3. Complete the following sentences:

a. "The slope of a linear position graph tells us the _________________________ of the object."


b. "The slope of a linear velocity graph tells us the Acceleration of the object."


c. "For an object moving at a constant speed, we would expect to see a position graph with a ___________________ shape and a velocity graph with a ___________________ shape."


d. "For an object moving at a constant acceleration, we would expect to see a position graph with a ___________________ shape and a velocity graph with a ___________________ shape."

The only force opposing the block's sliding as it slows down is friction with magnitude f . By Newton's second law, the net force in this direction is

∑ F = -f = ma = (4.00 kg) a

Assuming constant acceleration a , the acceleration applied by friction is such that

(1.5 m/s)² - (11 m/s)² = 2a (4.00 m)

Solve for the acceleration :

a = ((1.5 m/s)² - (11 m/s)²) / (8.00 m) ≈ -14.8 m/s²

Then the frictional force exerted a magnitude of

-f = (4.00 kg) (-14.8 m/s²)

f ≈ 59.4 N

and was directed opposite the block's motion.

Answer:

\(T=25166.4Nm\)

Explanation:

From the question we are told that:

Mass of beam \(m_b=510kg\)

Length \(l=8m\)

Mass of Worker \(M_w=66kg\)

Given the Weight acting on the Beam

Generally the equation for net torque on the beam is mathematically given by

\(T=\frac{l}{2}m_bg+(lm_wg)\)

\(T=\frac{8}{2}*510*9.8+(8*66*9.8)\)

\(T=25166.4Nm\)

\(T=25.2kNm\)

The average velocity of the particle between t = 2.0 s and t = 4.0 s is 4 m/2.0 s = 2.0 m/s.

Average velocity is the rate of change of an object's position, expressed as a vector quantity that tells both the speed and direction of the object's motion.

The average velocity of the particle between t = 2.0 s and t = 4.0 s can be calculated by taking the difference in the x-position of the particle at t = 4.0 s and t = 2.0 s, and dividing it by the difference in the time.
The x-position of the particle at t = 2.0 s is 4 m and the x-position of the particle at t = 4.0 s is 8 m.
Therefore, the difference in the x-position is 8 m - 4 m = 4 m.
The difference in time is 4.0 s - 2.0 s = 2.0 s. Therefore, the average velocity of the particle between t = 2.0 s and t = 4.0 s is 4 m/2.0 s = 2.0 m/s.

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The degree of data stability when the measurement is replicated under identical circumstances is known as reproducibility or reliability.

Reproducibility determines how an entire study an experiment can be replicated, whereas repeatability assesses the variation in data made by a single equipment or human under similar circumstances.

Science needs reproducibility because it enables more in-depth investigation, and replication validates our findings. There are several investigations and experiments, which result in a wide range of variables, unforeseen, and things that are either outside your influence or you cannot guarantee.

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The size of the angle θ of a point object moving from point A to point B along a circular path is 2πR / L.

To understand this, consider a simple example. Suppose that a point object that moves from point A to point B along a circular path with a radius of 1 meter. The distance between points A and B is also 1 meter. Therefore, the size of the angle θ is equal to 2π × 1 / 1 = 2π radians.

In general, the size of the angle θ = ratio of the circumference of the circle to the distance between points A and B. The circumference of the circle is equal to 2πR, where R = radius of the circle. Therefore, the size of the angle θ is equal to 2πR / L.

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Complete question:

A point object moves from point A to point B along a circular path with a radius R. What is the size of the angle θ?

The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.

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Answer: Weight changes with surface gravity.So in Moon mass will be same as 26 gram mes.

Explanation:

Answer:

It is increasing .60 m/s

Explanation:

The force acting on the electron is 1.92 x 10^-17 N.

The problem states that an electron of charge 1.6 x 10^-19 is located in a uniform electric field of 120 Vm^-1, and it asks us to determine the force acting on it.

We can use Coulomb's law, which states that the force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. If the charges are of opposite signs, the force is attractive, while if the charges are of the same sign, the force is repulsive.

The formula for Coulomb's law is F = kq1q2/r^2, where F is the force between the charges, k is Coulomb's constant, q1 and q2 are the magnitudes of the charges, and r is the distance between them.

Since the electron has a charge of 1.6 x 10^-19 C, and the electric field strength is 120 Vm^-1, we can use the equation F = qE to find the force acting on it.

F = qE = (1.6 x 10^-19 C)(120 Vm^-1) = 1.92 x 10^-17 N.

Therefore, the force acting on the electron is 1.92 x 10^-17 N.

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Answer: x=14

Explanation:

there is 90° in a right angle so

(4x)+(2x+6) =90

collect like terms

6x+6=90

 -6 from both sides

6x=84

 ÷6

x=14

The graph below shows the motion of a person leaving theater, line segment C represent : The person is moving away from the theater.

In physics, motion is a change with time of the position or orientation of a body. Motion along a line or a curve is called as translation whereas motion that changes orientation of a body is called rotation.

Motion is a change in position of an object over the  time and is described in terms of displacement, distance, velocity, acceleration, time and speed.

Change in position of a body with time when compared with another body is known as  motion.

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Answer:

s = 0.337 m

Explanation:

First, we will find the angular displacement of the reel:

\(\theta = \omega t\)

where,

θ = angular displacement = ?

ω = angular speed = 1.9 rad/s

t = time taken = 7.1 s

Therefore,

θ = (1.9\ rad/s)(7.1 s)

θ = 13.5 rad

Now, we will find out the length of tape:

s = rθ

where,

s = length of tape = ?

r = radius of reel = 2.5 cm = 0.025 m

Therefore,

s = (0.025 m)(13.5 rad)

s = 0.337 m

Answer:

pretty sure its A

Explanation:

please give brainliest if i'm correct

Answer:

A.

Explanation:

I have done this and that was correct

hope this helps

Answer:

The value is  \(KE = 9 J\)

Explanation:

From the question we are told that

      The mass is  \(m = 0.5 \ kg\)

     The velocity is  \(v = 6 \ m/s\)

Generally the kinetic energy is mathematically represented as

        \(KE = \frac{ 1}{2} * m*v^2\)

=>     \(KE = \frac{ 1}{2} * 0.5*6^2\)

=>     \(KE = 9 J\)

If the amount of potential energy and kinetic energy added up to equal the total amount of energy used, it would show an equal transformation of energy.

This can be defined as the ability or capacity to do work. The potential and kinetic energy equals the total amount of energy involved when Lana was on the playground.

This depicts an equal transformation of energy which is why the most appropriate choice in this scenario is option A.

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The most significant change in the comet's energy as it moves from point D to point A KE increases, GPE decreases.Option C is correct.

Comets are frozen leftovers from the formation of the solar system composed of dust, rock, and ice.

They range from a few miles to tens of miles wide, but as they orbit closer to the Sun, they heat up and spew gases and dust into a glowing head that can be larger than a plane.

As the comet transitions from point D to point A, the biggest energy shift is seen. GPE declines as KE rises. The right answer is C.

Hence option C is correct.

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Both of them are in big trouble !  I personally would write up each one of them for => no current valid driver's license, => no current vehicle insurance, => no current vehicle emission inspection sticker, => no visible current vehicle, => failure to signal turns, and => speeding in a school zone, since 19.4 m/s is equivalent to 43.4 mph.  

Answer:

Describe how one-dimensional vector quantities are added or subtracted.

According to the question the tension in each wire is 1.96 N.

Tension is a term that describes the psychological and physical state of a person or system in which there is a high degree of stress, uncertainty, and anxiety. It is often associated with conflict and is often experienced when individuals or groups feel threatened or constrained in some way. Tension can be experienced in a variety of different contexts, from interpersonal relationships to the workplace. It can result from a variety of different factors, including a lack of communication, conflicting goals or expectations, and unmet needs.

The body is in equilibrium when the sum of all forces acting on it is equal to zero. In this case, the forces acting on the metal tube are the two wires and the weight of the tube due to gravity.

The tension in each wire is equal to the weight of the tube divided by the length of the tube. This is because the tube is suspended horizontally, so the forces in each wire must be equal in order to keep the tube in equilibrium.

Therefore, the tension in each wire is:

T = (9 kg × 9.8 m/s2) / (5 cm × 0.01 m)

= 1.96 N

Therefore, the tension in each wire is 1.96 N.

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Answer:

Explanation:

For fundamental frequency in a vibrating string , the formula is

n = 1 / 2L  x  √ ( T /m₁ )

n is frequency , L is length , T is tension and m₁ is mass per unit length .

For first string ,

293 =  1 / 2L  x  √ ( 49 N  /m₁ )

For second string , let mass per unit length be m₂ .

196 =  1 / 2L  x  √ ( 49 N  /m₂ ) ------ ( 1 )

To bring its frequency back to previous one let tension be T

293  =  1 / 2L  x  √ ( T  /m₂ ) ------- ( 2 )

Dividing

293 / 196 = √ ( T  /49  )

1.4948 = √ ( T  /49  )

2.2344 = T  /49

T = 109.48 N .

Answer:

From second newton's equation of motion:

\(S = ut + \frac{1}{2} a {t}^{2} \)

s » displacement or distance

u » initial speed, u = 0 ( at rest )

a » acceleration

t » time

\(s = (0 \times 10) + ( \frac{1}{2} \times 3 \times 10) \\ \\ s = 5 \times 3 \\ \\ { \underline{ \underline{ \: \: distance = 15 \: meters}}}\)

A car starting from rest accelerates uniformly at 3 m/s for 10 seconds. The car's final speed in  m/s after the acceleration is 30 m/s.

Given the following data to find the acceleration:

Initial velocity, U = 0 m/s (since the cars starts from rest)

Time, t = 10 seconds

Acceleration, a = 3 meter per seconds square.

Velocity is defined as the rate of change of object's position with some function of time.

Mathematically, Velocity can be defined by the ratio of distance and time.

Velocity = Distance/ time.

The velocity after a certain time of acceleration can be described with the formula as,

V = u + at

where, v is the final velocity,

u is the initial velocity,

a is the acceleration,

t is the time.

Substituting all the given values in the formula,

V = 0+ 3 (10)

V=30m/s.

Therefore, the car's final speed in  m/s after the acceleration is 30 m/s.

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Answer:

P = P1 + P2     where P is a vector quantity

P1 = P2 = .10 kg * 30.0 m/s = 3 kg-m/sec

P = (p1^2 + p2^2)^1/2      add vectors and find magnitude of resultant

p = (3.0^2 + 3.0^2)^1/2 = 4.24      length of resultant vector

Since vectors are at right angles p is the length of the hypotenuse

tan θ = 3.0 / 3.0 = 1      where theta is measured with respect to the positive x-axis and will be below that axis

θ = tan^-1 1 = 45 deg      (45 degrees below positive x-axis)

One can find the value of tan θ from the length of the x-y vectors and from tan θ obtain θ

This question involves the concept of the orbital period.

The period of revolution of the second satellite is "3.95 x 10⁶ s".

First, we will consider the orbital period of the first satellite:

\(T_1=\sqrt{\frac{4\pi^2 r_1^3}{GM}}\)

where,

Therefore,

\(1\ x\ 10^6\ s=\sqrt{\frac{4\pi^2(8\ x\ 10^6\ m)^3}{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(M)}}\\\\M = \frac{4\pi^2(8\ x\ 10^6\ m)^3}{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(1\ x\ 10^6\ s)^2}\\\\M = 3.03\ x\ 10^{20}\ kg\)

Now, we find out the orbital period of the second satellite:

\(T_2=\sqrt{\frac{4\pi^2 r_2^3}{GM}}\)

where,

Therefore,

\(T_2=\sqrt{\frac{4\pi^2(2\ x\ 10^7\ m)^3}{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(3.03\ x\ 10^{20}\ kg)}}\)

T₂ = 3.95 x 10⁶ s

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Answer:

solution here

The correct anwer isB .

A box puts a pressure of 50 N/\(m^{2}\) on an area of 0.25 \(m^{2}\). The force of the box on the floor is 12.5 Newton (N)

Pressure is defined as the physical force exerted on an object. The force applied is perpendicular to the surface of objects per unit area. The basic formula for pressure is \(\frac{F}{A}\) (Force per unit area). Unit of pressure is Pascals (Pa). Types of Pressures are Absolute, Atmospheric, Differential, and Gauge Pressure.

Using the formula Force = Pressure × Area

given Pressure = 50 N/\(m^{2}\)

area = 0.25 \(m^{2}\)

Substituting the values ,

Force = 12.5 Newton

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Two objects of different mass when released simultaneously from the top of a 20-m tower will both hit the ground together. If air resistance is negligible.

The amount of matter that is contained in a substance or object is measured by its mass, which is a physical attribute of matter. Although the two are different amounts, they are frequently mistaken for weight. A recognised reference, such as a standard mass, can be used to compare an object's mass, which is expressed in kilogrammes (kg) or grammes (g). Because it is an inherent quality of an object, it is unaffected by location or gravitational influence. A key component of explaining the behaviour of moving objects, as well as the characteristics of materials and the dynamics of the cosmos, is the concept of mass, which is basic to physics.

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1)

Answer: speed = 8 m/s

Explanation:

The formula for calculating speed is

speed = distance/time

From the information given,

distance = 100

time = 12.5

speed = 100/12,5

speed = 8 m/s

Answer:

it is double the temperature change of iron

Answer:

Explanation:

s = s₀ + v₀t + ½at²

s = 0 + 0(15) + ½(6)(15²)

s = 675 m

Not sure what the free fall acceleration is needed for, but if the object is dropped from a high enough point, it will travel in 15 seconds

s = ½10(15²) = 2250 m  if air resistance is ignored

Answer:

We can use the law of conservation of momentum to solve this problem, which states that the total momentum of a system before an event (in this case, pushing off the raft) is equal to the total momentum of the system after the event, assuming no external forces act on the system.

Before the push-off, the raft and the two swimmers have a total momentum of zero, since they are motionless. After the push-off, the total momentum of the system is still zero.

Let's assume that the 50 kg swimmer moves away from the raft with a velocity of v1' after the push-off. The 80 kg swimmer moves away from the raft with a velocity of 3 m/s, in the opposite direction.

Using the law of conservation of momentum, we can write:

0 = m1 * v1' + m2 * v2'

where m1 is the mass of the 50 kg swimmer, m2 is the mass of the 80 kg swimmer, and v2' is the velocity of the 80 kg swimmer after the push-off.

Substituting the values given in the problem, we get:

0 = 50 kg * v1' + 80 kg * (-3 m/s)

Solving for v1', we get:

v1' = (80 kg * 3 m/s) / 50 kg

v1' = 4.8 m/s

Therefore, the 50 kg swimmer moves away from the raft with a velocity of 4.8 m/s after the push-off.