Answers
Option A, a magnet, is the best choice for separating small iron filings from a mixture with sand.
The best option to separate small iron filings from a mixture with sand would be:
A) a magnet
Using a magnet is an effective method to separate iron filings from a mixture. Iron filings are magnetic, while sand is not. By placing a magnet near the mixture, the iron filings will be attracted to the magnet and can be easily separated from the sand. This process is known as magnetic separation.
To separate the iron filings, you can move the magnet over the mixture, and the iron filings will cling to the magnet. This can be repeated until all the iron filings have been separated from the sand.
Filter paper (option B) is not suitable for this purpose because it is primarily used for separating solid particles from a liquid or gas by filtration. In this case, we are dealing with a solid mixture, not a liquid or gas.
A hot plate (option C) is used for heating substances and would not be effective for separating iron filings from sand.
Running water (option D) may help in some cases to separate different components of a mixture, but in this specific scenario, where we want to separate iron filings from sand, using a magnet would be a more efficient and precise method.
In conclusion, option A, a magnet, is the best choice for separating small iron filings from a mixture with sand.
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Related Questions
What is boiling point in Farhrenheit
Answers
Answer:
212° F
Explanation:
what are the three types of soil?
Answers
Answer: Loamy, sandy and clayey
Answer:
Sand, silt and clay
Explanation:
Soil can be classified into three primary types based on its texture – sand, silt and clay. However, the percentage of these can vary, resulting in more compound types of soil such as loamy sand, sandy clay, silty clay, etc.
Source: https://byjus.com/biology/types-of-soil/#:~:text=Soil%20can%20be%20classified%20into,clay%2C%20silty%20clay%2C%20etc.
Hope this helps! :)
Happy Late Valentine's Day!
Brainliest, Please!
What type of reaction?
HCN,Na2So4
Mg3N2
Co2, H2O
Cu,Zn(NO3)2
Na,N2
Answers
HCN, Na2SO4: Combination of compounds.
Mg3N2: Chemical compound.
CO2, H2O: Dissolution or hydration reaction.
Cu, Zn(NO3)2: Single-replacement reaction.
Na, N2: Combination of elements.
Let's analyze each chemical combination to determine the type of reaction involved:
HCN, Na2SO4:
The combination of hydrogen cyanide (HCN) and sodium sulfate (Na2SO4) does not represent a specific chemical reaction. It is simply the combination of two compounds.
Mg3N2:
Mg3N2 represents a chemical compound, magnesium nitride. It does not indicate a specific reaction.
CO2, H2O:
The combination of carbon dioxide (CO2) and water (H2O) represents a chemical reaction known as hydration or dissolution. When carbon dioxide dissolves in water, it forms carbonic acid (H2CO3), which can further dissociate into hydrogen ions (H+) and bicarbonate ions (HCO3-).
Cu, Zn(NO3)2:
The combination of copper (Cu) and zinc nitrate (Zn(NO3)2) represents a single-replacement reaction. Copper displaces zinc from the compound, resulting in the formation of copper nitrate (Cu(NO3)2) and zinc metal (Zn).
Na, N2:
The combination of sodium (Na) and nitrogen gas (N2) does not represent a specific reaction. It is simply the combination of two elements.
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what are the properties of acid and that can be distinguish is it explain any two
Answers
Answer:
Acid solutions have pH values lesser than
7
it turn blue litmus paper red
A 1.0 L solution AgNO3(ag) of and Pb(NO3)2(aq) has a Agconcentration of 0.020 M and a Pb2+ concentration of
0.0010 M. A 0.0010 mol sample of K2SO4(s) is added to the solution. Based on the information in the table above,
which of the following will occur? (Assume that the volume change of the solution is negligible.)
No precipitate will form.
(B) Only Ag2SO4(s) will precipitate.
(C) Only PbSO4(s) will precipitate.
(D) Both Ag2SO4(s) and PbSO4(s) will precipitate.
Answers
With an Ag concentration of 0.020 M and a Pb2+ concentration of
0.0010 M, Only PbSO4(s) will precipitate,
Option C is correct
What will precipitate?Generally, the equation for the Chemical Reaction is mathematically given as
Ag2SO4--->2Ag++SO4^{-2}
Where
PbSO4--->Pb2+ +SO4^{-2}
Therefore
Ag2SO4=[0.02^2[0.001]]
Ag2SO4=4*10^{-7}
and
PbSO4=[0.001^2[0.001]]
PbSO4=4*10^{-6}
In conclusion,Since PbSO4>>PAg2SO4, Only PbSO4(s) will precipitate.
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Help please from science
Answers
The correct answers to the fill in the blank problems given above are as follows:
Mitotic phase is the part of the cell cycle that divides the material
This process happens only in somatic cells, also is known as body cells.
There are 4 parts of this process:
1. Prophase: the phase that DNA coils into the chromosome.2. Metaphase: the phase where the chromosome organize in the middle of the cell to prepare to divide.3. Anaphase: the phase where chromosome pull apart4. Telophase: the phase where 2 nuclear membranes surround the divided genetic materials What is meant by mitosis?Mitosis can simply be defined as a special process of cell division in which a single cell divides into two different identical daughter cells.
Aside, mitosis; another major cell division which occurs in the cells of living organisms is the meiosis. Below are the phases involved in mitotic cell division, these are as follows:
ProphaseMetaphaseAnaphaseTelophaseIn conclusion, it can be deduced from the explanation given above that mitosis is a process of cell division.
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Which element has 38 protons and 50 neutrons? __________________
What is its mass number? __________________
What group is this element in? __________________
What is the family name for this group? __________________
Answers
There are various kind of elements that are present in periodic table. Some elements are harmful, some are radioactive, some are noble gases. Therefore, Strontium belongs to group 2, alkaline earth metal family of the periodic table.
What is periodic table?Periodic table is a table in which we find elements with properties like metals, non metals, metalloids and radioactive element arranges in increasing atomic number.
Periodic table help a scientist to know what are the different types of elements are present in periodic table so that they can discover the new elements that are not being discovered yet.
Strontium is the element having 38 protons and 50 neutrons.
mass number= proton number + neutron number
=38+ 50
=88
Group number of this element is group 2. Strontium belongs to akaline earth metal family.
Therefore, Strontium belongs to group 2, alkaline earth metal family of the periodic table.
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Help please :) with this
Answers
Answer:
option C 5
hope this answer helps you dear! take care
Answer:
5, the coefficient is the number right before the variable. The ² and ³ (even though Mines on top and yours is on the bottom) are not coefficient because. . . well it just doesn't make sense.
What is the H3 O+ concentration of 0.25 M NH4 Cl? (Ka for NH4+ = 5.6 × 10-10 )
Answers
The concentration of H3O+ of 0.25 M NH4 Cl is calculated as 1.13 × 10⁻⁵ M.
What is the H3 O+ concentration?Hydronium ion concentration is found from pH by reverse of the mathematical operation that is employed to find pH.
NH4Cl + H2O → NH4+ + Cl- + H2O
NH4+ + H2O → H3O+ + NH3
Ka = [H3O+][NH3] / [NH4+]
[NH4+] = 0.25 M - x
At equilibrium, the concentration of NH3 will also be equal to x (since NH4+ and NH3 are in a 1:1 ratio). The concentration of H3O+ will also be equal to x (since NH4+ donates a proton to form H3O+).
5.6 × 10-10 = (x)(x) / (0.25 - x)
x = 1.13 × 10⁻⁵ M
Therefore, the concentration of H3O+ is 1.13 × 10⁻⁵ M.
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The chemical formula for strontium sulfide is SrS . A chemist measured the amount of strontium sulfide produced during an experiment. She finds that 199.g of strontium sulfide is produced. Calculate the number of moles of strontium sulfide produced. Be sure your answer has the correct number of significant digits.
Answers
Answer:
The number of moles of strontium sulfide produced is:
= 1.663.
Explanation:
Chemical formula for strontium sulfide = SrS
Production of strontium sulfide = 199g
1 mole = 1 moles Strontium Sulfide, which is equal to 119.685 grams
The number of moles of strontium sulfide produced = 1.663 (199/119.685)
The number of moles of strontium sulfide produced is the dividend of the amount of strontium sulfide produced during the experiment divided by the mass of 1 mole.
If 5.0 mL of 0.10 M NaOH is added to 50. mL of 0.10 M HCI, what will be the resulting
pH of the solution?
Round your answer to two decimal places.
Provide your answer below:
PH
Answers
Note that NaOH and HCl are the reactants of the reaction. Since they’re a strong acid and base, they would completely dissociate, meaning the molarity of H+ is equal to the molarity of HCl (same applies for NaOH and OH-) which also means the moles are the same.
Solve for the moles after the reaction has fully occurred then use the total volume (since this is the end of the reaction, volumes are fully mixed) and find the new molarity of H+ since our NaOH was our limiting reactant.
The plug the molarity of H+ into the formula pH = -log[H+] and get the pH of 1.09
Answer:
1.09
Explanation:
Keep in mind that the volume of the solution changes during this titration, so to compute the amount of hydronium that is neutralized during this addition of base (in order to calculate the final pH of the solution), we must calculate the moles of all species in solution initially present. Because both NaOH and HCl ionize completely:initial mol OH−=mol NaOH=(0.0050 L)(0.10 molL)=0.00050 mol OH−initial mol H3O+=mol HCl=(0.050 L)(0.10 molL)=0.0050 mol H3O+The acid is in excess, so all of the OH− present will neutralize an equivalent amount of H3O+, forming water. Thus we simply subtract the moles of hydroxide from the moles of hydronium in solution to find the resultant moles of H3O+ after this neutralization:final mol H3O+= initial mol H3O+−initial mol OH−final mol H3O+=0.0050 mol−0.00050 mol=0.0045 mol H3O+We now calculate the total volume of the solution by adding the volumes of acid and base initially combined: 0.050 L+0.0050 L=0.055 LTo get [H3O+], we divide the final moles of hydronium by the final solution volume:[H3O+]=final mol H3O+ total volume=0.0045 mol0.055 L≈0.08181molLFinally, to find pH:pH=−log[H3O+]=−log(0.08181)=1.09Since the hydronium concentration is only precise to two significant figures, the logarithm should be rounded to two decimal places.
Why is the combined gas law the most practiced gas law
Answers
The combined gas law allows you to derive any of the relationships needed by combining all of the changeable peices in the ideal gas law: namely pressure, temperature and volume.
lesson 6.1 ngsss benchmark mini assessment
Answers
Answer:
hey some times you need to help us too and I'm 10
Select the missing words to complete the definition of buffer capacity. Buffer capacity is the _____________ of acid or base a buffer can handle before pushing the _____________ outside of the buffer range.
Answers
Answer:
amount, pH value.
Explanation:
The buffer range is the pH range in which the buffer performs optimally, i.e., neutralizes even when a strong acid or base is introduced to it and resists any major change in its pH value.
The buffer capacity is the amount of acid or base that can be added before the pH of the buffer solution changes significantly.
Thus, the final statement becomes,
Buffer capacity is the amount of acid or base a buffer can handle before pushing the pH value outside of the buffer range.
Answer:
Amount
pH value
Buffer capacity is the amount of acid or base a buffer can handle before pushing the pH outside of the buffer range.
A buffer however consists of a weak acid and its conjugate base.Its major advantage is the ability to resist changes in pH when an acid or a base is added to the solution.
The human blood is also an example of a buffer solution as it is able to resist changes in pH when we eat or drink certain types of food.
An example of a buffer include acetic acid (HC₂H₃O₂) which is a weak acid and sodium acetate (NaC₂H₃O₂) which is a salt derived from that acid).
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A sample of ammonia, NH3, has a mass of 78.25 g. Calculate the number of ammonia molecules in the sample.
number of molecules:
Answers
There are approximately \(2.76 * 10^{24\) ammonia molecules in the given sample.
To calculate the number of ammonia molecules in the sample, we need to use Avogadro's number and the molar mass of ammonia.
The molar mass of ammonia \((NH_3)\) can be calculated by adding up the atomic masses of nitrogen (N) and hydrogen (H):
Molar mass of \(NH_3\) = (1 x atomic mass of N) + (3 x atomic mass of H)
= (1 x 14.01 g/mol) + (3 x 1.01 g/mol)
= 14.01 g/mol + 3.03 g/mol
= 17.04 g/mol
Now, we can calculate the number of moles of ammonia in the sample using the formula:
Number of moles = Mass of the sample / Molar mass
Number of moles = 78.25 g / 17.04 g/mol
≈ 4.5865 mol (rounded to four decimal places)
Finally, we can use Avogadro's number, which represents the number of particles (atoms, molecules, etc.) in one mole of a substance. Avogadro's number is approximately \(6.022 * 10^{23\) particles/mol.
Number of ammonia molecules = Number of moles x Avogadro's number
Number of ammonia molecules ≈ 4.5865 mol x (\(6.022 * 10^{23\) molecules/mol)
≈ \(2.76 * 10^{24\) molecules (rounded to two significant figures)
Therefore, the provided sample contains roughly \(2.76 * 10^{24\) ammonia molecules.
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The number of ammonia molecules in the sample is approximately 2.764 x \(10^{24}\) molecules.
To calculate the number of ammonia molecules in a given sample, we need to use Avogadro's number and the molar mass of ammonia.
The molar mass of ammonia (NH3) is calculated as follows:
Molar mass of N = 14.01 g/mol
Molar mass of H = 1.01 g/mol
Total molar mass of NH3 = 14.01 g/mol + (3 * 1.01 g/mol) = 17.03 g/mol
Now, we can calculate the number of moles of ammonia in the sample:
Number of moles = Mass of sample / Molar mass of NH3
Number of moles = 78.25 g / 17.03 g/mol = 4.594 moles
Next, we use Avogadro's number, which states that there are 6.022 x \(10^{23}\) molecules in one mole of a substance.
Number of molecules = Number of moles * Avogadro's number
Number of molecules = 4.594 moles * 6.022 x \(10^{23}\) molecules/mol = 2.764 x \(10^{24}\) molecules
Therefore, there are approximately 2.764 x \(10^{24}\) ammonia molecules in the given sample of 78.25 g.
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How many grams of water at 25 C must be mixed in an insulated container with 250 grams of water at 93 C if the final temperature of the combined water is to be 75 C.
Answers
Answer:
Explanation
Comment
Normally you would just use m*c*delta T. But the c is the same in both cases, so you need just use m*deltaT
Givens
25 degrees
m = ?
T = 25
t = final temp = 75
93 degrees
m = 250
T = 93
t = final temp = 75
Solution
(t - 25)*m = (93 - t) * 250 Remove the brackets
75*m - 25m = 93*250 - 250*75 Combine the right
m(75 - 25) = 23250 - 250*75
50 m = 23250 - 18750 Combine
50 m = 4500 Divide both sides by 50
50*m/50 = 4500/50
m = 90
Answer: 90 grams are needed.
A helium balloon with an internal pressure of 1.00 atm and a volume of 4.50 L at 20.00 C is released. What volume will the balloon occupy at an altitude where the pressure is 0.600 atm and the temperature is -20.00 C?
Answers
The volume the balloon will occupy at an altitude where the pressure is 0.600 atm and the temperature is -20.00 C is 6.15 L.
The ideal gas law can be used to solve the given problem, which is as follows:P1V1/T1 = P2V2/T2 Where:P1 is the initial pressure (1.00 atm)P2 is the final pressure (0.600 atm)V1 is the initial volume (4.50 L)V2 is the final volume (what we want to find)T1 is the initial temperature (20.00 C = 293.15 K)T2 is the final temperature (-20.00 C = 253.15 K)The problem does not provide the mass or number of moles of helium gas, but these quantities are not required to solve the problem as they cancel out in the calculation.The problem also does not mention any change in altitude, so we can assume that the balloon rises to an altitude where the pressure and temperature are lower.We can rearrange the equation above to solve for V2, which gives:V2 = (P1V1T2)/(P2T1) Substituting the given values gives:V2 = (1.00 atm × 4.50 L × 253.15 K)/(0.600 atm × 293.15 K)V2 = 6.15 L.
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A liquid ester used to flavour food is believed to be impure. What would be the best way of testing its purity?
Answers
Answer:
Filter it
Explanation:
Which of the following conclusions can be drawn from the curves in the
energy diagram?
OA. The reaction represented by curve B will go faster than the curve A
reaction.
OB. The molecules represented in curve A have higher kinetic energy
than curve B.
C. The reaction represented by curve B has a larger equilibrium
constant than curve A.
OD. The reaction represented by curve A requires less added energy
than curve B.
SUBMIT
Answers
OD. The reaction represented by curve A requires less added energy than curve B.
Curve A represents an exothermic reaction because the products have less energy than the reactants, and curve B represents an endothermic reaction because the products have more energy than the reactants. The difference in energy between the reactants and products in curve A is less than the difference in energy between the reactants and products in curve B, which means that less energy is required to reach the transition state in curve A than in curve B. Therefore, curve A requires less added energy than curve B.
Option A is incorrect because the speed of a reaction is not determined by the shape of the energy diagram.
Option B is incorrect because the shape of the curves does not provide information about the kinetic energy of the molecules.
Option C is incorrect because the size of the equilibrium constant is not determined by the shape of the energy diagram.
oxidation number of Ag in Ag2O
Answers
The oxidation number of Ag in Ag2O is +1.
In Ag2O, there are two silver atoms (Ag) and one oxygen atom (O). Oxygen is known to have an oxidation number of -2 in most compounds. Since the compound is neutral, the sum of the oxidation numbers of all the atoms must equal zero.
Therefore, the oxidation numbers of the two silver atoms must add up to +2 to balance out the -2 oxidation number of the oxygen atom. Since there are two silver atoms, each silver atom must have an oxidation number of +1 to yield a total oxidation number of +2 for the compound.
In Ag2O, the silver atoms lose one electron each to form Ag+ ions. This results in an oxidation number of +1 for each silver atom. The oxygen atom gains two electrons from the silver atoms to achieve a stable octet configuration, resulting in an oxidation number of -2 for the oxygen atom. The compound Ag2O is formed through the transfer of electrons, with each silver atom exhibiting an oxidation number of +1.
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A compound that consists of atoms of nonmetals that are held together by covalent bonds are.
Answers
You can consider CsI3(Cesium Iodide).
It has Cs+ and I3 - cation and anion respectively bonded by ionic bond . And I3- is bonded by covalent bonds.
Answer:
You can consider CsI3(Cesium Iodide).
It has Cs+ and I3 - cation and anion respectively bonded by ionic bond . And I3- is bonded by covalent bonds.
Do the ch3f molecules appear to attract each other much? briefly describe their interaction.
Answers
Neither attract much nor allows it be free.
How the molecules behave in such way?
Because fluorine has a higher electronegativity than carbon and hydrogen, CH3F possesses a non-zero dipole moment. As a result, fluorine draws a partial negative charge whereas other atoms (such as carbon or hydrogen) draw a partial positive charge, leading to a non-zero dipole moment in CH3F. Lewis' structure, CH3F, is made up of one carbon atom, three hydrogen atoms, and one fluorine atom. Carbon is the key atom in the CH3F lewis structure because it is the least electronegative. The CH3F lewis dot structure consists of 3 lone pairs and a total of 4 bound pairs.
Properties of CH3F
It molar mass is 34.03 g/mol.The density of CH3F is 1.4397 g/L and 0.557 g/cm³ at saturated pressure and temperature.The melting point of CH3F is -137.8ºC and the Boiling point is -78.4ºC.Its vapor pressure is 3.3 MPa.Its IUPAC name is Fluoromethane.Know more about carbon here:
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The combustion of octane, C8H18, proceeds according to the reaction shown.
2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l)
If 354 mol of octane combusts, what volume of carbon dioxide is produced at 15.0 ∘C
and 0.995 atm?
Answers
The concept ideal gas equation is used here to determine the volume of the carbondioxide. Combustion reactions are generally highly exothermic reactions. The volume of CO₂ is
A combustion is a chemical reaction in which a fuel undergoes oxidation as a result of the reaction with an oxidizing agent which causes the release of energy in the form of heat.
15.0 °C = 288 K
The ideal gas equation is:
PV = nRT
V = nRT / P
V = 354 × 0.0821 × 288 / 0.995 = 8412.3 L
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A solution of sodium oxalate (Na 2C 20 4) in acidic solution is titrated with a solution of potassium permanganate (KMnO 4) according to the following
balanced chemical equation:
2KMnO4(aq) + 8H2SO4(aq) + 5Na2C204(aq) 2MnSO4(aq) - 8H20() +10C02(9) + SNa2SO4(aq) + K2SO4(aq)
What volume of 0.0206 M KMnO4 is required to titrate 0.176 g of Na2C204 dissolved in 50.0 mL of solution?
O a. 8. 54 ml
O b. 500 ml
OC 25 5 ml
O d.3.42 m
e. 63 8 ml
X
Answers
The volume of 0.0206 M KMnO₄ required to titrate 0.176 g of Na₂C₂O₄ dissolved in 50.0 mL of solution is 25.5 mL (Option C)
How to determine the mole of Na₂C₂O₄Mass of Na₂C₂O₄ = 0.176 gMolar mass of Na₂C₂O₄ = 134 g/mol Mole of Na₂C₂O₄ =?
Mole = mass / molar mass
Mole of Na₂C₂O₄ = 0.176 / 134
Mole of Na₂C₂O₄ = 1.313×10¯³ mole
How to determine the mole of KMnO₄2KMnO₄ + 8H₂SO₄ + 5Na₂C₂O₄ —> 2MnSO₄ + 8H₂O +10CO₂ + 5Na₂SO₄ + K₂SO₄
From the balanced equation above,
5 moles of Na₂C₂O₄ reacted with 2 moles of KMnO₄
Therefore,
1.313×10¯³ mole of Na₂C₂O₄ will react with = (1.313×10¯³ × 2) / 5 = 5.252×10¯⁴ mole of KMnO₄
How to determine the volume of KMnO₄Mole of KMnO₄ = 5.252×10¯⁴ moleMolarity of KMnO₄ = 0.0206 MVolume of KMnO₄ =?Volume = mole / molarity
Volume of KMnO₄ = 5.252×10¯⁴ / 0.0206
Volume of KMnO₄ = 0.0255 L
Multiply by 1000 to express in mL
Volume of KMnO₄ = 0.0255 × 1000
Volume of KMnO₄ = 25.5 mL
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Proton, Neutron and Electron of 23 13 Aluminum
Answers
The atomic mass of Aluminum is 23, which means it has a total of 23 particles in its nucleus, including protons and neutrons.
Aluminum has an atomic number of 13, which means it has 13 protons in its nucleus.
To find the number of neutrons, we subtract the atomic number from the atomic mass. So, Aluminum has 23 - 13 = 10 neutrons in its nucleus. Electrons are the negatively charged particles that orbit around the nucleus of an atom.
Aluminum, being a neutral atom, has an equal number of electrons to the number of protons in its nucleus, which is 13. These electrons are distributed in different energy levels or shells around the nucleus.
Aluminum is a widely used metal in different applications due to its unique properties such as low density, high strength, and resistance to corrosion. It is used in the manufacturing of cans, foils, and aircraft parts. The number of protons and electrons determines the atomic number and chemical properties of an element. The number of neutrons affects the stability and isotopes of an element.
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How many mL are in 0.365 L?
Answers
Answer:
365 mL
Explanation:
There are 1,000 mL per every 1 L. As such, to convert between the two measurements, you need to multiply the given volume (0.365 L) by the conversion. To allow for the cancellation of units (liters), liters should be in the denominator of the conversion.
1,000 mL = 1 L
0.365 L 1,000 mL
---------------- x ----------------- = 365 mL
1 L
Introduction
Sodium bicarbonate, NaHCO3 (MW 84.007 g/mol), is commonly known as baking soda. Sodium bicarbonate is a solid crystalline and
appears as a white powder. Sodium bicarbonate can be easily be converted to sodium carbonate, Na2CO3 (MW 105.988 g/mol) by
decomposition to produce H₂O and CO₂. This can be accomplished by placing the sample in the oven at 176 deg F.
Unbalanced chemical equation: NaHCO3 (s) + heat-> Na₂CO3 (s)+ H₂O(g) + CO₂(g)
Demonstration Video: [Click here for video]
Percent yield - (actual yield/ theoretical yield) x 100
Purpose
This assignment is designed to teach students about decomposition reactions and determine the percent yield. At the end of the experiment, the
student will have a better understanding of how this assignment will benefit their learning.
Task
-Write a balanced chemical equation
- Calculate the percent yield of the decomposition reaction (Must show your work)
Answers
We can actually deduce here that the purpose of this assignment is to teach students about decomposition reactions and allow them to determine the percent yield.
What is the experiment all about?By performing the experiment, students will gain a better understanding of the concepts involved and how they relate to their overall learning.
The specific focus of this assignment is the decomposition of sodium bicarbonate (NaHCO3) to produce sodium carbonate (Na2CO3), water (H2O), and carbon dioxide (CO2). The unbalanced chemical equation for this reaction is:
NaHCO3 (s) + heat -> Na2CO3 (s) + H2O (g) + CO2 (g)
To understanding the reaction itself, students will also learn about the concept of percent yield. Percent yield is a measure of the efficiency of a chemical reaction and is calculated by dividing the actual yield of the desired product by the theoretical yield, then multiplying by 100.
This calculation allows students to assess how well the reaction proceeds in terms of producing the expected amount of sodium carbonate.
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17. HAZWOPER training and certification recognizes:
a. A large number (as much as 80%) will self-present or be self-referred victims
b. Awareness level training will promote proper initial triage actions
c.
Victims will use any entrance they can enter at the hospital, in addition to the
emergency department entrance
d. Both A and C
Answers
HAZWOPER training and certification recognize:
a large number (as much as 80%) will self-present or be self-referred victimsVictims will use any entrance they can enter at the hospital, in addition to the emergency department entranceThe correct option is both A and C
What is the HAZWOPER training and certification?HAZWOPER (Hazardous Waste Operations and Emergency Response) training and certification recognize that a large number of victims (as much as 80%) in hazardous waste incidents or emergencies will self-present or be self-referred for medical treatment.
Additionally, HAZWOPER training acknowledges that victims may use any entrance they can access at a hospital, not just the emergency department entrance.
This is because individuals affected by hazardous materials may arrive at different areas of the hospital seeking medical assistance.
Therefore, option d. Both A and C are correct statements regarding the recognition of HAZWOPER training and certification.
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Determine the number of grams of 10 moles of CCI4
Answers
Answer:
10 moles of CCl4 is equal to 1538.1 grams.
Explanation:
To determine the number of grams in 10 moles of CCl4, we can use the molar mass of CCl4. The molar mass of a substance is the mass of one mole of that substance and is often expressed in grams per mole (g/mol).
The molar mass of CCl4 is 153.81 g/mol. To convert from moles to grams, we multiply the number of moles by the molar mass:
10 moles x 153.81 g/mol = 1538.1 g.
So, 10 moles of CCl4 is equal to 1538.1 grams.
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Explain why phosphorus pentafluoride, PF5 is a stable well known molecule but the very similar molecule NF5 where the phosphorus is replaced by nitrogen doe not exist
Answers
There are vacant orbitals on the phosphorus atom that allows it to expand its octet.
Why is it that the phosphorus pentafluoride is stable?There is a concept that we would need to consider as we are answering the question that we here and that is the idea of the octet rule. The octet rule states that it is only about eight electrons that can be found on the outermost shell of an atom and as such all of the compounds can be formed in obedience to this rule.
Now we should know that there are no vacant d orbitals that are present on the nitrogen atom and this stems from the fact that it does not have a 3d level as such there are no orbitals that can be able to help the Nitrogen atom so as to be able to expand its octet. This is the reason why its pentafluoride can be easily formed.
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