4. How is the coordination number determined?

Answer:

Hazen uses small metal cylinders called pressure bombs to blast minerals with insanely high pressures and temperatures. He's using that knowledge to figure out how ancient minerals might have been involved in the evolution of the first primitive life-forms.

Explanation:

Answer:

8.68 moles of BaI₂

Explanation:

Given data:

Number of moles of BaI₂ = ?

Number of formula units = 5.23× 10²⁴

Solution:

By using Avogadro number,

1 mole of any  substance contain 6.022× 10²³ formula units.

5.23× 10²⁴ formula units of BaI₂ × 1 mol / 6.022× 10²³ formula units

0.868 × 10¹ moles of BaI₂

8.68 moles of BaI₂

Thus, 5.23× 10²⁴ formula units of BaI₂ contain 8.68 moles of BaI₂

I apologize of I'm wrong but its probably OA

Sorry once again!

~wise rat

Answer: C.

Explanation:

gasoline evaporating into the air

Answer:

D-60

Explanation:

Mass number =Proton number(P) + Neutron number

100=P+40

collect like terms

P=100-40

P=60

Answer:

During the early Paleozoic Era, the Earth's surface was very different from what it is today. The continents were arranged differently, forming one large supercontinent called Pangea. This landmass was surrounded by a single large ocean called Panthalassa. The climate was much warmer and wetter than it is today, with no ice caps at the poles.

The first land plants, known as bryophytes, appeared during the early Silurian Period, around 430 million years ago. These plants were small and simple, lacking roots and vascular tissue. They grew in damp environments, such as along the edges of lakes and streams. They were important in the development of soils and in the colonization of land by other organisms, such as insects and other arthropods.

Answer:

The correct answer is -

takes place in the Sun

plays a role in the production of essentially all elements heavier than helium

releases large amounts of energy

Explanation:

Fusion reaction takes place when two or more small atomic nuclei come in close proximation for a longer time so the nuclear force pulling them together and form into heavier molecules than helium and releases a huge amount of energy by this process.

A great example of this fusion reaction is the sun where nuclear fusion takes place inside the core of the sun and result in a huge amount of release as it is an exothermic reaction.

Answer:

Explanation

EDGE2021

Taking into account the reaction stoichiometry, a mass of 2.75×10⁻³ grams of carbon dioxide is produced from the complete combustion of 1×10⁻³ grams of methane.

In first place, the balanced reaction is:

CH₄ + 2 O₂  → CO₂ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 16 grams of CH₄ form 44 grams of CO₂, 1×10⁻³ grams of CH₄ form how much mass of CO₂?

mass of CO₂= (1×10⁻³ grams of CH₄× 44 grams of CO₂)÷ 16 grams of CH₄

mass of CO₂= 2.75×10⁻³ grams

Finally, a mass of 2.75×10⁻³ grams of carbon dioxide is produced.

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The answer responses to  the structures shown in the diagram are:

A. chromosomes

C. They would be the same.

B. They are in pairs because each one comes from a different parent.

The chromosomes are in pairs because humans have a diploid number of chromosomes, meaning they have two sets of chromosomes, one inherited from each parent.

The nucleus is important in eukaryotic cells and has many important parts that help the cell work properly. There are some parts inside cells called the nuclear membrane, nucleoplasm, nucleolus, and chromatin. Chromatin is made up of DNA and other proteins.

Every part of a person's body has the same genes, but the way they are organized can be different in different types of cells. The chromosomes in our skin cells might not be the same as the chromosomes in our muscle cells, even if they come from the same person.

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Identify the structures shown.

A. chromosomes

B. mitochondria

C. nuclei

D. vacuoles

C

Describe how the structures from this cell would compare to the structures in the nucleus of another body cell from the same person.

A. There would be longer.

B. They would be shorter.

C. They would be the same.

D. They would be different.

Describe how the structures from this cell would compare to the structures in the nucleus of another body cell from the same person.

A. There would be longer.

B. They would be shorter.

C. They would be the same.

D. They would be different.

Explain why the structures are in pairs.

A. They aren't in pairs.

B. They are in pairs because each one comes from a different parent.

C. This cell is making a copy of itself.

D. The cell always has 2 copies in case 1 is damaged.

Answer:

the answer is applied force

As a result, the 50 gramme sample's estimated end temperature is around 37.57°C.

The amount of energy in a system that is available to perform beneficial work at a constant temperature is shown by the Helmholtz free energy equation, often known as the thermal equilibrium equation (F = U - TS). The Helmholtz free energy (F), internal energy (U), absolute temperature (T), and entropy are the variables in the Helmholtz equation (S).

Two items are said to have the same temperature when they are in thermal equilibrium. Heat, a kind of energy, is transmitted between the objects as they approach thermal equilibrium.

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Answer:

Question (a):

Answer: 2:8:7

Explanation: Chlorine, Cl is in period 3 hence two energy levels [ 2:8:_]. Chlorine is in group IV (halogen) hence it has 7 outermost energy level electrons. Hence deducing 2:8:7

Question (b)

» (i): Carbon and silicon [ C and Si ]

A group is a column in a periodic table

» (ii): Silicon and Chlorine [ Si and Cl ]

A period is a row in a periodic table

» (iii): Hydrogen and Chlorine [ H and Cl ]

It forms hydrogen chloride gas. When this gas is passed on warm water or steam, hydrochloric acid is formed.

» (iv): Chlorine [ Cl ]

An element has electron number equivalent to group number. Group I elements have one electron, Group ii elements have two electrons and so on.

Helium is in group Viii but in period 1, so it has eight electrons.

But chlorine has seven outermost electrons but since it is in period 3, its electrons are 8 + 7 = 15 electrons.

» (v): Chlorine [ Cl ]

Chlorine only lacks one electron to become full and stable. So it is assigned by Cl- (-1)

The mass, in grams of BaCrO4 that will be produced, according to the illustration, would be 0.1329 grams

From the equation of the reaction:

Ba(NO3)2 + (NH4)2CrO4 → BaCrO4 + 2(NH4)NO3

The mole ratio of the reactants is 1:1.

Mole of (NH4)2CrO4 = 3.86/1000 x 0.716

                                       = 0.0028 moles

Mole of Ba(NO3 )2 = 2.76/1000 x 0.19

                               = 0.0005 moles

Thus, Ba(NO3 )2 is limiting in availability.

Mole ratio of Ba(NO3 )2 and BaCrO4  = 1:1

Mole equivalent of BaCrO4  = 0.0005 moles

Mass of 0.0005 moles BaCrO4  = 0.0005 x 253.37

                                                        = 0.1329 grams

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Reagents that are entirely consumed by a chemical reaction are known as limiting reagents.

Thus, They are additionally known as limiting reactants or limiting agents. A predetermined quantity of reactants are necessary for the reaction to be completed, according to the stoichiometry of chemical reactions.

In the aforementioned reaction, 2 moles of ammonia are created when 3 moles of hydrogen gas react with 1 mole of nitrogen gas.

In most cases, this reactant dictates when the reaction will end. The reaction stoichiometry can be used to determine the precise quantity of reactant that will be required to react with another element. The limiting agent is determined by the mole ratio rather than the mass of the reactants.

Thus, Reagents that are entirely consumed by a chemical reaction are known as limiting reagents.

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Answer:

We need more? What else is in the question? This is unanswerable.

Explanation:

Answer:

Final volume  = 0.44 L

Explanation:

Given data:

Initial volume of balloon = 1.1 L

Initial pressure = 0.80 atm

Final volume = ?

Final pressure = 2.0 atm

Solution:

The given problem will be solved through the Boly's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

0.80 atm × 1.1 L = 2.0 atm × V₂

V₂ = 0.88 atm. L/ 2.0 atm

V₂ = 0.44 L

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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Answer:

if you meant CH3-CH=CH-CH3, the IUPAC name is 2-butene.

Answer:

Na k

Explanation:

because na is a metal and potassium is also a metal and both are active metal so is less likely to react as no bond is formed between them

Answer:

Enzymes are required to slow down biological reactions within cells,

this could be not sure

Answer:

D

Explanation:

Enzymes bind substrates so that reactive groups have many different orientations.

Answer:

answer is c

Explanation: cause there breaking it

By using the ideal gas law and Avogadro's number, we find that there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.

To determine the number of molecules of CO2 in 2.5 L at STP (Standard Temperature and Pressure), we can use the ideal gas law and Avogadro's number.

Avogadro's number (N_A) is a fundamental constant representing the number of particles (atoms, molecules, ions) in one mole of substance. Its value is approximately 6.022 × 10^23 particles/mol.

STP conditions are defined as a temperature of 273.15 K (0 °C) and a pressure of 1 atmosphere (1 atm).

First, we need to convert the volume from liters to moles of CO2. To do this, we use the ideal gas law equation:

PV = nRT,

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

Since we have STP conditions, we can substitute the values:

(1 atm) × (2.5 L) = n × (0.0821 L·atm/(mol·K)) × (273.15 K).

Simplifying the equation:

2.5 = n × 22.4149.

Solving for n (the number of moles):

n = 2.5 / 22.4149 ≈ 0.1116 moles.

Next, we can calculate the number of molecules using Avogadro's number:

Number of molecules = n × N_A.

Number of molecules = 0.1116 moles × (6.022 × 10^23 particles/mol).

Number of molecules ≈ 6.72 × 10^22 molecules.

Therefore, there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.

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The mass of Aluminum Sulfate is 5.373 grams if you have \(2.837*10^{26\) atoms of Sulfur .

The molecular formula of Aluminum Sulfate is \(Al_2(SO_4)_3.\) In one molecule of aluminum sulfate, there are 3 sulfur atoms. To calculate the mass of aluminum sulfate, follow the steps below:

Step 1: Calculate the molar mass of aluminum sulfate using the periodic table.Al = 27.0 g/molS = 32.1 g/molO = 16.0 g/mol

(2 × Al) + (3 × S) + (12 × O) = molar mass of \(Al_2(SO_4)_3.\) = 342.2 g/mol

Step 2: Find the number of moles of sulfur in the given number of atoms of sulfur.2\(2.837*10^{26\) atoms of sulfur × 1 mol S/\(6.022 * 10^{23\)atoms S = 0.0470 mol S

Step 3: Use the molar ratio of sulfur to aluminum sulfate to calculate the number of moles of aluminum sulfate.1 mol \(Al_2(SO_4)_3.\) / 3 mol S = 0.333 mol\(Al_2(SO_4)_3.\) per mol S0.0470 mol S × 0.333 mol \(Al_2(SO_4)_3.\)/mol S = 0.0157 mol \(Al_2(SO_4)_3.\)

Step 4: Calculate the mass of aluminum sulfate.0.0157 mol \(Al_2(SO_4)_3.\) × 342.2 g/mol\(Al_2(SO_4)_3.\)= 5.373 g\(Al_2(SO_4)_3.\)

Therefore, the mass of Aluminum Sulfate is 5.373 grams if you have \(2.837*10^{26\) atoms of Sulfur.

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The heat of formation, or enthalpy of formation, of a compound, can be found in a reference such as the appendix of a textbook or a thermochemistry table. The heat of the formation of Fe2O3(s) is -824 kJ/mol. It represents the heat change that occurs when one mole of Fe2O3 is formed from its elements under standard state conditions. So the answer is 824 kJ will be released.

The heat of formation, also known as enthalpy of formation, is the heat energy change that occurs when a substance is formed from its element under standard state conditions. It is usually expressed in kJ/mol.

When we are dealing with the combustion of a substance, this value is used to determine how much heat is released or absorbed in the process. In this case, the substance is iron and we need to form Fe2O3.

To find the amount of heat released, we can use the heat of formation value of Fe2O3, which is -824 kJ/mol.

Since the value is negative, this means that 824 kJ of heat is released when 1 mole of Fe is burned to form Fe2O3 under standard state conditions.

It is also important to note that these values are usually provided at a specific temperature, usually at 25 degrees Celsius, and standard pressure.

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Answer:

B

Explanation:

Planting several seeds from each brand being tested is a way of repeating the test to gain better results.

Kierra could collect more accurate data on her lettuce plants by planting several seeds from each brand. Hence, option B is correct.

The annual lettuce plant, Lactuca sativa, belongs to the Asteraceae family. Although occasionally cultivated for its stem and seeds, it is typically grown as a leaf vegetable. Although it can be found in various dishes like soups, sandwiches, and wraps, lettuce is most frequently used in salads. It can also be grilled.  

To experiment on different brands of a plant we can either conduct research on them from their culturing places or else we could have a survey on the previous studies on it.

If its seeds are available to grow, then we can directly study the growth and difference in features of each varieties of the lettuce  plant. Hence, Kierra can plant several seeds from each brand.

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The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).

Empirical formula is the simplest whole number ratio of atoms present in given compound.

Element   %   Atomic mass   Relative no. of atoms  Simplest whole ratio

C          40.6       12                   \(\frac{40.6}{12}\) = 3.3                        \(\frac{3.3}{3.3} = 1\)

H          5.1          1                      \(\frac{5.1}{1}\) = 5.1                          \(\frac{5.1}{3.1} = 2\)

O         54.2       16                    \(\frac{54.2}{16}\) = 3.3                        \(\frac{3.3}{3.3} = 1\)

The Empirical formula of compound is C₁H₂O₁ or CH₂O

Molecular formula = Empirical formula × n

\(n = \frac{\text{Molecular weight}}{\text{Empirical Formula weight}}\)

   \(= \frac{118.084}{30}\)

   = 4

Molecular formula = n × Empirical formula

                              = 4 (C₁H₂O₁)

Thus from the above conclusion we can say that The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).

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Answer:

soil

Explanation:

The average atomic mass of a chemical element is calculated by taking into account the atomic masses of its naturally occuring isotopes and their respective abundances.

avg. atomic mass=∑i(isotopei×abundancei)

atomic masses of four isotopes of sulphur are

32S: 31.972 u→95.002%

33S: 32.971 u→0.76%

34S: 33.967 u→4.22%

36S: 35.967 u→0.014%

the average atomic mass of sulfur will be

Average atomic mass=31.972 u×0.95002+32.971 u×0.0076+33.967 u×0.0422+35.967 u×0.00014

Average atomic mass=32.063 u

Answer:

C. 6.52 x 10^14 Hz

Explanation:

hope this helps

26.5cm to dm

is 2.65 Decimeters