10-e=e-10
show you work.

The greatest possible number of intersection points for four circles of different sizes is 12.

The greatest possible number of intersection points of four circles of different sizes can be calculated by considering the maximum number of intersection points each pair of circles can have and then summing them up.

When two circles intersect, they can have a maximum of two intersection points. So, if we have four circles, we can find the maximum number of intersection points by considering each pair of circles separately.

For the first circle, it can intersect with the other three circles at most two times each, giving us a total of 2 * 3 = 6 intersection points.

For the second circle, it can intersect with the remaining two circles at most two times each, giving us a total of 2 * 2 = 4 intersection points.

The third circle can intersect with the last remaining circle at most two times, giving us a total of 2 * 1 = 2 intersection points.

Finally, the fourth circle doesn't have any other circle left to intersect with, so it doesn't contribute any additional intersection points.

Now, we can sum up the intersection points from each pair of circles: 6 + 4 + 2 + 0 = 12.

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The term that refers to the fact that the distance between two or more points is equal is "equidistant".

In geometry, the concept of equidistance is important when dealing with circles, which are sets of points that are equidistant from a single point called the center. This property is what allows circles to be defined in terms of their radius, which is the distance between the center and any point on the circle.

Equidistance is also important in other areas of mathematics and science. For example, in physics, equidistant points can be used to define a plane or surface that is perpendicular to a given line or axis. This is useful in many applications, such as designing electronic circuit boards or constructing buildings.

The concept of equidistance is not limited to mathematics and science, however. It can also be applied in everyday life. For instance, if you are planning a road trip and want to visit several destinations that are equidistant from your starting point, you can use this information to help plan your route and estimate your travel time.

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The probability that an arriving student will find at least one other student waiting in line is approximately 0.167.

To solve this problem, we'll use the M/M/1 queueing model with Poisson arrivals and exponential service times. Let's calculate the required values: (a) Percentage of time Judy is idle: The utilization of the system (ρ) is the ratio of the average service time to the average interarrival time. In this case, the average service time is 10 minutes, and the average interarrival time is 12 minutes. Utilization (ρ) = Average service time / Average interarrival time = 10 / 12 = 5/6 ≈ 0.8333

The percentage of time Judy is idle is given by (1 - ρ) multiplied by 100: Idle percentage = (1 - 0.8333) * 100 ≈ 16.67%. Therefore, Judy is idle approximately 16.67% of the time. (b) Average waiting time for a student:

The average waiting time in a queue (Wq) can be calculated using Little's Law: Wq = Lq / λ, where Lq is the average number of customers in the queue and λ is the arrival rate. In this case, λ (arrival rate) = 1 customer per 12 minutes, and Lq can be calculated using the queuing formula: Lq = ρ^2 / (1 - ρ). Plugging in the values: Lq = (5/6)^2 / (1 - 5/6) = 25/6 ≈ 4.17 customers Wq = Lq / λ = 4.17 / (1/12) = 50 minutes. Therefore, on average, a student spends approximately 50 minutes waiting in line.

(c) Average length of the line: The average number of customers in the system (L) can be calculated using Little's Law: L = λ * W, where W is the average time a customer spends in the system. In this case, λ (arrival rate) = 1 customer per 12 minutes, and W can be calculated as W = Wq + 1/μ, where μ is the service rate (1/10 customers per minute). Plugging in the values: W = 50 + 1/ (1/10) = 50 + 10 = 60 minutes. L = λ * W = (1/12) * 60 = 5 customers. Therefore, on average, the line consists of approximately 5 customers.

(d) Probability of finding at least one student waiting in line: The probability that an arriving student finds at least one other student waiting in line is equal to the probability that the system is not empty. The probability that the system is not empty (P0) can be calculated using the formula: P0 = 1 - ρ, where ρ is the utilization. Plugging in the values:

P0 = 1 - 0.8333 ≈ 0.1667. Therefore, the probability that an arriving student will find at least one other student waiting in line is approximately 0.167.

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stimulates controlled lowering of the foot during 1st ankle rocker bottom sole The controlled lowering of the foot during the first ankle rocker is facilitated by the activation of the tibialis anterior muscle.

This muscle is located in the anterior compartment of the leg and is responsible for dorsiflexion of the ankle joint, which means it lifts the foot upwards towards the shin. However, during the first ankle rocker, the tibialis anterior is activated eccentrically, which means it contracts while lengthening, to control the lowering of the foot towards the ground. This eccentric contraction of the tibialis anterior slows down the rate of plantarflexion and helps to maintain a smooth and controlled descent of the foot, allowing for a controlled heel strike and efficient transfer of weight to the forefoot.

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Full Question

stimulates controlled lowering of the foot during 1st ankle rocker______

Answer:

4,20,C

Step-by-step explanation:

1/7 of 28 is 4

5/7 of 28 is 20

and if you multiply 4 times 5 you get 20

hope this helped

Step-by-step explanation:

tan 51= jl/jm = jl/14

jl = 17.28

cos 72=kl/jl

kl = 5.33

We need to find the inverse of the function gof (x). First we need to find the composite function gof (x) which is given by:

\(g(f(x)) = g(3x - 6)\)

= \((1/3)(3x - 6) + 1\)

= x - 1 + 1

= x

Thus,

gof (x) = x.

Now we need to find the inverse of the function gof (x) to obtain

\((gof)^-1 (x).\)

We have gof (x) = x

which implies\((gof)^-1 (x)\)

= gof (x)^-1

= x^-1

= 1/x,

x ≠ 0

Therefore,

\((gof)^-1 (x) = 1/x\)

which is option (3) (x+1) since 1/x can be written as 1/(x+1-1), where (x+1-1) is the denominator of 1/x.

Hence, the correct option is (3).

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To find (g(f))^-1 (x), substitute the expression for f(x) into g(x) and simplify. The composition of g(f) is x and its inverse is also x. Therefore, (g(f))^-1 (x) equals x.

To find (g(f))^-1 (x), we need to first find the composition of g(f) and then find its inverse. Start by substituting the expression for f(x) into g(x): g(f(x)) = g(3x-6) = \frac{1}{3}(3x-6) + 1 = x - 1 + 1 = x. So, g(f(x)) = x. Now, to find the inverse of g(f), we switch the x and y variables and solve for y: y = x. Therefore, (g(f))^-1 (x) = x.

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The negative square root of three is not included in the range since it correlates to negative radial distances.

The radial distance (r), which is always a non-negative value in polar coordinates, represents the distance from the origin to a point in the xy-plane.

The equation x2 + y2 = 3 denotes a circle with a radius of √3 and is centered at the origin. This equation can be expressed in polar coordinates as r2 = 3. It is impossible for r to be negative because it denotes the radial distance. Consequently, the range for r is 0 ≤ r ≤ √3.

Since it would correlate to negative radial distances, which are meaningless in the context of the issue and do not correspond to points inside the contained solid, the negative square root of three is excluded from the range.

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Answer:

15.7%

Step-by-step explanation:

You can't add points once you have posted the question. For those who are interested 50 points is more than enough.

Remark

There are two ways of calculating % error. Chemistry uses one way. Most others use the second method. I have used the second method.

Measurements

L = 10 in

w = 9 in

h = 4.5 in

Estimated result

350 cubic cm

Solution

Find the volume from the measurements of the Prism

V = L * w * h

V = 10 * 9 * 4.5

V = 405 in^3

Percent Error

% error = 100 * (Calculated Value - Estimated value)/(Estimated Value)

% error = 100 * (405 - 350)/350

% error = 100 * ( 55) / 350

% error = 15.71      

% error = 15.7      (rounded)

Answer:

279.987

this is da answer

Step-by-step explanation:

There are 280.035 lbs in 127 kilograms. The answer is obtained by applying the unit conversion.

What is unit conversion?

A unit conversion is used to express the same property in a different unit of measurement. For instance, you could use minutes instead of hours to represent time or feet instead of miles to indicate distance. It commonly occurs when measurements are provided in one system of units, such as feet, but are required in a different system, such as chains.

Now,

we have been given 127 kilograms which are to be converted into pounds and to be represented in lbs.

We know that 1 kilogram = 2.205 lbs (approx)

Therefore,

⇒127 kilograms = 127 * 2.205

⇒127 kilograms = 280.035 lbs

Hence,

          There are 280.035 lbs in 127 kilograms.

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Answer:

x = 67

y = 23.5

Step-by-step explanation:

Sum of angles in a triangle is supplementary,

x + 90 + 23 = 180

x + 113 = 180

x = 180 - 113

x = 67

y = ?

180 - 67 / 2

= 133 / 2

= 66.5

y + 66.5 = 90

y = 90 - 66.5

y = 23.5

Answer:

1/8

Step-by-step explanation:

m=male

7m=female

m/7m+m = m/8m

=1/8

Answer:

22

Step-by-step explanation:

f(x) = 2x² + 4                         f(3)

f(3) = 2(3)² + 4

f(3) = 2(9) + 4

f(3) = 18 + 4

f(3) = 22

36 different sandwiches

can be made.

To calculate the number of different sandwiches that can be made using 1 type of bread, 1 type of meat, and 1 type of cheese, we need to multiply the number of options for each ingredient together.

In this case, there are 3 options for bread, 4 for deli meat, and 3 for cheese. To find the total number of different sandwiches, we multiply these numbers:

3 (options for bread) x 4 (options for meat) x 3 (options for cheese) = 36

Therefore,

36 different sandwiches can be made

using 1 type of bread, 1 type of meat, and 1 type of cheese.

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Step-by-step explanation:

False.

intersects the y-axis => x=0

tan (0+ π/6) = tan π/6 = 0.58

instead of 1.73

The equation of the tangent line represents a straight line that passes through the point of tangency and has a slope of -16.

The slope of the tangent line to the graph of the function y = x^4 - 10x^2 + 9 at x = 1 can be found by taking the derivative of the function and evaluating it at x = 1. The equation of the tangent line can then be determined using the point-slope form.

Taking the derivative of the function y = x^4 - 10x^2 + 9 with respect to x, we get:

dy/dx = 4x^3 - 20x

To find the slope of the tangent line at x = 1, we substitute x = 1 into the derivative:

dy/dx (at x = 1) = 4(1)^3 - 20(1) = 4 - 20 = -16

Therefore, the slope of the tangent line is -16.

To find the equation of the tangent line, we use the point-slope form: y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.

Given that the point of tangency is (1, y(1)), we substitute x1 = 1 and y1 = y(1) into the equation:

y - y(1) = -16(x - 1)

Expanding the equation and simplifying, we have:

y - y(1) = -16x + 16

Rearranging the equation, we obtain the equation of the tangent line:

y = -16x + (y(1) + 16)

To find the slope of the tangent line, we first need to find the derivative of the given function. The derivative represents the rate of change of the function at any point on its graph. By evaluating the derivative at the specific value of x, we can determine the slope of the tangent line at that point.

In this case, the given function is y = x^4 - 10x^2 + 9. Taking its derivative with respect to x gives us dy/dx = 4x^3 - 20x. To find the slope of the tangent line at x = 1, we substitute x = 1 into the derivative equation, resulting in dy/dx = -16.

The slope of the tangent line is -16. This indicates that for every unit increase in x, the corresponding y-value decreases by 16 units.

To determine the equation of the tangent line, we use the point-slope form of a linear equation, which is y - y1 = m(x - x1). We know the point of tangency is (1, y(1)), where x1 = 1 and y(1) is the value of the function at x = 1.

Substituting these values into the point-slope form, we get y - y(1) = -16(x - 1). Expanding the equation and rearranging it yields the equation of the tangent line, y = -16x + (y(1) + 16).

The equation of the tangent line represents a straight line that passes through the point of tangency and has a slope of -16.

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Class limits indicate the largest and smallest data values that can be included in the class. Class limits are referred to actual data values. On the other hand, class boundaries give values that remove gaps between the classes in the frequency distribution. Class boundaries are considered to be one decimal place more accurate in comparison to the data. Options A, B, D, and F correctly describe differences between a class boundary and a class limit.

Following are the potential differences between a class boundary and a class limit.

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Divide the total cost by 4:

272 / 4 = 68

It cost $68 for 1 tire

Answer:

68

Step-by-step explanation:

272/4=68

Answer:

2240 hope that this helps!!!!!!

Shape R and Shape S were put in the same group because they are the shapes with perpendicular line segments. Therefore the correct option is option D.

Shape S, a trapezium with one vertical side, and Shape R, a square, both have perpendicular line segments. All of the sides of a square are perpendicular, while one of the non-parallel sides of a trapezium with a vertical side is perpendicular to the base.

Reasons for ruling out other options

Option A, "Shapes without any right angles," is incorrect because Shape R (a square) has four right angles.

Option B, "Shapes with exactly one pair of parallel sides," is incorrect because Shape S (a trapezoid with one vertical side) has only one pair of parallel sides, while Shape R(a square) has two pairs of parallel sides.

Option C, "Shapes without parallel line segments," is also incorrect because all the other shapes P, Q, and T have parallel line segments.

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Critical values of the function f(θ) = 2cos(θ) +(sin(θ))² on the interval 0≤ θ < 2π is 0 and π.

Therefore, the answer is 0 and π.

f(θ) = 2cos(θ) +(sin(θ))²

f'(θ) = -2sin(θ) +2sin(θ)cos(θ)

Critical values of f are points at which f' is zero or not defined.

For all values of θ, we can find that f'(θ) is defined.

f'(θ) = 0

-2sin(θ) +2sin(θ)cos(θ) = 0

cos(θ) - 1 = 0 or sin(θ) = 0

cos(θ) = 1

θ = nπ, n = 0, 1, 2, ...

sin(θ) = 0

θ = nπ, n = 0, 1, 2, ...

Therefore in the interval 0 ≤ θ < 2π, critical values are 0 and π.

2π is not there as it is not included in the interval.

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Answer:

onkine survey tool i think

Answer:

cookies

Step-by-step explanation:

Answer: 6

Step-by-step explanation:

The factors of 42 are: 1, 2, 3, 6, 7, 14, 21, 42

The factors of 78 are: 1, 2, 3, 6, 13, 26, 39, 78

Then the greatest common factor is 6.

Heres something you need to learn about the greatest common factor (gcf)

What is the Greatest Common Factor?

The largest number, which is the factor of two or more numbers is called the Greatest Common Factor (GCF). It is the largest number (factor) that divide them resulting in a Natural number. Once all the factors of the number are found, there are few factors that are common in both. The largest number that is found in the common factors is called the greatest common factor. The GCF is also known as the Highest Common Factor (HCF)

Let us consider the example given below:

Greatest Common Factor (GCF)

For example – The GCF of 18, 21 is 3. Because the factors of the number 18 and 21 are:

Factors of 18 = 2×9 =2×3×3

Factors of 21 = 3×7

Here, the number 3 is common in both the factors of numbers. Hence, the greatest common factor of 18 and 21 is 3.

Similarly, the GCF of 10, 15 and 25 is 5.

How to Find the Greatest Common Factor?

If we have to find out the GCF of two numbers, we will first list the prime factors of each number. The multiple of common factors of both the numbers results in GCF. If there are no common prime factors, the greatest common factor is 1.

Finding the GCF of a given number set can be easy. However, there are several steps need to be followed to get the correct GCF. In order to find the greatest common factor of two given numbers, you need to find all the factors of both the numbers and then identify the common factors.

Find out the GCF of 18 and 24

Prime factors of 18 – 2×3×3

Prime factors of 24 –2×2×2×3

They have factors 2 and 3 in common so, thus G.C.F of 18 and 24 is 2×3 = 6

Also, try: GCF calculator

GCF and LCM

Greatest Common Factor of two or more numbers is defined as the largest number that is a factor of all the numbers.

Least Common Multiple of two or more numbers is the smallest number (non-zero) that is a multiple of all the numbers.

Factoring Greatest Common Factor

Factor method is used to list out all the prime factors, and you can easily find out the LCM and GCF. Factors are usually the numbers that we multiply together to get another number.

Example- Factors of 12 are 1,2,3,4,6 and 12 because 2×6 =12, 4×3 = 12 or 1×12 = 12. After finding out the factors of two numbers, we need to circle all the numbers that appear in both the list.

Greatest Common Factor Examples

Example 1:

Find the greatest common factor of 18 and 24.

Solution:

First list all the factors of the given numbers.

Factors of 18 = 1, 2, 3, 6, 9 and 18

Factors of 24 = 1, 2, 3, 4, 6, 8, 12 and 24

The largest common factor of 18 and 24 is 6.

Thus G.C.F. is 6.

Example 2:

Find the GCF of 8, 18, 28 and 48.

Solution:

Factors are as follows-

Factors of 8 = 1, 2, 4, 8

Factors of 18 = 1, 2, 3, 6, 9, 18

Factors of 28 = 1, 2, 4, 7, 14, 28

Factors of 48 = 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

The largest common factor of 8, 18, 28, 48 is 2. Because the factors 1 and 2 are found all the factors of numbers. Among these two numbers, the number 2 is the largest numbers. Hence, the GCF of these numbers is 2.

If you know it, dont read it

Answer:

(1, 4)

Step-by-step explanation:

im assuming that the point is h(1) = 4

this point is basically just h(x) = y

1 is your x

4 is your y

you plot it at the point (1, 4)

The surface area of the similar model is 0.04 ft^2. Rounded to the nearest tenth, this is 0.0 ft^2.

Since the scale factor is 1/300, the dimensions of the similar model will be 1/300 of the original dimensions.

Let's denote the length, width, and height of the original skyscraper as L, W, and H, respectively. Then, the surface area of the original skyscraper is given by:

SA = 2LW + 2LH + 2WH

We can use the scale factor to find the dimensions of the similar model:

L' = L/300

W' = W/300

H' = H/300

The surface area of the similar model is given by:

SA' = 2L'W' + 2L'H' + 2W'H'

Substituting the expressions for L', W', and H', we get:

SA' = 2(L/300)(W/300) + 2(L/300)(H/300) + 2(W/300)(H/300)

Simplifying this expression, we get:

SA' = (2/90000)(LW + LH + WH)

Now, we know that the surface area of the original skyscraper is 1,298,000 ft^2. Substituting this into the equation above, we get:

1,298,000 = (2/90000)(LW + LH + WH)

Solving for LW + LH + WH, we get:

LW + LH + WH = 1,798.5

Now, we can substitute this expression into the equation for SA':

SA' = (2/90000)(1,798.5)

Simplifying, we get:

SA' = 0.04 ft^2

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Answer:

y=-2/3

x=-20/3

a) Yes, It does. The scatterplot support the newspaper report about number of semesters and starting salary.

b) The value is relatively low, indicating that there are other factors that also contribute to starting salary.

c) The correlation coefficient is a value between -1 and 1 that measures the strength and direction of the linear association between two variables.

a) The scatterplot appears to show a positive association between the number of semesters needed to complete an academic program and the starting salary in the first year of a job. As the number of semesters increases, the starting salary generally increases as well. Therefore, the scatterplot supports the newspaper report.

b) The coefficient of determination, or R-squared value, represents the proportion of the variation in the dependent variable (starting salary) that is explained by the independent variable (number of semesters). A value of 0.335 means that 33.5% of the variation in starting salary is explained by the number of semesters. This value is relatively low, indicating that there are other factors that also contribute to starting salary.

c) The correlation coefficient is a value between -1 and 1 that measures the strength and direction of the linear association between two variables. A value of 1 indicates a perfect positive correlation, a value of -1 indicates a perfect negative correlation, and a value of 0 indicates no correlation. The correlation coefficient for this data is not provided in the problem, so it is not possible to determine it. Without the correlation coefficient, it is not possible to interpret the strength and direction of the association between number of semesters and starting salary.

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Answer:

760

Step-by-step explanation:

Answer:

760 of course

Step-by-step explanation:

3 is below 5 so its 760

If the last digit was a 5 or higher,it'll be 770

The area of the drafting section on the screen after Jenny left a right margin for editing marks is 1,077,120 pixels.

The first step is to determine the dimensions of the drafting section:

Length = 11 inches

Width = (1 - 1/5) x 8.5 = 6.8 inches

The second step is to convert the dimensions to pixels:

Length = 11 inches x 120 = 1320

Width = 6,8 inches x 120 = 816

Area = 1320 x 816 = 1,077,120 pixels

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Answer:

1,077,120 pixels

Step-by-step explanation:

I got a 100% on the test

The magnitude of the force per unit length that each wire exerts on the other wire is 3 × 10⁻⁷ N/m.

Using Ampere's law, the force per unit length (F/L) between two parallel wires carrying currents I1 and I2 and separated by a distance d can be calculated as:

F/L = (μ0 ⨯ I1 ⨯ I2) / (2 ⨯ π ⨯ d)

Where μ0 is the permeability of free space (4π × 10⁻⁷ T⋅m/A),

I1 is the current in the first wire (4.00 A),

I2 is the current in the second wire (6.00 A), and d is the distance between the wires (0.400 m).

F/L = (4π × 10⁻⁷ T⋅m/A ⨯ 4.00 A ⨯ 6.00 A) / (2 ⨯ π ⨯ 0.400 m)

F/L = (24π × 10⁻⁷ T⋅m/A) / (0.800 m)

F/L = 3 × 10⁻⁷ ) T⋅m/A

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