12. A 2.5 x 10¹8 Hz x-ray photon strikes a metal foil and frees an electron. After the collision a lower energy 2.3 x 10¹8 Hz x-ray photon emerges. What is the speed of the electron? [P4]

Answers

Answer 1

The speed of the electron is 5.5 x 10⁶ m/s after the collision.

A photon with a frequency of 2.5 × 10¹⁸ Hz collides with a metal foil, freeing an electron. A lower-energy 2.3 × 10¹⁸ Hz X-ray photon emerges from the collision. We need to find out the electron's velocity after the collision.

hf = E, where h is Planck's constant and f is the frequency.

The energy of the photon can be calculated by multiplying the Planck's constant h by the frequency f.

\(E = h * fE_1 = (6.626 * 10^-^3^4 J.s) * (2.5 * 10^1^8 Hz)E_1 = 1.66 * 10^-^1^5 J\).

The frequency of the emitted X-ray photon is calculated in the same way.

\(E = h * fE_2 = (6.626 * 10^-^3^4 J.s) * (2.3 * 10^1^8 Hz)E_2 = 1.53 * 10^-^1^5 J\).

The electron's kinetic energy can be calculated by subtracting the energy of the emitted photon from the energy of the incident photon.

\(KE = E_1 - E_2\)

\(KE = (1.66 * 10^-^1^5 J) - (1.53 * 10^-^1^5 J)\)

\(KE = 0.13 * 10^-^1^5 J\).

To find the electron's velocity, we'll first convert the kinetic energy to joules.

\(KE = (1/2)mv^2v = \sqrt{(2KE/m)}\) where m is the mass of the electron, which is 9.11 × 10⁻³¹ kg.

\(v = \sqrt{ [(2 * 0.13 * 10^-^1^5 J)/9.11 * 10^-^3^1 kg]v}\) \(= 5.5 * 10^6 m/s\) (to two significant figures).

Therefore, the speed of the electron is 5.5 x 10⁶ m/s after the collision.

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Related Questions

A)What is the mass, in grams, of 28.76 mL of acetone?
B)What is the volume, in milliliters, of 6.40 g of acetone?
both in significant figures

Answers

A) The mass of 28.76 mL of acetone is approximately 22.7 g.

B) The volume of 6.40 g of acetone is approximately 8.12 mL.

A) To determine the mass of 28.76 mL of acetone, we need to know the density of acetone. The density of acetone is approximately 0.789 g/mL. Therefore, we can calculate the mass as follows:

Mass = Volume * Density

Mass = 28.76 mL * 0.789 g/mL

Performing the calculation:

Mass ≈ 22.67564 g

Rounding the result to the correct number of significant figures, the mass of 28.76 mL of acetone is approximately 22.7 g.

B) To determine the volume of 6.40 g of acetone, we can rearrange the formula:

Volume = Mass / Density

Volume = 6.40 g / 0.789 g/mL

Performing the calculation:

Volume ≈ 8.116 g/mL

Rounding the result to the correct number of significant figures, the volume of 6.40 g of acetone is approximately 8.12 mL.

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light waves bounce off of an object and move through your cornea, pupil, and lens. which step is this in the 4-step process of sensation and perception?

Answers

The step where light waves bounce off an object and move through the cornea, pupil, and lens corresponds to the first step in the four-step process of sensation and perception.

The four-step process of sensation and perception involves the following steps: stimulation, transduction, transmission, and interpretation. In the context of vision, the process begins with the stimulation of light waves bouncing off an object. This stimulation occurs when light waves from the object enter the eye.

The light waves first pass through the cornea, which is the transparent outer covering of the eye. Then they enter the pupil, which is the adjustable opening in the center of the iris. The iris controls the size of the pupil, regulating the amount of light that enters the eye. After passing through the pupil, the light waves reach the lens, which further focuses the light onto the retina at the back of the eye.

This initial step of the light waves moving through the cornea, pupil, and lens represents the process of stimulation in the sensation and perception cycle. It involves the physical interaction of light with the eye's structures, setting the stage for further processing and interpretation of visual information.

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which are true of tides? multiple select question. in most places, high and low tides occur every 12 hours and 25 minutes. variance in high and low tide levels is the same from place to place. they are cyclic changes in the height of the sea surface. they usually only vary between high and low levels by 1 to 3 m. they are only observed in the open ocean, not in bays or estuaries.

Answers

The true statements about tides are:
1. In most places, high and low tides occur every 12 hours and 25 minutes.
2. They are cyclic changes in the height of the sea surface.
3. They usually only vary between high and low levels by 1 to 3 meters.

The false statements are:
- Variance in high and low tide levels is not the same from place to place, as it can be influenced by factors like coastline shape, water depth, and other geographical factors.
- Tides are not only observed in the open ocean; they can also be observed in bays and estuaries.

Therefore, the following propositions are true: 1. High and low tides typically occur every 12 hours and 25 minutes.

2. The height of the sea surface cycles back and forth.

3. There is typically only a 1 to 3 metre difference between high and low levels.

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Independent Variable vs. Dependent Variable--Compare Them

Answers

Answer:

A independent variable is the variable that is changed or controlled in a scientific experiment to test the effects on the dependent variable.

Explanation:

I think this is right i hope so.

Independent variable is the thing being tested in the experiment, while, the dependent variable is the result of the independent. In other word, a dependent variable depends on the independent.

if the jet in ngc 5128 is traveling at 5000 km/s and is 40 kpc long, how long will it take for gas to travel from the core of the galaxy to the end of the jet?

Answers

It would take approximately 2.4688 × 10^17 seconds or 7.82 million years for gas to travel from the core of the galaxy to the end of the jet, assuming a constant speed of 5000 km/s.

To calculate the time it would take for gas to travel from the core of the galaxy to the end of the jet, we need to use the formula: time = distance / speed.

Given that the jet in NGC 5128 is traveling at 5000 km/s and is 40 kpc (kiloparsecs) long, we first need to convert the distance from kpc to km. 1 kpc = 3.086 × 10^16 meters, which means 1 kpc = 3.086 × 10^19 km.

Therefore, the length of the jet in kilometers is 40 x 3.086 × 10^19 km = 1.2344 × 10^21 km.

Now we can calculate the time it would take for gas to travel from the core of the galaxy to the end of the jet as follows:

time = distance / speed
time = 1.2344 × 10^21 km / 5000 km/s
time = 2.4688 × 10^17 seconds

So, it would take approximately 2.4688 × 10^17 seconds or 7.82 million years for gas to travel from the core of the galaxy to the end of the jet, assuming a constant speed of 5000 km/s.

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what is the correct answer?​

what is the correct answer?

Answers

The effective resistance of the Parallel circuit is 3 ohms.

option B.

What is the effective resistance of the circuit?

In a parallel circuit, the sum of the currents through each path is equal to the total current that flows from the source.

The total resistance or effective resistance in a Parallel circuit with the following formula:

1/Rt = 1/R1 + 1/R2

where;

Rt is the effective resistanceR1 is the resistance of the first resistorR2 is the resistance of the second resistor

1/Rt = 1/4 + 1/12

1/Rt = (3 + 1 ) / 12

Rt = ( 12 ) / ( 4 )

Rt = 3 ohms

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on bode's advice, herschel named his newly discovered planet after:

Answers

Answer:

On Bode's advice, Herschel named his newly discovered planet after: the Greek god Uranus.

Explanation:

Herschel named his newly discovered planet Uranus on Bode's advice for a couple of reasons:

Mythological Naming Convention: During that time, it was a common practice to name celestial objects after mythological figures, particularly gods from Greek and Roman mythology. Bode suggested following this convention and recommended that Herschel choose a name from Greek mythology for the newly discovered planet.

Connection to the Sky: Uranus was chosen as the name for the planet because it was the name of the Greek god of the sky. Given that Herschel had discovered a celestial object in the sky, naming it after the god associated with the sky seemed fitting.

By naming the planet Uranus, Herschel paid homage to the mythological tradition of naming celestial bodies while also establishing a connection between his discovery and the vastness of the sky.

Hope this helps!

Jovan starts at his house. He, then, walks 5.0 miles to a store eastward. He then walks to his grandma’s house 3.0 miles west from the store. What is Jovan's displacement?

2.0 miles, east
2.0 miles, west
8.0 miles, east
8.0 miles, west

Answers

The displacement of the object is obtained as shown as 2.0 miles east. Option A

What is the displacement?

We must be able to remind ourselves that the displacement is a vector and that we would find the resultant displacement in a manner that is quite different from the the manner that we would be able to find the total speed.

We know that speed is a vector quantity so we can be able to find the total speed by the simple use of algebra but this is not the case when we want to find the resultant velocity. This must have to be done in a vectoral manner as we shall do below.

We have the following information';

Eastward displacement =  5.0 miles

West ward displacement = 3.0 miles

Since the movements are found to be in opposite direction;

Total displacement = 5 - 3

= 2.0 miles east

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calculate the frequency of a photon of electromagnetic radiation for red light (750 nm). group of answer choices

Answers

Using the theories of electromagnetic radiations, we got that  4×\(10^{4}\)nm. is the  frequency of a photon of electromagnetic radiation for red light

We know very well that there is a relation between velocity of light, frequency and wavelength of light.

The relation is given by c=vλ where v is the frequency of light and λ is the wavelength of the light.

We are given for wavelength as 750nm or 750×\(10^{-9}\)m

We, know that speed of light is =\(10^{8}\)m/sec

So putting the values in formula, we get

=>3×\(10^{8}\)=v×750×  \(10^{-9}\)

=>v=(3/750)×\(10^{17}\)

=>v=0.004×\(10^{17}\)

=>v=4×\(10^{13}\)m or 4×\(10^{4}\)nm.

Hence, the frequency of a photon of electromagnetic radiation for red light(750nm) is 4×\(10^{4}\)nm.

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Compare the momentum of a 7160 kg truck moving at 5.00 m/s to the
momentum of a 2240 kg car moving at 15.0 m/s.

Answers

Answer:

2,200

Explanation:

truck=35800,car=33600

Jane watches her twin sister Julie disappear over the horizon in a high powered space ship which travels at 290 000 000 m/s into deep space. Julie's watch shows she has been gone 45 minutes, however Jane think otherwise. Calculate how long Jane has waited for the return of her sister.

Answers

Jane watches her twin sister Julie disappear over the horizon in a high powered space ship which travels at 290 000 000 m/s into deep space. Julie's watch shows she has been gone 45 minutes, however Jane think otherwise. Jane has waited for approximately 25.5 minutes for the return of her sister.

To calculate the time Jane has waited for the return of her sister, we need to consider the concept of time dilation due to relativistic effects.

According to the theory of relativity, as an object approaches the speed of light, time for that object slows down relative to an observer at rest. This phenomenon is known as time dilation.

Julie, traveling in a high-powered spaceship at a speed of 290,000,000 m/s, experiences time dilation. We can calculate the time dilation factor using the equation:

γ = 1 / √(1 - v^2 / c^2)

Where γ is the time dilation factor, v is the velocity of the spaceship, and c is the speed of light (approximately 299,792,458 m/s).

Plugging in the given values, we have:

γ = 1 / √(1 - (290,000,000)^2 / (299,792,458)^2)

γ ≈ 1 / √(1 - 0.9607)

γ ≈ 1 / √(0.0393)

γ ≈ 1 / 0.1982

γ ≈ 5.048

This means that for every 1 minute experienced by Jane, 5.048 minutes have passed for Julie on the spaceship.

Given that Julie's watch shows she has been gone for 45 minutes, we can calculate the time Jane has waited using the equation:

Jane's Wait Time = Julie's Time / γ

Jane's Wait Time ≈ 45 minutes / 5.048

Jane's Wait Time ≈ 8.91 minutes

Therefore, Jane has waited for approximately 8.91 minutes, which is approximately 8 minutes and 54.6 seconds, for the return of her sister.

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a box is pushed along the ground with a force of 20N. If the box is pushed 0.5M.How much work done is on it?

Answers

Answer:

10J

Explanation:

work (W)= force (F)× distance (d)

W= 20N × o.5m

=10J (Joule)

Answer:

10 joules(j)

Explanation:

while the woman is repairing a leaky pipe under her kitchen sink, she looks at close objects through the upper half of her bifocal lenses. what is the closest object that she can see clearly?

Answers

Thus the closest object that the woman should be able to see while looking through the upper part of the bifocal lens would be the object that lies between 25cm of the lens.

Bifocal spectacles are specs which are created of both convex and concave lens. The upper part is made up of the concave lens while the lower part consists of convex lens.

When looking through the upper part of the bifocal lens the objects at a little distance become clearer as the upper part of bifocal lens consists of diverging lens that is used to correct distant or vision at some distance.

There are two types of lens the converging or convex lens and the diverging lens or concave lens.

Convex lens is called the converging lens as a two parallel rays of light when passing through a convex lens get bent towards each other and converge at some point.

Concave lens is called the converging lens as two parallel rays on passing through the concave lens get diverged from each other.

The clearest image that is formed by a concave lens is when the object lies between the focal point and the lens, where the image is formed at the focal point on the image side of the lens.

Thus the closest object that she would be able to see is the object that she would be able to see clearly would be the object that lies between 25cm of the lens.

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what are the example of ultraviolet rays

Answers

Ultraviolet (UV) rays are a type of electromagnetic radiation that are invisible to the human eye. They have shorter wavelengths than visible light and are divided into three categories: UVA, UVB, and UVC. Examples of sources of ultraviolet rays include:

1. Sunlight: The sun is the primary natural source of UV rays. UV radiation from the sun is responsible for causing sunburn, skin aging, and an increased risk of skin cancer.

2. Tanning beds: Tanning beds and sun lamps emit UVA and UVB radiation, which can also cause skin damage and increase the risk of skin cancer.

3. Fluorescent lights: Some types of fluorescent lights emit small amounts of UV radiation.

4. Welding torches: Welding torches emit high levels of UV radiation, which can cause eye damage and skin burns if protective gear is not worn.

5. Germicidal lamps: These lamps are used to disinfect surfaces and air, but can also emit UVC radiation, which is harmful to living organisms and can cause skin and eye damage.

a force acts on a particle that undergoes a displacement. find the work done by the force on the particle. what is the angle between f and r

Answers

To determine the work done by a force on a particle, we need to consider the displacement of the particle and the angle between the force and the displacement vector.

When the force acts on a particle, it causes the particle to undergo a displacement. The work done by the force is equal to the magnitude of the force multiplied by the magnitude of the displacement vector, and then multiplied by the cosine of the angle between the force and displacement vector.

To find the work done by the force, you must first calculate the magnitude of the force, the magnitude of the displacement vector, and the angle between the force and displacement vector.

Once these three components have been calculated, the work done by the force can be calculated using the equation W = F * r * cos(θ).

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What is the maximum speed at which a car can safely travel around a circular track of radius 142 meters if the coefficient of friction between the tires and the road is 1.07? Include units in your answer. Answer must be in 3 significant digits.

Answers

Given that the radius of the circular path is r = 142 m and the coefficient of the friction is

\(\mu=1.07\)

The condition for the car to travel safely is

Frictional force = centrifugal force

\(\mu mg=\frac{mv^2}{r}\)

Here, m is the mass of the car and the acceleration due to gravity is g = 9.8 m/s^2.

v is the maximum speed of the car.

\(\begin{gathered} v=\sqrt[]{ugr} \\ =\sqrt[]{1.07\times9.8\times142} \\ =38.58\text{ m/s} \end{gathered}\)

Practice questions 1) A flea has a mass of 4.5 x10^-7 and can jump vertically upwards to a height of 6cm.calculate (a) the kinetic energy of the flea as it leaves the ground (b)its initial velocity.

Answers

The kinetic energy of the flea is 2.7×10^-7J and the initial velocity is 1.09m/s

What is kinetic energy?

The kinetic energy of an object is the energy that it possesses due to its motion. It is also defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.

Kinetic energy is measured in Joules and it is expressed as K.E = ½mv². Where m is the mass of the object and v is it's velocity.

the initial velocity of the object can be calculated as

V²= u²-2gh. At this point the final velocity will be 0

u²= 2gh

u² = 2× 9.8× 0.06m

u² = 1.18

u= √1.18

u= 1.09m/s

therefore K.E = ½× 4.5× 10^-7× 1.09²

K.E = 2.7×10^-7 J

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What is cpp code to traverse a vector?

Answers

To traverse a vector in C++, you can use a for loop that iterates over the vector and accesses each element using the vector's index.

Here is some sample code that illustrates this.:

#include <iostream>

#include <vector>

using namespace std;

int main() {

   vector<int> vect = {1, 2, 3, 4, 5, 6, 7};

   // traverse the vector using a for loop

   for (int itr = 0; itr < vect.size(); itr++) {

       cout << vect[i] << " ";

   }

   cout << endl;

   return 0;

}

In this example, we create a vector of integers containing the values 1 through 5. We then use a for loop to iterate over the vector and print out each element using the vector's index. The size() method is used to determine the number of elements in the vector, which is used as the upper bound for the loop.

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I'm walking 1.6m/s to 7-11 and it started to rain so I sped up to 2.7m/s in 1.2
seconds. What is my acceleration?
a=(vf-viyt
-0.92m/s2
O 01.1m/s2
0.92m/s2
1.1m/s2
1 points
Save A

I'm walking 1.6m/s to 7-11 and it started to rain so I sped up to 2.7m/s in 1.2seconds. What is my acceleration?a=(vf-viyt-0.92m/s2O

Answers

Answer:

Explanation:

\(a = \frac{v_f-v_0}{t}\) which is the final velocity minus the initial velocity in the numerator, and the change in time in the denominator.  For us:

\(a=\frac{2.7-1.6}{1.2}\) so

a = .92 m/s/s (NOT negative because you're speeding up)

A
heat engine is measured to have 30% efficiency. Is the theoretical
efficiency going to be greater or less than that? Why?

Answers

The theoretical efficiency is greater than that of the actual efficiency of the engine. This is because heat engine always produces some waste heat.

The Second Law of Thermodynamics states that a heat engine cannot be 100% efficient. In practice, a heat engine is only 100% efficient when it is operating at about 30-50% efficiency.

If we were to multiply this by 100, we would get the efficiency as a percent: 49%. This is the theoretical maximum efficiency. If we were to actually build an engine, it would be less efficient than the theoretical engine. The theoretical engine that can achieve this theoretical maximum efficiency is called the Carnot Engine.

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A piece of metal has a mass of 60 g and a volume of 3 cm^3, what is the density of the metal..?

Answers

Answer:  20 g/cm^3

====================================================

Work Shown:

density = mass/volume

d = m/v

d = (60 grams)/(3 cubic cm)

d = (60/3) g per cm^3

d = 20 g per cm^3

d = 20 g/cm^3

This means that each cubic centimeter of material has about 20 grams of mass.

A cubic centimeter is a cube that has all sides each 1 cm.

The density of the piece of metal is equal to 20 g/cm³ when the mass is 60 g and a volume of 3 cm³ of metal.

What is the density?

The density of a substance can be measured as the mass per unit volume of that substance. The average density is equal to the total mass of the substance divided by its total volume.

The formula for the density of the substance is represented as follows:

The density of material = Mass/Volume

The density of a material is an intrinsic property as it does not depend on its size and the S.I. unit of the density is Kg/m³. If the size of the substance increases, the mass increases as well but the density of the material remains the same.

Given, the mass of the metal, M = 60 g

The volume of the metal, V = 3cm³

The density of metal = M/V = 60 /3 = 20 g/cm³

Therefore, the density of a piece of metal is 20g/cm³.

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which way would 2 negatively charged balloons naturally move? what would that do to the amount of potential energy stored in the field?

Answers

Answer:

gsg

Explanation:

The balloons with negative charges moves apart from each other by electrostatic force of repulsion. The potential energy in them increases as they move away.

What is force of repulsion?

The basic principle of charges is that, two like charges repel and unlike charge attracts. That is: two negative charged bodies or two positively charged bodies will repel each other and one negative charged body attracts a positively charged body.

In both cases attraction or repulsion the charged particles exerts a force with each other called the electrostatic force. The electrostatic force between two charges is directly proportional to the magnitude of charges and inversely proportional to the distance between them.

The balloons with negative charges moves apart from each other by electrostatic force of repulsion. The potential energy in them increases as they move away.

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Suppose 435 mL of Ne gas at 21 °C and 1. 09 atm, and 456 mL of SF6 at 25 °C and 0. 89 atm are put into a 325 mL flask at 30. 2 °C (a) What will be the total pressure in the flask? (b) What is the mole fraction of for each of the gases in the flask?

Answers

(a) To determine the total pressure in the flask, we need to consider the partial pressures of each gas present and add them together.

Using the ideal gas law, we can calculate the partial pressure of each gas:

PV = nRT

For Ne gas:

P₁V₁ = n₁RT

P₁ = (n₁/V₁)RT

For SF6 gas:

P₂V₂ = n₂RT

P₂ = (n₂/V₂)RT

To find the total pressure, we add the partial pressures:

P_total = P₁ + P₂

(b) The mole fraction (χ) of each gas can be calculated using the formula:

χ = moles of gas / total moles of gas

To find the moles of each gas, we use the ideal gas law rearranged:

n = PV / RT

Now, let's calculate the values.

Given:

Volume of Ne gas (V₁) = 435 mL = 0.435 L

Temperature of Ne gas (T₁) = 21 °C = 294 K

Pressure of Ne gas (P₁) = 1.09 atm

Volume of SF6 gas (V₂) = 456 mL = 0.456 L

Temperature of SF6 gas (T₂) = 25 °C = 298 K

Pressure of SF6 gas (P₂) = 0.89 atm

Volume of flask (V_total) = 325 mL = 0.325 L

Temperature of flask (T_total) = 30.2 °C = 303.2 K

Gas constant (R) = 0.0821 L·atm/(K·mol)

(a) To calculate the total pressure:

P₁ = (n₁/V₁)RT₁

P₁ = (PV₁/RT₁)

P₂ = (n₂/V₂)RT₂

P₂ = (PV₂/RT₂)

P_total = P₁ + P₂

(b) To calculate the mole fraction:

n₁ = P₁V_total / RT_total

n₂ = P₂V_total / RT_total

χ₁ = n₁ / (n₁ + n₂)

χ₂ = n₂ / (n₁ + n₂)

By plugging in the given values and performing the calculations, we can find the total pressure in the flask and the mole fraction of each gas.

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Describe the energy of the skier at location W.*

At point W, potential energy is greatest and kinetic energy is least.
At point W, potential energy is least and kinetic energy is greatest.
At point W, potential energy and kinetic energy are the same.

Describe the energy of the skier at location W.*At point W, potential energy is greatest and kinetic

Answers

Answer:

The description of the energy of the skier at point W is,

At point W, potential energy is greatest and kinetic energy is least

Explanation:

The given parameters are;

The highest point of the skier's path = Point W

The lowest point of the skier's path = Point X

The height of the peak after point X = Intermediate between point W and point X

The potential energy of the skier, P.E. = m·g·h

The kinetic energy of the skier, K.E. = 1/2·m·v²

The total mechanical energy of the skier, M.E. = P.E. + K.E.= Constant

Where;

m = The mass of the skier

g = The acceleration due to gravity = 9.8 m/s²

h = The height of the skier

v = The velocity of the skier

Therefore, the P.E. of the skier is highest at the highest point of the skier's path which is the point W, where h = Maximum

Similarly, the potential energy of the skier will be lowest at point X which is the lowest point on the skier's path

From P.E. + K.E. = constant, the kinetic energy will be least at point W, where the potential energy is highest.

Therefore, the description of the energy of the skier at point W is that the potential energy is greatest and kinetic energy is least.

consider the spring-mass system with external forcing. webassign plot suppose the object attached to the spring has mass of 2 kg and the spring exerts a linear resistive force with spring constant k

Answers

The behavior of the spring-mass system with external forcing depends on the mass of the object, the spring constant, and the presence of a linear resistive force.

What factors determine the behavior of a spring-mass system with external forcing?

The spring-mass system with external forcing refers to a mechanical system consisting of a mass attached to a spring, where an external force is acting on the system. The main answer highlights that the behavior of this system depends on three key factors: the mass of the object, the spring constant, and the presence of a linear resistive force.

The mass of the object plays a significant role in determining the response of the system. A higher mass will result in a slower response and greater inertia, while a lower mass will lead to a faster response and less resistance to motion.

The spring constant, denoted as 'k,' represents the stiffness of the spring. It determines the amount of force exerted by the spring for a given displacement. A higher spring constant implies a stiffer spring, resulting in a stronger restorative force and thus affecting the system's oscillation characteristics.

The presence of a linear resistive force introduces damping into the system. Damping opposes the motion of the mass and dissipates energy, leading to a decrease in amplitude over time. The magnitude of the resistive force depends on various factors, such as the speed of the object and the medium through which it moves.

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A basketball is dropped from top of the rim. It takes 1.3s to fall, what is the displacement?
a. 8.45 m
b. 8.321 m
c. 33.67 m
d. 33.8 m

Answers

Answer:

d = 8.45 m

Explanation:

Given that,

A basketball is dropped from top of the rim.

It takes 1.3s to fall.

We need to find the displacement of the basketball. Let the displacement is d. Using second equation of kinematics,

\(d=ut+\dfrac{1}{2}at^2\)

Where

u is the initial velocity, u = 0

a = g

So,

\(d=\dfrac{1}{2}\times 10\times 1.3^2\\\\d=8.45\ m\)

So, the displacement of the basketball is 8.45 m.


The velocities of light in air and glass are 3.0 x 10^8ms and 2.0×10^8ms respectively. If the angle of refraction is 30°, the sine of the angle of incidence is?
Pls help​

Answers

Answer:

0.75

Explanation:

\(refractive \: index \: = \frac{3.0 \times {10}^{2} }{2.0 \times {10}^{2} } \)

= 1.5

\(refractive \: index = \frac{ \sin(angle \: of \: incidence) }{ \sin(angle \: of \: refraction) } \)

\(1.5 = \ \frac{ \sin(i) }{ \sin(30) } \)

1.5 × ½ = sin(i)

\( \sin(i) = 0.75\)

A) write the name of any two instrument based on atmoshpheric pressure.
B)Which chemical is used to increase the setting period of cement?
C)What are the near point and far point of normal eye?​

Answers

Answer:

Explanation:(a)Mercury Barometer and Aneroid Barometer

(b)Gypsum

(c)Near point of human eye is 25 cm and the far point is infinity.

1. why were you told to measure to the middle of the stack of pennies to get the length of the pendulum?

Answers

When measuring the length of a pendulum, it is important to measure to the middle of the stack of pennies because this point is the center of mass of the pendulum. The center of mass of an object is the point at which the object's mass is evenly distributed, meaning that if the object is suspended from this point, it will remain in a stable position.

For a pendulum, the center of mass is located at the point where the mass is concentrated, which is usually at the bottom of the pendulum. However, when using a stack of pennies to adjust the length of the pendulum, the center of mass shifts to the middle of the stack.

Measuring to the middle of the stack of pennies ensures that the length of the pendulum is measured from the point of maximum stability. If the length were measured from the bottom of the stack of pennies, for example, the center of mass would be shifted, and the pendulum would not swing in a predictable manner.

Additionally, measuring to the middle of the stack of pennies allows for consistent measurements between different pendulums. By measuring to a standardized point, such as the middle of the stack of pennies, researchers can compare the lengths and periods of different pendulums, which is important in experiments that require precise measurements.

In summary, measuring to the middle of the stack of pennies ensures that the length of the pendulum is measured from the point of maximum stability and allows for consistent measurements between different pendulums.

Scientific law provides descriptions.


True

False

Answers

Answer:

True

Explanation:

I am right

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