2.5x-1.5x=21 Solve for x:

Answer:

gvvvvvbb

Step-by-step explanation:

gghhhhbbhhjhhhhh

Answer:

AS a fraction: 1\(\frac{11}{20}\)

AS a decimal: 1.55

Step-by-step explanation:

4/5 + 3/4

least common multiple of 5 and 4 is 20. Conver \(\frac{4}{5}\) and \(\frac{3}{4}\) to fractions with denominator 20.

16/20 + 15/20

since \(\frac{16}{20} and \frac{15}{20}\)  have the same denominator, add them by adding their numerators.

\(\frac{16 + 15}{20}\)

Add 16 and 15 to get 31.

\(\frac{31}{20}\)

\(\frac{31}{2^{2}x5 } = 1\frac{11}{20}\)

Hope that helps and have a great day! =) ~sunshine~

Check the picture below.

so since the shaded area is really just the area of those triangles, let's simply get the area of those two triangles with that base and height.

\(2\left[\cfrac{1}{2}\stackrel{ base }{\left( \cfrac{x+6}{2} \right)}\stackrel{ height }{(x+5)} \right]\implies \cfrac{(x+6)(x+5)}{2}\implies \stackrel{ \textit{shaded region} }{\cfrac{x^2+11x+30}{2}}\)

Answer:

After 1.5 seconds, the rocket will have reached a height of 90 centimeters.

Step-by-step explanation:

You know  that for Jivesh's Model A rocket, he uses the equation:

h = −40*t² + 120*t

You want to know at what time the height of the model A rocket is 90 centimeters, that is, at what time t the height of the rocket h has a value of 90. Substituting this value in the equation you obtain:

90= −40*t² + 120*t

A quadratic equation has the general form:

a*x² + b*x +c= 0

where a, b and c are known values ​​and a cannot be 0.

Taking the equation for Jivesh's model A rocket to that form, you get:

-40*t² +120*t - 90= 0

The roots of a quadratic equation are the values ​​of the unknown that satisfy the equation. And solving a quadratic equation is finding the roots of the equation. For this you use the formula:

\(\frac{-b+-\sqrt{b^{2}-4*a*c } }{2*a}\)

In this case, solving the equation is calculating the values ​​of t, that is, you find the moment when the rocket will have reached a height of 90 centimeters.

Being a= -40, b=120 and c= -90, then

\(\frac{-120+-\sqrt{120^{2}-4*(-40)*(-90) } }{2*(-40)}\)

\(\frac{-120+-\sqrt{14,400-14,400} }{2*(-40)}\)

\(\frac{-120+-\sqrt{0} }{2*(-40)}\)

\(\frac{-120+-0 }{2*(-40)}\)

\(\frac{-120 }{2*(-40)}=\frac{-120}{-80} =1.5\)

This means that after 1.5 seconds, the rocket will have reached a height of 90 centimeters.

The probability that the rook ends at a8 after infinite time is 7/296.  

Given that the rook is on a chessboard with 8 rows and 8 columns. The rows are numbered 1, 2, ... , 8 and the columns are lettered a, b, ... , h. The rook begins at a1 (the square in both row 1 and column a).

Every minute, the rook randomly moves to a different square either in the same row or the same column. The rook continues to move until it arrives a square in either row 8 or column h. We have to find the probability that the rook ends at a8.

We can see that there are 14 such squares from a1 to a8 that lie in either the 8th row or the h column. Let's assume that the rook is at a square that is neither in the 8th row nor the h column.

Then the rook has 14 squares to move to in the 8th row or the h column out of the remaining 14 + 62 - 2 = 74 squares on the board.

Therefore, the probability that the rook will move to either row 8 or column h is 14/74 = 7/37.

So, if the rook moves to a square in row 8 or column h, the probability that it ends at a8 is 1/8.

So, the probability that the rook ends at a8 is (7/37) × (1/8) = 7/296.

Thus, the probability that the rook ends at a8 after infinite time is 7/296.  

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The answers are D.)3, B.) Values were not subtracted from each side, and A.) The substitution property of equality

A straight line is a combination of endless points joined on both sides of the point.

We have;

UX=WZ

VW=XY

In line 3 the statement does not justify.

Because values were not subtracted from each side.

The reason should be substitution property of equality.

Thus, the answers are D.)3, B.) Values were not subtracted from each side, and A.) The substitution property of equality

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Answer:

I just got it right on the test

Step-by-step explanation:

Answer:

slope is -2/3, and the y intercept is 1.

Step-by-step explanation:

Using y=Mx+b (slope intercept form), where M=slope, and B = Y intercept , you can find which valurs are which.

Answer:

\(a_c=16m/s^2\)

Step-by-step explanation:

the centripetal acceleration is defined by the following formula:

\(a=v^2/r\)

where v is the tangential velocity, and r is the radius.

if we have an acceleration of \(20m/s^2\) and a radius of 4m the equation becomes:

\(20m/s^2=v^2/(4m)\)

and from here we can find the tangential velocity of the object:

\(v^2=(20m/s^2)(4m)\\v^2=80m^2/s^2\)

we can use this quantity to find the centripetal acceleration when the radius is 5m.

Again using the centripetal acceleration formula:

\(a=v^2/r\)

we substitute \(v^2\) and \(r=5m\):

\(a_c=(80m^2/s^2)/(5m)\\a_c=16m/s^2\)

the centripetal acceleration is 16 \(m/s^2\)

Answer:

5 hours

Step-by-step explanation:

Let x represent the number of hours

12 + 9x = 57

9x = 57 - 12

9x = 45

x = 5

Answer:

36.166

Step-by-step explanation:

The chance of selecting a card that is either red or has an even number is 10/11 or about 91%.

To find the probability of drawing a red card or an even-numbered card, we need to use the laws of probability. We can calculate the probability of each event separately and then add them together to get the probability of both events happening.

The probability of drawing a red card is 6/11, since there are 6 red cards out of a total of 11 cards.

The probability of drawing an even-numbered card is 5/11, since there are 5 even-numbered cards out of a total of 11 cards.

To find the probability of drawing a red card or an even-numbered card, we add the probability of drawing a red card and the probability of drawing an even-numbered card and then subtract the probability of drawing a card that is both red and even-numbered (i.e., the card numbered 2).

P(R or E) = P(R) + P(E) - P(R and E)

P(R or E) = 6/11 + 5/11 - 1/11

P(R or E) = 10/11

Therefore, the probability of drawing a red card or an even-numbered card is 10/11 or approximately 0.91.

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The coordinate of points of the image are:

A' = (-1, 1), B' = (1, 1) and C' = (1, -1)

To dilate the preimage about the origin using a scale factor of 1/3, we can use the following formula:

image coordinate = scale factor * preimage coordinate

Substituting the values, we get:

A' = 1/3 * (-3, 3)

A' = (-1, 1)

B' = 1/3 * (3, 3)

B' = (1, 1)

C' = 1/3 * (3, -3)

C'  = (1, -1)

Thus, the coordinate of points of the image are A' = (-1, 1), B' = (1, 1) and C'  = (1, -1)

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we have the function

f(t)=9500(0.1)^t

this is an exponential function of the form

y=a(b)^x

where

a is the initial value

b is the base of the function

In this problem

b=0.1

the value of b is less than 1

that means

b=1-r

r=1-0.1

r=0.90

the rate of change is 90%

Step-by-step explanation:

1+1 is 2 because 1 and 1 will be 2

Part A: The system of inequalities is x + 3y ≤ 9 and x + y ≥ 2, where x represents servings of dry food and y represents servings of wet food.

Part B: The graph consists of two lines: x + 3y = 9 and x + y = 2. The feasible region is the shaded area where the lines intersect and satisfies non-negative values of x and y. It represents possible combinations of dog food Michelle can buy to feed at least two dogs with $9.

Part A: To write the system of inequalities that models this scenario, let's introduce some variables:

Let x represent the number of servings of dry food.

Let y represent the number of servings of wet food.

The cost of a serving of dry food is $1, and the cost of a serving of wet food is $3. We need to ensure that the total cost does not exceed $9. Therefore, the first inequality is:

x + 3y ≤ 9

Since we want to feed at least two dogs, the total number of servings of dry and wet food combined should be greater than or equal to 2. This can be represented by the inequality:

x + y ≥ 2

So, the system of inequalities that models this scenario is:

x + 3y ≤ 9

x + y ≥ 2

Part B: Now let's describe the graph of the system of inequalities and the solution set.

To graph these inequalities, we will plot the lines corresponding to each inequality and shade the appropriate regions based on the given conditions.

For the inequality x + 3y ≤ 9, we can start by graphing the line x + 3y = 9. To do this, we can find two points that lie on this line. For example, when x = 0, we have 3y = 9, which gives y = 3. When y = 0, we have x = 9. Plotting these two points and drawing a line through them will give us the line x + 3y = 9.

Next, for the inequality x + y ≥ 2, we can graph the line x + y = 2. Similarly, we can find two points on this line, such as (0, 2) and (2, 0), and draw a line through them.

Now, to determine the solution set, we need to shade the appropriate region that satisfies both inequalities. The shaded region will be the overlapping region of the two lines.

Based on the given inequalities, the shaded region will lie below or on the line x + 3y = 9 and above or on the line x + y = 2. It will also be restricted to the non-negative values of x and y (since we cannot have a negative number of servings).

The solution set will be the region where the shaded regions overlap and satisfy all the conditions.

The description of the solution set is as follows:

The solution set represents all the possible combinations of servings of dry and wet food that Michelle can purchase with her $9, while ensuring that she feeds at least two dogs. It consists of the points (x, y) that lie below or on the line x + 3y = 9, above or on the line x + y = 2, and have non-negative values of x and y. This region in the graph represents the feasible solutions for Michelle's purchase of dog food.

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Answer:

The length of side AB is equal to 3.

After the translation, the length of the side AB will remain the same.

Explanation:

To determine the length of the side AB, Let us first locate the coordinates of A and B on the graph;

The length AB can be calculated using the formula for the distance between two points.

Substituting the values of the coordinates;

Therefore, the length of side AB is equal to 3.

After the translation, the length of the side AB will remain the same.

Because translation does not affect the size of an image, it only changes its position.

The option that follows is c .

The between-group estimate for calculating the degrees of freedom in ANOVA is calculated using the formula k - 1, where k represents the number of groups or treatments being compared.

This estimate represents the variability between the group means and is used in the F-ratio calculation to determine if the differences between the groups are significant.

When conducting ANOVA, the between-group estimate is an important factor in determining the degrees of freedom. This estimate represents the variability between the group means and is used to calculate the F-ratio, which determines if the differences between the groups are significant. The between-group estimate is calculated using the formula k - 1, where k represents the number of groups being compared. This formula is used because the estimate is based on the number of independent sources of variation between the groups. By accurately calculating the degrees of freedom, researchers can determine if the differences between the groups are statistically significant.

The between-group estimate for calculating the degrees of freedom in ANOVA is crucial for determining the statistical significance of differences between groups. It is calculated using the formula k - 1, where k represents the number of groups being compared. This estimate represents the variability between the group means and is used in the F-ratio calculation. Accurately calculating the degrees of freedom is essential in conducting valid ANOVA analyses.

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Answer: i think

Step-by-step explanation:

Answer:

Graph B!!!!

On Edge 2023 Quiz

Step-by-step explanation:

To implement a one-bit full adder using a 74x138 binary decoder with high enable, you would follow these steps:

1. Connect the 74x138 binary decoder's inputs (A0, A1, A2) to the inputs of the full adder (A, B, and Cin).
2. Connect the high enable input (G1) to ground (LOW) and G2A and G2B to Vcc (HIGH).
3. Create an OR gate using diodes/resistors, with inputs from the decoder outputs (Y0, Y2, and Y4) for Sum.
4. Create another OR gate using diodes/resistors, with inputs from the decoder outputs (Y3 and Y7) for Cout.
5. Connect the OR gate outputs to the full adder outputs (Sum and Cout).

In this configuration, the 74x138 binary decoder decodes the input combinations into 8 output lines. The full adder adds binary digits A, B, and Cin (carry-in) to produce a Sum and Cout (carry-out) result.

The decoder's output lines, which represent different combinations of A, B, and Cin, are combined using OR gates to obtain the desired Sum and Cout values. The high enable feature ensures that the decoder is active and functional during the process.

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The statement 'The distribution of the sample​ mean, x overbar, will be normally distributed if the sample is obtained from a population that is normally​ distributed, regardless of the sample size.'  is True

In this question we have been given a statement 'The distribution of the sample​ mean, x overbar, will be normally distributed if the sample is obtained from a population that is normally​ distributed, regardless of the sample size.'

We need to state whether the statement is True or False.

We know that the sampling distribution of the sample mean is the probability distribution of all possible values of the random variable x that are computed from a sample of size n.

Also if a random variable X is normally​ distributed, the distribution of the sample​ mean, x overbarx​, is normally distributed.

Therefore, given statement is True.

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Answer:

Small scooters = 6

Large scooters = 4

Step-by-step explanation:

Let S represents small scooter and L represents large scooter

The cost of a small scooter is £80

Mathematically,  the cost of S number of small scooters is

80S

The cost of a large scooter is £130

Mathematically,  the cost of L number of large scooters is

130L

The total amount spent on both scooters is £1000

Mathematically,

80S + 130L = 1000

So we have 2 unknowns and only 1 equation. Therefore, we have use trial and error method .

Trial and Error Method:

80S + 130L = 1000

80S = 1000 - 130L

S = (1000 - 130L)/80

Let’s suppose they bought 1 large scooter

S = (1000 - 130(1))/80

S = 10.875

Number of scooters cannot be in fraction so 1 doesn’t work

Let’s suppose they bought 2 large scooter s

S = (1000 - 130(2))/80

S = 9.25

Number of scooters cannot be in fraction so 2 doesn’t work

Let’s suppose they bought 3 large scooter s

S = (1000 - 130(3))/80

S = 7.625

Number of scooters cannot be in fraction so 3 doesn’t work

Let’s suppose they bought 4 large scooters

S = (1000 - 130(4))/80

S = 6

So that means they bought 6 small scooters and 4 large scooters.

Similarly, other combinations for scooters don’t work since they yield either fractional value or negative value which cannot be correct.

Therefore, the only possible combination of small and large scooters is

6 Small scooters

4 Large scooters

Verification:

80S + 130L = 1000

80(6) + 130(4) = 1000

480 + 520 = 1000

1000 = 1000 (satisfied)

When two variables are highly positively correlated, the correlation coefficient, r, would most likely be closer to 1 (0.7 - 1).

The correlation coefficient, r, shows the extent to which two variables are correlated. Correlation coefficient ranges from 1 to -1.

The stronger the correlation, the closer the correlation coefficient, r, is to -1 or 1.

Therefore, when two variables are highly positively correlated, the correlation coefficient, r, would most likely be closer to 1 (0.7 - 1).

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Answer:

What? What's the question

Step-by-step explanation:

(t₁......t₆) = (5, 1, 44, 10, 90, 20) is the solution of the given matrix.

(A) An augmented matrix for a system of equations is a matrix of numbers where each column represents all the coefficients for a single variable and each row represents the constants from one equation (both the coefficients and the constant on the other side of the equal sign).

The system's augmented matrix is shown here:

\(\left[\begin{array}{cccccc|c}1 & 1 & 1 & -\frac{1}{2} & -\frac{1}{2} & 0 & 0 \\0 & 1 & 1 & 1 & -\frac{1}{2} & -\frac{1}{2} & 0 \\0 & 1 & 0 & 0 & 0 & 0 & 1 \\0 & 0 & 0 & 1 & 0 & 0 & 10\end{array}\right]\)

(B) Use these row operations to convert this augmented matrix to a reduced echelon form.

Here is the augmented matrix's reduced echelon form:

\(\left[\begin{array}{ccccccc}1 & 0 & 0 & 0 & 0 & \frac{1}{2} & 15 \\0 & 1 & 0 & 0 & 0 & 0 & 1 \\0 & 0 & 1 & 0 & -\frac{1}{2} & -\frac{1}{2} & -11 \\0 & 0 & 0 & 1 & 0 & 0 & 10\end{array}\right]\)

(C) There are more rows:

\(\begin{array}{lllllll}0 & 0 & 0 & 0 & 0 & 1 & 20\end{array},\\\begin{array}{lllllll}1 & 1 & 1 & 0 & 0 & 0 & 50\end{array}\)

Augmented matrix:

\(\left[\begin{array}{ccccccc}1 & 0 & 0 & 0 & 0 & \frac{1}{2} & 15 \\0 & 1 & 0 & 0 & 0 & 0 & 1 \\0 & 0 & 1 & 0 & -\frac{1}{2} & -\frac{1}{2} & -11 \\0 & 0 & 0 & 1 & 0 & 0 & 10 \\0 & 0 & 0 & 0 & 0 & 1 & 20 \\1 & 1 & 1 & 0 & 0 & 0 & 50\end{array}\right]\)

(D) You must employ these row operations in order to solve the system.

\(\left[\begin{array}{lllllll}1 & 0 & 0 & 0 & 0 & 0 & 5 \\0 & 1 & 0 & 0 & 0 & 0 & 1 \\0 & 0 & 1 & 0 & 0 & 0 & 44 \\0 & 0 & 0 & 1 & 0 & 0 & 10 \\0 & 0 & 0 & 0 & 1 & 0 & 90 \\0 & 0 & 0 & 0 & 0 & 1 & 20\end{array}\right]\)

Therefore, (t₁......t₆) = (5, 1, 44, 10, 90, 20) is the solution of the given matrix.

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Answer:

4

Step-by-step explanation:

yeah yeah yeah yeah 2+2=4

Answer:

son 4 ya que 2+2 son 4 y para 5 1

Step-by-step explanation:

espero y te sirva bro

Answer:

A. 136 stars

B. 340 stars

Answer:

At 10 pm he counted 136 stars and at 12 pm he counted 340

Step-by-step explanation:

for 10 pm:

68 x 2

for 12 pm:

68 x 5

The ratio of corresponding sides for the given similar triangles is 2/5.

In the given options, the ratio of corresponding sides is provided for each set of similar triangles. Let's analyze each option to determine the correct ratio:

a. 10

This option only provides a single number and does not specify the ratio of corresponding sides. Therefore, it is not the correct answer.

b. 4/5

This option provides the ratio 4/5 for the corresponding sides of the similar triangles. However, the ratio can be simplified further.

To simplify the ratio, we divide both the numerator and denominator by their greatest common divisor (GCD). In this case, the GCD of 4 and 5 is 1.

Dividing 4 and 5 by 1, we get:

4 ÷ 1 = 4

5 ÷ 1 = 5

Therefore, the simplified ratio is 4/5.

c. 10/85

This option provides the ratio 10/85 for the corresponding sides of the similar triangles. However, this ratio cannot be simplified further, as 10 and 85 do not have a common factor other than 1.

Therefore, the correct ratio of corresponding sides for the given similar triangles is 2/5, as determined in option b.

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