3. if the initial amount of radionuclide is 50 mci and the half-life is 75 days, what is the activity remaining after 200 days?
Answers
If the initial amount of radionuclide is 50 mci and the half-life is 75 days. Then, the activity remaining after 200 days is approximately 2.19515 mCi.
To determine the activity remaining after a certain time, we can use the radioactive decay equation;
A = A₀ × \((1/2)^{(t}\) / T₁/₂)
Where; A is the remaining activity after time t
A₀ is the initial activity
T₁/₂ is the half-life of the radionuclide
Given; A₀ = 50 mCi (millicuries)
T₁/₂ = 75 days
t = 200 days
Plugging in the values into the equation, we get;
A = 50 mCi × (1/2)²⁰⁰ / 75)
Calculating this expression, we find;
A ≈ 50 mCi × 0.043903
A ≈ 2.19515 mCi
Therefore, the activity remaining after 200 days will be 2.19515 mCi.
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Related Questions
Arrange the organic compounds from most soluble in water to least soluble in water: Most soluble in water Least = soluble in water Answer Bank CH; OH CH CH, OCH,
Answers
The order from most soluble to least soluble is CH3CH2CH2OH > CH3CH2OCH3 > CH3CH2CH3.
The solubility of a compound depends on the nature of the solute and the solvent. If the nature of both is the same (either both polar or both nonpolar) the salute will be soluble in that solvent.
The solubility of an organic compound in water depends on the following factor:
Hydrogen bonding: If the solute is capable to form hydrogen bonding with water, it will be soluble in the water.
Polarity: As the polarity of the solvent increases the water solubility also increases.
The most soluble compound in water is alcohol. The alcohol is the highest polar molecule from the given molecules. It also forms hydrogen bonding with the water as follows:
The second most soluble compound in water is ether, CH3CH2OCH3. Ether is less polar than alcohol and forms fewer hydrogen bonds with water.
The least soluble compound in water is propane, CH3CH2CH3. Propane is a nonpolar compound and it is insoluble in a polar solvent, water.
Therefore the order is as follows:
CH3CH2CH2OH>CH3CH2OCH3>CH3CH2CH3
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what product is finally formed when the initial compound formed from cyclohexanone and morpholine is mixed with methyl iodide and that product is heated and then hydrolyzed
Answers
When the initial compound formed from cyclohexanone and morpholine is mixed with methyl iodide and heated and then hydrolyzed, the product that is finally formed is N-Methylaminoethylcyclohexanone.
The reaction between cyclohexanone and morpholine in the presence of an acid catalyst produces a cyclic imine named N-morpholino-cyclohexanone, which is an intermediate in the synthesis of several drugs. It reacts with methyl iodide and potassium carbonate in methanol to form N-methylaminoethylcyclohexanone, which upon hydrolysis produces the final product, N-methylaminoethylcyclohexanone. This reaction is an example of the Mannich reaction.N-methylaminoethylcyclohexanone is a synthetic intermediate and a building block for the synthesis of various drugs. It's commonly used as an intermediate in the synthesis of sedatives and analgesics. It's also used in the synthesis of ephedrine analogs and the anticancer agent 2-[2-(4-ethoxyphenyl)ethyl]aminoethylcyclohexanone.
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Sec. 5.1: “Simple Ions”
1) How much an element __________ depends on its ________________ configuration.
a) __________ gases are the __________ reactive elements because their outer energy levels
are ____________ with ______ electrons.
(except He, which is full with 2)
b) In most chemical reactions, atoms try to ______________ the electron configurations of the
noble gases by either ______________ or _______________ electrons.
c) Most atoms want to become __________.
2) Octet rule: a concept of chemical ______________ theory that is based on the assumption that
______________ tend to have either ________________ valence shells (energy levels) or
_____________ valence shells of _________ electrons. “8 is _____________”
3) **_____________ Metals and ____________ are the _____________ Reactive Elements
a) As members of Group _____, alkali metals have only _____ electron in their outermost
__________ __________.
b) By _____________ that 1 electron, an ___________ metal can get an electron configuration
like a ____________ gas, with ______ electrons in its outermost energy level.
c) 1s22s22p63s23p64s1
_________________
Potassium will lose the 1 electron in the 4th energy level so that its outmost energy level is empty.
4) Remember, potassium’s electron configuration was 1s22s22p63s23p64s1
a) Question: Why doesn’t potassium gain 7 electrons to become stable instead of losing 1?
Answer: _______________________________________________________________
5) As members of Group _____, the halogens have _____ electrons in their outermost
__________ __________.
a) By gaining _____ electron, a __________ can get an electron configuration like a
__________ gas, with _____ electrons in its outermost energy level.
b) 1s22s22p63s23p5 _________________
Chlorine will gain 1 electron to make its outmost energy level full.
6) After it __________ one electron, potassium has the __________ electron configuration as
____________ does after it __________ one electron.
a) Both are the same as the noble gas ___________. 1s22s22p63s23p6
b) The atoms of many ____________ become __________ by achieving the electron
configuration of a __________ __________.
c) Remember, the ___________ in the outermost energy level are called _________ electrons.
7) To find out how many ______________ electrons an atom has, check the _____________
_____________.
a) Magnesium, Mg, has the shorthand electron configuration: [Ne] 3s2
b) The outermost energy level is the _______ energy level.
c) This means that a magnesium atom has _______ _____________ electrons, both in the 3s
orbital.
8) The shorthand electron configuration for phosphorus, P, is: [Ne] 3s23p3
a) The outermost energy level is the ________ energy level.
b) This means that each phosphorus atom has ________ valence electrons: _______ in the 3s
orbital, and _____ in the 3p orbital.
9) Atoms Gain or Lose Electrons to Form __________ __________.
a) All atoms are _______________ because they have ___________numbers of
____________ and _____________.
b) For example, a potassium atom has _________ protons and 19 ____________.
c) After _______________ 1 electron, potassium still has _______ protons but now only has 18
_________________.
d) Because the numbers are ________ the same, there is a net _________________ charge.
10) Ion: an atom, radical, or molecule that has ______________ or ____________ one or more
_______________ and has a _______________ or _____________ charge.
a) Show how a potassium atom forms an ion with a 1+ charge:
b) Cation: an ___________ that has a ______________ charge. (think of the cat!)
11) In the case of chlorine, far less __________ is required for an atom to __________ one
electron rather than lose its ________ valence electrons to become _____________.
a) Show how a chlorine atom forms an ion with a 1- charge:
b) Anion: an _______ that has a ___________ charge. (think of the ant!)
12) Both an __________ and its __________ have the same number of __________ and
__________ so the nuclei are the same.
a) But, an atom and its ion have _______________ numbers of _________________.
b) The chemical properties of an atom depend on the __________ and configuration of its
___________.
c) So, an atom and its ion have __________ __________ __________!!!
Answers
The chemical properties of an atom of an element depends on its electronic configuration.
Ions are formed by loss or gain of electrons by atoms.
What is electronic configuration of an atom?Electronic configuration is the arrangement of electrons around the nucleus of an atom.
How much an element reacts depends on its electronic configuration.Noble gases are the least reactive elements because their outer energy levels are filled with octet electrons. (except He, which is full with 2)In most chemical reactions, atoms try to have the electron configurations of the noble gases by either losing or gaining electrons.
Most atoms want to become stable.
What is the octet rule?Octet rule is a concept of chemical bonding theory that is based on the assumption that atoms tend to have either empty valence shells (energy levels) or full valence shells of eight electrons. “8 is octet”
What are Alkali metals and Halogens?Alkali Metals and Halogens are the most Reactive Elements
As members of Group 1, alkali metals have only one electron in their outermost shell.By losing that 1 electron, an alkali metal can get an electron configuration like a noble gas, with eight electrons in its outermost energy level.1s22s22p63s23p64s1 is the electronic configuration of potassium.
Potassium will lose the 1 electron in the 4th energy level so that its outmost energy level is empty.
Potassium does not gain 7 electrons to become stable instead of losing because the energy associated with losing one electron is less than that needed to gain 7 electrons.
As members of Group 7, the halogens have seven electrons in their outermost shell.By gaining one electron, a halogen can get an electron configuration like a noble gas, with eight electrons in its outermost energy level.1s22s22p63s23p5 is the electronic configuration of chlorine
Chlorine will gain 1 electron to make its outmost energy level full.
After it losing one electron, potassium has the same electron configuration as chlorine does after it gains one electron.
Both are the same as the noble gas argon 1s22s22p63s23p6
The atoms of many elements become stable by achieving the electron configuration of a noble gas.The electrons in the outermost energy level are called valence electrons.What are valence electrons?To find out how many valence electrons an atom has, check the shorthand electronic configuration.
Magnesium, Mg, has the shorthand electron configuration: [Ne] 3s2
The outermost energy level is the 3 energy level.
This means that a magnesium atom has two electrons, both in the 3s
orbital.
The shorthand electron configuration for phosphorus, P, is: [Ne] 3s23p3
The outermost energy level is the 3 energy level.
This means that each phosphorus atom has five valence electrons: 2 in the 3s
orbital, and 3 in the 3p orbital.
What are ions?Atoms Gain or Lose electrons to form ions.All atoms are different because they have different numbers of protons and electrons.For example, a potassium atom has 19 protons and 19 electrons .
After losing 1 electron, potassium still has 19 protons but now only has 18 electrons .
Because the numbers are not the same, there is a net positive charge.
An Ion is an atom, radical, or molecule that has lost or gained one or more electrons and has a positive or negative charge.
The formation of potassium ionPotassium atom forms an ion with a 1+ charge in the following step:
K ---> K+ + e-
What are Cations and Anions?Cation: an ion that has a positive charge.In the case of chlorine, far less energy is required for an atom to gain one
electron rather than lose its seven valence electrons to become stable.
Show how a chlorine atom forms an ion with a 1- charge:
Cl + e- ----> Cl-
Anion: an ion that has a negative charge.Both an atom and its ion have the same number of protons and neutrons so the nuclei are the same.
But, an atom and its ion have different numbers of electrons.
The chemical properties of an atom depend on the number and configuration of its electrons .
So, an atom and its ion have same number atomic number.
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Use the polar coordinates to find the volume of the given solid Above the cone z=sqrt(x^2+y^2) and below the sphere x^2+y^2+z^2=1
Answers
The volume of the solid above the cone and below the sphere is π/3 cubic units.
To find the volume of the given solid above the cone and below the sphere, we can use the triple integral in cylindrical coordinates.
The cone has a vertex at the origin and a base radius of 1. Its equation in cylindrical coordinates is z = r. The sphere has a radius of 1 and is centered at the origin. Its equation in cylindrical coordinates is r^2 + z^2 = 1.
The limits of integration for the cylindrical coordinates are:
0 ≤ r ≤ 1
0 ≤ θ ≤ 2π
r ≤ z ≤ √(1 - r^2)
The triple integral for the volume can be set up as follows:
V = ∫∫∫ dV
where dV = r dz dr dθ is the volume element in cylindrical coordinates.
Thus, the integral for the volume is:
V = ∫0^1 ∫0^2π ∫r^√(1-r^2) r dz dr dθ
Integrating with respect to z first, we get:
V = ∫0^1 ∫0^2π r(√(1-r^2) - r) dr dθ
Using a u-substitution with u = 1 - r^2, du = -2r dr, we get:
V = ∫0^1 ∫0^2π -1/2 (√u - 1) du dθ
Integrating with respect to θ, we get:
V = -π ∫0^1 (√u - 1) du
Simplifying, we get:
V = -π [2/3 u^(3/2) - u]0^1
V = -π [2/3 - 1]
V = π/3
Therefore, the volume of the solid above the cone and below the sphere is π/3 cubic units.
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Which of the following contains polyatomic ion?
Oa
BeHCO
Ob
PCI
Ag!
Mgs
Answers
.Answer the following questions about laboratory situations involving acids, bases, and buffer solutions.
(a) Lactic acid, HC3H5O3, reacts with water to produce an acidic solution. Shown below are the complete Lewis structures of the reactants. In the space provided, complete the equation by drawing the complete Lewis structures of the reaction products.
(b) Choosing from the chemicals and equipment listed below, describe how to prepare 100.00 mL of a 1.00 M aqueous solution of NH4Cl (molar mass 53.3 g molâ€"1). Include specific amounts and equipment where appropriate.
NH4Cl (s) 50 mL buret 100 mL graduated cylinder 100 mL pipet
Distilled water 100 mL beaker 100 mL volumetric flask Balance
Mass of NH4Cl: 100 mL = 5.33 g NH4Cl
(1) Weigh out 5.33 g NH4Cl(s) using the balance. (2) Carefully transfer the solid into a 100 mLvolumetric flask. (3) Add distilled water up to the etched line. (4) Mix.
Answers
The complete Lewis structure of lactic acid is:
H H
| |
H-C-C-OH
| |
H-C-C=O
| |
H OH
When lactic acid reacts with water, one of the OH groups will dissociate and form H+ ions. The complete Lewis structure of the product, H3O+, is:
H
|
H O-H
| ||
H-C-C=O
| |
H OH
(b)
To prepare 100.00 mL of a 1.00 M aqueous solution of NH4Cl, we need to dissolve 5.33 g of NH4Cl in distilled water. Here are the steps:
(1) Use the balance to weigh out 5.33 g of NH4Cl(s).
(2) Carefully transfer the solid into a 100 mL volumetric flask.
(3) Add distilled water up to the etched line.
(4) Mix the solution thoroughly until all the solid is dissolved.
You can use a stirring rod to help dissolve the NH4Cl.
The 50 mL buret, 100 mL graduated cylinder, and 100 mL pipet are not needed for this procedure.
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a balloon contains 0.76 mol n2, 0.18 mol o2, 0.031 mol he and 0.026 mol at 739 mm hg. what is the partial pressure of o2?
Answers
Assume that every gas in the list will act perfectly. Using the mole fraction of O2 and the specified pressure, the partial pressure of O2 may be computed (P).
What is specified?
The following diagram illustrates the mathematical link between partial pressure of oxygen (P1) and oxygen mole fraction (X1):
P₁=X₁P
By dividing the total number of moles of gases (0.76 + 0.18 + 0.031 + 0.026) by the number of moles of O2 (0.18 mol), it is possible to determine the mole fraction of O2 as follows:
X₁= 0.18 / (0.76+0.18+0.031+0.026)= 0.1805
In this manner, the partial pressure of O2 (P1) is determined:
P1=0.1805x739mmHg, or 133.4mmHg
According to the estimate above, the partial pressure of oxygen is almost equal to 130 mm Hg. As a result, option C is the best one.
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A teacher asks a student to write the chemical equation for photosynthesis. The student's response is shown below.
CO2+H2O→C6H12O6+O2
The equation is not balanced correctly. Which of these is a balanced equation for photosynthesis?
Answers
Answer:
A
Explanation:
Trust me bro :) I just know it
How many atoms are found inside a unit cell of a simple cubic, body-centered cubic, and face-centered cubic crystal? How far apart in terms of lattice constant a are nearest-neighbor atoms in each case, measure from center to center?
Answers
Simple Cubic (SC): 1 atom, nearest-neighbor distance = a/2
Body-Centered Cubic (BCC): 2 atoms, nearest-neighbor distance = a
Face-Centered Cubic (FCC): 4 atoms, nearest-neighbor distance = a√2
In a crystal lattice, the number of atoms found inside a unit cell and the distance between nearest-neighbor atoms vary depending on the type of lattice structure. Let's explore the characteristics of each type of cubic crystal lattice:
Simple Cubic (SC)
Number of atoms in a unit cell: 1
Nearest-neighbor distance: The nearest-neighbor atoms are located at the corners of the cube. The distance between the center of the cube (where the atom is located) and the corner atoms is equal to half of the length of one side of the cube.
Nearest-neighbor distance = a/2
Body-Centered Cubic (BCC)
Number of atoms in a unit cell: 2
Nearest-neighbor distance: The nearest-neighbor atoms are located at the corners of the cube and one atom at the center of the cube. The distance between the center atom and the corner atoms is equal to the length of one side of the cube.
Nearest-neighbor distance = a
Face-Centered Cubic (FCC)
Number of atoms in a unit cell: 4
Nearest-neighbor distance: The nearest-neighbor atoms are located at the corners of the cube and one atom at the center of each face of the cube. The distance between the center atom of one unit cell and the corner atom of a neighboring unit cell (center to center) is equal to the length of one side of the cube multiplied by the face diagonal of a cube (√2).
Nearest-neighbor distance = a√2
It's important to note that the "a" in the above equations represents the lattice constant, which is the length of one side of the unit cell.
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HELP MEEEEE PLEASEEEE
Answers
shshjshdjajhs
What are the uses of Diamonds?
your own answer
please help
Answers
Answer:
Diamonds are very important in our daily lives ,so therefore it has many uses
1.They are used ad beauty products
2.They are used in automative industry
3.They are used in making windows
4.They are used as medicine
Describe a few abiotic factors found within the taiga that limit its biodiversity.
Answers
Answer:
Some abiotic factors of the taiga are temperature, precipitation, soil, and sunlight.
Explanation:
emperature affects the taiga because the winter temperature range is -65*F to 30*F (-54*C to -1*C), while the temperature range in the summer is 20*F to 70*F (-7*C to 21*C)
Precipitation affects the taiga because there's some precipitation that falls [30-85 cm. (12-33 in.)].
Soil affects the taiga because there's some acidic and low-in-nutrients soil, and some fertile soil.
Sunlight affects the taiga because there are small amounts of it that reach the ground.
The taiga biome's abiotic components include temperature, sunshine, soil, air, water, etc. Cold arctic air predominates in the taiga environment. The taiga receives more light in the summer, which causes the days to be hotter.
What are abiotic components ?Abiotic elements, also known as abiotic factors, are non-living chemical and physical elements of the environment that have an impact on the health of living things and the operation of ecosystems. Biology as a whole is supported by abiotic causes and the phenomena that go along with them.
Biotic and abiotic components, such as rainfall, in that order. The taiga is the biggest biome on Earth's surface and features a diversity of migratory and resident creatures. It also has long, cold, and dry winters and short, warm, and moist summers.
The Taiga biome is restricted by four primary criteria. Fire, temperature, the quantity of nutrients in the soil, and sunshine are the four limiting elements. Because certain plants, like the Jack Pine, recover after fire, it is a limiting element in the Taiga biome.
Thus, The taiga biome's abiotic components include temperature, sunshine, soil, air, water, etc.
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Monica has $20. She needs to buy a gallon of milk that costs $2.50. She also wants to buy yogurt, which costs $1.20 a cup. What is the greatest number of cups of yogurt Monica can buy? Use the inequality 1.20x + 2.5 ≤ 20 to solve the problem
Answers
1.20x <20-2.5
1.20 x<17.5
Divide both sides by 1.20
X< 14.58
At the most she can buy 14 cups
ethyl acetate has a normal boiling point of 77°c, and a vapor pressure of 73 torr at 20.°c. what is the δhvap of ethyl acetate in kj/mol?
Answers
The ΔHvap of ethyl acetate in the given conditions is 35.08 kJ/mol.
Enthalpy of vaporization:
To find the ΔHvap (enthalpy of vaporization) of ethyl acetate in kJ/mol, you can use the Clausius-Clapeyron equation, which is:
ln(P1/P2) = (ΔHvap/R) * (1/T2 - 1/T1)
Given:
Normal boiling point (T2) = 77°C = 350.15 K (converting to Kelvin by adding 273.15)
Vapor pressure at 20°C (P1) = 73 Torr
Temperature at P1 (T1) = 20°C = 293.15 K (converting to Kelvin)
P2 = 760 Torr (normal atmospheric pressure at boiling point)
R = 8.314 J/(mol*K) (universal gas constant)
First, plug the values into the equation:
ln(73/760) = (ΔHvap/8.314) * (1/350.15 - 1/293.15)
Now, solve for ΔHvap:
ΔHvap = 8.314 * (ln(73/760) / (1/350.15 - 1/293.15))
ΔHvap ≈ 35079 J/mol (rounded to the nearest whole number)
Finally, convert ΔHvap to kJ/mol:
ΔHvap ≈ 35.08 kJ/mol (rounded to two decimal places)
So, the ΔHvap of ethyl acetate is approximately 35.08 kJ/mol.
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What is the Index Value for an exposure of low?
Answers
The concept is to provide diagnostic images using the optimal amount of radiation. If the index is too low, it may indicate poor image quality. If the dose index is too high, it may mean using more radiation than is needed for imaging.
Various Kinds of Index NumbersThere are three kinds of index numbers, namely:
a. Price index figures, namely comparative figures to measure price changes from one period to another.
b. Number index (quantity), which is a comparison number to measure changes in the amount from one period to another.
c. Value index number, which is a comparison number to measure changes in value from one period to another. Value is calculated by multiplying the price by the amount (quantity).
Your question is incomplete but most probably your full question was:
Explain. What is the Index Value for an exposure of low?
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explain what is water of crystallization
Answers
Explanation:
In chemistry, water(s) of crystallization or water(s) of hydration are water molecules that are present inside [crystal]s. Water is often incorporated in the formation of crystals from aqueous solutions. ... Water of crystallization can generally be removed by heating a sample but the crystalline properties are often lost
Please help me do this question
Answers
How many pages is 5000 words? Double spaced, 5000 words is around 20 pages; single spaced about 10 pages. Now, if you're using an unconventional formatting or margins you could see different results, however, with standard word processor defaults and a 12 point Arial or Times New Roman font your output should be very similar. Examples of 5000 word count pages include college theses, dissertation research, or very comprehensive, in-depth blog posts.
Answer: 5000 words is 10 pages single spaced or 20 pages double spaced.
Pages by Word Count
Use our handy table to discover how many pages a given word count yields, single or double spaced, in Times New Roman or Arial 12 point font.
Word Count Pages (single spaced) Pages (double spaced) Font Size
250 WORDS ½ PAGE 1 PAGE 12 POINT
300 WORDS ⅔ PAGE 1⅓ PAGES 12 POINT
400 WORDS ⅘ PAGE 1⅗ PAGES 12 POINT
500 WORDS 1 PAGE 2 PAGES 12 POINT
600 WORDS 1⅓ PAGE 2⅔ PAGES 12 POINT
750 WORDS 1½ PAGES 3 PAGES 12 POINT
800 WORDS 1⅗ PAGES 3⅕ PAGES 12 POINT
1000 WORDS 2 PAGES 4 PAGES 12 POINT
1200 WORDS 2⅖ PAGES 4⅘ PAGES 12 POINT
1500 WORDS 3 PAGES 6 PAGES 12 POINT
2000 WORDS 4 PAGES 8 PAGES 12 POINT
2500 WORDS 5 PAGES 10 PAGES 12 POINT
3000 WORDS 6 PAGES 12 PAGES 12 POINT
3500 WORDS 7 PAGES 14 PAGES 12 POINT
4000 WORDS 8 PAGES 16 PAGES 12 POINT
5000 WORDS 10 PAGES 20 PAGES 12 POINT
6000 WORDS 12 PAGES 24 PAGES 12 POINT
7500 WORDS 15 PAGES 30 PAGES 12 POINT
8000 WORDS 16 PAGES 32 PAGES 12 POINT
10000 WORDS 20 PAGES 40 PAGES 12 POINT
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How Many Pages is 4000 Words?
How many pages does 4000 words equal? Single spaced, 4000 words would produce about 8 pages; double spaced around 16 pages.
How Many Pages is 300 Words?
How many pages is 300 words? The answer is close to two-thirds of a page single spaced, and around one and one-third of a page double spaced.
How Many Pages is 400 Words?
How many pages does 400 words take? A word count of 400 words will result in around four-fifths of a page single spaced and and one and three-fifths of a page double spaced.
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The concentration of a trace mineral is found to be 2.53 PPB in an aqueous solution. what volume of solution contains 2.53 g of the mineral?
Answers
Answer:
4. A concentration of a trace mineral was found to be 2.53 ppb in an aqueous solution. A. What mass of solution contains 2.53 g of the mineral? (1 point - Knowledge, 2 points - Inquiry, 1 point - Communication) m=? C = 2.53 ppm or 2.53X106 n = Con ܗ B. What volume of solution contains 2.53 g of the mineral? (1 point - Knowledge, 2 points - Inquiry, 1 point - Communication) VE? C: 2,53 ppm ns Cen
Temperature is a measure of the average kinetic energy of the particles in a object.
A.True
B.False
Answers
How is humility related to air pressure
Answers
Answer: Edmentum question:
The following graph shows the barometric pressure over the course of the day in Bellingham. What effect will this trend likely have on cloud cover and precipitation over the city?
a scatter plot showing the barometric pressure of an area, with air pressure on the y-axis and time on the x-axis
Explanation: edmentum answer:
In the graph, barometric pressure is decreasing. The drop in pressure represents a low-pressure system. This type of system will cause an increase in cloud cover and precipitation.
explain why the density of the metal has a high inheirt percetenage of error than the value for the liquid
Answers
The density of the metal has the high inherit percentage of error than the value for the liquid because the possibility error in measuring the volume of the solid is more than the liquid.
The density is expressed as follows :
Density = mass / volume
The volume of the solid cannot be measure directly. The volume of the solid can be measured by immersing the solid in to the liquid and then we measure the volume of the liquid displaced. The possibility error in measuring the volume of the solid, especially when the shape of the solid is irregular, is more than the liquid.
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PLEASE HELP PLS PLS PLS
Methane, CH4(g), and oxygen gas, O2(g) react to produce carbon dioxide, CO2(g), and water H2O(g). What volume of methane is required to react with oxygen to produce 32.5 L of carbon dioxide? *
a) 65.0 L
b) 48.8 L
c) 16.3 L
d) 32.5 L
Answers
Answer:
D)
Explanation:
CH4 + 2O2 = CO2 + 2H2O
1 (L CO2)= 32.5(L CO2)
1 (CH4) = 32.5 (L CH4)
You would like to make a phosphate buffer with a pH of 7.40 using phosphoric acid (H3PO4) or its conjugate bases. Which acid and conjugate base would you use? The pka values for phosphoric acid are 2.16. 7.21, and 12.32. a OH3PO4 and NaH2PO4 b NaH2PO4 and Na2HPO4 c Na2HPO4 and Na3PO4
d H3PO4 and Na3PO4
e OH3PO4 and H20
Answers
To make a phosphate buffer with a pH of 7.40, we need to select an acid and its conjugate base with pKa values that bracket the desired pH. In this case, the pKa values of phosphoric acid (H3PO4) are 2.16, 7.21, and 12.32.
We want the pH to be higher than the pKa of the acid and lower than the pKa of the conjugate base. From the given pKa values, the pH of 7.40 falls between the pKa values of 7.21 and 12.32.
Therefore, we would use the acid with pKa 7.21 and its conjugate base with pKa 12.32.
The correct choice for the acid and conjugate base pair would be:
b) NaH2PO4 (dihydrogen phosphate) and Na2HPO4 (monohydrogen phosphate)
This combination of NaH2PO4 (the acid) and Na2HPO4 (the conjugate base) can be used to prepare a phosphate buffer with a pH of 7.40.
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Q3.
Rock salt is a mixture of sand and salt.
Salt dissolves in water. Sand does not dissolve in water.
Some students separated rock salt.
This is the method used.
1.
2.
3.
(c)
4.
5.
(a)
(b)
Place the rock salt in a beaker.
Add 100 cm³ of cold water.
Allow the sand to settle to the bottom of the beaker.
Carefully pour the salty water into an evaporating dish.
Heat the contents of the evaporating dish with a Bunsen burner until salt crystals
start to form.
Suggest one improvement to step 2 to make sure all the salt is dissolved in the
water.
The salty water in step 4 still contained very small grains of sand.
Suggest one improvement to step 4 to remove all the sand.
Suggest one safety precaution the students should take in step 5.
€
(1)
Answers
To ensure that all the salt is dissolved in the water in step 2, one improvement could be to stir the mixture gently.
In step 5, where the contents of the evaporating dish are heated with a Bunsen burner, it is important for the students to take a safety precaution.
By stirring, the surface area of the salt particles in contact with the water increases, allowing for faster dissolution. This will help to ensure that the salt completely dissolves in the water before moving on to the next step.
To remove all the sand from the salty water in step 4, one improvement could be to use a filtration step. After allowing the sand to settle to the bottom of the beaker, the students can carefully pour the salty water through a filter paper or a fine-mesh sieve. This will help to separate the water from the sand particles, ensuring that only the clear salty water is collected in the evaporating dish.
In step 5, where the contents of the evaporating dish are heated with a Bunsen burner, it is important for the students to take a safety precaution. They should make sure to wear heat-resistant gloves or use tongs to handle the evaporating dish. The dish will become hot during the heating process, and direct contact with bare hands could lead to burns. By using proper protective equipment, the students can minimize the risk of injury and ensure their safety during the heating step.
Overall, these improvements and safety precautions will help to enhance the effectiveness and safety of the rock salt separation process carried out by the students.
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determine the ph change when 0.071 mol hclo4 is added to 1.00 l of a buffer solution that is 0.435 m in hno2 and 0.283 m in no2-.
Answers
The \(p^{H}\) change is -0.092.
To measure the acidity or alkalinity of a sample, we use the \(p^{H}\) scale.
⇒ \(H^{+} + NO_{2}\) ⇄ \(HNO_{2}\)
when we add \(Hcl_{4}\), then the following takes place
\(NO^{-} _{2}\) + \(H ^{+}\) from \(Hcl_{4}\) → \(HNO_{2}\)
⇒ Moles of \(HNO_{2}\) = 0.435 - 0.071
= 0.364 mole
⇒ Moles of \(NO^{-} _{2}\) = 0.283 - 0.071
= 0.212 mole
⇒ \(P^{ka}\) + \(HNO_{2}\) = 3.15 ( from the table )
⇒ \(P^{H}\) after addition
\(P^{H}\) = \(P^{ka}\) + log( salt / acid )
= \(P^{ka}\) + log( \(NO^{-} _{2}\) / \(HNO_{2}\) )
= 3.15 + log( 0.212 / 0.364 )
= 3.15 + log( 0.582 )
= 3.15 + ( -0.235 )
\(P^{H}\) = 2.915
⇒ \(P^{H}\) after deletion
\(P^{H}\) = \(P^{ka}\) + log( salt / acid )
= \(P^{ka}\) + log( \(NO^{-} _{2}\) / \(HNO_{2}\) )
= 3.15 + log( 0.283 / 0.435 )
= 3.15 + log( 0.718 )
= 3.15 + ( -0.143 )
\(P^{H}\) = 3.007
\(P^{H}\) change Δ \(P^{H}\) = \(P^{H}\) after addition - \(P^{H}\) after deletion
= 2.915 - 3.007
Δ \(P^{H}\) = -0.092
Therefore, Δ \(P^{H}\) is -0.092 when 0.071 mol hclo4 is added to 1.00 l of a buffer solution that is 0.435 m in hno2 and 0.283 m in no2-.
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calculate the concentration of an hcl solution if 50 ml is titrated with a 5 m solution of naoh, and the buret delivers 15 ml to reach the end point.
Answers
Answer:
Explanation:
Solution
verified
Verified by Toppr
Correct option is B)
HCl+NaOH→NaCl+H
2
O
In this chemical reaction, the molar ratio is 1:1 between HCl and NaOH.
So, moles of HCl = moles of NaOH
M
HCl
× Volume of HCl = M
NaOH
× Volume of NaOH
M
HCl
=
volumeofHCl
M
NaOH
×volumeofNaOH
M
HCl
=
50.00ml
25.00ml×1.00M
M
HCl
=0.50MHCl
So, the concentration of HCl is 0.50M.
Video Explanation
How many atoms of potassium are needed to combine with one atom of chlorine
Answers
Answer:
1 atom
Explanation:
I'm not sure but
Chlorine have valency - 1
Sum of compound = 0
So K¹CL¯¹
Only one atom of potassium is needed to combine with one atom of chlorine, its form KCl (Potassium Chloride) by combining to each other.
What is an Atomic Structure?Atomic structure is the structure of an atom having a nucleus at the centre in which the protons, positively charged particles and neutrons, neutral in nature are present. Protons and neutrons together called as Nucleons. Electrons, negatively charged particles revolve around the centre of these Nucleons.
These subatomic particles like protons, neutrons, and electrons are made up of smaller substances. These substances are called quarks and leptons.
An atom shows how many protons is present in its nucleus, this is known as atomic number. This atomic number determines the type of atom. Each and every atomic number represent a specific chemical element. Each chemical element has a unique atomic number.
For example, Helium has an atomic number of 2 because helium atom has two proton in its nucleus. No other element has an atomic number of 2.
So, only one atom of potassium is needed to combine with one atom of chlorine, its form KCl (Potassium Chloride) by combining to each other.
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What is the mass of 0.45 mol of ammonium sulfate, (NH4)2SO4?
Answers
Answer:
59.46 g
Explanation:
To answer this question, the molecular weight of ammonium sulfate must be computed. To accomplish this, the weights of the individual elements must be noted.
N=14.01\(\frac{g}{mol}\)
H=1.01\(\frac{g}{mol}\)
S=32.07\(\frac{g}{mol}\)
O=16.00\(\frac{g}{mol}\)
To compute the molecular weight:
\(2[14.01\frac{g}{mol}+4(1.01\frac{g}{mol})]+32.07\frac{g}{mol}+4(16.00\frac{g}{mol})=132.14\frac{g}{mol}\)
To calculate the mass:
\(0.45 mol(\frac{132.14g}{1mol})=59.463g\)
if you mistakenly extract the solution first with naoh (aq), and then with nahco3(aq), what results you will observe and why?
Answers
The NaOH extraction step would remove some acidic components, while the NaHCO3 extraction step may have limited effect if the significant acidic components have already been neutralized.
If you mistakenly extract a solution first with NaOH (aq) and then with NaHCO3 (aq), you would observe the following results:
NaOH Extraction:
When NaOH (aq) is added to the solution, it will react with acidic components present in the solution, such as carboxylic acids, phenols, or acidic functional groups. This reaction results in the formation of water-soluble salts or compounds, which will dissolve in the aqueous NaOH solution. As a result, the acidic components will be removed from the solution.
NaHCO3 Extraction:
When NaHCO3 (aq) is added to the remaining solution from the previous step, it will react with acidic components that were not neutralized by NaOH. NaHCO3 is a weaker base compared to NaOH and is primarily used to extract acidic compounds such as phenols and carboxylic acids. These acidic components will react with NaHCO3 to form water-soluble salts, which will dissolve in the aqueous NaHCO3 solution.
However, if NaOH is mistakenly used first, it is possible that some acidic components in the solution may have already reacted and been removed in the previous step. Therefore, the NaHCO3 extraction step may not yield significant additional changes or observable results.The results of mistakenly extracting the solution first with NaOH (aq) and then with NaHCO3 (aq) would depend on the nature and concentration of the acidic components present in the solution.
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Write a balanced Al(s), Ba(s), Ag(s), and Na(s) for the synthesis reaction of Br2(g).
Answers
The synthesis reaction of Br2(g) with Al(s), Ba(s), Ag(s), and Na(s) are as follows:Br2(g) + 2 Al(s) → 2 AlBr3(s)3 Br2(g) + Ba(s) → BaBr6(s)2 Ag(s) + Br2(g) → 2 AgBr(s)2 Na(s) + Br2(g) → 2 NaBr(s)
Balanced equation for the synthesis reaction of Br2(g) with Al(s), Ba(s), Ag(s), and Na(s)Br2(g) + 2 Al(s) → 2 AlBr3(s) 3 Br2(g) + Ba(s) → BaBr6(s) 2 Ag(s) + Br2(g) → 2 AgBr(s) 2 Na(s) + Br2(g) → 2 NaBr(s)The synthesis reaction of Br2(g) can be carried out using different metals such as Al(s), Ba(s), Ag(s), and Na(s). The balanced chemical equation for the reaction will be based on the type of metal used. However, all of the reactions will produce a metal bromide salt.The first equation represents the reaction of Br2(g) with aluminum. This reaction results in the formation of aluminum tribromide salt. The balanced chemical equation for the reaction is as follows:Br2(g) + 2 Al(s) → 2 AlBr3(s)The second equation represents the reaction of Br2(g) with barium. This reaction results in the formation of barium hexabromide salt. The balanced chemical equation for the reaction is as follows:3 Br2(g) + Ba(s) → BaBr6(s)The third equation represents the reaction of Br2(g) with silver. This reaction results in the formation of silver bromide salt. The balanced chemical equation for the reaction is as follows:2 Ag(s) + Br2(g) → 2 AgBr(s)The fourth equation represents the reaction of Br2(g) with sodium. This reaction results in the formation of sodium bromide salt. The balanced chemical equation for the reaction is as follows:2 Na(s) + Br2(g) → 2 NaBr(s)In conclusion, the balanced chemical equations for
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