3. Which of the following statements about matter is FALSE?
O Matter can be classified as an element and a mixture.
O Matter is anything that occupies and has mass.
O Matter exhibits two types of change: physical and chemical.
O Mafter refers to everything that makes up the entire universe.

Answer:

See explanation.

Explanation:

Hello there!

In this case, according to the described chemical reaction, we first write the corresponding equation to obtain:

\(Cu+2AgNO_3\rightarrow 2Ag+Cu(NO_3)_2\)

Thus, we proceed as follows:

Part 1 of 3: here, since the molar mass of silver and copper (II) nitrate are 107.87 and 187.55 g/mol respectively, and the mole ratio of the former to the latter is 2:1, we can set up the following stoichiometric expression:

\(m_{Cu(NO_3)_2}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu(NO_3)_2}{2molAg}*\frac{187.55gCu(NO_3)_2}{1molCu(NO_3)_2} \\\\m_{Cu(NO_3)_2}=1.12gCu(NO_3)_2\)

Part 2 of 3: here, the molar mass of copper is 63.55 g/mol and the mole ratio of silver to copper is 2:1, the mass of the former that was used to start the reaction was:

\(m_{Cu}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{1molCu}{2molAg}*\frac{63.55gCu)_2}{1molCu} \\\\m_{Cu}=0.380gCu\)

Part 3 of 3: here, the molar mass of silver nitrate is 169.87 g/mol and their mole ratio 2:2, thus, the mass of initial silver nitrate is:

\(m_{AgNO_3}=1.29gAg*\frac{1molAg}{107.87gAg}*\frac{2molAgNO_3}{2molAg}*\frac{169.87gAgNO_3}{1molAgNO_3} \\\\m_{AgNO_3}=2.03gAgNO_3\)

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The rapid destruction of tropical rain forests is harmful because it reduces habitats for animals and plants, leading to a decrease in biodiversity.

It can also cause climate change due to reduced carbon absorption and an increase in heat-trapping greenhouse gases, resulting in more extreme weather patterns.  The destruction of tropical rain forests is a serious concern, with millions of acres destroyed worldwide each year. This destruction can be attributed to many causes, such as illegal logging, wildfires, over-farming and over-grazing. As a result, essential services and resources provided by the forests, such as clean water and soil health, are diminished. Additionally, the trees themselves can store large amounts of carbon, which is released into the atmosphere when they are burned or cut down. This further contributes to climate change, as carbon dioxide is a major heat-trapping greenhouse gas. Furthermore, deforestation reduces the habitats of many animals, leading to a decrease in biodiversity.

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Answer:

No, it is not an example of a mutation.

Explanation:

Mutations occur in the chromosomes of the organism, in this case the fly. A mutation is a permanent alteration in the DNA of the fly. Therefore, if the fly were to have purple wings when it was born then it would be a mutation. However, in this case we dyed the wings of the fly purple. This does not alter or change the DNA in any way to cause a mutation.

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- Kay

The standard free-energy change at 25 ∘C for the given reaction, Mg(s)+Fe₂+(aq)→Mg₂+(aq)+Fe(s) can be calculated using the equation:ΔG∘ = ΣnΔGf∘ (products) − ΣnΔGf∘ (reactants)where ΔGf∘ is the standard free energy of formation of the compound, n is the stoichiometric coefficient of each compound in the reaction.

The values of ΔGf∘ for the given reaction are:

Mg₂+ (aq):−467.2 kJ/mol Fe(s): 0 kJ/mol Fe₂+(aq): −237.2 kJ/mol Mg(s): 0 kJ/molΔG∘ =

ΣnΔGf∘ (products) − ΣnΔGf∘ (reactants)ΔG∘ =

[ΔGf∘ (Mg₂+ (aq)) + ΔGf∘ (Fe(s))] - [ΔGf∘ (Mg(s)) + ΔGf∘ (Fe₂+(aq))]ΔG∘ =

[−467.2 kJ/mol + 0 kJ/mol] - [0 kJ/mol + (−237.2 kJ/mol)]ΔG∘ =

−230.0 kJ/mol At 25 ∘C, the standard free-energy change for the given reaction is −230.0 kJ/mol. The units of ΔG∘ are kilojoules per mole (kJ/mol). Hence, the answer is -230.0 kJ/mol.

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The term IE1 refers to the first ionization energy, which is the energy required to remove the first electron from an atom. Generally, as you move across a period in the periodic table, the IE1 increases due to an increase in effective nuclear charge, which makes it more difficult to remove an electron. As you move down a group, the IE1 generally decreases due to an increase in distance between the nucleus and outer electrons.

In this case, we are given four elements: Mg (magnesium), Cl (chlorine), P (phosphorus), and Rb (rubidium). To arrange them in order of increasing IE1, we need to consider their positions in the periodic table.

Starting with the first option, Cl is the first element, which is located in group 17 (also known as the halogens) and period 3. P is next, located in group 15 (also known as the pnictogens) and period 3. Rb is in group 1 (also known as the alkali metals) and period 5. Mg is the last element, located in group 2 (also known as the alkaline earth metals) and period 3.

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This means that the solution with pH₆ has one thousand times less hydrogen ions compared to a solution with pH₃. The correct option is b) one thousand times less.

We know that pH is the negative log of hydrogen ions concentration in a solution.

So, pH is given as:

pH = -log[H+]

The hydrogen ions concentration can be calculated as:

[H+] = 10^-pH

Now, the given pH values are:

For solution 1,

pH = 6

For solution 2, pH = 3

The hydrogen ions concentration in solution 1 can be calculated as:

[H+]1 = 10^-6

The hydrogen ions concentration in solution 2 can be calculated as:

[H+]2 = 10^-3

Now, to find the ratio of hydrogen ion concentrations in solution 1 and solution 2,

we can divide [H+]1 by [H+]2.

[H+]1/[H+]2 = 10^-6/10^-3

= 10⁻⁶ × 10³

= 10⁻³

So, we can see that [H+]1/[H+]2 = 10⁻³.

This means that the solution with pH 6 has one thousand times less hydrogen ions compared to a solution with pH 3.

Therefore, the correct option is b) one thousand times less.

the final answer is one thousand times less.

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Answer:

C3H8(g) + 5O2(g) —> 3CO2(g) + 4H2O(g)

Explanation:

The burning of propane is simply called Combustion of propane.

When an organic compound under goes Combustion, carbon dioxide, CO2 and water, H2O are produced respectively.

Thus, the burning of propane will yield the following:

C3H8(g) + O2(g) —> CO2(g) + H2O(g)

Now, let us balance the equation. This is illustrated below:

C3H8(g) + O2(g) —> CO2(g) + H2O(g)

There are 3 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 3 in front of CO2 as shown below:

C3H8(g) + O2(g) —> 3CO2(g) + H2O(g)

There are 8 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of H2O as shown below:

C3H8(g) + O2(g) —> 3CO2(g) + 4H2O(g)

There are 2 atoms of O on the left side and a total of 10 atoms on the right side. It can be balance by putting 5 in front of O2 as shown below:

C3H8(g) + 5O2(g) —> 3CO2(g) + 4H2O(g)

Now, the equation is balanced.

The amount of heat evolved by a reaction is, 53.84 kJ

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

q = [q1 + q2]

q = [c1× ∆T]+[m2×c2×∆T]

where,

q = heat released by the reaction

q1 = heat absorbed by the calorimeter

q2 = heat absorbed by the water

c1 = specific heat of calorimeter = 600 j/g°c

c2 = specific heat of water = 4.184 j/g°c

m2 = mass of water = 500 g

∆T = change in temperature = 20°c

Now put all the given values in the above formula, we get:

q = (600×20) + (500×4.184×20)

q = 12000 + 41840

q = 53840 J

q = 53.84 kJ

Therefore, the amount of heat evolved by a reaction is, 53.84 kJ

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Explanation:

So if V œ T, then V = kT ; if we solve for k under different conditions of volume and temperature......

\( \frac{v1}{t1} = \frac{v2}{t2} \)

temperature is measured in degrees Kelvin.

And

\( v2 = \frac{v1}{t1} \times t2 = \frac{275 . ml}{298 \: . \: k } \times 403 \: . \: k = ?\)

?mL

0.403 L is the new volume where the initial volume is 275 mL and the initial temperature is 273 K.

Gas laws relate to the pressure, volume, and temperature of a gas. Boyle's law—named for Robert Boyle—states that, at constant temperature, the pressure P of a gas varies inversely with its volume V, or PV = k, where k is a constant.

The relationship between volume and temperature is: \(\frac{V_1}{T_1} =\frac{V_2}{T_2}\) where \(V_1\)and \(T_1\) are the initial volumes and \(V_2\) and \(T_2\) are the final volumes.

\(\frac{V_1}{T_1} =\frac{V_2}{T_2}\)

Given data:

\(V_1 =\) 275 mL, \(T_1 =\) 0

\(V_2 =\) 275 mL, \(T_2 =\) 130

Putting all the values in the equation:

\(\frac{V_1}{T_1} =\frac{V_2}{T_2}\)

\(\frac{0.275}{273} =\frac{V_2}{403}\)

\(V_2 =\) 0.403 L

Hence, 0.403 L is the new volume.

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Answer:

Molarity = 1.12 mol/L

Explanation:

To make an aqueous solution of Na₂O, the concentration will be calculated by: concentration (c) (or molarity) = number of moles present (n) ÷ volume needed (V) (in litres)

since we don't have moles, we can calculate moles by:

number of moles (n) = mass present (m) (in grams) ÷ molar mass (M) (in grams per mole), which we can find using a standard IUPAC Periodic Table

∴ n(Na₂O) = m/M = 34.8/(22.99×2+16.00) = 0.56147 mol

Now we have the number of moles present, we can calculate concentration:

∴ c(Na₂O) = n/V = 0.56147/0.50L = 1.12 mol/L

Answer:

Ok then answer my question

Explanation:

sorry i cant answer

Answer:

a) 3

b) 5

c) 4

d) it can be 1/2/3

e) it can be 2/3

f) it can be 2/3/4

g) it can be 4/5

h) 4

Explanation:

The empitical formula shows the simplest ratio of elements in a compound (not the total number of atoms in the molecule).

So to find the empirical formula we need to calculate how many moles of each atom we have in this sample. Then we will see the ratio of each element.

We are given the mass, so to convert it to moles we use the molar mass. For this we go to the periodic table and see that the values for each element are:

Na (sodium): 22,99 g/mol

H (hydrogen): 1 g/mol

P (phosphorus): 25,81 g/mol

So we calculate the moles of each element as follows:

And as we see, for every 0.833 moles of Na we have the same number of moles of P, so the ratio of these elements in the molecule is 1 to 1.

As for the hydrogen:

So the ratio Na to H is 1 to 2.

Now we can write the empirical formula as follows=

Answer:

The empirical formula is the simplest form;

Given:

Oxygen O at 94.1% and

H at 5.9%

Assume 100grams.

94% = 0.941 x 100gm. = 94.1 gm x 1mole/16gm. = 5.88 moles of O

5.9% = 0.059 x 100gm. = 5.9gm. X 1moleH/1.002gm. = 5.88 moles of H

There is one mole of O for each mole of H so the empirical formula is \(O_1H_1\)

and written as OH.

Explanation:

\(given \: that \: oxygen \: by \: 94.1\% (.941)\\ hydrogen \: by5.9\%(.059) \\ in \: 100gram \: \\ oxygen = 100 g\times .941 = 94.1 \times \frac{1(mol)}{16g} \\ = 5.88moles \: of \: oxygen \\ in \: hydrogen \: = .059\times 100 = 5.9 \times \frac{1mol}{1.002gram} \\ = 5.88mole \: of \: hydrogen \\ \: so \: here \: \: both \: oxygen \: andhydrogen = 5.88 \\their \: ratio = 1 \: 1 \\ so \: emparical \: formula = oh \\ thank \: you\)

Equilibrium partial pressures of PCl₃ , Cl₂ , and PCl₅ are 0.3atm,0.2atm and 0.6atm respectively.

In a combination of gases, every constituent gas has a partial pressure which is the notional pressure of that constituent gas as though it alone involved the whole volume of the first blend at the equivalent temperature.[1] The complete tension of an ideal gas blend is the amount of the halfway tensions of the gases in the blend (Dalton's Regulation).

The  partial pressure  of a gas is a proportion of thermodynamic action of the gas' particles. Gases break down, diffuse, and respond as per their halfway tensions yet not as per their focuses in gas blends or fluids. This overall property of gases is additionally evident in compound responses of gases in science. For instance, the fundamental measure of oxygen for human breath, and the sum that is harmful, is set by the halfway tension of oxygen alone.

This is valid across an exceptionally extensive variety of various groupings of oxygen present in different breathed in breathing gases or broke down in blood;[2] subsequently, blend proportions, similar to that of breathable 20% oxygen and 80%, not entirely settled by volume rather than by weight or mass.

Besides, the  partial pressure  of oxygen and carbon dioxide are significant boundaries in trial of blood vessel blood gases. All things considered, these pressure can likewise be estimated in, for instance, cerebrospinal liquid.

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Answer:

Electrons occupy the regions around the nucleus(energy levels) while protons and neutrons are found in the nucleus

Answer:

See below.

Explanation:

A dynamic equilibrium in chemistry refers to a situation in which the reaction of reactants to form product(s) in which the products can reverse the reaction by falling apart and back to the reactants.  Reactions that go to completion are irreversible.  In cases where reactants form products (in a forward reaction), but the products can change back into reactants (in a reverse reaction) are called reversible.

An example is the reaction of carbon dioxide with water to form carbonic acid (think soft drinks).

     CO2(g)+H2O(l) ⇌ H2CO3(aq)

As anyone who has opened a warm can of soda knows, it can erupt suddenly and spray anyone nearby with a shower of bubbly, and sticky, soda.  Carbonic acid is unstable and will happily decompose back to it's reactant molecules if given the chance.

Experience tells us what to expect when giving a brother or sister a can of warm soda that you've shaken hard for a minute.  But if you are a chemist, such responses aren't always easy to predict with a new reaction.  Equilibrium constants were developed to provide a means for presdicting the exstent of these reactions.  They are used in equilibrium equations to predict the concentrations of products and reactants, given conditions of temperature and pressure, under defined conditions of temperature and pressure.

The equations themselves include concentrations as the key input.  In the carbonic acid example, if one were to add excessive amounts of one of the reactants, one would expect the equilibrium to "shift to the right."  This simply means that more carbonic acid would be made.  The chances of the forward reaction increase as concentration increases.  The amount of CO2 given off as a gas depends on the concentration of the CO2 in the gas phase, which is given by the partial pressure of the gas.

The space above the soda and the cap represents one place that the CO2(g) can escape the solution.  The CO2 pressure in the gas phase is a measure of it's concentration.  An equilbium calculation takes this concentration in account when decidng how much much of each component is present.  Other compouns that are present may also impact the equilibrium since they may interfere with one of the reaction steps.  Pressure and emperature either dirctly impact the concentration (e.g., gases) or they affect the "effective" concentrations of the compunds.  A higher temperature creates more collisons between reactant molucules that may change the equilibrium constant..

Answer:

metaloides

Explanation:

Answer:

The answer is B.

Explanation:

The logical explanation is that fossils from animals are changing over time caused by enviroment change ,natural disaters,astronmical events,and so on.These organisms  need to adapt over time and so there features change.For Example the dragon fly used to be as big as a bus now that it has adapted and changed from when the cretaceous period it is as small as your index finger.

Answer:

bamboo is the biggest/tallest grass in the world

Answer:

Giant Bamboo

Explanation:

Giant bamboo, which can grow up to 151 feet tall, is the largest variety of grass.

The atomic theory have been developed over the years by the works of many scientists.

The atomic theory is the series of postulations that sought to explain the behavior of the atom. The study of the atom started as far back as the time of Democritus and Aristotle.

The first empirical study of the nature of the atom started with the work of John Dalton when he proposed the famous Dalton's theory. Further empirical work was carried out by J.J Thompson which gave rise to the plum pudding model of the atoms.

The work of Ernest Rutherford introduced the planetary model of the atom which was latter replaced by the Bohr model based on energy levels. Today, the work of Erwin Schrödinger has led us to the appreciation of the wave mechanical model of the atoms which is the mot accepted model for the atom today.

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Answer: 574000000

Explanation: I hope this helps!

5.74 ⇒ 57.4 ⇒ 574 ⇒5740 ⇒ 57400 ⇒ 574000 ⇒ 5740000 ⇒

57400000 ⇒ 574000000

Answer:

45km/hr

Explanation:

270/6=45

Minerals with covalent bonding, such as diamond, are typically very hard. Metallic bonding results in minerals that are malleable and ductile, but not necessarily hard.

Van der Waals bonding is weaker and results in minerals that are relatively soft and have a low melting point.

The four types of bonding that are important in minerals are covalent, metallic, Van der Waals. The property of a mineral's resistance to scratching is called hardness.

Hardness is a physical property of minerals that describes their resistance to scratching by other minerals or materials. The Mohs scale is a way of ranking minerals according to their hardness.

The scale runs from 1 (the softest mineral, talc) to 10 (the hardest mineral, diamond). Minerals with covalent bonding, such as diamond, are typically very hard. Metallic bonding results in minerals that are malleable and ductile, but not necessarily hard.

Van der Waals bonding is weaker and results in minerals that are relatively soft and have a low melting point.

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Answer:

4tbs

Explanation:

A 75-lb dog must be dewormed. If the daily dose of the dewormer is 1 tsp/25 lb of body weight for 3 days, approximately how much should be given each day?

1 tbs = 3 tsp

answer: 1 tbs

false,

sodium has a vigorous reaction with water.

This can be observed by putting a piece of sodium in water,

it moves swiftly across the surface of water and reacts violently.