28. Which method or operator can be used to concatenate lists? A. * B. + C. % D. concat

Let $x ij$ represent the quantity of cars that will be delivered in the following two hours from city I to city j.

Network Diagram:

LP Formulation:

Maximize Z = 150x14 + 150x24

Subject to:

x11 + x12 + x13 + x14 <= 300 (flow from city 1 to other cities)

x21 + x22 + x23 + x24 <= 300 (flow from city 2 to other cities)

x31 + x32 + x33 + x34 <= 300 (flow from city 3 to other cities)

x41 + x42 + x43 + x44 <= 300 (flow from city 4 to other cities)

x11 + x21 + x31 + x41 = 150 (flow into city 1)

x12 + x22 + x32 + x42 = 150 (flow into city 2)

x13 + x23 + x33 + x43 = 150 (flow into city 3)

x14 + x24 + x34 + x44 = 150 (flow into city 4)

xij >= 0 (all variables must be positive)

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Answer:

The sum of all numbers between 0 and 21 inclusively can be represented as Σ21 i=1 i, so the correct answer is: Σ21 i=1 i.

Explanation:

The correct answer is a. brittle deformation. therefore the correct option is (a) option.

Brittle deformation is when rocks fail as rigid solids. The rocks will break, rather than bend, under these conditions to produce fractures. Brittle deformation occurs along discrete planes in the rock instead of involving the rock body as a whole.Brittle materials include glass, ceramic, graphite, and some alloys with extremely low plasticity, in which cracks can initiate without plastic deformation and can soon evolve into brittle breakage.

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More cooking is done before the water actually begins to boil thanks to the raised pressure inside the cooker, which raises the boiling point of water above 1000C. In the end, food cooks more quickly.

Slow-cooked meals can be quickly prepared with pressure cookers. They are efficient in terms of electricity consumption and are excellent for tenderizing less expensive portions of meat. They are a healthy cooking method since they effectively retain nutrients and can cut cooking times by up to 50%. Water boils at 121°C (250°F) at that pressure. As a result, food may cook at considerably greater temperatures than it could under atmospheric pressure. Additionally, because cooking reactions quicken at higher temperatures, food cooks more quickly it is a good technology.

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Answer:

1/8 is the maximum length for opening any on the surface of 2 gtam guided bend test specimen

Answer:

defining the need

Explanation:

Of course, since the first stage of the engineering design phase involves defining the need of the design, it is at this stage that the researcher/engineer should determine the criteria and constraints.

This stage involves asking such questions as:

Answer:

Automotive engineering

In crow's foot style E-R diagrams, a hash mark (#) across the relationship line near an entity indicates a minimum cardinality of mandatory and a maximum cardinality of one (option B).

The crow's foot notation is a graphical representation used in E-R diagrams to represent the cardinality of the relationships between entities.

In this notation, an entity is represented as a rectangle, and a relationship is represented as a line connecting two entities.

The crow's foot notation uses various symbols to represent the cardinality of the relationship, including a hash mark (#).

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Answer:

20% of the critical value. Determine (a) the damping factor, (b) the

Explanation:

Answer:

b. American Society of Mechanical Engineers

Explanation:

The "American Society of Mechanical Engineers" (ASME) is an organization that ensures the development of engineering fields. It is an accreditation organization that ensures parties will comply to the ASME Boiler and Pressure Vessel Code or BPVC.

The BPVC is a standard being followed by ASME in order to regulate the different pressure vessels and valves. Such standard prevents boiler explosion incidents.

Answer:

No matter what u post on a football page, some fatherless dude will either say "pessi" or "penaldo"

a) The undrained shear strength of this clay is 1605.6 psi, and ∅ = 0.

b) As the value of  ∅ = 0, this the reason for which diameter Mohr's circle is same.

c) Ratio of clay, c/p = 0.3211

d) At the depth of 120 feet below, shear strength remains same, i.e. S = 11.15 psi, as ∅ = 0.

Shear strength in engineering refers to a material or component's resistance to a particular type of yield or structural failure when the material or component fails under shear. A force called a "shear load" tends to cause a material to fail slidingly along a plane parallel to the direction of the force. Scissors fail to shear a piece of paper when they are used to cut it.

For designing the dimensions and materials to be used for the manufacture or construction of a component, shear strength of a component is important in structural and mechanical engineering (e.g. beams, plates, or bolts). Reinforcing bar stirrups, also known as rebar, are used in reinforced concrete beams primarily to increase shear strength.

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Answer:

Exponential Series

Explanation:

Answer:

\({ \rm{x(t) = a_{0} + \sum a_{k} \cos \omega t + \sum b _{k} \sin \omega t }}\)

\({ \tt{ a_{0} = \frac{2}{t} \int x(t) \: dx}} \\ \\ { \tt{ a_{k} = \frac{1}{t} \int x(t) \cos \omega t \: dx }} \\ \\ { \tt{ b_{k} = \frac{1}{t} \int x(t) \sin \omega t \: dx }}\)

Generators must be oversized when supplying non-linear loads to reduce heating and voltage waveform distortion.An oversized generator is an electrical generator that is larger than the anticipated electrical load.

The need for an oversized generator may arise if the original electrical load changes, if the system's future expansion is expected, or if the generator must run at low loads.Overloading a generator can result in system overloads, poor power quality, and device failures.

When a generator is oversized, its electrical power output capability is greater than the load that it will supply, and it will not be loaded to its full potential.

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The three individual navigation services provided by a VORTAC facility are as follows:VOR (Very High-Frequency Omnidirectional Range)DME (Distance Measuring Equipment)TACAN (Tactical Air Navigation).

A VORTAC facility is a ground-based radio navigation aid that provides aircraft with directional guidance.The term "VORTAC" refers to the combination of two navigation aids:VOR (Very High-Frequency Omnidirectional Range)TACAN (Tactical Air Navigation)A VORTAC provides three separate navigation services: VOR (Very High-Frequency Omnidirectional Range), DME (Distance Measuring Equipment), and TACAN (Tactical Air Navigation).

Each navigation aid uses a different type of radio signal to provide pilots with the information they need to navigate.A VOR provides azimuth (directional) information to the aircraft. It is based on the principle of measuring the phase difference between two signals transmitted from the ground station.

A VOR provides a 360-degree coverage around the station.DME (Distance Measuring Equipment) is an additional component of a VOR/TACAN that provides pilots with slant range distance information from the aircraft to the ground station.

TACAN (Tactical Air Navigation) is a military navigation aid that provides both azimuth and distance information. It is similar to a VOR/DME, but uses a different type of signal. TACAN provides both azimuth (directional) and distance (range) information to the aircraft.

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PMMA and polycarbonate polymers are known to plastically deform following the Sternstein and Ongchin's hydrostatic-stress-dependent yield criterion. The yielding mechanisms for the given (proportional) loading modes are discussed below:a) Hydrostatic compression mechanism:This loading mechanism applies equal force from all directions of the object.

Hydrostatic compression causes deformation in the material when the forces applied from all directions are equal or when the ratio of the stresses are identical. Here, the polymers will deform plastically following the Sternstein and Ongchin's hydrostatic-stress-dependent yield criterion.b) Pure shear mechanism:

Pure shear is a type of deformation in which the body experiences forces parallel to its surface but in opposing directions. When this is done, the object undergoes deformation that results in the shape of the object changing, while the volume remains constant. In this case, the mechanism of yielding for the polymer would be related to the deformation and the applied force, which causes the molecular orientation of the polymer to be distorted and induces shearing of the material.The mechanisms of yielding for PMMA and polycarbonate polymers under hydrostatic compression and pure shear loading modes are discussed above in long answer format.

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Answer:

Explanation:

write each force in terms of magnitude and directions  

Fx = F sin Ф

Fy = F cos Ф

where Ф is to be measured from x axis.

∑F at y = o

FAy + FBy + FCy + FDy + FEy + FGy = 0

∑F at x = o

FAx + FBx + FCx + FDx + FEx + FGx = 0

Let  

FA = FA sin (110)   +   FA cos (110)

FB = 20 sin (270)  +  20 cos (270)

FC = 16 sin (140)    +  16 cos (140)

FD = 9 sin (40)       +  9 cos (40)

FE = 20 sin (270)    +  20 cos (270)

FG = FG sin (50)     +  FG cos (50)

add x and y forces:

FAx + FBx + FCx + FDx + FEx + FGx = 0

FAy + FBy + FCy + FDy + FEy + FGy = 0

FA sin (110)  + 0  + 16 sin (140)  + 9 sin (40)  + 0   + FG sin (50) = 0

FA cos (110) - 20 + 16 cos (140) + 9 cos (40) - 20 + FG cos (50 = 0

FA sin (110)  + 0  + 10.285  + 5.785  + 0   + FG sin (50) = 0

FA cos (110) - 20 - 12.257 + 6.894 - 20 + FG cos (50) = 0

FA sin (110)  + 16.070 + FG sin (50) = 0        

FA cos (110) - 45.363 + FG cos (50) = 0

solving for FA, and FG

FA = 13 kN

FG = 15.3 kN

From the given information, we can say that the sum of the upward forces is equivalent to the sum of the downward forces.

From the diagram, equating the component of the upward forces and the downward forces, we have:

\(\mathbf{-F_a sin 70 +F_c sin 40+F_d sin 40 + F_g sin50= F_b+F_e}\) --- (1)

Also, the sum of the horizontal positive x-axis as well as the horizontal negative x-axis can be computed as:

\(\mathbf{F_g cos 50 +F_d cos 40 = F_c cos 40 +F_a cos 70 --- (2)}\)

If:

\(F_B = F_E = 20 \ kN \\ \\ F_c = 16 \ kN \\ \\ F_D= 9\ kN\)

Then, from equation (1), we can have the following:

\(\mathbf{F_a sin 70 + 16 sin 40 + 9 sin40 + F_gsin 50 = (20 + 20 )kN}\)

collecting like terms;

\(\mathbf{F_a sin 70 + F_gsin 50 = 40 - 16 sin 40 - 9 sin40 }\)

\(\mathbf{F_a sin 70 + F_gsin 50 =23.93}\) --- (3)

From equation (2);

\(\mathbf{F_g cos 50 + 9cos 40 = 16 cos 40 + F_a cos 70}\)

collecting like terms:

\(\mathbf{F_g cos 50 -F_a cos 70 =16cos 40 -9cos 40}\)

\(\mathbf{-F_a cos 70 +F_g cos 50 =5.36 ----- (let \ this \ be \ equation (4))}\)

Suppose we equate (3) and (4) together using the elimination method;

\(\mathbf{F_a sin 70 + F_gsin 50 =23.93}\) --- (3)

\(\mathbf{-F_a cos 70 +F_g cos 50 =5.36 --- (4)}\)

Let's multiply (3) with ( cos 70 ) and (4) with (sin 70);

Then, we have:

\(\mathbf{F_a sin 70 cos 70 + F_gsin 50 cos 70 =23.93 cos 70}\)

\(\mathbf{-F_a cos 70 sin 70 +F_g cos 50 sin 70 =5.36 sin 70}\)

Adding both previous equations together, we have:

\(\mathbf{F_a sin 70 cos 70 + F_gsin 50 cos 70 =23.93 cos 70}\)

\(\mathbf{-F_a cos 70 sin 70 +F_g cos 50 sin 70 =5.36 sin 70}\)

\(\mathbf{(0 + F_g(sin 50 cos 70 + sin70 cos50) = 23.93 cos 70 + 5.36 sin 70)}\)

\(\mathbf{( F_g(0.262 + 0.604)) =(8.19 + 5.04)}\)

\(\mathbf{( F_g(0.866)) =(13.23)}\)

\(\mathbf{ F_g =\dfrac{(13.23)}{(0.866)}}\)

\(\mathbf{ F_g =15.28 \ N}\)

Replacing the value of \(\mathbf{F_g}\) into equation (3), to solve for \(\mathbf{F_a}\), we have:

\(\mathbf{F_a sin 70 + F_gsin 50 =23.93}\)

\(\mathbf{F_a sin 70 + 15.28sin 50 =23.93} \\ \\ \mathbf{F_a sin 70 +11.71 =23.93} \\ \\ \mathbf{F_a sin 70 =23.93-11.71 } \\ \\ \mathbf{F_a sin 70 =12.22 } \\ \\ \mathbf{F_a =\dfrac{12.22 }{sin 70}} \\ \\\)

\(\mathbf{F_a =13.01 \ N}\)

Therefore, we can conclude that the magnitudes of \(\mathbf{F_a}\) and \(\mathbf{F_g}\) are 13.0 N and 15.28 N respectively.

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According to the given statement, technician a says that some FWD vehicles use unequal length front driveshafts called half shafts. Technician b says that unequal length driveshafts may cause a pull during hard acceleration called torque steer. It is required to determine which technician is correct.

Here is the answer: The answer is Technician B is correct because the unequal length driveshafts may cause a pull during hard acceleration called torque steer. In FWD vehicles, unequal length front driveshafts are called half shafts. Half shafts are used in FWD (front-wheel drive) systems to transfer power from the engine/transaxle to the front wheels to make them spin.

Torque steer is a phenomenon in which the unequal length of the half-shafts causes the wheels to pull in the direction of the longer side.

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The power exerted by the dominant group over minority groups through institutions, such as mass media and popular culture, in order to communicate and reinforce ruling values and beliefs that may be adopted by members of the minority group is referred to as hegemony.

The term "hegemony" best describes the concept described in the question. Hegemony refers to the social, cultural, and ideological influence wielded by the dominant group over subordinate groups within a society. It involves the imposition of dominant norms, values, and beliefs that shape the worldview and behavior of both the dominant and subordinate groups.

In this context, institutions like mass media and popular culture play a significant role in disseminating and reinforcing the ideologies and narratives of the dominant group. By controlling the representation, portrayal, and dissemination of information, the dominant group can shape public opinion and maintain their position of power and control.

However, it is important to note that while hegemony influences the beliefs and behaviors of some members of the minority group, it does not encompass all forms of discrimination, racism, or oppression. These terms represent specific manifestations of power imbalances and discriminatory practices, which can be reinforced by hegemonic systems but are not limited to them.

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In order to determine the height of the tower, we would apply the second equation of motion and assume that the downward motion is negative.

Mathematically, the second equation of motion is given by this formula:

S = ut + ½gt²

Where:

Substituting the given parameters into the formula, we have;

S = S₀ + ut - ½gt²

0 = S₀ + (0)4.0 - ½ × (9.8) × 4.0²

0 = S₀ - 4.9 × 16.0

Height, S₀ = 78.4 meters.

In order to calculate the bearing's impact velocity, we would apply the first equation of motion:

V = u - at

V = 0 - 9.8(4.0)

Impact velocity, V = 39.2 m/s.

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Complete Question:

Ball bearings can be made by letting spherical drops of molten metal fall inside a tall tower, called a shot tower, and solidify as they fall.

a. If a bearing needs 4.0 s to solidify enough for impact, how high must the tower be?

b. What is the bearing's impact velocity?

Answer:

newspaper, radio, televison

Explanation:

had avid in 7th :)

Answer:

1. will help for colcollares.

2. gives you money for studies

3. helps you choose the perfect collage

Formwork is a temporary structure that is used in construction to provide support and shape to freshly poured concrete until it is strong enough to stand on its own.

It is a crucial component of any construction project as it ensures that the concrete is poured into the desired shape and size, and prevents any potential collapses or deformations. Additionally, formwork helps to create a smooth and uniform finish to the concrete surface, which is important for both aesthetic and functional purposes. Overall, formwork is an essential tool in modern construction, providing a safe and reliable method of shaping and supporting concrete structures.

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Answer:

Explanation:

It really all depends, it varies from 375 to 830, you can't mark one as " Lamborghinis have this much hp always " seeing it fluctuates so much car to car

8 MB Physical memory needed to storing for page table.

Given

Virtual address = 33 bit.= 2³³ B

Page Number (P) Page Size (d)

21 12

Page Size = 4KB= 4*2¹⁰ B= 2²*2¹⁰ B (12 bit)

( 1K = 2¹⁰).

Total Number of Page (P) =

Virtual address Size/ Page Size

= 2³³B/ 2¹²B

= 2²¹ .

Page Table data structure used to mapping between Virtual Address and Physical Address.

page table contains all information about every page in PTE (Page Table Entry) .

In one PTE contain information of one page.

Size of Page Table

= Number of Page * Size of PTE

= 2²¹ * 4 B

= 2²¹ * 2² B

= 2²³ B

= 2³ MB. ( 1M = 2²⁰)

= 8MB.

8 MB Physical memory needed to storing for page table.

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To remove an electrical plug from its socket, your hands must be dry, and you should grip the plug's base, not the cord. Here are more than 100 words on why you need to take these precautions:Electrical plugs are among the simplest components of electronic devices and the most prone to problems.

As simple as they are, plugs require a basic understanding of how to handle them safely. Electrical shock can result from even a minor mistake, such as not dry hands. Electrical shock can be lethal, and it can cause burns, pain, and injury.The first rule for removing a plug safely is to ensure that your hands are dry.

It's critical to be cautious when unplugging a device from a socket because the electrical energy inside the device can pass through your body if your hands are wet or damp. Always dry your hands before handling a plug, particularly if you have sweaty hands. Using a dry cloth is a good idea.

The second rule is to grip the base of the plug rather than the cord. If you pull on the cord instead of the plug's base, you risk damaging the cord's wires or even tearing them apart. You may also cause the plug to come loose, which can result in an electrical shock.

Always hold the plug firmly, but not too tightly, at the base when removing it from the socket. Never yank on the cord to remove the plug.These two simple rules can go a long way in ensuring your safety when working with electrical plugs.

It is important to remember that electricity can be extremely dangerous, so it is critical to take precautions when working with electronic devices.

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Answer:

Flow rate = 118.8 gpm, discharge pressure= 331.5 psig, shaft power = 26.3 hp and Efficiency = 87.5%.

Explanation:

Without mincing words, let us dive straight into the solution to the question above. So, the following parameters or data are given in the question above:

gpm = 80 gpm, shaft power = 8hp, and the pressure of  150 psig.

The flow rate =[ 80 × 1500] ÷ 100g = 118.9 gpm.

Hence, the discharge pressure = 150 × [ 1500/100]² = 331.5 psig.

Also, the required shaft power = 8 × [ 1500/100]³ = 26.3 hp.

The last part that is the efficiency can be calculated as given below:

Efficiency = [ 80 × 0.00223 × 144 × 150 ] ÷ [550 × 8 ] = 0.875 = 87.5%.

Answer:

See attachment for chart

Explanation:

The IPO chart implements he following algorithm

The expressions in bracket are typical examples

Input

Input Number (5, 4.2 or -1.2) --- This will be passed to the Processing module

Processing

Assign variable to the input number (x)

Calculate the square (x = 5 * 5)

Display the result (25) ----> This will be passed to the output module

Output

Display 25