This is an example of elimination reaction which is resulting in the formation of 1-butene.
A sort of chemical process called an elimination reaction involves the removal of a number of atoms from a molecule, usually in pairs or groups. The elimination typically occurs as a result of the activity of metals, acids, and bases. The procedure of heating at elevated temps can also cause it.
The kind of atoms or clusters of atoms that are expelled from the molecule is a typical way to identify elimination processes. Dehydrohalogenation, for instance, is the elimination of a hydrogen atom and a halogen atom; dehalogenation is the reaction's name when both departing atoms are halogens.
Methoxide will deprotonate the butane 1-methyl group, forming a carbon-carbon double bond in the second position and rupturing the carbon-bromine bond all at once.
As a consequence, 1-butene is produced.
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What is physical since ?
Answer:
Phycical science is the study of the body.
Explanation:
I NEED HELP! An iron cube is placed in liquid water. Which particles have the higher kinetic energy?
Answer:
Liquid water has higher kinetic energy thn iron cube
Explanation:
Please mark as brainliest
which of the following objects will expert the greatest gravitational force on a box, if the distance between them remains the same? 2 kg mass 4 kg mass 6 kg mass 8 kg mass
PLEASE HELP!!!
In the mass spectrum of pentane, the presence of a peak with an m/z = 29 most likely is due to the loss of what radical from the molecule?
In the mass spectrum of pentane, the presence of a peak with an m/z = 29 most likely is due to the loss of butyl radical from the molecule.
A spectrum (spectra or spectra) is a state that is not confined to a particular set of values and can vary seamlessly on a continuum. The term was first used scientifically in optics to describe the rainbow colors of visible light after passing through a prism.
The Spectrum of Life in the Hall of Biodiversity is an evolutionary journey through the incredible diversity of life on Earth. The 1,500 specimens represent a wide range of bacteria, fungi, plants and animals, from the smallest microbes to giants of land and water. A spectrum is defined as the characteristic wavelengths of electromagnetic radiation (or parts thereof) emitted or absorbed by an object or substance, atoms or molecules. Examples of spectra include the rainbow, the colors of the sun's emission, and infrared absorption wavelengths of molecules.
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gosh i rly need help in the previous questions I asked and no one answered I wish I was smart to answer them alone why am I d.umb
Answer:
gonna check them rn :) youre not d u mb dont worry (:
How would you make 41 mL of 43% vinegar in water solution?
41ml of 43% vinegar in water solution can be made by mixing 17.63ml vinegar in 23.37ml of water.
According to condition, the total volume of the solution to be made should be 41ml and it should have a concentration of 43% of vinegar in it.
43% of the 41ml can be calculated using percentage formula, we can find the concentration required,
Let say we have to add L ml of vinegar to make the solution, then,
%age = Amount to be obtained/ total amount x 100
43 = L/41 x 100
L = 41 x 43/100
L = 1763/100
L = 17.63 ml.
Total volume of the solution is 41ml,
So the amount of the water needed,
Water needed = 41ml - 17.63ml
water needed = 23.37ml
So we can conclude,
41ml of 43% vinegar in water solution can be made by mixing 17.63ml of vinegar with 23.37ml of water.
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Please help me with this! It’s not timed so take your time!
Answer:
pretty sure they're called groups
Which of the following liquids is most volatile? Select one: a. cooking oil b. motor oil c. alcohol d. water
Answer:
Alcohol.
Explanation:
It has the lowest boiling point and high vapour pressure.
Add curved arrows to the reactant side of the following SN2 reaction to indicate the flow of electrons. Dravw the product species to show the balanced equation, including nonbonding electrons and formal charges Do draw in the leaving group as well as the main organic product, adn show the lone pairs and formal charge on the leaving group.
A graphic showing curved arrows pointing to the catalyst surface of the provided SN2 reaction to represent the passage of electrons cannot be produced since the statement is not complete.
When drawing in the leaving group and the major organic product, as well as showing the lone pairs with formal charges on the leaving group, the product species should be used to demonstrate the balanced equation, nonbonding electrons, and formal charges.
What do lone pairs mean?Lone pairs are those valence electrons in a covalent connection that are not shared with another atom.
One bond is ruptured and another is completed in one step in a chemical reaction known as an SN2 reaction.
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how to build 6 individual atoms?
The 6 models of the atom:
1. John Dalton's atomic model: Daltons Billiard Ball (Solid Sphere) Model
2. J.J. Thomson's model: Plum Pudding model
3. Ernest Rutherford's model: Nuclear model
4. Niels Bohr's model: Planetary model
5. Erwin Schrdinger's model: Electron Cloud Model/Quantum Model
6. Wave mechanical model
AtomThe smallest component that makes up a chemical element is an atom. Atoms that are neutral or ionized are the building blocks of all solids, liquids, gases, and plasma. A normal atom is 100 picometers across, which is incredibly small. Because of quantum effects, they are so small that it is impossible to predict their behavior with sufficient precision using classical physics, as if they were, say, tennis balls. One or more electrons are attached to the nucleus of every atom, which is made up of a nucleus. Protons and neutrons, in various numbers, make up the nucleus. Neutrons exist only in the most prevalent type of hydrogen. An atom's nucleus makes up more than 99.94% of its mass.
how to build 6 individual atoms?
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What color are the stars on the diagram with the lowest surface temperatures?
Answer:
red supergiants is the answer
If you react 59.54 g of S and 78 g of HNO3, how many grams of NO2 can you
theoretically produce?
S + 6 HNO3 + H2SO4 + 6 NO2 + 2 H2O
Answer:
56.94759 grams of NO2
Explanation:
Stoichiometric Equation:
1 S + 6 HNO3 → 1 H2SO4 + 6 NO2 + 2 H2O.
This is so you can create ratios between each compound in the reaction, and identify the limiting and excess reactants to determine exactly how much can be produced?
The coefficients or molecular quantity of each compound in the balanced equation represents the amount of moles.
To figure out how much can be produced, you have to convert 59.54 g of S into moles of S and 78 g of HNO3 into moles of HNO3.
A reference such as a periodic table can be very helpful as it has the atomic mass of each element which is the mass with respect to 1 mol of that element.
what are two ways in which minerals can form from a solution? read more >>
Evaporation and crystallization are two common processes by which minerals form from a solution. Here option C is the correct answer.
When a solution containing dissolved minerals is left undisturbed, the water content of the solution gradually decreases through evaporation. As the water evaporates, the concentration of dissolved minerals increases, eventually reaching a point where the solution becomes supersaturated.
At this stage, the excess minerals start to come together and form solid crystals. This process is known as crystallization. Evaporation and crystallization commonly occur in environments with high rates of evaporation, such as hot and arid regions or shallow bodies of water.
Examples of minerals formed through evaporation and crystallization include halite (rock salt), gypsum, and borax. These minerals often precipitate and accumulate in layers, forming distinctive sedimentary deposits.
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Complete question:
Which of the following are two ways in which minerals can form from a solution?
A) Sublimation and condensation
B) Fusion and solidification
C) Evaporation and crystallization
D) Oxidation and reduction
what is the hydronium-ion concentration of a 0.210 m oxalic acid, h2c2o4, solution? for oxalic acid, ka1
The hydronium-ion concentration of a 0.210 m oxalic acid solution is 0.205 M.
How to calculate the hydronium ion concentration of a solution?The hydronium-ion concentration of a solution of oxalic acid (\(H_{2}C_{2}O_{4}\) ) can be calculated using the acid dissociation constant (Ka) for the first dissociation step (Ka1) of oxalic acid, which is 5.90 x \(10^{-2}\) at 25°C.
The balanced chemical equation for the dissociation of oxalic acid in water is:
\(H_{2}C_{2}O_{4}\) (aq) + \(H_{2}O\) (l) ⇌ \(H_{3}O^{+}\) (aq) + \(HC_{2}O_{4}^{-}\) (aq)
Oxalic acid has two dissociation constants (ka1 and ka2), but we are only given ka1, which is 5.90 × \(10^{-2}\). This constant is used to find the concentration of H+ ions produced by the first dissociation step of oxalic acid:
ka1 = [H+][C2O4 2-] / [\(HC_{2}O_{4}^{-}\)]
We can assume that the concentration of [\(C_{2}O_{4}^{2-}\)] is negligible compared to [\(HC_{2}O_{4}^{-}\)] and [H+], so we can simplify the equation to:
ka1 = [H+]^2 / [\(HC_{2}O_{4}^{-}\)]
Solving for [H+], we get:
[H+] = sqrt(ka1 x [\(HC_{2}O_{4}^{-}\)])
Plugging in the given concentration of oxalic acid (0.210M), we get:
[H+] = sqrt(5.90 × \(10^{-2}\) x 0.210) = 0.205 M
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What is the pH of a solution that contains 20.0% acetic acid and
80.0% sodium acetate by concentration?
Hint: The pKa of acetic acid is 4.76.
The pH of the solution is 5.23.
The pH of a solution that contains 20.0% acetic acid and 80.0% sodium acetate by concentration can be calculated using the Henderson-Hasselbalch equation.
The equation is given by:
pH = pKa + log([A-]/[HA])Where:
pKa = 4.76[A-] is the concentration of the acetate ion
[HA] is the concentration of the acetic acid ion
pH is the solution pH
We can obtain [HA] and [A-] using the percentages given.
Since the percentages given are by weight, we can assume that the total weight of the solution is 100g.
Then we can find the masses of acetic acid and sodium acetate in the solution.
Mass of acetic acid = 20.0% of 100g = 20g
Mass of sodium acetate = 80.0% of 100g = 80g
The molar masses of acetic acid and sodium acetate are:
Acetic acid = 60.05 g/mol
Sodium acetate = 82.03 g/mol
Using the mass and molar mass, we can find the number of moles of each substance:
For acetic acid:20 g / 60.05 g/mol = 0.333 mol
For sodium acetate:80 g / 82.03 g/mol = 0.976 mol
The total number of moles in the solution is:
0.333 mol (acetic acid) + 0.976 mol (sodium acetate) = 1.309 mol
We can use this to find the molarities of acetic acid and acetate ion:
Acetic acid molarity = 0.333 mol / 0.100 L = 3.33 M
Acetate ion molarity = 0.976 mol / 0.100 L = 9.76 M
Now we can plug these values into the Henderson-Hasselbalch equation:
pH = 4.76 + log([9.76]/[3.33])pH = 4.76 + log(2.935)pH = 4.76 + 0.467pH = 5.23
Therefore, the pH of the solution is 5.23.
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a) C8H18
Name the organic compound
Answer:
Explanation:
Octane
Octane is a straight chain alkane composed of 8 carbon atoms.
.Which of the following is not a part of Dalton's atomic theory?
A
All matter is composed of indivisible atoms.
B
The properties of atoms of the same element can be different.
C
Compounds form when atoms combine in whole number ratios.
D
An atom can neither be created nor destroyed.
The answer is B - The properties of atoms of the same element can be different. This is not a part of Dalton's atomic theory. According to Dalton's atomic theory, all matter is composed of indivisible atoms, compounds form when atoms combine in whole number ratios, and an atom can neither be created nor destroyed.
Your answer: B - The properties of atoms of the same element can be different.
This statement is not a part of Dalton's atomic theory, as according to his theory, atoms of the same element have the same properties.
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how many electrons should be shown in the lewis dot structure for hydrogen?
The Lewis dot structure for hydrogen should show one electron. Hydrogen (H) has one electron in its outermost energy level, known as the 1s orbital.
In the Lewis dot structure, also known as the Lewis structure or electron dot structure, the valence electrons of an atom are represented by dots placed around the atomic symbol.
Hydrogen (H) has one electron in its outermost energy level, known as the 1s orbital. Therefore, in the Lewis dot structure for hydrogen, we represent this lone valence electron as a single dot placed next to the atomic symbol H. Since hydrogen has only one electron, only one dot is shown in its Lewis dot structure.
The Lewis dot structure for hydrogen is H •
The dot represents the single valence electron of hydrogen.
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The following properties are either physical or chemical. Which one is different from the rest, based on those two categories ?
A. Boiling Point
B. Flammability
C. Magnetism
D. Thermal conductivity
Answer:
B. Flammability
I know because I am a chemistry FLVS student
I left explanations just in case you wanted to know why.
Explanation:
I have seen no one with the correct answer so I'm here to help
A. Boiling point- this is a physical property if you boil water, it evaporates it is still water just a different form, the molecules inside are the same just arranged differently making it a physical property.
B. Flammability- this is a chemical property. Flammability is a chemical property. It describes how easily a substance can be set on fire. This is very important when it comes to building safety.
C. Magnetism- this is a physical property. This is an intensive physical property. a physical property that is not dependent on sample size. Magnetism, density, melting and boiling points, and color are classified as intensive physical properties. Intensive properties do not depend on the size of the sample. No matter how much or how little of the substance you have, an intensive physical property stays the same.
D. Thermal conductivity- this is a physical property. The ability of a substance to conduct an electrical charge or heat is measured by conductivity. It is a physical property because the identity of the substance used is not changed i.e. no change in chemical composition. It just transmits the form of energy, such as electricity or heat.
.
Which sequence is most correct?
galaxies began to form; stars were born in galaxies; planetary systems (like the solar system) formed around some stars; dust and gases in space drawn together by gravity
dust and gases in space drawn together by gravity; planetary systems (like the solar system) formed from dust and gases around some stars; galaxies began to form; stars were born in galaxies
dust and gases in space drawn together by gravity; galaxies began to form; stars were born in galaxies; planetary systems (like the solar system) formed around some stars
dust and gases in space drawn together by gravity; stars were born in galaxies; galaxies grew from dust and gas clouds; planetary systems (like the solar system) formed around some stars
(its actually not chemistry its science)
dust and gases in space drawn together by gravity; galaxies began to form; stars were born in galaxies; planetary systems (like the solar system) formed around some stars
Describe the change that you made that led to the increase in the size of the clawcat population. Explain why the change led to an increase in the clawcat population size.
The first step is to lessen the number of the organism which consumes clawcats. The second is to enhance the resources Clawncat requires to live.
What is population?Population is the total number of people living in a region (such as a nation or the planet), which is always changing due to births, immigration, and natural mortality.
There are two ways to boost the Clawcat population. The first step is to lessen the number of the organism which consumes clawcats. The second is to enhance the resources Clawncat requires to live, namely by expanding the plantation of Clawncat, providing enough irrigation, giving full access to sunshine, and increasing the richness of the soil through proper and effective fertilization.
Therefore, in the above given ways we can increase the population of Clawncat.
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a 2.5000 g sample of epsom salt (maghesiun sulfate hydrate) is heated until the crystals arereduced to a dry powder. after cooling the residue was found to weigh 1.7525 g. calculate g
The mass of the water of crystallization is 0.7475 g.
What is the mass of the water?We know that a hydrated compound is a compound that contains in it the water of crystallization. This is the water that becomes attached to the structure of the compound that is in question.
In this case, we have that the salt that is question is a hydrate of magnesium sulfate and we have.
Mass of the hydrated salt = 2.5000 g
Mass of the anhydrous salt = 1.7525 g
Mass of water present = 2.5000 g - 1.7525 g
= 0.7475 g
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Missing parts;
A 2.5000 g sample of epsom salt (maghesiun sulfate hydrate) is heated until the crystals arereduced to a dry powder. after cooling the residue was found to weigh 1.7525 g. calculate the mass of the water.
describes a chemical weathering process where the products are typically . oxidation / coal beds hydrolysis / clay minerals precipitation / dissolved bicarbonate ions dissolution / iron oxides (hematite)
Answer: The chemical weathering process that dissolves iron oxides (hematite) is called dissolution.
What is chemical weathering?
Chemical weathering is the process by which rocks and minerals are broken down by chemical reactions. This kind of weathering transforms the original composition of rocks and minerals into new compounds that are more stable at the Earth's surface. Chemical weathering can change the overall appearance, strength, and porosity of rocks over time.
Types of chemical weathering processes Chemical weathering processes can take a variety of forms, such as: Hydrolysis ,Oxidation, Carbonation ,Dissolution.
Students must keep in mind that these processes may occur simultaneously in a specific area to produce new minerals with varied properties. And among the different chemical weathering processes, the one that dissolves iron oxides (hematite) is called dissolution.
What is dissolution?
The process in which a chemical compound is dissolved in a solvent is known as dissolution. It is a physical change rather than a chemical change since the chemical composition of the substance being dissolved is not altered. Dissolution is used in many processes, such as extracting and separating minerals, preparing solutions, purifying liquids, and so on.
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A sample of gas has a pressure of 600 volume of 2.5 L, and a temperature of 22°C . If the pressure is changed to 760 mmHg and the volumes changed to 1.8L what will the new temperature be in K?
A) -4K
B)269K
C)-8K
D)435K
it is A it got to be A)-4k
Explanation:
What is the mass number of hydrogen? DUE TODAY!!!!
Compared to the atom of calcium -40, an atom of potassium - 39 contains fewer ______,
Protons (the number on the right of calcium-40 represents number of protons). The tiniest component of ordinary matter, an atom, makes up a chemical element.
Neutral or ionized atoms make up every solid, liquid, gas, and plasma. Atoms typically have a diameter of 100 picometers or less. Due to quantum effects, they are so small atoms that it is impossible to precisely anticipate their behavioral using traditional physics, as if they were tennis balls, for example.
The positively charged particles called protons are found in the hydrogen atom's nucleus. Protons, electrons, and neutrons are the building blocks of an atom. An atom's nucleus, which is located in the middle, contains all of its mass.
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When alkaline hydrolysis was first invented what jobs were people hiring to do?
When alkaline hydrolysis was first invented, people were hired for various roles related to the process and implementation of this technology. Some of the jobs that emerged include Chemical engineers, Technicians and operators, Waste management specialists, Scientists and researchers.
Chemical engineers: These professionals played a crucial role in developing and optimizing the alkaline hydrolysis process. They were responsible for designing the equipment, developing the necessary chemical reactions, and ensuring the efficient operation of the system.
Technicians and operators: Skilled technicians and operators were hired to operate and maintain the alkaline hydrolysis equipment. They were trained to monitor the process parameters, handle the chemicals involved, and ensure the proper functioning of the system.
Waste management specialists: With the introduction of alkaline hydrolysis as a method for disposal of organic waste, specialized professionals in waste management were employed to oversee the proper handling and treatment of the waste materials. They were responsible for implementing safety protocols, managing waste streams, and complying with environmental regulations.
Scientists and researchers: Alkaline hydrolysis required scientific expertise for continuous improvement and innovation. Scientists and researchers were hired to study the process, analyze the results, and explore potential applications in various fields such as biofuel production and chemical synthesis.
Overall, the introduction of alkaline hydrolysis created employment opportunities for professionals in engineering, chemistry, waste management, and research, among others, as this technology gained recognition and adoption.
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What is the coefficient of the permanganate ion when the following equation is balanced? mno4- br- → mn2 br2 (acidic solution)
In acidic solition, the coefficient of permanganate ion in the balanced redox equation is 2.
How can a redox equation be balanced?A redox equation showing a reduction and an oxidation reaction occurring simultaneously.
To balance redox equations, the atoms reacting as well as the electrons transferred are balanced.
In the reaction of permanganate ion and bromide ion in acidic solution, the balanced redox equation is given as follows:
2 MnO4- + 10Br- + 16 H+ → 2 Mn2+ 5 Br2 + 8 H2OTherefore, the coefficient of permanganate ion in the balanced redox equation is 2.
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The coefficient of the permanganate ion of the MNO₄ - Br- → MN₂ + Br₂ is 2.
What is a redox reaction?A redox equation depicting a simultaneous reduction and oxidation reaction.
The atoms reacting as well as the electrons transferred must be balanced to balance redox equations.
The balanced redox equation for the reaction of permanganate ion and bromide ion in acidic solution is:
\(\rm 2 MnO_4- + 10Br^- + 16 H^+ \rightarrow2 Mn_2+ 5 Br_2 + 8 H_2O\)
Thus, the coefficient of the permanganate ion of the MNO₄ - Br- → MN₂ + Br₂ is 2.
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If you add 5.0 mL of 0.50 M NaOH solution to 20.0 mL to Buffer C, what is the change in pH of the buffer? (where buffer C is 8.203 g sodium acetate with 100.0 mL of 1.0 M acetic acid)
The initial pH of the buffer is not given, we cannot determine the exact change in pH. The final pH of the buffer after adding NaOH is 4.762.
To determine the change in pH of buffer C after adding 5.0 mL of 0.50 M NaOH solution, we first need to calculate the moles of acetic acid and sodium acetate in the buffer. Then, we will calculate the moles of NaOH added and finally use the Henderson-Hasselbalch equation to determine the change in pH.
1. Calculate moles of acetic acid and sodium acetate:
Buffer C has 8.203 g of sodium acetate and 100.0 mL of 1.0 M acetic acid.
Moles of sodium acetate = (8.203 g) / (82.03 g/mol) = 0.1 mol
Moles of acetic acid = (100.0 mL) * (1.0 mol/L) = 0.1 mol
2. Calculate moles of NaOH added:
Moles of NaOH = (5.0 mL) * (0.50 mol/L) = 0.0025 mol
3. Determine moles of acetic acid and sodium acetate after the reaction:
NaOH will react with acetic acid, producing water and sodium acetate.
Moles of acetic acid after reaction = 0.1 mol - 0.0025 mol = 0.0975 mol
Moles of sodium acetate after reaction = 0.1 mol + 0.0025 mol = 0.1025 mol
4. Calculate the new pH using the Henderson-Hasselbalch equation:
pH = pKa + log ([sodium acetate] / [acetic acid])
The pKa of acetic acid is 4.74.
pH = 4.74 + log (0.1025 mol / 0.0975 mol) = 4.74 + 0.022 = 4.762
5. Determine the change in pH:
Since the initial pH of the buffer is not given, we cannot determine the exact change in pH. However, the final pH of the buffer after adding NaOH is 4.762.
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a solution containing a mixture of metal cations was treated as outlined. dilute hcl hcl was added and no precipitate formed. h2s h 2 s was bubbled through the acidic solution. a precipitate formed and was filtered off. the ph was raised to about 9 9 and h2s h 2 s was again bubbled through the solution. a precipitate formed and was filtered off. finally, sodium carbonate was added to the filtered solution and no precipitate formed. what can be said about the presence of each of these groups of cations in the original solution?
The tests suggest that the original solution contains Group 2 cations (Zn²⁺, Cd²⁺, Pb²⁺), Group 3 cations (Fe³⁺), and possibly Group 4 cations (Ni²⁺, Co²⁺), but does not contain Group 1 cations, Group 2 cations (Mg²⁺), Group 3 cations (Al³⁺), Group 4 cations (Mn²⁺), or Group 5 cations (Cu²⁺).
No precipitate formed when dilute HCl was added, indicating the absence of Group 2 cations (Ca²⁺, Sr²⁺, Ba²⁺) and Group 3 cations (Al³⁺). When H₂S was bubbled through the acidic solution, a precipitate formed and was filtered off. This indicates the presence of Group 2 cations (Zn²⁺, Cd²⁺, Pb²⁺), Group 3 cations (Fe³⁺, Al³⁺), and Group 4 cations (Ni²⁺, Co²⁺, Mn²⁺).
The pH was raised to about 9 and H₂S was bubbled through the solution again. Another precipitate formed and was filtered off. This indicates the presence of Group 4 cations (Ni²⁺, Co²⁺) and Group 5 cations (Cu²⁺). Finally, sodium carbonate was added to the filtered solution and no precipitate formed, indicating the absence of Group 1 cations (Li⁺, Na⁺, K⁺), Group 2 cations (Mg²⁺, Ca²⁺, Sr²⁺, Ba²⁺), Group 3 cations (Al³⁺), Group 4 cations (Ni²⁺, Co²⁺, Mn²⁺), and Group 5 cations (Cu²⁺).
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