-3 7/9 + (-2 1/3)

awnser 1: -6 1/9

awnser 2: -8 1/9

which anwser please help

Answer:

-½ + (root2 / 2) i + root½ i

Step-by-step explanation:

\( \frac{a}{b} - \frac{c}{d} = \frac{ad - cb}{bd} \)

I used this formula to do it but let me know if it's enough or you have to simplify it further

Answer:

45

Step-by-step explanation:

To accumulate $100,000 over 20 years at a 10% annual interest rate compound annually, you would need to make annual payments of $8,218.64.

You can use the formula for the future value of an annuity to accumulate $100,000 over 20 years at a 10% annual interest rate compound on a yearly basis:

\(FV = Pmt * [(1 + r)^n - 1] / r\)

Where:

FV is future value, which is $100,000 in that case

Pmt: annual payment

r: annual interest rate, which is 10%

n: number of payment periods, which is 20

By plugging in values:

\($100,000 = Pmt * [(1 + 0.1)^(20) - 1] / 0.1\)

Solving for Pmt, we get:

\(Pmt = $100,000 / [(1 + 0.1)^(20) - 1] / 0.1\\Pmt = $100,000 / 12.167\\Pmt = $8,218.64\)

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Answer:

I'm pretty sure it's

14x + 12.50y = 500

Recall that like terms are terms that have the same variables and powers. The coefficients of the terms do not have to match.

a.- Notice that 4z and -3z are like terms since they have the same variables with the same exponents, therefore:

b.- Notice that 3n and -3n are like terms, but 6 is a constant, therefore:

c.- In the given expression, the similar terms are 2g and -8g, and -3 and 11, therefore:

d.- In the last expression, first, we have to apply the distributive property:

Now, adding like terms we get:

Answer:

a.-

b.-

c.-

d.-

Answer:

A

Step-by-step explanation:

Proofs attached to answer

Answer:

A

Step-by-step explanation:

There is no way to tell a pattern.

The probability that he rolls a 4 and flips a head is 1/12

Probability determines odds that a random event would happen. The odds of the random event happening lie between 0 and 1.

The probability that he rolls a 4 and flips a head = (number of sides that is a 4 / total number of sides) x (number of sides that is a head / total number of sides)

(1/6) x (1/2) = 1/12

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Answer: 1/12

Step-by-step explanation:

just say the answer

Answer:

C

Step-by-step explanation:

Multiply by 12 on both sides.

Start with step one

y/3 - 1/4 = 5              Multiply both sides by 12

12(y/3 - 1/4) = 5*12

12*y/3 - 12 * 1/4 = 60

3 goes into 12 four times

4 goes into 12 three times. In both cases you are cancelling.

4y - 3 = 60

To use the splitpts function in Matlab, you will first need to define two sets of points with different arrays for each set. Then, you can use the syntax newSetOfPoints = splitpts(originalSetOfPoints) to split the original set of points into two new sets.

The "splitpts" function in MATLAB is used to split a set of points into two sets based on a specified split point. Here are the steps to use this function:

1. Define the set of points you want to split. For example:
```
points = [1 2 3 4 5 6 7 8 9 10];
```

2. Specify the split point. This can be any number between the minimum and maximum values of the set of points. For example:
```
splitPoint = 5;
```

3. Use the "splitpts" function to split the set of points into two sets. The first set will contain all the points less than or equal to the split point, and the second set will contain all the points greater than the split point. For example:
```
[set1, set2] = splitpts(points, splitPoint);
```

4. The resulting sets will be stored in the variables "set1" and "set2". You can display these sets using the "disp" function:
```
disp(set1);
disp(set2);
```

The output will be:
```
1 2 3 4 5
6 7 8 9 10
```

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Answer:

1±i sqrt(7/2)

Step-by-step explanation:

For this equation you would need to use quadratic formula: x=(-b+-square root b^2-4ac)/2a

Answer:the answer is option E (see pic)

Step-by-step explanation:

One root would be: x =(4-√88)/-4=1+1/2√ 22 = 1.345

Answer:

A. True

B. False

C. True

D. False

E. True

The mixed fraction equations which are true are C , D and E

A mixed number is a whole number, and a proper fraction represented together. A mixed number is formed by combining three parts: a whole number, a numerator, and a denominator. The numerator and denominator are part of the proper fraction that makes the mixed number.

Given data ,

Let the mixed number equation be represented as A

Now , the value of A is

To solve each equation, we can convert mixed numbers to improper fractions, then multiply the fractions, and simplify the result if possible.

A)

A = 5/6 × 4 2/3 = (5/6) × (4×3 + 2)/3

A = (5/6) × 14/3 = 35/9, which is not equal to 3 8/9.

Therefore, equation A is false.

B)

B = 1 1/10 × 8 3/5 = (11/10) × (43/5)

B = 473/50 = 9 23/50, which is not equal to 9 1/2.

Therefore, equation B is false.

C)

C = 3 2/9 × 2 1/6 = (29/9) × (13/6)

C = 377/54 = 6 53/54

Therefore, equation C is true.

D)

D = 2 3/7 × 1 7/8 = (17/7) × (15/8)

D = 255/56 = 4 23/56 = 2 3/8

Therefore, equation D is true.

E)

E = 7/12 × 4 = 7/3 = 2 1/3

Therefore, equation E is true.

Hence , the equations that are true are C, D, and E

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Answer:

Thank youuu !

Step-by-step explanation:

Answer:

Thank you

Step-by-step explanation:

The partial order | on the set {1, 2, 3, ..., 10} does not have an antichain of size 6.

To prove that the partial order | on the set {1, 2, 3, ..., 10} does not have an antichain of size 6, we can use a proof by contradiction.

Assume, for the sake of contradiction, that there exists an antichain A of size 6 in the partial order | on the set {1, 2, 3, ..., 10}. An antichain is a subset of elements in a partially ordered set where no two elements are comparable.

Since A is an antichain, for any two elements a, b ∈ A, neither a | b nor b | a. This means that any two elements in A are not comparable.

Now, let's analyze the size of A and the maximum number of elements that can be in an antichain of a partial order on a set of size n.

In a partial order, the maximum number of elements in an antichain is given by the length of the longest chain (a totally ordered subset) in the partial order. Let's find the length of the longest chain in the partial order | on the set {1, 2, 3, ..., 10}.

The longest chain in this case is a chain with all the elements in increasing order: 1 < 2 < 3 < ... < 10. This chain has a length of 10.

According to the theorem, Dilworth's theorem, which we are not using here, the maximum size of an antichain in a partial order is equal to the minimum number of chains in a chain decomposition of the partial order. In this case, the maximum size of an antichain would be equal to the minimum number of chains needed to cover all the elements of the partial order.

Since the length of the longest chain is 10, the minimum number of chains required to cover all the elements is also 10.

However, we assumed that there exists an antichain A of size 6. This contradicts the fact that the minimum number of chains needed to cover all the elements is 10.

Therefore, our initial assumption that there exists an antichain of size 6 is false.

Hence, the partial order | on the set {1, 2, 3, ..., 10} does not have an antichain of size 6.

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Answer:

To find the total length of the two sides, we simply add them together:

Total length = Side 1 + Side 2

Total length = (8x^2 - 5x - 2) + (7x - x^2 + 3)

Total length = -x^2 + 8x^2 - 5x + 7x - 2 + 3

Total length = 7x^2 + 2x + 1

Therefore, the total length of the two sides of the triangle is 7x^2 + 2x + 1.

Step-by-step explanation:

To find the length of the third side of the triangle, we need to use the formula for the perimeter of a triangle:

Perimeter = Side 1 + Side 2 + Side 3

We are given the perimeter of the triangle as 4x^3 - 3x^2 + 2x - 6 and we know the lengths of Side 1 and Side 2. Therefore, we can rewrite the formula as:

4x^3 - 3x^2 + 2x - 6 = (8x^2 - 5x - 2) + (7x - x^2 + 3) + Side 3

Simplifying the right-hand side:

4x^3 - 3x^2 + 2x - 6 = 7x^2 + 2x + 1 + Side 3

Side 3 = 4x^3 - 3x^2 + 2x - 6 - 7x^2 - 2x - 1

Simplifying further:

Side 3 = 4x^3 - 7x^2 - x - 7

Therefore, the length of the third side of the triangle is 4x^3 - 7x^2 - x - 7.

Yes, the answers for Part A and Part B show that the polynomials are closed under addition and subtraction.

Closure under addition means that when two polynomials are added, the result is also a polynomial. In Part A, we added the two polynomials 8x^2 - 5x - 2 and 7x - x^2 + 3 to get the total length of the two sides of the triangle, which is 7x^2 + 2x + 1. Since the total length is also a polynomial, this shows that the polynomials are closed under addition.

Closure under subtraction means that when one polynomial is subtracted from another polynomial, the result is also a polynomial. In Part B, we subtracted the two polynomials 8x^2 - 5x - 2 and 7x - x^2 + 3 from the given perimeter of the triangle, 4x^3 - 3x^2 + 2x - 6, to get the length of the third side of the triangle, which is 4x^3 - 7x^2 - x - 7. Since the length of the third side is also a polynomial, this shows that the polynomials are closed under subtraction.

Therefore, the answers for Part A and Part B demonstrate that the polynomials are closed under addition and subtraction.

Answer:

2(4)-3+5

Step-by-step explanation:

8-3+5

13-3

10

Answer:

i would say a

Step-by-step explanation:

Answer:

6 meters

Step-by-step explanation:

\(A=a^2+2a\sqrt{\frac{a^2}{4}+h^2} \)is the formula that you use

h=vertical altitude and

a=side length of the base

\(85=5^2+(2*5)\sqrt{\frac{25}{4}+h^2}\)

\(85-25=10\sqrt{\frac{25}{4}+h^2}\)

\(\frac{60}{10}=\sqrt{\frac{25}{4}+h^2}\)

\(6=\sqrt{\frac{25}{4}+h^2}\)

\(36=\frac{25}{4}+h^2\)

\(36-\frac{25}{4}=h^2\)

\(36-6.25=h^2\)

\(29.75=h^2\)

Vertical altitude (h) and \(\frac{1}{2}a\) and the slant height form a right triangle with the slant height being the hypotenuse

\(h^2+(2.5)^2=s^2 \)where s=slant height

\(29.75+6.25=s^2\)

\(36=s^2\)

s=6 meters

Answer:

slant height = 6 meters

Step-by-step explanation:

surface area of pyramid: 2bs + b²

2*5*s + 5² = 85

10s = 85 - 25

10s = 60

s = 6

The slant height is 6 meters.

If a rancher has 720 feet of fencing with which to enclose two adjacent rectangular corrals, the dimensions are 90 feet and 120 feet

From the figure

4x + 3y = 720

3y = 720 - 4x

y = 240 - (4/3)x

The area = l × w

Where l is the length

w is the width

Substitute the values in the equation

A = 2x × y

= 2x (240 - (4/3)x)

Apply the distributive property

= 480x - (8/3)x^2

Differentiate the values

0 = (-16/3)x + 480

(16/3) x = 480

x = 480 / (16/3)

x = 90 feet

Then,

y = 240 - (4/3)(90)

= 120 feet

Hence, the dimensions are 90 feet and 120 feet

I have answered the question is general, as the given question is incomplete.

The complete question is

A rancher has 720 feet of fencing with which to enclose two adjacent rectangular corrals (see figure). what dimensions should be used so that the enclosed area will be a maximum?

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Answer:v = y(1-n)dv/dx = (1-n)y-n dy/dxso dy

Step-by-step explanation:

The ways that the exercise can be expressed such that for every 6 squares there are 3 circles include:

This question is asked in Spanish on an English site so the answer will be provided in English for better learning by other students.

The ratio of squares to circles is 6:3 or simplified, 2:1. This means for every 2 squares, there is 1 circle.

You could also use a proportional statement such that the number of squares is twice the number of circles. For every 6 squares, there are 3 circles.

There is also equation form where we can say, if S is the number of squares and C is the number of circles, the relationship could be expressed as S = 2C. This means the number of squares is twice the number of circles.

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The translated question is:

How to express this exercise for every 6 squares there are 3 circles.

Answer:

\( \sin(120) \\ = \sin(90 + 30) \\ = \cos(30) \\ = \frac{ \sqrt{3} }{2} \\ \\ \tan( \frac{3\pi}{4} ) \\ = \tan(135) \\ = \tan(90 + 45) \\ = - \cot(45) \\ = - 1\)

\(\\ \rm\longmapsto sin120\)

\(\\ \rm\longmapsto sin(90+30)\)

\(\\ \rm\longmapsto cos30\)

\(\\ \rm\longmapsto \dfrac{\sqrt{3}}{2}\)

Now

\(\\ \rm\longmapsto tan\left(\dfrac{2\pi}{4}\right)\)

\(\\ \rm\longmapsto tan135\)

\(\\ \rm\longmapsto -1\)

Answer:

b

Step-by-step explanation:

what grade?

In method (1), the answer is expressed as -cot(x) + C, while in method (2), the answer is expressed as -csc(x) + C.

To evaluate the integral ∫(csc²x)cot(x)dx using the two suggested methods, let's go through each approach step by step.

Method 1: Let u = cot(x)

To use this substitution, we need to express everything in terms of u and find du.

Start with the given integral: ∫(csc²x)cot(x)dx

Let u = cot(x). This implies du = -csc²(x)dx. Rearranging, we have dx = -du/csc²(x).

Substitute these expressions into the integral:

∫(csc²x)cot(x)dx = ∫(csc²x)(-du/csc²(x)) = -∫du

The integral -∫du is simply -u + C, where C is the constant of integration.

Substitute the original variable back in: -u + C = -cot(x) + C. This is the final answer using the first substitution method.

Method 2: Let u = csc(x)

Start with the given integral: ∫(csc²x)cot(x)dx

Let u = csc(x). This implies du = -csc(x)cot(x)dx. Rearranging, we have dx = -du/(csc(x)cot(x)).

Substitute these expressions into the integral:

∫(csc²x)cot(x)dx = ∫(csc²(x))(cot(x))(-du/(csc(x)cot(x))) = -∫du

The integral -∫du is simply -u + C, where C is the constant of integration.

Substitute the original variable back in: -u + C = -csc(x) + C. This is the final answer using the second substitution method.

Difference in appearance of the answers:

Upon comparing the answers obtained in (1) and (2), we can observe a difference in appearance. In method (1), the answer is expressed as -cot(x) + C, while in method (2), the answer is expressed as -csc(x) + C.

The difference arises due to the choice of the substitution variable. In method (1), we substitute u = cot(x), which leads to an expression involving cot(x) in the final answer. On the other hand, in method (2), we substitute u = csc(x), resulting in an expression involving csc(x) in the final answer.

This discrepancy occurs because the trigonometric functions cotangent and cosecant have reciprocal relationships. The choice of substitution variable influences the form of the final result, with one method giving an expression involving cotangent and the other involving cosecant. However, both answers are equivalent and differ only in their algebraic form.

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Answer:

Step-by-step explanation:

The phase of the systems life cycle during which users are trained to use the new system is called the implementation phase. In this phase, the new system is installed and made operational, and users are trained on how to use it effectively. This phase typically follows the design and development phases and precedes the maintenance phase.

What is the main focus of the implementation phase in the systems life cycle?

The main focus of the implementation phase is training users to use the new system effectively. This includes installing the system and making it operational, as well as providing necessary support and training to ensure users are able to utilize the system efficiently.

The phase of the systems life cycle during which users are trained to use the new system is the implementation phase. This is the phase where the new system is actually implemented and made available for use by the users. It is important to provide training to users during this phase so that they are able to effectively use the new system and understand its functionality.

Therefore, users are trained to use the new system during the implementation phase.

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The implementation phase of the systems life cycle is the time when users are taught how to utilize the new system.

The new system is installed, made operational, and users are instructed on how to utilize it efficiently during the implementation phase. In most cases, this phase comes after the design and development phases and comes before the maintenance period.

Why is user training important during the implementation phase of the systems life cycle?

User training is important during the implementation phase of the systems life cycle because it ensures that users are able to effectively use the new system and understand how it works. This is essential for the successful adoption and utilization of the system by the organization. Without proper training, users may struggle to use the system effectively, leading to reduced productivity and potentially even causing issues with data accuracy and integrity. By providing thorough user training, organizations can ensure that their employees are able to use the new system efficiently and effectively, leading to a successful implementation.

The implementation phase of the systems life cycle is the time when users are taught how to utilise the new system. In this stage, the new system is really put into use and made accessible to users. During this stage, it's crucial to give users training so they can utilize the new system correctly and comprehend its functions.

Therefore, during the implementation phase, users are instructed on how to utilize the new system.

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Step-by-step explanation:

Remove the parentheses: = ff x 2

Apply exponent rule: f^1+^1x2

Add the numbers 1+1=2 = 2f^2

I hope this is right.

Answer:

Step-by-step explanation:

(a) To find the probability that it is raining when you arrive in Oneirabad on a random day, we need to use the law of total probability.

Let A be the event that it is raining, and B be the event that it is the Wet season.

P(A) = P(A|B)P(B) + P(A|B')P(B')

Given that the Wet season lasts for 1/3 of the year, we have P(B) = 1/3. The probability that it is raining during the Wet season is 3/4, so P(A|B) = 3/4.

The Dry season lasts for 2/3 of the year, so P(B') = 2/3. The probability that it is raining during the Dry season is 1/6, so P(A|B') = 1/6.

Now we can calculate the probability that it is raining when you arrive:

P(A) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it is raining when you arrive in Oneirabad on a random day is 13/36.

(b) Given that it is raining when you arrive, we can use Bayes' theorem to calculate the probability that your visit is during the Wet season.

Let C be the event that your visit is during the Wet season.

P(C|A) = (P(A|C)P(C)) / P(A)

We already know that P(A) = 13/36. The probability that it is raining during the Wet season is 3/4, so P(A|C) = 3/4. The Wet season lasts for 1/3 of the year, so P(C) = 1/3.

Now we can calculate the probability that your visit is during the Wet season:

P(C|A) = (3/4)(1/3) / (13/36)

= 1/4 / (13/36)

= 9/52

Therefore, given that it is raining when you arrive, the probability that your visit is during the Wet season is 9/52.

(c) Given that it is raining when you arrive, the probability that it will be raining when you return to Oneirabad in a year's time depends on the season. If you arrived during the Wet season, the probability of rain will be different from if you arrived during the Dry season.

Let D be the event that it is raining when you return.

If you arrived during the Wet season, the probability of rain when you return is the same as the probability of rain during the Wet season, which is 3/4.

If you arrived during the Dry season, the probability of rain when you return is the same as the probability of rain during the Dry season, which is 1/6.

Since the season you arrived in is independent of the weather when you return, we need to consider the probabilities based on the season you arrived.

Let C' be the event that your visit is during the Dry season.

P(D) = P(D|C)P(C) + P(D|C')P(C')

Since P(C) = 1/3 and P(C') = 2/3, we can calculate:

P(D) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it will be raining when you return to Oneirabad in a year's time, given that it is raining when you arrive, is 13/36.

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The alternating series test is a technique for demonstrating convergence of an alternating series when its terms (1) become smaller in absolute value and (2) get closer to zero in the limit.

The Leibniz test, often referred to as the alternating series test, is a form of series test used to ascertain whether two alternate series are converging. Remember that the test cannot determine whether the series diverges. There are three conditions that must be met for the Alternating Series Test: The series needs to switch up. For large n, the words must become less significant. The nth term must equal zero. The second prerequisite appears superfluous. Another test must be used to demonstrate that a series diverges. The ideal plan is to use the Divergence Test to check for divergence in an alternating series first. You've reached your conclusion if the terms do not converge to zero.

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We have shown that h = 40 / √(\(tan^{2}\)70°+ \(tan^{2}\) 55° + 1.1472 tan 70° tan 55°).

What is trigonometry?

The relatiοnship between the sides and angles οf triangles is the subject οf the branch οf mathematics knοwn as trigοnοmetry.

A. Here is the diagram that represents the situatiοn:

           T (top of tower)

            /\

           /  \

          /    \

         /      \

        /        \

       P         Q

P is due sοuth οf the tοwer.

Q is 40 meters east οf the tοwer.

The angle οf elevatiοn frοm P tο the tοp οf the tοwer is 20 degrees.

The angle οf elevatiοn frοm Q tο the tοp οf the tοwer is 35 degrees.

B. Let's use trigοnοmetry tο sοlve fοr h.

Frοm triangle PTQ, we knοw that:

PT = h / tan 20° (using οppοsite οver adjacent)

TQ = h / tan 35° (using οppοsite οver adjacent)

PQ = 40 meters (given)

Frοm triangle PTQ, we can alsο use the Law οf Cοsines:

\(PQ^{2}\)= \(PT^{2}\) + \(TQ^{2}\) - 2 PT TQ cos 125° (using \(a^{2}\) = \(b^{2}\) + \(c^{2}\) - 2bc cos A)

Substituting the values we know:

\((40)^{2}\) =\((h/tan 20)^{2}\) + \(h/tan^{2}\)20° - 2 (h/tan 20°(h/tan 35°) cos 125°

Simplifying the equation, we get:

\((40)^{2}\) = \(h^{2}\) (\(1/tan^{2}\) 20° + 1/tan² 35° - 2/tan 20° tan 35° cos 125°)

\((40)^{2}\) = \(h^{2}\) (\(tan^{2}\) 70° + tan² 55° - 2 tan 70° tan 55° (-0.5736))

\((40)^{2}\) = \(h^{2}\) (\(tan^{2}\) 70° + tan² 55° + 1.1472 tan 70° tan 55°)

\(h^{2}\) = \((40)^{2}\) / (\(tan^{2}\) 70° + tan² 55° + 1.1472 tan 70° tan 55°)

h = sqrt[\((40)^{2}\) / (\(tan^{2}\) 70° + tan² 55° + 1.1472 tan 70° tan 55°)]

h = 40 / sqrt(\(tan^{2}\) 70° + \(tan^{2}\) 55° + 1.1472 tan 70° tan 55°)

Therefore, we have shown that h = 40 / √(\(tan^{2}\) 70°+ \(tan^{2}\) 55° + 1.1472 tan 70° tan 55°).

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