(12y+2x)+4y
A. 20x+8y
B. 16y+2x
C. 19x+4y

Answer:

Put a dot on 7 on the y axis then draw a horizontal line through y=7

Step-by-step explanation:

Answer:

Hope that helps! :)

-Aphrodite

Step-by-step explanation:

Answer:

D)

hope this helped

Step-by-step explanation:

Answer:

B.

Step-by-step explanation:

Answer:

the answer is A because none of the x-values or y-values repeat

Step-by-step explanation:

Answer: x≠±2, x<±2, x>1, x<1, and x>±2

explanation:

for this equation to be true

Case 1

either (x-1) should be a negative while (x²-4) should be positive

which gives:-

x-1<0

so, x<1

also, x²-4>0

so, x²>4

⇒x>±2

Case 2:-

x-1>0 and x²-4<0

which gives

x>1 and x²-4<0

so, x>1 or x<±2

Case 3:-

either way, the denominator can't be 0

so, x²-4≠0

which gives,

x≠±2

compiling all, we have,

x≠±2, x<±2, x>1, x<1, and x>±2

These solutions can be pointed to as points on a number line and the behavior shows their discontinuity.

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The values of the missing angles and sides after dilation are:

m∠C'B'D' = 95°,  CQ = 6 and  B'D' = 11.

m∠C'B'D = 180° - m∠B'C'D' - m∠B'D'C'

m∠B'C'D = m∠BCD, m∠B'D'C' = m∠BDC  (dilation)

m∠C'B'D = 180° - 34° - 51° = 95°

Thus, by way of scale factor we can say that:

BC/B'C' = BD/B'D' = 36/18 = 2

B'D' = ¹/₂BD = ¹/₂ * 22 = 11

ΔC'P'Q ∼ ΔCPQ

Thus:

C'Q'/CQ = C'D'/CD = D'Q'/DQ

CQ = 2C'Q' = 2 * 3 = 6

Therefore, m∠C'B'D' = 95°,  CQ = 6 and  B'D' = 11.

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We have two samples, A and B, so we need to construct a 2 Samp T Int using this formula:

In order to use t*, we need to check conditions for using a t-distribution first.

Since 2/3 conditions aren't met, we can still proceed with the problem but keep in mind that the results will not be as accurate until more data is collected or more information is given in the problem.

Solve for t*:

We need the tail area first.

Next we need the degree of freedom.

The degree of freedom can be found by subtracting the degree of freedom for A and B.

The general formula is df = n - 1.

Use a calculator or a t-table to find the corresponding t-score for df = 5 and tail area = .05.

Now we can use the formula at the very top to construct a confidence interval for two sample means.

Substitute the variables into the formula: \(\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }\).

Simplify this expression.

Adding and subtracting 3.73139 to and from -16 gives us a confidence interval of:

If we want to interpret the confidence interval of (-20.5707, -11.4293), we can say...

We are 90% confident that the interval from -20.5707 to -11.4293 holds the true mean of items sold at locations A and B.

Answer:

  see attached

Step-by-step explanation:

Rotation 270° counterclockwise is equivalent to rotation 90° clockwise. The transformation of coordinates is ...

  (x, y) ⇒ (y, -x) . . . . . . . rotation 270° CCW

This means the points are moved to ...

  A(-2, 1) ⇒ A'(1, 2)

  B( 1, 2) ⇒ B'(2, -1)

  C(-2, 4) ⇒ C'(4, 2)

The rotated triangle is shown in the attachment. You may notice that A' and B are the same point.

The value of the diagonal will be equal to 20√2.

Pythagorean theorem states that in the right angle triangle the hypotenuse square is equal to the square of the sum of the other two sides.

The value of the diagonal by the Pythagorean theorem.

H²  =  B²  +  P²

H²  =  20²  +   20²

H²  =  400   +  400

H  =  √800

H  =  20√2

Therefore the value of the diagonal will be equal to 20√2.

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For the answer of factors of expression (12 + 54), in the form of a(b + c), where a is the GCF of 12 and 54 is equals to 6( 2 + 9).

In math, to factor a number means to express it as a product of (other) whole numbers, called its factors. For example, if 7x5 = 35, 7 and 5 are both factors. The divisors that give the remainder to be 0 are the factors of the number. We have an expression of numbers, 12 + 54. We have to write this expression in form of a( b + c), where a is GCF of 12 and 54. Now, we can write the factors of 12 and 54 are 12 = 2×2×3

54 = 2×3 ×3×3

The greatest common factor, GCF of 12 and 54 is 2×3 = 6. So, 12 + 54 = 6× 2 + 6×9

Taking out the common factor 6 from above expression, 6( 2 + 9) which is required form a( b + c). Hence, required expression is 6( 2 + 9).

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To prove that triangle FGE and triangle IJH we need information like the two sides of each triangle and the included angle to be congruent.

To prove two triangles are similar by the SAS is that you need to show that two sides of one triangle are proportional to two corresponding sides of another triangles, with the included corresponding angles being congruent.

For the SAS postulate you need two sides and the included angle in both triangles.

Side-Angle-Side (SAS) postulate:-

If two sides and the included angles of one triangle are congruent to two sides and the included angle of a second triangle, then the two triangles are congruent. SAS postulate relate two triangles and says that two triangles are congruent if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle.

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Answer: C. Buenos Aries-Tucuman-Bahia Blanca-Salta-Buenos Aries

Step-by-step explanation:

Edg 2022

Answer:

4 ways i think

Step-by-step explanation:

Hope this helps!

Answer:

its 20

Step-by-step explanation:

hope this helps

The probability that an even number or a number greater than 3 is rolled on a 12-sided die is 0.833.

A 12-sided die has 12 equally likely outcomes, numbered from 1 to 12. To find the probability of rolling an even number or a number greater than 3, we need to count the number of outcomes that satisfy this condition and divide it by the total number of possible outcomes.

There are 6 even numbers on a 12-sided die, namely 2, 4, 6, 8, 10, and 12, and there are 9 numbers greater than 3, namely 4, 5, 6, 7, 8, 9, 10, 11, and 12. However, we need to be careful not to count the numbers that satisfy both conditions twice, namely 4, 6, 8, 10, and 12.

Therefore, the number of outcomes that satisfy the condition is 6 + 9 - 5 = 10. The probability of rolling an even number or a number greater than 3 is therefore 10/12, which simplifies to 5/6 or approximately 0.833.

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Answer: (7, -2)

use for any math questions m a t h  p a p a it helps me a lot.

Step-by-step explanation:

Answer: Looks pretty good :) !

To determine if a data point is considered an outlier for a data set, we need to calculate the interquartile range (IQR) and use it to define the outlier boundaries. The IQR is the difference between the third quartile (Q3) and the first quartile (Q1). The correct option is (B).

We have that Q1 = 9 and Q3 = 17, we can calculate the IQR as follows:

IQR = Q3 - Q1 = 17 - 9 = 8

To identify outliers, we can use the following rule:

- Any data point that is less than Q1 - 1.5 * IQR or greater than Q3 + 1.5 * IQR is considered an outlier.

Using this rule, we can evaluate each data point:

A. 27: This data point is greater than Q3 + 1.5 * IQR = 17 + 1.5 * 8 = 29. It is considered an outlier.

B. 17: This data point is not an outlier because it is equal to the third quartile (Q3).

C. 3: This data point is less than Q1 - 1.5 * IQR = 9 - 1.5 * 8 = -3. It is considered an outlier.

D. 41: This data point is greater than Q3 + 1.5 * IQR = 17 + 1.5 * 8 = 29. It is considered an outlier.

Therefore, the outliers in the data set are A (27) and D (41).

As for when to use the mean, it is generally recommended to use the mean as a measure of central tendency when the data is symmetric and does not have extreme values.

Therefore, the correct option would be B. When the data is symmetric.

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Answer:

x + 12 = 22 - 9x

x = 10 - 9x

10x = 10

x = 1

5x + 11 > 2x + 38

3x + 11 > 38

3x = 27

x = 9

15x - 40 = 20

-15x = 60

-x = 4

x = -4

Answer:

D

Step-by-step explanation:

40% = \(\frac{40}{100}\) = \(\frac{2}{5}\) ← in simplest form

Then

\(\frac{2}{5}\) of $120 = \(\frac{2}{5}\) × $120 = 2 × $24 = $48

she pays $120 - $48 = $72

The number of edges that the prism has is

When a plane intersects a prism, the shape formed is known as the cross section. The cross section of the prism will have the same form as the base if it is divided by a plane that runs horizontally and parallel to the base.

A prism is a 3-dimensional object with two congruent and parallel bases (which are polyggonal) connected by rectangular lateral faces. The number of edges of a prism is equal to the sum of the number of edges of the two bases and the number of lateral faces.

Each base of the prism has n edges, so the two bases together have 2n edges. The number of lateral faces of the prism is equal to the number of edges of one of its bases, so there are n lateral faces. Each lateral face has 4 edges, so the total number of edges of the lateral faces is 4n.

Therefore, the total number of edges of the prism is equal to the sum of the number of edges of the two bases (2n) and the number of lateral faces (4n), which is 2n + 4n = 6n.

In conclusion, the cross section of a prism is an n-sided polygon and the prism has n + 2 edges.

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The equivalent expression is: \(-x^5 y^3 + 6x^3 y^5\).

Let's simplify the given expression step by step using the given terms:
Expression:

\(3x^3 y^5 + 3x^5 y^3 - (4x^5 y^3 − 3x^3 y^5)\)
Distribute the negative sign outside the parentheses to the terms inside:
\(3x^3 y^5 + 3x^5 y^3 - 4x^5 y^3 + 3x^3 y^5\)
Combine like terms, which are terms that have the same variables raised to the same power:
\((3x^3 y^5 + 3x^3 y^5) + (3x^5 y^3 - 4x^5 y^3)\)
Add or subtract the coefficients of the like terms:
\(6x^3 y^5 - x^5 y^3\)
So, the simplified expression is:
\(6x^3 y^5 - x^5 y^3\)

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the probability of drawing 2 red marbles from the bag will be 0.0455.

Number of Red marbles = 3

Number of blue marbles = 5

Number of green marbles = 4

Total marbles = 3 + 5 + 4 = 12

Probability of drawing 2 red marbles from the bag will be:

P = 3 / 12 × 2 / 11

P = 6 / 132

P = 3 / 66

P = 1 / 22

P = 0.0455

Therefore, the probability of drawing 2 red marbles from the bag will be 0.0455.

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The correlation coefficient (r) is approximately 0.9689.

To calculate the correlation coefficient, we can use the following formula:

r = (nΣxiyi - Σxi * Σyi) / √[(nΣx2i - (Σxi)^2)(nΣy2i - (Σyi)^2)]

Given the values provided:

n = 7

Σxi = 70

Σx2i = 896

Σyi = 77

Σy2i = 949

Σxiyi = 907

Let's substitute these values into the formula:

r = (7 * 907 - 70 * 77) / √[(7 * 896 - (70)^2)(7 * 949 - (77)^2)]

Calculating further:

r = (6349 - 5390) / √[(6272 - 4900)(6643 - 5929)]

= 958 / √[1372 * 714]

= 958 / √980,408

≈ 958 / 990.12

≈ 0.9689

Therefore, the correlation coefficient (r) is approximately 0.9689.

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the width of the reproduced piece is 2.78 inches.

Now, we first need to find the original area of the painting.

Since, The original area is,

= 29 inches x 25 inches

= 725 square inches

Now. we know that the reproduction has 1/9 of the original area, which means that the area of the reproduction is:

= 725 square inches / 9

= 80.56 square inches

Hence, for the width of the reproduced piece, we need to find the width of a rectangle whose area is 80.56 square inches, given that the height is 29 inches which remains constant in the reproduction.

Hence, We can use the formula for the area of a rectangle,

Area = length x width

In this case, we know the area is, 80.56 square inches)

and the length is, 29 inches

Thus, we can solve for the width:

80.56 square inches = 29 inches x width

width = 2.78 inches

Thus, the width of the reproduced piece is 2.78 inches.

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A because 2 is half of 4 and 18 is half of 36.

Step-by-step explanation: because 2 is half of 4 and 18 is half of 36.

Main Answer:The values of k are ±2√5,0, ±π, ±2π, ±3π, and so on.

Supporting Question and Answer:

What conditions must the function y = sin(kt) satisfy in order to be a solution to the differential equation y'' + 20y = 0?

The function y = sin(kt) must satisfy the conditions where either kt is a multiple of π, or k is equal to zero, for it to be a solution to the differential equation y'' + 20y = 0.

Body of the Solution: To find the values of k for which the function y = sin(kt) satisfies the differential equation y'' + 20y = 0, we need to differentiate y two times and substitute it into the differential equation.

First, let's differentiate y = sin(kt)  two times  with respect to t:

y' = kcos(kt)

y'' = -k^2sin(kt)

Now, substitute y'' into the differential equation:

y'' + 20y = 0

(-k^2sin(kt)) + 20sin(kt) = 0

k^2sin(kt)  20sin(kt) = 0

sin(kt)*(k^2 -20) = 0

For this equation to hold true, either sin(kt) = 0 or (k^2 - 20) = 0.

Case 1: sin(kt) = 0 This occurs when kt is a multiple of π: kt = nπ, where n is an integer.

t = nπ/k

Case 2: k^2 + 20 = 0 Solving for k: k^2 = 20 k = ±√(20) =±2√5

Combining both cases, the values of k that satisfy the differential equation y'' + 20y = 0 are given by: k =±2√5, 0, ±π/1, ±2π/1, ±3π/1, ...

Final Answer: So, the values of k are±2√5, 0, ±π, ±2π, ±3π, and so on.

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The values of k are ±2√5,0, ±π, ±2π, ±3π, and so on.

What conditions must the function y = sin(kt) satisfy in order to be a solution to the differential equation y'' + 20y = 0?

The function y = sin(kt) must satisfy the conditions where either kt is a multiple of π, or k is equal to zero, for it to be a solution to the differential equation y'' + 20y = 0.

To find the values of k for which the function y = sin(kt) satisfies the differential equation y'' + 20y = 0, we need to differentiate y two times and substitute it into the differential equation.

First, let's differentiate y = sin(kt)  two times  with respect to t:

y' = kcos(kt)

y'' = -k² sin(kt)

Now, substitute y'' into the differential equation:

y'' + 20y = 0

(-k² sin(kt)) + 20sin(kt) = 0

k² sin(kt)  20sin(kt) = 0

sin(kt)*(k²  -20) = 0

For this equation to hold true, either sin(kt) = 0 or (k² - 20) = 0.

Case 1: sin(kt) = 0 This occurs when kt is a multiple of π: kt = nπ, where n is an integer.

t = nπ/k

Case 2: k²  + 20 = 0 Solving for k: k²  = 20 k = ±√(20) =±2√5

Combining both cases, the values of k that satisfy the differential equation y'' + 20y = 0 are given by: k =±2√5, 0, ±π/1, ±2π/1, ±3π/1, ...

Final Answer: So, the values of k are±2√5, 0, ±π, ±2π, ±3π, and so on.

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We can conclude that the mode of the following data are 4 and 5.

As the given data set is:

Mode is calculated when in the given data set the number appears most often.

So, count each number as we get the result:

Therefore, the modes are 4 and 5.

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Answer:

Step-by-step explanation:

(5p)(7q)=35pq

Answer:

The product of five t imes p and 7 times q is just:

5p(7q), which is 42pq

Let me know if this helps!