13. What bone runs parallel to the fibula?
A. Radius
B. Femur
C. Tibia
D. Ulna

According to a periodic table, Krypton was created during the fission of Uranium.

Atomic number is a characteristic associated with an element and indicates its number of protons, when a fision occurs, the total number protons is conserved.

Thus, the fission of uranium is led by two elements with atomic numbers 56 and 36. According to a periodic table, those atomic numbers are associated to elements Barium (Ba) and Krypton (Kr), respectively.

According to a periodic table, Krypton was created during the fission of Uranium. \(\blacksquare\)

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Answer:

a transverse wave consisting of changing electric fields and changing magnetic fields.

Explanation:

An electromagnetic wave is a wave generated by the vibration of perpendicular electric and magnetic fields, which may progate through vacuum (empty space) or a material medium.

All electromagnetic waves propagate at the same speed in vacuum. This speed is approximately 3.0 × 10⁸ m/s. Which is generally referred as the speed of light, but it is the same constant speed of any electromagnetic wave in the vacuum, c.

In general, waves transfer energy when they travel, but only electromagnetic waves can travel in vacuum. The waves that cannot travel in vacuum are named mechanical waves (they need a medium to travel).

There are two types of waves depending on how they propagate: transverse waves and longitudinal waves. The transverse waves travel perperdiculary to the direcction of the vibration, while longitudinal waves travel parallel to the direction of the vibration.

The classical example of transverse waves is a rope that oscilates up and down. The classical example of  longitudinal waves is a spring that you pull and push by an end and so it  moves forward and back. Sound is also a longitudinal wave.

Answer: the type of collision is elastic collision because both momentum and kinetic energy are conserved.

hope this helped!

The maximum pressure of the block is 3560 N/m².

Pressure can be defined as the force acting perpendicular per unit surface.

The S.I unit of pressure is N/m².

To calculate the  maximum pressure from the question, we use the formula below.

⇒ Formula:

⇒ Where:

From the question,

⇒ Given:

Substitute these values into equation 1

Hence, The maximum pressure of the block is 3560 N/m².

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Answer:

a. 14000

Explanation:

Given parameters:

Efficiency of the machine  = 70%

Work done on machine  = 20000J

Unknown:

Work done by machine = ?

Solution:

 Efficiency of a machine is determined by;

  Efficiency  = \(\frac{Work done by machine}{Work done on machine} x 100\)  

   70  = \(\frac{Work done by machine}{20000}\) x 100

   70  = \(\frac{work done by machine}{200}\)  

 Work done by machine  = 70 x 200 = 14000J

Answer:

C) The book's inertia carried it forward.

When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.

The work done on the box from y=0 to 6.0m is 120 J.

To calculate the work done on the box from y=0 to 6.0m, we need to find the area under the force vs. position graph over that interval.

First, we can find the work done from 0 m to 2 m. Since the force is constant at 40 N over this interval, the work done is simply:

W = F * d = 40 N * 2 m = 80 J

From 2 m to 6 m, the force is constant at -20 N, so the work done is:

W = F * d = (-20) N * 4 m = -80 J

Note that the negative sign indicates that the work is done by the box on the force (since the force is in the opposite direction of the displacement).

Therefore, the total work done on the box from y=0 to 6.0m is:

W_total = 80 J - 80 J = 0 J

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Answer:

A student could conclude that the cart gained momentum as it rolled down.

Explanation:

If the cart was allowed to roll down the ramp from rest, it means that the initial velocity of the cart is zero (0). Also, if the final velocity of the cart became 25 cm/s, it means that the velocity of the cart increased from 0 to 25 cm/s.

Therefore, A student could conclude that the cart gained momentum as it rolled down.

The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Given that an insect lands 0.1m from the center of the turn table.

Rotational speed of the turn table = 55 rev/min

= (55×2π/60) rad/second

= 5.759 rad/second.

Hence, the speed of the insect be = Rotational speed × length

= 5.759 rad/second × 0.1 M.

= 0.5759 meter/second.

Therefore, the speed of the insect be 0.5759 meter/second.

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Answer:

PEgrav = 21.4J

Explanation:

Use the gravitational potential energy formula

m= 0.95kg h=2.3m g= 9.8 N/kg

PEgrav = m *• g • h

PEgrav = 0.95kg * 9.8N/kg * 2.3m

PEgrav = 21.4J

The narration style in the para is third person omniscient

As it narrates the whole incident which is going on.

What is third person omniscient?

The most flexible and open POV available to writers is third person omniscient. An omniscient narrator is one who has all knowledge and all sight, as the name suggests.

The narrator may occasionally access the consciousness of a few or many different characters while the narration is taking place outside of any one particular character.

Some authors employ this viewpoint to build a more "godlike" or purposefully "authorial" persona that enables them to offer dispassionate commentary on the action. Detailed location descriptions that contribute to the mood or atmosphere of a scene may be an example of this, as well as philosophical tangents that serve to develop concepts that only loosely link to the action of the story.

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Answer:

The reading of the scale during the acceleration is 446.94 N

Explanation:

Given;

the reading of the scale when the elevator is at rest = your weight, w = 600 N

downward acceleration the elevator, a = 2.5 m/s²

The reading of the scale can be found by applying Newton's second law of motion;

the reading of the scale  = net force acting on your body

R = mg + m(-a)

The negative sign indicates downward acceleration

R = m(g - a)

where;

R is the reading of the scale which is your apparent weight

m is the mass of your body

g is acceleration due to gravity, = 9.8 m/s²

m = w/g

m = 600 / 9.8

m = 61.225 kg

The reading of the scale is now calculated as;

R = m(g-a)

R = 61.225(9.8 - 2.5)

R = 446.94 N

Therefore, the reading of the scale during the acceleration is 446.94 N

Answer:

C -) The friction between an object and air.

Explanation:

The frictional force is the force that exists between two surfaces in contact, which is opposed to the movement.

That is, this type of force exists as long as there is physical contact between surfaces.

While the other types of force always act at a separation distance between bodies.

A is the answer  because it is the answer

The work done in the spring is calculated to be 2.8 J

Hooke's law states that, the extension of a given material is directly proportional to the applied force as long as the elastic limit is not exceeded . First, we must bear in mind that the material must remain within the elastic limit for us to apply the Hooke's law in solving the problem.

Now;

From Hooke's law;

F = Ke

F = force applied

K = force constant

e = extension

F = W = mg =  2.50 - kg * 9.8 m/s^2 = 24.5 N

K = 24.5 N/ 2.76 * 10^-2

K = 888 N/m

e = F/K

F = W =  1.25 - kg * 9.8 m/s^2 = 12.25 N

e = 12.25 N/ 888 N/m = 0.014 m or 1.4 cm

Work done by an external agent = 1/2 Kx^2

= 0.5 * 888 * (8 * 10^-2)^2

= 2.8 J

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ANSWER

A. Thermal energy will move from a region of higher temperature to a region of lower tmperature

EXPLANATION

We want to determine which of the options is required by the second law of thermodynamics.

The second law of thermodynamics deals mainly with the direction of the flow of heat. It states that:

Ths implies that hno system can totally convert all heat energy it has received to work and that heat will only flow from a region of higher temperature to one of lower temperature.

Therefore, the correct option is option A.

The work done by \(\vec F\) along the given path C from A to B is given by the line integral,

\(\displaystyle \int_C \mathbf F\cdot\mathrm d\mathbf r\)

I assume the path itself is a line segment, which can be parameterized by

\(\vec r(t) = (1-t)(-2\,\vec\imath + 5\,\vec\jmath) + t(4\,\vec\imath+7\,\vec\jmath) \\\\ \vec r(t) = (6t-2)\,\vec\imath+(2t+5)\,\vec\jmath \\\\ \vec r(t) = x(t)\,\vec\imath + y(t)\,\vec\jmath\)

with 0 ≤ t ≤ 1. Then the work performed by F along C is

\(\displaystyle \int_0^1 \left(6x(t)^3\,\vec\imath-4y(t)\,\vec\jmath\right)\cdot\frac{\mathrm d}{\mathrm dt}\left[x(t)\,\vec\imath + y(t)\,\vec\jmath\right]\,\mathrm dt \\\\ = \int_0^1 (288(3t-1)^3-8(2t+5)) \,\mathrm dt = \boxed{312}\)

Answer:

(D) x = 93.8 m

Explanation:

v^2 = v0^2 + 2ax

(20 m/s)^2 = (5 m/s)^2 + 2(2 m/s^2)x

Solving for x,

x = 93.8 m

Answer:

"Both kinetic energy and angular moment of the system" is the correct solution.

Explanation:

The kinetic energy is:

\(KE=\frac{1}{2}m_{1}v_{1}^2 + \frac{1}{2}m_{2}v_{2}^2\)

Its conversion is:

⇒ \((KE)_{1}=(KE)_{f}\)

Angular momentum is:

\(L=I_{1}\omega_{1}+I_{2}\omega_{2}\)

Its conversion is:

⇒ \(L_{i}=L_{f}\)

So that both "KE" and "L" of the system conserved.

Answer:

Chemical weathering demands chemical reactions with minerals inside the rock and causes changes in rock composition. Sometimes this process will produce a different kind of product due to the reaction. Mechanical weathering only involves the physical breakage of rocks to smaller pieces of fragments.

Explanation:

Answer:

1992.008J

Explanation:

Answer:

protons: 6

electrons: 6

neutrons: 8

Explanation:

atomic number -> number of protons -> 6

mass number -> number of protons + number of neutrons

    so 14-6 = 8. 8 neutrons

this atom is neutral (net charge is 0), so the number of electrons is the same as the number of protons, which is 6

The question is incomplete. The mass of the object is 10 gram and travelling at a speed of 2 m/s.

Solution:

It is given that mass of object before explosion is,m = 10 g

Speed of object before explosion, v = 2 m/s

Let \($m_1, m_2 \text{ and}\ m_3$\) be the masses of the three fragments.

Let \($v_1, v_2 \text{ and}\ v_3$\) be the velocities of the three fragments.

Therefore, according to the law of conservation of momentum,

\($mv=m_1v_1 +m_2v_2+m_3v_3$\)

\($10 \times 2 \hat i=3 \times 12 \hat{j} + 3(v_{2x} \hat{i}+v_{2y} \hat{j})-4 \times 9 \hat{j}$\)

So the x- component of the velocity of the m2 fragment after the explosion is,

\($3v_{2x} = 20$\)

∴ \($v_{2x} = 6.67 \ m/s$\)

The reading on a vernier caliper can be represented as 45.75mm.

1. Understand the components of a vernier caliper: A vernier caliper consists of two main scales - the main scale and the vernier scale. The main scale is typically graduated in millimeters, while the vernier scale is a smaller scale that slides along the main scale.

2. Locate the main scale: Identify the main scale on the vernier caliper. The main scale is usually marked on the fixed jaw of the caliper and extends in a linear fashion.

3. Identify the vernier scale: The vernier scale is attached to the movable jaw of the caliper. It slides along the main scale and consists of smaller divisions.

4. Align the zero marks: Close the jaws of the caliper and ensure that the zero marks on both the main and vernier scales are aligned.

5. Determine the main scale reading: Read the main scale value that aligns with the zero mark on the vernier scale. In this case, the main scale reading will be 45mm.

6. Locate the vernier scale reading: Examine the vernier scale and identify the division on the vernier scale that lines up perfectly with a division on the main scale. This will give you the additional measurement beyond the main scale reading.

7. Determine the vernier scale reading: Find the division on the vernier scale that aligns with a division on the main scale. The value of this vernier division corresponds to the additional measurement. In this case, the vernier scale reading will be 0.75mm.

8. Add the main scale and vernier scale readings: Combine the main scale reading and the vernier scale reading to get the final measurement. In this case, the final reading will be 45.75mm.

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Answer:

28 j

Explanation:

because when you add you get 28

The kinetic energy of the book after it is slids a distance of 2 meters will be 10 Joules.

The work-energy theorem states that "the work done on an object is the change in its kinetic energy".

Hence;

Kinetic energy = work done

Note that: work-done is expressed as:

Work done = f × d

Where f is force applied and d is distance traveled.

Given that:

Force applied f = 5 newton

Distance d = 2 meters

Work done = ?

Plug these values into the above formula and solve for the workdone.

Work done = f × d

Work done = 5N × 2m

Work done = 10Nm

Work done = 10 Joules

Therefore, the kinetic energy is 10 Joules.

Option B) 10 J is the correct answer.

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Answer:

Below

Explanation:

speed = wavelength * frequency

speed / frequency = wavelength

frequency =  4 waves / 2 sec = 2 wave/s = 2 hz

10 m/s  /  2 hz   = wavelength   = 5 m