Answer:
c.) magnetosphere
Explanation:
I think is C
What is the difference between abiotic and biotic factors?
Answer:
Abiotic referfers to non-living and biotic factors are living or once living
Explanation:
What is the frequency of a wave if the speed of the wave is 7.9m/s and the wavelength is 3.1m?
Answer:
2.55 HzExplanation:
The frequency of the wave given it's velocity and wavelength can be found by using the formula
\(f = \frac{c}{ \lambda} \\ \)
where
c is the velocity of the wave in m/s
\( \lambda\) is the wavelength in m
From the question
c = 7.9 m/s
\( \lambda\) = 3.1 m
We have
\(f = \frac{7.9}{3.1} = 2.548387... \\ \)
We have the final answer as
2.55 HzHope this helps you
Mr. Chowder ties an eraser to a string and swings it in a circle with a radius of 0.974 meters. The eraser makes 127 revolutions in a minute. Determine its acceleration (in m/s/s).
The acceleration of the eraser is 169.19 m/s².
What is centripetal acceleration?A body travelling in a circle has centripetal acceleration. Due to the fact that velocity is a vector quantity (i.e., it has both a magnitude and a direction), when a body travels in a circle, its direction is continually changing, which causes a change in velocity, which results in an acceleration.
Given that angular velocity of the eraser: ω = 127 rpm
= 126×2π/60 radian/second
= 13.2 radian/second.
radius of the circle: r = 0.974 meter.
Hence, its centripetal acceleration is = ω²r
= 13.2×13.2×0.974 m/s²
=169.19 m/s².
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Study the current winds aloft chart for the Great Lakes (Michigan is fine) region. Estimate the average wind speed for 3000’ 12,000’ and FL350.
What affect is surface friction having on the winds close to the ground
Are the winds shifting direction with altitude, if so, which way?
What is the approximate location of the Jetstream currently? (Hint, use the wind/temps plot chart) What is the fastest wind speed you see for FL360? Which direction flight would it benefit?
How does this change seasonally?
Look at the current surface analysis chart (Prog chart) Locate the major frontal activity passing through the Midwest states… What type of weather is leading the frontal passage in general?
Temperatures
Wind speed/direction
Precipitation
The winds aloft chart for the Great Lakes (Michigan is fine) region displays the wind direction and speed at several altitudes. At 3000 feet, the wind speed is approximately 17 knots.
At 12,000 feet, the wind speed is about 44 knots. The wind speed at FL350 is approximately 67 knots.Surface friction has an effect on the winds close to the ground, slowing them down due to the frictional force exerted on the ground by air molecules. The winds shift direction with altitude, veering to the right of the direction of travel in the northern hemisphere. The approximate location of the Jetstream can be obtained by examining the wind/temperature plot chart. The fastest wind speed at FL360 appears to be approximately 145 knots, traveling towards the northeast. Flight to the east or southeast would benefit from this wind speed.Seasonally, winds aloft change depending on the position of the jet stream, which moves towards the poles during the summer months and towards the equator during the winter months.
The current surface analysis chart (Prog chart) shows the major frontal activity passing through the Midwest states. Precipitation is what leads the frontal passage in general, with both temperature and wind speed/direction changing from behind to ahead of the front.
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What are the disadvantages of driverless cars? Check all that apply
Answer:
Explanation:
,,,,,,,,,,,,,,,,,,,,,,,,,,,
They cannot tell the difference between people and other objects.
They will wait for crossing pedestrians even if signaled to keep driving. Explanation:
Just did it
what is the smallest separation (in nm) between two slits that will produce a ninth-order maximum for any visible light?
the smallest separation between two slits that will produce a ninth-order maximum for any visible light is approximately **15.75 μm** (micrometers).
To determine the smallest separation between two slits that will produce a ninth-order maximum for any visible light, we can use the formula for the position of the nth-order maximum in a double-slit interference pattern:
y = (nλL) / d
where y is the position of the nth-order maximum, λ is the wavelength of light, L is the distance from the slits to the screen, and d is the separation between the slits.
In this case, we want to find the smallest separation (d) that will produce a ninth-order maximum for any visible light. Visible light has a wavelength range of approximately 400 nm to 700 nm.
Let's assume the worst-case scenario where the wavelength is at the shortest end of the visible light spectrum, which is 400 nm.
For the ninth-order maximum (n = 9), substituting the values into the formula, we get:
400 nm = (9 * λ * L) / d
To find the smallest separation (d), we rearrange the formula:
d = (9 * λ * L) / 400 nm
Since we want the smallest separation, we consider the maximum value for λ (700 nm) and the minimum value for L (the order of magnitude of the size of the interference pattern).
Considering L to be around 1 meter (approximately 1e9 nm), we can substitute the values:
d = (9 * 700 nm * 1e9 nm) / 400 nm
Simplifying the expression, we get:
d ≈ 15.75 μm
Therefore, the smallest separation between two slits that will produce a ninth-order maximum for any visible light is approximately 15.75 μm (micrometers).
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A stationary block of mass 35 Kg is suspended on a string.What is the tension in the string ?( Neglect the mass of the string)
Answer:
Tstring = 343.35 [N].
Explanation:
Since the block is in equilibrium, we can say that the sum of the forces on the Y-axis or vertical is equal to zero.
∑Fy = 0
\(T_{string}-W=0\)
where:
Tstring = tension of the string [N]
W = weight of the block [N]
And the weight can be calculated multiplying the mass of the block by the gravity acceleration.
Now replacing:
\(T_{string}=m*g\\T_{string}=35*9.81\\T_{string}=343.35[N]\)
Dave Ramsey mentions that insurance is the defense for managing your money. Why is this true?
It is true that insurance is the defense for managing money because it ensures that your money is efficiently utilized even in your absence.
What is insurance?Insurance refers to a means of indemnity against a future occurrence of an uncertain event such as an accident, death, robbery etc.
Insurance is a way to protect one's assets from getting lost when faced with unforeseen circumstances.
For example;
A liability insurance protects one in case another person sues for injuries or loss caused by one's negligence or improper actions. Life insurance protects one's beneficiaries from loss of income by paying them money after one's death.Therefore, it is true that insurance is the defense for managing money because it ensures that your money is efficiently utilized even in your absence.
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Which of the following waves in the electromagnetic spectrum do all objects emit?
Radio Waves
Infrared Waves
Visible Light waves
Ultraviolet Waves
please answer ASAP
Answer:
radio waves
Explanation:
Answer:
the answer is A radio waves
Select the correct words from the drop-down menus to complete the sentence.
The
v work of a machine can never exceed the
work because
some of the work.
uses
Answer:
1. C
2. B
3. B
Explanation:
Took assignment on edge
The
the maximum value of the electric field in an electromagnetic wave is 1.5 v/m. what is the maximum value of the magnetic field associated with this wave?
The maximum value of the magnetic field in the given wave is 5 nT.
Given;
maximum value of the electric field, E₀ = 1.5 V/m
The maximum value of the magnetic field in the given wave is calculated as;
B₀ = \(\frac{E_{0} }{c}\)
where;
c is the speed of light = 3 x 10⁸ m/s
B₀ = \(\frac{E_{0}}{c}\)
B₀ = \(\frac{1.5}{3 . 10^{8} }\) = 0.5 x 10⁻⁸ = 5 x 10⁻⁹
B₀ = 5 nT
Therefore, the maximum value of the magnetic field in the given wave is 5 nT.
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what is an asteroid and where are most asteroids located
A rocky, metallic object in the Sun's orbit is called an asteroid. It is bigger than a meteoroid but smaller than a planet in size.
The asteroid belt, a region in our solar system that lies between Mars and Jupiter's orbits, is where the majority of asteroids are found. The wide array of oddly shaped asteroids that make up the asteroid belt range in size from microscopic rocky fragments to massive things with diameters of several hundred kilometres. However, asteroids can also be discovered in other places, including as in the outer solar system and in orbits that are close to the Earth. They are leftovers from the solar system's early development and can be used to learn more about the system's past and current makeup.
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An asteroid is a stony or metallic object that orbits the Sun, is smaller than a planet, and lacks an atmosphere. Most asteroids are found in the asteroid belt, which lies between the orbits of Mars and Jupiter. Despite the asteroid belt house a large number of these celestial bodies, they are not closely spaced, allowing spacecraft to navigate through without collisions.
Explanation:An asteroid is a stony or metallic object orbiting the Sun that is smaller than a planet and shows no evidence of an atmosphere or other types of activity associated with comets.
The majority of asteroids are located in the asteroid belt, a region of the solar system between the orbits of Mars and Jupiter. This main belt is where the orbits are generally the most stable, extending from 2.2 to 3.3 AU from the Sun. While this area contains over 75% of all known asteroids, they are not closely spaced. The typical spacing between such objects down to 1 kilometer in size is actually several million kilometers. This vast distance between asteroids is why spacecraft like Galileo, Cassini, Rosetta, and New Horizons have been able to travel through the asteroid belt without collision.
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Disease samples from two patients were collected and subjected to serial dilutions before running an elisa. What does it mean if the disease can be detected in samples from one person only at a dilution of 1/5, but the disease can be detected in the other patient at a dilution of 1/5 and 1/100?.
If diseases can be detected with the samples of serial dilution means that both patients have the disease. But, the second patient has the disease at a higher level than the first patient.
ELISA test stands for enzyme-linked immunosorbent assay test. This test is performed to detect the amount and the type of antibodies for a disease present in your blood. ELISA test may be performed to diagnose the diseases like syphilis, HIV, Lyme disease, rotavirus, zika virus, etc.
Serial dilution is a process of performing dilution of a sample in a series to know the number of organisms present in that sample. In a dilution of 1:5, the concentration is lesser than the 1/100 dilution, it is more likely to provide lesser numbers of pathogen colonies.
In 1/5 dilution, a total of 5 parts comprise 1 part of the sample as solute and 4 parts of the diluent or solvent. While, in a dilution of 1/100, a total of 100 parts comprises 1 part of solute and 99 parts of solvent. 1/100 would provide a large number of disease-causing organisms in the sample.
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a boy blows softly across the top of a soda bottle. the sound waves vibrate with a frequency of 1580 hz at the second lowest harmonic. how deep is the bottle?
A boy blows softly across the top of a soda bottle. the sound waves vibrate with a frequency of 1580 hz at the second lowest harmonic. The depth of the bottle is approximately 0.109 meters.
Sound waves can be described as longitudinal waves because the particles in the medium vibrate parallel to the direction of wave propagation. As the sound wave travels, it creates areas of compression and rarefaction, where the air particles are closer together or farther apart, respectively.
Humans perceive sound waves through their ears, where the vibrations of the sound waves are detected by the eardrums and converted into electrical signals that the brain interprets as sound. Sound waves are not only important for communication and music but also have various applications in fields such as acoustics, medicine, and engineering.
To determine the depth of the bottle, we need to use the formula:
L = (n/2) x (v/f)
Where L is the length of the air column in the bottle, n is the harmonic number (in this case, it is the second lowest harmonic, which means n=2), v is the speed of sound in air (which is approximately 343 m/s at room temperature), and f is the frequency of the sound wave (which is 1580 Hz).
Plugging in these values, we get:
L = (2/2) x (343/1580)
L = 0.109 m
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According to the octet rule, the first energy level is stable with ________ electrons and the outermost energy level is stable with__________electrons.
According to the octet rule, the first energy level, also known as the K shell, is stable with a maximum of 2 electrons. This is because the K shell only has one subshell, which can hold a maximum of 2 electrons.
The outermost energy level, also known as the valence shell, is stable with a maximum of 8 electrons. This is because the valence shell has multiple subshells, including s, p, d, and f subshells, which can hold a total of 8 electrons. The octet rule states that atoms tend to gain, lose, or share electrons in order to achieve a full outermost energy level with 8 electrons, which results in greater stability.
The octet rule states that atoms are most stable when they have a full set of electrons in their outermost energy level, which typically means having 8 electrons (except for the first energy level). This is why atoms often form bonds with other atoms to achieve this stable configuration.
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a man is tied to one end of a 42-m elasticized (bungee)cord. The other end of the cord is secured to a winch at the middle of a bridge. If the man jumps off the bridge, for how long will he fall before the cord begins to stretch? (Use 4.9t2=s, where t is time and s is distance.)
The man will fall for approximately 0.97 seconds before the cord begins to stretch, and then another 0.97 seconds for the cord to stretch and rebound, for a total fall time of approximately 1.92 seconds.
The man will fall for approximately 1.92 seconds before the cord begins to stretch.
To solve for this, we can use the equation 4.9t^2 = s, where t is time and s is distance. In this case, s is equal to the length of the cord, which is 42 meters.
So, we can plug in 42 meters for s:
4.9t^2 = 42
Next, we can solve for t by dividing both sides by 4.9:
t^2 = 8.571
And then taking the square root of both sides:
t ≈ 2.93 seconds
However, this is the total time it will take for the man to stop falling, which includes the time it takes for the cord to stretch and rebound. So we need to subtract the time it takes for the cord to begin stretching, which is half of the total time.
t - 1/2t = 1/2t
1/2t ≈ 0.97 seconds
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4.
A block of copper of density 8.9 g/cm² measures 5 cm x 3 cm x 2 cm.
Given that the force of gravity is 10 Nkg !, determine:
(a) the maximum pressure.
(b) the minimum pressure that it can exert on a horizontal surface
Answer:
(a) 4450n/m²
(b) 1780n/m²
Explanation:
maximum pressure=small area
Area=3cm*2cm=6cm²
mass=density*volume
8.9*(5*3*2)=267grammes force=mass*gravity 0.267*10=2.67
pressure=force/area 2.67/0.0006(change 6cm²intom²)=4450
Answer (a)=4450
minimum pressure=Force/Area 5*3=15cm²(into m²)
15/10000=0.0015m² 2.67/0.0015=1780
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a 42 ω resistor and a 20 ω resistor are connected in parallel, and the combination is connected across a 240 v dc line. (a) what is the resistance of the parallel combination? (b) what is the total current through the parallel combination? (c) what is the current through each resistor?
In parallel combination
a. The total resistance is 13.55 Ω
b. The total current is 17.71 A
c. The current on 42 Ω resistor is 5.71 A , The current on 20 Ω resistor is 12 A.
We need to know parallel circuits to solve this problem. The total resistance of the parallel circuit is
1/Rtotal = 1/R1 + 1/R2
the voltage on each resistor will be the same
Vtotal = V1 = V2
From the question above, we know that:
R1 = 42 Ω
R2 = 20 Ω
V = 240 V
1/Rtotal = 1/R1 + 1/R2
1/Rtotal = 1/42 + 1/20
1/Rtotal = 31/420
Rtotal = 13.55 Ω
Itotal = V / Rtotal
Itotal = 240 / 13.55
Itotal = 17.71 A
I1 = V / R1
I1 = 240 / 42
I1 = 5.71 A
I2 = V / R2
I2 = 240 / 20
I2 = 12 A
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guys pls thi is my last pointa just answer this!!!!(WILL GIVE BRAINLY) A student takes apart a wooden box. What can they build with the materials from the box?
A) They cannot make anything with the materials.
B) They can make something new with the materials.
C) They can only make a wooden box from the materials.
Answer:
i guess u could pick "B" :)
Explanation:
Light of wavelength 675 nm passesthrough a double slit, and makes itsfirst minimum (m = 1) at an angle of0.111 deg. What is the separation ofthe slits, d, in MILLIMETERS?(Remember, milli means 10-3.)(Unit = mm)
wavelength = 675 nanometer
\(\begin{gathered} \wedge=675nm \\ \text{Convert to mm} \\ \wedge=0.000675\operatorname{mm} \end{gathered}\)Therefore,
\(\begin{gathered} d\sin 0.111=m\wedge \\ d=\frac{m\wedge}{\sin0.111} \\ d=\frac{1\times0.000675}{0.00193731425\times2} \\ d=\frac{0.000675}{0.00193731425\times2} \\ d=0.17421063226\operatorname{mm} \\ d=0.174\operatorname{mm} \end{gathered}\)calculate the amount of work done to move 1 kg mass from the surface of the earth to a point 10⁵ km from the centre of the earth
The quantum of work done to move a 1 kg mass from the face of the earth to a point 10 ⁵ km from the centre of the earth is4.92 x 10 ⁸J.
The quantum of work done to move 1 kg mass from the face of the earth to a point 10 ⁵ km from the centre of the earth can be calculated using the gravitational implicit energy formula.
The gravitational implicit energy is the quantum of work done by an external force in bringing an object from perpetuity to a point in space where it can be told by graveness. When an object is moved from the face of the earth to a point 10 ⁵ km from the centre of the earth, the gravitational implicit energy of the object increases.
The formula for gravitational implicit energy is given by U = - GMm/ r where U is the gravitational implicit energy G is the universal gravitational constant M is the mass of the earth m is the mass of the object r is the distance between the object and the centre of the earth.
We know that the mass of the object is 1 kg, the mass of the earth is and the distance from the centre of the earth to a point 10 ⁵ km down is Plugging these values into the formula, we get thus, the quantum of work done to move a 1 kg mass from the face of the earth to a point 10 ⁵ km from the centre of the earth is 4.92 x 10 ⁸J.
the mass of the earth is \(5.97 * 10^2^4 kg\),
and the distance from the centre of the earth to a point 10⁵ km away is:
\(= 6.38 * 10^6 + 10^5 km\)
\(= 6.48 * 10^6 km\)
\(= 6.48 * 10^9 m\).
Plugging these values into the formula, we get
\(U = -6.67 * 10^-^1^1 * 5.97 * 10^2^4 * 1 / 6.48 * 10^9\)
\(= -4.92 * 10^8 J\)
Therefore, the amount of work done to move a 1 kg mass from the surface of the earth to a point 10⁵ km from the centre of the earth is 4.92 x 10⁸ J.
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A particle moves along an s-axis, use the given information to find the position function of the particle.
To find the position function of the particle, we can integrate the given acceleration function, a(t), twice with respect to time. Given that a(t) = t^2 + 2t - 7, we'll integrate it twice to obtain the position function, s(t).
Let's proceed with the integration step by step:
Step 1: Integrate a(t) with respect to time to find the velocity function, v(t):
∫(a(t) dt) = ∫((t^2 + 2t - 7) dt)
Integrating each term separately:
∫(t^2 dt) + ∫(2t dt) - ∫(7 dt)
= (1/3)t^3 + t^2 - 7t + C1
Since we know that v(0) = 0, we can substitute t = 0 and solve for the constant C1:
v(0) = (1/3)(0)^3 + (0)^2 - 7(0) + C1
0 = 0 + 0 + 0 + C1
C1 = 0
Therefore, the velocity function becomes:
v(t) = (1/3)t^3 + t^2 - 7t
Step 2: Integrate v(t) with respect to time to find the position function, s(t):
∫(v(t) dt) = ∫(((1/3)t^3 + t^2 - 7t) dt)
Integrating each term separately:
∫((1/3)t^3 dt) + ∫(t^2 dt) - ∫(7t dt)
= (1/12)t^4 + (1/3)t^3 - (7/2)t^2 + C2
Since we know that s(0) = 0, we can substitute t = 0 and solve for the constant C2:
s(0) = (1/12)(0)^4 + (1/3)(0)^3 - (7/2)(0)^2 + C2
0 = 0 + 0 + 0 + C2
C2 = 0
Therefore, the position function becomes:
s(t) = (1/12)t^4 + (1/3)t^3 - (7/2)t^2
Hence, the position function of the particle moving along the s-axis is given by s(t) = (1/12)t^4 + (1/3)t^3 - (7/2)t^2.
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What is a physical property of matter 
A. ability to react with acid
B. State of matter
C. flame ability
D. ability to react with oxygen
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A cheetah runs at 93km/he to the east. This describes the cheetah’s
A.) Displacement
B.) Instantaneous Speed
C.) Average Speed
D.) Average Velocity
human cell has 46 chromosomes. At the end of mitosis, there are two cells, each with 46 chromosomes, for a total of 92 chromosomes split between both cells.
Which statement describes meiosis in a human cell?
1. At the end of meiosis, there are two cells, each with 46 chromosomes, for a total of 92 chromosomes split between both cells.
2. At the end of meiosis, there are four cells, each with 23 chromosomes, for a total of 92 chromosomes split between the four cells.
3. At the end of meiosis, there are four cells, each with 46 chromosomes, for a total of 184 chromosomes split between the four cells.
4.At the end of meiosis, there are two cells, each with 23 chromosomes, for a total of 184 chromosomes split between both cells.
Answer:
2.At the end of meiosis, there are four cells each with 23 chromosomes, for a total of 92 chromosomes split between the four cells.
10 points
A 61.0 kg box is sitting at rest. In order to change the box's state of
motion, Jamie must apply 75.1 Newtons of force on the box. Which of the
following represents a possible value for the force of static friction when
Jamie applied 75.1 Newtons of force on the box? (**hint- you do not need
to do math for this problem) *
A. 71.9 N
B. 75.1 N
C. 85.3 N
D. 133 N
A possible value for the force of static friction when Jamie applied 75.1 Newtons of force on the box is 75.1N. Option B is correct.
For the box sitting on a horizontal surface, the formula for calculating the force on the box along the horizontal based on Newton's law is expressed as;
\(\sum F_x=ma_x\)Since the forces acting along the horizontal are the frictional force and moving force, the formula above will become;
\(F_m-F_f=ma_x\)Since the body is static, hence \(a_x=0m/s^2\), the equation becomes;
\(F_m-F_f=m(0)\\F_m-F_f=0\\F_m=F_f\)Given the force Jamie apply on the box to be 75.1Newtons, this shows that the moving force is 75.1N. Hence;
\(F_m =F_f=75.1N\)Hence a possible value for the force of static friction when Jamie applied 75.1 Newtons of force on the box is 75.1N
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Suppose a luminous cloud of gas is discovered emitting an emission spectrum. What can be learned about the cloud from this observation
9. A bicyclist is moving down a hill. Her position on the hill gives her 720 J of potential energy, and her
movement gives her 680 J of kinetic energy. What is her total mechanical energy?
A. 260 J
B. 1400 J
C. 2648 J
D. 2.86×105 J
The total mechanical energy of the bicyclist is 1400 J, obtained by adding her potential energy of 720 J and kinetic energy of 680 J. The correct answer is option B.
The total mechanical energy of a moving object is the sum of its kinetic energy and potential energy. Kinetic energy is defined as the energy an object has due to its motion, whereas potential energy is the energy an object has due to its position or configuration.Therefore, the total mechanical energy of the bicyclist is calculated by adding her kinetic energy and potential energy. According to the question, the bicyclist has 720 J of potential energy and 680 J of kinetic energy.Total mechanical energy = Potential energy + Kinetic energy = 720 J + 680 J = 1400 JTherefore, the total mechanical energy of the bicyclist is 1400 J. Therefore, the correct answer is option B.For more questions on mechanical energy
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the tension in a string from which a 4.0-kg object is suspended in an elevator is equal to 44 n. what is the acceleration of the elevator?
The acceleration of the elevator is 11 m/s² Given: Tension in a string = 44 N, Weight of object = 4 kg. Acceleration is a fundamental concept in physics that refers to the rate at which the velocity of any object changes with the time and is defined as the change in velocity per unit of time.
Formula used: Newton's second law of motion F = ma
Where, F = force applied, m = mass of the object, a = acceleration of the object
We know that, F = ma
Applying the above formula to the object:
44 = 4a
Solving for a, we get: a = 11 m/s²
Therefore, the acceleration of the elevator is 11 m/s².
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A person slaps her leg with her hand, which results in her hand coming to rest in a time interval of 2.35 ms from an initial speed of 3.25 m/s. What is the magnitude of the average contact force exerted on the leg, assuming the total mass of the hand and the forearm to be 1.65 kg? magnitude ____ N Would the contact force on the same hand be any different if the woman clapped her hands together, each with an initial speed of 3.25 m/s, if they come to rest in the same time interval of 2.35 s? O yes, because the initial momentum of the system will be different due to the second hand O no, because the second hand has zero momentum O no, because the change in momentum for the first hand will be the same yes, because the change in momentum is different O It depends on the coeffcient of friction between the two hands. Question Credit: OpenStax College Physics
The answer is C. no, because the change in momentum for the first hand will be the same.
Using the equation F = Δp/Δt, where F is the average contact force, Δp is the change in momentum, and Δt is the time interval, we can solve for the magnitude of the average contact force.
First, we need to find the initial momentum of the hand. Using the equation p = mv, where p is momentum, m is mass, and v is velocity, we can calculate the initial momentum of the hand:
p = (1.65 kg)(3.25 m/s) = 5.3625 kg*m/s
Next, we need to find the final momentum of the hand, which is zero since it comes to rest. Therefore, the change in momentum is:
Δp = 0 - 5.3625 kg*m/s = -5.3625 kg*m/s
Finally, we can plug in the values to find the magnitude of the average contact force:
F = \FRAC{(-5.3625 kg*m/s)}{(2.35 * 10^{-3} s) }≈ 2285 N
So the magnitude of the average contact force exerted on the leg is approximately 2285 N.
If the woman clapped her hands together, each with an initial speed of 3.25 m/s and they come to rest in the same time interval of 2.35 ms, then the contact force on the same hand would be no different. This is because the change in momentum for the first hand would be the same as before (-5.3625 kg*m/s), and the second hand would also have a change in momentum of -5.3625 kg*m/s, resulting in a total change in momentum of -10.725 kg*m/s. Therefore, the answer is C. no, because the change in momentum for the first hand will be the same.
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