A triangle has vertices at A (−2, −2), B (−1, 1), and C (3, 2). Which of the following transformations produces an image with vertices A′ (−2, 2), B′ (−1, −1), and C′ (3, −2)?
Jessie has a board that is 8 feet long how many 1/4 foot sections can she cut from this board
Answer:
2.
Step-by-step explanation:
Divide 8 by 1 over 4. The line in a fraction represents the division line. 1/4 is 0.25, so you do 0.25 x 8. Hope this helps!
Find the values of X and y in the diagram.
The ________ of event a is the event consisting of all simple events in the sample space s that are not in a.
Answer:
I think it is complement. Not so sure so sorry If i get it wrong I haven't done this in 2 or 3 years
Step-by-step explanation:
what is the value of x
Answer:
X=6
Step-by-step explanation:
Simplify:
(2p^3x)^3 = 8p^54 into:
2p^3x = 2p^18
p^3x = p^18
3x = 18
x=6
could you help me with this question
Answer: the thing in your photos of June fifth grade or something but the thing in your account says that you were in high school what does that mean
Step-by-step explanation:
The value of XY if Y is between X and Z, XY = 3a, XZ = 5a-4, and YZ = 14
What’s the answer ?? Please help
Answer: 27
Step-by-step explanation:
\(XY+YZ=XZ\\\\3a+14=5a-4\\\\14=2a-4\\\\18=2a\\ \\ a=9\\\\\implies XY=3(9)=27\)
Find the coordinates of the midpoint of MN with endpoints M(-2,6) and N(8,0).
(3,2)
(1,0)
(8,0)
(3,3)
Answer:
(3, 3)
Step-by-step explanation:
Use the midpoint formula (x1+x2/2, y1+y2/2)
so its (-2+8/2, 6+0/2)
which is (3,3)
Sonequa has two containers one in the shape of a cylinder and the other in the shape of a cone the two containers of equal radii and equal Heights she investigated the relationship between the volume of the cone and the cylinder by transferring water between the two containers which of the following claims is most likely to be supported using the result of sonequa investigation
Answer:35
Step-by-step explanation:
The volume of a cylinder is calculated by multiplying the area of its base by its height. The formula for the volume of a cylinder is V = πr²h, where r is the radius of the base and h is the height.
The volume of a cone is calculated by multiplying the area of its base by its height and then dividing by 3. The formula for the volume of a cone is V = (1/3)πr²h, where r is the radius of the base and h is the height.
Since Sonequa’s two containers have equal radii and equal heights, it can be concluded that the volume of the cylinder is three times the volume of the cone. This means that if Sonequa fills the cone with water and pours it into the cylinder, she will need to repeat this process three times to fill the cylinder completely.
So, the claim that is most likely to be supported using the result of Sonequa’s investigation is: “The volume of a cylinder with the same radius and height as a cone is three times greater than the volume of the cone.”
Determine the measure of <1 in the figure.
Answer:
∠1 = 36°
Step-by-step explanation:
The triangle in the image is a right triangle.
The sum of interior angles in a triangle is equal to 180° and one of the angles is given as 54° while the other would be 90° since this is a right triangle.
90 + 54 + ∠1 = 180 add like terms
144 + ∠1 = 180 subtract 144 from both sides
∠1 = 36°
The sales tax rate is 10%. Of Tim buys a plastic bowl priced at $1, how much will he pay?
Answer:
$1.10
Step-by-step explanation:
If sales tax is ten percent then Tim's tax will be 10 cents
3/4 + 1/2 + 1/3 sum to infinity
Answer:
18/12
Step-by-step explanation:
Answer:
5/3 or u could make it 5/4 since only 2 n 4 can have 2468 u cant put 4 back
Step-by-step explanation:
In a certain week, the time Lisa spent on
sport was 3 hours less than twice the time
she spent doing her school homework. The
time she spent on reading was of the time
she spent doing her school homework. The
total time she spent on these three
activities was 30 hours in that week. Form
an equation and solve it to find the amount
Answer:
2M + 3 hrs
Step-by-step explanation:
Lisa spent doing her mathematics homework = M hrs
the amount of time spent watching television was 3 hours more than twice the time she spent doing her mathematics homework.
lisa spent on watching television = 2M + 3 hrs
Total time spent on these two activities = M + 2M + 3
= 3M + 3 hrs
3 M + 3 = 30
=> 3M = 27
M = 9
What is the equation of the line of best fit for the following data? Round the
slope and yintercept of the line to three decimal places.
Need help ASAP!!
Answer:
The second choice should be the best fit line.
find the exact value of sin(0) when cos(0) =3/5 and the terminal side of (0) is in quadrant 4
When the cosine of an angle (0) is 3/5 and the angle lies in quadrant 4, the exact value of the sine of that angle is -4/5.
To find the exact value of sin(0), we can utilize the Pythagorean identity, which states that \(sin^2(x) + cos^2(x) = 1,\) where x is an angle in a right triangle. Since the terminal side of the angle (0) is in quadrant 4, we know that the cosine value will be positive, and the sine value will be negative.
Given that cos(0) = 3/5, we can determine the value of sin(0) using the Pythagorean identity as follows:
\(sin^2(0) + cos^2(0) = 1\\sin^2(0) + (3/5)^2 = 1\\sin^2(0) + 9/25 = 1\\sin^2(0) = 1 - 9/25\\sin^2(0) = 25/25 - 9/25\\sin^2(0) = 16/25\)
Taking the square root of both sides to find sin(0), we have:
sin(0) = ±√(16/25)
Since the terminal side of (0) is in quadrant 4, the y-coordinate, which represents sin(0), will be negative. Therefore, we can conclude:
sin(0) = -√(16/25)
Simplifying further, we get:
sin(0) = -4/5
Hence, the exact value of sin(0) when cos(0) = 3/5 and the terminal side of (0) is in quadrant 4 is -4/5.
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Note the correct and the complete question is
Q- Find the exact value of sin(0) when cos(0) =3/5 and the terminal side of (0) is in quadrant 4 ?
confused on how to read the diagram for the questions..
Answer:
mode in class 8A = 157 cm
mode in class 8B = 176 cm
median in class 8B = 165 cm
range in class 8A = 173-148= 25 cm
• many students class 8A are taller than class 8B
• the tallest student is in class 8B
The Moon appears to be 0.50wide in the sky. If the Moon's diameter is 3,480 km, how far away is it from the Earth in kilometers km Part 1 of 3 We can use the small angle approximation to relate the physical size and distance of objects in the sky to their angular size. angular diameter d 2.06 x 10' arc seconds/radian D Part 2 of 3 If the Moon is 0.50° across on the sky, we need to first figure out how big that is in are seconds. (Give the number of arc seconds in one degree, and then give the angular diameter in arc seconds) 1 degree = Nas arc seconds = 3600 3600 arc seconds as deg as arc seconds/degree = 1800 35 1800 are seconds Part 3 of 3 How far away (in km) is the Moon (3,480 km linear diameter) from the Earth if it has this angular diameter on the sky Solving for in the small angle formula gives us: 4.2.06 10 arc seconds/radian Dm a as km Submit Skip
The D = (Dm/2) / tan(α)D = (3480/2) / tan(0.004848)D = 3.84 x 10⁵ kmHence, the distance between the Moon and Earth is 3.84 x 10⁵ km.
Part 1 of 3The small angle approximation formula is given by:tan(α) = (opposite side) / (adjacent side)The opposite side is the diameter of the moon, Dm
.α is the angular diameter of the Moon in radians.D is the distance between the Moon and the Earth.In the question, the angular diameter of the Moon is given as 0.50°.
So, we first convert this to arc seconds using the formula:1 degree = 60 minutes of arc1 minute of arc = 60 seconds of arcSo,1 degree = 60 x 60 = 3600 seconds of arc
Therefore, the angular diameter of the Moon in arc seconds is:0.50° x 3600 = 1800 arc seconds Part 2 of 3
We know that the angular diameter of the Moon in radians is:α = (180° / π) x (1800 / 3600) radian= 0.004848 radianAnd the small angle formula states that tan(α) = (Dm/2) / D
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A 95% confidence interval for the proportion of young adults who skip breakfast is 0.20 to 0.27. Which of the following is the correct interpretation of the 95% confidence interval?
a. There is a 95% probability that the proportion of young adults who skip breakfast is between 0.20 and 0.27.
b. If this study were to be repeated with a sample of the same size, there is a 95% probability that the sample proportion would be between 0.20 and 0.27.
c. We can be 95% confident that the proportion of young adults in the sample who skip breakfast is between 0.20 and 0.27.
d. We can be 95% confident that the proportion of young adults in the population who skip breakfast is between 0.20 and 0.27.
b. If this study were to be repeated with a sample of the same size, there is a 95% probability that the sample proportion would be between 0.20 and 0.27.
ung adults who skip breakfast is between 0.20 and 0.27.
The correct interpretation of the 95% confidence interval is c. We can be 95% confident that the proportion of young adults who skip breakfast is between 0.20 and 0.27.
This means that if we were to repeat the study multiple times, we would expect 95% of the resulting confidence intervals to contain the true proportion of young adults who skip breakfast.
It does not mean that there is a 95% probability that the true proportion falls between 0.20 and 0.27 (option a) since the true proportion either is within that range or it is not. Also, the confidence interval is about the population parameter (the proportion of young adults who skip breakfast), not the sample statistic (the sample proportion) as stated in option b.
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At the beginning of the school year, 396 students attended the first football game. Attendance at the next was 505 students. Estimate the percent of increase.
Answer:
27.5253% increase
Step-by-step explanation:
i got this answer right on khan academy
Write an equation in slope-intercept form of the line that is a segment bisector of both AB and CD.
Answer:
y = -5x + 7
Step-by-step explanation:
Segment bisector of the segments AB and CD will pass through the midpoint of these segments.
Midpoint of a segment is given by the coordinates = \((\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\)
where, \((x_1,y_1)\) and \((x_2,y_2)\) are the coordinates of the extreme ends of the segments.
Coordinates of the midpoint of AB = \((\frac{6-4}{2},\frac{3+1}{2})\)
= (1, 2)
Coordinates of the midpoint of CD = \((\frac{5-1}{2},\frac{-5-1}{2})\)
= (2, -3)
Let the equation of the line will be,
\(y-y_1=m(x-x_1)\)
Slope of the line passing through two points \((x_1,y_1)\) and \((x_2,y_2)\) is,
m = \(\frac{y_2-y_1}{x_2-x_1}\)
= \(\frac{2+3}{1-2}\)
= -5
Therefore, equation of the line will be passing through (1, 2) and slope (-5),
y - 2 = (-5)(x - 1)
y = -5x + 5 + 2
y = -5x + 7
After preparing and posting the closing entries for revenues and expenses, the income summary account has a debit balance of $23,000. The entry to close the income summary account will be: Debit Owner Withdrawals $23,000; credit Income Summary $23,000. Debit Income Summary $23,000; credit Owner Withdrawals $23,000. Debit Income Summary $23,000; credit Owner Capital $23,000. Debit Owner Capital $23,000; credit Income Summary $23,000. Credit Owner Capital $23,000; debit Owner Withdrawals $23,000
Debit Income Summary $23,000; credit Owner Capital $23,000.
The entry to close the income summary account will be to debit the Income Summary by $23,000 and credit the Owner Capital account by $23,000. This entry transfers the net income or loss from the income summary account to the owner's capital account. Since the income summary account has a debit balance of $23,000, it means that expenses exceeded revenues, resulting in a net loss. By crediting the Owner Capital account, the loss is allocated to the owner's equity, reducing their capital by the amount of the loss.
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[6](5) In real-number multiplication, if uv₁ = uv2 and u 0, we can cancel the u and conclude that v1 = U₂. Does the same rule hold for the dot product? That is, if u V₁ = u-V₂ and u 0, can you
In real-number multiplication, if uv₁ = uv₂ and u ≠ 0, we can cancel the u and conclude that v₁ = v₂.
In real-number multiplication, if uv₁ = uv₂ and u ≠ 0, we can divide both sides of the equation by u to cancel it out. This cancellation rule holds because u ≠ 0 ensures that division by u is valid. Consequently, we can conclude that v₁ = v₂.
However, the same cancellation rule does not hold for the dot product of vectors. If u ⋅ V₁ = u ⋅ V₂ and u ≠ 0, we cannot simply divide both sides of the equation by u to cancel it out. This is because the dot product is a different operation that involves both magnitude and direction of vectors. Dividing by u would affect the magnitudes and alter the dot product result.
Therefore, in the context of dot product, the cancellation rule does not apply.
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Air is being pumped into a spherical balloon at the rate of 7 cm³/sec. What is the rate of change of the radius at the instant the volume equals 36n cm³ ? The volume of the sphere 47 [7] of radius r is ³.
the rate of change of the radius at the instant the volume equals 36π cm³ is 7 / (36π) cm/sec.
The volume V of a sphere with radius r is given by the formula V = (4/3)πr³. We are given that the rate of change of the volume is 7 cm³/sec. Differentiating the volume formula with respect to time, we get dV/dt =(4/3)π(3r²)(dr/dt), where dr/dt represents the rate of change of the radius with respect to time.
We are looking for the rate of change of the radius, dr/dt, when the volume equals 36π cm³. Substituting the values into the equation, we have: 7 = (4/3)π(3r²)(dr/dt)
7 = 4πr²(dr/dt) To find dr/dt, we rearrange the equation: (dr/dt) = 7 / (4πr²) Now, we can substitute the volume V = 36π cm³ and solve for the radius r: 36π = (4/3)πr³
36 = (4/3)r³
27 = r³
r = 3 Substituting r = 3 into the equation for dr/dt, we get: (dr/dt) = 7 / (4π(3)²)
(dr/dt) = 7 / (4π(9))
(dr/dt) = 7 / (36π)
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What is the formula of distance according to class 9th?
Distance is calculated using the formula distance=√(y2²-y1²)+(x2²-x1²).
What is coordinate?A pair of numbers called coordinates are used to locate a point or a shape in a two-dimensional plane. The x-coordinate and the y-coordinate are two numbers that define a point's location on a 2D plane. The term "ordinate" refers to a point's separation from the x-axis when scaled with the y-axis. Cord's are the collective noun for the abscissa and ordinate. The study of algebraic equations on graphs is known as coordinate geometry. The plotting of points, lines, and curves on an x and y axis is an illustration of coordinate geometry.
Here,
The formula of distance according to class 9th is distance=√(y2²-y1²)+(x2²-x1²).
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Consider the points below. P(θ),−4,0),Q(5,1,−2),R(6,4,1) (a) Find a nonzero vector orthogonal to the plane through the points P,Q, and R. (b) Find the area of the triangle PQR.
(a) A nonzero vector orthogonal to the plane through the points P, Q, and R is (9, -17, 35). (b) The area of triangle PQR is \(\sqrt\)(811) / 2.
(a) To determine a nonzero vector orthogonal to the plane through the points P, Q, and R, we can first find two vectors in the plane and then take their cross product. Taking vectors PQ and PR, we have:
PQ = Q - P = (5, 1, -2) - (-4, 0, 0) = (9, 1, -2)
PR = R - P = (6, 4, 1) - (-4, 0, 0) = (10, 4, 1)
Taking the cross product of PQ and PR, we have:
n = PQ x PR = (9, 1, -2) x (10, 4, 1)
Evaluating the cross product gives n = (9, -17, 35). Therefore, (9, -17, 35) is a nonzero vector orthogonal to the plane through points P, Q, and R.
(b) To determine the area of triangle PQR, we can use the magnitude of the cross product of vectors PQ and PR divided by 2. The magnitude of the cross product is given by:
|n| = \(\sqrt\)((9)^2 + (-17)^2 + (35)^2)
Evaluating the magnitude gives |n| = \(\sqrt\)(811).
The area of triangle PQR is then:
Area = |n| / 2 = \(\sqrt\)(811) / 2.
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what is 77/12 as a mixed number.
I'm giving you 68 + 1 points.
Answer:
6 5/12
Step-by-step explanation:
77/12 as a mixed fraction will be 6 5/12
Answer:
6 5/12
Step-by-step explanation:
77/12 is the same as saying 77 divided by 12, the numerator is always going to be divided by the denominator. This means that if you divide 77 by 12 you will get a number like 6.4 but we dont want any decimals, we are just looking for how many times 12 can go into 77, which is 6 and we can take the leftover 5 and make it the new numerator over 77, somyou would get 6 5/12 and to check this answer, multiply 12 by 6 and add 5 and you should get what you started with, 77/12
Triangle MNO has vertices M(6,5), N(2,2), and O(7,0). It's image has vertices M'(-6,5), N'(-2,2), and
O'(-7,0). Which line of reflection maps triangle MNO onto its image?
x = 1
y=1
x = 0
.y=0
Answer:
x=0
Step-by-step explanation:
because the y values are not changing and the x values are only changing from positive to negative.
What do you have to remember about the signs of the numbers in factored form of a quadratic compared to the signs of the actual x-intercepts on the graph?
In contrast to the signs of the real x-intercepts on the graph, we must remember the signs of the values in a quadratic's factored form. because the cartesian coordinate points are shifted.
What is a quadratic function?Any function of the form \(\rm f(x) =ax^2+bx+c\).where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic function.
When factoring by grouping is used, the replacement terms will both share the same middle-term sign. The factor signs will have one of each sign with the "stronger" number (the larger absolute value) matching the middle term if the last term is negative.
We can locate the function's x-intercepts or zeros with the aid of factored form.
Thus, in contrast to the signs of the real x-intercepts on the graph, we must remember the signs of the values in a quadratic's factored form. because the cartesian coordinate points are shifted.
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Evaluate the integral. (Use C for the constant of integration.) 1₁ 17z³ e² dz
To evaluate this integral, we have used integration by parts. We have taken u = 17z³ and dv = e² dz. We have evaluated this integral by parts twice. After that, we have evaluated the integral and the final answer obtained is 1/2 (17z³ e² - 51z² e²/2 + 51z e² - 51z + C) where C is the constant of integration.
Given the integral 1₁ 17z³ e² dz
Here the integrand is in the form of the product of the exponential function and a polynomial.
To evaluate this integral, we will use integration by parts as follows:
∫udv = uv − ∫vdu
where u = 17z³ and dv = e²
dzdu = 51z² dz and v = 1/2 e²
Using this substitution, the integral is transformed as follows:
∫17z³ e² dz = 1/2 (17z³ e² − ∫51z² e² dz)
We again use integration by parts for the remaining integral.
Let u = 51z² and dv = e²
dzdu = 102z dz and
v = 1/2 e² ∫51z² e² dz
= 1/2 (51z² e² − ∫102z e² dz)
Applying integration by parts again, let
u = 102z and
dv = e² dzdu
= 102 dz
and v = 1/2 e² ∫102z e² dz
= 1/2 (102z e² − ∫102 dz)
= 1/2 (102z e² − 102z)
= 51z e² − 51z
Finally, substituting the results back into the original integral, we get:
∫17z³ e² dz
= 1/2 (17z³ e² − ∫51z² e² dz)
= 1/2 (17z³ e² − 1/2 (51z² e² − 102z e² + 102z))
= 1/2 (17z³ e² - 51z² e²/2 + 51z e² - 51z + C)
where C is the constant of integration.
Therefore, the answer is 1/2 (17z³ e² - 51z² e²/2 + 51z e² - 51z + C).
In this given integral, we have an integrand in the form of the product of the exponential function and a polynomial.
To evaluate this integral, we have used integration by parts. We have taken u = 17z³ and dv = e² dz.
We have evaluated this integral by parts twice.
After that, we have evaluated the integral and the final answer obtained is 1/2 (17z³ e² - 51z² e²/2 + 51z e² - 51z + C)
where C is the constant of integration.
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An experiment was conducted to measure the effectiveness of various feedsupplements on the growth rate of chickens. A five number summary of theweights of the chicks in grams six weeks after hatching is as follows. Source:Anonymous (1948) Biometrika, 35, 214.• Min - 107• Q1 - 197• Median - 264• Q3 - 312• Max - 4261. Aboutpercent of the chicks weigh more than 1972. Aboutpercent of the chicks weigh more than 264.3. Aboutpercent of the chicks weigh more than 312.4. Aboutpercent of the chicks weigh between 197 and 312
We have a sample of x=weights with the following data:
• Min = 107
,• Q1(x) = 197
,• Median(x) = 264
,• Q3(x) = 312
,• Max(x) = 426
1) The percent of the chicks weight more than 197, this is the value of the Q1. The quartile 1 represent the value of x that the 25% of the sample has a value less o equal to that.
So the percent of chicks that have a weight greater than 197 is 75%.
2) For the weight more than 264, correspond to the Median, so the 50% of sample has a weight lower or equal 264, and the other 50% has a weight greater or equal to 264.
So, the percent is 50%.
3) The weight of 312 correspond with Q3, so the 75% of the sample has a weight less or equal to 312, and the other 35% has a weight greater than 312.
So, the percent is 25%.
4) The weigth are the percentil Q1 and Q3, respectively. So the percent of chicks that have a weigth between 197 and 312 is 75%-25% = 50%