25.0 ml of a weak base is titrated with 0.696m solution of hcl. the equivalence point is reached when 10.0 ml of hcl is added. calculate the concentration of oh- in the initial weak base solution.
Answers
The salt completely dissociates in solution, the concentration of OH- is also 0.278 M. This is equal to the concentration of the weak base in the initial solution, since they have a 1:1 stoichiometry. Therefore, the concentration of OH- in the initial weak base solution is 0.278 M.
The balanced chemical equation for the reaction between the weak base and HCl is:
Base + HCl -> Salt + H2O
At the equivalence point, the moles of acid (HCl) added is equal to the moles of base present in the solution:
n(HCl) = n(Base)
The volume of the HCl solution used at the equivalence point is 10.0 mL or 0.0100 L. The molarity of the HCl solution is 0.696 M, so the number of moles of HCl added is:
n(HCl) = 0.696 M x 0.0100 L = 0.00696 mol
Since the stoichiometry of the reaction is 1:1 between HCl and the base, the number of moles of the weak base present in the initial solution is also 0.00696 mol.
The volume of the weak base solution used is 25.0 mL or 0.0250 L. The concentration of the weak base can be calculated as:
C(Base) = n(Base) / V(Base) = 0.00696 mol / 0.0250 L = 0.278 M
At the equivalence point, all of the weak base has been neutralized by the HCl, leaving only the salt of the weak base and H2O in solution. Since the salt of the weak base is a strong electrolyte, it dissociates completely in solution to form its constituent ions. The ion that is basic is the conjugate base of the weak acid, so we can assume that it reacts with water to form hydroxide ions and the weak acid:
Salt + H2O -> Weak acid + OH-
Therefore, the concentration of OH- in the solution at the equivalence point is equal to the concentration of the salt, which can be calculated using the following equation:
\(C(Salt) = C(HCl) x V(HCl) / V(Base) = 0.696 M x 0.0100 L / 0.0250 L = 0.278 M\)
To know more about concentration here
https://brainly.com/question/17206790
#SPJ4
Related Questions
Determine E cell for the reaction: 2 Al +3 Zn^2+→ 2 Al^3+ + 3 Zn. The half reactions are Al^3+(aq) + 3 e- → Al(s) E° = -1.676 V
Zn^2+(aq) + 2 e- → Zn(s) E = -0.763 V
Answers
The E cell for the reaction 2 Al +3 \(Zn^2^+\) → 2 \(Al^3^+\) + 3Zn is 0.913 V.
The cell potential (Ecell) of a redox reaction can be calculated using the standard reduction potentials of the half-reactions involved. The cell potential is given by the equation:
Ecell = E°(reduction) - E°(oxidation)
where E°(reduction) is the standard reduction potential of the reduction half-reaction and E°(oxidation) is the standard oxidation potential of the oxidation half-reaction.
In this case, the reduction half-reaction is:
\(Zn^2^+\) +(aq) + 2 e- → Zn(s) E°(reduction) = -0.763 V
The oxidation half-reaction is:
2 Al(s) → 2 \(Al^3^+\)(aq) + 6 e- E°(oxidation) = -1.676 V
To balance the number of electrons, we need to multiply the reduction half-reaction by 3 and the oxidation half-reaction by 2. Then, the overall balanced redox reaction is:
2 Al(s) + 3 \(Zn^2^+\)(aq) → 2\(Al^3^+\) (aq) + 3 Zn(s)
Substituting the standard reduction and oxidation potentials into the formula for Ecell, we get:
Ecell = E°(reduction) - E°(oxidation)
= -0.763 V - (-1.676 V)
= 0.913 V
Therefore, the cell potential for the given redox reaction is 0.913 V.
For more such questions on cell potential, click on:
https://brainly.com/question/31742433
#SPJ11
The calculated standard cell potential (E°cell) for the given reaction is 2.44 V, which is a positive value. The cell potential is calculated using the formula E° cell = E° cathode - E° anode.
The E° values of the half-reactions are provided, so we can simply add them to obtain the overall E° cell.
The positive value of the cell potential indicates that the reaction is spontaneous, meaning that the forward reaction will occur spontaneously, and the reverse reaction will not occur spontaneously under standard conditions.
This implies that aluminum can be used as a reducing agent for \(Zn^2\)+ ions, with the reaction releasing energy that can be harnessed for useful work.
The positive value of E°cell indicates that the reaction is spontaneous and will proceed in the forward direction as written. The half-reaction for the reduction of \(Zn^{2+}\) has a more positive standard reduction potential than the half-reaction for the reduction of \(Al^{3+}\).
Thus, \(Zn^{2+}\) is a stronger oxidizing agent than \(Al^{3+}\), and Zn will be oxidized while Al will be reduced. The flow of electrons will be from Al to Zn in the external circuit, and this will result in the production of a positive voltage.
The E°cell value can be calculated using the formula E°cell = E°reduction (cathode) - E°reduction (anode). In this case, E°cell = 0.763 V - (-1.676 V) = 2.44 V.
Learn more about standard cell potential here :
https://brainly.com/question/29797132
#SPJ11
1. Fill in the blanks.
a. Breathing is a combined form of______and_______.
b. Oxygen is absorbed by diffusion from______of the lungs.
c. Plants take______gas for respiration. d. Plants have______and______for respiration.
e. Plants have_______and_______for transportation.
Answers
Respiration deals with the gaseous exchange that occur between the individuals and the environment.
What is respiration?The term respiration deals with the gaseous exchange that occur between the individuals and the environment. The individuals take in a gas from the environment and pass out a gas to the environment. This is the way in which the balance of the universe is maintained.
Now, plants take in carbon dioxide and give out oxygen whereas animals take in oxygen and give out carbon dioxide. By so doing, the delicate carbon - oxygen balance in nature is maintained unless it is upturned by anthropogenic activities.
The following fill in the blanks as requested in the question;
a) Inhalation and exhalation'
b) trachea
c) carbon dioxide
d) leaves and stomata
e) xylem and phloem
Learn more about respiration:https://brainly.com/question/12605249
#SPJ1
Answer:
a) inhalation and exhalation
b) trachea
c) carbon dioxide
d) leaves and stomata
e) xylem and phloem
A tank initially holds 200 gal of brine solution containing 3lb of salt. At t=0, another brine solution containing 3lb of salt per gallon is poured into the tank at the rate of 6gal/min, while the well stirred mixture leaves the tank at the same rate. Find the time at which the mixture in the tank contains 6lb of salt. 0.216min 0.168min 2.13min 0.02min
Answers
The tank contains 200 gallons of brine solution with 3 lb of salt. At t = 0, another solution is poured at 6 gal/min, leaving the tank at the same rate. The incoming rate of salt is 18 lb/gal, and the outgoing rate is 6 gal/min. The solution's volume remains constant.
Given that,Initially, the tank holds 200 gallons of brine solution containing 3 lb of salt.At t = 0, another brine solution containing 3 lb of salt per gallon is poured into the tank at the rate of 6 gal/min.The mixture leaves the tank at the same rate.The volume of the tank remains constant.
Now, let's assume that x(t) be the amount of salt in the tank at time t.Therefore,x(0) = 3 lb.
Now, let's find the differential equation that x(t) follows.
In the tank, the incoming rate of salt = 3 lb/gal x 6 gal/min = 18 lb/min.The outgoing rate is 6 gal/min.
The volume of the tank is constant, and it is equal to 200 gallons.∴ (d/dt)x(t) = (18 - 6x(t)/200) lb/min = (9 - 3x(t)/100) lb/min (On dividing by 2)Separating the variables and integrating, we get:
∫(1/9 - x/300) dx = ∫dt Let u = x/300,
then du = (dx/300)Hence,
∫(1/9 - x/300) dx = ∫\(dt(u/2 - u^2/2)\) = t + C [Where C is the constant of integration]
x/600 - x^2/600 = t + C
Now, we need to find the value of C.
\(C = x(0)/600 - x(0)^2/600C\)
3/600 - 9/360000C = -1/2000
Hence,
\(x/600 - x^2/600 = t - 1/2000\)
Multiplying by 600 on both sides, we get,
\(x - x^2 = 600t - 0.3\)...(1)
Now, we need to find the value of t at which the mixture in the tank contains 6 lb of salt.Substituting x = 6 in equation (1), we get:6 - 6^2 = 600t - 0.3...5 = 600t...t = 5/600 = 0.00833 hours = 0.5 minutes
Therefore, the time at which the mixture in the tank contains 6 lb of salt is 0.5 minutes (approximately).Hence, the correct option is 0.02 min.
To know more about solution Visit:
https://brainly.com/question/15757469
#SPJ11
How many grams of naoh are needed to prepare 546 ml of solution with a ph of 10. 00?.
Answers
Answer:
1. determining the pOH of the solution from the given pH of 10.00 assuming the solution is at 25° C.
A sample of radon gas has a volume of 0.650 L at a temperature of -55.0 C. What volume will the gas occupy at 40.0 C, assuming constant pressure?
Answers
Answer:
0.933 L
Explanation:
Since the pressure is the same, we use the equation \(\frac{V_{1}}{T_{1} } = \frac{V_{2} }{T_{2} }\)
V = Volume
T = Temperature
Since we are given the temperature in Celsius, we need to convert it to Kelvin by adding 273:
-55.0 + 273 = 218
40.0 + 273 = 313
\(\frac{0.650}{218} = \frac{x}{313}\)
\(0.933 = x\)
The gas will occupy a volume of 0.933 L.
(Side note - If the temperature increases, the gas will want to expand, leading to a higher volume.)
the operation of the diesel oxidation catalyst (doc) monitor is being discussed. technician a says that if the temperature at the outlet of the catalyst is not at the predicted temperature, the monitor will fail. technician b says that if the doc fails, the dpf regeneration may not occur. which technician is correct?
Answers
Both of the technicians are being discusing about the operation of the diesel oxidation catalyst (DOC) monitor is correct.
What are the parts and operations of temperature sensors?The temperаture sensor mаy be used to verify а component is operаting аs designed. For exаmple, the normаl operаtion of а diesel oxidаtion cаtаlyst (DOC) will generаte heаt. The PCM cаn monitor the temperаture аt the outlet of the DOC under specific operаting conditions, аnd determine if t is functioning аs designed. This is а criticаl input when meeting the OBDII monitoring requirements. The temperаture sensors cаn аlso be used to control the operаtion of а system.
А DPF needs to be аt а specific temperаture during the regenerаtion process to effectively reduce the level of pаrticulаte mаtter. Using the input from the temperаture sensors, the PCM is аble to chаnge fuel delivery strаtegies to bring the DPF to the desired temperаture for the durаtion of the regenerаtion event.
For more information about diesel oxidation catalysts refer to the link:
https://brainly.com/question/8589209
#SPJ4
A student is working hard on a chemistry lab experiment that uses a strong acid. Halfway through the lab, the student gets hungry and starts eating a bag of chips. When the student licks their fingers, they start to have a severe reaction. summary
Answers
what systems might not work right when you have a cold
Answers
Answer:
hello :3
A cold is a contagious upper respiratory infection that affects your nose, throat, sinuses and trachea (windpipe).
Explanation:
have a nice day :3
Calculate the percent by mass of each element in the following compounds.
HCIO3
Answers
The percent by mass of each element in \(HClO_{3}\) is approximately:
Hydrogen (H): 1.05%, Chlorine (Cl): 36.75%, Oxygen (O): 31.20%
What is mass?
To calculate the percent by mass of each element in the compound \(HClO_{3}\) , we need to determine the molar mass of the compound and the molar mass of each element present in the compound.
The molar mass of \(HClO_{3}\) can be calculated as follows:
Molar mass of H = 1.01 g/mol
Molar mass of Cl = 35.45 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of \(HClO_{3}\) = (1 x 1.01) + (1 x 35.45) + (3 x 16.00) = 96.46 g/mol
Therefore, the percent by mass of each element in \(HClO_{3}\) is as follows:
Percent by mass of H = (mass of H / molar mass of \(HClO_{3}\) ) x 100%
= (1.01 g / 96.46 g) x 100%
= 1.05%
Percent by mass of Cl = (mass of Cl / molar mass of \(HClO_{3}\) ) x 100%
= (35.45 g / 96.46 g) x 100%
= 36.75%
Percent by mass of O = (mass of O / molar mass of \(HClO_{3}\) ) x 100%
= (3 x 16.00 g / 96.46 g) x 100%
= 31.20%
Therefore, the percent by mass of each element in \(HClO_{3}\) is approximately:
Hydrogen (H): 1.05%Chlorine (Cl): 36.75%Oxygen (O): 31.20%To know more about molar mass, visit:
https://brainly.com/question/31545539
#SPJ1
The sodium-potassium pump functions to pump
sodium ions out of the cell and potassium ions into the cell.
sodium ions into the cell and potassium ions out of the cell.
sodium and potassium ions into the cell.
sodium and potassium ions out of the cell.
sodium and potassium ions in both directions across the cell membrane.
Answers
The sodium potassium pump helps in maintaining the acid-base balance of the body and helps in proper kidney function.
Explain about sodium-potassium pump:Operation sodium-potassium pump of moves sodium ions out of the cell and potassium ions into the cell. When a cell membrane moves molecules or ions against a concentration gradient or against an electrical or pressure gradient, the process is called active transport. Different substances that are actively transported include:
--> sodium ions,
--> potassium ions,
--> calcium ions and
--> some amino acids.
There are two types of active transport which are divided according to the energy that is used to cause the transport. They include:
--> primary and
--> secondary active transport.
PRIMARY ACTIVE TRANSPORT
A typical example is the SODIUM-POTASSIUM PUMP( Na+ - k+). This is a transport process that pumps sodium ions outward through the cell membrane of all cells and at the same time pumps potassium ions from the outside to the inside. This pump helps to:
--> maintain the sodium and potassium concentration differences across the cell membrane
--> establish a negative electrical voltage inside the cells.
The mechanism or operation of the pump involves the following steps:
--> two potassium ions bind on the outside of the carrier protein and three sodium ions bind on the inside.
To learn more about sodium-potassium pump refer to:
https://brainly.com/question/11257671
#SPJ4
what ionic compound is gold found in
Answers
Gold is found in various ionic compounds, but one of the most well-known and commercially significant compounds is gold chloride, also known as auric chloride or gold(III) chloride.
The chemical formula for gold chloride is AuCl₃. Gold chloride is an ionic compound composed of gold cations (Au³⁺) and chloride anions (Cl-). It is a yellow-orange solid that is highly soluble in water. Gold chloride can be formed by reacting the gold metal with chlorine gas or by dissolving the gold metal in aqua regia, which is a mixture of concentrated nitric acid and hydrochloric acid.
Gold chloride has several uses and applications. It is commonly used in the field of nanotechnology for the synthesis of gold nanoparticles. These nanoparticles have unique optical, electronic, and catalytic properties, making them valuable in various fields such as medicine, electronics, and materials science.
In addition to gold chloride, gold can also form other ionic compounds with different anions, such as gold bromide (AuBr), gold iodide (AuI), gold sulfide (Au2S), and gold cyanide (AuCN). These compounds have their own unique properties and applications.
know more about anions here:
https://brainly.com/question/31485566
#SPJ8
Organic reactions have competing pathways that lead to side products. Indicate which side products could be produced in the dehydration of cyclohexanol to cyclohexene?.
Answers
Side products produced in the dehydration of cyclohexanol to cyclohexene would be ethers
Alcohols to alkene
Alcohols are converted into desired alkene using acid catalysed elimination reaction Alcohols undergo dehydration reaction with conc. Sulphuric acid or conc. Phosphoric acid by undergoing elimination reaction where one mole of alcohol gives one mole of the alkene as the product.C6H11OH with conc H2SO4 gives C6H10 + H2O
Dehydration of cyclohexanol follows E1 mechanismWhat is E1 mechanism?
The E1 mechanism, also known as unimolecular elimination, are usually two steps involved – ionization and deprotonation. During ionization there is formation of carbocation as an intermediate. In deprotonation, a proton is lost by the carbocation.Dehydration reaction involves 3 steps:
First is the protonation of the alcohol by the acid. In this process, the Hydroxyl-group is converted from a poor leaving group to a much better one by protonation of oxygen to create an oxonium ion The carbocation intermediate is then formed in rate-determining step by the loss of a water molecule. Finally we generate an alkene following the loss of a proton adjacent to carbocation.Even weakly basic substances such as water, can deprotonate a carbocation to create an alkene.
Learn more about E1 mechanism at https://brainly.com/question/17045412
#SPJ4
Suppose the cylinder had a mass of 20kg and started at a height of 2,000m .if the initial temperature of the water was 25° C, what would be the final temperature.?
Answers
Answer:
Explanation:
m-mass of substance
s- specific heat capacity
dt- change in temperature.
So equating, mgh=ms(dt), we get (dt)=gh/s.
Students place paper clips on a desk and then hold a magnet under the desk. What evidence would BEST show that the
magnetic field was able to pass through the desk?
O A The top of the desk is made of a kind of plastic.
OB. The paper clips move when the magnet is moved under the desk.
OC. The magnet they are using is the largest one in the classroom.
OD. The students were able to pick up these paper clips with a magnet.
Answers
Answer:
B
Explanation:
got it right on test
Answer:
Yes the correct answer is B
Explanation:
Have a good day!!!
HELP ASAP 10 POINTS
What type of interference caused a "super crest" to form during Young's experiment?
Constructive interference
Doppler interference
Destructive interference
Operational Interference
Answers
Answer:
the answer is destructive interference
What do we mean when we say a chemical reaction is balanced? (Several choices can be correct.)
There is an equal number of solids, liquids, and gases on both sides of the reaction arrow.
There is an equal number of products on the right side of the equation as there are reactants on the left side of the
arrow.
The total number of each atom is the same on both sides of the reaction arrow.
The net charge on both sides of the reaction arrow is the same.
Answers
Answer:
2 and 3
Explanation:
A chemical reaction is defined as the process in which two or more reactants combined together chemically and gives a different product.
A balanced chemical equation involves an equal number of atoms on the reactant and product side. A balanced chemical reaction occurs when the atoms present on the reactant side or left side of the arrow is equal to the atoms on the product side or right side of the arrow.
The process of the balanced chemical equation is based on errors and trials in which the atoms in each element is identified, the atoms are then multiplied with required numbers, the addition of coefficient in front of molecules and check the equation at last.
Hence, the correct options are "2 and 3".
for a certain chemical reaction, the equilibrium constant at . calculate the standard gibbs free energy of your answer to significant digits.
Answers
The standard Gibbs free energy of a chemical reaction can be calculated using the equilibrium constant. In this case, with an equilibrium constant of \(9.4*10^(^-^1^1)\) at \(10.0 ^0C\), the standard Gibbs free energy is approximately 200 J/mol.
The standard Gibbs free energy change (Δ\(G^0\)) of a reaction can be calculated using the equilibrium constant (K) and the formula Δ\(G^0\) = -RTln(K), where R is the gas constant (8.314 J/(mol·K)) and T is the temperature in Kelvin. To convert the given temperature of \(10.0 ^0C\) to Kelvin, we add 273.15 to it, resulting in 283.15 K.
Plugging the values into the formula, we have:
\(\Delta G^0 = - (8.314 J/(mol.K)) * ln(9.4*10^(^-^1^1^))\\\Delta G^0 = - (8.314 J/(mol.K)) * (-24.660)\\\Delta G^0= 204.67 J/mol\)
Rounding the answer to 2 significant digits, the standard Gibbs free energy of the reaction is approximately 200 J/mol. This value represents the energy change associated with the reaction under standard conditions (1 atm pressure, 1 M concentrations) at \(10.0 ^0C\).
Learn more about Gibbs free energy here:
https://brainly.com/question/29753420
#SPJ11
The complete question is:
for a particular chemical reaction, the equilibrium constant K - \(9.4*10^(^-^1^1)\) at \(10.0 ^0C\). Calculate the standard Gibbs free energy of the reaction. Round your answer to 2 significant digits.
Which statement is true about oxygen -17 and oxygen-18, A they do not have the same number of protons. B there atoms have a identical mass. C they are isotopes of oxygen. D they have the same mass number .
Answers
23. Fatty acyl CoA desaturase is responsible for the synthesis of: a. Saturated fatty acid c. Strictly essential fatty acid b. Unsaturated fatty acid d. Glucogenic amino acid 24. Ketone bodies are: a. Water-soluble compounds produced as byproducts when fatty acids are broken down for energy in the liver (produced by liver mitochondria) and kidney 3
Answers
23. Correct option is b. Fatty acyl CoA desaturase is responsible for the synthesis of unsaturated fatty acid. 24. Correct option is a. Ketone bodies are water-soluble compounds produced as byproducts when fatty acids are broken down for energy in the liver and kidney.
Fatty acyl CoA desaturase is a vital enzyme that is responsible for the desaturation of fatty acyl CoA to unsaturated fatty acids. It helps to convert fatty acyl CoA molecules with long, saturated carbon chains into molecules with at least one double bond, producing fatty acids. The reaction is important for the biosynthesis of unsaturated fatty acids, which are important components of the cell membrane.
Saturated fatty acid is produced by enzymes such as stearoyl-CoA desaturase. Saturated fatty acids have no double bonds between the carbon atoms of the fatty acid chain, so they are saturated with hydrogen atoms. They are solid at room temperature and are abundant in dairy products, meats, and some oils.
Ketone bodies are water-soluble compounds produced as byproducts when fatty acids are broken down for energy in the liver and kidney. They are formed when the body uses fat instead of glucose as a source of energy, and they provide an alternative fuel for the brain and other organs. The liver can produce ketone bodies from fatty acids when glucose is scarce. This occurs during fasting or when a low-carbohydrate diet is followed. The three types of ketone bodies are acetone, acetoacetate, and β-hydroxybutyrate.
To know more about Ketone bodies visit-
brainly.com/question/15199415
#SPJ11
Cuando haces ejercicios abdominales estas realizando un trabajo. Si haces el mismo numero de abdominales en la mitad de tiempo que acostumbras, ¿como seria tu rendimiento en terminos de potencia comparandolo con el tiempo normal en que las haces?
Answers
Answer:
El rendimiento seria mayor ya que la potencia aumenta.
Explanation:
La potencia aumenta cuando determinado trabajo se realiza en menor cantidad de tiempo.
3. Briefly discuss the results of the TLC. Was there evidence of unreacted p-nitrobenzaldehyde in either product
Answers
TLC means Thin Layer Chromatography. It is a method that can best be described as "Affinity-Based" used in the separation of compounds that are in a mixture.
What is unreacted p-nitrobenzaldehyde?Unreacted p-nitrobenzaldehyde is simply an organic aromatic compound that contains a nitro group para-substituted to an aldehyde. in this case, if it is unreacted, that means it is the same as before the chemical reation.
Note that the question is missing key information hence the general answer.
Learn more about TCL at:
https://brainly.com/question/10296715
Question :-
How to balance chemical equations?
I need steps
Don't spam from Go0gle
!!!!CLASS 10 CHEMISTRY!!!!
Answers
Answer:
the main aim of balance in an equation is making show that the total number of substances on the reactant side is equal to the total number of substances on the product side
Explanation:
so if we were to balance the equation of water water is a compound containing two molecules of hydrogen and one molecule of oxygen therefore
H+O=H2O
\(H+O_2= H_2O\)
Element | Reactant | Product
H | 1 × 4 | 2×2
O | 2 | 1 × 2
\(4H+O_2= 2H_2O\)
should i get this? i heard it smells good
Answers
Answer: Maybe not? Unless you care about namebrand, theres lots of dupes.
Which of the following would cause a decrease in the volume of a sealed balloon filled with helium? (4 points)
Adding oxygen gas
Decreasing temperature
Adding more helium
Decreasing pressure
Answers
Answer:
Decreasing temperature
Explanation:
Just took the test
If the volume of the sealed balloon is decreased, then it is because of a decrease in the temperature. Thus, option b is correct.
What is the relation between volume and temperature?The volume of the gas and the temperature show a direct relationship in accordance with the ideal gas equation. The increase or decrease in volume is directly affected by the temperature.
When the balloon is sealed no new volume of the oxygen or helium gas can be added nor the decrease in pressure will decrease the volume. But a decrease in temperature will decrease in volume as,
V ∝ T
Therefore, option B. decreases the temperature decreases the volume.
Learn more about volume here:
https://brainly.com/question/1414456
#SPJ2
How many rh atoms would have to be placed side by side to span a distance of 6.0?
Answers
24074 (Rh) atoms would have to be placed side by side to span a distance of 6.0.
What is Atom?The smallest piece of matter that exists in the universe is an atom. Atoms that are neutral or ionized make up every material in our environment. The atoms are tiny, spherical objects, and the Armstrong unit is used to measure their diameter.
1A = (10^-10)
According to the given information :The diameter of a rhodium atom (Rh) is approximately d = 2.7 x 10^-10
so,
It is assumed that if we keep n atoms next to one another, we will create a distance of L = 6.5μm = 6.5 x 10^-6
In this case,
We can see that if we keep the atoms side by side, the total length of them will be determined by adding the total diameters.
we have:
L = n d
n = L/d
Putting values :
n = (6.5 x 10^-6)/( 2.7 x 10^-10)
n = 24074
24074 (Rh) atoms would have to be placed side by side to span a distance of 6.0
To know more about Atom visit:
https://brainly.com/question/1566330
#SPJ4
Calculate the pH and the pOH of an aqueous solution that is 0.045 M in HCl(aq) and 0.095 M in HBr(aq) at 25 °C. pH = pОН: =
Answers
The pH and the pOH of an aqueous solution that is 0.045 M in HCl(aq) and 0.095 M in HBr(aq) at 25 °C is 1.35, and 12.98 respectively.
To calculate the pH and pOH of the solution, we need to use the concentration of the acidic solutions and the dissociation constants of HCl and HBr.
First, calculate the pH:
For HCl (aq):
[HCl] = 0.045 M
HCl is a strong acid and dissociates completely in water, so the concentration of H⁺ ions is equal to the concentration of HCl:
[H⁺] = 0.045 M
Taking the negative logarithm (base 10) of the H⁺ concentration gives us the pH:
pH = -log10(0.045)
pH = 1.35
Now, let's calculate the pOH:
For HBr(aq):
[HBr] = 0.095 M
HBr is also a strong acid, and its dissociation is similar to HCl. The concentration of H⁺ ions is equal to the concentration of HBr:
[H⁺] = 0.095 M
Again, taking the negative logarithm (base 10) of the H⁺ concentration gives us the pH:
pH = -log10(0.095)
pH = 1.02
Since pH + pOH = 14 (at 25 °C), we can calculate the pOH:
pOH = 14 - pH
pOH = 14 - 1.02
pOH = 12.98
Therefore, the pH of the solution is approximately 1.35, and the pOH is approximately 12.98.
To know more about aqueous solution here
https://brainly.com/question/1382478
#SPJ4
What are the parts of the cell theory?Mark all that apply
Answers
Answer:
Cell theory states that cell living organisms are composed of at least one cell, which are the basic unit of life. Cells are always produced from other living cells, and cannot spontaneously generate
Write the net ionic equation for the reaction of aqueous solutions of lead(II) nitrate and sodium iodide. Group of answer choices
Answers
When a lead (II) nitrate and a sodium iodide are mixed, the following reaction takes place: Solution: Pb(NO3)2 + 2 NaI → PbI2 + 2 NaNO3
Lead nitrate reacts with sodium iodide to produce lead iodide and sodium nitrate. When dissolved in water, these reactants are dissociated into their respective cations and anions.
This allows for a net ionic equation to be formed.
Net Ionic Equation:
Pb2+ + 2 I- → PbI2
There are no spectators present in this reaction, which means that all ions will participate in forming products.
As a result, the above equation is the net ionic equation because it represents only those species that take part in the reaction.
Thus, the net ionic equation for the reaction of aqueous solutions of lead (II) nitrate and sodium iodide is
"Pb2+ + 2 I- → PbI2" which consists of only those species that take part in the reaction.
to know more about reactants visit:
https://brainly.com/question/14449229
#SPJ11
2. What is the mathematical equation for kinetic energy?
Hi guy’s
I need help plz.
Answers
Explanation:
The kinetic energy of an object given it's mass and velocity can be found by using the formula
\(kinetic \: \: \: energy = \frac{1}{2} m {v}^{2} \\ \)where
m is the mass
v is the velocity
Hope this helps you
a certain drug is made from only two ingredients: compound a and compound b. there are milliliters of compound a used for every milliliters of compound b. if a chemist wants to make milliliters of the drug, how many milliliters of compound a are needed?
Answers
To calculate it using the formulas and learn about drug.
What is drug?
Drugs are by definition chemicals that, when ingested into a living system, influence or modify physiology. Both natural and artificial materials are acceptable. They are low-mass chemical structures, both in terms of atomic and molecular mass.
What is chemist?
At the atomic and molecular levels, chemists look into the characteristics of matter. They gauge proportions and reaction rates to better comprehend new substances and their behavior or to develop novel compounds for use in a variety of real-world scenarios.
Ratio of the compounds A and B are given as
compound A: compound B= 6:5
Now, chemist own to make a drug of 814ml, so we have to distribute these 814 ml in the ratio of 6:5. To make chemically correct drug.
Amount of compound=6/(6+5*814)
=6/11*814=444 ml
∴ Amount of compound a is needed 44 ml.
Therefore, 44 millimeters of a compound are needed.
To learn more about drug from the given link.
https://brainly.com/question/1189815
#SPJ4