3. How is using a model to study cells helpful?

Answer:

160m/s

Explanation:

The speed of a wave is related to its frequency and wavelength, according to this equation:

v=f ×λ

During an earthquake, it is important to take appropriate steps to ensure safety

(i) When you are in the classroom

Drop, Cover, and Hold On: Quickly drop to the ground, take cover under a sturdy desk or table, and hold on to it to protect yourself from falling objects and potential structural collapse.

Protect Your Head: If possible, use your arms to cover your head and neck to provide additional protection.

Stay Indoors: Remain inside the classroom until the shaking stops and it is safe to exit. Be prepared for aftershocks, which are smaller tremors that may occur after the main earthquake.

(ii) When you are out of danger:

Evacuate to Open Space: If you are no longer in immediate danger, move quickly to an open space away from buildings, trees, streetlights, and utility wires that may pose a risk of falling or collapsing.

Watch for Falling Debris: Be aware of your surroundings and watch out for any hazards such as falling debris, broken glass, or damaged infrastructure.

Stay Clear of Buildings: Avoid entering damaged buildings or structures as they may be unstable. Keep a safe distance until authorities confirm it is safe to enter.

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a. The gravitational potential energy change is 449.105 kJ

b. The gravitational potential energy change is 449.105 kJ

Gravitational potential energy is the energy due to the position of an object. It is given by U = mgh where

Since the mountain is 2574 ft high, the gravitational potential energy change is given by ΔU = mg(h' - h) where

Substituting the values of the variables into the equation, we have

ΔU = mg(h' - h)

ΔU = 69 kg × 9.8 m/s²(784.56 - 120.40) m

ΔU = 69 kg × 9.8 m/s² × 664.16 m

ΔU = 449104.992 J

ΔU = 449.104992 kJ

ΔU ≅ 449.105 kJ

So, the gravitational potential energy change is 449.105 kJ

We know that the gravitational potential energy change is ΔU = U' - U = mg(h' - h) where

Substituting the values of the variables into the equation, we have

ΔU = U - U' = mg(h' - h)

ΔU = 0 - U' = 69 kg × 9.8 m/s²(784.56 - 120.40) m

ΔU = 69 kg × 9.8 m/s² × 664.16 m

ΔU = 449104.992 J

ΔU = 449.104992 kJ

ΔU ≅ 449.105 kJ

So, the gravitational potential energy change is 449.105 kJ

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Answer:

B. 10 cm

x^3 = 1 L

1 L = 1000 cm^3 (since 1 L = 1000 cm^3)

x^3 = 1000 cm^3

ANSWER

B) 25 turns

EXPLANATION

The relationship between the number of turns of a transformer and the input and output voltage is:

Where Np is the number of turns of the primary, Ns is the number of turns of the secondary, Vp is the input voltage (in the primary) and Vs is the output voltage.

Solving for Ns:

In this problem Np = 500, Vp = 120 and Vs = 6:

Hence, the correct option is B. The secondary has 25 turns

Answer:

PE = 137.2931 J

Explanation:

PE = 137.2931 J

Answer:

Archimedes principle states that when a body is partially/wholly/completely immersed in fluid (liquid or gas),it experiences an upthrust which is equal to the weight of the fluid displaced....

You must concentrate on the catch to win a water balloon contest without breaking the balloon. Momentum, impulse, force, and impact time are all important factors in the catch's success. The key to catching a water balloon without breaking it is to reduce the balloon's impact force. The momentum of the balloon, the impulse applied to the balloon, and the impact time all contribute to the impact force.

The product of an object's mass and velocity is its momentum. As it is thrown towards you, the water balloon has a certain mass and velocity. The greater the balloon's momentum, the more difficult it will be to catch it without breaking it.

In order to catch a water balloon, you must apply an impulse to the balloon. The higher the impulse, the more effectively you can stop the balloon. To catch a water balloon without breaking it, apply a large impulse to the balloon in a short period of time. This reduces the impact force on the balloon and keeps it from breaking.

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Explanation:

Given that,

Current, I = 0.015 A

Voltage, V = 240 volts

We need to find the resistance. Using Ohm's law we can find it as follows :

\(V=IR\\\\R=\dfrac{V}{I}\\\\R=\dfrac{240}{0.015}\\\\R=16000\ \Omega\)

So, When a current of 0.015 A passes through human body at 240 volts p.d it  causes​  16000 ohms of resistance.

I apologize, but I can't help with the specific calculations you've provided. Calculating forces and friction coefficients requires specific numerical values and equations. However, I can explain the concepts and provide a general understanding of the questions you've asked.

3.1 To calculate the magnitude of the force exerted by the athlete vertically on the track, you need the vertical component of the force applied. If the angle of 50° is measured from the horizontal, you can calculate the vertical component using the equation: horizontal force = force × sin(angle).

3.2 To calculate the magnitude of the force exerted by the athlete horizontally on the track, you need the horizontal component of the force applied. Using the same angle of 50° measured from the horizontal, you can calculate the horizontal component using the equation: vertical force = force × cos(angle).

3.4 To determine the minimum value of the static friction coefficient, you would need additional information such as the mass of the athlete. In addition, you would need the normal track force. The coefficient of static friction is a dimensionless value that represents the maximum frictional force that can exist between two surfaces without causing them to slip. The formula to calculate static frictional force is static frictional force = coefficient of static friction × normal force.

3.5 To determine the resultant force exerted on an object when three forces are applied, you need to calculate the vector sum of the forces. You can add forces vectorially by breaking them down into their horizontal and vertical components. You can also sum up the components separately, and then combine them to find the resultant force.

Please provide more specific numerical values or equations if you would like assistance with the calculations.

Kepler’s laws are useful when the sun is located on a permanent spot and they can be considered purely descriptive.

Kepler’s laws are a set of scientific models to understand the motion (movement) of the planets around the sun.

These laws state that a planet's orbit can be considered as elliptical around the Sun and this motion rate is constant over time, thereby Kepler's laws are descriptive and do not explain planetary movement.

In conclusion, Kepler’s laws are useful when the sun is located on a permanent spot and they can be considered purely descriptive.

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Answer:

Mass and Acceleration

Explanation:

The typical Force equation is:

F = ma

where m = mass, and a=acceleration.

Answer:

Gravity is the main force responsible for mass movements. Gravity is a force that acts everywhere on the Earth's surface, pulling everything in a direction toward the center of the Earth

Explanation:

It is not recommended to fire a gun straight up into the air.

When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.

Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.

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Answer:

I believe you put how you think you'd feel it's that simple

Answer:

utilizing positive values

Explanation:

The correct answer is Option B. The statement "they have the same A-number but different Z-number" is true .

Atoms of the same element only differ because one of the atoms has more electrons, making it an ion.

This difference does not affect the mass of the atom, which is determined by the sum of its protons and neutrons, represented by the atomic mass or A-number.

The number of protons in an atom is called the atomic number or Z-number.

The Z-number of an element is unique to it. All the atoms of a given element have the same number of protons.

Thus, for example, all carbon atoms have six protons, making the Z-number of carbon 6.

However, different isotopes of an element can have different numbers of neutrons.

This means that they have a different atomic mass or A-number.

Therefore, they have the same A-number but different Z-number.

Therefore the correct Option is B.

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Answer:

\(\Rightarrow L=70 .03472 cm\)

Explanation:

For convenience, let's represent the thermal expansion coefficient by \(\alpha\), i.e. \(????=\alpha\).

Given that, for steel \(\alpha =1.24\times 10^{-5}\) °\(C^{-1}\),

initial length, \(L_0=70 cm\), initial temperature, \(T_0=70\) °\(C\), and the final temperature, \(T=110\) °\(C\).

Let the length of the rod at \(T=110\) °\(C\) be \(L\).

Now, change in length, \(\Delta L=\alpha L_0 \Delta T\)

\(\Rightarrow \Delta L=\alpha L_0 (T-T_0)\)

\(\Rightarrow L-L_0=1.24\times 10^{-5}\times 70 (110-70)\)

\(\Rightarrow L-70=1.24\times 10^{-5}\times 70 \times 40\)

\(\Rightarrow L=70 + 0.03472 cm\)

\(\Rightarrow L=70 .03472 cm\)

Hence, the length of the rod at \(T=110\) °\(C\) be \(70.03472 cm\).

A car is moving at 16 m/s at a time t = 0. With an acceleration of 0.50t, in m/s², for t, in seconds, it slows down. At t = 8 seconds, it stops. Option D is correct.

The change of displacement with respect to time is defined as the velocity.  velocity is a vector quantity.

Given data;

t = 0 ,u=16 m/s

acceleration = −0.50t m/s²

v=0,t=?

The acceleration is found as;

\(\rm a= \frac{dv}{dt} \\\\\ dv=adt \\\\ dv=-0.50 \ t dt\)

Intregating both sides we get;

\(\rm [v]_0^{16}=-0.50\frac{t^2}{2} \\\\ 16=0.25 t^2\\\\\ t^2=\frac{16}{0.25} \\\\\ t= 8 \ sec\)

Hence, the car stops at t=8sec. Option D is correct.

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A is the answer  because it is the answer

Answer: Hope this helps ;) don't forget to rate this answer !

Explanation:

There are two correct answers:

A) A corporation leader makes direct payment to the candidate.

D) A corporation contributes to a Super PAC that a PAC accepts contributions for a candidate.

Option A describes a scenario where a corporation directly donates money to a presidential candidate, which is allowed as long as it is done within the limits set by campaign finance laws.

Option D describes a scenario where a corporation donates money to a Super PAC, which is a type of political action committee that can accept unlimited donations from individuals, corporations, and other organizations. The Super PAC can then use the money to support or oppose a particular candidate, but it is not allowed to coordinate directly with the candidate or the candidate's campaign.

I hope this helps! Let me know if you have any other questions.

Answer:

Explanation:

Nothing happens unless we know the position relationship between launch ramp and landing slope. That missing figure would sure be helpful.

ASSUMING the landing slope starts its 45° slope at the position where the skier leaves the launch track. Also assuming no air resistance or lift due to airfoil action on body and skis. (projectile trajectory)

With the launch point as origin and original velocity in the positive direction, horizontal position can be described as

x = 28t

With the launch point as origin and DOWN being positive direction, vertical position can be described as

y = ½(9.8)t²

y = 4.9t²

On a 45° downward slope, y will increase at the same rate as x. time t is common to both equations. When our y equals our x, landing occurs.

4.9t² = 28t

4.9t = 28

t = 5.714285...s

t = 5.71 s

The horizontal and vertical distances at landing are

x = 28(5.714285) = 160 m

so along the slope, the distance is

d = √(2(160²)) = 226.2741699...

d = 226 m

velocities will give us the angle of flight, subtract the slope.

φ = arctan(gt/vx) - 45 = arctan(9.8(5.714285) / 28) - 45 = 18.434948...

φ = 18°

A coal power station generates electricity by first burning coal to heat water into steam, then passing that steam through a turbine to make it spin.

A. Energy stores:

Chemical potential energy in the coal

Thermal energy in the water

Kinetic energy in the steam

Kinetic energy in the turbine

Electrical energy in the generator

Energy transfers:

Chemical potential energy in the coal to thermal energy in the water (by burning the coal)

Thermal energy in the water to kinetic energy in the steam (by boiling the water)

Kinetic energy in the steam to kinetic energy in the turbine (by passing through the turbine)

Kinetic energy in the turbine to electrical energy in the generator (by driving the generator)

B. Energy transferred into heat store of water: 20,000 J x 0.9 = 18,000 J

Energy dissipated in the turbine: 18,000 J x 0.3 = 5,400 J

Remaining energy after turbine: 18,000 J - 5,400 J = 12,600 J

Energy transferred as electrical energy: 12,600 J x 0.85 = 10,710 J

C. Power output = energy input per second = 10,000 J/s

So, the power output of the power station is 10,710 J/s (since 85% of the remaining energy is transferred as electrical energy).

D. Three specific improvements that could be made to the power station to make it more efficient are:

Implementing better combustion techniques to increase the efficiency of burning coal.

Using better insulation materials to minimize heat loss in the power station.

Using more efficient turbines and generators to convert kinetic energy to electrical energy.

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Answer:

The correct answer is - Plantae.

Explanation:

Drosera magnifica is discovered in 2015 for the first time and the characteristics this organism's cell shows are -

- permanent vacuoles

- surrounded by cellulose layer

Vacuoles are present in both Plantae and Animalia kingdom of the eukaryotic organism but in animal cells, there are small and numerous vacuoles present and they are not permanent whereas in plant cells vacuoles are present permanently.

The cell of an animal cell has no surrounding layer other than cell membrane while in the plant cell there is a supporting and protecting layer of cellulose cell wall present.

On the basis of the given characteristics, it is confirmed that the Drosera magnifica belongs to Plantae kingdom.

(a) For the density function, the value of B is 2.5 g/cm³   and the value of C is 1.3 g/cm⁴

(b) The total mass of the rod is 1470 g.

The density of the rod is a function of distance and it is given as;

ρ = B + Cx

where;

ρ = 2.5 g/cm³  +  (19.5 g/cm³ ) / ( 15 cm ) x

ρ = 2.5 g/cm³  +  1.3 g/cm⁴  x

The total mass of the rod is calculated by integrating the function;

dm = ( B + Cx)(8 cm² ) dx

m = 8B + 8Cx

m = 8Bx  +  8Cx² / 2

m = ( 8 x 2.5 x 15 )  +  ( 8 x 1.3 x 15² ) / 2

m = 1470 g

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Answer:

Explanation:

Earth's atmosphere contains greenhouse gases that trap heat. While they allow sunlight to pass through the atmosphere, they also prevent the heat it brings from leaving it.

When Sally puts on wool socks and rubs her feet on a nylon carpet, static electricity builds up through a process involving the movement of electrons. The friction between the wool socks and the nylon carpet causes electrons from the wool socks to move to the carpet, resulting in Sally and her socks gaining a negative charge.

The correct answer would be the friction causes electrons from the wool socks to move to Sally, giving Sally a negative charge.

The friction between the wool socks and the nylon carpet causes electrons from the wool socks to move to the carpet, resulting in Sally and her socks gaining a negative charge. This is due to the phenomenon known as the triboelectric effect.

The triboelectric effect occurs when two materials come into contact and then separate. During the rubbing process, the atoms in the two materials interact, causing the transfer of electrons between them. In this case, the wool socks have a greater affinity for electrons compared to the nylon carpet. As a result, electrons from the socks are transferred to the carpet, leaving the socks with a positive charge and the carpet with a negative charge.

Sally, wearing the wool socks, experiences an accumulation of excess electrons on her feet, giving her a negative charge. This excess negative charge on her body can lead to static electricity-related phenomena, such as experiencing a shock when touching a metal object or seeing her hair stand on end when near certain surfaces.

It's important to note that the movement of electrons determines the charge distribution during the triboelectric effect. In this scenario, electrons move from the wool socks to the nylon carpet, resulting in Sally and her socks gaining a negative charge.

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smartphones break due to forces acting on the material.

force causes material to deform.

material is often brittle and cracks due to a limit on hardness / electricity in screens.

newton's 2nd law states

force = DV / DT

to help phones we must slow down change in momentum to reduce the force

thus we must use some form of damping in the form of a case .

the case is typically able to deform and rubber is elastic converting the kinetic energy to heat as it deforms instead of transferring it through the screen.

therefore the change in velocity occurs over a longer time. therefore the impulse decreases

By decreasing the velocity of the strike the change in the momentum is less resulting in a less impulsive force that can protect a smartphone screen during a collision.

Newton's second law of motion is concerned with the behavior of objects for which all existing forces are imbalanced.

The force is given as the product of mass and change of velocity. The impulsive force is given by the change in momentum.

\(\rm I=\frac{m(v-u)}{} \\\\ \frac{m(v-u)}{}= \rm Ft \rm \\\\ \rm F= \frac{m(v-u)}{t}\)

Smartphones break due to forces acting on the material force causing the material to deform. Material is often brittle and cracks due to a limit on hardness in screens.

To help phones we must slow down changes in momentum to reduce the force.

Hence, by decreasing the velocity of the striking the change in the momentum is less resulting in a less impulsive force.

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