3.1 Deliverables: • Working scripts that produce requesite plots Narrative (or print blocks) that supply answer questions • CCMR citations for sources (Lab 14, Lesson 9. ... is OK for using internal sources, URL for outside sources)

Answer: a = change in w =0.00656

b = q = 5.1kj/kg

Explanation:

Find explanation in the attached file

The amount of steam added to the air  a = change in w =0.00656 b = q = 5.1kj/kg

The digital game retail and distribution service Steam is provided by Valve. In order to allow Valve to automatically update its games, it was first released as a software client in September 2003. In late 2005, it was expanded to include the distribution and sale of games from other publishers.

a) We can use the absolute humidity we and wg to determine the amount

of moisture added Aw.

Aww3-W2

Aw= 0.01291 -0.00635

Aw= 0.00656

b) To determine the heat transfer q we will need the enthalpies h and h2.

kJ

kg 9 = 36.2

kJ  kg

31.1

q=5.1

kJ

kg

RESULT

Do = 0.00656

kJ

kg

9 = 5.1

Therefore, The amount of steam added to the air  a = change in w =0.00656 b = q = 5.1kj/kg

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Answer:

Option B

Explanation:

Atoms of ferromagnetic materials have north and south pole but these atoms are oriented in random directions due to which they do no exhibit magnetic properties until unless they are brought into influence of any external temporary or permanent magnetic field.

Under the influence of external magnetic force, the atoms of the ferromagnetic material get oriented in a particular direction.

Hence, option B is correct

Answer:

See explanation

Explanation:

Since no figure was given, I'll explain how to do this problem theoretically. The formula for shear flow is \(q=\frac{VQ}{I}\) where V is the shear force, Q is the moment of area (more on this later), and I is the moment of inertia.

The first step to solve this problem is to find the resultant internal forces of the beam. This can be done in several ways, but the easiest is to solve the beam statically and draw a shear diagram to determine the maximum shear force V.

The second step to solving this problem is to determine the location of the neutral axis of the cross section if it is not given. The formula for the neutral axis is  \(NA = \frac{\sum y*A}{\sum A}\). The y in this equation represents the middle of the small shapes that the web is divided into. An I-beam can be thought of as 3 rectangles, while a T-beam can be thought of as 2. The A in this formula represents the area of each of the rectangles (an I-beam will have 3 of these and a T-beam will have 2).

The third step for this problem is to find the moment of inertia. There are several formulas for moment of inertia depending on the shape of the cross section. I-beam's and T-beams both can be thought of as multiple rectangles, so they have the same base formula of \(I=\frac{1}{12}bh^3\) where b is the base of the rectangles and h is the height. For I-beams, the easiest way to calculate moment of inertia is to think of the entire cross section as a big rectangle that had two smaller rectangles cut out of it. The formula for this moment of inertia becomes \(I=\frac{1}{12} b_{big}h^{3} _{big}-\frac{1}{6}b_{small}h^{3}_{small}\). Note that this form of moment of inertia already takes into account subtracting 2 small rectangles. For T-beams, this approach will not work, so the parallel axis theorem must be used. The moment of inertia for the T-beam becomes \(I=\frac{1}{12}b_{1} h^{3}_{1} +b_{1}h_{1}dy_{1}^{2} +\frac{1}{12}b_{2} h^{3}_{2} +b_{2}h_{2}dy_{2}^{2}\) where the terms with the subscript 1 represent the first rectangle and the terms with the subscript 2 represent the second rectangle. The dy terms represent the distance from the center of that specific rectangle to the neutral axis.

The fourth step for this problem is to find Q. The formula to find Q is \(Q=\sum y'A'\) where y' represents the distance from the neutral axis to the center of the "wanted" point and A' is the area of the rectangle that has the wanted point at its center. (This would be the area above or below the thickness (t) if you were solving for maximum shear \(\tau=\frac{VQ}{It}\)).

The last step for this problem is to substitute the found values into the formula for shear flow \(q=\frac{VQ}{I}\). V came from step 1, Q came from step 4, and I came from step 3.

Answer:

For  lower disk :   V = e^θ​rω(0)/h  = 0

At the upper disk:  V = e^θ​rω(h)/h  = e^θ​rω

Hence The physical boundary conditions are satisfied

Explanation:

Velocity field ( V ) = e^θ​rωz/h

Upper disk located at  z = h

Determine the dimensions of the velocity field

velocity field is two-dimensional ; V = V( r , z )

applying the no-slip condition

condition : The no-slip condition must be satisfied

For  lower disk Vo = 0 when disk is at rest z = 0

∴  V = e^θ​rω(0)/h  = 0

At the upper disk  V = e^θ​rω  given that a upper disk it rotates at z = h

∴ V = e^θ​rω(h)/h  = e^θ​rω

Hence we can conclude that the velocity field satisfies the appropriate physical boundary conditions.

Answer:

english

Explanation:

a. Yes, because you will be working in a team of 10 design engineers and take note some of them are experienced and capable nuclear plant designers.And from what i have learn about engineers, they can't be called engineers for nothing.All you have to do is trust yourself and your team.

b.Of course i cannot but because i have my team (10 design engineers) i know i can do a great job and they are experienced in this stuff so i am confident that i can participate and can make a good job and even if i do not have any experience i know i will learn from them.I can call this assignment as my experience right?

Nuclear power plants uses nuclear fuels as a source of energy.

A nuclear power plant is a power generating plant that makes use of nuclear fuels as a source of energy for power generation. This means of power generation has the advantage that 1 g of nuclear fuel can be used for several years.

On the downside, this means of power generation is prone to hazards such as nuclear explosions and radioactive fallout. This means of power generation is ethical as long as all the safety standards are followed.

I can participate in such a design as a trainee engineer without any previous experience because participating in such project is a huge learning opportunity for me.

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It means that the gas with the lowest molecular weight will have the highest effusion rate.

The given gases' effusion rates are listed in order from highest to lowest. The effusion rate of a hydrogen molecule is the highest, whereas that of a hydrocarbon is the lowest.

A gas will effuse faster when it is lighter and more slowly when it is heavier. Helium (He) will have the highest rate of effusion since it has the lowest molecular weight (atomic weight, in this example).

The following equation can be used to compare the rate of effusion for two gases: The effusion rates in this case are inversely related to the square root of the gas molecules' masses. A container contains an amalgam of neon and argon gas.

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Answer:

Engineering drawing abbreviations and symbols are used to communicate and detail the characteristics of an engineering drawing.

There are many abbreviations common to the vocabulary of people who work with engineering drawings in the manufacture and inspection of parts and assemblies.

Technical standards exist to provide glossaries of abbreviations, acronyms, and symbols that may be found on engineering drawings. Many corporations have such standards, which define some terms and symbols specific to them; on the national and international level, like BS8110 or Eurocode 2 as an example.

Explanation:

The only process I can think of that would satisfy the conservation of energy principle but does not occur in nature is a perpetual motion machine.

Perpetual Motion Machine would produce work indefinitely without any external input of energy, thus violating the first law of thermodynamics which states that energy cannot be created or destroyed, only converted from one form to another.

While it is theoretically possible to design a machine that appears to produce more energy than it consumes, such a machine cannot exist in reality due to the various energy losses that occur in any real-world system.

These losses can occur due to factors such as friction, heat transfer, and resistance in electrical circuits, among others.

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Answer:

b

Explanation:

A closed section will have a bottom surface.

It is to be noted that all UHRS platforms are optimized for the popular kinds of internet browser applications.

The Universal Human Relevance System (UHRS) is a crowdsourcing platform that allows for data labeling for a variety of AI application situations.

Vendor partners link people referred to as "judges" to offer data labeling at scale for us. All UHRS judges are bound by an NDA, ensuring that data is kept protected.

A browser is a software tool that allows you to see and interact with all of the knowledgeon the World Wide Web. Web sites, movies, and photos are all examples of this.

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If people see a well-known film that encourages and even glorify a particular conduct.

The term "behavior" in psychology refers to the distinctive characteristics or aspects that characterize how a person behaves, especially toward others and under particular circumstances, such as while intoxicated, stimulated, joyful, suffering from a disease or illness, etc. Reinforcement is a term used frequently in psychology to describe the strengthening and acting out of a desirable behavior that is being demonstrated by a live organism, particularly through the application of stimuli. Thus, psychologists believe that positive reinforcement is the most successful reinforcement strategy for conditioning because it finally implies that positive reinforcement usually results in an individual exhibiting a desirable behavior in the future.

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The egg-shaped surfaces machined onto a camshaft are called the Camshaft lobes.

As the camshaft rotates, lobes (referred to as cams) push against the valves to open them; the valves' springs close the valves back up. This is a crucial task that can significantly affect how well an engine performs at various speeds.

As long as the wear on the lobes is not extreme, camshafts can be rebuilt. Examples of a rebuildable and non-rebuildable camshaft are shown above.

The term "camshaft lobes" refers to the egg-shaped surfaces machined onto a camshaft.

Thus, answer is Camshaft lobes.

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MicroSD cards are fingernail-size expansion cards that plug into slots on laptops, tablets, and cell phones.

These cards are designed to provide additional storage capacity for the devices they are used with.  With their small form factor, microSD cards offer a convenient and portable solution for expanding the storage capabilities of mobile devices. They are commonly used to store files such as photos, videos, music, and documents.

MicroSD cards utilize flash memory technology, which allows for fast and reliable data transfer rates. They are available in different storage capacities, ranging from a few gigabytes to several terabytes. The capacity of the card needed will depend on the user's specific requirements and the amount of data they intend to store.

To use a microSD card, one simply needs to insert it into the designated slot on the device. This enables the device to access and store data on the card, expanding its storage capacity and allowing for more flexibility in managing digital files.

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To prevent wear and lower the likelihood that either the pin or the clevis may fail, clevis pins should be tightly fitted to the holes in the clevis.

Threaded and unthreaded clevis pins are the two primary varieties. Unthreaded clevis pins feature a domed head on one end and a cross-hole on the other. A split pin or cotter pin secures the clevis pin in place (used in the USA). A formed head and a partially threaded shank are characteristics of threaded clevis pins. When putting the pin into the shackle, the formed head's cross-holed flat tab and lip act as a stop. Because of the flattened tab and the cross-hole, the pin may be moused easily during installation.

Although a bolt can serve as a clevis pin, it is not designed to withstand the lateral force that a clevis pin must withstand. While clevis pins and bolts are made to endure shearing forces, normal bolts are made to bear tension stresses.

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Answer:

Following are the solution to the given question:

Explanation:

Line voltage:

\(V_L=\sqrt{3}V_{ph}=\sqrt{3}(120) \ v\)

Power supplied to the load:

\(P_{L}=\sqrt{3}V_{L}I_{L} \cos \phi\)

\(10\times 10^3=\sqrt{3}(120 \sqrt{3}) I_{L}\ (0.85)\\\\I_{L}= 32.68\ A\)

Check wye-connection, for the phase current:

\(I_{ph}=I_L= 32.68\ A\)

Therefore,

Phasor currents: \(32.68 \angle 0^{\circ} \ A \ ,\ 32.68 \angle 120^{\circ} \ A\ ,\ and\ 32.68 -\angle 120^{\circ} \ A\)  

Magnitude of the per-phase load impedance:

\(Z_{ph}=\frac{V_{ph}}{I_{ph}}=\frac{120}{32.68}=3.672 \ \Omega\)

Phase angle:

\(\phi = \cos^{-1} \ (0.85) =31.79^{\circ}\)

Please find the phasor diagram in the attached file.

b. False, Emergency lighting is used during power outages or failures to ensure safety and visibility, while additional lighting refers to supplementary illumination added to improve lighting conditions.

They serve different purposes and are not interchangeable. Emergency lighting refers to the lighting systems that are designed to operate when the power supply to the normal lighting fails, such as during a power outage or in the event of an emergency. These systems are critical for ensuring the safety of people in buildings, especially in situations where a rapid evacuation may be required. Emergency lighting can take many forms, including exit signs, illuminated escape route signs, and high-visibility low-level lighting. These systems are typically powered by batteries or generators and are required by law in many countries to be installed in commercial and public buildings. Effective emergency lighting can help to reduce the risk of injury or loss of life during an emergency, making it a crucial aspect of building design and safety planning.

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An employee who believes they have been discriminated against for reporting a safety or health hazard has 30 days from the date of the alleged discrimination to file a complaint with OSHA.

This is in accordance with the whistleblower protection provisions of the Occupational Safety and Health (OSH) Act.

It is important for employees to report safety and health hazards without fear of retaliation, and OSHA takes such complaints very seriously.

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Answer:

Construction, the techniques and industry involved in the assembly and ... Early building materials were perishable, such as leaves, branches, and animal hides. ... The well-developed masonry technology of Mesopotamia was used to build large ... although its precise description is unknown; the concealed faces of stones

Explanation:

20

Explanation:

Technician A says that primary vibration is created by slight differences in the inertia of the pistons between top dead center and bottom dead center. Technician B says that secondary vibration is a strong low-frequency vibration caused by the movement of the piston traveling up and down the cylinder. Who is correct? O A. Neither Technician A nor B OB. Technician B O C. Both Technicians A and B D. Technician A​

Main Answer:

The Bureau of Indian standards developed the national electric code, the national building code, and the national fire prevention code.

Sub heading:

explain BIS?

Explanation:

1.BIS-bureau of indian standard is the national standard body of india.

2.BIS is responbility for the harmonious deve;opment of the activities of standardization.marking .

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The correct answer choice for implementing the enqueue() method in a queue with a linked list in Java is append().

When implementing a queue using a linked list, the enqueue operation adds an element to the end of the list, as it follows the FIFO (First-In-First-Out) principle. The append() method in the linked list class would typically be used to add a new element at the end of the list, making it the most appropriate choice for the enqueue operation.

The other answer choices are not directly related to the enqueue operation in a queue implementation using a linked list:

removeafter() is used to remove an element after a specified node, which is not necessary for the enqueue operation.

prepend() is used to add an element at the beginning of the list, which does not follow the FIFO principle of a queue.

insertafter() is used to insert an element after a specified node, but it is not typically used in the enqueue operation of a queue.

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Both Tech A and Tech B are correct in their statements about planetary gear sets, but they are describing different scenarios.

Tech A is correct in saying that to obtain a direct drive or a 1:1 gear ratio in a planetary gear set, the transmission locks together any two members of the set. This can be achieved by locking either the sun gear, the planet carrier, or the ring gear, depending on the specific configuration and desired gear ratio.

Tech B is correct in saying that to obtain reverse in a planetary gear set, the ring gear is attached to the output shaft (the driven component) while the planet carrier is held stationary. By keeping the planet carrier fixed, the rotation of the sun gear is transferred to the ring gear in the opposite direction, resulting in a reverse gear ratio.

In summary, both Tech A and Tech B are providing accurate information about the operation of a planetary gear set. Tech A explains the concept of obtaining a direct drive or a 1:1 gear ratio by locking two members together, while Tech B describes how reverse can be achieved by holding the planet carrier stationary and attaching the ring gear to the output shaft.

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Answer:

The total people are at the concert

= 296

Explanation:

a) Data and Calculations:

Ratio of the number of people singing along at the concert to the number of people not singing along

= 3:5

The number of more people not singing along = 180

Therefore, the total number of people not singing along = 185 (180 +5)

Every person singing along = 185/5 * 3 = 111

Total number of people at the concert = number of people not singing along plus number of people singing along

= 185 + 111

= 296

Answer:

recombinant human growth

Explanation:

Answer:

recombinant human growth

Explanation:

yes

If diverse current-bearing conductors are integrated into a raceway, the ampacity of the conductors must be altered to accommodate the elevated amount of heat released due to their close contact.

The recalculation factor relies on the kind of raceway, the number of victuals, and the caliber of the victuals.

As an illustration, per the National Electrical Code (NEC), if five flow conductors inhabit a metal tube, the adjustment portion for 90°C rated cables is fifty percent. This implies that the ampacity of the lines ought to be multiplied by 0.5 or thinned out by half.

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Answer:

No matter what u post on a football page, some fatherless dude will either say "pessi" or "penaldo"

Answer:

Soap and water

Explanation:

   then report the injury....