11. Which type of cloud is shown in this image?

Answers

Answer 1

Cumulus, cirrus, and stratus clouds are the three types of clouds shown in this photograph.

How does a cloud behave in the sky?

The importance of clouds cannot be overstated. One of the causes is precipitation, such as rain or snow.

Clouds make the surface warmer at night by reflecting heat back to it. Clouds may shield us from the sun and make Earth cooler throughout the day.

The type of cloud is shown in this image is;

1.Cumulous

2.Cirrus

3.Stratus

1. Cumulous

The fluffy, white, cotton-top clouds known as cumulus have such a gentle appearance that you may imagine angels relaxing and going about their business on them.

2. Cirrus

High clouds in the cirrus genus are comprised of ice crystals. The characteristic appearance of cirrus clouds is fragile and wispy with white filaments.

3. Stratus

Contrary to convective or cumuliform clouds, which are produced by rising thermals, stratus clouds are low-level clouds with horizontal stratification and a homogenous base.

Hence, the type of clouds shown in this image is cumulus, cirrus, and stratus.

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11. Which Type Of Cloud Is Shown In This Image?
Answer 2

Answer: Cumulus

Explanation:the answer is Cumulus i just passes my test when i put this in so u try


Related Questions

What is the classification of the reaction shown in the equation below?
Fe + O2 → FeO2
A
decomposition
B
double replacement
C
single replacement
D
synthesis

Answers

Answer:

d

Explanation:

because is a reducing agent, O 2 is an oxidizing agent.

How would the potential energy of a magnet change if you removed it from a refrigerator door and put it on a table?

Answers

The potential energy of a magnet would increase if you removed it from a refrigerator door and put it on a table.

How would potential energy of magnet change if removed from refrigerator door and put it on table?

Potential energy of magnet would increase if you removed it from refrigerator door and put it on table.

This is because when the magnet is on refrigerator door, it is in a position where it is attracted to metal surface of the door, and this attraction creates  certain amount of potential energy. When the magnet is removed from door and placed on table, it is no longer in that attractive position, so potential energy that was associated with magnet's attraction to the door is no longer present. Instead, magnet now has gravitational potential energy, which depends on its height above the ground and acceleration due to gravity.

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How much can having a lighted candle increase the temperature inside the shelter?

Answers

a lighted candle produces heat however not as much heat as a heater or the sun would.

A lighted candle can increase the temperature inside a shelter by a few degrees Celsius.

A lighted candle produces heat by burning fuel. The heat from the candle is transferred to the air in the shelter by conduction, convection, and radiation. Conduction is the transfer of heat through direct contact. Convection is the transfer of heat through the movement of fluids. Radiation is the transfer of heat through electromagnetic waves.

The amount of heat that is transferred to the air in the shelter depends on the size of the candle, the number of candles, and the insulation of the shelter. The larger the candle, the more heat it will produce. The more candles, the more heat will be produced. The more insulation the shelter has, the less heat will be lost to the outside. In general, a lighted candle can increase the temperature inside a shelter by a few degrees Celsius.

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A sphere of radius =0.280 m and uniform charge density 151 nC/m^3 lies at the center of a spherical, conducting shell of inner and outer radii 3.50 and 4.00, respectively. If the conducting shell carries a total charge of =−11.9 nC, find the magnitude of the electric field at the given radial distances from the center of the charge distribution.

A sphere of radius =0.280 m and uniform charge density 151 nC/m^3 lies at the center of a spherical,
A sphere of radius =0.280 m and uniform charge density 151 nC/m^3 lies at the center of a spherical,

Answers

The magnitude of the electric field at the given radial distances from the center of the charge distribution is, For the first case electric field=E₁= 1211.37N/C, For the second case electric field =E₂=762.82 N/C, For the third case electric field= E₃= 3276.7 N/C, For the fourth case electric field=E₄=555.04N/C

What is electric field?

Electric field is defined in a way that a field is present in a frame. There is two electric source is present that associated with each other and make the field electrified and source of electric. It can be shown in electric per unit area.

How can I calculate the electric field?

The conducting shell carries a total charge of=Q=−11.9 nC=11.9*10⁻⁹C

A sphere of radius=R =0.280m

A uniform charge density of a sphere=ρ₁= 151 nC/m³= 151×10⁻⁹C/m³

A uniform charge density of a spheric shell,

ρ₂=Q/(4/3)π[(4.00R)³−(3.50R)³]

Or,ρ₂=3Q/4πR³[(4.00)³−(3.50)³]

Or,ρ₂=3*11.9*10⁻⁹/4π(0.280)³[(4.00)³−(3.50)³]

Or,ρ₂=6.15*10⁻⁹ C/m³

We know the law of electric field,

E=(1/4πϵ₀)*(q/r²)

(a) r₁=0.76R

The electric field, in this case, can be given as:

E₁=(1/4πϵ₀)*(q₁/r₁²)

Or, E₁=(1/4πϵ₀)*(ρ₁*{(4/3)πr₁³}/r₁²)

Or, E₁=(1/4πϵ₀)*(ρ₁*(4/3)πr₁)

Or, E₁=9*10⁹*( 151×10⁻⁹*(4/3)π*0.76*0.280)

Or, E₁= 1211.37N/C

According to the calculation, The electric field for this case is, E₁= 1211.37N/C

(b) r₂=3.65R

The electric field, in this case, can be given as:

E₂=(1/4πϵ₀)*(q₂/r₂²)

Here, q₂=Q+(4/3)π[(4.00)³−(3.50)³]

Or, q₂=11.9*10⁻⁹+(4/3)π[(4.00)³−(3.50)³]

Or, q₂=88.488*10⁻⁹C

Now, E₂=(1/4πϵ₀)*(q₂/r₂²)

Or, E₂=(1/4πϵ₀)*(88.488*10⁻⁹/(3.65*0.280)²)

Or, E₂=762.82 N/C

According to the calculation, The electric field for this case is, E₂=762.82 N/C

(c) r₃=2.30R

The electric field, in this case, can be given as:

E₃=(1/4πϵ₀)*(q₃/r₃²)

In this case, electric charge enclosed by the Gaussian surface is given by: q₃=151×10⁻⁹C/m³

Now, E₃=(1/4πϵ₀)*(q₃/r₃²)

Or, E₃=(1/4πϵ₀)*(151×10⁻⁹/(2.30*0.280)²)

Or, E₃= 3276.7 N/C

According to the calculation, The electric field for this case is,  E₃= 3276.7 N/C

(d) r₄=4.50R

Here, q₄=Q+(4/3)π[(4.00)³−(3.50)³]

Or, q₄=11.9*10⁻⁹+(4/3)π[(4.00)³−(3.50)³]

Or, q₄=88.488*10⁻⁹C

Now, E₄=(1/4πϵ₀)*(q₄/r₄²)

Or, E₄=(1/4πϵ₀)*(88.488*10⁻⁹/(4.50*0.280)²)

Or, E₄=555.04N/C

According to the calculation, The electric field for this case is, E₄=555.04N/C

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What is the gravitational force related to the distance between two objects?

Answers

Answer:

Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces. So as two objects are separated from each other, the force of gravitational attraction between them also decreases.

answer: It is inversely proportional to the square of the distance.

Explanation:

for the team

what does it mean to do science

Answers

Answer:

Doing science could be defined as carrying out scientific processes, like the scientific method, to add to science's body of knowledge.

A student conducts an experiment to determine how the temperature of water affects the time for sugar to di solve. In each trial, the
student uses a different amount of sugar and a different temperature of water.
What is wrong with this experimental design?
The student changed too many variables
The student did not change enough variables
The student needs to perform more trials
The student does not have a dependent variable

Answers

Answer:

I think it's A

Explanation:

he shouldn't have changed the amount of sugar, because the whole point is to see which temperature dissolves sugar more quickly.

An object has mass M (uppercase) and is located at the origin of the coordinate system. A second object has mass m (lowercase) and is located at a distance r from the origin. This exercise explores the potential energy of the two-mass system. A spherical coordinate system is appropriate, but only the radial direction, r^, needs to be considered.

Enter a vector expression for the force, F⃗ , acting on mass m . The expression must be valid for all values of the radial coordinate, 0 0, and the zero of potential energy is taken as limr→∞UG=0.

Answers

Mass of the second object located at a distance r from the origin, r^ is the unit vector in the radial direction, and the negative sign indicates that the force

What is a system ?

The System can refer to a set of interacting or interdependent components forming an integrated whole. The term can be applied to various fields, including physics, engineering, biology, and social sciences, among others. In physics, a system typically refers to a collection of objects or particles that are studied together, often with the goal of understanding the behavior of the system as a whole. In engineering, a system can refer to a group of components that work together to perform a specific function, such as an electrical power grid or an automobile engine. In biology, a system can refer to an organism or group of organisms that interact with their environment, such as an ecosystem or the human body.

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A wave travels through a rope at a speed of 2.1 m/s and has a wavelength of 0.15 m. The wave then passes into a spring where it
travels at a speed of 5.0 m/s. The wave's wavelength in the spring is
m.

Answers

The wavelength of the wave in the spring is 0.357 m.

What is wavelenth?

Wavelength is the length of a complete revolution of a wave.

To calculate the wavelength of the wave in the spring, we use the formula below

Formula:

v'/λ' = v/λ........................ Equation 1

Where:

v' = Speed of the wave in the ropeλ' = Wavelength of the wave in the ropev = Speed of the wave in the springλ = Wavelength of the wave in the spring

From the question,

Given:

v' = 2.1 m/sλ' = 0.15 mv = 5.0 m/s

Substitute these values into equation 1 and solve for λ

2.1/0.15 = 5.0/λλ = (5×0.15)/2.1λ = 0.357 m

Hence, the wavelength is 0.357 m.

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This is 30% of my overall grade

Earth has a greater mass than the moon. If the mass of the moon was as great as the earth’s mass, how would it affect the moon’s orbit?

A - The moon will end out crashing into the earth.

B - The moon will continue to orbit as usual.

C - The moon will take a larger loop around the earth.

D - The moon will circle closer to the earth, but not crash into it.

Answers

Answer: C

Explanation:

Answer: C - The moon will take a larger loop around the earth.

Explanation:

A concave mirror creates a real, inverted image 16.0 cm from its surface. If the image is 3.5 times larger, how far away is the object? Use the GUESS method to solve the problem and show all your work. Record you final answer using the correct number of significant digits

Answers

Answer:

3.6, make sure you study

7) Three resistors having resistances of 4.0 Ω, 6.0 Ω, and 10.0 Ω are connected in parallel. If the combination is connected in series with an ideal 12-V battery and a 2.0-Ω resistor, what is the current through the 10.0-Ω resistor?

A) 0.59 A

B) 2.7 A

C) 6.4 A

D) 11.2 A

E) 16 A

E) 16 A

Answers

Answer:

A, 0.59A

Explanation:

The total resistance in the circuit is the resistances in parallel plus that in series.

Total resistance for those in parallel is;

1/(1/4 +1/6 +1/10) = 1/ (15+10+6 /60)

1/(31/60)= 60/31 ohms

Hence total resistance of the circuit is;

60/31 + 2 = (60+62)/31 = 122/31=3.94 ohms

To calculate the current flowing through the 10ohm resistance we need to know the voltage drop by subtracting the voltage drop in the 2ohm resistance from the total voltage drop.

Voltage drop on the 2 ohm resistance is;

Current on the 2 ohm resistor × 2 ohms

V = I ×R ; I - current

R - resistance

Current drop on the 2ohm resistance is;

Total voltage in the circuit/ total resistance in the circuit

12/3.94= 3.05A

Voltage drop on the 2 ohm resistance;

3.05 × 2 = 6.10volts

Hence voltage drop on the parallel resistance would be ;

12-6.10= 5.90V

Now voltage drop in a parallel circuit is the same hence 5.90v is dropped in each of the parallel resistance.

That said, the current drop on the 10 ohm resistor would be;

5.90/10 = 0.59A

Remember V= I× R so that I = V/R

The current flowing through the 10 ohms resistor is 0.59 A.

The given parameters;

resistors in parallel, = 4.0 Ω, 6.0 Ω, and 10.0 Ωresistor in series = 2 0 Ω,

The equivalent resistance of the parallel resistors;

\(\frac{1}{R_e} = \frac{1}{4} + \frac{1}{6}+ \frac{1}{10} \\\\\frac{1}{R_e} = \frac{31}{60} \\\\R_e = \frac{60}{31} = 1.94 \ ohms\)

The overall resistance with series resistor

R = 1.94+ 2 = 3.94 ohms

The current flowing in the entire circuit is calculated as follows;

\(I = \frac{V}{R} \\\\I = \frac{12}{3.94} \\\\I =3.05 \ A\)

The voltage drop due to the 2 ohms resistor is calculated as follows;

V = 12 - 3.05(2)

V = 5.9 V

The current flowing in the 10 ohms resistor is calculated as follows;

\(I = \frac{5.9}{10} \\\\I = 0.59 \ A\)

Thus, the current flowing through the 10 ohms resistor is 0.59 A.

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If you travel from Tucson to Argentina, you will see some different constellations in the night sky. true or false

Answers

Answer:

its true!!

Explanation: have a nice day !!

Emma has $70 in a savings account. The interest rate is 5%, compounded annually.To the nearest cent, how much will she have in 2 years?

Answers

Using compound interest formula:

\(A=P(1+\frac{r}{n})^{nt}\)

Where:

A = Amount

P = Principal = $70

r = Interest rate = 5% = 0.05

n = Number of times interest is compounded per year = 1

t = time = 2

So.

\(\begin{gathered} A=70(1+0.05)^2 \\ A=70(1.05)^2 \\ A=77.175 \\ A\approx77.18 \end{gathered}\)

Answer:

$77.18

If a wheel rotates 5 times in 90 seconds, what is the period and frequency

Answers

Answer:

i think it should be 18

Explanation:

Derive Lorentz transformation​

Answers

Lorentz transformation is a mathematical framework that describes how the coordinates of an event in space and time change for two observers in relative motion.

What is Lorentz transformation?

Consider two inertial frames of reference, S and S', moving relative to each other along the x-axis with a constant velocity v. Let an event occur at position (x, y, z, t) in frame S, and let (x', y', z', t') be the corresponding position in frame S'.

The transformation equations for space and time are given by:

\(x' = γ(x - vt)\\y' = y\\z' = z\\t' = γ(t - vx/c^2)\)

where\(γ = 1/√(1 - v^2/c^2)\) is the Lorentz factor, and c is the speed of light.

These equations show how the coordinates of an event in one frame of reference are related to the coordinates in another frame of reference that is moving relative to the first frame. They are known as the Lorentz transformations and are a fundamental aspect of special relativity.

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Mention the objective of the Experiment?

Answers

Answer:

I don't understand your question ❓,the object.....of what experiment

The objective of this experiment is to learn whether any Brainly contributor can give a reasonable or helpful answer to a question that contains totally zero information.

Please help ill mark youas brainliest !!

Please help ill mark youas brainliest !!

Answers

Answer:

can you put on a clearer image this one is hard to see

(5 points) find the kinematic and dynamic viscosity of air and water at a temperature of 40 oc (104 of) and an absolute pressure of 170 kpa (25 psia). (note: read the viscosity part in chapter 2 and learn how to look up viscosity in a table)

Answers

CentiStoke (cSt) conversion: 1 mm2/s = 106 m2/s. The kinematic viscosity of water at 20 °C is approximately 1 cSt.

What does water have at 30 C in terms of kinematic viscosity?

0.8 mm2 per second or soWater has a kinematic viscosity that ranges from 1.3 mm2 per second at 10 °C to 0.8 mm2 per second at 30 °C. The viscosity of water reduces as temperature rises.

How is kinematic viscosity determined?

By dividing a fluid's absolute viscosity by its mass density, the kinematic viscosity of the fluid may be calculated.

Dynamic viscosity calculation: how does it work?

The shear stress is divided by the rate of shear strain to get dynamic viscosity, also known as absolute viscosity.

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A twin-sized air mattress used for camping has dimensions of 100 cm by 194 cm by 14 cm when blown up. The weight of the mattress is 4 kg. How heavy a person (in N) could the air mattress hold if it is placed in freshwater

Answers

Answer:

\(2625.156\ \text{N}\)

Explanation:

Dimensions of mattress 100 cm by 194 cm by 14 cm

\(m_m\) = Mass of mattress = 4 kg

\(\rho\) = Density of water = \(1000\ \text{kg/m}^3\)

g = Acceleration due to gravity = \(9.81\ \text{m/s}^2\)

Volume of mattress

\(V=100\times 194\times 14=271600\ \text{cm}^3=0.2716\ \text{m}^3\)

Weight of water displaced is equal to the buoyant force

Mass of water

\(m=\rho V\\\Rightarrow m=1000\times 0.2716\\\Rightarrow m=271.6\ \text{kg}\)

Mass of person would be

\(m_p=m-m_m=271.6-4\\\Rightarrow m_p=267.6\ \text{kg}\)

Weight of the person would be

\(w=m_pg\\\Rightarrow w=267.6\times 9.81\\\Rightarrow w=2625.156\ \text{N}\)

The air mattress could hold a person that weighs up to \(2625.156\ \text{N}\).

What is the electric potential energy of the group of charges in the figure? (Figure 1)

What is the electric potential energy of the group of charges in the figure? (Figure 1)

Answers

that the relative placements of the charges as well as their multiples affect a set of ions' potential energy. When the specific charge have the same sign or have equal signs, the energy is positive. Or else, it is negative.

How is potential energy calculated?

The force acting just on two objects affects the potential energy formula. The formula for gravitational force is P.E. (= mgh, where g seems to be the acceleration caused by gravity (9.8 m/s2 at the earth's surface) while h represents the elevation in metres.

What is a system with two charges' potential energy?

As a result, the system's potential energy equals the sum of a work that was done to set up the entire system of two counts. The potential energy that exists in the combination of two charges in such an external field can be stated as follows: q1V(r1) = q2V(r2) + (q1q2/4or12).

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Ok I am done waiting for an answer for 5 hours can somebody PLEASE PLEASE PLEASE help me TIMED ASSESMENT HERE!!!! PLEASE
A graph titled Speed as a Function of Time with horizontal axis time (seconds) and vertical axis speed (meters per second). A straight orange line labeled A starts at 0 seconds 4 meters per second and runs to 6 seconds 7 meters. A straight blue line labeled B starts at 0 seconds 4 meters and upward to 6 seconds 4 meters. A straight green line starts at 0 seconds 4 meters and runs to 4 seconds 0 meters.
Use the graph of speed versus time to answer the questions about acceleration.



Which of the cars is speeding up?



Which of the cars is slowing down?



Which of the cars is maintaining a constant speed?

Answers

Answer:

Explanation:

I'm going to assume that all the givens are in m/s. If I am correct, The orange line is speeding up. It is going from 4 m/s to 7 m/s. Its slant is from lower left to upper right. It is increasing in speed.

The green line is slowing down. It is going from 4 to 0 m/s. It's slant is from upper left to lower right.

The blue line is horizontal. It is neither slowing down or speeding up.

Answer:

sorry for being very very very late, but here is your answer)

car speed A

car slow down C

car constant speed B

hope this helped!!!!

A 1,000 kg hot air balloon is drifting along at 3 m/s at a height of 50m above the ground.

How much kinetic energy does the balloon have? ___

How much potential energy does the balloon have? ____

How much total mechanical energy does the balloon have? ___

Answers

The Kinetic energy of the hot air balloon is 4500 Joules, the potential energy is 4.9 × 10⁵ Joules, and the total mechanical energy is 4.95 × 10⁵ Joules.

What is the Kinetic energy?

The Kinetic energy is the amount of energy which is present in the body of an object which is under motion. The kinetic energy is a vector quantity because it has both the magnitude and direction. The SI unit of KE is Joule. The KE of an object can be calculated by the formula:

KE = 1/2 mv²

KE = 1/2 × 1000 × (3)²

KE = 500 × 9

KE = 4500 Joules

PE = m × g × h

PE = 1000kg × 9.8 × 50

PE = 490,000 Joules

Total Mechanical energy = PE + KE

Total Mechanical energy = 4500 + 490000

Total Mechanical energy = 494500 Joules

Total Mechanical energy = 4.95 × 10⁵ Joules

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What is the best description of a wave?
O a pulse that carries energy
O a disturbance that moves matter
O a medium disturbed by a vibration
matter that is moved from one place to another

Answers

Is the first option (hope so)
I think it’s a pulse that carrie’s energy ??

Say the turbine is 10 feet in diameter (that's the radius of the dashed circle). Also say that the coil has 100 turns and has a square cross-section with a length of 10 feet and a height of 6 feet. Say that the magnetic rotor has the same height but is only 2 feet wide, it has a magnetic field strength is 0.1T, and it is rotating at 60Hz (note this is not the angular frequency). A typical turbine supplies 10kW of power. Use Faraday's law to find the induced emf in the coil and the amount of induced current.

Answers

Answer:

a. ε = 21,014sin(120πt) V

b. 0.476cosec(120πt)  

Explanation:

a. Induced emf

We know the induced emf, ε = -dΦ/dt where Φ = magnetic flux through coil = NABcosθ where N = number of turns of coil =, 100, A = area of coil = 10 ft × 6 ft = 60 ft² = 60 × 1 ft² = 60 × (0.3048)² m² = 5.574 m², B = magnetic field strength = 0.1 T and θ = angle between B and normal to A = ωt.

So, Φ = NABcosθ = 100 × 5.574 m² × 0.1 T cosθ  = 55.74cosθ Tm²

So, ε = -dΦ/dt = ε = -d(55.74cosθ Tm²)/dt = -d(55.74cosθ Tm²)/dθ × dθ/dt = -55.74 ×(-sinθ) Tm²)/dθ × ω (ω = dθ/dt = angular frequency of shaft = 2πf where f = frequency of rotor = 60 Hz )

ε = 55.74sinθ Tm²) × 2πf

ε = 55.74sinθ Tm²) × 2π(60 Hz)

ε = 6689πsinθ V

ε = 21,014sinθ V

ε = 21,014sinωt V

ε = 21,014sin(2πft) V

ε = 21,014sin(2π(60 Hz)t) V

ε = 21,014sin(120πt) V

b. Current in coil

Since power P = Iε where I = current and ε = induced emf = 21,014sinθ V.

Since power, P = 10 kW = 10000 W

I = P/ε

= 10000 W/21,014sinθ V

= 0.476/sinθ

= 0.476cosecθ

= 0.476cosecωt

= 0.476cosec(120πt)  

The maximum current is obtained when θ = 90°

I =  10000 W/21,014sin90 V

I = 10000 W/21,014 V

I = 0.476 A

I = 476 mA

A car travels south on a highway for 2 h at 90 km/h. The car reverses direction and head north for 0.5 h at 8 km/h. What is the car’s position relative to where it started ?

Answers

Answer:

220

Explanation:

The letter 'J' represent
a. Wavelength
b. Crest
c. Trough
d. Amplitude
of the wave (3.2.1)

The letter 'J' representa. Wavelengthb. Crestc. Troughd. Amplitudeof the wave (3.2.1)

Answers

Explanation:

J is amplitude

I is wavelength

K is trough

L is crest

M is midline

A baseball is popped straight up into the air and has a hang-time of 6.25 S.
Determine the height to which the ball rises before it reaches its peak. (Hint: the
time to rise to the peak is one-half the total hang-time.)

A baseball is popped straight up into the air and has a hang-time of 6.25 S.Determine the height to which

Answers

Answer:

To determine the height to which the ball rises before it reaches its peak, we need to know the initial velocity of the ball and the acceleration due to gravity. Let's assume the initial velocity of the ball is v and the acceleration due to gravity is g.

The time it takes for the ball to reach its peak is one-half the total hang-time, or 1/2 * 6.25 s = 3.125 s.

The height to which the ball rises can be calculated using the formula:

height = v * t - (1/2) * g * t^2

Substituting in the values we know, we get:

height = v * 3.125 s - (1/2) * g * (3.125 s)^2

To solve for the height, we need to know the value of v and g. Without more information, it is not possible to determine the height to which the ball rises before it reaches its peak.

Explanation:

Answer:

Approximately \(47.9\; {\rm m}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\) and that air resistance on the baseball is negligible.)

Explanation:

If the air resistance on the baseball is negligible, the baseball will reach maximum height at exactly \((1/2)\) the time it is in the air. In this example, that will be \(t = (6.25\; {\rm s}) / (2) = 3.125\; {\rm s}\).

When the baseball is at maximum height, the velocity of the baseball will be \(0\). Let \(v_{f}\) denote the velocity of the baseball after a period of \(t\). After \(t = 3.125\; {\rm s}\), the baseball would reach maximum height with a velocity of \(v_{f} = 0\; {\rm m\cdot s^{-1}}\).

Since air resistance is negligible, the acceleration on the baseball will be constantly \(a = (-g) = (-9.81\; {\rm m\cdot s^{-2}})\).

Let \(v_{i}\) denote the initial velocity of this baseball. The SUVAT equation \(v_{f} = v_{i} + a\, t\) relates these quantities. Rearrange this equation and solve for initial velocity \(v_{i}\):

\(\begin{aligned}v_{i} &= v_{f} - a\, t \\ &= (0\; {\rm m\cdot s^{-1}}) - (-9.81\; {\rm m\cdot s^{-2}})\, (3.125\; {\rm s}) \\ &\approx 30.656\; {\rm m\cdot s^{-1}}\end{aligned}\).

The displacement of an object is the change in the position. Let \(x\) denote the displacement of the baseball when its velocity changed from \(v_{i} = 0\; {\rm m\cdot s^{-1}}\) (at starting point) to \(v_{t} \approx 30.656\; {\rm m\cdot s^{-1}}\) (at max height) in \(t = 3.125\; {\rm s}\). Apply the equation \(x = (1/2)\, (v_{i} + v_{t}) \, t\) to find the displacement of this baseball:

\(\begin{aligned}x &= \frac{1}{2}\, (v_{i} + v_{t})\, t \\ &\approx \frac{1}{2}\, (0\; {\rm m\cdot s^{-1}} + 30.565\; {\rm m\cdot s^{-1}})\, (3.125\; {\rm s}) \\ &\approx 47.9\; {\rm m}\end{aligned}\).

In other words, the position of the baseball changed by approximately \(47.9\; {\rm m}\) from the starting point to the position where the baseball reached maximum height. Hence, the maximum height of this baseball would be approximately \(47.9\; {\rm m}\!\).

A tuning fork is vibrating the air around it. What best describes the waves produced by the tuning fork?

Answers

The waves produced by a vibrating tuning fork are longitudinal waves, also known as compression waves.

What are Longitudinal Waves?

Longitudinal waves are waves that oscillate along the direction of propagation, meaning they create alternating regions of compression and rarefaction in the medium through which they travel.

In the case of a vibrating tuning fork, the tines of the fork move back and forth, causing the surrounding air to alternately compress and expand. These pressure changes propagate through the air as longitudinal waves.

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A baseball is hit almost straight up into the air with a speed of 22 m/s. Estimate (a) how high it goes, and (b) how long it is in the air. (c) What factors make this an estimate ?

Answers

(a) The ball goes up to the height of 31.89 m. (b) The ball stays for 5.1 s in the air. (c) The acceleration due to gravity and wind resistance can affect the estimation.

What is Acceleration due to gravity?

Acceleration owing to gravity is the term used to describe the rate at which a body's velocity changes as a result of the earth's gravitational pull. In general, it is assumed that the acceleration caused by gravity is in the downward direction.

The acceleration caused by gravity has been calculated as, however as it changes from location to location, it may have an impact on the estimation.

You may have thought that the wind has no impact, but it can actually generate drag and even cause the ball to shift course.

Therefore, (a) The ball goes up to the height of 31.89 m. (b) The ball stays for 5.1 s in the air. (c) The acceleration due to gravity and wind resistance can affect the estimation.

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