Answer:
Wavelength is the distance between the two closest points that are in phase with each other along a wave.
Explanation:
most of the waves in the electromagnetic spectrum are
Answer:
The entire electromagnetic spectrum, from the lowest to the highest frequency (longest to shortest wavelength), includes all radio waves (e.g., commercial radio and television, microwaves, radar), infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays.
answer questions show work #3
3. Determine the value of ID and VDs for the DS following amplifier. 10 RD 10V 3KD Points 0.47μF 01 G= 0.47μF Hilt RG 1.5MO -1V N5486 VGSoff = -4V IDSS = 14mA
The given amplifier circuit is a common-source amplifier. The equivalent circuit diagram of the amplifier includes a MOSFET N5486 transistor. We can determine the drain current (ID) and drain-source voltage (VDS) using the following equations:
1. Voltage at the source terminal (VS) is calculated using Ohm's law: VS = IS x RS.2. The drain current (ID) can be calculated using the equation ID = IS (1 + GVin), where Vin is the input voltage, G is the voltage gain, and IS is the current flowing through RD.Let's calculate the values of ID and VDS:
Given:- IS = VDD / RD = 10V / 10Ω = 1A- Vin = -1V / (1.5 x 10^6Ω + 0.47μF) = -0.6666667μA (using voltage divider rule)- G = -RD / RS = -10Ω / 3kΩ = -0.003333 Calculating ID:ID = 1A (1 - 0.003333 x 0.6666667 x 10^6)≈ 0.997A = 997mACalculating VDS:VDS = VDD - IDRD= 10V - 997mA x 10Ω≈ 10V - 9.97V≈ 0.03VTherefore, the values of ID and VDS are approximately ID = 997mA and VDS ≈ 0.03V, respectively.
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Two small speakers, 0.695 m apart, are facing in the same direction. They are driven by one 668 Hz oscillator and therefore emit identical sound waves in phase with one another at the respective points of origin. (The speed of sound waves in air is 343 m/s.)
(a) A sound engineer wishes to stand in front of one of the speakers, at the closest point (i.e., smallest x-value) where intensity is at a relative maximum. At what distance x from the nearest speaker should he position himself? (Enter your answer in m.)
(b) The sound engineer now wishes to stand at the closest point along that line where intensity is at a relative minimum. At what distance x should he position himself now? (Enter your answer in m.)
A) The distance x from the nearest speaker when intensity is at maximum ; 0.4272 m
B) The distance x from the nearest speaker when intensity is at minimum ; 0.8123 m
Given data :
Distance between speakers ( d ) = 0.695 m
Frequency of oscillator = 668 Hz
Speed of sound waves in air ( v ) = 343 m/s
A) Determine the distance x from the nearest speaker when he stands where intensity is at maximumGiven that
λ = v / f
= 343 / 668
= 0.5135
Also
Δx = \(\sqrt{d^2+x^2} - x\)
Δx = λ for maximum intensity
λ = \(\sqrt{d^2+x^2} - x\)
x = ( d² - λ² ) / λ
= ( 0.695² - 0.5135² ) / 0.5135
= 0.4272 m
B) Determine the distance x from the nearest speaker when he stands where intensity is at minimumGiven that
λ = v / f
= 343 / 668
= 0.5135
Also
Δx = S₁P - S₂P
Δx = \(\sqrt{d^2+x^2} - x\)
since the intensity is minimum
Δx = λ/2
Therefore
λ/2 = \(\sqrt{d^2+x^2} - x\)
x = ( d² - λ²/4 ) / λ
= ( 0.695² - 0.5135² / 4 ) / 0.5135
= ( 0.695² - 0.0659 ) / 0.5135
= 0.4171 / 0.5135 = 0.8123 m
Hence we can conclude that The distance x from the nearest speaker when intensity is at maximum ; 0.4272 m and The distance x from the nearest speaker when intensity is at minimum ; 0.8123 m.
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Noah drops a rock with a density of 1.73 g/cm° into a
pond. Will the rock float or sink? Explain your answer.
Answer:
the rock will probably sink in water because density of rock heavier than the density of water.
Density of water=1g/cm
density of rock=1.73g/cm
1g/cm< 1.73g/cm
Need answers only for question 4 & 5
Need the correct answer ASAP.
Will give the brainliest!
#4
Resistors are connected in parallel circuit
Voltage is constant as usual in circuitsCurrent is different#5
They differs
Because
For series connection
\(\\ \rm\rightarrowtail R_{net}=R_1+R_2\dots\)
For parallel connection
\(\\ \rm\rightarrowtail \dfrac{1}{R_{net}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\dots\)
So resistance becomes low in parallel circuitSo, here for question no. 4 and 5, we are given a Diagram, which have 3 resistors connected in parallel each having a resistance of \({\bf{2\Omega}}\), \({\bf{3\Omega}}\) and \({\bf{4\Omega}}\). And we are told to find a factor which will change for the given combination, and a factor which will not change, So here, as the resistors are connected in parallel, so the voltage will remain same for all the resistors, while the Current will be different for every resistor, And that's what the reason of why we always do connection in parallel for home purposes, because, we need voltage same in every resistor of the circuit. So, the factor which will change is \({\boxed{\bf{Current}}}\) and the factor which willn't change is \({\boxed{\bf{Voltage}}}\), and if the resistors were connected in Series combination, then current should be same for all resistors, while voltage will change.
Well, if the resistors are connected in the above way we have, and if we call our Resistors as \({\bf{R_{1}}}\), \({\bf{R_{2}}}\) and \({\bf{R_{3}}}\), then the equivalent resistance we will be having is :
\({:\implies \quad \boxed{\bf{\dfrac{1}{R_{eq.}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}}}}\)
Also, we can prove this fact just with the help of the reason provided in the above question, i.e that in Parallel combination, voltage remains same, but current changes, while in Series combination, current remains same but voltage changes, so we are just gonna prove the formula for both series combination and Parallel as well
So, let's prove the formula for series combination first, so consider n resistors connected in series, let Resistors as \({\bf{R_{1},R_{2},R_{3}\cdots \cdots R_{n}}}\), now as current will be same through all the resistors as connected in series, so if the current \({\bf{I}}\) from then, same current will flow through the whole circuit and each resistors, also let the voltages of every resistors being \({\bf{V_{1},V_{2},V_{3}\cdots \cdots V_{n}}}\), so now by Ohm's law, we can deduce that, the current from first circuit will be \({\bf{V_{1}=IR_{1}}}\)...and so on for all Resistors, and now if we add all resistors, so the equivalent Voltage will just be ;
\({:\implies \quad \sf V_{eq.}=V_{1}+V_{2}+V_{3}+\cdots \cdots +V_{n}}\)
\({:\implies \quad \sf IR_{eq.}=IR_{1}+IR_{2}+IR_{3}+\cdots \cdots IR_{n}}\)
\({:\implies \quad \sf I(R_{eq.})=I(R_{1}+R_{2}+R_{3}+\cdots \cdots R_{n})}\)
\({:\implies \quad \boxed{\bf{R_{eq.}=R_{1}+R_{2}+R_{3}+\cdots \cdots R_{n}}}}\)
Therefore, we proved for series.
Now, consider n resistors connected in parallel, with resistances, \({\bf{R_{1},R_{2},R_{3}\cdots \cdots R_{n}}}\), now as voltage will be same through all the resistors as connected in parallel,while current will change, so let total voltage be \({\bf{V}}\), and current for each resistor as \({\bf{I_{1},I_{2},I_{3}\cdots \cdots I_{n}}}\),so by using the same concept as above we can write by using ohm's law :
\({:\implies \quad \sf I_{eq.}=I_{1}+I_{2}+I_{3}+\cdots \cdots +I_{n}}\)
Rewrite using ohm's law :
\({:\implies \quad \sf \dfrac{V}{R_{eq.}}=\dfrac{V}{R_1}+\dfrac{V}{R_2}+\dfrac{V}{R_3}+\cdots \cdots +\dfrac{V}{R_n}}\)
\({:\implies \quad \sf V\dfrac{1}{R_{eq.}}=V\bigg(\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}+\cdots \cdots +\dfrac{1}{R_n}\bigg)}\)
\({:\implies \quad \boxed{\bf{\dfrac{1}{R_{eq.}}=\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}+\dfrac{1}{R_{3}}+\cdots \cdots +\dfrac{1}{R_{n}}}}}\)
Hence, we proved for Parallel combination too
Also, refer to the attachment for a better understanding, and just a point that Voltmeter is always connected in parallel while ammeter in series, and all the things above are taken in SI units
A solenoid of 100 turns has a length of 50.0 cm and a cross-sectional area of 0.385m^2. a) Find the self-inductance of the solenoid. b) Suppose the current in the solenoid increases according to the following formula. I(t)=(5.00A)e^t/2.00s
Find the induced emf in the solenoid when t=20.0 s.
Length of the solenoid, l = 50.0 cm = 0.50 mA = 0.385 m²µ₀ = 4π x 10⁻⁷ H/m. L = (µ₀N²A)/lL = [4π x 10⁻⁷ H/m × (100)² × 0.385 m²]/0.50 mL = 7.87 x 10⁻⁴ H. The induced emf in the solenoid when t=20.0 s is -4.13 V
a) Find the self-inductance of the solenoid.
A solenoid is a type of electromagnet, the wire coiled up such that it produces a magnetic field when electric current passes through it.
The self-inductance of the solenoid can be given by the formula:
L= (µ₀N²A)/
lwhere µ₀ is the permeability of free space
N is the number of turns of the solenoid
l is the length of the solenoid
A is the cross-sectional area of the solenoid
Given that, Number of turns, N = 100
Length of the solenoid, l = 50.0 cm = 0.50 mA = 0.385 m²µ₀ = 4π x 10⁻⁷ H/m. L = (µ₀N²A)/lL = [4π x 10⁻⁷ H/m × (100)² × 0.385 m²]/0.50 mL = 7.87 x 10⁻⁴ H.
b) Find the induced emf in the solenoid when t = 20.0 s.
The induced emf (ε) can be calculated by the formula;
ε = -L dI/dt
where L is the self-inductance of the solenoid and dI/dt is the time rate of change of the current given by;
I(t)=(5.00A)e^t/2.00s
Differentiating I(t) with respect to t gives; dI/dt = 5e^t/2 V/s (Volts per second)Given that L = 7.87 x 10⁻⁴ HWhen t = 20.0s; ε = - L dI/dt = -7.87 × 10⁻⁴ H × (5e^20/2) = -4.13 V
Therefore, the induced emf in the solenoid when t=20.0 s is -4.13 V.
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Two forces, F1 and F2, having magnitudes 20 N and 35 N, respectively, act on an object at angles of 32∘ and 146∘ (angles in standard position). 10 polnts a. Find the resultant vector. Round coefficients to the nearest hundredth. 4 points b. Approximate the magnitude of the resultant vector. Round your answer to the nearest hundredth.
a. The resultant vector is 8.46 N, 43.05 N. (Rounded to the nearest hundredth) b. The magnitude of the resultant vector is approximately 44.00 N. (Rounded to the nearest hundredth).
The resultant vector (R) is given by adding the two vectors (F1 and F2) together, where R = F1 + F2. The following steps can be followed to solve the problem:
1: Break each force vector into its x- and y-components by using trigonometry.
F1x = F1cos(32°) = 16.91 N (positive because it's in the +x-direction)
F1y = F1sin(32°) = 10.58 N (positive because it's in the +y-direction)
F2x = F2cos(146°) = -8.45 N (negative because it's in the -x-direction)
F2y = F2sin(146°) = 32.47 N (positive because it's in the +y-direction)
2: Add the x-components and y-components separately to identify the components of the resultant vector.
Rx = F1x + F2x
= 16.91 N + (-8.45 N)
= 8.46 N (positive because it's in the +x-direction)
Ry = F1y + F2y = 10.58 N + 32.47 N = 43.05 N (positive because it's in the +y-direction)
3: Identify the magnitude of the resultant vector by using the Pythagorean theorem.
R = √(Rx² + Ry²) = √(8.46² + 43.05²) ≈ 44.00 N (rounded to the nearest hundredth)
b. Approximate the magnitude of the resultant vector is 44.00 N by rounding the answer to the nearest hundredth.
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According to the tachometer in the car the engine is rotating at 3500 RPM. Through what angle will this engine rotate each minute?
Answer:
Please look at the Explanation.
Explanation:
Assuming that the engine runs at a constant speed of 3500 revolutions per minute (RPM), we can calculate the angle through which it rotates each minute using the following steps:
Convert RPM to RPS (revolutions per second) by dividing by 60, since there are 60 seconds in a minute:
3500 RPM ÷ 60 = 58.33 RPS
Multiply RPS by 2π (the number of radians in a complete circle) to find the angle in radians per second:
58.33 RPS × 2π = 366.93 radians/second
Finally, multiply by 60 to convert radians per second to radians per minute:
366.93 radians/second × 60 seconds/minute = 22,015.8 radians/minute
Therefore, the engine rotates through an angle of approximately 22,015.8 radians each minute when it is running at 3500 RPM.
which of the following conditions describes the planet that would be least likely to have an atmosphere?
a.low mass, small radius, low temperature b.large mass, large radius, high temperature c.low mass, large radius, high temperature d.large mass, large radius, low temperature
Option A - low mass, small radius, low temperature: condition describes the planet that would be least likely to have an atmosphere.
The presence of an atmosphere on a planet depends on several factors, including the planet's mass, radius, and temperature. Let's evaluate each option:
a. low mass, small radius, low temperature:
A low mass and small radius indicate a relatively small and less massive planet.
Additionally, a low temperature suggests that the planet is unable to retain heat effectively.
As a result, the gravitational force on this planet would be weak, making it difficult for the planet to hold onto an atmosphere.
The low temperature would also inhibit the ability to sustain gases in a gaseous state.
b. large mass, large radius, high temperature:
A large mass and radius suggest a massive planet with a strong gravitational force.
In this case, it would be easier for the planet to retain an atmosphere due to the higher gravity.
The high temperature indicates that gases would have more energy, increasing the likelihood of them being in a gaseous state.
c. low mass, large radius, high temperature:
A low mass combined with a large radius indicates a relatively low density planet.
Although it has a large radius, the weak gravitational force resulting from the low mass would make it challenging for the planet to hold onto an atmosphere.
The high temperature would increase the energy of gases, making it more likely for them to escape into space.
d. large mass, large radius, low temperature:
A large mass combined with a large radius suggests a massive planet with a strong gravitational force.
Consequently, it would be easier for the planet to retain an atmosphere due to the higher gravity.
The low temperature would reduce the energy of gases, making it less likely for them to escape into space.
Based on the factors discussed above, the planet described in option A - low mass, small radius, low temperature - would be least likely to have an atmosphere.
The weak gravitational force resulting from its low mass, along with the low temperature, would make it difficult for the planet to retain gases in a gaseous state and hold onto an atmosphere.
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10. A cheetah accelerates at 7.3 m/s² with a force of 420 N. What is
the cheetah's mass?
if a car has a negative acceleraction, what is the car doing?
An object has 23 Kg*m/s of momentum and a mass of 3 Kg. What is the objects velocity
Answer:
23 m/s
Explanation:
TRUE OR FALSE, PLEASEE HELPPP ASAP
6) The amount of work done on an object depends on the final speed of the object
7) 1 Horsepower (hp) is equal to 746 Watts.
8) The SI unit for Work is the Joule.
9) The lower the percentage, the better the efficiency
10) The Work-Energy theorem states that the change in kinetic energy also equals the amount of work done on an object or system.
Answer: You do not deserve help, You dont help other people you only use them for points so...do not ask for help from us now
Explanation:
A 136 kg defensive lineman is about to tackle a 100 kg quarterback. Right before
impact, the lineman is moving north at 6.0 m/s and the quarterback is moving
north at 1.0 m/s. Determine the speed and direction of the two players
immediately after the tackle.
Answer:
3.88 m/s North
Explanation:
We are given that
\(m_1=136kg\)
\(m_2=100 kg\)
\(v_1=6 m/s\)
\(v_2=1m/s\)
We have to find the speed and direction of the two players
immediately after the tackle.
Using linear conservation of momentum
\(m_1v_1+m_2v_2=(m_1+m_2)v\)
Substitute the values
\(136\times 6+100\times 1=(136+100)v\)
\(916=236v\)
\(v=\frac{916}{236}\)
\(v=3.88m/s\)
Direction of the two players immediately after the tackle is North.
Global heating trend on Earth, the atmosphere expands and the length of the day increases very slightly. Explain why the length of day increases
Answer:
Due to increase in the inertia and velocity of the earth by the warming of air.
Explanation:
Due to the rise of global warming, the effects of GHG gases are increasing and the atmosphere warms and starts to expand with the length of the day. This is due to the movement of the earth's expanding air cause the earth's inertia to increase which causes the mass to go or bulge outwards. The velocity increases with the movement of inertia and thus causes the day to lengthen.the body acts on a force of 3N with the shoulder 20 cm. What is her moment?
Answer:
0.6Nm
Explanation
Given
Force = 3N
Distance = 20cm = 0.2m
Moment = Force * perpendicular distance
Substitute
Moment = 3N * 0.2
Moment = 0.6Nm
Hence her moment is 0.6Nm
What is the Eg, Ek, and Ediss of a skier starting at an elevation of 40m and ending at 0m elevation
Answer:
E_g = m 392 J, Ek = m 392
Explanation:
Mechanical energy is a very important concept since if the system does not have friction it remains constant
the potential energy of a system is
E_g = U = m g (y2 - i)
E_g = m 9.8 (40 -0)
E_g = m 392 J
The kinetic energy for this system assuming it started from rest
E_k = K = ½ m v2
how mechanical energy is conserved
E_g = E_k
Ek = m 392
Two objects in a closed system collide. After the collision, one object has lost speed, but the other object has gained speed. Explain what has happened. A. Total momentum in a closed system is conserved. B. Gravitation potential energy converts to kinetic energy. C. Kinetic energy converts to gravitational potential energy. D. Mass is conserved
A. Total momentum in a closed system is conserved
the law of momentum conservation states that The total amount of momentum before the collision is the same as the total momentum after the collision. Regardless of the change of momentum of each object.
when light somewhat penetrates the surface of a material and reflects in all directions, with some of the light being absorbed, the reflection is called
When light somewhat penetrates the surface of a material and reflects in all directions, with some of the light being absorbed, the reflection is called diffuse reflection.
Diffuse reflection occurs when light is scattered in all directions after it strikes a surface. This happens because the surface is rough or has a low-reflectivity coating, which causes the light to bounce in many directions instead of being reflected in a single direction.
In the case of diffuse reflection, some of the light is absorbed by the material, while the rest is reflected in all directions. This means that the overall intensity of the reflected light is reduced compared to specular reflection, which occurs when light is reflected in a single direction from a smooth, highly reflective surface.
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A rectangular block of steel measures 4cm*2cm*1.5cm*. its mass is 93.6g
a) calculate the density of steel.
b) Steel is made entirely of iron atoms but is denser than iron.
suggest a reason for this
Answer:
b
Explanation:
What are the advantages and/or disadvantages of the radiation that technology has had for the human economy?
8. An object has a force applied. The object has a mass of 36 Kg and accelerates at 3.4 m/sec2. What is the force acting on the object? *
a. 120.6 N
b. 126.9 N
c. 122.4 N
d. 118.3 N
Answer:
122.4
Explanation:
What function does large volumes of moving water have in generating electricity
Impoundment or dams are used to collect the water to enhance the amount of running water. Gravity is used to direct water down a pen stock pipe from a hole in the dam. The turbine is spun by the flowing water, and this rotation of the magnets inside the generator produces power.
What is Hydroelectric Energy?Hydroelectric energy, also known as hydroelectric power or hydroelectricity, is a type of energy that uses the force of moving water to produce electricity, such as water running down a waterfall. This force has been utilized by people for ages. Greeks have been grinding wheat into flour for over 2,000 years by using flowing water to turn their mill's wheel.
The majority of hydroelectric power plants feature a water reservoir, a gate or valve to regulate the amount of water that flows out of the reservoir, and an outlet or location where the water ends up after flowing downstream. Just before water rushes over the top of a dam or cascades down a hill, it gains potential energy. Water flowing downhill changes potential energy into kinetic energy. When a turbine's blades are turned by water, electricity is produced and sent to the power plant's users.
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Suppose Alex is navigating using a compass. She starts walking at an angle of 60° north of east and walks a total of 100 m. How far north is she from the starting point? How far east?
Answer:
\(50\:\mathrm{m\: North}\\50\sqrt{3}\:\mathrm{m\: East}\)
Explanation:
We can create a 30-60-90 triangle. The distance she walked is then the hypotenuse of the triangle, and using 30-60-90 triangle rules, we have the following:
The North leg is opposite to the \(30^{\circ}\) angle. Therefore, if we call this distance \(y_N\), we have the following:
\(\sin 30^{\circ}=\frac{y_N}{100},\\\frac{1}{2}=\frac{y_N}{100},\\y_N=\fbox{$50\:\mathrm{m}$}\).
The East leg is opposite to the \(60^{\circ}\\\) angle. If we call this distance \(x_E\), we have:
\(\sin 60^{\circ}=\frac{x_E}{100},\\\frac{\sqrt{3}}{2}=\frac{x_E}{100},\\x_E=\fbox{$50\sqrt{3}\:\mathrm{m}$}\).
Four different balls with different masses (measured in grams) were dropped from the same height on Earth. Assuming no other forces acted on the balls, match each ball with the gravitational force (measured in newtons) it experienced as it fell.gravitational force = 9.8 m/s2
We will have the following:
1. 143 g = 0.143 kg:
\(F=(0.143kg)(9.8m/s{}^2)\Rightarrow F=1.4014N\)2. 110 g = 0.110 kg:
\(F=(0.110kg)(9.8m/s^2)\Rightarrow F=1.078N\)3. 410 g = 0.410 kg:
\(F=(0.410kg)(9.8m/s^2)\Rightarrow F=4.018N\)4. 46 g = 0.046 kg:
\(F=(0.046kg)(9.8m/s^2)\Rightarrow F=0.4508N\)From this we can see that the given weights do not correspond to any of the values of column B, since the calculations to obtain the values of column B were done using grams, instead of kg, thus those values do not correspond to the unit of force Newtons.
You push a block to the top of an inclined plane. The mechanical advantage of the plane is 5. The inclined plane is 10 meters long. What is the height of the inclined plane?
0.5 m
2 m
50 m
10 m
Answer:
Height of the inclined plane = 2 m
Explanation:
Given:
Mechanical advantage of the plane = 5 m
Inclined plane = 10 meters
Find:
Height of the inclined plane = ?
Computation:
⇒ Height of the inclined plane = Inclined plane / Mechanical advantage of the plane
⇒ Height of the inclined plane = 10 m / 5 m
⇒ Height of the inclined plane = 2 m
A dog owner wants to test how exercise affects how his dog sleeps. On day 1, he exercises his dog for 2 hours and then records the amount of sleep the dog experiences that evening. The next day he exercises the dog for 4 hours and records the amount of sleep experienced by the dog and finally he records the amount of sleep with 6 hours of exercise. He was careful to give his dog the same amount of food on the days he did the experiment.
Answer:
Independent Variable - Hours of Exercise
Dependent Variable - Hours of Sleep
Control - Food
Explanation:
In an experiment, there are two variables independent variable and dependent variable. The independent variable is defined as the variable that can be changed or manipulated while the dependent variable is defined as the variable that is measured as an effect of the independent variable. Constant is a value in an experiment that does not change.
In the given example, hours of exercise is the independent variable because it is changing every day, and hours of sleep is the dependent variable because it is the measurable effect or outcome in which the dog owner is interested. Food is constant because the dog is getting the same amount of food on the days of the experiment.
Hence, the correct answer is "Independent Variable - Hours of Exercise
Dependent Variable - Hours of Sleep
Control - Food".
You just completed an observational experiment and discovered a mathematical relationship involving the magnetic interaction. Describe a second experiment you could do involving magnetism that would lead to discovering another mathematical relationship.
A second experiment involving magnetism that could lead to discovering another mathematical relationship is the investigation of the magnetic field strength as a function of distance from a magnet.
Set up a magnetic field strength measuring device, such as a magnetometer or a Hall probe.
Place a magnet at a fixed position.
Measure the magnetic field strength at different distances from the magnet, ranging from close to the magnet to increasing distances.
Record the magnetic field strength readings at each distance.
Once the data is collected, you can plot the magnetic field strength (B) as a function of the distance from the magnet (r). To establish a mathematical relationship, you can perform regression analysis or curve fitting on the data points to determine the best-fit equation or mathematical model that describes the relationship between magnetic field strength and distance. This may involve various mathematical functions, such as inverse square law, exponential decay, or other mathematical expressions.
By conducting the experiment and analyzing the data, you can determine the mathematical relationship between magnetic field strength and distance from a magnet. This relationship will provide insights into how the magnetic field strength changes with distance and can be used to predict or calculate the magnetic field strength at any given distance from the magnet. This discovery can have practical applications in various fields, such as engineering, physics, and magnetism-related technologies.
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shapley, in order to understand the shape of the milky way, traced out the distribution of . a. globular clusters b. neutrinos c. quasars d. black holes
shapley, in order to understand the shape of the milky way, traced out the distribution of . a. globular clusters.
The location of globular clusters
Our Milky Way galaxy has roughly 200 globular clusters, which are normally found in the outer regions (the halos) of galaxies. Because of their placement in the halos as well as the fact that they include many of the oldest known stars, globular clusters are of interest to astronomers.
What can we learn from globular clusters?Globular clusters are compact groups of former stars. They have a roughly spherical form and hundreds of thousands or even millions of stars. Astronomers can determine the location of the galaxy's centre or the age of the cosmos by studying them.
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Acceleration is a change in what quantity Over time?A- speed B- distance C- force D- displacement
To find
Acceleration is a change in what quantity Over time?
Explanation
Acceleration is defined as the change in velocity with respect to time interval.
Conclusion
The required quantity is
A. speed