18.74 g of P4 is reacted with 9.6 g of Cl2 balanced is P4 (s) + 6 Cl2 (g) → 4 PCl3 (l) how many PlC3 can I make?

Answer:

yes that is true........

Answer:

Explanation:

62.3018064. We assume you are converting between grams MgF2 and mole.

Answer:

(9.20×10)-7

92-7

=85

Explanation:

Multiplication comes first in BODMAS

Hope it helps

Answer:

sdipgjaeri0ae

Explanation:

Answer:

The trachea, also called the windpipe, is a cartilaginous tube that connects the larynx to the bronchi of the lungs, allowing the passage of air, and so is present in almost all air-breathing animals with lungs. The trachea extends from the larynx and branches into the two primary bronchi. At the top of the trachea the cricoid cartilage attaches it to the larynx. The trachea is formed by a number of horseshoe-shaped rings, joined together vertically by ligaments over their substance and by the trachealis muscle at their ends. The epiglottis closes the opening to the larynx during swallowing.

Explanation:

You asked I answered.

Hope this helped! :)

P.S. If you still don't get where the trachea is, look at the graph below. :)

The tile's suggested answers include amine, alcohol, carboxyl group, and halocarbon.

Hydrocarbons are organic substances comprised of hydrogen and carbon, and include petroleum, methane gas, and coal. Alkanes are both a highly combustible chemical and the main source of fuel in the planet. Its uses include diesel, jet fuel, propane, petrol, and petroleum, to name a few.

The most fundamental category of organic compounds is referred to as a hydrocarbon. As their name implies, they are exclusively made up of the elements hydrogen and carbon. Atoms surround one or more core carbon atoms in hydrocarbon molecules, which are branching or chain-like in shape.

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The complete question is-

Drag each tile to the correct image. Match each hydrocarbon class to its structure. carboxylic acid amine halocarbon alcohol.

The percent ionization of an acidic solution can be calculated from the H+ concentration. the percent ionization of the monoprotic acid of 0.141 M is 18.23 %.

Percent ionization of an acidic solution is the percent of H+ ions in the solution. Thus, mathematically, it is the ratio of H+ ion concentration to the concentration of solution multiplied by 100.

Let HA be the monoprotic acid when it ionizes, forming equal concentration of H+ and A- let it be x. Thus ionization  constant can be written as follows:

Ka = [x]² /[HA]

0.00469 =[x]²/[0.141 M]

   [X] = 0.025. = [H+]

Percentage ionization  = (0.025 M / 0.141 M)× 100

                                      = 18.23 %

Therefore percentage ionization of the acid is 18.23%.

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The purpose of a lab report is to provide information about an experiment in a clear, concise, and consistent format. Therefore, option (D) is correct.

The lab report can be described as a paper that documents the outcome of an experiment. People create this form of paper to demonstrate the student's understanding of the experimental procedure and the result's relevance.

The primary goal of this is not the documentation of the process but the illustration of the theory behind the experimental procedure and its ability to describe the behavior of variables. lab reports are described as comprehensive documentation of the entire experimentation process including theoretical analysis.

Therefore, lab reports are prepared to provide information about an experiment in a clear, concise, and consistent pattern.

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Answer:

A ) New rocks floating to the surface of the crust.

TRUST

When hydrogen bromide (HBr) is added to 2-methylbut-2-ene ((CH3)2CCHCH3), an electrophilic addition reaction takes place, where the π bond of the alkene is broken, and the hydrogen and bromine atoms are added to the resulting carbocation.

The reaction proceeds through a Markovnikov addition, where the hydrogen atom attaches to the carbon atom with the greater number of hydrogen atoms.

In this case, the initial addition of HBr to 2-methylbut-2-ene leads to the formation of a primary carbocation, as the positively charged carbon atom only has one alkyl group attached to it. The primary carbocation is relatively unstable, and it can undergo a rearrangement to form a more stable secondary carbocation.

The major product that is typically obtained is the 2-bromo-2-methylbutane. The hydrogen atom from HBr adds to the carbon with three hydrogen atoms (the more substituted carbon), resulting in the formation of a secondary carbocation.

On the other hand, a minor product is also formed, which is 3-bromo-2-methylbutane. This product arises from the addition of HBr to the primary carbocation, which is less stable. Although the primary carbocation is less favored, it can still be formed and lead to the formation of the minor product.

In summary, the addition of HBr to 2-methylbut-2-ene yields two products: the major product is 2-bromo-2-methylbutane, resulting from the addition of HBr to the more stable secondary carbocation, and the minor product is 3-bromo-2-methylbutane, originating from the less stable primary carbocation.

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Answer:

C3H8 + 5O2 = 3Co2 + 4 H2o

Explanation:

we can balance this equation by algebric method ( ABC method)

Answer:

The answer is "\(\bold{0.525\ \ atm^{-1}}\)"

Explanation:

Given equation:

\(2SO_2(g) + O_2(g) \leftrightharpoons 2SO_3(g)\)

Given value:

\(\Delta rH =-198.2 \ \ \frac{KJ}{mol}\)

\(Kp=1100 \ K\)

\(\Delta x = 2-(2+1)\\\\\)

     \(= 2-(2+1)\\\\= 2-(3)\\\\= -1\)

\(\left\begin{array}{cccc}I\ (atm)&1&0.5&0\\C\ (atm)&2x&-x&2x\\E\ (atm) &1-2x&0.5-x&2x\end{array}\right\)

calculating the total pressure on equilibrium=  \((1-2x)+(0.5-x)+2x \ atm\\\\\)

                                                                         \(= 1-2x+0.5-x+2x\\\\= 1+0.5-x\\\\=1.5-x\\\)

\(\therefore \\\\\to 1.50-x= 1.35 \\\\\to 1.50-1.35= x\\\\\to 0.15= x\\\\ \to x= 0.15\\\\\)

calculating the pressure in  \(So_2\):

\(= (1-2 \times 0.15)\)

\(= 1-0.30 \\\\ =0.70 \ atm\)

calculating the pressure in  \(O_2\):

\(= (0.5- 0.15)\\\\= 0.35 \ atm \\\)

calculating the pressure in  \(So_3\):

\(= (2 \times 0.15)\\\\= (.30) \ atm \\\\\)

Calculating the Kp at 1100 K:

\(= \frac{(Pressure(So_3))^2}{(Pressure(So_2))^2 \times Pressure(O_2)}\\\\= \frac{0.30^2}{0.70^2 \times 0.35}\\\\= \frac{0.30 \times 0.30 }{0.70\times 0.70 \times 0.35}\\\\= \frac{0.09 }{0.49\times 0.35} \\\\= \frac{0.09 }{0.1715} \\\\= 0.5247 \ \ or \ \ 0.525 \ \ atm^{-1} \\\\\)

Answer: If a neutral atom gains electrons, then it will become negatively charged

Explanation: If a neutral atom gains electrons, then it will become negatively charged. If a neutral atom loses electrons, then it become positively charged.

In a protein molecule, the number of amino acid molecules may be as few as d. 50.

Proteins are large macromolecules composed of chains of amino acids. These amino acids are linked together through peptide bonds to form the primary structure of a protein. The number of amino acids present in a protein molecule can vary greatly and depends on the specific protein.

Proteins can range in size from small peptides composed of just a few amino acids to large complex proteins containing thousands of amino acids. The minimum number of amino acids required for a protein to be considered functional is typically around 50. This is because proteins need a certain length and structural complexity to carry out their specific functions.

Proteins play vital roles in living organisms and are involved in various biological processes such as enzyme catalysis, cell signaling, structural support, and immune response. The specific number and sequence of amino acids in a protein molecule determine its unique structure and function.

Therefore, while some proteins may consist of as few as 50 amino acids, larger and more complex proteins can contain thousands of amino acids, enabling them to perform intricate and diverse functions within living systems. Therefore, Option D is correct.

The question was incomplete. find the full content below:

In a protein molecule, the number of amino acid molecules may be as few as

a. 5

b. 5,000

c. 500

d. 50

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Answer: d

Explanation:because it makes sence i think

Answer:

I think its C a scientific journal article

Explanation:

Any kind of journal is considered a primary source because  journals contain info that the original author wrote. Encyclopedias are considered teritary sources, but im not sure if that counts ...so id go with journals.

A scientific journal article is  a primary source. Therefore, the correct option is option C among all the given options.

A primary source, also known as an original source, in the academic study of history is any item, document, journal, manuscript, biography, recording, or other source of data that was produced during the period being examined.

It acts as an authentic resource for knowledge on the subject. Although several domains have slightly distinct definitions, library science as well as other areas of academia might utilize comparable terms. A primary source in journalism might be a person who has firsthand knowledge of an event or a written account of it. A scientific journal article is  a primary source.

Therefore, the correct option is option C.

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Statements on salinity;

Salinity refers to the measure of the concentration of dissolved salts, such as sodium and chloride ions, in a body of water. It is usually expressed in parts per thousand (ppt) or practical salinity units (PSU).

Salinity can vary in different bodies of water due to factors such as evaporation, precipitation, freshwater input from rivers, and ocean currents.

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Answer:

Evaporation is a type of vaporization of a liquid that only occurs on the liquid's surface. Usually, the molecules in a glass of water do not have enough heat energy to escape from the liquid. With sufficient heat, however, the liquid would quickly turn into vapor.

Explanation:

Evaporation is a type of vaporization of a liquid that only occurs on the liquid's surface. Usually, the molecules in a glass of water do not have enough heat energy to escape from the liquid. With sufficient heat, however, the liquid would quickly turn into vapor.

The heat released by 100g of the compound is  2.8 x10^3 kJ .

We know that the process of combustion is the process that enables a substance to be burnt in air. Heat and light can be produced in the process of the combustion.

Number of moles of the Methylhydrazine =  mass/ molar mas = 100.0g/46 g/mol = 2.17 moles

If from the balanced reaction equation;

1 moles of Methylhydrazine produces 1.30x10^3 kJ

Then 2.17 moles of Methylhydrazine produces  2.17 moles *  1.30x10^3 kJ/1 mole

= 2.8 x10^3 kJ of heat.

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Answer: A

Explanation:

Answer:

strongly acidic

Explanation:

Soils can be classified according to their pH value: 6.5 to 7.5—neutral. over 7.5—alkaline. less than 6.5—acidic, and soils with pH less than 5.5 are considered strongly acidic.

If your typing this I would recommend that you don't copy this word for word because of plagerism I dont want to be the source for that. You may alternate it and put it in your own words tho :)

Answer:

Malleability

Explanation:

Answer:

Malleability is not chemical property

The concentration of AB, in mol/dm³, after 6 minutes : 0.125

For first-order reaction :

\(\tt [A]=[A]oe^{-kt}\rightarrow t1/2=\dfrac{ln~2}{k}\)

The half-life of the reaction is 2 minutes⇒t1/2=2 minutes

The concentration of AB, in mol dm, after 6 minutes ⇒ t=6 minutes

The rate constant (k) :

\(\tt k=\dfrac{ln~2}{t1/2}=\dfrac{0.693}{2}=0.3465\)

The concentration after 6 minutes :

\(\tt [A]o=0.1~mol/100~cm^3=1~~mol/dm^3\\\\(A]=1\times e^{-0.3465\times 6}\\\\(A]=0.125\)

Mass of Aluminum= 8.829 g

Given

Reaction

2Al + 6HCl → 2AlCl₃ + 3H₂

Required

mass of Aluminum

Solution

At STP, 1 mol gas = 22.4 L

For 11 L of Hydrogen :

= 11 : 22.4

= 0.491

From equation, mol ratio Al : H₂ = 2 : 3, so mol Al :

= 2/3 x mol H₂

= 2/3 x 0.491

= 0.327

Mass Aluminum(Ar=27 g/mol) :

= 0.327 mol x 27 g/mol

= 8.829 g

Answer: Mendeleev predicted elements that would later be discovered.

In the J = 0 state, the BrF molecule does not undergo any revolutions per second. In the J = 1 state, it undergoes approximately 0.498 revolutions per second, and in the J = 10 state, it undergoes approximately 15.71 revolutions per second.

To calculate the rotational constant B, we can use the formula:

B = 1 / (2 * π * Δν)

Where:

B = rotational constant

Δν = spacing between consecutive lines in the rotational spectrum

Given that the spacing between consecutive lines is 0.71433 cm^(-1), we can substitute this value into the formula:

B = 1 / (2 * π * 0.71433 cm^(-1))

B ≈ 0.079 cm^(-1)

The moment of inertia (I) of the molecule can be calculated using the formula:

I = h / (8 * π^2 * B)

Where:

h = Planck's constant

Given that the value of Planck's constant (h) is approximately 6.626 x 10^(-34) J·s, we can substitute the values into the formula:

I = (6.626 x 10^(-34) J·s) / (8 * π^2 * 0.079 cm^(-1))

I ≈ 2.11 x 10^(-46) kg·m^2

The bond length (r) of the molecule can be determined using the formula:

r = sqrt((h / (4 * π^2 * μ * B)) - r_e^2)

Where:

μ = reduced mass of the molecule

r_e = equilibrium bond length

To calculate the wavenumber (ν) of the J = 9+ to J = 10 transition, we can use the formula:

ν = 2 * B * (J + 1)

Substituting J = 9 into the formula, we get:

ν = 2 * 0.079 cm^(-1) * (9 + 1)

ν ≈ 1.58 cm^(-1)

To determine the most intense spectral line at room temperature (300 K), we can use the Boltzmann distribution law. The intensity (I) of a spectral line is proportional to the population of the corresponding rotational level:

I ∝ exp(-E / (k * T))

Where:

E = energy difference between the levels

k = Boltzmann constant

T = temperature in Kelvin

At room temperature (300 K), the population distribution decreases rapidly with increasing energy difference. Therefore, the transition with the lowest energy difference will have the most intense spectral line. In this case, the transition from J = 0 to J = 1 will have the most intense spectral line.

To calculate the number of revolutions per second, we can use the formula:

ω = 2 * π * B * J

Where:

ω = angular frequency (in radians per second)

J = rotational quantum number

For J = 0:

ω = 2 * π * 0.079 cm^(-1) * 0 = 0 rad/s

For J = 1:

ω = 2 * π * 0.079 cm^(-1) * 1 ≈ 0.498 rad/s

For J = 10:

ω = 2 * π * 0.079 cm^(-1) * 10 ≈ 15.71 rad/s

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In this question, we have the following reaction:

2 H2 + O2 -> 2 H2O

At STP (standard temperature and pressure), 1 mol of gas is equal to 22.4 Liters of volume, and also equal to 6.022*10^23 molecules or particles, and this is the Avogadro's constant number. For our question, we have 2 moles of H2, 1 mol of O2 and 2 moles of H2O, according to this, we will have:

1.204*10^24 molecules of H2

2 moles of H2

44.8 L of H2

6.022*23 molecules of O2

1 mol of O2

22.4 L of O2

1.204*10^24 molecules of H2O

2 moles of H2O

44.8 L of H2O

Answer:

\(\boxed {\tt Carbohydrate \ or \ monosaccharides}\)

Explanation:

There are 4 main types of macromolecules: lipids, proteins, carbohydrates, and nucleic acids.

If you are looking for some quick energy, the best choice is carbohydrates. Carbohydrates are the easiest for the body to break down and turn into ATP/energy.

There are also different types of carbohydrates. If you want a more specific answer, monosaccharides is the best answer. They are the simplest sugars. Also, glucose is a monosaccharide, and it shows up directly in the cellular respiration formula. If glucose is consumed, the body doesn't have to break it down before starting respiration.