2. A woman lifts up a laundry basket 1. 5m and carries it 20m across the room. This takes 15s.


Work is done on the laundry basket_*


(20 Points)


in walking across the room


during the entire 15s


work is not done


in lifting the basket

Initial velocity of car is 0.

Final velocity of car is 36 km/h.

Time taken to attain final speed is 2 minutes.

What is the acceleration of car ?

v = u + at

First change the final velocity from km/h to m/s and also time to seconds.

[ To change km/h to m/s multiply by 5/18 ]

➙ Final velocity = 36(5/18) = 10 m/s.

[ 1 minutes = 60 seconds ]

➙ 2 minutes = 2(60) = 120 seconds.

Now, we have

v = 10 m/s.

u = 0 m/s.

t = 120 s.

Hence, the acceleration of car is 0.083 m/s².

➟ The rate of change of velocity is called acceleration. It is denoted by a.

➟ The velocity at which motion starts is termed as initial velocity. It is denote by u.

➟ The last velocity of an object after a period of time. It is denoted by v.

\(\boxed{\large{\bold{\blue{ANSWER~:) }}}}\)

By 1st Equation of motion

we know that,

\(\boxed{\large{\sf{v \: = u \: + a \: t}}}\)

according to the question,

\(10 = 0 + a \times 120\\\\a \: = \frac{10}{120}\\\\a \: = \frac{1}{12}\\\\a=0.083\: m {s}^{ - 2}\)

Therefore,

Acceleration of the car is 0.083 ms^-2

Answer: i love you babe

Explanation:

The structure of a typical vertebra includes Pedicle, body, vertebral arch, etc. These are discussed in the section below.

Pedicle: The sides of the vertebral arch are formed by a pair of short, thick bony structures that protrude from the back of the vertebral body.

The thick, anterior section of the vertebra known as the "body" is what supports and supports the weight of the vertebral column.

Lamina: A pair of flat plates that combine to create the back of the vertebral arch and extend posteriorly from the pedicles.

The vertebral arch, which is made up of the pedicles and laminae, forms the posterior opening of the vertebra and surrounds and shields the spinal cord.

Articular facet: The superior and inferior portions of the vertebral arch's smooth, flat surfaces that form the facet joints when they articulate with the surrounding vertebrae.

The spinal cord goes through the vertebral foramen, which is the vertebral arch's main aperture.

Transverse process: Laterally extending bony projections from the sides of the vertebral arch that act as points of attachment for ligaments and muscles.

Spinous process: A single, posterior bony projection that arises from the laminae's junction and serves as a point of attachment for ligaments and muscles.

Thus, the vertebral body is the broad bone region that the question alludes to.

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Your question seems incomplete, the probable complete question is:

Label the structures of a typical vertebra. Pedicle ook Body of vertebra rences Lamina Vertebral arch Articular facet Vertebral foramen Transverse process Spinous Name the large bony area. process ME M < Prev 10 of 13 Next

1.When two objects collide, both objects experience forces that are equal in magnitude and opposite in direction. Such forces often cause one object to accelerate (gain speed) and another object to slow down (lose speed).

2. The effect of the forces experienced on the objects during the collision is different if the masses of the objects are different. The same  force causes different changes in velocity for objects with different masses. An object with a smaller mass has a greater change in velocity when the same force is applied.

A collision means that two objects collide with each other for a very short time. In other words, a collision is the interaction of two masses in a very short period of time, where the momentum and energy of the colliding masses change.

The law of conservation of momentum usually applies to collisions between two masses, but some collisions may involve kinetic energy. Depending on the conservation of energy there can be two types of conservation:

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The half-width of the central line is approximately 0.0401 radians.

The half-width of the central line (in rad) can be calculated using the formula:

θ = λ/d

where θ is the angle of diffraction, λ is the wavelength of light, and d is the slit spacing of the diffraction grating.

First, we need to find the distance between the slits (d).

Since the grating is 2.00 cm wide and has 3296 slits, we can find the distance as follows:

Substituting the given values, we have:

θ = (531 nm)/(3296 slits/cm x 2.00 cm)

θ = 0.0802 rad

Therefore, the half-width of the central line is approximately 0.0401 radians.

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Answer:

с

creates its own light, which is blocked by the Sun during an eclipse.

Explanation:

might not be right but its what i remember

Answer: the force applied to the object and the distance the object move Work can be calculated with this equation: Work equals Force x Distance.

Explanation:

Stars form from molecular clouds through a process known as stellar formation.

These clouds, characterized by low temperatures and high densities, provide the ideal conditions for atoms to combine and form molecules. With a mass range spanning from a few solar masses to millions of solar masses, molecular clouds serve as the birthplaces of new stars. The Pleiades cluster serves as a notable example of stars that have recently formed within such a stellar nursery.

The formation of stars from molecular clouds involves several key steps. Firstly, gravitational forces acting on regions of higher density within the cloud cause them to collapse under their own gravity. As the cloud collapses, it begins to fragment into smaller, denser clumps called protostellar cores. These cores continue to collapse, and their central regions become increasingly dense and hot. At this stage, they are known as protostars.

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457280.13 8 J change in gravitational potential energy is needed.

where

m = 68 kj

H = 2574 ft

where = 32 5 ft

a )if Gravitational potential energy is zero at see level .

then at strating

point,

Equation

G. P . E ( Ui ) = mgh

Change in G PE ;

AU = UJ - Vi

= mgy- mgh = mg ( H-h)

= 68 x9.81 [2574 - 325 0.3048

AU = 457280' 138 Joules

at top

GPE ( Uf ) = mgy

P . E = 0

GPF = Gravitational potential Energy .

at Top ape = 0

b)then change in GPE ;

ΔU = U(top) - Vata

= 0 - [-mg ( 4-h )]

= mg ( H-h j

= 68 * 9 . 81 [ 257 4 - 325 ) 0.3048

ΔU = 45 7280 . 13 8 J.

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The International Space Station takes approximately 90 minutes to complete one orbit around the Earth at an altitude of  about 340km.

The time it takes for the International Space Station to complete one orbit around the Earth is determined by the speed and altitude of the station. The station travels at a speed of approximately 28,000 kilometers per hour, fast enough to make one complete orbit every 90 minutes.

This means that the station travels approximately 17,500 miles per hour, or 28 times faster than the speed of sound. The altitude of the station, at around 340 km above Earth's surface, also affects the orbital period. At this altitude, the station experiences very little atmospheric drag, allowing it to maintain a stable orbit for an extended period.

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The buoyant force on a Styrofoam sphere that is 10% submerged in water is smaller that the buoyant force on a metal sphere that is 100% submerged in water, if the two volumes of the sphere are equal. Because water is incompressible, its density, stickiness, and other properties stay pretty much the same as you go deeper… and so the buoyant force stays the same as well.

A fluid's buoyancy, also known as upthrust, opposes the weight of an item that is partially or completely submerged by exerting an upward push. The weight of the fluid on top causes pressure in a fluid column to rise with depth. As a result, the pressure at the bottom of a fluid column is higher than at the top. Similar to this, an object submerged in a fluid experiences greater pressure at its bottom than it does at its top. A net upward force is exerted on the item as a result of the pressure differential. The size of the force equals the weight of the fluid that would otherwise fill the submerged volume of the item, direction, and its magnitude is proportional to the pressure difference.

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When polychromatic visible light shines through a diffraction grating, the central maximum will be visible as a mixture of the wavelengths present. option c

A diffraction grating is an optical element that separates white light into its component colors using an array of equally spaced, parallel slits.

A beam of light is diffracted by the grating to produce a series of spectra, the brightest of which is called the central maximum, with the other spectra organized around it. The angles and intensity of the spectra are determined by the wavelength of the light being diffracted, as well as the spacing and number of slits on the grating. Hence, option c is correct.

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Energy cannot be generated or destroyed; it can only be changed from one form of energy to another, according to the rule of conservation of energy. This implies that a system always possesses the same amount of energy, barring external energy addition.

According to the rule of conservation of energy, energy cannot be generated or destroyed. It can only be changed from one form to another, though. It is simply changed from a form that we can use to one that is less useful. Energy problem as a result of this

Energy efficiency is necessary to save expenses and extend the life of the resources.

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Intense light of a narrow range of wavelengths is called "monochromatic light." Monochromatic light consists of a single specific wavelength or color, typically produced by sources such as lasers or filtered light.

Unlike polychromatic light, which contains a broad spectrum of wavelengths, monochromatic light is highly focused and uniform in its color.

The narrow wavelength range allows for precise control and manipulation of light in various scientific, industrial, and medical applications.

Monochromatic light is utilized in fields such as spectroscopy, microscopy, optical communications, and phototherapy. Its distinct properties make it valuable for specific experiments and technologies that require light of a specific wavelength or color.

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Answer:    

Soil absorbs heat faster than sand, which absorbs heat faster than water. The air over Earth's surfaces absorbs heat from the materials of Earth.

Explanation:

Land surfaces absorb much more solar radiation than water. ... Water reflects most solar radiation that reaches its surface back to the atmosphere. Since land absorbs more solar radiation the land surface retains more heat as do the vegetation for energy. Thus, land surfaces warm more quickly than water.

Hope this helps!     Thank you,

Soil absorbs heat faster than sand, which absorbs heat faster than water. The air over Earth's surfaces absorbs heat from the materials of Earth.

When solar radiation strikes the earth's surface, land surfaces absorb the energy differently than ocean surfaces. They both heat up and cool down at different speeds.

Water takes longer to heat than land, but once heated, it keeps its heat for a longer period of time.

Land surfaces absorb far more solar energy than water. The majority of solar energy that reaches the surface of the water is reflected back into the atmosphere.

Because land absorbs more solar radiation, the land surface retains more heat, as does vegetation. As a result, terrestrial surfaces warm faster than water.

Hence soil absorbs heat faster than sand, which absorbs heat faster than water. The air over Earth's surfaces absorbs heat from the materials of Earth.

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Answer:b

Explanation:

The closest answer to our calculation is option B: 0.75 m.

To find the distance between Successive compressions, we need to calculate the wavelength of the sound wave. We can use the formula:
Wavelength = Speed of sound / Frequency
The speed of sound in air at STP (Standard Temperature and Pressure) is approximately 343 meters per second. Given that the frequency of the sound wave produced by the trumpet is 440 Hz, we can calculate the wavelength as follows:
Wavelength = 343 m/s / 440 Hz = 0.78 m

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Answer:

Because the ball is dropped, we are going to assume its initial velocity is 0. With that said, acceleration is essentially the change in the velocity versus the change in time, hence the unit m/s^2, which can be thought of as “meters per second per second.” The only force acting on the ball is gravity.

That being said, you can simply divide the change in velocity by the change in time, giving you an answer of 9.8 m/s^2, which is the value of g. Even if they did not give you a time, the answer would still always be the value of g (that is if the question pertains to earth), as acceleration due to gravity is a constant.

Explanation:

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The moment of inertia of a small ball on the end of a thin rod rotating in a horizontal circle of radius 1.2 m is 0.504 kg m². To keep the ball rotating at a constant angular velocity in the presence of air resistance, a torque of 0.024 Nm is needed.

a. The moment of inertia of the ball about the center of the circle is given by I = mr², where m is the mass of the ball and r is the radius of the circle. Substituting the given values, we get I = 0.35 kg x (1.2 m)² = 0.504 kg m².

b. The torque needed to keep the ball rotating at constant angular velocity is given by τ = Iα, where τ is the torque, I is the moment of inertia, and α is the angular acceleration. Since the ball is rotating at a constant angular velocity, α = 0, and the torque needed is zero.

However, air resistance exerts a force on the ball, which tends to slow it down. To counteract this force, an external torque must be applied in the opposite direction.

The magnitude of this torque is given by τ = Fr, where F is the force of air resistance and r is the radius of the circle. Substituting the given values, we get τ = 0.020 N x 1.2 m = 0.024 Nm.

In summary, the moment of inertia of a small ball on the end of a thin rod rotating in a horizontal circle of radius 1.2 m is 0.504 kg m². To keep the ball rotating at a constant angular velocity in the presence of air resistance, a torque of 0.024 Nm is needed.

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The electron and proton in a hydrogen atom would emit light with a wavelength of 600 nm when the electron is at a radius of approximately 0.053 nm and the total mechanical energy of the hydrogen atom is approximately -2.18 x 10⁻¹⁸

a. To calculate the radius at which the electron and proton in a hydrogen atom would emit light with a wavelength of 600 nm, we can use the formula for the Bohr radius:

r = n² × (h² / (4π² × m × e²))

The reduced mass, denoted as μ, is given by:

μ = (m\(_{e}\) × m\(_{p}\)) / (m\(_{e}\) + m\(_{p}\))

where m_e is the mass of the electron (9.109 x 10⁻³¹ kg) and m\(_{p}\) is the mass of the proton (1.673 x 10⁻²⁷ kg).

Substituting the values, we can calculate the radius:

μ = \(\frac{(9.109 x 10⁻³¹ kg × 1.673 x 10⁻²⁷ kg)}{(9.109 x 10⁻³¹ kg + 1.673 x 10⁻²⁷ kg)}\)

=9.093 x 10⁻³¹ kg

\(\frac{ (1² × (6.626 x 10⁻³⁴ J·s)²)}{(4π² × (9.093 x 10⁻³¹ kg)} (1.602 x 10⁻¹⁹ C)^²)\)

Now, let's calculate the radius:

r =  \(\frac{ (1 × (6.626 x 10¹³⁴ J·s)²)}{(4 × π² × (9.093 x 10⁻³¹ kg)} (1.602 x 10⁻¹⁹ C)²)\)

Calculating the expression, we find:

r = 0.053 nm

b. The total mechanical energy of the atom can be calculated using the formula:

E = - (k × e²) / (2 × r)

where E is the energy, k is the Coulomb constant (8.988 x 10⁹ N·m²/C²), e is the elementary charge, and r is the radius.

Substituting the values, we can calculate the total mechanical energy:

E = - (8.988 x 10⁹ N·m²/C² × (1.602 x 10⁻¹⁹ C)²) / (2 × 0.053 x 10⁻⁹ m)

Calculating the expression, we find:

E = -2.18 x 10⁻¹⁸J

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Answer:

40° (nice and warm)

Explanation:

40° is very cold (below freezing)

The given amplifier circuit is a common-source amplifier. The equivalent circuit diagram of the amplifier includes a MOSFET N5486 transistor. We can determine the drain current (ID) and drain-source voltage (VDS) using the following equations:

1. Voltage at the source terminal (VS) is calculated using Ohm's law: VS = IS x RS.2. The drain current (ID) can be calculated using the equation ID = IS (1 + GVin), where Vin is the input voltage, G is the voltage gain, and IS is the current flowing through RD.Let's calculate the values of ID and VDS:

Given:- IS = VDD / RD = 10V / 10Ω = 1A- Vin = -1V / (1.5 x 10^6Ω + 0.47μF) = -0.6666667μA (using voltage divider rule)- G = -RD / RS = -10Ω / 3kΩ = -0.003333 Calculating ID:ID = 1A (1 - 0.003333 x 0.6666667 x 10^6)≈ 0.997A = 997mACalculating VDS:VDS = VDD - IDRD= 10V - 997mA x 10Ω≈ 10V - 9.97V≈ 0.03VTherefore, the values of ID and VDS are approximately ID = 997mA and VDS ≈ 0.03V, respectively.

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Answer:

It should be shortened. hope this helps!:)

Answer:

Shortened

Explanation:

A longer pipe will have a longer wavelength, and therefore a lower frequency.

A shorter pipe will have a shorter wavelength, and therefore a higher frequency.

A "flat" note has a low frequency, so the pipe should be shortened.

The same phenomenon can be demonstrated with guitar strings.  The longer the string, the lower the pitch.

Answer:

The correct option is;

πR³(2/3 + (1/3)cos³θ - cosθ)

Explanation:

The volume of a segment of a sphere is given by the relation;

\(V = \pi \cdot h^2 \cdot \left (R - \dfrac{h}{3} \right)\)

We note that h = R - R·cos(θ)

Therefore by substituting the value of h in the equation of a segment of a sphere, we have;

\(V = \pi \cdot \left (R - R\cdot cos(\theta) \right ) ^2 \cdot \left (R - \dfrac{\left (R - R\cdot cos(\theta) \right )}{3} \right)\)

Which gives;

\(\dfrac{R^3\cdot \pi \cdot cos^3 (\theta) -3 \cdot R^3 \cdot\pi \cdot cos (\theta) + 2 \cdot R^3 \cdot \pi}{3}\)

\(R^3\cdot \pi \cdot \left (\dfrac{cos^3 (\theta) -3 \cdot cos (\theta) + 2 }{3} \right )\)

\(R^3\cdot \pi \cdot \left (\dfrac{cos^3 (\theta) + 2 }{3} - cos (\theta) \right )\)

\(R^3\cdot \pi \cdot \left (\dfrac{cos^3 (\theta) }{3} + \dfrac{2}{3} - cos (\theta) \right )\)

Therefore, the correct option is πR³(2/3 + (1/3)cos³θ - cosθ).

Answer:

emotions

Explanation:

emotions are how you feel and can happen any time

Hope it helps <333

Answer:

emotions affect your body and how you feel

Explanation:

\(from \: newton \: first \: equation \\ V = U + at \\ 0 = U + ( - 6 \times 2) \\ U = 12 \: m {s}^{ - 1} \\ from \: newtons \: third \: equation \\ {V}^{2} = {U}^{2} + 2aS \\ 0 = {12}^{2} + (2 \times - 12 \times \: S ) \\ 144 = 24S \\S = 6 \: m \)

The option that is not a requirement for the National Weather Service (NWS) to determine if a thunderstorm is severe is "frequent cloud to ground lightning" .

What is a thunderstorm ?

The thunderstorm is defined as "a rain-bearing cloud that also produces the lightning" .

and for the National Weather Service (NWS) a thunderstorm is termed as "severe" when it has the following :

(a) hail one inch or greater,

(b) winds gusting in excess of 50 knots (57.5 mph), or

(c) a tornado.

So , the only condition that is not for the severe thunderstorm is frequent cloud to ground lightning .

Therefore , the correct option is (a) .

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If the period of the oscillator doubles, the wavelength also doubles meanwhile the wave speed remain unchanged.

The wavelength is directly proportional to the period so when the period doubles the wavelength double and when the period decreases the wavelength decreases.  It can be demonstrating with the formulas:

λ = v / f     where v= velocity and f= frequency of the wave

f = 1 / T      where T= period

λ = \(\frac{v}{\frac{1}{T} }\)

λ = T*v

λ = 2Tv

If the period of the oscillator doubles, the wavelength also doubles.

v = \(\sqrt\frac{Ft}{\frac{m}{L} }\)  where Ft= tension, m= mass and L= length

From this question we can see that the speed doesn't depend on period. Therefore, if the period of the oscillator doubles, wave speed remain unchanged.

In physics, it is the spatial period of a periodic wave. It is the distance between identical points of two consecutive waves.

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Mass of the bumper =M2=1*10^5 kg

It is given that collision is inelastic and after Collision Both Boat and Bumber moves with 2m/see then, velocity from conservation of momentum.

M_{1}*v_{1} = (M_{1} + M_{2}) * v_{2}

(m_{1}*v_{1})/v - m_{1} =m 2

M_{2} =2*10^5*3/2-2*10^5 = 1*10^5 kg

According to the principle of momentum conservation, momentum is only modified by the action of forces as they are outlined by Newton's equations of motion; momentum is never created nor destroyed inside a problem domain.

Conservation of momentum states that the center of mass's mass times velocity remain constant. Conserving Angular Momentum: The system's overall angular momentum is constant. Newton's Third Law: Since all internal forces occur in pairs, there can be no net force generated within the system.

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If we know the stall torque and no load speed of a pm dc motor, the maximum power motor can deliver is P max = 1/2* Tstall * 1/2* ω(no load).

A mechanical device that produces stall torque has an output rotational speed of zero. Electric motors are capable of developing torque when stalled.

However, as the current flowing is at its maximum while an electric motor is halted, they are vulnerable to overheating and potential damage.

The no load speed is the speed when running at nominal voltage and zero load.

So, the maximum power motor can deliver is P max = 1/2* Tstall * 1/2* ω(no load).

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