400.0 g of a metal absorbs 10000. j of heat energy and its temperature rises from 20.0 ºc to 103.0 ºc. what is the specific heat of the metal?

Option D is correct. In venturi meter a converging section of a pipe is used to increase the flow velocity and corresponding pressure drop, from which the fluid flow rate is calculated using Bernoulli's equation.

A venturimeter is a flow measurement device. The meter is connected between two sections of the pipe; the cross-sectional area A of the meter's entrance and exit corresponds to the cross-sectional area of the pipe. The fluid flows from the pipe with speed V between the entrance and exit, and then through a narrow throat with cross-sectional area a with speed v. A venturi works by measuring the difference in pressure between two points. The pressure difference is created by narrowing the pipe, causing the fluid to flow faster. In the larger section of the venturi, the fast moving fluid has a lower pressure than the slower fluid.

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Answer:

C. 2 N left

Explanation:

Subtract the smaller number from the bigger number, the difference will go to the side with the larger number.

Answer:

B

Explanation:

the balloon has a negative charge and the metal sphere has a positive charge

Answer: B

Explanation:

The balloon will pick up stray electrons, so it will become negatively charged. Since it is attracted to the metal sphere, the sphere must be positively charged.

Answer:

(2) the work required to move the electron is 4.8 x 10⁻¹⁹ J.

Explanation:

Given;

potential difference, V = 3.00 volts

charge of electron, q = 1.6 x 10⁻¹⁹ C

The work required to move an electron is calculated as;

W = Vq

where;

W is the work done in Joules

Substitute the given values and solve for W;

W = (3.00)(1.6 x 10⁻¹⁹)

W = 4.8 x 10⁻¹⁹ J.

Therefore, the work required to move the electron is 4.8 x 10⁻¹⁹ J.

Water coming from a reservoir that can be utilized to generate hydroelectric power or for enjoyment is dammed, resulting in low water flow rates in the area.

The tops of smooth, rounded hills, broad plains, bodies of water, and mountain gaps that concentrate and increase wind are all desirable locations. At higher altitudes above the earth's surface, wind resources are typically more advantageous for the generation of electricity. In the form of charcoal and firewood, wood is frequently utilized as fuel. Due to its accessibility, it is frequently utilized in underdeveloped nations. Organic material that has partially decomposed and may be burned as fuel is called peat.

Fossil fuels, nuclear, biomass, geothermal, and solar thermal energy are used to generate the majority of the world's power using steam turbines. Other significant electricity-generating technologies include gas turbines, hydro turbines, wind turbines, and solar photovoltaics. Water in motion generates hydroelectric power. Hydro is a translation of the Greek word meaning water. For thousands of years, hydroelectric power has been used.

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Answer:

Incomplete question, but let analyse generally a torque acting on a rotating body

Explanation

Toque is given as

τ = r × F

Where

τ is the torque (Nm)

r is the position vector (m)

F is the force (N).

Let assume we have the following data

F= x•i + y•j + z•k

Also let assume the position vector is

r'= a•i + b•j + c•k

a. The first question, torque at the origin

The origin will have a position vector of r1(0,0,0)

Then, the displacement is

r=AB=AO+OB=-OA+OB

r = r'-r1 = (a, b, c)-(0,0,0)

r=(a, b, c)

Then, the torque is given as

τ = r×F

τ = (a, b, c) × (x, y, z)

Note that

i×i=j×j=k×k=0

i×j=k, j×i=-k

j×k=i, k×j=-i

k×i=j, i×k=-j

τ = (a•i + b•j + c•k) × (x•i + y•j + z•k)

τ = a•i×(x•i + y•j + z•k) + b•j×(x•i + y•j + z•k) + c•k×(x•i + y•j + z•k)

τ = (a•i × x•i)+ (a•i × y•j) + (a•i × z•k) + (b•j × x•i) + (b•j × y•j) + (b•j × z•k) + (c•k × x•i) + (c•k × y•j) + (c•k × z•k)

Now, using the above law.

τ = 0 + ay•k - az•j - bx•k + 0 + bz•i + cx•j - cy•i + 0

τ= ay•k - az•j - bx•k + bz•i + cx•j -cy•i

Then, rearranging

τ = (bz - cy)•i + (cx - az)•j + (ay - bx)•k

This is general formula for the torque at the origin, so you can apply it to the given values in your question because the question given is not complete.

b. Now let, analyse at the position vector (2.61 m, 0, -8.03 m)

Using the same analysis

position vector of r1(2.61, 0, -8.03)m

Then, the displacement is

r=AB=AO+OB=-OA+OB

r = r'-r1 = (a, b, c)-(2.61,0,-8.03)

r=(a-2.61, b, c+8.03)

Then, the torque is given as

τ = r×F

τ = (a-2.61, b, c+8.03) × (x, y, z)

Note that

i×i=j×j=k×k=0

i×j=k, j×i=-k

j×k=i, k×j=-i

k×i=j, i×k=-j

τ =([a-2.61]•i, b•j, [c+8.03]•k) × (x•i + y•j + z•k)

τ = (a-2.61)•i×(x•i + y•j + z•k) + b•j×(x•i + y•j + z•k) + (c+8.03)•k×(x•i + y•j + z•k)

τ = ((a-2.61)•i × x•i)+ ((a-2.61)•i × y•j) + ((a-2.61)•i × z•k) + (b•j × x•i) + (b•j × y•j) + (b•j × z•k) + ((c+8.03)•k × x•i) + ((c+8.03)•k × y•j) + ((c+8.03)•k × z•k)

Now, using the above law.

τ = 0 + (a-2.61)y•k - (a-2.61)z•j - bx•k + 0 + bz•i + (c+8.03)x•j - (c+8.03)y•i + 0

τ= (a-2.61)y•k - (a-2.61)z•j - bx•k + bz•i + (c+8.03)x•j -(c+8.03)y•i

Then, rearranging

τ = (bz - cy - 8.03y)•i + (cx + 8.03x - az - 2.61z)•j + (ay - 2.61y - bx)•k

This is general formula for the torque at the point (2.61 m, 0, -8.03 m), so you can apply it to the given values in your question because the question given is not complete.

(a) Torque acting on the pebble about the origin is (-1.5i - 4j - 1k) Nm.

(b) Torque acting on the pebble about the given coordinate is 20j Nm.

Torque is defined as the rotational analogue of force. It is the cross product of force and the perpendicular distance.

Here,

The position coordinates of the pebble, r = (0.5 m)j - (2 m)k

Force acting on the pebble, F =  (2 N)i - (3 N)k

(a) About the origin

 Torque acting on the pebble, τ = r x F

   τ = (0.5j - 2k) x (2i - 3k)

   τ = (0.5j x 2i) + (0.5j x -3k) + (-2k x 2i) + (-2k x -3k)

   τ = -1k - 1.5i - 4j + 0

   τ = (-1.5i - 4j - 1k) Nm

(b) At a point with coordinates (8.62m, 0, -2.93m)

    Torque acting on the pebble,

   τ = r x F

   τ = (8.62i - 2.93k) x (2i - 3k)

   τ = (8.62i x 2i) + (8.62i x -3k) + (-2.93k x 2i) + (-2.93k x -3k)

   τ = 25.86j - 5.86j

   τ = 20j Nm

Hence,

(a) Torque acting on the pebble about the origin is (-1.5i - 4j - 1k) Nm.

(b) Torque acting on the pebble about the given coordinate is 20j Nm.

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Your question was incomplete, but most probably your question was:

Force (2 N)i - (3 N)k acts on a pebble with position vector (0.5 m)j - (2 m)k, relative to the origin. What is the resulting torque acting on the pebble about (a) the origin and (b) a point with coordinates (8.62 m, 0, -2.93 m)

All human cells contain mitochondria, which function as the cell's main "power generator" by transforming energy from food into a form the cell can use. Mitochondria are found in the cytoplasm of all human cells.

How do a generator and a mitochondria compare?

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Answer:

I. Period = 1.3 seconds

II. Frequency = 0.769 Hertz

Explanation:

Given the following data;

Number of oscillation = 240 cycles

Time = 5.2 minutes.

Conversion:

1 minute = 60 seconds

5.2 minutes = X seconds

X = 60 * 5.2

X = 312 seconds

To find the following;

I. Period

Mathematically, the number of oscillation of a pendulum is given by the formula;

\( Number \; of \; oscillation = \frac {Time}{Period} \)

Making period the subject of formula, we have;

\( Period = \frac {Time}{Number \; of \; oscillation} \)

Substituting into the formula, we have;

\( Period = \frac {312}{240} \)

Period = 1.3 seconds

II. Frequency

\( Frequency = \frac {1}{Period} \)

Substituting the values into the formula, we have;

\( Frequency = \frac {1}{1.3} \)

Frequency = 0.769 Hertz

Answer:

Explanation:

a) The second arm measures the minutes. The difference between 9:17:30 and 9:15:00 is 2 minutes 30 seconds. This means the second arm would have revolved 2.5 times.

The circumference = 2πr= 2π(13.5 cm) = 84.823 cm

Distance = 2.5 × 84.823 cm = 212 cm = 2.12 m

b) Displacement of an object is the shortest distance between the initial and final point. Since the second arm revolves 2 and half times, we use only the half times (a semicircle)

Displacement for semicircle = 2r = 2(13.5) = 27 cm

c) Average speed = distance / time

time = 2 minutes 30 seconds = 150 seconds

Average speed = 212 cm / 150 s = 1.41 cm/s

d) Average velocity = displacement / time = 27 cm / 150 s = 0.18 cm/s

e) number of revolutions = 100 m / circumference = 100 m / 0.848 m = 117.92

but 1 revolution = 1 minute

117.92 revolution = 117 minutes 55 seconds = 1 hour 57 minutes 55 seconds

Hence the time would be: 11:12:55

Answer:

the price per gallon of gas leah paid is 8.58

Explanation:

42.90/5=8.58

Because copper is the second-best electrical conductor, it's cheaper and more plentiful than silver, and it's relatively easy to get it out of the ground, refine it, and form it into wires.

(If the electrical wiring in your house was all silver wire, I guess nothing would ever work, because people would keep stealing your wiring.)

a. The current in the resistor is 17.3 mA

b. The power in the resistor is 196.9 mW

Current is the rate of flow of electric charge

Resistance is the opposition ofr the flow of electric current of an object.

Power is the rate at which work is done.

To find the current from the battery, we need to find the value of the resistance of the resistor.

Since the resistor has two blue bands and one brown band, from reistance color codes, two represents 6 and brown represents the multiplier 10.

So, the resistance value is 66 × 10 Ω = 660 Ω

Now electric current is given by Ohm's law which is V = IR where

Naking I subject of the formula, we have that

I = V/R

Since

Substituting these into the equation, we have that

I = V/R

I = 11.4 V/660 Ω

= 0.01727

≅ 0.0173 A

= 17.3 × 10⁻³ A

= 17.3 mA

So, the current is 17.3 mA

The power in the reistor is given by P = IV where

Given that

Substituting the values of the variables into the equation, we have that

P = IV

= 17.3 mA × 11.4 V

= 196.9 mW

So, the power is 196.9 mW

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Answer:

Mechanical waves

Electromagnetic waves

Matter waves

Longitudinal waves

Transverse waves

Surface waves

Explanation:

Pls give Brainliest!!

By using the thrust force, the acceleration is  0.001 m/s².

We need to know about force to solve this problem. According to second Newton's Law, the force applied to an object will be proportional to mass and acceleration. Hence, it can be written as

F = m . a

where F is force, m is mass and a is acceleration

From the question above, we know that

F = 1 N

m = 1000 kg

By substituting the given parameters, we can calculate the acceleration

F = m . a

1 = 1000 . a

a = 1/1000

a = 0.001 m/s²

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Answer:

At positions C and E potential energy is maximum. At position D kinetic energy is maximum.

Explanation:

See below~

Explanation:

Given, P = 2 kVA = 2 kW,

t = 90 min = 1.5 h

(a) (i) Electrical Energy Consumed = power * time

= 2 kW x 1.5 h

= 3 kWh ( or 3 commercial unit)

(ii) Since 1 kW = 3.6 x 10^6 J

therefore,

Electrical energy consumed = 3 x 3.6 x 10^6 J

= 1.08 x 10^7 J

(b) Cost of electricity

= energy consumed in kWh x cost per kWh

= 3 x Rs 4.50 = Rs. 13.50

the second and third one

The resistance of the battery if a current of 23A flows through a circuit and the battery produces a potential difference of 9V is 0.39 ohms.

Resistance is the force that tends to oppose motion. It is measured in ohms. The resistance of a battery can be calculated using the following formula;

V = IR

Where;

According to this question, a current of 23A flows through a circuit and the battery produces a potential difference of 9V. The resistance can be calculated as follows:

R = V/I

R = 9/23

R = 0.39ohms

Therefore, 0.39ohms is the resistance of the battery.

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Explanation:

Hooke's law is a law of physics that states that the force needed to extend or compress a spring by some distance scales linearly with respect to that distance—that is, Fₛ = kx, where k is a constant factor characteristic of the spring, and x is small compared to the total possible deformation of the spring.

Answer:

Since gravitational potential is generally defined to be zero at infinity

and gravity does work as an object moves from infinity in a gravitational field,  

(the potential becomes more negative)  the farther the satellite is from the attractive force the greater is its gravitational potential. Since point E is most distant from the attractive force it has the most gravitational potential.

The Gravitational potential energy connected to a planet's position within the gravitational field of a central object, such as a star or a larger planet, is referred to as its gravitational energy.

The gravitational potential energy is given by:

PE = -G × (M × m) ÷ r

Here, (G) is the gravitational constant, (M) is the mass of a planet, (m)  is the mass of a planet, and distance (r).

From the given figure, points E and A are the farthest.

Hence, at points E and A satellite have the most gravitational potential energy

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Part A: To find the angular magnification for the telescope, we can use the formula:

Angular magnification (M) = -f_objective / f_eyepiece

Given:

Focal length of the objective lens (f_objective) = 90.0 cm = 0.9 m

Focal length of the eyepiece lens (f_eyepiece) = 20.0 cm = 0.2 m

Plugging the values into the formula, we have:

M = -0.9 m / 0.2 m = -4.5

Therefore, the angular magnification for the telescope is -4.5.

Note: The negative sign indicates that the image formed is inverted.

Part B: To find the height of the image formed by the objective of a building, we can use the magnification formula:

Magnification (magnification) = -f_objective / u_objective = h_image / h_object

Given:

Height of the building (h_object) = 60.0 m

Distance to the building (u_objective) = 3.00 km = 3000 m

Focal length of the objective lens (f_objective) = 90.0 cm = 0.9 m

Plugging the values into the formula, we have:

magnification = -0.9 m / 3000 m = h_image / 60.0 m

Rearranging the formula to solve for h_image:

h_image = magnification * h_object = -0.9 m / 3000 m * 60.0 m

h_image ≈ -0.018 m

Therefore, the height of the image formed by the objective of the building is approximately -0.018 meters.

Note: The negative sign indicates that the image formed is inverted.

Part C: The angular size of the final image as viewed by an eye close to the eyepiece can be calculated using the formula:

Angular size = Angular magnification * Angular size of the object

Given:

Angular magnification (M) = -4.5 (from Part A)

Since both the object being viewed and the final image are at infinity, the angular size of the object can be considered as zero.

Angular size = -4.5 * 0 = 0

Therefore, the angular size of the final image as viewed by an eye very close to the eyepiece is zero.

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Answer:

Explanation:

A vote is maybe a vote

The work required to move a proton from the negative plate to the positive plate is 4.32 x 10⁻¹⁸joules.

To calculate the electric potential difference between the plates, we can use the formula:

Electric Potential Difference (V) = Electric Field (E) * Distance (d)

Given:

Electric Field (E) = 1800 N/C

Distance (d) = 1.5 cm = 0.015 m

Substituting the given values:

V = 1800 N/C * 0.015 m

V = 27 V

Therefore, the electric potential difference between the plates is 27 volts.

To calculate the work required to move a proton from the negative plate to the positive plate, we can use the formula:

Work (W) = Charge (q) * Electric Potential Difference (V)

Given:

Charge of a proton (q) = 1.6 x 10⁻¹⁹ C

Electric Potential Difference (V) = 27 V

Substituting the given values:

W = 1.6 x 10⁻¹⁹  C * 27 V

W = 4.32 x 10⁻¹⁸J

As a result, the effort involved in moving a proton from the negative plate to the positive plate is 4.32 x 10⁻¹⁸ joules.

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The question is: The weight (w) of a person on Earth is 550N. Determine the mass (m) of the person and the weight (w) of the person on the Moon.

Answer: The mass (m) of the person is 550 N and the weight (w) of the person on the Moon is 891 kg.

Explanation:

Given: Mass = 550 N

When a person moves towards moon then its mass will remain the same but there will occur change in its weight because the acceleration due to gravity on moon is different than that on Earth.

Therefore, formula used to calculate the weight of person on moon is as follows.

\(W = m \times g_{m}\)

where,

m = mass

\(g_{m}\) = acceleration due to gravity on moon = 1.62 \(m/s^{2}\)

Substitute the values into above formula as follows.

\(W = m \times g_{m}\\= 550 N \times 1.62 m/s^{2}\\ (1 N = 1 kg \times m/s^{2})\\= 891 kg\)

Thus, we can conclude that the mass (m) of the person is 550 N and the weight (w) of the person on the Moon is 891 kg.

The initial velocity of the ball thrown from the top of a building is 13.29 m/s.

When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion is called projectile.

A ball thrown horizontally from the top of a building 24 m above the ground strikes the ground at the distance of 18 m from the base of the building.

Range of a projectile is given by

R = u²sin2θ /g

where θ =0°, g =9.81 m/s²

Put the values, we get

18 =  u² /9.81

u = 13.29 m/s

Thus, the initial velocity is 13.29 m/s.

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In the peak of summer, it hasn't rained in a week, and the plants are looking rough, so watering the plants for an hour is a good idea.

However, the next day, you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. Plants absorb water through their roots. The root system of a plant is responsible for drawing water and nutrients from the soil. A plant's root system must be able to absorb water quickly in order for the plant to grow and thrive. When the soil around the root system is dry, the roots will stop growing and will not be able to absorb water.

It may even start to die. Watering plants during the peak of summer is important because it will help keep the soil moist and prevent the roots from drying out. However, watering a plant too much can be harmful. If a plant is overwatered, the water may not be able to penetrate the soil and reach the roots. Instead, it may just sit on top of the soil, causing the roots to rot and die. This can cause the plant to wilt and die.To summarize, if the soil around the plant is too dry, the roots may not be able to absorb the water you gave them, causing the plant to look worse than before. Conversely, overwatering can also be harmful because the water may not be able to penetrate the soil and reach the roots, causing the roots to rot and die.

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Rain cell 1: 2 mm/hr, 3 km wide, absorption = 0.02 dB/km, Rain cell 2: 4 mm/hr, 3 km wide, absorption = 0.05 dB/km. The total propagation factor seen by the radar for a target at 12 km is 0.048 dB.

To calculate the total propagation factor (F2) at a range of 12 km, we need to consider the clear air absorption and the absorption due to the rain cells at different ranges.

Given information:

Clear air absorption at X-Band: 0.004 dB/km

Rain cell 1: 2 mm/hr, 3 km wide, absorption = 0.02 dB/km

Rain cell 2: 4 mm/hr, 3 km wide, absorption = 0.05 dB/km

To plot the propagation factor as a function of range, we'll calculate the contributions from each component and sum them up.

Clear Air Absorption:

At 12 km range, the clear air absorption factor is:

Clear air absorption = Clear air absorption coefficient * Range

= 0.004 dB/km × 12 km

= 0.048 dB

Rain Cell 1:

The rain cell 1 is located between 5 km to 8 km. Within this range, the absorption factor is constant at 0.02 dB/km.

We need to calculate the fraction of the rain cell coverage within the range of interest.

Fraction of rain cell 1 coverage = (Coverage within range of interest) / (Total rain cell width)

= (min(8 km, 12 km) - max(5 km, 12 km)) / 3 km

Since the range of interest is 12 km, the coverage within the range is:

Coverage within range of interest = min(8 km, 12 km) - max(5 km, 12 km)

= min(8 km, 12 km) - 12 km

= min(8 km, 12 km) - 12 km

= 8 km - 12 km

= -4 km (No coverage within the range)

Since there is no rain cell coverage within the range of interest, the propagation factor due to rain cell 1 is 0 dB.

Rain Cell 2:

The rain cell 2 is located between 8 km to 11 km. Similar to rain cell 1, we calculate the fraction of rain cell coverage within the range of interest.

Fraction of rain cell 2 coverage = (Coverage within range of interest) / (Total rain cell width)

= \(\frac{ (min(11 km, 12 km) - max(8 km, 12 km))}{3 km}\)

Within the range of interest, the coverage is:

Coverage within range of interest = min(11 km, 12 km) - max(8 km, 12 km)

= min(11 km, 12 km) - 12 km

= 11 km - 12 km

= -1 km (No coverage within the range)

Since there is no rain cell coverage within the range of interest, the propagation factor due to rain cell 2 is 0 dB.

Now, we can calculate the total propagation factor (F2) at 12 km by summing up the contributions:

F2 = Clear air absorption + Rain Cell 1 + Rain Cell 2

= 0.048 dB + 0 dB + 0 dB

= 0.048 dB

Therefore, the total propagation factor seen by the radar for a target at 12 km is 0.048 dB.

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Answer:

I think the echo sounds do not depend on the direction of the sound and sound the same as the original sound

Explanation:

An echo is defined as a sound that is produced when a sound wave is reflected back from any hard surface and repeated.

Two major application of echo include:

- Bats, fisherman, and dolphins use echoes to detect or identify any object /obstruction.

- Echo is widely used in medical science applications for imaging of human organs such as echocardiography and ultrasound.

I hope this help you!:)