16. A horizontal pipe with a cross-section of 10 cm?which is joined to another horizontal pipe of 50 cm Cross-sectional area. The speed of water in the small pipe is 6 m/s and the pressure there is 200 kPa. The pressure in the large pipe, in Pa. is

A. 183
B. 217000
C. 217
D. 235000​

Answer:

b 1.3

Explanation:

The length of the lane is 27.66 m and the velocity of the bowling ball just before it hits the pins is 10.12 m/s.

The three equations of motion are -

v = u + at

S = ut + 1/2at²

v² - u² = 2aS

Given is a bowling ball that rolls down the lane with a velocity of 12 m/s. After that, the ball slows down at a constant rate of 0.75 m/s².

[u] = 12 m/s

[a] = 0.75 m/s²

Part A

time taken to reach the pins = [t] = 2.5 s

S = ut + 1/2at²

S = 12 x 2.5 + 1/2 x - 0.75 x 2.5 x 2.5

S = 12 x 2.5 - 2.34

S = 30 - 2.34

S = 27.66 m

Part B

Assume that the velocity is v m/s.

v² = u² + 2aS

v² = (12)² - 2 x 0.75 x 27.66

v² = 144 - 41.49

v² = 102.51

v = 10.12 m/s

Therefore, the length of the lane is 27.66 m and the velocity of the bowling ball just before it hits the pins is 10.12 m/s.

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The distance traveled by the Spacecraft is  2.3 x 10² m.

To have a constant velocity, the change in velocity or speed of the object must be zero.

Constant speed will elapse equal distance in an identical period of time as a result is an example of steady speed.

For a Spacecraft is traveling in inner planetary space at a constant velocity and a given time of motion, the distance traveled by the Spacecraft is calculated as follows;

Distance = speed x time

the speed is given as 24.21 m/s

the time of motion is given as 9.5 seconds

distance = 24.21 m/s  x 9.5 s

distance = 2.3 x 10² m

Thus, the distance traveled by the Spacecraft is  2.3 x 10² m.

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The complete question is below;

Spacecraft is traveling in inner planetary space at a constant velocity of 24.1 m/s. What it estimated distance traveled by the spacecraft in 9.50 seconds?

Answer:

The force is being pulled my the gravity or it could be a third party thing like a black hole you feel me

Explanation:

Answer:0.2 m/s^2

Explanation:

mass=18.15kg

Force=3.63N

Acceleration=force ➗ mass

Acceleration=3.63 ➗ 18.15

Acceleration=0.2 m/s^2

A girl pushes a wagon of mass 18.15 kg with a force of 3.63 N, so the acceleration of the wagon will be 0.2 m/s².

In mechanics, acceleration is the measure of how rapidly an object's velocity changes over time. Accelerations as a vector quantity. An object's acceleration depends on the direction of the net force exerted on it.

A vector quantity, acceleration, is something that has both a magnitude and a direction. As a vector quantity, velocity is also. The ratio of the velocity vector change over a time interval to that interval is the definition of acceleration.

Mass, m =18.15 kg

Force, f = 3.63 N

Force = m × a

a= f / m

a =3.63 / 18.15

a = 0.2 m/s²

Hence, the acceleration of the wagon will be 0.2 m/s².

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The refraction of a sound wave occurs when the sound wave bends as it passes through the boundary between media. Refraction occurs when there is a difference in the speed of sound waves in two different media.

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The law of motion that accounts for an apple accelerating as it falls from a tree is the law of gravity, specifically Newton's Second Law of Motion.

Newton's Second Law of Motion states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. In the case of an apple falling from a tree, the net force acting on it is the gravitational force pulling it toward the Earth. The acceleration of the apple is therefore determined by the strength of this gravitational force and the mass of the apple.

As the apple falls from the tree, it accelerates toward the ground due to the gravitational force acting on it. The faster the apple falls, the greater its acceleration. This acceleration is commonly referred to as acceleration due to gravity, which is a constant value of 9.81 m/s^2 near the surface of the Earth.

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From the given stem plot of the heights of students in inches, the height of a student will be 51 inches, i.e., option C.

Each data value in a stem and leaf plot is divided into a “stem” (the first number of the digit) and a “leaf” (often the final digit).

The “leaf” values follow the “stem” values to the right (or left) in a list format.

Each “leaf” displays the individual scores within each group, while the “stem” is used to categorize the results.

The list of heights (in inches) of students from the following stem plot graph is as follows – 51, 53, 56, 57, 57, 58, 58, 60, 62, 67, 69, 72, 73

So, the height corresponding to a student from the given list is 51 inches. Therefore, the correct option is C, 51 inches.

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Answer:

A. the wavelength of light is reflected by what it is hitting and directed back into the eye.

Explanation:

The magnitude of the charge of the given moveable beads is 9.33 nC.

The tension in the string is calculated as follows;

Tcos45 = mg

where;

F = Tsin45

\(\frac{kq^2}{r^2} = Tsin(45)\\\\\frac{kq^2}{r^2} = \frac{mg}{cos45} \times sin(45)\\\\\frac{kq^2}{r^2} = mg\\\\q = \sqrt{\frac{mgr^2}{k} }\)

\(q = \sqrt{\frac{(0.032 \times 10^{-3})(9.8)(0.05)^2}{9\times 10^9} } \\\\q = 9.33\times 10^{-9} \ C\\\\q = 9.33 \ nC\)

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Answer:

5.99 m  = 6 m

Explanation:

PE = m*g*h

235.2 J = (4 kg)(9.81 m/s^2)(h)

h = (235.2 J)/(9.81*4)

h = 5.99 m

h = 6 m

B. More of the salt dissolves because the additional water can hold more salt ions

In order to measure the angle of incidence and the angle of refraction using Tracker's protractor tool (the green angle in the video frame), the following steps should be followed:

Step 1: Open the video in Tracker software.

Step 2: Click on the "Measure" button on the toolbar at the top of the software.

Step 3: From the dropdown menu, select "Angle".

Step 4: Click on the "protractor tool" icon (the green angle in the video frame).

Step 5: Position the vertex of the protractor exactly at the origin of the coordinate axis and move the arms of the protractor so that one arm is on the vertical axis (above or below, as appropriate) and the other on the light ray.

Step 6: Measure the angle of incidence and the angle of refraction for the frame numbers specified in the table below by using the step buttons on the right to advance the video a frame at a time.

Step 7: Record the measured angles in the table below. Note that the angle of incidence should be measured on the incident ray (the ray that is coming from the left), and the angle of refraction should be measured on the refracted ray (the ray that is coming from the right).In conclusion, by following these steps, one can measure the angle of incidence and the angle of refraction using Tracker's protractor tool.

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Answer: Because the hunter will try to aim at the fish, but the image of fish he sees is actually the apparent image of the fish at a location.

Heres an image to help

Hope this helps!

The airplane change in velocity be 120 m/sec

The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration.

The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.

acceleration = velocity/time

Velocity = acceleration * time

Velocity = 60*2

Velocity = 120 m/sec

The airplane change in velocity be 120 m/sec

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The mass of the the object, given that the same force acted upon it to accelerate at 2 m/s² is 34 Kg

First, we shall determine the force. This can be obtained as follow:

Force (F) = mass (m) × acceleration (a)

Force = 4 × 17

Force = 68 N

Finally, we shall determine the mass of the object that will accelerate at 2 m/s² when the force of 68 N is applied to it. Details below:

Force = mass × acceleration

68 = mass × 2

Divide both sides by 2

Mass = 68 / 2

Mass = 34 Kg

Thus, from the above calculation, we can conclude that the mass is 34 Kg

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The momentum of first player can be given as,

The momentum of second player can be given as,

The total momentum of both the players can be given as,

Plug in the known expressions,

Substitute the known values,

Thus, the total momentum of both the players is 1531.7 Ns.

Answer: A. If the surface aquifer has a high water table

Explanation:

The water table refers to the water level underground. If it is high, it means that the water underground is close to the surface such that if a well was dug, it would not need to be dug too far for water to be seen.

When heavy rain falls, flooding is avoided if the water is either able to run off efficiently or if the ground is able to absorb the water. When the water table is high, it means that the ground will not be able to absorb much because the water is already close to the surface which means that should heavy rain fall, there will most likely be a flood.

Answer:

I KNOW THE ANSWER IT WILL COST 30$

Explanation:

Answer:

1.8 m/s

Explanation:

Distance = 2*50 +2*40 [m] = 180 [m]

Time = 100 [s]

Velocity = Distance/Time = 1.8 m/s

Average velocity for the lap is 1.8 m/s

GIven:

Length of rectangular track = 50 m

Width of rectangular track = 40 m

Time taken to cover a lap = 100 seconds

Find:

Average velocity for the lap

Computation:

Perimeter of rectangle = Length of one lap

So,

Perimeter of rectangle = 2(l + b)

So,

Length of one lap = 2[50 + 40]

Length of one lap = 2[90]

Length of one lap = 180 meter

Average velocity = Distance / Time

Average velocity for the lap = 180 / 100

Average velocity for the lap = 1.8 m/s

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The tension in the string holding the tassel and the vertical will the tension in the string

Generally, the equation for Tension is  mathematically given as

\(TCos\theta = mg\)

Therefore

\(TCos6.58^{o} = 19.8*10^{-3}*9.8\)

T = 0.1953 N

b).

Where

\(T* sin \theta = ma\)

\(0.1953*Sin6.58 \textdegree = 19.8*10^{-3}*a\)

a = 1.13 m/s^2

In conclusion

T* sinФ = ma

2msinФ = ma

2sinФ = a

\(sin\theta = \frac{a}{2}\)

\(\theta = sin^{-1}\frac{a}{2} \\\\\theta= sin^{-1}\frac{1.13}{2}\)

Ф = 34.4 °

In conclusion, The tension in the string holding the tassel and the vertical will the tension in the string

T = 0.1953 N

Ф = 34.4 °

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Answer:

C

Explanation:

The answer is C because if you look at the 1 hour mark it shows 10km

Answer:It will be 10km/hour

Explanation:

Explanation: ΔL = τ(average) * Δt
Change in angular momentum = average torque * change in time

solve for average torque for each objects
τ(average) = ΔL / Δt

Object y average torque
τy = ΔLy / Δt = 20 / 5 = 4
τy = 4

Object x average torque
τx = ΔLx / Δt = 10 / 5 = 2
τx = 2

Relates τy and τx
2τx = τy

Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey.

The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. The precise relation between torquey and torquex is torquey = 2 * torquex.

To relate torquey to torquex, we are able to use the concept of angular momentum and torque. Angular momentum is described because the manufactured from the moment of inertia and angular velocity:

L = I * ω

Differentiating this equation with an appreciation of time, we get:

dL/dt = d(I * ω)/dt

Using the product rule of differentiation, we've got:

dL/dt = I * dω/dt + ω * dI/dt

Now, we realize that torque (τ) is described because of the charge of the exchange of angular momentum:

τ = dL/dt

Substituting the expression for dL/dt in terms of angular velocity and second of inertia:

τ = I * dω/dt + ω * dI/dt

Let's denote the common price of torque for item X as torquex. Since object X has a moment of inertia I0, we can write:

torquex = I0 * dω/dt + ω * dI0/dt

Now, let's consider item Y. It has a moment of inertia 2I0. Using the identical expression, we will write:

torquey = (2I0) * dω/dt + ω * d(2I0)/dt

torquey = 2I0 * dω/dt + ω * (2 * dI0/dt)

torquey = 2I0 * dω/dt + 2ω * dI0/dt

Comparing the expressions for torquex and torquey, we will see that:

torquey = 2 * torquex

Therefore, the precise relation between torquey and torquex is;

torquey = 2 * torquex.

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The correct question is;

"Two objects, X and Y, experience external net torques that vary over a period of 5 seconds. Object X has a moment of inertia I0, and Object Y has a moment of inertia 2I0. The average value of the magnitude of the external net torque exerted on Object X from time t=0 to t=5s is torquex. Similarly, the average value for ObjectY is torquey. The magnitudes of the angular momenta L of Objects X and Y versus t are shown in the graph. Which of the following expressions correctly relates torquey to torquex?"

The velocity of the car 1 can be seen from the calculation as 20 m/s West

A coordinate system or point of view used to observe motion is known as a frame of reference. It can be used as a guide when describing an object's position, speed, and acceleration. Different frames of reference may result in various motion observations.

The relative velocity is the velocity of an object or observer as observed from a particular frame of reference.

We can see that the velocity of the car 1 is;

45 m/s - 25 m/s

= 20 m/s West

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Cooling coil is a part of air conditioner and  you are likely to find it located in the ductwork of a large apartment building. Hence, option (B) is correct.

The cooling coils are a part made up of tubes made of various materials that allow a fluid to move through them. These tubes also have an exterior contact with air or another gas, which enables a heat exchange.

In the fluid that flows through the cooling coils, either water or a refrigerant may be present.

The cooling coils are elements that cool or warm the air in a cooling system intended for comfort.

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The value of accelerating the rocket sled from rest to 5 sec with the speed of,

Thus, the acceleration of the rocket sled is,

where g is the acceleration due to gravity.

The rocket sled is declerated to the rest in 1.4 s from the speed v1,

Thus, the decleration of the rocket sled is,

Hence, the rocket sled is accelerated at 5.8g and decelerated at -20.6g.

The energies that the ball possess when it is in rest at the top of the hill is electrostatic  potential energy. When the ball at the level ground, it has gravitational potential energy and when it at the half way down hill , it possess rotational kinetic energy.

Potential energy of a body is generated by virtue of its position. When the object is placed at rest on the surface the gravitational field, the stored energy is called gravitational potential energy.

When the object starts to move it gains kinetic energy.  When the ball is at rest on the top of the hill it has the electrostatic potential energy. When starts to roll to the ground , then its potential energy converts to rotational kinetic energy.

When, the ball reaches the ground its kinetic energy again transforms to potential energy where the ball is falling down to the gravitational field and thus it possess gravitational potential energy.

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Answer:

C , E , A , D , B

Explanation:

We evaluate the accelerations for each case, using the formula: a = (vf - vi) / t

A)  a = (10.3 - 0.5 ) / 1 = 9.8 m/s^2  --> magnitude: 9.8 m/s^2

B)  a = (0 - 20) / 1 = - 20 m/s^2  -->  magnitude : 20 m/s^2

C)  a = (0.02 - 0.004) / 1 = 0.016 m/s^2 -->  magnitude : 0.016  m/s^2

D)  a = (4.3 - 0) / 0.4 = 10.75 m/s^2  -->  magnitude : 10.75 m/s^2

E)  a = (1 - 2) / 8.3 = - 0.12 m/s^2  -->  magnitude: 0.12 m/s^2

Then, comparing magnitudes from least to greatest:

C , E , A , D , B

The order of the magnitude of the acceleration, from least to greatest is:

C < E < A < D < B

In physics, acceleration (a) is the rate at which velocity changes (Δv) with time (t).

We will calculate the acceleration for each scenario using the following expression.

\(a = \frac{v-u}{t}\)

where,

Data

\(a = \frac{10.3m/s-0.50m/s}{1.0s} = 9.8 m/s^{2}\)

Data

\(a = \frac{0m/s-20m/s}{1.0s} = -20 m/s^{2}\\\\|a| = 20 m/s^{2}\)

Data

\(a = \frac{2.0cm/s-0.40cm/s}{0.50s} = 3.2cm/s^{2} \times \frac{1m}{100cm} = 0.032 m/s^{2}\)

Data

\(a = \frac{4.3m/s-0m/s}{0.40s} = 11 m/s^{2}\)

Data

\(a = \frac{1.0m/s-2.0m/s}{8.3s} = -0.12 m/s^{2}\\\\|a| = 0.12 m/s^{2}\)

The order of the magnitude of the acceleration, from least to greatest is:

C < E < A < D < B

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