186.555 rounded to the nearest hundredth

Answer:

m<NQS = 32°

Step-by-step explanation:

Given:

m<BQS = 80°

m<BQN = 48°

Required:

m<NQS

SOLUTION:

Angle BQN and angle NQS are adjacent angles having a common line, QN, and a common corner point, Q.

Therefore:

m<BQN + m<NQS = m<BQS (angle addition postulate)

48° + m<NQS = 80° (substitution)

m<NQS = 80 - 48° (Subtraction of 48 from each side)

m<NQS = 32°

Answer:

32

Step-by-step explanation:

took test

m<A = 112.5

m<B = 67.5

m<C = 67.5

m<D = 112.5

Consider the provided information.

The sum of all interior angle of a polygon is: (n-2)*180

Substitute n = 8.

(8-2)*180 = 1080

Thus, the measure of each angle is:

∠B and ∠C are congruent and their sum is 135°

∠B+∠C=135°

∠B=67.5°

Hence, the m angle B and m angle C is 67.5°.

The sum of all angles of a quadrilateral is 360°.

∠A+∠D+∠B+∠C=360°

∠A+∠D=360°-135°

∠A+∠D=225°

∠A and ∠D are congruent and their sum is 225°

∠A+∠D=225°

∠A=∠D=112.5°

Hence, the m angle A and m angle D is 112.5°.

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When coding a SELECT statement in SQL, it is crucial to follow a specific order for the four main clauses to ensure accurate and efficient retrieval of data. The correct order to code the clauses is c. SELECT, FROM, WHERE, ORDER BY.

Firstly, the SELECT clause specifies the columns that you want to retrieve data from. This clause is always coded at the beginning of the statement. Next, the FROM clause identifies the table or tables from which you want to retrieve data. It is important to note that the tables in the FROM clause must be listed before the WHERE clause.
The WHERE clause is used to filter the data based on certain criteria or conditions. This clause is typically coded after the FROM clause. Lastly, the ORDER BY clause sorts the retrieved data in ascending or descending order based on a specified column. This clause is always coded at the end of the statement.
Therefore, the correct order for coding the four main clauses in a SELECT statement is SELECT, FROM, WHERE, and ORDER BY. By following this order, you can ensure that your query runs smoothly and returns the correct results.

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Answer:

\(\sqrt{125}\)

Step-by-step explanation:

5 squared + 10 squared is root 125

Answer:

MP = 12 cm

Step-by-step explanation:

4cm : 6cm

8cm : x

8 * \(\frac{6}{4}\) = 12 cm

MP = 12 cm

Answer:

Step-by-step explanation:

Simple Interest = 7000×3×5/100

= 70×15 = 1050 $

Answer:

1050

Step-by-step explanation:

p=7000

r=5%

t=3

s.i =PxTxR/100

=7000x5x3/100

= 1050 #

The test statistic is 1.177, and the p-value is approximately 0.120, which is greater than the significance level of 0.05, indicating that there is not enough evidence to conclude that the proportion of defective circuit boards is greater than 3%.

To test the hypothesis that more than 3% of circuit boards are defective, we can use a one-tailed test with the following null and alternative hypotheses:

\(H_0\): p ≤ 0.03 (proportion of defective boards is less than or equal to 3%)

\(H_a\): p > 0.03 (proportion of defective boards is greater than 3%)

where p is the true proportion of defective boards in the population.

To calculate the test statistic, we can use the following formula:

z = (p-cap - p0) / √(p0(1-p0)/n)

where p is the sample proportion of defective boards, p0 is the hypothesized proportion (0.03), and n is the sample size.

In this case, we have p-cap = 0.04, p0 = 0.03, and n = 100, so the test statistic is:

z = (0.04 - 0.03) / √(0.03(1-0.03)/100) = 1.177

To determine the p-value associated with this test statistic, we can use a standard normal distribution table or a calculator to find the probability of observing a z-value of 1.177 or greater under the null hypothesis. This probability is approximately 0.120, which is the area to the right of z = 1.177 on the standard normal distribution curve.

Since this p-value is greater than the common significance level of 0.05, we fail to reject the null hypothesis.

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Answer:

Q(-1 , 6)

Step-by-step explanation:

Midpoint M(5 , -2)

\(Midpoint = \left(\dfrac{x_{1}+x_{2}}{2},\dfrac{y_{1}+y_{2}}{2} \right)\\\\P(11 , -10) \ ; x_{1} = 11 \ & \ y_{1}=-10\\\\\left(\dfrac{11+x_{2}}{2},\dfrac{-10+y_{2}}{2}\right)= \left( 5 , -2 \right )\\\\\dfrac{11+x_{2}}{2}=5 \ ; \dfrac{-10+y_{2}}{2}=-2\)

11 + x₂ = 10         ;  -10 + y₂ = -4

      x₂ = 10 - 11   ;      y₂ = - 4 + 10

      x₂ = -1          ;       y₂ = 6

Q(-1 , 6)

the coordinates of point Q is (-1,6)

384,000 bacteria would be present at the end of 7 hours if it doubles itself every hour.

Initial number of bacteria=3000

Number of bacteria at the end = initial number of bacteria * (base)ⁿ

where, n= number of hours

Number of bacteria at the end=3000*2⁷

                                                    =3000*128

                                                     =384,000

Therefore, there will be 384000 bacteria at the end of seven hour if the bacteria doubles itself every hour.

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Answer:

4

Step-by-step explanation:

Answer:

1250 7500 3

Step-by-step explanation: im just smart

Answer:

x ≈ 16.2

Step-by-step explanation:

tan56° = \(\frac{24}{x}\) ( multiply both sides by x )

x × tan56° = 24 ( divide both sides by tan56° )

x = \(\frac{24}{tan56}\) ≈ 16.2 ( to the nearest tenth )

Answer:

10

Step-by-step explanation:

7 1/2 = 7.5

3/4 = 0.75

7.5 ÷ 0.75 = 10

Check work:

0.75 x 10 = 7.5

Answer:

10√2

Step-by-step explanation:

5√2³ = 5√8 = 5√(2 x 4) = (2 x 5)√2 = 10√2

An association between the two variables can be implied if the relative frequencies vary across the columns.

In a two-way table, the relative frequencies represent the proportion of observations within each cell relative to the total number of observations in that column. If the relative frequencies differ significantly across the columns, it suggests that there is an association between the two variables being examined. This indicates that the distribution of one variable is not independent of the other variable, and there may be a relationship or dependence between them. It is important to analyze the patterns in the data, perform additional statistical tests, and consider other factors to confirm the presence and strength of the association.

An association between the two variables can be implied if the relative frequencies vary across the columns.

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Answer:

\(\frac{x-5}{x-7}\)

Step-by-step explanation:

Given

\(\frac{x^2-2x-15}{x^2-4x-21}\) ← factor numerator and denominator

= \(\frac{(x-5)(x+3)}{(x-7)(x+3)}\) ← cancel (x + 3) on numerator and denominator

= \(\frac{x-5}{x-7}\)

Answer:

\(\frac{x-5}{x-7}\) is the answer

Step-by-step explanation:

\(\frac{x^{2}-2x -15 }{ x^{2}-4x-21}\)

Factorising,

\(\frac{x^{2}-5x+3x-15}{x^{2}-7x+3x-21 }\)

\(\frac{x(x-5)+3(x-5)}{x(x-7)+3(x-7)}\)

\(\frac{(x+3)(x-5)}{(x+3)(x-7)}\)

\(\frac{x-5}{x-7}\)

Answer:S = Speed

D = Distance

T = Time

S = D/T

S = 50m/1/2

50 divided by 1/2 = 25

25 = 50/1/2

S = 25 m/min.

Step-by-step explanation:

Answer:

100

Step-by-step explanation:

I hope it helps u dear

The hypothesis for the given scenario can be written as follows:

Null hypothesis

H_0: μ = 7.2

Alternative hypothesis

H_1: μ ≠ 7.2

Here, μ = Population mean

The mean pressure produced by the valve is not 7.2 lbs/square inch.

The given level of significance (α) = 0.05

The given population variance is known to be 1.

Need to determine if there is sufficient evidence to show that the valve does not perform to the given specifications if the valve was designed to produce a mean pressure of 7.2 lbs/square inch. That is, whether to reject or accept the null hypothesis with the given level of significance (α) = 0.05.

The sample mean pressure of 190 engines tested was 7.3 lbs/square inch. Mean pressure (μ) = 7.3 lbs/square inch, σ² = Variance = 1, n = Number of observations = 190

Significance level (α) = 0.05

Test Statistic: Z = (x - μ) / (σ / √n)

where x = Sample mean

The formula for the test statistic can be written as:

Z = (7.3 - 7.2) / (1 / √190)Z = 4.3588 (approx.)The calculated value of Z = 4.3588 is greater than the Z critical value at 0.05 level of significance.

Hence, there is sufficient evidence to reject the null hypothesis H_0. Therefore, we can conclude that the valve does not perform to the given specifications. The mean pressure produced by the valve is not 7.2 lbs/square inch.

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Check the picture below.

Answer: 1550/3

Step-by-step explanation:  it is logically posiblie

Answer: 120

Step-by-step explanation: divide 24 by 5 to get 4.8 so its 4.8 minutes for one question

25 x 4.8 = 120

The equation of a line into slope-intercept form is represented as:

y = mx + c

where m = slope of the line

c = y-intercept of the line

On simplifying 8x - 20y = 40, the equation will be:

⇒ 2 (4x - 10y) = 2 (20)

⇒ 4x - 10y = 20

⇒ 2x - 5y = 10

⇒ 2x - 10 = 5y

⇒ 5y = 2x + (-10)

⇒ y = 2x/5 + (-10/5)

⇒ y = 2x/5 + (-2)

The slope of this line = 2/5

y-intercept of the line = -2

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The change in profit (ΔP) when the number of units (Δx) increases by 5, based on the given marginal profit function, is -18331.50

To find the change in profit (ΔP) when the number of units (Δx) increases by 5.

we need to evaluate the marginal profit function and multiply it by Δx.

The marginal profit function is given by dP/dx = 12.1(60 - 3x).

We are given the value of x as 121, so we can substitute it into the marginal profit function to find the marginal profit at that point.

dP/dx = 12.1(60 - 3(121))

= 12.1(60 - 363)

= 12.1(-303)

= -3666.3

Now, we can calculate the change in profit (ΔP) by multiplying the marginal profit by Δx, which is 5 in this case.

ΔP = dP/dx×Δx

= -3666.3 × 5

= -18331.5

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Answer:

Step-by-step explanation:

Answer:

The answer is B

Step-by-step explanation:

If you were to rotate the shape 180* it would turn 2 times leaving the point "H" at (5, -3)

Answer:

Undefined.

Step-by-step explanation:

Slope is the Rise/Run of a straight line.  Run is the change in the value of y for a change in x.  The graph shows all values are possible for y even when there is zero change in x.  All Values/0 = Undefined.

Answer:

The answer is -285

Step-by-step explanation:

The scale of the diagram as described in the task content is; 1: 8 where k= 8.

It follows from the task content that the original length of the room in discuss is 8cm. It therefore follows that the length of the room in the scale diagram is 1cm. On this note, the scale of the diagram in discuss is; 1 : 8 as 1cm on the diagram corresponds to 8cm actual length.

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