12. Cooking oil comprises of a mixture of compounds which have a boiling point range of 23°C to 27°C. i. What evidence is there to support that cooking oil is a mixture (1mk) ii. Name another experimental technique that could be used to confirm your answer in part (i) above (1mk)​

Answer:

a liquid which has passed through a filter.

Explanation:

Filtration is a physical separation process that separates solid matter and fluid from a mixture using a filter medium that has a complex structure through which only the fluid can pass

Wascana Chemicals should use emissions reduction technologies to reduce the amount of sulphur dioxide emitted during paint production.

To comply with the Ministry of Environment's directive, Wascana Chemicals, a paint manufacturer, needs to reduce the amount of sulphur dioxide released during paint production. This can be accomplished through the use of emissions reduction technology, such as scrubbers, catalytic converters, or gasification systems.Scrubbers are devices that use a wet process to remove pollutants from gas streams. The gas stream is forced through a scrubbing solution that traps pollutants, including sulphur dioxide.Catalytic converters, on the other hand, use a chemical process to transform pollutants into less harmful substances. Gasification systems convert solid or liquid materials into a gas, which can be combusted to generate energy.

In conclusion, to comply with the Ministry of Environment's emissions reduction regulations, Wascana Chemicals should consider implementing one or more emissions reduction technologies such as scrubbers, catalytic converters, or gasification systems to reduce the amount of sulphur dioxide emitted during paint production.

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Approximately 12.45 grams of solid silver chromate will precipitate when 150 mL of 0.500 M silver nitrate solution is added to excess potassium chromate.

To determine the number of moles of AgNO3 present in 150 mL of a 0.500 M AgNO3 solution, we can use the formula:

moles = concentration × volume

Given:

Concentration of AgNO3 solution = 0.500 M

Volume of AgNO3 solution = 150 mL

First, we need to convert the volume from milliliters (mL) to liters (L) since the concentration is given in moles per liter (M).

1 L = 1000 mL

Therefore, the volume of the AgNO3 solution in liters is:

150 mL × (1 L / 1000 mL) = 0.150 L

Now we can calculate the moles of AgNO3 using the formula:

moles = concentration × volume

moles = 0.500 M × 0.150 L

moles = 0.075 mol

So, there are 0.075 moles of AgNO3 present in 150 mL of the 0.500 M AgNO3 solution.

Now, let's proceed to determine how many grams of solid silver chromate (Ag2CrO4) will precipitate when the AgNO3 solution reacts with excess potassium chromate (K2CrO4).

From the balanced chemical equation:

2AgNO3(aq) + K2CrO4(aq) → Ag2CrO4(s) + 2KNO3(aq)

We can see that the molar ratio between AgNO3 and Ag2CrO4 is 2:1. Therefore, for every 2 moles of AgNO3, we will form 1 mole of Ag2CrO4.

Since we have 0.075 moles of AgNO3, we can calculate the moles of Ag2CrO4 formed:

moles of Ag2CrO4 = 0.075 mol / 2 = 0.0375 mol

To determine the mass of Ag2CrO4, we need to multiply the moles by its molar mass. The molar mass of Ag2CrO4 is calculated by summing the atomic masses of each element in the compound:

Ag2CrO4 = 2(Ag) + 1(Cr) + 4(O) = 2(107.87 g/mol) + 1(52.00 g/mol) + 4(16.00 g/mol) = 331.87 g/mol

mass of Ag2CrO4 = moles of Ag2CrO4 × molar mass of Ag2CrO4

mass of Ag2CrO4 = 0.0375 mol × 331.87 g/mol = 12.45 g

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Answer:

The atoms are vibrating in place.

Explanation:

One of the properties of an ionic substance is the possession of a crystalline structure. As Gerry observed the salt under a microscope, he discovered that it has a crystalline structure. Crystalline salts are all ionic in nature, hence the salt observed by Gerry is an ionic salt.

Solids containing a definite crystalline structure always has their particles vibrating in place. This is immediately evident as Gerry looks at the salt through a microscope.

Answer:

D.The atoms are vibrating in place

Explanation:

The bond energy per mole for breaking all the bonds of oxygen (O2) can be calculated by considering the energy required to break each individual bond.

Oxygen gas (O2) consists of a double bond between two oxygen atoms. The bond energy represents the energy required to break this bond. The average bond energy for an O-O bond in oxygen is approximately 498 kilojoules per mole (kJ/mol).

Since there are two O-O bonds in O2, the total bond energy per mole for breaking all the bonds of oxygen can be calculated by multiplying the bond energy by the number of bonds, resulting in approximately 996 kJ/mol. This represents the energy needed to completely break apart all the O-O bonds in one mole of oxygen molecules.

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The chemical progressively cools after heating. Another illustration of a substance is water..

What is specific heat, precisely?

The amount of energy required to elevate the temperature of 1 kilogram of a substance by 1 degree Celsius (°C) is known as specific heat. Since water has a higher specific heat than other substances, it requires more energy to raise its temperature.

In plain English, what's really specific heat capacity?

A pure substance's heating value per unit mass is referred to as its heat capacity, or just specific heat. It is represented in terms of J/kgK or, more accurately, J/kg°C and therefore is described as the amount of warmth required to raise the temperature pf 1 kg of a substance by 1 K.

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Answer:a mouse

Explanation:

Answer: a mouse

Explanation:

The oxidative step of the citric acid cycle that is not linked to the reduction of nad is the reaction catalyzed by isocitrate dehydrogenase.

What is  citric acid cycle?

C6H8O7 is the chemical formula for citric acid, a weak acid. Both monohydrate and water-free forms are possible for it (anhydrous). Citrus fruits including lemons, oranges, and others typically contain this acid. Tribasic acids are thought to be what it is. It appears as a white crystalline solid, has no smell, and a sour flavour.

What is reduction ?

An increase in the number of electrons linked to an atom or group of atoms is the definition of a reduction, which includes all chemical reactions in the reduction class. To provide the electrons that are absorbed by the reduced molecule, a different substance is oxidised. Identify the oxidation-reduction reaction.

Therefore the oxidative step of the citric acid cycle that is not linked to the reduction of nad is the reaction catalyzed by isocitrate dehydrogenase.

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Answer:

Fahrenheit and Celsius

Explanation:

A battery is a device that converts chemical energy into electrical energy through a process known as an electrochemical reaction.

When a battery is connected to a circuit, the electrochemical reaction causes a flow of electrons from the anode to the cathode, generating an electric current that can power a device.

The metal chosen for the anode must be capable of losing electrons easily, while the metal chosen for the cathode must be capable of accepting electrons. The choice of metals can also affect the voltage and capacity of the battery, as well as its overall efficiency.

In general, the metals used in a battery should have a large difference in their electronegativity values, which determines how easily an atom can attract electrons. Common metals used in batteries include zinc, lithium, nickel, and cadmium.

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The specific heat capacity of water is 4.18 J/(g K) and the given amount of water is more than 100 grams. We need to calculate the energy absorbed by the water to reach boiling point when 5.39 × 10^5 J of heat is supplied.

The amount of water used is not provided in the question, therefore, let's first calculate the energy required to raise the temperature of 100g of water from room temperature (25°C) to its boiling point (100°C) using the formula,Q = m × c × ΔTwhere,Q = energy absorbedm = mass of waterc = specific heat capacity of waterΔT = change in temperature of water= 100 - 25 = 75°C (since the water is heated until it just begins to boil)Thus,Q = \(100 g × 4.18 J/(g K) × 75°C= 31350 J= 31.35 kJ\) of energy is required to heat 100g of water from 25°C to 100°C.

Now, let's determine the mass of water using the amount of heat energy supplied:Q =\(m × c × ΔT, where Q = 5.39 × 10^5 Jm = Q / (c × ΔT)= 5.39 × 10^5 J / (4.18 J/(g K) × 75°C)= 204.55 g\)(approx.)Therefore, more than 100 g of water is required to absorb 5.39 × 10^5 J of heat to reach its boiling point.

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Answer:

Explanation: 11

Answer:

a

Explanation:

Answer: 121.2416 psi

Explanation:

Answer: 32P labeled DNA only; 35S labeled protein only.

Explanation: Not requested.

Answer:

\(T1=166.66K\)

Explanation:

According to Gay-Lussac’s law simply states that the ratio of the initial pressure and temperature is equal to the ratio of the final pressure and temperature for a gas of a fixed provided that the mass is kept at a constant volume.

Given:

Initial pressure, P1 = 1 atm

Final pressure, P2 = 1.5 atm

Final temperature, T2 = 250 K

The law can be applied using the below formula

P1T2 = P2T1

Then,

T1 = (P1T2)/P1 = (1*250)/(1.5) = 166.66 Kelvin.

\(T1=166.66K\)

:

Answer:

\(T_1=166.7K\)

Explanation:

Hello,

In this case, by applying the Gay-Lussac's law which help us to understand the pressure-temperature gas behavior via a directly proportional relationship:

\(\frac{P_1}{T_1} =\frac{P_2}{T_2}\)

In such a way, as we are asked to compute the initial temperature knowing the initial pressure and final both temperature and pressure, so we solve for it:

\(T_1=\frac{T_2P_1}{P_2}=\frac{250K*1atm}{1.5atm} \\\\T_1=166.7K\)

Best regards.

There are 1.8  × \(10^{24}\) atoms present in 2 mole of water molecule.

A mole is the mass of such a substance that includes 6.023 × \(10^{23}\) of that substance's particles. The mole would be the SI unit used to measure a substance's quantity. It has the symbol mol.

It is known that,

one mole = 6.02 × \(10^{23}\)atoms.

The chemical formula of water is \(H_{2}O\). There are 2 hydrogen atom and 1 oxygen atom present in water molecule. Total 3 atom present in water.

2 mole of water = 3 × 6.02 × \(10^{23}\)atoms = 1.8  × \(10^{24}\) atoms.

Therefore, 1.8  × \(10^{24}\) atoms present in 2 mole of water molecule.

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The pH at the half-stoichiometric point for this titration is approximately 3.37.

The half-stoichiometric point is the point in the titration where exactly half of the acid has reacted with the base. In this case, the balanced chemical equation for the reaction is:

HNO2 + KOH → KNO2 + H2O

The stoichiometry of the reaction is 1:1, meaning that 1 mole of HNO2 reacts with 1 mole of KOH. Therefore, at the half-stoichiometric point, 0.11 moles of HNO2 have reacted with 0.11 moles of KOH.

To calculate the pH at this point, we need to first calculate the concentration of HNO2 remaining in solution. The initial concentration of HNO2 is 0.22 M, and at the half-stoichiometric point, half of it has reacted, leaving 0.11 M remaining.

To calculate the pH, we can use the acid dissociation constant (Ka) for HNO2:

Ka = [H+][NO2-]/[HNO2]

At the half-stoichiometric point, we can assume that all of the HNO2 has dissociated, so:

Ka = [H+][NO2-]/(0.11)

Solving for [H+], we get:

[H+] = sqrt(Ka*[HNO2]) = sqrt(4.3E-4 * 0.11) = 0.0125 M

Using the pH formula, pH = -log[H+], we can calculate the pH:

pH = -log(0.0125) = 1.90

Therefore, the pH at the half-stoichiometric point for the titration of 0.22 M HNO2 with 0.01 M KOH is 1.90.

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The pH at the half-stoichiometric point for this titration is approximately 3.37.

The half-stoichiometric point is the point in the titration where exactly half of the acid has reacted with the base. In this case, the balanced chemical equation for the reaction is:

HNO2 + KOH → KNO2 + H2O

The stoichiometry of the reaction is 1:1, meaning that 1 mole of HNO2 reacts with 1 mole of KOH. Therefore, at the half-stoichiometric point, 0.11 moles of HNO2 have reacted with 0.11 moles of KOH.

To calculate the pH at this point, we need to first calculate the concentration of HNO2 remaining in solution. The initial concentration of HNO2 is 0.22 M, and at the half-stoichiometric point, half of it has reacted, leaving 0.11 M remaining.

To calculate the pH, we can use the acid dissociation constant (Ka) for HNO2:

Ka = [H+][NO2-]/[HNO2]

At the half-stoichiometric point, we can assume that all of the HNO2 has dissociated, so:

Ka = [H+][NO2-]/(0.11)

Solving for [H+], we get:

[H+] = sqrt(Ka*[HNO2]) = sqrt(4.3E-4 * 0.11) = 0.0125 M

Using the pH formula, pH = -log[H+], we can calculate the pH:

pH = -log(0.0125) = 1.90

Therefore, the pH at the half-stoichiometric point for the titration of 0.22 M HNO2 with 0.01 M KOH is 1.90.

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We know the standard reduction potentials of the half-cells involved, so we can find the cell voltage and the spontaneous reaction. Thus;

The anode reaction is:

Pb(s) → Pb2+(aq) + 2e-

This is the oxidation half-reaction that occurs in the Pb half-cell.

The cathode reaction is:F2(g) + 2e- → 2F-(aq).

This is the reduction half-reaction that occurs in the F2 half-cell.

The spontaneous cell reaction is

:Pb(s) + F2(g) → Pb2+(aq) + 2F-(aq).

This is the combination of the oxidation and reduction half-reactions, with the electrons canceled out from both sides.

The cell voltage is 2.996 V The standard cell potential is calculated as follows:

standard cell potential = E°(reduction) - E°(oxidation)standard cell potential = 2.870 V - (-0.126 V)standard cell potential = 2.996 V, The cell voltage is positive, indicating that the reaction is spontaneous.

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The ground pressure on that condition will be 1.4 Atm. The condition of that space is isotherms, to solve it we use Boyle's law in isotherms condition.

To solve this problem we are using Boyle's law. As Boyle's law state that " a gas's pressure and volume are inversely proportional" which is formulated as  P1 x V1 = P2 x V2. As per data given: early volume(V1) = 735 mL; pressure(P2) = 0.8 atm; and volume(V2) = 1286 mL. The calculation will be:

P1 x V1 = P2 x V2

P1 x 735 = 0.8 x 1286

P x 735 = 1028.8

P = 1.4 Atm

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Answer: The elements in Groups 2,15,16 and 17 of the Periodic Table are called alkali metals. They form ionic compounds when they react with non-metals. Their ions have a single positive charge. For example, sodium forms sodium ions, Na+

Explanation:

hope you understood

Option a. CH3CH2Br would react the fastest with OH⁻ in the SN2 reaction.

The reactivity in SN2 (substitution nucleophilic bimolecular) reactions follows the trend: CH3X < 1° < 2° < 3°, where X represents the halogen atom. This trend is based on the steric hindrance experienced by the nucleophile and the stability of the transition state.

In the given options, the alkyl halides are arranged in increasing order of alkyl group substitution:

a. CH3CH2Br (1°)

b. CH3CH2Cl (1°)

c. CH3CH2F (1°)

d. CH3CH2I (1°)

According to the reactivity trend, the fastest reaction with OH⁻ in the SN2 mechanism will be observed with the least substituted alkyl halide, which is CH3CH2Br (option a). It is a primary (1°) alkyl halide and has the least steric hindrance, allowing the nucleophile to attack the carbon atom easily.

Therefore, option a. CH3CH2Br would react the fastest with OH⁻ in the SN2 reaction.

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To make a buffer with a pH of 4.5 using acetic acid, we need to add 42.5 mL of 0.1 M acetic acid and 57.5 mL of 0.1 M sodium acetate.

We can convert an aqueous solution containing 0.26 M ammonium perchlorate into a buffer by adding a weak acid and its conjugate base.

One example of a weak acid that can be added is acetic acid, which has a Ka value of 1.8 x 10^-5.

Assuming we want to make a 1 L buffer with a pH of 4.5, we need to add 42.5 mL of 0.1 M acetic acid and 57.5 mL of 0.1 M sodium acetate.

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Answer:

saturated

Explanation:

It is not dense enough to be supersaturated.

Answer:

unsaturated

Explanation:

salts arent fatty

The question is incomplete, the complete question is;

As Danny was pouring cereal for his breakfast, he noticed that the cereal box says that the cereal contains 5 milligrams of iron per serving. Danny decided to perform an experiment to test this claim. He found that the cereal contains 4.6 milligrams of iron per serving. Based on Danny's measurement, the value reported on the label is ( CORRECT OR INCCORECT) because A: (IT IS DIFFERENT FROM THE VALUE DANNY MEASURED) B: (IT IS REORTED TO THE NEAREST MILLIGRAM) C: (IT USES THE SAME UNITS THAT DANNY USED).

Answer:

CORRECT because IT IS REORTED TO THE NEAREST MILLIGRAM

Explanation:

In mathematics, values may be rounded up or down as required. In the case of this measurement of cereals by Danny, it is customary to measure the amount of iron per serving to the nearest milligram.

As such, even though Danny found out that the actual amount of iron per serving in the cereal is 4.6 milligrams, the value reported on the cereal box is still correct because it was reported to the nearest milligram hence the value had to be rounded up.