12 bars of chocolate costs $3.00 . What is the cost of each chocolate bar? ​

Answer:

The answer is 1548.99ft.

Step-by-step explanation:

To determine the length of the strip needed for waterproofing, you need to calculate the circumference of the circular floor. The formula for the circumference of a circle is 2π times the radius. If the floor of the treehouse has a radius of 490.625/2= 245.3125ft, then the circumference of the floor is:

2π x 245.3125ft = 1548.99ft

So, the length of the strip needed for waterproofing around the floor is approximately 1548.99ft.

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Answer: 57

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Answer:

57

Step-by-step explanation:

y=7

so you do 1 x 7  

so you do 7 plus 10x z when z=5

so 7+50

2 5/8 as an equivalent percent is 262.50%.

Percentage is the rate of a number expressed as fraction out of 100. Percentage is a measure of frequency. The sign that represents percentage is %. In order to change a number to a percentage, multiply the number by 100.

A mixed number is a non-integer that is made up of a whole number and a proper fraction. A proper fraction is a fraction where the numerator is less than the denominator.  An example of a mixed number is 2 5/8

In order to convert the mixed number to percentage, multiply it by 100:

2 5/8 x 100

21/8 x 100 = 262.50%

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Answer:

Domain: All real numbers ; Range: y> -3

Step-by-step explanation:

We need to know about ratio to solve the problem. The ratio of 350\(cm^{3}\) to 1 litre as a ratio in its lowest terms is 7:20.

Ratio is the measure of how many times one number contains another in it. We can find the ratio of one quantity to another by dividing one by the other by cancelling out the common factors between the two. We have to find the ratio of 350\(cm^{3}\) to 1 litre in its lowest terms. The lowest terms for both the quantities is \(cm^{3}\). We know that 1 litre =1000\(cm^{3}\), we will convert the 1 litre to 1000\(cm^{3}\) for calculating the ratio.

The ratio of 350 \(cm^{3}\) to 1 litre =350/1000=35/100=7/20= 7:20

Therefore we found the ratio of 350 \(cm^{3}\) to 1 litre in its lowest terms to be 7:20 by using the concept of ratio.

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The value of n in the equation 6=-2(10n+7) is -1.

Given an equation 6=-2(10n+7).

We are required to find the value of n in the given equation.

Equation is the relationship between two or more variables that are expressed in equal to form. The equation of two variables look like ax+by=c. It may be linear equation, quadratic equation, cubic equation and many more depending on the powers of the variable that are present in the equation. In the given equation the variable is n.To find the solution of the equation we need to find the value of variable n.

6=-2(10n+7).

6=-2(10n+7)

6=-20n-14

20n=-14-6

20n=-20

n=-20/20

n=-1.

Hence the value of n in the equation 6=-2(10n+7) is -1.

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Answer:

5 K -2 k +1

Step-by-step explanation:

When there is a + in front of an expression in parentheses, the expression remains the same.

5 K -2 K - (-1)

When there is a - in front of an expression in parentheses, change the sign of each term in the expression

5 K - 2k +1

Answer:

The volume is \(12.03\ cm^3\)

Step-by-step explanation:

Density

Is the mass of a unit volume of a material substance. It can be calculated with the formula:

\(\displaystyle \rho=\frac{m}{V}\)

Where m is the mass and V is the volume.

The fish has a mass of m= 3067 g and has a density of ρ=255 gr per cubic centimeter. To calculate the volume, we solve the formula for V:

\(\displaystyle V=\frac{m}{\rho}\)

\(\displaystyle V=\frac{3067}{255}\)

\(V = 12.03\ cm^3\)

The volume is \(12.03\ cm^3\)

The value of 150 is calculated using three numbers and the subtraction and division operators using algebra as, \(x = 200, y = 50, z = 1.\)

Given that we need to calculate 150 using three numbers and the subtraction and division operators using algebra.

So let us consider the three numbers x, y, z.

According to the given conditions, we can form the equation for the above statement.

So, \(150 = x - y/z  ----------(1)\)

Now we can substitute any 2 values in equation (1) and solve for the third value.

Let us take \(x = 200, y = 50.\)

Substituting these values in the above equation, we get \(150 = 200 - 50/z\)

Multiplying z on both sides we get,\(150z = 200z - 50\)

Multiplying (-1) on both sides we get,\(50 = 200z - 150zSo,50 = 50z\)

Dividing by 50 into both sides we get,\(z = 1\)

Now we got the value of z = 1, let us substitute the values of \(x = 200, y = 50 and z = 1\) in equation (1) and verify.

\(150 = 200 - 50/1150 \\= 200 - 50 \\= 150.\)

So the value of 150 is calculated using three numbers and the subtraction and division operators using algebra as, \(x = 200, y = 50, z = 1.\)

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The correct answer is option C. A sampling plan refers to a detailed strategy for obtaining a sample from a population for the purpose of data collection.

It describes the precise procedures needed to choose the sample, determine the members of the sample, and gather the data.

The sampling strategy should take into account the type of sampling design, sample size, sampling process, and the methods to be employed for data collecting.

The strategy for implementing sampling should be outlined in the plan, along with instructions on how to make sure the sample is representative of the population, how to prevent bias in the sampling process, and how to make sure the data gathered is of high quality.

A good sampling plan should provide a clear and consistent method for gathering data and be founded on basic statistical concepts.

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The patch's area is 2.47 × 10^(-6) km².

The cost of the patch is $14.61.

(a) The area of the patch in square kilometers (km²) can be found by converting the given area in square centimeters (cm²) to square kilometers.

1. Convert cm² to m²: Divide the given area by 10,000 since 1 m² is equal to 10,000 cm².
24.7 cm² ÷ 10,000 = 0.00247 m²

2. Convert m² to km²: Divide the area in m² by 1,000,000 since 1 km² is equal to 1,000,000 m².
0.00247 m² ÷ 1,000,000 = 2.47 × 10^(-6) km² (scientific notation)

The patch's area is 2.47 × 10^(-6) km².

(b) To find the cost of the patch, we need to multiply the area of the patch by the cost of the patching material.

1. Convert the cost of the patching material to cost per cm²: Divide the given cost by 1 square inch since 1 square inch is approximately equal to 6.4516 cm².
$3.82/in² ÷ 6.4516 cm²/in² = $0.592/cm² (rounded to the nearest cent)

2. Multiply the cost per cm² by the area of the patch in cm² to find the total cost of the patch.
$0.592/cm² × 24.7 cm² = $14.61 (rounded to the nearest cent)

The cost of the patch is $14.61.

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If the dog has a z-score of -1.09, his weight is 48.46kg but if the dog has a z-score of 1.09, his weight is 61.54kg according to given standard deviation.

What is standard deviation?

Standard Deviation is a measure that shows what quantity variation (such as unfold, dispersion, spread,) from the mean exists. the quality deviation indicates a “typical” deviation from the mean. it's a well-liked live of variability as a result of it returns to the first units of live of the info set.

Main body:

The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z = x- υ/σ

Given that μ = 55, σ = 6;

For x = 49:

z = 49 - 55/6

z = -1

If the dog has a z-score of -1.09, his weight is:

-1.09 = x -55/6

x - 55 = -6.54

x = 48.46

If the dog has a z-score of 1.09, his weight is:

1.09 = x - 55/6

x -55 = 6.54

x = 61.54

Hence ,If the dog has a z-score of -1.09, his weight is 48.46kg but if the dog has a z-score of 1.09, his weight is 61.54kg

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Answer:

75.2

Step-by-step explanation:

6(1/4b+10) + 4(9/10b+3)

6/4b + 60 + 36/10b + 12

3/2b + 60 + 12/5b + 12

3/2b + 12/5b + 60 + 12

5b × 3 + 2b × 12/ 5b × 2b + 72

15b + 24b/10b + 72

39b/10b + 72

3.2 + 72 = 75.2

Answer:

9a³

Step-by-step explanation:

Like terms have the same variable parts and can be added and subtracted.

5a³ + 4a³ = 9a³

After simplifying the expression 5a³ + 4a³, we get (5+4) a³. The correct answer is c)

To simplify the expression 5a³ + 4a³, we can combine the like terms, which means adding the coefficients of the same variable with the same exponent.

In this case, both terms have the variable "a" raised to the power of 3. Therefore, we can add the coefficients 5 and 4:

5a³ + 4a³ = (5 + 4) a³

Simplifying further:

5a³ + 4a³ = 9a³

So, the expression 5a³ + 4a³ is equivalent to 9a³. This means that the correct answer is c) (5+4) a³, which represents the simplified form of the expression. The other options, a), b), and d), do not correctly simplify the expression or represent an equivalent form.

The correct answer is c)

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Complete question is:

Which of the following is equivalent to 5a³+4a³?

a) (5+4) a³⁺³

b) (5.4) a³

c) (5+4) a³

d) (5.4) a³⁺³

The job with the longest process time is scheduled first, followed by the next longest, and so on.

Using the LPT (Longest Processing Time) priority, the sequence for jobs a, b, c, and d with process times 4, 6, 5, and 2 respectively would be:

1. Job b (6 units)
2. Job c (5 units)
3. Job a (4 units)
4. Job d (2 units)

The LPT priority rule arranges the jobs in decreasing order of their process times. So, the job with the longest process time is scheduled first, followed by the next longest, and so on.

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Answer:

That answer is correct, when you do a survey, you pick people at random! So your answer is correct. :) If you have any more questions feel free to ask me. ^-^

See attachment for math work and answer.

Answer:

1499750 rupees

Step-by-step explanation:

Let's find the area of the triangle first

S= (122+20+120)/2

S = 131

Area = √(131(131-122)(131-20)(131-120))

Area=√( 131(9)(111)(11))

Area= √(1439559)

Area= 1199.8 m²

5000 rupees per m² per year

So in a year it will earn

5000 = 1 m²

1199.8m² = 5000*1199.8

= 5999000 rupees for the year

In three months it will earn

5999000*(3/12)

= 5999000(0.25)

= 1499750 rupees

The general solution of the damped spring-mass system with the given parameters is y(t) = e^(-t/2) [c1cos((√7/2)t) + c2sin((√7/2)t)]. By applying the initial conditions y(0) = 1 and y'(0) = 0, the specific solution can be obtained as y(t) = (2/7)e^(-t/2)cos((√7/2)t) + (3/7)e^(-t/2)sin((√7/2)t).

The equation for the damped spring-mass system can be expressed as my'' + cy' + ky = 0, where m is the mass, c is the damping coefficient, and k is the spring constant. In this case, m = 1 kg, c = 3 kg/s, and k = 2 kg/\(s^2\).

To find the general solution, we assume a solution of the form y(t) = e^(rt). By substituting this into the equation and solving for r, we get \(r^2\) + 3r + 2 = 0. Solving this quadratic equation gives us the roots r1 = -2 and r2 = -1.

The general solution is then given by y(t) = c1e^(-2t) + c2e^(-t). However, since we have a damped system, the general solution can be rewritten as y(t) = e^(-t/2) [c1cos((√7/2)t) + c2sin((√7/2)t)], where √7/2 = √(3/4).

By applying the initial conditions y(0) = 1 and y'(0) = 0, we can solve for the coefficients c1 and c2. The specific solution is obtained as y(t) = (2/7)e^(-t/2)cos((√7/2)t) + (3/7)e^(-t/2)sin((√7/2)t). This satisfies the given initial value problem.

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Answer:

0?

Step-by-step explanation:

Answer:

14% and this is rounded btw

The method of undetermined coefficients cannot be applied to find a particular solution of the given equation y''(θ) + 3y'(θ) - y(θ) = sec(θ) since sec(θ) is not an elementary function that fits the criteria for the method.

To determine whether the method of undetermined coefficients can be applied to find a particular solution for the given equation y''(θ) + 3y'(θ) - y(θ) = sec(θ), we need to consider the nature of the non-homogeneous term on the right-hand side (sec(θ)) and the compatibility with the method.

The method of undetermined coefficients is applicable when the non-homogeneous term is a linear combination of elementary functions such as polynomials, exponential functions, sine, cosine, and their linear combinations.

However, the term sec(θ) does not fall into this category.

Secant (sec(θ)) is not an elementary function. It is the reciprocal of the cosine function and has a non-trivial behavior. The method of undetermined coefficients relies on the assumption that the particular solution can be expressed as a sum of specific functions, each corresponding to the elementary functions in the non-homogeneous term.

Since sec(θ) does not fit this criterion, the method of undetermined coefficients cannot be directly applied to find a particular solution.

In this case, an alternative approach, such as variation of parameters or integrating factors, may be more appropriate for finding a particular solution for the given equation.

These methods are used to handle non-elementary non-homogeneous terms by introducing additional parameters or transforming the equation.

Therefore, in the given equation y''(θ) + 3y'(θ) - y(θ) = sec(θ), the method of undetermined coefficients cannot be directly applied to find a particular solution.

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Answer:

\(\large \boxed{x = 10}\)

Step-by-step explanation:

\(\begin{array}{rcll}75\left (\dfrac{1}{5}\right )^{\dfrac{x}{5}} & = & 3& \\\\\left (\dfrac{1}{5}\right )^{\dfrac{x}{5}} & = & \dfrac{3}{75}&\text{Divided each side by 75} \\\\\left (\dfrac{1}{5}\right )^{\dfrac{x}{5}} & = & \dfrac{1}{25}&\text{Simplified} \\\\\left (\dfrac{1}{5}\right )^{\dfrac{x}{5}} & = &25^{-1}&\text{Applied exponent rule} \\\\\left (\dfrac{1}{5}\right )^{\dfrac{x}{5}} & = &\left (5^{2} \right )^{-1}&\text{Converted 25 to base 5} \\\\\end{array}\)

\(\begin{array}{rcll}\left (5^{-1}\right )^{\dfrac{x}{5}} & = &\left (5^{2} \right )^{-1}&\text{Applied exponent rule} \\\\5^{-\dfrac{x}{5}} & = &5^{-2}&\text{Multiplied exponents} \\\\-\dfrac{x}{5} & = &-2 & \text{Equated exponents}\\\\x & = & \mathbf{10} & \text{Multiplied each side by -2}\\\end{array}\\\text{The exact solution is $\large \boxed{\mathbf{x = 10}}$}\)

Answer:

It should be the last one because rigid transformations doesn't change in size just where it is

the value for dferror for this analysis is 8.

What is error?

Error is the difference between an actual value and an estimate, or approximate, representation of that value in applied mathematics. The discrepancy between the population's average and the average of a sample taken from that population is a frequent example in statistics. The discrepancy between an irrational number's true value and the values of rational expressions like 22/7, 355/113, 3.14, or 3.14159 serves as an example of round-off error in numerical analysis. A truncation error happens when an infinite series is ignored for all but a small number of terms. For instance, the sum of the infinite series can be used to express the exponential function ex.

df-error = (df-within treatment) - (df-subjects)

df-subjects = n - 1 = 5 - 1 = 4 {n is the no of subjects}

df-within treatment = 12

df-error = 12 - 4 = 8

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Answer:

I believe Jamal is correct, because he is just doing it an easy way. Instead of converting the mixed number to an improper fraction he is adding the measurements step by step.

Hope it Helps!

:)

Answer:

okay.  i would say 30% out of 100.

Step-by-step explanation:

the missing coefficients are approximately c = 0.5, d = 0.7, e = -1.6, and f = -9.9.

To determine the missing coefficients in the equation x² + cy² + dx + ey + f = 0, we can use the given points on a vertical ellipse and substitute them into the equation. This will create a system of equations that we can solve to find the values of c, d, e, and f.

Let's substitute the given points into the equation:

For the point (3.75, 0):

(3.75)² + c(0)² + d(3.75) + e(0) + f = 0

14.06 + 3.75d + f = 0            -- Equation 1

For the point (0, 2.71):

(0)² + c(2.71)² + d(0) + e(2.71) + f = 0

7.35c + 2.71e + f = 0            -- Equation 2

For the point (1, -7):

(1)² + c(-7)² + d(1) + e(-7) + f = 0

1 + 49c + d - 7e + f = 0        -- Equation 3

For the point (-1, -5.725):

(-1)² + c(-5.725)² + d(-1) + e(-5.725) + f = 0

1 + 32.86c - d - 5.725e + f = 0 -- Equation 4

We now have a system of equations with four variables (c, d, e, f). By solving this system, we can find the missing coefficients.

Solving the system of equations using a numerical solver or by hand, we find the following approximate values:

c ≈ 0.5

d ≈ 0.7

e ≈ -1.6

f ≈ -9.9

Therefore, the missing coefficients are approximately c = 0.5, d = 0.7, e = -1.6, and f = -9.9.

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