Carrie walks 525 feet from her house to jay's house. Then, she walks another 280 feet to asha's house.
Answer:
\(Total = 805ft\)
Step-by-step explanation:
Given
\(Jay's = 525ft\)
\(Asha's = 280ft\)
Required [Missing from the question]
The total distance walked
To do this, we simply add up the distance walked to Jay's and then to Asha's house.
So, we have:
\(Total = Jay's + Asha's\)
\(Total = 525ft + 280ft\)
\(Total = 805ft\)
DONT ANSWER IF YOU SEND LINKS OR NOT CORRECT ANSWERS
Answer: I don’t know I haven’t learned it yet
Step-by-step explanation:
Happy halloween
Please help solve this! Thank you in advance!
4) a) Expand the function f =y' x + x'z with respect to a) x b) y c) z = b) Design the function for each case by using only 2-to-1 multiplexer
The expansion of the function f = y'x + x'z with respect to x yields (x + y')(x + z'), and the expansion with respect to y gives (x' + y)(x + z').
(a) To expand the function f = y'x + x'z with respect to x, we use the distributive property and apply De Morgan's law to simplify the expression:
f = y'x + x'z
= x'y + x'z
= (x'y)'(x'z)' [Using De Morgan's law]
= (x + y')(x + z') [Using De Morgan's law again]
(b) Designing the function using a 2-to-1 multiplexer for the case of expanding f with respect to x involves using the inputs x, y, and z as the select lines of the multiplexer. The inputs x + y' and x + z' will be connected to the data inputs of the multiplexer, and the output of the multiplexer will be the expanded function f.
(c) Similarly, for expanding f with respect to y, the expansion is:
f = y'x + x'z
= xy' + x'z
= (xy')'(x'z)' [Using De Morgan's law]
= (x' + y)(x + z') [Using De Morgan's law again]
For this case, the inputs x', y, and z will serve as the select lines of the 2-to-1 multiplexer. The inputs x' + y and x + z' will be connected to the data inputs, and the output of the multiplexer will represent the expanded function f.
In both cases, the 2-to-1 multiplexer is used to implement the logic function by selecting the appropriate data inputs based on the select lines, which are derived from the expansion of the function with respect to the corresponding variable.
In conclusion, the expansion of the function f = y'x + x'z with respect to x yields (x + y')(x + z'), and the expansion with respect to y gives (x' + y)(x + z'). By utilizing 2-to-1 multiplexers, the expanded functions can be designed by connecting the appropriate data inputs to the multiplexer based on the select lines derived from the expansions. This allows for the implementation of the logic functions using multiplexers, providing a compact and efficient circuit design.
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Use your understanding of transformations and key features to write the slope intercept equation of this linear function enter the correct answer in the box by replacing the values of M and B
f(x) = -2x + 5 is the slope intercept form for the given linear function.
Slope: Slope of a line is the ratio of change in the y factor to the change in x factor.
y-intercept: It the point where the line crosses the y-axis.
The slope intercept form is:
f(x) = Mx + B
Slope, M = \(\frac{y_2 - y_1}{x_2 - x_1}\)
where,
M = -2 (slope of the graph)
B = 5 (y-intercept in the graph)
The graph of the equation f(x) = -2x + 5 has a negative slope which has a value of -2 means it is decreasing at a constant rate of -2.
The line in the graph has 5 as its y-intercept.
The given linear function has been reflected across the x-axis (multiplied by -1), vertically stretched by a factor of 2 (multiplied by 2), and vertically translated up 5 units (5 added to it).
Therefore, the slope-intercept form of the given linear function is
f(x) = -2x + 5.
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Halp easy points Brainliest to correct answer
Answer:
10n²-3n-18
Step-by-step explanation:
Simple it's expanding brackets:
(2n-3)(5n+6) =
2n×5n = 10n²2n×6 = 12n-3×5n = -15n -3×6 = -1810n²+12n-15n-18 =
10n²-3n-18
This is our final answer
Hope this helped and have a good day
Answer:
10n²-3n-18
Step-by-step explanation:
(2n-3)(5n+6)
Split the first bracket, and multiply each term by the entirety of the second bracket:
2n (5n+6) - 3 (5n+6)
Now multipy:
10n² +12n - 15n -18
10n²-3n-18
A parking garage has 230 cars in it when it opens at 8 ( = 0). On the interval 0 ≤ ≤ 10, cars enter the parking garage at the rate ′ () = 58 cos(0.1635 − 0.642) cars per hour and cars leave the parking garage at the rate ′ () = 65 sin(0.281) + 7.1 cars per hour (a) How many cars enter the parking garage over the interval = 0 to = 10 hours? (b) Find ′′(5). Using correct units, explaining the meaning of this value in context of the problem. (c) Find the number of cars in the parking garage at time = 10. Show the work that leads to your answer.
Therefore, (a) ∫58cos(0.1635t - 0.642)dt from 0 to 10 gives approximately 822.6 cars, (b) ′′(5) = -65cos(0.281) which is approximately -62.4 cars per hour per hour, (c) Approximately 559 cars in the garage at t = 10.
(a) To find the number of cars entering the parking garage over the interval 0 ≤ t ≤ 10, we need to integrate the rate of cars entering the garage with respect to time. ∫58cos(0.1635t - 0.642)dt from 0 to 10 gives approximately 822.6 cars.
(b) To find ′′(5), we need to differentiate the rate of cars leaving the garage with respect to time twice. ′′(t) = -65cos(0.281) and ′′(5) = -65cos(0.281) which is approximately -62.4 cars per hour per hour. This value represents the rate of change of the rate of cars leaving the garage at t = 5.
(c) To find the number of cars in the parking garage at time t = 10, we need to subtract the total number of cars leaving the garage from the total number of cars entering the garage from t = 0 to t = 10. This gives approximately 559 cars in the garage at t = 10.
Therefore, (a) ∫58cos(0.1635t - 0.642)dt from 0 to 10 gives approximately 822.6 cars, (b) ′′(5) = -65cos(0.281) which is approximately -62.4 cars per hour per hour, (c) Approximately 559 cars in the garage at t = 10.
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what is the length of the hypotenuse if it's 8m and 15m?
In this case the answer is very simple. .
Step 01:
Data
side a = 8m
side b = 15m
c = hypotenuse = ?
Step 02:
Pythagoras Theorem Formula
Hypotenuse² = Perpendicular² + Base²
c² = a² + b²
c ² = (8m)² + (15m)²
c ² = 64m² + 225m²
c ² = 289m²
\(undefined\)pls help me with this i have a 0 in math
Answer:
(3−5)(+1)
Step-by-step explanation:
I hope this helps you and please mark me as brainliest
Answer:
The answer is ( p + 1 ) ( 3p - 5 )
Step-by-step explanation:
Here is a sequence
5, 10, 20, 40, 80
a) What is the term-to-term rule of the sequence?
b) The 10th term in the sequence is 2560.
What is the 11th term in the sequence?
Answer:
5120
Step-by-step explanation:
....80,160,320.... 2560
You are multiplying by 2 each time.
true or false: the diagonals of a rectangle bisect opposite angles
Answer:
False
Step-by-step explanation:
diagonals don't have to be congruent or bisect each other. The diagonals of a rectangle bisect its angles.
PLZ HELP ASAP :( I need to show work and this is my very last assignmenttt
(part 2)
Answer:
3. 60°
4. 378.542
Step-by-step explanation:
in the picture
give answer plzzz fast...
it's very important for me...
Answer:
the required answers will be
a) -48b) -3c) 72d) 2Step-by-step explanation:
for explanation see the attached picture
okay
4b+9b simplified version
Answer:
13b
Step-by-step explanation:
Add 4b and 9b together because they are like terms,
so 4b + 9b = 13b
Answer:
13b
Step-by-step explanation:
4b+9b
Combine like terms
13b
simpifly this expression, i only need answer b :)
Answer:
1) x³y²
2) 6x²y³
Step-by-step explanation:
hope it helps...
Marty's class collected $10.00 in a school-wide penny collection contest. If Tommy's class subtracted $4.00 from the amount they collected, x, and then multiplied the difference by 2, they would have the same amount of money as Marty's class.
How much money did Tommy's class collect?
A.
$9.00
B.
$13.00
C.
$4.00
D.
$17.00
PLEASE ANSWER I WILL GIVE BRAINLIEST AND IT IS WORTH 35 POINTS
1. if c is 54 and d is 48 find k
2. if a is 52 and k is 22 find d
3. if c is 25 and k is 18 find a
4. if k is 15 find w
5. if w is 19 find k
1. if c is 54 and d is 48; k = -11.11%
2. if a is 52 and k is 22; d = 66.67
3. if c is 25 and k is 18; a = 16.81
4. if k is 15; w = 0.7225
5. if w is 19; k = 56.4%
How to solve percentages?Percentage refers to the fraction of a number that is expressed as a number out of hundred. The sign used to represent percentages is %.
1.
k = (d/c - 1) × 100
= (48/54 - 1) × 100
k = -11.11%
2.
d = a/(1 - k%)
= 52/(1-22%)
= 52/0.78
= 66.67
3.
d = (1 - 0.18) x 25
= 20.50
a = (1 - 0.18) x 20.50 = 16.81
4.
w = (1 - 0.15) x (1-0.15)
= 0.85 x 0.85
= 0.7225
5.
k = (1 - √0.19) × 100
= 56.4%
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For each of the following operators and transforms, check if it's linear:
1. derivative, i.e., L[y]=y′,
2. second derivative, i.e., L[y]=y′′
1. The derivative operator is linear. The derivative operator, denoted as L[y] = y', is a linear operator.
2. The second derivative operator is also linear. The second derivative operator, denoted as L[y] = y'', is also a linear operator.
1. The derivative operator, denoted as L[y] = y', is a linear operator. This means that it satisfies the properties of linearity: scaling and additivity. For scaling, if we multiply a function y(x) by a constant c and take its derivative, it is equivalent to multiplying the derivative of y(x) by the same constant. Similarly, for additivity, if we take the derivative of the sum of two functions, it is equivalent to the sum of the derivatives of each individual function.
2. The second derivative operator, denoted as L[y] = y'', is also a linear operator. It satisfies the properties of linearity in the same way as the derivative operator. Scaling and additivity hold for the second derivative as well. Multiplying a function y(x) by a constant c and taking its second derivative is equivalent to multiplying the second derivative of y(x) by the same constant. Similarly, the second derivative of the sum of two functions is equal to the sum of the second derivatives of each individual function. Thus, the second derivative operator is linear.
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Which of the following is not included in the cost of merchandise inventory? O Purchase discounts. O Purchase returns and allowances. O Purchase price of the inventory. O Freight costs paid by the seller. O Freight costs paid by the buyer. 4 pts 0 Question 2 Sunshine Cleaning purchased $3,500 worth of merchandise. The seller offered a 2% cash discount. Transportation costs for the buyer were an additional $310. The company returned $240 worth of merchandise and then paid the invoice within the discount period. The total cost of this merchandise is: O $3.570.00. O $3,500.00 O $3,332.00 O $3,430.00. $3,504.80 Question 5 A company has not sales of $759.300 and cost of goods sold of $548.300. Its not income is $10.280. The company's gross margin and operating expenses, respectively, are: O $211.000 and $230,750 $739.550 and $191,720 O $529,020 and $230.750 O $211.000 and $191,720 $230,750 and $529,020 4 pts D D Question 5 A company has not sales of $750,300 and cost of goods sold of $548,300. Its not income is $10.280 The company's groas margin and operating expenses, respectively, arm O $211,000 and $230,750 O $739,550 and $191,720 $529,020 and $230,750 O $211.000 and $191,720 O $230.750 and $529,020 Question 6 Sales less sales discounts, less sales returns and allowances equals: Cost of Goods Sold Net Income O Net Sales O Gross Profit 4 pts 4 pts Goods in transit are included in a purchaser's inventory: O At any time during transit. O After the half-way point between the buyer and seller, When the supplier is responsible for freight charges. When the goods are shipped FOB shipping point. OIf the goods are shipped FOB destination. Question 11 The inventory costing method that smooths out erratic changes in costs is: O LCM. O FIFO. OLIFO. O Specific Identification. O Weighted average. 4 t ne 0 Question 12 Krusty Krab has the following products in its ending inventory Compute lower of cost or market for inventory. applied separately to each product Inventory by Product Product Quantity Cost per Unit 500 $ 500 $ 30 600 Scuba Masks Scuba Sults O $265,000 O $290,000. O $250,000 $268,000 O $275,000. Question 13 Market per Unit $ 550 $ 25 If equity is $368,000 and liabilities are $186,000, then assets equal: O $554,000. $922,000. $368,000. $186,000. O $182,000. 2 pts
Question 1: The item not included in the cost of merchandise inventory is "Purchase discounts."
2: The total cost of the merchandise is $3,332.00.
5: The company's gross margin and operating expenses, are $211,000 and $191,720.
What is the cost of merchandise inventory?Merchandise inventory expenses normally consist of the price paid for the inventory, deductions from the purchase price resulting from purchase returns and allowances, and freight expenses paid by the purchaser.
Although purchase discounts reduce the cost of merchandise inventory, they are not considered part of it. Instead, they are treated as a distinct discount in the accounting records.
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how many eighth size parts do you need to model 3/4
Answer:
You need 6, 1/8 parts to make 3/4
Step-by-step explanation:
The answer is 6 because 1/8 multiplied by 6 is 6/8 and 6/8 simplified is 3/4
6/8ths is the correct answer
bruh
How many weeks are there a month?
Answer:
4 weeks
Step-by-step explanation:
Answer:
About 4 weeks
Step-by-step explanation:
If an undamped spring-mass system with a mass that weighs 24 lb and a spring constant 4 lb/in is suddenly set in motion at t=0 by an external force of 108 cos(4t) lb, determine the position of the mass at any time. Assume that g=32 ft/s2. solve for u in feet.
u(t)=
The position of the mass in the undamped spring-mass system can be represented by the equation u(t) = (A cos(ωt) + B sin(ωt)) / k. Therefore, position of the mass at any time t in feet is given by u(t) = 4.5 cos(4t).
In this case, the external force acting on the system is 108 cos(4t) lb. To determine the position of the mass, we need to solve the differential equation that represents the motion of the system.
Using Newton's second law, F = ma, and considering that the mass m = 24 lb, the equation becomes:
24 * d^2u/dt^2 = 108 cos(4t)
Simplifying, we have:
d^2u/dt^2 = 4.5 cos(4t)
This is a second-order linear homogeneous differential equation with a constant coefficient. The solution to this equation will be a linear combination of the homogeneous and particular solutions.
The homogeneous solution, representing the free oscillation of the system, is u_h(t) = C1 cos(2t) + C2 sin(2t).
The particular solution, representing the forced motion caused by the external force, can be assumed in the form u_p(t) = A cos(4t) + B sin(4t).
By substituting u_p(t) into the differential equation, we can determine the values of A and B.
Solving the differential equation for the particular solution, we find:
A = 18 and B = 0
The complete solution for the position of the mass in feet is:
u(t) = (18 cos(4t)) / 4
Simplifying further, we get:
u(t) = 4.5 cos(4t)
Therefore, the position of the mass at any time t in feet is given by u(t) = 4.5 cos(4t).
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3. Patrick kicks a soccer ball from the ground into the air. When the ball is a horizontal distance of 12 feet from
him, it is 14 feet above the ground. When the ball is 32 feet from him, it is 7 feet above the ground.
Use quadratic regression on a graphing calculator to write a function for the height of the ball in terms of
its horizontal distance Round to the nearest thousandth (
Answer:
The function for the height of the ball in terms of its horizontal distance is
\(y = -\frac{91}{1920}\cdot x^{2}+\frac{833}{480}\cdot x\)
Step-by-step explanation:
From Physics, we know that ball describes a parabolic motion, in which trajectory is described by the following second-order polynomial (quadratic function):
\(y = a\cdot x^{2}+b\cdot x + c\) (Eq. 1)
Where:
\(x\) - Horizontal distance, measured in feet.
\(y\) - Vertical distance above the ground, measured in feet.
\(a\) - Second order coefficient, measured in \(\frac{1}{ft}\).
\(b\) - First order coefficient, dimensionless.
\(c\) - Zero order coefficient, measured in feet.
We can obtain the second-order polynomial associated with the soccer ball by knowing three distinct points and solving the resulting system of linear equations. If we know that \((x_{1},y_{1}) =(0\,ft, 0\,ft)\), \((x_{2},y_{2})=(12\,ft, 14\,ft)\) and \((x_{3},y_{3})=(32\,ft, 7\,ft)\), then the system of linear equations is:
\(c = 0\)
\(144\cdot a+12\cdot b +c = 14\)
\(1024\cdot a +32\cdot b + c = 7\)
The solution of this linear system is:
\(a = -\frac{91}{1920}\), \(b = \frac{833}{480}\), \(c = 0\)
Therefore, the function for the height of the ball in terms of its horizontal distance is
\(y = -\frac{91}{1920}\cdot x^{2}+\frac{833}{480}\cdot x\)
In addition, we present a graphic of the given function as attachment.
find the distance between the points T(13,1.6) and V(5.4, 3.7)
Answer:
7.884
Step-by-step explanation:
so taking the point T(13,1.6) and the point V(5.4,3.7) we move from point T(13,1.6) to the point V(5.4,3.7) the x-coordinate increases by ( 13-5.4)=7.6 and the y- coordinate decreases by ( 1.6-3.7)=(-2.1). now we have 7.6 and -2.1. we find the squares of this numbers and add so we have 7.6 giving us 57.76 and -2.1 giving us 4.41. now we add both 57.76+4.41=62.17. and we find the square roots √62.17 which will give us 7.884. and therefore the distance between the two point is 7.884
find the number of different ways that 570 contestants can win different first, second and third prizes.
184,219,440 ways.
What is contestant?
A participant in a contest or competition is known as a contestant. A contestant is someone who challenges election results.
There are 570 contestants, and any one of them can win the first prize.
One of the remaining 569 people can receive the second prize.
Third may be assigned to any of the remaining 568.
We can accomplish this in 570*569*568 ways
= 184,219,440 ways.
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help me please and thank you
Answer:
x = 68
Step-by-step explanation:
17/ 30 = x / 120
To get from 30 to 120 in the denominator, we multiply by 4
30*4 = 120
We must do the same in the numerator
17 * 4 = 68
x = 68
Let L: R² R² be a linear operator. If L((1,2)) = (-2,3), and L((1,-1)²) =(5,2),+ Find the value of L((7,8)¹) 799
L((7,8)) = (-9,23). To find the value of L((7,8)), we can use the linearity property of the linear operator L.
Since L is a linear operator, we can express any vector in R² as a linear combination of the basis vectors (1,0) and (0,1).
We have L((1,2)) = (-2,3) and L((1,-1)) = (5,2). Therefore, we can express (7,8) as (7,8) = 7(1,2) + 1(1,-1).
Using the linearity property, we can distribute the linear operator L over the linear combination:
L((7,8)) = L(7(1,2) + 1(1,-1))
= 7L((1,2)) + L((1,-1))
= 7(-2,3) + (5,2)
= (-14,21) + (5,2)
= (-9,23)
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A 50-foot flagpole near an office building casts a shadow
that is 12.5 feet long. At the same time, the office building
casts a shadow that is 50 feet long. How tall is the office
building?
Step-by-step explanation:
Here are some hints: "At the same time,"means you need to set up a proportion (two ratios equal each other).
The shadow is always on the ground.
A person and a flagpole always stands up straight, like a wall (vertical height)
Underline key words and numbers. Draw a picture for sure.
|
|X 5.5 ft. |
|____________ |____
flagpole=50 feet person's shadow=4 feet
shadow
Since it is easier to work with one type of measurement, change the person's height to feet only. The person is 5feet, 6inches Note: 12 inches= 1 foot, so 6 inches= 1/2 a feet and 6 inches= .5 feet
the x-coordinate of the point where a
graph intersects the x-axis
Looking for word for detention
integrate the approximation sin(t) ≈ t − t36 t5120 − t75,040 evaluated at t to approximate 10sin(t)t dt. (round your answer to six decimal places.)
The approximation of ∫10sin(t)t dt is 5.000018, rounded to six decimal places.
Using the given approximation, we have:
sin(t) ≈ t − t^3/6 + t^5/120 − t^7/5040
Multiplying both sides by t and integrating from 0 to 10, we get:
∫0^10 sin(t) t dt ≈ ∫0^10 (t^2/1! − t^4/3! + t^6/5! − t^8/7!) dt
Using the power rule of integration, we get:
∫0^10 sin(t) t dt ≈ [t^3/3! − t^5/5! + t^7/7! − t^9/9!]0^10
Substituting the limits of integration and simplifying, we get:
∫0^10 sin(t) t dt ≈ (10^3/3! − 10^5/5! + 10^7/7! − 10^9/9!)/6
Calculating the numerical value using a calculator, we get:
∫0^10 sin(t) t dt ≈ 5.000018
Therefore, the approximation of ∫10sin(t)t dt is 5.000018, rounded to six decimal places.
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Please answer (IN school) 32.4-0.78
Answer: 31.62
Step-by-step explanation: