Question:
Two rowing teams are having a race. Boat A had a head start, crossing the start line first and traveling at a speed of 3 meters per second. Boat B waited and then crossed the start line 6 seconds after Boat A. The speed of Boat B was 4.8 meters per second.
Part A- Write two equations, one for Boat A and one for Boat B. In both equations, let t equal the time in seconds since Boat A crossed the start line and d equal the distance traveled in meters.
Part B- Solve the system of equations from part A. show your work
Answer:
A. Equations
\(d = 3t\)
\(d = 4.8t - 28.8\)
b.
\(t = 16\)
\(T = 10\)
\(d = 48km\)
Step-by-step explanation:
For Boat A:
\(Speed = 3m/s\)
\(Time = t\)
For Boat B:
\(Speed = 4.8m/s\)
Boat B waited 6 seconds later. So, the time is:
\(T = t - 6\)
Solving (a): Equations
Speed is calculated as:
\(Speed = \frac{Distance}{Time}\)
For Boat A:
\(3 = \frac{d}{t}\)
Make d the subject
\(d = 3t\)
For Boat B:
\(4.8 = \frac{d}{T}\)
Make d the subject
\(d = 4.8T\)
Substitute t - 6 for T
\(d = 4.8(t - 6)\)
\(d = 4.8t - 28.8\)
Hence, the equations are:
\(d = 3t\)
\(d = 4.8t - 28.8\)
Solving (b): The value of d
\(d = 3t\)
\(d = 4.8t - 28.8\)
Substitute 3t for d in the second equation
\(3t = 4.8t - 28.8\)
Collect like terms
\(3t - 4.8t = - 28.8\)
\(- 1.8t = - 28.8\)
\(1.8t = 28.8\)
Solve for t
\(t = 28.8/1.8\)
\(t = 16\)
Recall that:
\(T = t - 6\)
\(T = 16 - 6 = 10\)
Next, calculate the distance:
\(d = 3t\)
\(d = 3 * 16\)
\(d = 48km\)
So:
Boat A travels for 16 seconds
Boat B travels for 10 seconds
The distance is 48km
You have $50 in your bank account. Each week you plan to deposit $6 from your allowance and $20 from your paycheck. The equation b = 60 + (20+6)w gives the amount b in your account after w weeks. How many weeks from now will you have $215 in your bank account?
6 weeks from now, you will have $215 in your bank account
How many weeks from now will you have $215 in your bank account?The given parameters are:
b = 60 + (20+6)w
When the account balance is $215, we have
60 + (20+6)w = 215
Subtract 60 from both sides
(20+6)w = 155
This gives
26w = 155
Divide both sides by 26
w = 5.96
Approximate
w = 6
Hence, 6 weeks from now, you will have $215 in your bank account
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A box measures 18 inches wide by 9 inches deep. The height of the box is 1 1/2 feet. What is the volume of the box? Remember if ft is equivalent to 12 in.
Answer: 2,916 inches³
Step-by-step explanation:
The volume of a box is:
= Length * Width * Height
But all of these have to have the same units for it to work. This means that the height of the box will have to be converted to inches :
1 ft is 12 inches so:
= 1¹/₂ * 12
= 3/2 * 12
= 18 inches
Volume is therefore:
= 18 * 9 * 18
= 2,916 inches³
Prior to recording the following, Elite Electronics, Inc. had a credit balance of $1,500 in its Allowance for Doubtful Accounts.
Required:
Prepare journal entries for each transaction. (If no entry is required for a transaction/event, select "No Journal Entry Required" in the first account field.)
a. On August 31, a customer balance for $250 from a prior year was determined to be uncollectible and was written off.
b. On December 15, the customer balance for $250 written off on August 31 was collected in full.
Journal Entry Worksheet
Record the write-off of a certain customer account from a prior year which is not collectible totaling $250.
Transaction General Journal Debit Credit a b(1) Record the reversal of the write-off the $250 customer account
Tansaction General Journal Debit Credit
b(1) b(2) Record the reciept of cash of $250 from the customer
Transaction General Journal Debit Credit
b(2)
Explanation:
Here is the solution to the given problem:
Journal entries for Elite Electronics, Inc. are given below:
a) Write-off of a customer balance of $250 from a prior year which is not collectible:
General Journal Debit Credit
Allowance for doubtful accounts $250
Accounts receivable $250
b(1) Reversal of the write-off the $250 customer account:
General Journal Debit Credit
Accounts receivable $250
Allowance for doubtful accounts $250
b(2) Receipt of cash of $250 from the customer:
General Journal Debit Credit
Cash $250
Accounts receivable $250
Therefore, the journal entries for Elite Electronics, Inc. are given below:
Journal entry for the write-off of a customer account that is uncollectible:
Allowance for doubtful accounts $250
Accounts receivable $250
Journal entry for the reversal of the write-off $250 customer account:
Accounts receivable $250
Allowance for doubtful accounts $250
Journal entry for the receipt of cash of $250 from the customer:
Cash $250
Accounts receivable $250
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Find the third partial sum of the series. (picture included!!!) please I'm in dire need of help cus my grades a D if I could get help ill be so so happy ill probably cry a little tear of joy
Consequently, 15 is the third partial total of the sequence.
What in mathematics is arithmetic?The area of mathematics known as arithmetic deals with the mathematical study of numbers and the numerous procedures that can be performed on them. Addition, subtraction, multiplication, and division are the fundamental mathematical processes. The icons listed above stand in for these processes.
The given series is an arithmetic series with first term a1 = 2 and common difference d = 3.
To find the third partial sum, we need to add the first three terms of the series:
S₃ = 2 + 5 + 8
S₃ = 15
Therefore, the third partial sum of the series is 15.
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Consider the following system. Dx/dt = 7x + 13y Dy/dx = -2x + 9y Find the eigenvalues of the coefficient matrix At). (Enter your answers as a comma-separated list. ) Find an eigenvector corresponding to the eigenvalue with positive imaginary part. KE K = ____
Find the general solution of the given system. (X(t), y(t)) = __________
The eigenvalues of the coefficient matrix A is λ = 5 ± 6i
An eigenvector corresponding to the eigenvalue with a positive imaginary part is v = k(3 + 2i, 1)
The general solution can be expressed as
X(t) = e^(5t) × (C1 × cos(6t) + C2 × sin(6t)) × (3 + 2i, 1)
Given, dx/dt = 7x + 13y and dy/dt = -2x + 9y.
Eigenvalues of the coefficient matrix A:
The coefficient matrix A is:
\(A = \left[\begin{array}{cc}7&13\\-2&9\end{array}\right]\)
To get the eigenvalues, we have to solve the characteristic equation.
| (7 - λ) (9 - λ) - (-2)(13) | = 0
63 - 7λ - 9λ +λ² + 26 =0
λ² - 16λ + 89 =0
Solving this equation, we get the eigenvalues λ = 5 ± 6i.
The positive imaginary part eigenvalue λ = 5 + 6i. Let v be the eigenvector now we have to solve the system (A - λI)v = 0.
| (2 - 6i) 13 | |x| = |0|
| -2 (4 - 6i)| |y| = |0|
After solving this system, we get an eigenvector v = k(3 + 2i, 1), where k is a constant.
The general solution of the given system:
The general solution can be expressed as
X(t) = e^(5t) × (C1 × cos(6t) + C2 × sin(6t)) × (3 + 2i, 1)
Where C1 and C2 are constants.
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If f(x)= -3x - 5 and g(x) = 4x-2 ,find (f-g)(x)
Answer:
\((f-g)(x)=-7x-3\)
Step-by-step explanation:
The width of bolts of fabric is normally distributed with mean 952 mm (millimeters) and standard deviation 10 mrm (a) What is the probability that a randomly chosen bolt has a width between 941 and 957 mm? (Round your answer to four decimal places.) (b) What is the appropriate value for C such that a randomly chosen bolt has a width less than C with probability 0.8749? (Round your answer to two decimal places.)
a. Using the calculated z-score, the probability that a randomly chosen bolt has a width between 941 and 957 mm is approximately 0.5558.
b. The appropriate value for C such that a randomly chosen bolt has a width less than C with probability 0.8749 is approximately 963.5 mm.
What is the probability that a randomly chosen bolt has a width between 941 and 957mm?(a) To find the probability that a randomly chosen bolt has a width between 941 and 957 mm, we can use the z-score formula and the standard normal distribution.
First, let's calculate the z-scores for the given values using the formula:
z = (x - μ) / σ
where:
x is the value (941 or 957)μ is the mean (952)σ is the standard deviation (10)For x = 941:
z₁ = (941 - 952) / 10 = -1.1
For x = 957:
z₂ = (957 - 952) / 10 = 0.5
Next, we need to find the probabilities corresponding to these z-scores using a standard normal distribution table or a calculator.
Using the standard normal distribution table, we find:
P(z < -1.1) ≈ 0.135
P(z < 0.5) ≈ 0.691
Since we want the probability of the width falling between 941 and 957, we subtract the two probabilities:
P(941 < x < 957) = P(-1.1 < z < 0.5) = P(z < 0.5) - P(z < -1.1) ≈ 0.691 - 0.135 = 0.5558
Therefore, the probability that a randomly chosen bolt has a width between 941 and 957 mm is approximately 0.5558.
(b) To find the appropriate value for C such that a randomly chosen bolt has a width less than C with probability 0.8749, we need to find the z-score corresponding to this probability.
Using a standard normal distribution table or calculator, we find the z-score corresponding to a cumulative probability of 0.8749 is approximately 1.15.
Now, we can use the z-score formula to find the value of C:
z = (x - μ) / σ
Substituting the known values:
1.15 = (C - 952) / 10
Solving for C:
C - 952 = 1.15 * 10
C - 952 = 11.5
C ≈ 963.5
Therefore, the appropriate value for C such that a randomly chosen bolt has a width less than C with probability 0.8749 is approximately 963.5 mm.
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Kiara has​ $520 in her bank account. each week she deposits​ $80 and withdraws​ $35. gael has​ $310 in his account. each week he deposits​ $95 and withdraws​ $20. write and solve an equation to determine the week w when gael and kiara have the same amount of money in their accounts.
Answer:
fuimaa
Step-by-step explanation:
What are the first 3 terms of the sequence represented by the expression n(n – 2) – 4 ?
The first 3 terms of the sequence using the expression are -5, -4 and -1
Calculating the first 3 terms of the sequence using the expressionFrom the question, we have the following sequence that can be used in our computation:
n(n – 2) – 4
This means that
T(n) = n(n – 2) – 4
Set n = 1, 2 and 3
So, we have
T(1) = 1 * (1 – 2) – 4 = -5
T(2) = 2 * (2 – 2) – 4 = -4
T(3) = 3 * (3 – 2) – 4 = -1
Hence, the first 3 terms of the sequence using the expression are -5, -4 and -1
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pls solve the following math from trigonometry
Step-by-step explanation:
\( \tan(2x) = 1.5\)
Take the arc tangent,
\( \tan {}^{ - 1} ( \tan(2x) ) = \tan {}^{ - 1} (1.5) \)
\(2x = 56.3\)
\(x = 28.15\)
b.
\((3 \cos(x) + 1)(2 \cos(x) + 3) = - 2\)
\(6 \cos {}^{2} (x) + 11 \cos(x) + 3 = - 2\)
\(6 \cos {}^{2} (x) + 11 \cos(x) + 5 = 0\)
\(6 \cos {}^{2} (x) + 6 \cos(x) + 5 \cos(x) + 5 = 0\)
\(6 \cos(x) ( \cos(x) + 1) + 5( \cos(x) + 1) = 0\)
\((6 \cos(x) + 5)( \cos(x) + 1) = 0\)
Set each factor equal to zero.
\(6 \cos(x) + 5 = 0\)
\(6 \cos(x) = - 5\)
\( \cos(x) = - \frac{5}{6} \)
\(x = \cos {}^{ - 1} ( \frac{5}{6} ) \)
\(x = 146.4\)
For the second factor,
\( \cos(x) + 1 = 0\)
\( \cos(x) = - 1\)
\(x = 180\)
So the answer for the second one is
146.4 and 180.
Select the step in the solution that FIRST shows an error.
Step 1: 4x – 10 = 10
Step 2: 4x = 20
Step 3: 4x = 5
Step 4: X = 1.25
Step 1
Step 2
Step 3
Step 4
Answer:Step 3
Step-by-step explanation:
Pierre de fermat a 17th century french lawyer stated that any whole number can be written as the sum of four or less square numbers for example 15 equals three squared +2 squared plus one squared plus one squared express 61 as such a sum
61 is the sum of two consecutive integers (-6,-5 ) and (5,6).
According to Pierr De Fermat any whole number writteen as the sum of four or less square numbers.
So 61 is the whole number so we can write in the sum of squares,
Now we know even+odd=odd so that let a and a+1 integer , according to Pierr De Fermat we can write,
a²+(a+1)²=61;
⇒a²+a²+2a+1=61
⇒2a²+2a-60=0
⇒a²+a-30=0 (∵divided by 2)
⇒a²+6a-5a-30=0
⇒a(a+6)-5(a+6)=0
⇒(a+6)(a-5)=0
⇒a+6=0 or a-5=0 ⇒a=-6 or a=5
If a=-6 then a+1=-6+1=-5.
if a=5 then a+1=5+1= 6.
so 61= (-6)²+(-5)² and 61= 6²+5².
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Rebekah uses a balance scale to measure the weight of a rock in science class. She finds that its weight is 380 grams. If the actual weight is 363 grams, which of the following is closest to her percent error? Show how you made your choice.
Answer:
Step-by-step explanation:
4.5 %
What is the Y-INTERCEPT from the equation? y=5x + 12*
A) 5
B) 12
Answer:
B-12
Step-by-step explanation:
Answer:
B) 12
Step-by-step explanation:
Set x equal to zero and you get y= 12
This question checks whether you can covert currencies properly. Suppose 1 British pound = US $1.25 and 1 British pound = 39 Thai baht. How many baht per US dollar? Approximately 49 Thai baht per US dollar. Approximately 31 Thai baht per US dollar. Approximately 38 Thai baht per US dollar. Approximately 0.80 Thai baht per US dollar.
Approximately 49 Thai baht per US dollar.
Approximately 31 Thai baht per US dollar.
Approximately 38 Thai baht per US dollar.
Approximately 0.80 Thai baht per US dollar.
It would be 31 Thai baht per US dollar. the correct answer is B
To determine the number of Thai baht per US dollar, we need to calculate the exchange rate between the British pound and the Thai baht and between the British pound and the US dollar, and then convert from baht to US dollars.
Given the information provided:
1 British pound = US $1.25
1 British pound = 39 Thai baht
To find the exchange rate between the Thai baht and the US dollar, we can divide the exchange rate between the British pound and the Thai baht by the exchange rate between the British pound and the US dollar.
Exchange rate (Thai baht per US dollar) = (Exchange rate British pound to Thai baht) / (Exchange rate British pound to US dollar)
Exchange rate (Thai baht per US dollar) = 39 Thai baht / US $1.25
Exchange rate (Thai baht per US dollar) ≈ 31 Thai baht per US dollar
Therefore, the correct option is B) 31 Thai baht per US dollar.
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For what values of x'is x2 + 2x = 24 true?
--6 and -4
4 and 6
4 and -6
6 and 4
Next
Save and Exit
Answer:
\( \boxed{Values \: true \: of \: 'x' \: for \: equation \: {x}^{2} + 2x = 24 \: is \: -6 \: and \: 4} \)
Step-by-step explanation:
\( = > {x}^{2} + 2x = 24 \\ \\ = > {x}^{2} + 2x - 24 = 0 \\ \\ = > {x}^{2} + (6 - 4)x - 24 = 0 \\ \\ = > {x}^{2} + 6x - 4x - 24 = 0 \\ \\ = > x(x + 6) - 4(x + 6) = 0 \\ \\ = > (x + 6)(x - 4) = 0 \\ \\ = > x + 6 = 0 \: \: \: \: \: \: \: \: and \: \: \: \: \: \: \: \: \: x - 4 = 0 \\ \\ = > x = - 6 \: \: \: \: \: \: \: \: \: \: and \: \: \: \: \: \: \: \: \: x = 4\)
Values true of 'x' for equation x² + 2x = 24 is -6 and 4
The trampoline park charges a $8 for kids and $4 for adults. Your extended family is going there to celebrate your birthday. Your family has at most $190 dollars to spend on entrance fees. You can invite at most 35 people. What are some possible combinations of adults and kids who could go to your party? Write a system of equations for this situation.
Answer:
The answer is below
Step-by-step explanation:
Let x represent the number of kids and y represent the number of adults that can be invited to the park.
Since the family has at most $190 to spend, hence:
8x + 4y ≤ 190 (1)
Also, the maximum number of invites is 35 people. This is represented by the equation:
x + y ≤ 35 (2)
Graphing equation 1 and equation 2 using geogebra online graphing
We have the solution as:
(0, 35), (23.75, 0) and (12.5, 22.5)
Since the number of people must be a whole number, the possible solutions are:
0 children and 35 adults or 23 children and 0 adults or 12 children and 22 adults
what is the number of the parking space 16, 06, 68
The number formed by the digits 16, 06, and 68 is 160668, which is determined by concatenating them in the given order.
To determine the number formed by the given digits, we concatenate them in the given order. Starting with the first digit, we have 16. The next digit is 06, and finally, we have 68. By combining these three digits in order, we get the number 160668.
When concatenating the digits, the position of each digit is crucial. The placement of the digits determines the resulting number. In this case, the digits are arranged as 16, 06, and 68, and when they are concatenated, we obtain the number 160668. It's important to note that the leading zero in the digit 06 does not affect the value of the resulting number. When combining the digits, the leading zero is preserved as part of the number.
Therefore, the number formed by the digits 16, 06, and 68 is 160668.
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10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the
female in the household rather than the male in the household. A coupon book was sent at
random to either the male or female in a random sample of 50 male-female households. A
month later, a coupon book was sent to the other member of the pair. The manufacturer found
that the mean difference (female-male) in the number of coupons redeemed was 1.5 with a
standard deviation of 4.75.
Do these data provide convincing evidence that the mean number of coupons redeemed is
greater when the coupons were addressed to a female? Use a = 0.01.
а
Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.
What are the hypothesis tested?At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:
\(H_0: \mu = 0\)
At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:
\(H_1: \mu > 0\)
What is the test statistic?The test statistic is given by:
\(t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}\)
The parameters are:
\(\overline{x}\) is the sample mean.\(\mu\) is the value tested at the null hypothesis.s is the standard deviation of the sample.n is the sample size.In this problem, the parameters are given as follows:
\(\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50\).
Hence, the test statistic is given by:
\(t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}\)
\(t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}\)
t = 2.23
What is the conclusion?Considering a right-tailed test, as we are testing if the mean is greater than a value, with a significance level of 0.01 and 50 - 1 = 49 df, the critical value is given by \(t^{\ast} = 2.4\).
Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.
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Bobby build a wooden rectangular sandbox with dimension of 3 1/4 by 5 1/2 he now wants to expand each side by 1/4 feet. What would be the new dimension of the sandbox?
farmer brown had ducks and cows. one day he noticed that the animals had a total of 13 heads and 46 feet. how many of the animals were cows?
Farmer brown had ducks and cows having a total of 13 heads and 46 feet, which means there are 10 cows and 3 ducks.
This is an algebraic problem that can be solved using a system of equations.
Let x be the number of cows and y be the number of ducks. We know from the problem statement that:
x + y = 13 (the number of heads)
4x + 2y = 46 (the number of feet)
We can use the first equation to solve for one of the variables in terms of the other.
For example, if we subtract y from both sides of the equation we get:
x = 13 - y
We can substitute this expression for x into the second equation:
4(13 - y) + 2y = 46
Simplifying, we get:
52 - 4y + 2y = 46
which gives us:
-4y = -6
then we get:
y=3
Now we can use this value of y to solve for x in terms of y:
x = 13 - y
x = 13 - 3
x = 10
Therefore, there are 10 cows and 3 ducks.
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Sami is trying out for the baseball team at school. He would like to play first base. His coach tells him he will need to be able to throw quickly and accurately to home plate, second base, and third base. The distance between consecutive bases on the baseball diamond is 90 feet. Third base is across the diamond and opposite first base.
How far will the ball have to be thrown from first base in order to reach third base?
A. The distance from first base to third base is 127.3 feet.
B. The distance from first base to third base is 180 feet.
C. The distance from first base to third base is 90 feet.
D. The distance from first base to third base is 135 feet.
Answer:
Step-by-step explanation:
B
Which statement about convergent infinite geometric series is true?
a.The graph of a convergent infinite geometric series goes to infinity.
b.The graph of an infinite geometric series curves away from its sum.
c.A finite geometric sequence will have an infinite geometric series.
d.An infinite geometric series converges if −1
Answer:
B. The graph curves away from its sum
Step-by-step explanation:
A convergent infinite geometric series, the graph of the series curves away from the sum, the correct option is B.
What is a Geometric Series?A sequence of numbers such that the consecutive term is increasing or decreasing by a fixed ratio is called a geometric series.
The standard equation for geometric series is
Tₙ = a₁ rⁿ⁻¹
The sum of an infinite geometric series is given by
S = a₁/(1-r)
where a₁ is the first term and r is the common ratio.
The graph of an infinite series curves away from its sum.
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Given the following diagram, find the missing measure. Given: PMIMO 2 P m2 = 30°, m P= 30 60 90 120
Express the sum of the polymonial 3x^2+15x-56 and the square of the binomial (x-8) as a polynomial in standard form.
Given:
Polynomial is \(3x^2+15x-56\).
To find:
The sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form.
Solution:
The sum of given polynomial and the square of the binomial (x-8) is
\(3x^2+15x-56+(x-8)^2\)
\(=3x^2+15x-56+x^2-2(x)(8)+8^2\) \([\because (a-b)^2=a^2-2ab+b^2]\)
\(=3x^2+15x-56+x^2-16x+64\)
On combining like terms, we get
\(=(3x^2+x^2)+(15x-16x)+(-56+64)\)
\(=4x^2-x+8\)
Therefore, the sum of given polynomial and the square of the binomial (x-8) as a polynomial in standard form is \(4x^2-x+8\).
On the unit circle, where 0 < theta < or equal to 2pi, when is tan theta undefined?
A. Theta=pi and theta=2pi
B. sin theta = cos theta
C. theta = pi/2 and theta=3pi/2
D. sin theta = 1/cos theta
Therefore, the answer is option C: theta = pi/2 and theta = 3pi/2.
To determine when tan(theta) is undefined on the unit circle, we need to remember the definition of the tangent function.
Tangent is defined as the ratio of the sine and cosine of an angle. Specifically, tan(theta) = sin(theta)/cos(theta).
Now, we know that cosine can never be equal to zero on the unit circle, since it represents the x-coordinate of a point on the circle and the circle never crosses the x-axis. Therefore, the only way for tan(theta) to be undefined is if the cosine of theta is equal to zero.
There are two values of theta on the unit circle where cosine is equal to zero: pi/2 and 3pi/2.
At theta = pi/2, we have cos(pi/2) = 0, which means that tan(pi/2) = sin(pi/2)/cos(pi/2) is undefined.
Similarly, at theta = 3pi/2, we have cos(3pi/2) = 0, which means that tan(3pi/2) = sin(3pi/2)/cos(3pi/2) is also undefined.
Therefore, the answer is option C: theta = pi/2 and theta = 3pi/2.
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The equation of a straight line that is parallel to a straight line. 2y =3x-1
The equation of the line that is parallel to 2y = 3x - 1 and passes through the point (4, 2) is: y = (3/2)x - 4
To find the equation of a straight line that is parallel to the line 2y = 3x - 1, we need to remember that parallel lines have the same slope.
First, let's rearrange the given equation into slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept:
2y = 3x - 1
y = (3/2)x - 1/2
So the slope of this line is 3/2.
Now, if we want to find the equation of a line that is parallel to this line, we just need to use the same slope. Let's call the new line y = mx + b, where m is the slope we just found and b is the y-intercept we need to find.
So the equation of the parallel line is:
y = (3/2)x + b
To find the value of b, we need to use a point on the line. Let's say we want the line to go through the point (4, 2):
2 = (3/2)(4) + b
2 = 6 + b
b = -4
So the equation of the line that is parallel to 2y = 3x - 1 and passes through the point (4, 2) is: y = (3/2)x - 4
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the qualified applicant pool for four management trainee positions consists of nine women and seven men. (a) how many different groups of applicants can be selected for the positions? (b) how many different groups of trainees would consist entirely of women? (c) probability extension: if the applicants are equally qualified and the trainee positions are selected by drawing the names at random so that all groups of four are equally likely, what is the probability that the trainee class will consist entirely of women? (round your answer to four decimal places.)
There are 1820 different groups of applicants for 4 management trainee positions, 126 different groups of trainees consisting entirely of women, and a 0.0692 probability that the trainee class will consist entirely of women.
The number of different groups of applicants that can be selected for the four management trainee positions can be calculated using the combination formula:
nCr = n! / (r! * (n-r)!)
where n is the total number of applicants (16 in this case) and r is the number of positions to be filled (4 in this case).
So the number of different groups of applicants that can be selected is:
16C4 = 1820
Therefore, there are 1820 different groups of applicants that can be selected for the four management trainee positions.
The number of different groups of trainees that would consist entirely of women can be calculated using the combination formula again, but this time we are selecting all 4 positions from the 9 female applicants:
9C4 = 126
Therefore, there are 126 different groups of trainees that would consist entirely of women.
Assuming that all groups of four are equally likely to be selected, the probability that the trainee class will consist entirely of women can be calculated by dividing the number of different groups of trainees that consist entirely of women (126) by the total number of different groups of applicants (1820):
Probability = 126 / 1820 = 0.0692
So the probability that the trainee class will consist entirely of women is 0.0692 (rounded to four decimal places).
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use green's theorem to find the counterclockwise circulation and outward flux for the field f=(7x−4y)i (9y−4x)j and curve c: the square bounded by x=0, x=4, y=0, y=4.
The counterclockwise circulation around c is 12 and the outward flux through c is zero.
Green's theorem is a useful tool for calculating the circulation and flux of a vector field around a closed curve in two-dimensional space.
In this case,
we have a field f=(7x−4y)i+(9y−4x)j and
a square curve c bounded by x=0, x=4, y=0, y=4.
To find the counterclockwise circulation, we can use the line integral of f along c, which is equal to the double integral of the curl of f over the region enclosed by c.
The curl of f is given by (0,0,3), so the line integral evaluates to 12.
To find the outward flux, we can use the double integral of the divergence of f over the same region, which is equal to zero since the divergence of f is also zero.
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c) when x is divided by 5 the result is 20
Answer:
x= 100
Step-by-step explanation:
x/5 = 20
multiply both the sides by 5 we get
5× x/5 = 20×5
x = 100