2.64 divided by 0.16?

The given problem can be solved using the following formulae and procedures: Failure rate is the frequency with which an engineered system or component fails, normally expressed in failures per million hours (FPMH) or in percentage per year.

Failure rate is calculated using the formula FR = Number of failures / Total time Units of Failure rate is percentage per year or failures per million hours.FR(%): Failure rate in percentage per year FR(N): Failure rate in failures per million hours MTBF: Mean Time Between Failures For the given problem, Number of batteries, n = 5

Design life, L = 72 months

Test results = 1 failure at 24 months, 1 failure at 30 months, 1 failure at 48 months, and 1 failure at 60 months. Failure rate is calculated by using the formula: FR = Number of failures / Total time Since all the batteries have different lifespan, calculate the total time for which batteries were used.

Total time, T = 24 + 30 + 48 + 60T

= 162 months

FR = 4 / 162 FR(%):To convert FR from failures per month to percentage per year, use the formula:

FR(%) = (1 - e^(-FR*t)) x 100%

Where, t = 1 year = 12 months

FR(%) = (1 - e^(-FR*t)) x 100%Putting the given values:0.29% is the annual failure rate of the Everstart battery after the given test. Frequency of Failure (FR(N)) is given by:

FR(N) = (Number of failures / Total time) x 10^6FR(N)

= (4 / 162) x 10^6FR(N)

= 24,691.358 failure per million hours.

Mean Time Between Failures (MTBF) can be calculated using the following formula: MTBF = Total time / Number of failures MTBF = 162 / 4

MTBF = 40.5 months

Therefore,FR(%) = 0.29%, FR(N) = 24,691.358 failures per million hours, and MTBF = 40.5 months.

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I think that for a its 1.12 and for b its 39424

100 + 12 = 112
112/100 = 1.12

35200 * 1.12 = 39424

Answer: (-15, 3)

Let's solve your system by substitution.

x+5y=0;3y+2x=−21

Rewrite equations:

x+5y=0;2x+3y=−21

Step: Solvex+5y=0for x:

x+5y=0

x+5y+−5y=0+−5y(Add -5y to both sides)

x=−5y

Step: Substitute−5yforxin2x+3y=−21:

2x+3y=−21

2−5y+3y=−21

−7y=−21(Simplify both sides of the equation)

−7y

−7

=

−21

−7

(Divide both sides by -7)

y=3

Step: Substitute3foryinx=−5y:

x=−5y

x=(−5)(3)

x=−15(Simplify both sides of the equation)

Answer:

x=−15 and y=3

Answer:

6:45pm

Step-by-step explanation:

Given: The time is currently 9:45am

To find: The time in 9 hours

To do this, we have to add 9 hours to 9:45am.

9:45am+9 hours=

6:45pm

Hope this helps! :)

Answer:

= 40g -24

Step-by-step explanation:

you would multiply everything in the bracket by 8 to expand this

e.g.

(8x5g )+ (8x5 )+ (8 x -2)

= 40g + 40 - 16

now simplify by subtracting the like terms

= 40g -24

Answer:

The dilation will create a similar rectangle with sides of half the length of the original rectangle

Answer:

Its B for the people who dont know what the other guy was talking about

Step-by-step explanation:

The $1314^\text{th}$ digit past the decimal point is 2.

To find the $1314^\text{th}$ digit past the decimal point in the decimal expansion of $\frac{5}{14}$, we can use long division to compute the decimal expansion of the fraction.

The long division of $\frac{5}{14}$ is as follows:

```

0.35    <-- Quotient

-----

14 | 5.00

   4.2    <-- Subtract: 5 - (14 * 0.3)

   -----

     80   <-- Bring down the 0

     70    <-- Subtract: 80 - (14 * 5)

     -----

     100   <-- Bring down the 0

      98    <-- Subtract: 100 - (14 * 7)

      -----

       20   <-- Bring down the 0

       14    <-- Subtract: 20 - (14 * 1)

       -----

        60   <-- Bring down the 0

        56    <-- Subtract: 60 - (14 * 4)

        -----

         40   <-- Bring down the 0

         28    <-- Subtract: 40 - (14 * 2)

         -----

         120   <-- Bring down the 0

         112    <-- Subtract: 120 - (14 * 8)

         -----

           80   <-- Bring down the 0

           70    <-- Subtract: 80 - (14 * 5)

           -----

           ...

```

We can see that the decimal expansion of $\frac{5}{14}$ is a repeating decimal pattern with a repeating block of digits 285714. Therefore, the $1314^\text{th}$ digit past the decimal point is the same as the $1314 \mod 6 = 0^\text{th}$ digit in the repeating block.

Since $1314 \mod 6 = 0$, the $1314^\text{th}$ digit past the decimal point in the decimal expansion of $\frac{5}{14}$ is the first digit of the repeating block, which is 2.

So, the $1314^\text{th}$ digit past the decimal point is 2.

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Answer:

A composite number is a whole number greater than 1 with more than two factors.

Step-by-step explanation:

Question isn't well formatted :

on a restaurant menu you can have three course meal by selecting one from each meal course they're five appetizers four main dishes and two desserts to choose from how many Possible full meals are there?

Answer:

40

Step-by-step explanation:

To solve questions of this nature, we apply combination.

nCr = n! ÷ (n - r)!r!

For the 3 course meal :

Selection procedure ;

Select 1 appetizer from 5 ; and 1 main dish from four and 1 dessert from 2

This gives :

5C1 * 4C1 * 2C1

5C1 = 5! ÷ (5-1)!1! = 5

4C1 = 4! ÷ (4-1)!1! = 4

2C1 = 2! ÷ (2-1)!1! = 2

Hence, we have

5 * 4 * 2 = 40 different meals

Answer:

40?

Step-by-step explanation:

The solution to the system of equations, rounded to the nearest integer is: (12, 489)

Given the system of equations:

y = 3.8x + 444 ---> Eqn. 1

y = 14.4x + 319 ----> Eqn. 2

To solve using the substitution method, substitute y for 3.8x + 444 in eqn. 2.

y = 14.4x + 319 ----> Eqn. 2

3.8x + 444 = 14.4x + 319

3.8x - 14.4x = -444 + 319

-10.6x = -125

x = 11.8

Substitute x for 11.8 into Eqn. 1.

y = 3.8x + 444 ---> Eqn. 1

y = 3.8(11.8) + 444

y = 488.84

Therefore, the solution to the system of equations, rounded to the nearest integer is: (12, 489)

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The number of early-admission tickets that it sells is 30.

From the information, 30% of the tickets sold at a school carnival were early-admission tickets and the school sold 100 tickets in all.

Therefore, the number of early admission will be:

= Percentage for early admission × Total number of tickets

= 30% × 100

= 0.3 × 100

= 30

Therefore, there are 30 early admission.

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Answer:

16^15

Step-by-step explanation:

16 is 2^4

So 2^60 = (2^4)^x power

2^60=2^4x

exponents of same bases are equal

60=4x

15=x

remember, (2^4) is still 16

lets convert it back to 16

2^60=16^x

and we know x is 15

2^60 = 16^15

Answer:(5x+8)/[(x+4)(x-1)(x+3)]

Step-by-step explanation:

1. First factorize the quad expressions in the denomeneter of both fractions.

2. Then choose you arithmetic common denomeneter .

3. And the rest is child's play.

Answer:

A.

Step-by-step explanation:

6/7  / 3/5   we invert the divisor and multiply:

= 6/7 * 5/3

Answer:

12

Step-by-step explanation:

-2x + 7=5

or, 7-5=2x

or, 2=2x

or, 2/2=x

or, 1=x

Then,

7x+5

=7×1+5

=7+5

=12

Answer:

x=1

Step-by-step explanation:

-7 both sides that will give you -2

-2x=-1 divide by -2 and u will get on i think that what you were asking

Answer:

\( y = {e}^{3}\)

Step-by-step explanation:

\(f(x) = {e}^{3x} \\ \\ plug \: x = 1 \\ \\ f(1) = {e}^{3 \times 1} \\ \\ f(1) = {e}^{3} \\ \\ plug \: f(1) = y \\ \\ y = {e}^{3}\)

The correct answer is: D.

The system has only one solution, and it is viable because it results in positive side lengths.

Let x be the shorter leg of the triangle, and y be the area. The longer leg is 4 + 6x, and the area of the triangle is y = (1/2) * x * (4 + 6x).

For the rectangle, the width is 5 + x, the length is 3, and its area is also y = (5 + x) * 3.

The system of equations is:

y = (1/2) * x * (4 + 6x)

y = (5 + x) * 3

Substitute equation (2) into equation (1) and solve for x:

(5 + x) * 3 = (1/2) * x * (4 + 6x)

30 + 6x = 4x + 6x^2

6x^2 - 2x - 30 = 0

Using the quadratic formula, we find two solutions for x:

x1 ≈ 2.62

x2 ≈ -1.95

Since x represents the length of the shorter leg, we discard the negative solution. Thus, there is only one viable solution for x: x ≈ 2.62. Now find y using equation (2): y ≈ 22.86.

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A carpenter is creating two new templates for his designs. One template will be in the shape of a right triangle, where the longer leg is 4 inches more than six times the shorter leg.

The second template will be in the shape of a rectangle, where the width is 5 inches more than the triangle’s shorter leg, and the length is 3 inches.

The carpenter needs the areas of the two templates to be the same. Write a system of equations to represent this situation, where y is the area, and x is the length of the shorter leg of the triangle. Which statement describes the number and viability of the system’s solutions?

A.

The system has two solutions, but only one is viable because the other results in negative side lengths.

B.

The system has two solutions, and both are viable because they result in positive side lengths.

C.

The system has only one solution, but it is not viable because it results in negative side lengths.

D.

The system has only one solution, and it is viable because it results in positive side lengths.

We assume that with a linear relationship between two variables, for any fixed value of x, the observed residuals follows a normal distribution.

This assumption is based on the Central Limit Theorem, which states that when the sample size is large enough, the distribution of sample means will be approximately normal, regardless of the shape of the underlying population distribution.

In the case of a linear relationship between two variables, we can assume that the residuals (the difference between the observed y values and the predicted values based on the linear regression model) follow a normal distribution with mean 0 and constant variance. This assumption is important because it allows us to use statistical methods that rely on normality, such as hypothesis testing and confidence intervals.

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The measure of the angles are;

X = 38 degrees

Y = 52 degrees

To determine the angles, we need to know the properties of a kite.

These properties includes;

Then, we can say that;

Y= 52 degrees

Note that the sum of the angles in a triangle is 180

Then, we get;

X + Y+ 90 = 180

X = 180 - 142

Subtract the values

X = 38 degrees

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The order of the quantity from least to the greatest will be π²/8 < √2  < √3 < π²/4 and the order of quantities, as in the numeric labels, is 2341.

A number is a mathematical entity that can be used to count, measure, or name things. For an example, 1, 2, 56 etc. are the numbers.

We have a quantity shown in the table with label 1 to 4

π²/4 = 2.467 → 1

π²/8 = 1.2337→ 2

√2 = 1.4142 → 3

√3 = 1.7320 → 4

The order of the quantity from  least to the greatest will be:

π²/8 < √2  < √3 < π²/4

The order of quantities, as in the numeric labels:

= 2341

Thus, the order of the quantity from least to the greatest will be π²/8 < √2  < √3 < π²/4 and the order of quantities, as in the numeric labels, is 2341.

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Answer:

x=50°

Step-by-step explanation:

Add all the number. 110+99+101=310

Then, 360-310=answer(x)

The surface is an elliptic cylinder with varying radii depending on t. The answer is c) elliptic cylinder.

To identify the surface with the given vector equation, we can compare it with the general form of a parametric surface

r(u, v) = ⟨x(u, v), y(u, v), z(u, v)⟩1.

In this case, we have

r(s, t) = s sin 5t, s2, s cos 5t.

We can see that x and z depend on both s and t, but y depends only on s.

This means that the surface is a cylinder with elliptic cross-sections parallel to the yz-plane2.

The equation of an elliptic cylinder is x2/a2 + z2/b2 = 13, where a and b are the semi-major and semi-minor axes of the ellipse.

Comparing this with the given equation, we can see that a = 1/sin 5t and b = 1/cos 5t. Therefore, the surface is an elliptic cylinder with varying radii depending on t.

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Answer:

2 why are your teacher so meannnnnn

Answer:

x = 13

Step-by-step explanation:

1. We can tell if the radical is in its simplest form if the square root term is a number that cannot be broken down to give a perfect square factor

what we are saying in this case is that if the number that is under the square root sign is one in which cannot be broken down to give a perfect square or that a perfect square is not its factor. Then it is in the simplest form

2. 512 = 2^(x-4)

512 = 2^9

2^9 = 2^(x-4)

since base is equal, we equate the powers

9 = x - 4

x = 9 + 4

x = 13

(a) The demand function is \(p = 150 - 0.5q.\)

(b) To find the equilibrium price and quantity, we need to set the demand function equal to the supply function and solve for q.

Demand: \(p = 150 - 0.5q\)

Supply: \(p = 0.002q^2 + 1.5\)

Setting them equal:

\(150 - 0.5q = 0.002q^2 + 1.5\)

Simplifying and rearranging the equation:

\(0.002q^2 + 0.5q - 148.5 = 0\)

This is a quadratic equation. Solving it, we find two possible values for q: \(q ≈ 118.6 and q ≈ -623.6.\) Since the quantity cannot be negative in this context, we discard the negative value.

So, the equilibrium quantity is \(q ≈ 118.6.\)

To find the equilibrium price, we substitute this value back into the demand or supply function:

\(p = 150 - 0.5qp = 150 - 0.5(118.6)p ≈ 93.7\)

Therefore, the equilibrium price is approximately $93.7 and the equilibrium quantity is approximately 118.6 items.

(c) To find the total gains from trade at the equilibrium price, we need to calculate the area of the consumer surplus and producer surplus.

Consumer Surplus:

To find the consumer surplus, we need to find the area between the demand curve and the equilibrium price. It is represented as the area under the demand curve and above the equilibrium quantity.

Consumer Surplus = \(0.5 * (150 - 93.7) * 118.6\)

Producer Surplus:

To find the producer surplus, we need to find the area between the supply curve and the equilibrium price. It is represented as the area above the supply curve and below the equilibrium quantity.

Producer Surplus = \(0.5 * (93.7 - 1.5) * 118.6\)

Total Gains from Trade = Consumer Surplus + Producer Surplus

Calculate these values to find the total gains from trade at the equilibrium price.

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Answer:

\(250 - 20x=y\)

Step-by-step explanation:

As per the given problem, Steve starts with $250, and spent $20 a week, the problem mentions nothing about Steve's savings, therefore, one can assume that they didn't save anything. As the problem requests, parameter (\(x\)) will be used for the time, and (\(y\)) for the savings.

Steve's saving would be equal to his initial value, minus his expense, in essence;

\(250 - 20x=y\)

The initial value, minus the amount spend per week multiplied by the week number will equal the savings left.

Answer:

y=250-(20x)

Step-by-step explanation:

15/19 + 14/19 = 29/19

Step-by-step explanation:

Add the number of balls in the basket together.

Subtract the number of white balls from the sample space ( the total amount of balls) your answer is written over the sample space and the same process is done for the green ball

When a\(_{n}\) = \(2^{n}\)+ n,  a₀ = 1,  a₁ = 3,  a₂ = 6, and a₃ = 11  

When a\(_{n}\) = n^(n+1)!,  a₀ = 0,  a₁ = 2,  a₂ = 2⁶, and a₃ = 3²⁴  

When a\(_{n}\) =  [n/2], a₀ = 0,  a₁ = 1/2,  a₂ = 1, and a₃ = 3/2      

When a\(_{n}\) = [n/2] + [n/2], a₀ = 0,  a₁ = 1,  a₂ = 2, and a₃ = 3/2  

Number sequence

A number sequence is a progression or a list of numbers that are directed by a pattern or rule.

Here,

a₀, a₁, a₂, and a₃ are terms of a sequence

from option a, a\(_{n}\) = \(2^{n}\)+ n

⇒ a₀  = 2⁰+ 0 = 1+0 = 1

⇒ a₁  = 2¹+ 1 = 2+1 = 3

⇒ a₂, = 2²+ 2 = 4+2 = 6

⇒ a₃  = 2³+ 3 = 8 +3 = 11  

from option b, a\(_{n}\) = n^(n+1)!

⇒ a₀  = 0^(0+1)! = 0

⇒ a₁  = 1^(1+1)! = 2² = 2

⇒ a₂, = 2^(2+1)! = 2^(3)! = 2⁶          [ ∵ 3! = 6 ]

⇒ a₃  = 3^(3+1)! = 3^(4)! = 3²⁴         [ ∵ 4! = 24 ]

from option c, a\(_{n}\) =  [n/2]          

⇒ a₀  = [0/2] = 0

⇒ a₁  = [1/2] = 1/2

⇒ a₂, = [2/2] = 1

⇒ a₃  = [3/2] =  3/2  

from option d, a\(_{n}\) = [n/2] + [n/2]

⇒ a₀  =  [0/2] + [0/2] = 0

⇒ a₁  =  [1/2] + [1/2] = 1/2 + 1/2 = 1

⇒ a₂, = [2/2] + [2/2] = 1 + 1 = 2

⇒ a₃  =  [3/2] + [3/2] = 6/4 = 3/2

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The Complete Question is -

What are the terms a₀, a₁, a₂, and a₃ of the sequence {a\(_{n}\)}, where a\(_{n}\) is where a\(_{n}\) equals

a. \(2^{n}\) + n                    b. n^(n+1)!

c. [n/2]                      d. [n/2] + [n/2]