Answer: D
Explanation: because
A 35.30-kg box is attached to a light string that is wrapped around a cylindrical frictionless spool of radius 10.0 cm and moment of inertia 4.00 kg * m^2. The spool is suspended from the ceiling, and the box is then released from rest a distance from rest a distance 3.50 m above the floor. How long does it take for the box to reach the floor?
Answer:
The velocity of the box is related to the angular velocity of the spool, which is given by the equation:
v = r * ω
where r is the radius of the spool and ω is the angular velocity of the spool. The angular velocity of the spool, in turn, is related to the torque applied to the spool by the tension in the string, which is given by the equation:
τ = I * α
where τ is the torque, I is the moment of inertia of the spool, and α is the angular acceleration of the spool.
The tension in the string is equal to the weight of the box, which is given by:
T = m * g
Putting all of these equations together, we can solve for the time it takes for the box to reach the floor. Here's how:
First, we can find the angular acceleration of the spool using the torque equation:
τ = I * α
T = m * g = τ
m * g = I * α
α = (m * g) / I
α = (35.30 kg * 9.81 m/s^2) / 4.00 kg*m^2
α = 86.53 rad/s^2
Next, we can find the angular velocity of the spool using the kinematic equation:
ω^2 = ω_0^2 + 2 * α * θ
where ω_0 is the initial angular velocity (which is zero), θ is the angle through which the spool has turned (which is equal to the distance the box has fallen divided by the radius of the spool), and ω is the final angular velocity (which is what we want to find). Solving for ω, we get:
ω^2 = 2 * α * θ
ω = sqrt(2 * α * θ)
ω = sqrt(2 * 86.53 rad/s^2 * (3.50 m / 0.10 m))
ω = 166.6 rad/s
Finally, we can find the time it takes for the box to reach the floor using the equation:
v = r * ω
v = 0.10 m * 166.6 rad/s
v = 16.66 m/s
t = d / v
t = 3.50 m / 16.66 m/s
t = 0.21 s
You are riding your bike at 5 mis. In order to avoid hitting a child that has
run into the street, you slam on your brakes and slow to a stop. It takes you
1.5 seconds to fully stop. What was your acceleration?
You are riding your bike at 5 m/s. In order to avoid hitting a child that has run into the street, you slam on your brakes and slow to a stop. It takes you 1.5 seconds to fully stop. Acceleration will be 3.33 \(m/s^{2}\)
The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.
given
speed = 5 m/s
time = 1.5 seconds
using
v = u + at
0 = 5 + a ( 1.5 )
a = -5 / 1.5
= 3.33 \(m/s^{2}\)
Acceleration will be 3.33 \(m/s^{2}\)
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A flat sheet of paper of area 0.450 m2 is oriented so that the normal to the sheet is at an angle of 600 to a uniform electric field of magnitude 18 N C-1. What is the magnitude of the electric flux through the sheet? A. 3.22 N m2 C-1 B. 21.42 N m2 C-1 C. 5.04 N m2 C-1 D. 11.72 N m2 C-1 E. 4.05 N m2 C
The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).
The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.
In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²
(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:
Electric flux = Electric field strength × Area
Electric flux = 18 N C⁻¹ × 0.450 m²
Electric flux = 8.1 N m² C⁻¹
In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.
The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).
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Bonito has potential energy while he is in the starting blocks, getting ready to run his 5-kilometer race. Which of the following statements are true about his potential energy? Choose the three statements that apply.
It is energy that has been stored.
It could be employed later.
It is capable of becoming kinetic energy.
What is the most accurate way to define potential energy?Potential energy is essentially stored energy that can be put to use as a result of the object's location or state. Potential energy is defined as the energy held within a system of physically interfering entities in more physics-focused terms.
Describe kinetic energy.Kinetic energy is the energy that an object has as a result of motion. To accelerate an object, a force must be supplied to it. To apply a force, we must exert effort. When work is finished, energy is transferred to the object, and the item now has a new motion.
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A lowest A on a piano has a frequency of 27.5 HZ if the tension in the 2.00m string is 308N and one half wavelength occupies the spring what is the mass of the wire
The mass of the wire of lowest A on a piano is 0.00165 kg.
The frequency of a vibrating string is given by the equation:
f = (1/2L) * sqrt(T/μ)
where f is the frequency of the string, L is the length of the string, T is the tension in the string, and μ is the linear mass density of the string (mass per unit length).
We know the frequency of the lowest A on a piano is 27.5 Hz. We also know that one half wavelength occupies the string, so the length of the string is half the wavelength:
L = (1/2) * λ
The wavelength of a sound wave is given by:
λ = 2L/n
where n is the number of nodes (points of zero displacement) in the wave. For the lowest A on a piano, n = 1, so we can write:
λ = 2L
Substituting this into the equation above for L, we obtain:
L = λ/2
Now we can substitute these values into the first equation:
27.5 = (1/2)(λ/2) * sqrt(308/μ)
Simplifying, we get:
λ = 4L
308/μ = 4(27.5)^2 (1/4)
μ = 0.000824 kg/m.
Since μ = m/L, where m is the mass of the wire and L is its length, we can find the mass of the wire by multiplying the linear mass density by the length of the string:
m = μL
The length of the string is given as 2.00 m, so we can write:
m = 0.000824 kg/m * 2.00 m = 0.00165 kg
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find the speed of the object in graph 1
The speed of the object for 1 second is 3 m/s.
The speed of the object for 2 seconds is 1.5 m/s.
The speed of the object for 3 seconds is 1.0 m/s.
The speed of the object for 4 seconds is 0.75 m/s.
The speed of the object for 5 seconds is 0.6 m/s.
What is the speed of an object?
The speed of an object is the distance travelled by the object divided by the total time taken for the motion.
The speed of the object for each of the time of motion and total distance traveled is calculated as follows;
v (1 ) = ( 3 m ) / ( 1 s ) = 3 m/s
v ( 2 ) = ( 3 m ) / ( 2 s ) = 1.5 m/s
v ( 3 ) = ( 3 m ) / ( 3 s ) = 1 m/s
v ( 4 ) = ( 3 m ) / ( 4 s ) = 0.75 m/s
v ( 5 ) = ( 3 m ) / ( 5 s ) = 0.6 m/s
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Drag the tiles to the correct boxes. Not all tiles will be used.
Match the molecular shapes to the correct Lewis structures.
trigonal pyramidal
trigonal planar
bent
tetrahedral
linear
Answer
1) AlH3= trigonal planar
2) CH2F2= tetrahedral
3) PH3= trigonal pyramidal
4) O3= bent
Explanation:
I took the test
A ball hangs on a string. The force of tension (Ft) in the string is 15n. The force due to gravity (Fg) pulls the ball down with a force of 15 N. Show your work.
Answer: 0N
Explanation: 15N-15N =0N
they are a balanced force,meaning they canceled each other out.
Calculate the force of your body on the ground. (Use your weight in pounds x 4.45 because 2.2lbs=kg)
Answer:
2.8ibs=kg check with someone else im not for sure.
Explanation:
if you divide 10 divided by 2 it gives you 5 and then subtract it by 2.2 = 2.8
there goes your answer.
help pls
I just need an explanation to why it’s that answer
Answer:
The area under the speed - time graph denotes the distance travelled by the object
In the given graph, we just have to think about the first 4 seconds, we also notice that the velocity at 4 seconds is 20 m/s
The distance travelled by the object in 4 seconds is the area of the triangle in the graph with a base of 4 units and height of 20 units (image included)
Distance Travelled = Area of triangle = 1/2 * base * height
Distance Travelled = 1/2 * 4 * 20
Distance travelled = 4 * 10
Distance travelled = 40 m
PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons
The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)
Why the electron number cannot be used instead?The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.
This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.
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A future space vehicle massing 250,00 kilograms lifts off vertically from the lunar surface at a net acceleration of 3.27 m/s^2. What is the net force that the Moon exerts on the space vehicle, in Newtons?
The net force acting on the future space vehicle be 81750 Newton.
What is force?The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.
An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
Given parameters:
Mass of the future space vehicle: m = 250,00 kilograms.
Net acceleration of the future space vehicle: a = 3.27 m/s^2.
Hence, according to Newton's 2nd law of motion:
Net force acting on the future space vehicle: F = mass × acceleration
= 25000 × 3.27 Newton
= 81750 Newton.
Hence, net force acting on the future space vehicle be 81750 Newton.
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A Spherical cloud of charge or radius R contains a total charge +Q with a nonuniform charge density that varies according to:
p(r)=p0Image for A Spherical cloud of charge or radius R contains a total charge +Q with a nonuniform charge density that variefor r<_ R
and p=0 for r>R1-r/R
Where r is the distance from the center of the cloud
Express all algebraic answers in terms of Q,R,r and fundamental constants,
(C) Derive an expression for p0
The expression for the charge density of a spherical cloud of charge of radius R and total charge +Q is given by:
p(r) = p0 for 0 ≤ r ≤ R
p(r) = 0 for r > R
Where p0 is the charge density at the center of the cloud, r is the distance from the center of the cloud, and C is a fundamental constant.
To derive an expression for p0, we can use Gauss' law to calculate the total charge within a sphere of radius r. Since the charge distribution is spherically symmetric, the electric field at any point outside the sphere is zero. Thus,
∫E·dA = Q/ε0
Where the integral is taken over a sphere of radius r, and ε0 is the permittivity of free space.
Using the divergence theorem, we can equate this to an integral of the charge density over the same sphere:
∫E·dA = ∫∇·p dV
Substituting in the expression for the charge density, we get:
Q/ε0 = ∫p0 (4πr2) dr
Integrating both sides and solving for p0, we get:
p0 = Q/(4πε0R3)
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in each of the images, two blocks are attached to a balance. Use the position and size of the blocks to determine which block is more dense in each image.
A scale weighs two boxes. The green box on the left has a large volume and pulls lower on the scale. The blue box on the right has a smaller volume and is higher on the scale.
Which block is more dense in the first image?
Which block is more dense in the second image?
Which block is more dense in the third image?
First image: Green block is larger and heavier than the blue block.
Second image: Blue and green block are the same size, but blue is heavier
Third image: Green block is smaller and heavier than the blue block
It is impossible to estimate the relative density of the blocks. The rightmost blue chunk is denser. The chunk of green on the left is denser. The mass of a material per unit volume is the definition of density.
Describe density with an example:Its density refers to how much material can fit into a specific quantity of space. For instance, a block of lead (Pb), which is heavier and less durable, will have a lower density than a block of gold (Au), which is stronger and lighter (Au).
Mass and density: what are they?The term "mass" refers to a thing's total amount of matter. The term "density" describes how tightly atoms are packed or how close together they are in a material. To calculate inertia, utilize the idea of mass.
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On a frictionless horizontal air table, puck A (with mass 0.251 kg ) is moving toward puck B (with mass 0.371 kg ), which is initially at rest. After the collision, puck A has velocity 0.120 m/s to the left, and puck B has velocity 0.654 m/s to the right.
What was the speed vAi of puck A before the collision?
Calculate ΔK , the change in the total kinetic energy of the system that occurs during the collision.
(a) The speed of puck A before the collision is determined as 0.847 m/s.
(b) The change in the total kinetic energy of the system that occurs during the collision is 0.009 J.
Speed of puck A before the collisionThe speed of puck A before the collision is calculated from the principle of conservation of linear momentum as follows;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0.251u₁ + 0.371(0) = 0.251( -0.12) + 0.371(0.654)
0.251u₁ = 0.2125
u₁ = 0.2125/0.251
u₁ = 0.847 m/s to the right
Change in the total kinetic energy of the systemInitial kinetic energy = ¹/₂ x 0.251 x (0.847)² + ¹/₂ x 0.371 x (0) = 0.09 J
Final kinetic energy = ¹/₂ x 0.251 x (-0.12)² + ¹/₂ x 0.371 x (0.654)² = 0.081 J
ΔK.E = 0.081 - 0.09 = 0.009 J ≈ 0 J
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I need help plz help me out 10 points!!!!!!!
Answer:
The answer is diffraction
Explanation:
Answer:
The answer is diffraction
Explanation:
I did the test! HOPE THIS HELPS!
For the cellar of a new house, a hole is dug in the ground, with vertical sides going down 2.10 m. A concrete foundation wall is built all the way across the 8.90 m width of the excavation. This foundation wall is 0.189 m away from the front of the cellar hole. During a rainstorm, drainage from the street fills up the space in front of the concrete wall, but not the cellar behind the wall. The water does not soak into the clay soil. Find the force that the water causes on the foundation wall. For comparison, the weight of the water is given by 2.10 m ✕ 8.90 m ✕ 0.189 m ✕ 1000 kg/m3 ✕ 9.80 m/s2 = 34.6 kN.
Answer:
The force on the foundation wall is \(F_f = 191394 \ N\)
Explanation:
From the question we are told that
The depth of the hole's vertical side is \(d = 2.10 \ m\)
The width of the hole is \(b = 8.90 \ m\)
The distance of the concrete wall from the front of the cellar is \(c = 0.189 \ m\)
Generally the area which the water from the drainage covers is mathematically represented as
\(A = d * b\)
substituting values
\(A = 2.10 * 8.90\)
\(A = 18.69 \ m^2\)
Now the gauge pressure exerted on the foundation wall is mathematically evaluated as
\(P_g = \rho * d_{avg} * g\)
Here is the average height foundation wall where the pressure of the water is felt and it is evaluated as
\(d_{avg} = \frac{h_1 + h_2 }{2}\)
where \(h_1\) at the height at bottom of the hole which is equal to \(h_1 = 0\)
and \(h_2\) is the height at the top of the hole \(h_2 = d = 2.10\)
\(d_{avg} = \frac{0 + 2.10 }{2}\)
\(d_{avg} = 1.05\)
Where \(\rho\) is the density of water with constant value \(\rho = 1000 \ kg/m^3\)
substituting values
\(P_g = 1000 * 1.05 * 9.8\)
\(P_g = 10290 \ Pa\)
Then the force exerted by the water on the foundation wall mathematically represented as
\(F_f = P_g * A\)
substituting values
\(F_f = 10290 * 18.69\)
\(F_f = 191394 \ N\)
Two stars M1 and M2 of equal mass make up a binary star system. They move in a circular orbit that has its center at the midpoint of the line that separates them. If M1 = M2 = 5.45 sm (solar mass), and the orbital period of each star is 3.20 days, find their orbital speed. (The mass of the sun is 1.99E30 kg.)
Since Two stars M1 and M2 of equal mass make up a binary star system. their orbital speed is 2.69E4 m/s.
What is the orbital speed about?The orbital period of a binary star system is given by the equation:
T = 2 * pi * sqrt(a³ / (G * (M1 + M2)))
where T is the orbital period, a is the semi-major axis of the orbit (half of the distance between the two stars at their closest approach), G is the gravitational constant, and M1 and M2 are the masses of the two stars.
Substituting the given values into this equation, we get:
3.20 days = 2 * pi * sqrt(a³ / (6.67E-11 m³ kg^⁻¹ s^⁻² * (5.45 sm * 1.99E30 kg/sm + 5.45 sm * 1.99E30 kg/sm)))
Solving for the semi-major axis, we find that a = 2.11E11 m.
The speed of each star in the orbit can be found using the equation:
v = sqrt(G * (M1 + M2) / a)
Substituting the values we have calculated, we find that v = 2.69E4 m/s. This is the speed of each star in the orbit.
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a stone of mass 100g is thrown vertically upwards with a force of 5N .what is its initial acceleration
Answer:
25 meter per second square
Answer:
\(F = ma = 0.1 \times a \\ a = \frac{5}{0.1} \\ a = 50 \: m. {s}^{ - 2} \)
Explain why a ship made of iron will float, but a small, solid chunk of iron will sink.
A ship made of iron will float, but a small, solid chunk of iron will sink, because of the buoyant force acting on the ship.
According to Archimedes' principle, the upward buoyant force that is applied to a body submerged in a fluid, whether wholly or partially, is equal to the weight of the fluid that the body displaces and that force acts in an upward direction towards the centre of mass of the displaced fluid.
Compared to the volume of the iron ship, a lot more water is expelled. As a result, the upthrust or the buoyant force exceeds the ship's weight in accordance with Archimedes' concept. As a result of this, the iron ship floats on the water.
But in the case of the solid iron chunk, the volume of the displaced water is higher than its volume, therefore, the solid iron chunk will sink.
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"You can't see the forest for the trees" might seem an appropriate analogy for astronomers attempting to determine the shape of the Milky Way galaxy when we are in fact located inside the galaxy. Discuss techniques used by astronomers to determine the type of galaxy in which we live, why it is so difficult to determine the shape of our galaxy, and where our Sun is located in our galaxy?
Some of the techniques used by astronomers to determine the type of galaxy in which we live are:
radio, optical, infraredx-ray astronomyWhat is Astronomy?This refers to the study of heavenly bodies and space and other things that space is made up of.
Hence, we can see that the reason why it is so difficult to determine the shape of our galaxy is that astronomers can only infer its presence from the motions of stars in the galaxy, and a precise shape is difficult to be determined.
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a force of magnitude 30 n stretches a spring 0.83 m from equilibrium. what is the value of the spring constant?
Answer:
36 N/m
Explanation: I got the answer right on the test ight noo cap
Is Saturn less dense than water which has a
density of 997 kg/m³? Find out by calculating the density of Saturn in kg/m³. The mass of Saturn is 5.68 x 1026 kg, and its radius is 5.6 x 107 m.
Density of Saturn:
The density of water at STP, which is \(997 kg/m^3\), we can see that Saturn is less dense than water.
To determine whether Saturn is less dense than water, we must compute its density and compare it to the density of water at standard temperature and pressure (STP), which is \(997 kg/m^3\).
Saturn's density can be computed using the following formula:
density equals mass divided by volume
Saturn's mass and volume may be computed given its mass and radius.
The volume of Saturn can be determined using the sphere volume formula:
volume =\((4/3) \pi (r^3)\)
where r is Saturn's radius.
Filling in the blanks:
volume = \((4/3) \pi (5.6 \times 107) m^3\)
8.27 x 1023 \(m^3\)volume
Saturn's mass is given as \(5.68 \times 10^{26} kg.\)
We can now compute Saturn's density:
density equals mass divided by volume
density= \((5.68 x 10^{26 }kg\)) /\((8.27 \times 10^{23 }\)m³) a density of\(687 kg/m^3\)
This is due to the fact that Saturn is mostly made up of hydrogen and helium, which are far less dense than water. In reality, Saturn is the least dense planet in the Solar System, and it would float in a large enough body of water.
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A helium-neon laser (λ = 633 nm) illuminates a single slit and is observed on a screen 1.50 m behind the slit. The distance between the first and second minima in the diffraction pattern is 3.75 mm .
Required:
What is the width (in mm) of the slit?
Answer:
d = 0.25 mm
Explanation:
The position that the Minimal fall in single silt diffraction pattern can be written as
y=λmD/d ..........eqn(1)
(y2 - y1 )= difference of y that exist between first and second minima
D= distance of slit from the screen=1.50m
d= width of the slit
λ= 633 nm = 633×10^-9m
y= position of pth minimal
eqn(1) can be written as
(y2 - y1)= λmD/d .........eqn(2)
If we substitute the given values we have
(y2 - y1 )= [ (2×633×10^-9 × 1.50) /d] -[ (1×633×10^-9 × 1.50) /d]
Simplyfying
(y2 - y1)=(9.495×10^-7)/d
But The distance between the first and second minima in the diffraction pattern = 3.75, which implies that (y2 - y1) = 3.75mm=
✓ we can substitute (y2 - y1)= 3.75mm=3.75 ×10^-3 into expression above
3.75 ×10^-3 =(9.495×10^-7)/d
The we can make "d" subject of the formula
d=(9.495×10^-7)/ (3.75 ×10^-3)
d=0.00025m
d=0.25×10^-3 m
d=0.25 mm
Hence, the width (in mm) of the slit is 0.25mm
X-Rays of wavelength 1.37nm incident on an atom cause photo emission of its electrons . If the emitted electrons have energy of 83 ev , what is the energy of the level from which the electrons were ejected?
a. 822 ev
b. -822 ev
C. 288 ev
d. -288 ev
The energy of the level from which the electrons were ejected is 822 eV.
option A.
What is the e energy of the level?The energy of the incident X-rays is given by the formula:
E = hc/λ
where;
h is Planck's constant, c is the speed of light, and λ is the wavelength of the X-rays.Substituting the given values, we get:
E = (6.626 × 10^-34 J s) × (3.00 × 10^8 m/s) / (1.37 × 10^-9 m)
= 1.45 × 10^-16 J
The energy of the emitted electrons is given as 83 eV. We can convert this to joules using the conversion factor:
1 eV = 1.602 × 10^-19 J
Therefore:
83 eV × (1.602 × 10^-19 J/eV) = 1.329 × 10^-17 J
The energy difference between the level from which the electron was ejected and the energy of the emitted electron can be calculated as:
ΔE = E - 1.329 × 10^-17 J
To determine the level energy, we need to know whether the electron was ejected from an energy level above or below the ionization level. Since the emitted electron has a positive energy, we know that it was ejected from an energy level above the ionization level.
Therefore, the energy level from which the electron was ejected is:
Elevel = -ΔE = - (E - 1.329 × 10^-17 J)
Substituting the values of E and ΔE, we get:
Elevel = - [1.45 × 10^-16 J - 1.329 × 10^-17 J]
= 1.3 × 10^-16 J
Converting this to electron volts, we get:
Elevel = (1.3× 10^-16 J) / (1.602 × 10^-19 J/eV)
= 822 eV
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Electromagnetic waves are commonly referred to as _________
O electricity
O magnetism
O light
If magma is defined as molten rock material,do you need to melt rocks to form magma?
Explanation: Magma is molten rock found below the earth's surface. ... On the other hand, if the rocks are under greater pressure, they will require higher temperatures to melt. Melting of rocks typically occurs in the lower lithosphere or upper asthenosphere. The earth gets hot pretty quickly as you dig down from the earth's surface.
Describe how J J Thompson discovered the electron and explain how this discovery led him to suggest a new model of the atom, known as Thompson’s plum-pudding model.
Answer:
Summary. J.J. Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons. Thomson proposed the plum pudding model of the atom, which had negatively-charged electrons embedded within a positively-charged "soup."
Explanation:
4. Interpret Data The graph below shows the
motion of an elevator. Explain its motion.
Answer:
Below
Explanation:
0-1 sec descends at constant rate from 10 to 6 m
1-2 sec stops at 6m
2-3 sec descends at constant rate to 2 m
3-4 sec stops at 2 m
4-5 sec descends at another constant rate to 0 m
A net force of 34N is applied to accelerate an object at a rate of 2.5m/s2. What is the mass of the object?
Answer: Mass= 13.6 kg
Explanation:
F = m * a
34 = m (2.5)
m = 34 / 2.5
m = 13.6 kg