Answer:
This is all I could do I don't know what you wanted or if I did the graphing correctly but this should help find ranges
how many lattice paths exist from ( 0 , 0 ) (0,0) to ( 17 , 15 ) (17,15) that pass through ( 7 , 5 ) (7,5)?
There are 7,210,800 lattice paths from (0,0) to (17,15) through (7,5) calculated using the principle of inclusion-exclusion.
To begin with, we number the number of cross-section ways from (0,0) to (17,15) without any limitations. To do this, we have to take add up to 17 steps to the proper and 15 steps up, for a add up to 32 steps.
We will speak to each step by an R or U (for right or up), and so the issue decreases to checking the number of stages of 17 R's and 15 U's. This will be calculated as:
(32 select 15) = 8,008,015
Next, we check the number of grid ways from (0,0) to (7,5) and from (7,5) to (17,15). To tally the number of ways from (0,0) to (7,5), we have to take add up to 7 steps to the proper and 5 steps up, to add up to 12 steps.
The number of such ways is (12 select 5) = 792. To check the number of ways from (7,5) to (17,15), we have to take add up to 10 steps to the proper and 10 steps up, to add up to 20 steps.
The number of such ways is (20 select 10) = 184,756.
In any case, we have double-counted the ways that pass through (7,5).
To adjust for this, subtract the number of paths from (0,0) to (7.5) that pass through (7.5) and the number of paths from (7.5) to (17.15 ) that also pass through (7.5).
To tally the number of ways from (0,0) to (7,5) that pass through (7,5), we got to take a add up to of 6 steps to the correct and 4 steps up, for a add up to 10 steps.
The number of such paths is (10 select 4) = 210. To count the number of ways from (7,5) to (17,15) that pass through (7,5), we have to take add up to 3 steps to the right and 5 steps up, to add up to 8 steps.
The number of such ways is (8 select 3) = 56.
Subsequently, the number of grid ways from (0,0) to (17,15) that pass through (7,5) is:
(32 select 15) - (12 select 5)(20 select 10) + (10 select 4)(8 select 3) = 7,210,800
So there are 7,210,800 grid paths from (0,0) to (17,15) through (7,5).
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Some objects, like the wrecking ball, have energy as a result of their motion.
4. How does the wrecking ball have the potential to exert force on another object?
The energy transferred to any object by wrecking ball is proportional to force exerted on the object.
What is law of conservation of energy?
The law of conservation of energy states that energy can never be created nor destroyed but can be converted from one form to another.
The wrecking ball, have energy as a result of their motion and this energy is known as kinetic energy.
K.E = ¹/₂mv
where;
v is the velocity of the wrecking ball in motion.Based on the law of conservation of energy, when a wrecking ball hits another object, some of its kinetic energy will be transferred to the object while some of the kinetic energy will be converted into thermal energy.
The energy transferred to any object by wrecking ball is proportional to force exerted on the object.
K.E = force x displacement
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i need some help please!!
What is the volume of this cube?
Answer: 1 inc^3
Step-by-step explanation:
V = A^3
Where a = side
V = 1 ^3
V = 1 inch^3
Or in meteres it is 1.6387064e-5
Step-by-step explanation:
HOPE THIS HELPS IF NOT SORRYYYY !!!!!
Two airplanes leave the airport. Plane A departs at a 41° angle from the runway, and plane B departs at a 43° angle from the runway. Which plane was farther away from the airport when it was 5 miles from the ground? Round the solutions to the nearest hundredth. Plane A because it was 7. 62 miles away Plane A because it was 6. 63 miles away Plane B because it was 6. 84 miles away Plane B because it was 7. 33 miles away.
Plane B was farther away from the airport when it was 5 miles from the ground. To determine which plane was farther away from the airport when it was 5 miles from the ground, we can use trigonometry.
We can consider the situation as a right triangle, with the distance from the airport as the hypotenuse and the altitude as one of the legs. For Plane A, the angle of departure is 41°. Using trigonometry, we can calculate the distance from the airport as follows:
Distance_A = altitude / sin(angle) = 5 / sin(41°) ≈ 7.62 miles.
For Plane B, the angle of departure is 43°. Similarly, we can calculate the distance from the airport as:
Distance_B = altitude / sin(angle) = 5 / sin(43°) ≈ 6.84 miles.
Comparing the distances, we find that Plane B was farther away from the airport when it was 5 miles from the ground, with a distance of approximately 6.84 miles, while Plane A was approximately 7.62 miles away. Therefore, the correct answer is "Plane B because it was 6.84 miles away."
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Answer please ASAP thank you
Answer:
1. quadrilateral, four,four
2.triangle, three, three
3. triangle, three, three
4. quadrilateral, four, four
5. triangle, three, three
Sandra needs a new bicycle tire. Her tire has a circumference of about 113,04 inches. What is the radius of her tire?
Answer:
113,04 square root is 10.632027088 divided by Pi
3.38427933228
so the radius of her tire is 3.38
Hope This Helps!!!
write the equation of the line that passes through the given point and parallel to: (1,2) ; y=2x+1
prove that on a surface s, the sum of the x-intercept y-intercept and z-intercept at any point on the tangent plane is k^2
To prove the sum of all the intercepts = k^2
xi + yj +zk = k^2
The gradient of the function f(x,y,z) = s
f(x,y,z = 1/2sxi + 1/2 syj =1/2 szk
And the tangent plane at the point (xo,yo,zo) is
sx/x + sy/y + sz/z
= sxo/xo + syo/yo + szo/zo
=> sxo/xo + syo/yo + szo/zo = k ........(1)
To find the x intercept , we set y =z=0 and obtain x = ksxo/sx. similarly, y = ksyo/yo and z= kszo/zo. their sum is
ksxo/xo + ksyo/yo + kszo/zo
=k( sx0/xo + syo/yo + szo/zo)
=k.k = k^2 ...from eqn 1
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Question 6 (2 points)
The parabola is in intercept form.
y=(x+1)(x+7)
The vertex is
Blank 1:
Blank 2:
Answer:
Blank 1: (-7,0)
Blank 2: (-1,0)
Step-by-step explanation:
Plug x=0 into the equation and solve the resulting equation y=7 for y
Plug y=0 into the equation and solve the resulting equation 0=(x+1)(x+7) for x
Need help with the following Questions
How would you calculate the distance in miles between two people on the same line of latitude? First, sum to the total distance between the points in degrees, then multiply that sum by the statute miles per degree for the shared line of latitude. (Hint: Sometimes it is easier to visualize this by plotting it on a graph).
A. How many miles are between the following two locations: 60°N, 30°W & 60°N 50°E
B. How many miles are between the following two locations: 30°S, 60°W & 30°S 90°E
The distance between two locations on the same line of latitude can be calculated by summing the total distance between the points in degrees and multiplying it by the statute miles per degree for the shared line of latitude.
To calculate the distance in miles between two locations on the same line of latitude, we first need to find the total distance between the points in degrees. In the case of location A, which is 60°N, 30°W, and location B, which is 60°N, 50°E, the total distance between the two points is 80 degrees (50°E - 30°W).
Next, we need to multiply the sum of the degrees by the statute miles per degree for the shared line of latitude. Since the line of latitude is 60°N, we need to determine the statute miles per degree at that latitude.
The Earth's circumference at the equator is approximately 24,901 miles, and since a circle is divided into 360 degrees, the distance per degree at the equator is approximately 69.17 miles (24,901 miles / 360 degrees).
Multiplying the total distance in degrees (80 degrees) by the statute miles per degree (69.17 miles), we find that the distance between the two locations is approximately 5,533.6 miles.
Similarly, for location C, which is 30°S, 60°W, and location D, which is 30°S, 90°E, the total distance between the points is 150 degrees (90°E - 60°W). Since the line of latitude is 30°S, we use the same statute miles per degree value (69.17 miles).
Multiplying the total distance in degrees (150 degrees) by the statute miles per degree (69.17 miles), we find that the distance between the two locations is approximately 10,375.5 miles.
Therefore, the distance between locations A and B is approximately 5,533.6 miles, and the distance between locations C and D is approximately 10,375.5 miles, when calculated using the given method.
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A and B are complementary angles. If mA = (x - 22)° and
m/B=(x-16)°, then find the measure of A.
Answer:
Complementary angles have a sum of 90°.
(x - 22) + (x - 16) = 90
2x - 38 = 90
2x = 128
x = 64
Substitute x into angle A
A = 64 - 22 = 42°
Write the equation of a line that passes through the points (4,6) and (−8,3)
Answer:
y= 1/4x+5
Step-by-step explanation:
y=mx+c
to calculate gradient: change in y/change in x
-3/-12 = 0.25
y = 1/4x+c
4 * 1/4 = 1
6-1 = 5
c= 5
Totally:
y= 1/4x+5
Which of the following would produce a graph that is the reflection of f(x)= (x−3)2−4 across the x-axis?
Answer:
c took the quiz on edge 2020
Answer:
\(x2 - 6x + 5\)
Step-by-step explanation:
The function f(x) = (x-3)^2 - 4
This can be written as ;
(x-3)(x-3) -4
x(x-3)-3(x-3)-4
\(x2 - 3x - 3x + 9 - 4 \)
find the determinant of the linear transformation t(f)=2f 3f' from p2 to p2
The determinant of the linear transformation t(f)=2f 3f' from p2 to p2 is 36.
To find the determinant of the linear transformation t(f)=2f 3f' from p2 to p2, we first need to represent the transformation as a matrix.
Let's start by choosing a basis for p2, say {1,x,x²}. Then, the linear transformation t can be represented by the matrix
[2 0 0]
[0 3 0]
[0 0 6]
To find the determinant of this matrix (and hence the determinant of the linear transformation), we can use the formula for the determinant of a 3x3 matrix:
det(A) = a11(a22a33 - a23a32) - a12(a21a33 - a23a31) + a13(a21a32 - a22a31)
Plugging in the entries of our matrix, we get:
det(t) = 2(3×6 - 0×0) - 0(2×6 - 0×0) + 0(2×0 - 3×0)
= 36
Therefore, the determinant of the linear transformation t(f)=2f 3f' from p2 to p2 is 36.
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Find the area of the triangle. Pls help!
Answer:
84 mm^2
Step-by-step explanation:
The area of a triangle is
A = 1/2 b *h
The base is 14 and the height is 12
A = 1/2 (14*12)
A = 84 mm ^2
Area of a triangle formula: A = 1/2bh
Solve using the values given in the picture.
A = 1/2(14)(12)
A = 1/2(168)
A = 84
Therefore, the volume of the triangle is 84mm²
Best of Luck!
Please HELP PLEASE PLEASE
PLEASE HELP
Simplify the following expression into a fraction with no exponents. Write your answer in the form a/b. 6^-2
Answer:
1/36
Step-by-step explanation:
6^-2
~Use negative exponent rule [ a^-b = 1/a^b ]
1/6^2
1/36
Best of Luck!
Answer:
\(\huge\boxed{\sf \frac{1}{36}}\)
Step-by-step explanation:
\(\displaystyle = 6^{-2}\\\\We \ know \ that\ a^{-b} = \frac{1}{a^b} \\\\= \frac{1}{6^2} \\\\= \frac{1}{36} \\\\\rule[225]{225}{2}\)
Hope this helped!
~AH1807Peace!8 oz equal how many lbs?
Answer: 8oz=0.5 lbs/pounds
Step-by-step explanation: 1 oz is 16 pounds
8 oz equals 0.5 lbs. The solution has been obtained by using the unit conversion.
What is unit conversion?
Using a unit conversion, the same property is stated in a different unit of measurement. For instance, instead of using hours to describe time, use minutes or feet to measure distance. It usually occurs when measurements are requested in one set of units, such as chains, but are provided in another set, such as feet.
In the question, we have been given 8 ounces which are needed to be converted into pounds.
We know that 1 pound = 16 ounces
So, 1 ounce = 1/16 pounds
Therefore,
⇒8 ounces = 8*1/16
⇒8 ounces = 0.5 lbs
Hence, 8 oz equals 0.5 lbs.
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What is the probability that a random sample of second grade students from the city results in a mean reading rate of more than words per minute?
The probability that a random sample of 28 second grade students from the city results in a mean reading rate of more than 96 wpm is 0.01715.
What is normal distribution?A normal distribution is a probability distribution that has been symmetrical around this mean, with most observations clustering around the central peak and probabilities tapering off evenly in both directions.
Now, according to the question,
The formula for normal distribution is;
z = (x - μ)/(σ/√s)
x is the sample size (= 96)
μ = standard mean (= 92)
σ = standard deviation (= 10)
s = random sample (= 28)
Substituting all the values in the equation;
z = (96 - 92)/(10/√28)
z = 2.117
Now, calculate the probability;
P(X > 96) = 1 - P(X ≤ 96)
= 1 - P(X ≤ 2.117)
= 1 - 0.98285
P(X > 96) = 0.01715
Therefore, the probability that a random sample of 28 second grade students from the city results in a mean reading rate of more than 96 wpm is 0.01715.
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The complete question is-
The reading speed of a second grade students in a large city is approximately normal with a mean of 92 words per minute and a standard deviation of 10 wpm. What is the probability that a random sample of 28 second grade students from the city results in a mean reading rate of more than 96 wpm?
How to do it
Step by step
Step-by-step explanation:
23.35......is answer.......
let ta: ℝ2 → ℝ3 be the matrix transformation corresponding to a = 3−1 12 14 . find ta(u) and ta(v), where u = 1 2 and v = 3 −2 .
The value of ta(u) 1 5 9 is and ta(v) is 9 -1 11.
To find the matrix transformation corresponding to a =
| 3 -1 |
| 1 2 |
| 1 4 |
and the transformation of vectors u =
| 1 |
| 2 |
and v =
| 3 |
|-2 |
We can compute ta(u) and ta(v) as follows:
ta(u) = a * u =
| 3 -1 |
| 1 2 |
| 1 4 | *
| 1 |
| 2 | =
| 1 |
| 5 |
| 9 |
So, ta(u) =
| 1 |
| 5 |
| 9 |
Similarly,
ta(v) = a * v =
| 3 -1 |
| 1 2 |
| 1 4 | *
| 3 |
|-2 | =
| 9 -7 |
|-1 2 |
|11 - 5 |
So, ta(v) =
| 9 |
|-1 |
|11 |
Note that the dimensions of ta(u) and ta(v) are 3x1 and 3x1 respectively, since the matrix transformation ta maps vectors in R^2 to vectors in R^3.
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please help urgent easy 8th grade math
Answer:
No Solution
Step-by-step explanation:
8x-3(1+6x) -2>5(1+2x)
-10x-5>-5-10x
(Add 5 to both sides)
-10>-10x
(Add 10x to both sides)
-10x+10x>-10x+10x
Therefore , this equation has no solutions.
Answer:
-1=x
Step-by-step explanation
8x-3(1+6x)-2> 5(1+2x)
8x-3(7x)-2>5(3x)
8x-21x-2>15x
13x-2>15x
-13 -13
-2 2x
2 2
-1 x
ANY MATH EXPERTS PLS HELP RN I GOT 5 MIN LEFT I'LL PUT BRAINLIEST TO WHOEVER ANSWERS CORRECTLY FIRST
Answer:
Answer: y=-4x+5. Use Desmos to graph the equation and get your answers
Step-by-step explanation:
I Think 99% sure
Answer:
y=-4x+5
Step-by-step explanation:
Find the maxima and minima, and where they are reached, of the function In f(x,y) = x² + y² + xy
{(x,y): x² + y² ≤ 1}
(I)Local. (ii) Absolutes. (iii) Identify the critical points inside the disk (not on the border) if any. Say if they are extreme '? what type?'o saddle points,'o we cannot tell using ___
i. The local maxima and minima are 3 and 2
ii. The absolute maximum of f(x,y) over the region is 3/2 at (1/√2, 1/√2), and the absolute minimum is -1/2, which is attained at (-1/√2, -1/√2).
iii. There are no other critical points inside the disk, so we cannot tell whether they are extreme or saddle points.
i. To find the maxima and minima of the function f(x,y) = x² + y² + xy over the region {(x,y): x² + y² ≤ 1}, we first find the critical points by setting the partial derivatives equal to zero:
f(x) = 2x + y = 0
fy = 2y + x = 0
Solving these equations simultaneously gives the critical point (-1/3, 2/3). We now need to check if this is a local maximum, local minimum or a saddle point. To do this, we use the second partial derivative test.
f(xx) = 2, f(xy) = 1, fyy = 2
The determinant of the Hessian matrix is Δ = f(xx)f(yy_ - (fxy)² = 2(2) - (1)² = 3, which is positive, and f(xx) = 2, which is positive. Therefore, the critical point is a local minimum.
ii. To find the absolute maximum and minimum, we need to consider the boundary of the region. Let g(x,y) = x² + y² be the equation of the circle with radius 1 centered at the origin. We can parameterize this curve as x = cos(t) and y = sin(t), where 0 ≤ t ≤ 2π.
Substituting this into the function f(x,y), we get:
h(t) = f(cos(t), sin(t)) = cos²(t) + sin²(t) + cos(t)sin(t) = 1 + (1/2)sin(2t)
We now find the critical points of h(t) by setting dh/dt = 0:
dh/dt = cos(2t) = 0
This gives t = π/4 and 5π/4.
Substituting these values into h(t), we get:
h(π/4) = 3/2
h(5π/4) = -1/2
Therefore, the absolute maximum of f(x,y) over the region is 3/2, which is attained at (1/√2, 1/√2), and the absolute minimum is -1/2, which is attained at (-1/√2, -1/√2).
iii. There are no other critical points inside the disk, so we cannot tell whether they are extreme or saddle points.
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-(3z)² how do I simplify it because the question tells me to simply -(3z)²
Answer:
-9z²
Step-by-step explanation:
-(3z)²
-(3z * 3z)
-(9z)
-9z²
Best of Luck!
Calculate the bearing of U from T. U N 32° T
The bearing of U from T in the image is 32 degrees South by West of T
What is Bearing?In mathematics, bearings refer to the direction of an object or location in relation to two points. It is determined by the angle between the line joining them and that of the north.
Measured typically in degrees, it follows a cardinal system where 0° or 360° signifies North; East stands for 90°, South denotes at 180° while West represents 270°.
Thus, it can be seen that the bearing of U from T in the image is 32 degrees South by West of T
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Enter the ordered pair for the vertices for rx-
axis(qrst).
q= (1,3)
r= (3,-3)
s= (0,-2)
t= (-2,1)
q' = ()
r' = ()
s'= ( )
t' = ()
Pls help I need it really soon
Answer:
q1 (1,-3)
r1 (3,3)
s1 (0,2)
t1 (-2,-1)
Step-by-step explanation:
When a shape is reflected, it must be reflected across a line
The vertices for \(\mathbf{rx-axis}\) of qrst are:
\(\mathbf{q'(1,-3)}\)\(\mathbf{ r'(3,3)}\)\(\mathbf{ s'(0,2)}\)\(\mathbf{t'(-2,-1)}\)The given parameters are:
\(\mathbf{q = (1,3)}\)
\(\mathbf{r = (3,-3)}\)
\(\mathbf{s = (0,-2)}\)
\(\mathbf{s = (-2,1)}\)
The transformation rule is given as:
\(\mathbf{rx-axis}\)
The above rule means that the vertices are reflected over the x-axis
The rule of the transformation is:
\(\mathbf{(x,y) \to (x,-y)}\)
So, we have:
\(\mathbf{q(1,3) \to q'(1,-3)}\)
\(\mathbf{r(3,-3) \to r'(3,3)}\)
\(\mathbf{s(0,-2) \to s'(0,2)}\)
\(\mathbf{t(-2,1) \to t'(-2,-1)}\)
Hence, the vertices for \(\mathbf{rx-axis}\) of qrst are:
\(\mathbf{q'(1,-3)}\)
\(\mathbf{ r'(3,3)}\)
\(\mathbf{ s'(0,2)}\)
\(\mathbf{t'(-2,-1)}\)
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The Sugar Sweet Company is going to transport its sugar to market. It will cost $5000 to rent trucks, and it will cost an additional $200 for each ton of sugar transported. Let C represent the total cost (in dollars), and let S represent the amount of sugar (in tons) transported. Write an equation relating C to S, and then graph your equation using the axes below.
Please find attached the graph of the linear equation for the total cost of transportation of sugar created with MS Excel is attached.
What is a graph of an equation?A graph is a pictorial representation of the relationship between the variables in an equation.
The amount it costs to rent the truck = $5000
The amount it cost to transport a ton of sugar = $200
The amount of sugar transported in tons = S
The equation for the total cost C is; C = 5000 + 200·s
The graph of the equation for the cost of transportation can be created with a spreadsheet application such as MS Excel, by entering the formula, = 5000 + 200*RefCell, in a cell and the value of S in an adjacent cell, the values for S are then populated and the values of C are generated using the formula in the cell
The two columns are then selected
Then the insert, Chart menu is then used to create the graph.
Please find attached the required graph created with MS Excel
The graph for the total cost for the transportation is therefore a straight line graph with a slope of 200 and a y-intercept of 5,000,
The
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which of the following statements is NOT true?
A. the ratios of the vertical rise to the horizontal run of any two distinct nonvertical parallel lines must be equal.
B. if two distinct nonvertical lines are parallel, then two lines must have the same slope.
C. Given two distinct lines in the cartesian plane, the two lines will either intersect of they will be parallel
D. Given any two distinct lines in the cartesian plane, the two liens will either be parallel or perpendicular
The statement "D. Given any two distinct lines in the Cartesian plane, the two lines will either be parallel or perpendicular" is NOT true.
A. The statement is true. The ratios of the vertical rise to the horizontal run, also known as the slopes, of any two distinct nonvertical parallel lines are equal. This is one of the properties of parallel lines.
B. The statement is true. If two distinct nonvertical lines are parallel, then they have the same slope. Parallel lines have the same steepness or rate of change.
C. The statement is true. Given two distinct lines in the Cartesian plane, the two lines will either intersect at a point or they will be parallel and never intersect. These are the two possible scenarios for distinct lines in the Cartesian plane.
D. The statement is NOT true. Given any two distinct lines in the Cartesian plane, they may or may not be parallel or perpendicular. It is possible for two distinct lines to have neither parallel nor perpendicular relationship. For example, two lines that have different slopes and do not intersect or two lines that intersect but are not perpendicular to each other.
Therefore, the statement "D. Given any two distinct lines in the Cartesian plane, the two lines will either be parallel or perpendicular" is the one that is NOT true.
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