Answer:
See Explanation
Explanation:
Given
Steps: a - f
Table
\(\begin{array}{ccccccc}{cm} & {9} & {10} & {13} & {18} & {50} & {83} \ \\ {Age} & {10} & {20} & {30} & {40} & {50} & {60} \ \end{array}\)
Note that: The question is a practical question and the result may differ base on individuals and environment.
So, I will pick up the question from how to determine the age of the eye after the distance between the eyes and the pencil has been established
In my case, the measurement is:
\(Length= 10.4\)
Approximate
\(Length= 10\)
From the above table, the corresponding age to 10cm is:
\(Age = 20cm\)
If in your measurement, the length is approximately (for example):
\(Length = 9cm\)
The age will be:
\(Age = 10\)
The article stated that the deepest crisis is political - the failure of various political institutions in the United States to "promote the public welfare" as promised by the US Constitution. What do you think?
There are certainly significant challenges facing the US political system, and there is a need for reforms that can improve the functioning of government and promote public welfare. However, there is also an ongoing debate about the nature of these challenges and the best path forward to address them.
What institutional failures have hindered the government's ability to address major public policy challenges?Critics of the US political system argue that several institutional failures have hindered the government's ability to address major public policy challenges. For example, some say that the US Congress has become increasingly dysfunctional. In contrast, others point to the role of money in politics, with the influence of wealthy donors and special interest groups limiting the ability of elected officials to act in the public interest.
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1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point. What is the heat of fusion of the substance?
1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point , the heat of fusion of the substance is 548 joules .
What is heat of fusion ?Heat of fusion, also known as enthalpy of fusion or latent heat of fusion, is the amount of energy required to melt or freeze a substance under constant pressure conditions. When it comes to chemistry, "fusion" is basically synonymous with "melting." In the classroom, heat of fusion is typically used when a substance is at its melting or freezing point. In such instances, most people consider heat of fusion to be a constant.
Water, for example, has a heat of fusion of 334 J/g at its melting point of 0°C. At 0°C, one grams of liquid water requires 334 Joules of energy to completely freeze into ice. In addition, one grams of ice requires 334 Joules of energy to melt entirely.
q = m×∆Hf
q: Total change in heat energy (in Joules)
∆Hf: Heat of fusion of substance (in Joules per gram)
m: Mass of substance (in grams)
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During the earthquake, what we need to do to be safe,write steps.
(i) When you are in the classroom.
(ii) When you are out of danger
During an earthquake, it is important to take appropriate steps to ensure safety
Steps you can follow in two different scenarios(i) When you are in the classroom
Drop, Cover, and Hold On: Quickly drop to the ground, take cover under a sturdy desk or table, and hold on to it to protect yourself from falling objects and potential structural collapse.
Protect Your Head: If possible, use your arms to cover your head and neck to provide additional protection.
Stay Indoors: Remain inside the classroom until the shaking stops and it is safe to exit. Be prepared for aftershocks, which are smaller tremors that may occur after the main earthquake.
(ii) When you are out of danger:
Evacuate to Open Space: If you are no longer in immediate danger, move quickly to an open space away from buildings, trees, streetlights, and utility wires that may pose a risk of falling or collapsing.
Watch for Falling Debris: Be aware of your surroundings and watch out for any hazards such as falling debris, broken glass, or damaged infrastructure.
Stay Clear of Buildings: Avoid entering damaged buildings or structures as they may be unstable. Keep a safe distance until authorities confirm it is safe to enter.
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which of the following statements about mass and weight is correct?
A. "Mass" is the scientific term for "weight''
B. Weight directly measures force while mass directly measures amount of matter.
C. Weight has unit of kilograms or grams. Mass has unit of newtons.
D. The mass of an object depends on the size of the object. The weight of an object dosent depend on the size of the object.
The correct answer is B. Weight directly measures force while mass directly measures the amount of matter.
Explanation:
Weight and mass are two related but not identical concepts. The first term "mass" can be found by measuring the amount of matter in a body or substance. For example, the mass in an apple is around 80 grams depending on its size. In this context, mass is measured using units such as grams or kilograms. On the other hand, weight considers not only the matter in an object but the force exerted in it, especially, the gravitational force. In the case of the apple, the weight is 1 N as newtons (N) are used to measure force and this is the result of multiplying the mass by gravity. According to this, option B is correct.
In the Skycoaster amusement park ride, riders are suspended from a tower by a long cable. A second cable then lifts them until they reach the starting position indicated in (Figure 1). The lifting cable is then released, and the riders swing down the circular arc shown. If the four riders have a total mass of 330 kg
, what is the tension in the left cable just before release?
Tension in the left cable is 4395.9 N.
What is meant by tension ?Tension is defined as a pulling force that acts along the length of a flexible medium like rope or cables.
Here,
The total mass of the riders is given, m = 330 kg
Let the tension in the left cable be T₁ and that in the right cable be T₂.
From the figure,
T₁ cos 15 = T₂ cos 26
T₁ = T₂ cos 26/cos 15
Also,
T₁ sin15 + T₂ sin 26 = mg
Substituting values,
(T₂ cos 26/cos 15) sin 15 + T₂ sin 26 = 330x 9.8
0.241 T₂ + 0.438 T₂ = 3234
0.679 T₂ = 3234
T₂ = 4762.8 N
Therefore, Tension in the left cable, T₁ = 0.930x 4762.8
T₁ = 4395.9 N
Hence, The tension in the left cable is 4395.9 N
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Your question was incomplete. Attaching the image here.
the dust bowl was an example of millions of pounds of dry soil being blown away by the wind this is an example of
A: erosion
B: weathering
C. Deposition
Answer: A: erosion
Explanation:
The Dust Bowl was a period of severe dust storms that occurred in the central United States during the 1930s. It was caused by a combination of factors, including prolonged drought, poor farming practices, and high winds. During this period, millions of pounds of dry soil were blown away by the wind, leading to a significant loss of topsoil. This is an example of erosion.
In an illustration, lines of force are drawn around a magnet to illustrate the magnetic
O field.
O induction.
O poles.
O force.
Need help now
Answer: A. Field
Explanation: Magnetic Field is the correct answer.
Answer:
A
Explanation:
Where are you atera11
Answer:
? who is atera11?
Explanation:
the radius of a white dwarf is determined by a balance between the inward force of gravity and the outward push of: ________
The correct answer for the radius of a white dwarf is determined by a balance between the inward force of gravity and the outward push of is Electron Degeneracy Pressure.
How does a white dwarf's mass affect its radius?
When you raise pressure, you also increase gravity and make the particles closer together, which causes the thing to get smaller because the only way to increase pressure is by adding mass. In other words, the radius of a white dwarf decreases with increasing mass.
A star's gravitational collapse will be stopped by electron degeneracy pressure if its mass is below the Chandrasekhar limit (1.44 solar masses). The force preventing a white dwarf star from collapsing is this one.
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The equilibrium between the outward push of "electron degeneracy pressure" and the inward force of gravity determines a white dwarf's radius.
What is quantum degeneracy pressure?
The more widespread phenomenon known as quantum degeneracy pressure has many different manifestations, including electron degeneracy pressure. As a result, a pressure is created to prevent the compression of matter into smaller amounts of space. The same fundamental process that determines the electron orbital structure of elements produces electron degeneracy pressure.
If a star's mass is below the Chandrasekhar limit, electron degeneracy pressure will prevent gravitational collapse (1.44 solar masses). A white dwarf star is kept from collapsing by this pressure. Because the degeneracy pressure provided by the electrons is weaker than the gravitational pull inward, a star that is larger than this limit.
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A light hollow tube of 2.00 cm diameter and 1.0 m length is filled with tiny beads of different density. The resulting density distribution is linear, with the left end having a density of 1.6 g/cm^3, and the right end having a density of 6.3 g/cm^3. How far from the left end will be the center of mass? (give answer in cm).
Answer:
i think c
Explanation:
cause
A spring of constant 10 N/m is oscillating a mass of 1kg. What is the period of oscillation?
a
Hi there!
We can use the following equation for the period of an oscillating spring system:
\(\large\boxed{T = 2\pi \sqrt{\frac{m}{k}}}\)
\(T\) = Period (s)
\(m\) = mass (kg)
\(k\) = Spring Constant (N/m)
Plug in the givens and solve.
\(T = 2\pi \sqrt{\frac{1}{10}} = \boxed{1.987 s}\)
Grains (pounds)
Nonfat/1% milk (gallons)
Poultry (pounds)
Seafood (pounds)
12
Vegetables (pounds)
271
1
Yogurt (pounds)
Fats and oils (pounds)
55
24
52
Soft drinks (gallons)
123
150
Sugars (pounds)
Source: U.S. Department of Agriculture, Hope Health Letter, April 1999
135
2
34
More people are:
What assumption can be made about the eating habits over the years?
6
63
15
320
4
67
O
A. becoming vegetarians
OB. eating more beef than chicken
OC. consuming whole milk dairy products
D. trying to eat healthier foods
E. eliminating soft drinks from their diets
Answer:
D. trying to eat healthier foods
Explanation:
A basketball player throws a ball horizontally toward another player 10 meters away. If the ball is
traveling at a speed of 20 m/s, neglecting air friction, how long does it take for the ball to get to the
other player?
Thank you!!!
Answer:
It will take 0.46 seconds to reach home plate by ball.
Explanation:
a question was asked by a teacher to a student. She gave the student a jumbled word and told him to make words out of it. The jumbled word is gzeysktqix. Now you know what to do. see ya!
When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.
When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.
This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.
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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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A physics book slides off a horizontal tabletop with a speed
of 1.10 m/s. It strikes the floor in 0.480 s. Ignore air resistance.
What is the height of the tabletop above the floor in meters.
A physics book slides off a horizontal tabletop with a speed of 1.10 m/s. It strikes the floor in 0.480 s. The height of the tabletop above the floor is 0.264 m.
Given data:
Speed = 1.10 m/s
Time taken to strike the floor = 0.480 s
We are supposed to find the height of the tabletop above the floor in meters.
We can use the formula of distance to calculate the height of the tabletop above the floor.
We also need to make use of kinematic equations to find out the distance fallen by the book.
Let us first calculate the distance fallen by the book.
Let the height of the table be ‘h’.
From the kinematic equations of motion, we know thats = ut + 1/2 at²Here, u = 1.10 m/s, a = acceleration due to gravity = 9.8 m/s², t = 0.480 s
Putting these values in the above equation, we get:s = 1.10 × 0.480 + 1/2 × 9.8 × (0.480)² = 0.264 m
Now, we can find the height of the tabletop using the formula of distance.d = h + sHere, d = distance fallen by the book = h, s = 0.264 m
Putting these values in the above equation, we get: h = d = s = 0.264 m
Therefore, the height of the tabletop above the floor is 0.264 m.
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A mass is oscillating on a frictionless surface at the end of a horizontal spring. Where, if anywhere, is the acceleration of the mass zero.a. At x = -Ab. At x = 0c. At x = +Ad. at both x = -A and x = +Ae. nowhere
If mass is oscillating on a frictionless surface at the end of a horizontal spring, then option B states that the acceleration of the mass is zero at x=0 everywhere.
What is acceleration?The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration. The rate at which velocity changes is called acceleration. Acceleration typically indicates a change in speed, but not always. An object that follows a circular path while maintaining a constant speed is still moving forward because the direction of its velocity is shifting. A point or object moving straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is constantly shifting.
Here,
When mass is oscillating on a frictionless surface at the end of a horizontal spring, the acceleration of the mass is zero at x=0, which is option B.
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A thin rod extends from
x = 0
to
x = 15.0 cm.
It has a cross-sectional area
A = 8.00 cm2,
and its density increases uniformly in the positive x-direction from 2.50 g/cm3 at one endpoint to 19.5 g/cm3 at the other.
(a)
The density as a function of distance for the rod is given by
= B + Cx,
where B and C are constants. What are the values of B (in g/cm3) and C (in g/cm4)?
B =
g/cm3
C =
g/cm4
(b)
Finding the total mass of the rod requires integrating the density function over the entire length of the rod. The integral is written as follows.
m =
allmaterial
dv =
all x
A dx =
15.0 cm
0
(B + Cx)(8.00 cm2) dx
What is the total mass of the rod (in kg)?
kg
(a) For the density function, the value of B is 2.5 g/cm³ and the value of C is 1.3 g/cm⁴
(b) The total mass of the rod is 1470 g.
What is the density function?The density of the rod is a function of distance and it is given as;
ρ = B + Cx
where;
B and C are constantsρ = 2.5 g/cm³ + (19.5 g/cm³ ) / ( 15 cm ) x
ρ = 2.5 g/cm³ + 1.3 g/cm⁴ x
The total mass of the rod is calculated by integrating the function;
dm = ( B + Cx)(8 cm² ) dx
m = 8B + 8Cx
m = 8Bx + 8Cx² / 2
m = ( 8 x 2.5 x 15 ) + ( 8 x 1.3 x 15² ) / 2
m = 1470 g
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A record has an angular speed of
38.9 rev/min.
What is its angular speed?
Answer in units of rad/s.
pt 2
Through what angle does it rotate in 1.9 s?
Answer in units of rad
The record will rotate through an angle of 1.24°.
Angular speed of the record, ω = 38.9 rev/min = 0.65 rev/s
Time taken for the rotation, t = 1.9 s
Motion in a circular path or around the circumference of a circle is referred to as circular motion. It may rotate at a particular speed and angular rate or it may rotate at a variable rate, making it either uniform or non-uniform circular motion.
The angular speed is the rate of change of angular displacement.
Therefore, angular displacement of the record,
θ = ωt
θ = 0.65 x 1.9
θ = 1.24°
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A pan of water is sitting on an electie over the stove is then turned on to high What will happen to the movement of the particles in the pan?
The particles that make up the pan will move closer together
The parties that make up the pan will not be affected
The particles that make up the pan will speed up
The partides that make up the pan will slow down
Answer:
The particles that make up the pan will speed up
Explanation:
A mole of a monatomic ideal gas at point 1 (101 kPa, 5 L) is expanded adiabatically until the volume is doubled at point 2. Then it is cooled isochorically until the pressure is 20 kPa at point 3. The gas is now compressed isothermally until its volume is back to 5 L (point 4). Finally, the gas is heated isochorically to return to point 1.
a. Draw the four processes and label the points in the pV plane.
b. Calculate the work done going from 1 to 2.
c. Calculate the pressure and temperature at point 2.
d. Calculate the temperature at point 3.
e. Calculate the temperature and pressure and point 4.
f. Calculate the work done going from from 3 to 4.
g. Calculate the heat flow into the gas going from 3 to 4. g
Answer:
(a). Check attachment.
(b). 280.305 J.
(c). 31.81 kpa; 38.26K.
(d). 24.05K.
(e). 24.05k; 40kpa.
(f). -138.6J.
Explanation:
(a). Kindly check the attached picture for the diagram showing the four process.
1 - 2 = adiabatic expansion process.
2 - 3 = Isochoric process.
3 - 4 = isothermal process.
4 - 1 = isochoric process.
(b). Recall that the process from 1 to is an adiabatic expansion process.
NB: b = 5/3 for a monoatomic gas.
Then, the workdone = (1/ 1 - 1.66) [ (p1 × v1^b)/ v2^b × v2 - (p1 × v1)].
= ( 1/ 1 - 5/3) [ (101 × 5^5/3) × 10^1 -5/3] - 101 × 5.
Thus, the workdone = 280.305 J.
(c). P2 = P1 × V1^b/ V2^b = 101 × 5^5/3/ 10^5/3 = 31.81 kpa.
T2 = P2 × V2/ R × 1 = 31.81 × 10/ 8.324 = 38.36k.
(d). The process 2 - 3 is an Isochoric process, then;
T3 = T2/P2 × P3 = 38.26/ 31.82 × 20 = 24.05K.
(e). The process 3 - 4 Is an isothermal process. Then, the temperature at 4 will be the same temperature at 3. Tus, we have the temperature; point 3 = point 4 = 24.05k.
The pressure can be determine as below;
P4 = P3 × V3/ V4 = 20 × 10/ 5 = 200/ 5 = 40 kpa.
(f) workdone = xRT ln( v4/v3) = 1 × 8.314 × 24.05 × ln (5/10) = - 138.6 J
What must you know about a nuclear reaction to calculate the amount of
energy it will produce?
OA. The sum of the total nuclear mass before and after the reaction
OB. The difference between the total nuclear mass before and after
the reaction
OC. The ratio of total nuclear mass before the reaction to the total
nuclear mass after the reaction
D. The product of the total nuclear mass before and after the
reaction
B. The difference between total nuclear mass before and after the reaction.
This is because you can see how much nuclear matter had actually been used in the reaction by finding the difference between the initial mass and final mass.
Given the two displacement
D=(6i +3j -k )
E=(4i - 5j +8k)
Find the magnitude of displacement 2D -E
The approximate value of the magnitude of the displacement vector 2D - E is roughly 16.88.
How to find the magnitude of the displacementIn order to find out the magnitude of the displacement vector 2D - E, you can use these steps:
multiplying D by 2. this would result to
12i + 6j - 2k
subtracting E from 2D. this would result to
8i + 11j - 10k
The calculation of Step three entails computing the magnitude of 2D - E where |V| = sqrt(Vi^2 + Vj^2 + Vk^2)
|2D - E| = sqrt((8^2) + (11^2) + (-10^2))
|2D - E| = sqrt(64 + 121 + 100)
|2D - E| = sqrt(285),
|2D - E| = 16.88 when rounded off to two decimal places.
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A 2 paragraph summary about the foundations of government
The foundations of government can be traced back to ancient civilizations, such as Mesopotamia, Egypt, Greece, and Rome.
What civilizations developed government?These civilizations developed forms of government that reflected their social, cultural, and economic structures. For example, in ancient Egypt, the pharaoh was considered a divine ruler, who had absolute power over his subjects. In Greece, the city-state of Athens developed a direct democracy, where citizens participated directly in the decision-making process. In Rome, the republic was established, which was based on the principles of representation and separation of powers.
In modern times, the foundations of government have been shaped by a variety of political theories and ideologies. One of the most influential political theorists was Thomas Hobbes, who argued that a strong central government was necessary to maintain social order and prevent chaos. Another influential political philosopher was John Locke, who believed that government should be based on the consent of the governed and that individuals had natural rights that should be protected by the state. Other political theories, such as socialism, communism, and fascism, have also influenced the development of government systems around the world.
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Position c
Position B
Position D
Position A
Position E
Position
Kinetic Energy
Potential Energy
A
B
С
D
Answer:
B porque tiene energía n..
Given the information in the velocity vs. time graph, what is the displacement of the object after 1 second?
_____ m
After 3 seconds?
_____ m
After 5 seconds?
_____ m
Thank you!!!
The displacement of the object after 1 second, is 3 m.
The displacement of the object after 3 seconds, is 9 m.
The displacement of the object after 5 seconds, is 15 m.
What is displacement?The displacement of an object is the change in the position of the object.
displacement of the object after 1 secondThe displacement of the object after 1 second, x = 3 m/s x 1 second = 3 m
displacement of the object after 3 secondThe displacement of the object after 1 second, x = 3 m/s x 3 s = 9 m
displacement of the object after 5 secondThe displacement of the object after 1 second, x = 3 m/s x 5 s = 15 m
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Two argon atoms form the molecule Ar2 as a result of a van der Waals interaction with U0 = 1.68×10-21 J and R0= 3.82×10 the frequency of small oscillations of one Ar atom about its equilibrium position.
Answer:
\(\mathbf{f_o =1.87 \times 10^{11} \ Hz}\)
Explanation:
From the given information:
The elastic potential energy can be calculated by using the formula:
\(U_o = \dfrac{1}{2}kR_o^2\)
Making K the subject;
\(K = \dfrac{2 U_o}{R_o^2}\)
\(k = \dfrac{2\times 1.68 \times 10^{-21}}{(3.82\times 10^{-10})^2}\)
k = 2.3 × 10⁻² N/m
Now; the frequency of the small oscillation can be determined by using the formula:
\(f_o = \dfrac{1}{2 \pi}\sqrt{\dfrac{k}{m}}\)
where;
m = mass of each atom = 1.66 × 10⁻²⁶ kg
\(f_o = \dfrac{1}{2 \pi}\sqrt{\dfrac{2.3 \times 10^{-2} N/m}{1.66 \times 10^{-26} \ kg}}\)
\(\mathbf{f_o =1.87 \times 10^{11} \ Hz}\)
A 200 g hockey puck is launched up a metal ramp that is inclined at a 30° angle. The coefficients of static and kinetic friction between the hockey puck and the metal ramp are μs = 0.40 and μk = 0.30, respectively. The puck's initial speed is 3.8 m/s. What speed does it have when it slides back down to its starting point?
A 200 g hockey puck is launched up a metal ramp that is inclined at a 30° angle. The coefficients of static and kinetic friction between the hockey puck and the metal ramp are μs = 0.40 and μk = 0.30, respectively. The puck's initial speed is 3.8 m/s, Speed it will have when it slides back down to its starting point is 2.36 m/s
What is Friction?The resistance to motion of one object moving in relation to another is known as friction. It is not regarded as a fundamental force like gravity or electromagnetic, according to the International Journal of Parallel, Emergent and Distributed Systems(opens in new tab). The electromagnetic attraction between charged particles in two contacting surfaces, according to scientists, is what causes it.
using work energy theorem ,
change in kinetic energy = work done by frictional force
\(\frac{1}{2}\) m(\(x^{2}\)-\(y^{2}\)) = μmghcos30°
where mass is m=200g
x is speed with which it slides back
y is speed at top of metal ramp=3.8 m/s
μ is coefficient of kinetic friction=0.3
g is gravity = 9.8m/\(s^{2}\)
h is height to which hockey puck is reached on metal ramp=1.18m
Substituting the values and solving for speed x,
x=2.36m/s
speed it will have when it slides back down to its starting point is 2.36m/s
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Type of tissue that helps with movement.Immersive Reader
a. Epithelial
b.Muscle
c.Connective
d.Nervous
Find the magnitude and direction of the resultant velocity vector for the following perpendicular velocities:
a. a surfer traveling at 1.5 m/s relative to the water across a wave that is traveling at 5.5 m/s.
b. a fish swimming at 2.5 m/s relative to the water across a river that moves at 4.5 m/s.
a) Resultant velocity is 15.63 m/s.
b) Resultant velocity is 12.97m/s.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
a) A surfer traveling at 1.5 m/s relative to the water across a wave that is traveling at 5.5 m/s.
Resultant velocity = √(1.5²+5.5²) m/s = 15.63 m/s.
b) A fish swimming at 2.5 m/s relative to the water across a river that moves at 4.5 m/s.
Resultant velocity = √(2.5²+4.5²) m/s = 12.97m/s.
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