 0.90

Using the exponential distribution formula:

1 - e^(-λt) = 0.90

e^(-λt) = 1 - 0.90

e^(-λt) = 0.10

Taking the natural logarithm of both sides:

-λt = ln(0.10)

t = ln(0.10) / -λ

Substituting λ = 1/16:

t ≈ 47.5957 minutes

So, the length of the interval of time such that the probability of at least one call is 0.90 is approximately 47.60 minutes.

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Answer:

A) x=sq rt 80

Step-by-step explanation:

by the Pythagorean theorem

4^2+8^2=x^2

16+64=x^2

80=x^2

x=sq root 80

Answer:

Step-by-step explanation:

Pythagorean theorem,

Hypotenuse² = Altitude² + Base²

x² = 8² + 4²

   = 64 + 16

  = 80

x = √80

Answer:

The answer is C.

mark me brainliest!

Answer:

Option C

Kindly award branliest

Step-by-step explanation:

Tn = n(n + 1)

T1 = 1(1 +1) = 1(2) = 2

T2 = 2(2+1) = 2(3) =6

T3 = 3(3 + 1) = 3(4) = 12

T4 = 4(4 + 1) = 4(5) = 20

... It obeys

Answer:

x = m × p - n

Step-by-step explanation:

\(m = n + \frac{x}{p} \)

We can first multiply both sides by p.

\(m \times p = n + x\)

And now we only have n left with x, so we subtract n on both sides.

\(m \times p - n = x \\or \\ x = m \times p - n\)

In this scenario, the shape of the sampling distribution of X-bar is approximately normal.

The sampling distribution of the sample mean, X-bar, can be determined by the Central Limit Theorem. In this case, since the sample size is large (n = 64) and the underlying distribution (X) is approximately normal, the sampling distribution of X-bar will also be approximately normal. The Central Limit Theorem states that regardless of the shape of the population distribution, as the sample size increases, the sampling distribution of X-bar tends to become more and more normal. Therefore, in this scenario, the shape of the sampling distribution of X-bar is approximately normal.

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The correct statement is "Stores A and B have an equal spread." (option b).

To determine the spread of the data, we first need to find the range. The range is calculated by subtracting the smallest number from the largest number in a dataset.

For Store A:

The smallest number recorded is 2, and the largest number is 4. Therefore, the range of Store A is 4 - 2 = 2.

For Store B:

The smallest number recorded is 3, and the largest number is 5. Thus, the range of Store B is 5 - 3 = 2.

Comparing the ranges of both stores, we see that both Store A and Store B have the same range, which means the spread of the data is equal for both stores.

Therefore, the correct statement is:

b) Stores A and B have an equal spread.

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So a slope of 1/4 means that for every 4 steps you take forward, you would go up 1.

With this, beginning at the point (6,3), lets take 4 steps back and go down 1. This is instead of going forward, as that value would be outside of your graph We would end up at (2,2). By using these two points, you can graph your line.

The value for x is 7π/6 and 11π/6.

sin2xsecx+2cosx=0

(2sinxcosx)(1/cosx)+2cosx=0

sinxcosx/cosx+2cosx=0

So,

2sinx+2cosx=0

2(sinx+cosx)=0

(2(sinx+cosx))²=0

4(sin²x+cos²x+2sinxcosx)=0

hence,

(sin²x+cos²x+2sinxcosx)/4=0/4

sin2x+cos2x+2sinxcosx=0

1+sin2x=0

sinx=−1/2

=7π/6 and 11π/6

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Answer:

By 3.

Step-by-step explanation:

-12-3=-15

Hope this helps!

Answer:

-12 exceeds -15 by 3

Step-by-step explanation:

To find out by how much a exceeds b, subtract a - b.

For example, by how much does 8 exceed 6?

Here, a = 8 and b = 6.

a - b = 8 - 6 = 2

2 is correct since we know that 8 is 2 greater than 6.

Now we do this problem.

By how much does -12 exceed -15?

a = -12; b = -15

a - b = -12 - (-15) = -12 + 15 = 3

Answer: -12 exceeds -15 by 3

Answer:

22.5

Step-by-step explanation:

first of all, the first sign in the designations of the triangles is not an A. it is the Greek Delta (capital) sign. standing for "triangle" due to its shape.

as the diagram shows (and the description says correctly), ADL and AKM are similar triangles.

that means they have the same angles.

and in order to keep the same angles even when the lengths of the sides are different, the relative relation of the side lengths must be the same for all sides.

that means, if one side changes by a factor f, then both other sides must change by the same factor.

so, by checking the change factor for AD (to AK), we can then determine the change of AL to AM. and then we simply subtract AL from AM and get LM.

the original AD = 14.

AK = AD + DK = 14 + 21 = 35

the change factor f is then AK/AD = 35/14 = 5/2

in other words AD grew by a factor of 5/2.

AM is then created by applying the same factor to AL.

=> AM = 15 * 5 / 2 = 75 / 2 = 37.5

=> LM = AM - AL = 37.5 - 15 = 22.5

Step-by-step explanation:

intindihin nyo na lang.

the distance from the plane to the radar station is increasing at a rate of approximately 30.84 kilometers per minute.

A triangle is said to be right-angled if one of its angles is exactly 90 degrees. The total of the other two angles is 90 degrees. Perpendicular and the triangle's base are the sides that make up the right angle. The longest of the three sides, the third side is known as the hypotenuse.

Given, A plane flying with a constant speed of 25 km/min passes over a ground radar station at an altitude of 12 km and climbs at an angle of 30 degrees.

We can use the law of cosines to find d:

d² = 12² + (h + 12)² - 2(12)(h + 12)cos(θ)

Since the plane is climbing at an angle of 30 degrees, we can use trigonometry to find h:

sin(30) = h / (25 km/min * 2 min)

h = 25 km/min

Now we can substitute this value of h into the equation for d and simplify:

d² = 12² + (25 + 12)² - 2(12)(25 + 12)cos(θ)

d² = 12² + 37² - 2(12)(37)cos(θ)

d² = 144 + 1369 - 888cos(θ)

d² = 1513 - 888cos(θ)

To find the rate at which d is changing, we can take the derivative of both sides of this equation with respect to time:

2dd/dt = -888(d(cos(θ))/dt)

Since the plane is flying with a constant speed of 25 km/min, we can use trigonometry to find d(cos(θ))/dt:

cos(θ) = 12/d

d(cos(θ))/dt = -(12/d²)(dd/dt)

d(cos(θ))/dt = -(12/d²)(25 km/min)

Now we can substitute these values into the equation for the rate of change of d:

2dd/dt = -888(-(12/d²)(25 km/min))

2dd/dt = (888*12)/(d²)(25 km/min)

dd/dt = (5328)/(d²) km/min

Finally, we can substitute the value we found for d into this equation to get the rate at which d is changing 2 minutes later:

d = sqrt(1513 - 888cos(θ))

θ = 30 degrees

dd/dt = (5328)/(d²) km/min

dd/dt = (5328)/(1513 - 888cos(30)) km/min

dd/dt ≈ 30.84 km/min

Therefore, the distance from the plane to the radar station is increasing at a rate of approximately 30.84 kilometers per minute.

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Answer:

Step-by-step explanation:

Step-1: Convert the mixed fractions into improper fractions.

Step-2: Multiply the improper fractions.

[The minuses on both fractions cancelled out because when there are 2 minuses multiplying each other, the minuses cancel out.]

Step-3: Convert the improper fraction into mixed fraction.

Hence, the answer is 9 1/5.

Hoped this helped.

\(BrainiacUser1357\)

Answer:

False, 82 inches is not greater than 5 feet and 10 inches

Step-by-step explanation:

1 feet = 12 inches

5x12=60+10=70

82 is greater than 70.

The percentage of races in will his finishing time is between 64.5 and 65.5 seconds is 68%.

According to the empirical rule, also known as the 68-95-99.7 rule, the percentage of values that lie within an interval with 68%, 95%, and 99.7% the values lies within one, two, or three standard deviations of the mean of the distribution.

\(\rm P(\mu - \sigma \ \ < X < \mu + \sigma) \ \approx 68\%\\\\P(\mu - 2\sigma < X < \mu + 2\sigma) \approx 95\%\\\\P(\mu - 3\sigma < X < \mu + 3\sigma) \approx 99.7\%\)

where we had were mean of the distribution of X is μ and the standard deviation from the mean of the distribution of X is σ (assuming X is normally distributed).

When Kiran runs the 400 meters dash, his finishing times are normally distributed with a mean of 65 seconds and a standard deviation of 0.5 seconds.

Then by the formula, we have

\(\rm P (65-0.5 < X < 65+0.5) = P(64.5 < X < 65.5) \approx 68\%\)

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The graph of -4x+3y=-30 is shown below.

The x-intercept of -4x+3y=-30 is: 7.5

The y-intercept of -4x+3y=-30 is: -10.

The x-intercept of a linear equation can be determined from its graph, where it is the point where the x-axis it intercepted by the line.

On the other hand, the y-intercept is the point on the y-axis that the graph intercepts or crosses.

Given the linear equation, -4x+3y=-30, find the x and y-intercepts as shown  below:

Find the x-intercept by substituting y = 0 into -4x+3y=-30:

-4x + 3(0) = -30

-4x = -30

x = -30/-4

x = 7.5

x-intercept is 7.5

Find the y-intercept by substituting x = 0 into -4x + 3y = -30:

-4(0) + 3y = -30

3y = -30

y = -30/3

y = -10.

y-intercept is -10.

The graph of the linear equation that shows the x and y-intercepts is shown in the diagram below.

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The required Matlab code to find the greatest common divisor of a number using the Euclidean algorithm is shown.

To find the greatest common divisor (GCD) of two numbers using the Euclidean algorithm in MATLAB, you can use the following code:

% Replace '12345678' with your actual student number

studentNumber = '12345678';

% Extract the first 4 digits as the first number

firstNumber = str2double(studentNumber(1:4));

% Extract the last 3 digits as the second number

secondNumber = str2double(studentNumber(end-2:end));

% Find the GCD using the Euclidean algorithm

gcdValue = gcd(firstNumber, secondNumber);

% Display the result

disp(['The GCD of ' num2str(firstNumber) ' and ' num2str(secondNumber) ' is ' num2str(gcdValue) '.']);

Make sure to replace '12345678' with your actual student number. The code extracts the first 4 digits as the first number and the last 3 digits as the second number using string indexing. Then, the gcd function in MATLAB is used to calculate the GCD of the two numbers. Finally, the result is displayed using the disp function.

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Answer:

Tell me you address right now!!!

Step-by-step explanation:

I am gonna call police for help!

-3 is less than 2

< is the symbol